The events f and s are conditional independent events given d and ~d respectively with p(D|F∩S) is 0.9529.
What is events?
An event in probability theory is a collection of experiment results to which a probability is ascribed. A single outcome might be a component of several events, and since various events in an experiment could have quite diverse groupings of outcomes, they are often not equally probable.
If F and S are conditionally independent given D and ~D, then
P(FSD)= P(D)P(F|D)P(S|D)
P(FS~D) = P(~D)P(F|~D)P(S|~D)
P(F|~D) = 1 - P(~F|~D)
P(S|~D) = 1 - P(~S|~D)
P(~D) = 1 - P(D)
P(D|FS) = P(FSD)/(P(FSD) + P(FS~D))
P(F|D) = P(S|D) = .9
P(~F|~D) = P(~S|~D) = .9
P(D = .2)
Then, P(FSD) = P(D)P(F|D)P(S|D) = .2*.9*.9 = .162
P(FS~D) = P(~D)P(F|~D)P(S|~D) = (1 - .2)(1 - .9)(1 - .9)= .008
P(D|FS) = P(FSD)/(P(FSD) + P(FS~D)) = .162/(.162+.008) = 162/170=81/85 = .9529
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An unpolarized beam of intensity Io = 796 W/m2 travels in the positive z-direction and is incident from the left on a series of three linear polarizers as shown. The transmission axis of the first polarizer is aligned with the y-axis. The following polarizers make angles of θ2 = 59 degrees, and θ3 = 30 degrees with the positive x axis.a) What is I2, the intensity of the beam immediately following the second polarizer?b) What is Ifinal, the intensity of the beam immediately following the third polarizer?c) The positions of the second and third polarizers are now interchanged. What is Ifinal-new, the intensity of the beam after passing through the new arrangement of the three polarizers?d) Suppose we now move our incident unpolarized beam so that it is incident from the right. That is, the beam is now incident upon the polarizer whose transmission axis makes an angle θ2 with the x-axis and exits the last polarizer. Suppose we now rotate the q1 by 90 degrees so that its transmission axis becomes aligned with the x-axis. With the beam still incident from the right (on the polarizer whose transmission axis makes an angle θ2 with the x-axis), what is the Ifinal,Rlnew?
a) I² = Io cos²(θ2) = 796 W/m² x (0.5)² = 198.5 W/m²
b) Ifinal = I2cos²(θ3) = 198.5 W/m² x (0.75)² = 137.2 W/m²
c) Ifinal-new = Io cos²(θ3)cos²(θ2) = 796 W/m² x (0.75)² x (0.5)² = 103.9 W/m²
d) We can calculate the Ifinal,Rlnew by first calculating the intensity of the beam after passing through the first polarizer (I1):
I1 = Io cos²(θ2) = 796 W/m² x (0.5)² = 198.5 W/m²
Then, we can calculate the intensity of the beam after passing through the second polarizer (I2):
I2 = I1cos²(θ3) = 198.5 W/m² x (0.75)²= 137.2 W/m²
Finally, we can calculate the intensity of the beam after passing through the third polarizer (Ifinal,Rlnew):
Ifinal,Rlnew = I2cos²(θ2) = 137.2 W/m² x (0.5)²= 34.3 W/m²
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A 20.0cm massless spring with spring constant 340N/m is suspended from the ceiling. A student carefully hangs a 450g mass from the free end. How long is the spring now?
After hanging the mass, the length of the spring is 21.3 cm using Hooke's law.
What is Hooke's law?According to the physics principle known as Hooke's Law, the force required to expand or compress a spring by a given distance is inversely proportional to that distance.
The first traditional example of an explanation of elasticity is Hooke's law. Elasticity is the quality of a substance or item that allows it to return to its original shape after distortion. A restoration force is a capacity to restore the original shape after experiencing distortion.
Given,
Equilibrium length of the massless spring = 20 cm
Spring constant k = 340 N/m
The spring is suspended from the ceiling.
Mass at the free end = 450 g
= 0.45 kg
A force is applied vertically downward on the spring due to the suspended mass which is equivalent to the weight of the mass i.e.
F = mg ... (1)
This force is balanced by the spring. If the spring is extended by a length of due to the suspension of the mass then by Hooke's law,
F = kx ... (2)
From equation (1) and (2)
mg = kx
x = mg/k
Put all the values
x = (0.45)(9.8)/(340)
= 0.013 m
= 1.3 cm
So, the length of the spring is
l = 20 + 1.3
= 21.3 cm
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a block of mass 500 g is attached to a horizontal spring, whose force constant is 25.0 n/m . the block is undergoing simple harmonic motion with an amplitude of 6.00 cm . at t
The block is undergoing simple harmonic motion with an amplitude of 6.00 cm . at t = 0.325343 sec.
What is simple harmonic motion ?
Simple harmonic motion is defined as a periodic motion of a point along a straight line, such that its acceleration is always towards a fixed point in that line and is proportional to its distance from that point.
given
mass of block(m) = 500 g
force constant (k) = 25.0 N/m
we know simple harmonic motion equation as
y = A sin (ωt + Φ)
where [tex]$\Phi=\sin ^{-1}(-4 / 6)$[/tex]
so we get
[tex]$\Phi=-0.729727656 \mathrm{rad}$[/tex]
and we know
[tex]$$\begin{aligned}& \omega=\sqrt{\frac{k}{m}} \\& y=A \sin \left(t \sqrt{\frac{k}{m}}-0.729727656\right)\end{aligned}$$[/tex]
now substitute the values we get as
[tex]$$\begin{aligned}& \mathbf{y}=\mathbf{0 . 0 6} \mathbf{m} \\& \left.0.06=0.06 \sin \left(t \sqrt{\left(\frac{25}{0.5}\right.}\right)-0.729727656\right) \\& \left(t \frac{25}{0.5}-0.729727656\right)=\frac{\pi}{2}\end{aligned}$$[/tex]
on solving these equation we get[tex]$t=0.325343 \mathrm{sec}$[/tex]
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Question 2 (1 point)
Which section shows constant velocity?
Question 2 options:
a
b
c
d
When the magnitude and direction of the rate at which an object is changing its position remain unchanged, the object has constant velocity.
Which area depicts constant velocity?When the rate at which such an object is changing its position remains constant in magnitude and direction, the object is said to have constant velocity.In other words, an object must move continuously in the same direction and at a constant speed in order to have constant velocity.Uniform velocity is the state in which a body travels the same distance in the same amount of time. When its magnitude and direction do not alter over time, it is possible to say that the body is moving at a constant speed.Although the object is moving at a constant speed, its velocity is changing. As a vector, velocity has a constant magnitude but a fluctuating direction.The various forms of velocities include uniform, variable, average, and instantaneous velocities.To learn more about constant velocity refer to:
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Light is refracted and spread out by a ____. Question 14 options: concave lens convex mirror concave mirror convex lens
Light is refracted and spread out by a concave lens.
What is refraction?Refraction refers to a phenomenon which describes a change (bend) in the path taken by light when it comes in contact with surfaces between different transparent materials. The refraction of light is inversely proportional to its wavelength.
When parallel rays of light enter into a concave lens, the light waves refract outward (spread out). The light rays refract twice: first when entering the lens and second when leaving the lens. Only the light rays passing through the center of the lens remain straight.
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a 2.4 kg purse is dropped from the top of the leaning tower of pisa and falls 55 m before reaching the ground with a speed of 27 m/s. What was the average force of air resistance?
The average force of air resistance is 18.36N.
A force is an influence that can change the motion of an object. A force can cause an object with mass to change its velocity (e.g. moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity. It is measured in the SI unit of newton (N). It is a standard mechanical quantity. Force is represented by the symbol F (formerly P).
Given;
mass=2.4Kg
Hight=55m
Final velocity (v)=27m/s
Noe from kinematics
[tex]v^{2} =u^{2} +2ah[/tex]
Putting the value
[tex]0^{2} =(27)^{2} +2a*55[/tex]
so, a=4.4m/s^2
now, By applying newton's law
mg-F=ma
F=m(g-a)
=2.4(9.8-4.4)
=18.36N
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fgure 24-30 shows a system of three charged particles. if you move th particle of charge from pooint a to point d
A) Moving the three-particle system from A to D has no effect on its electric potential energy.
B) When a particle is transferred from A to D, the total electric force exerted on it produces negative work.
C) When your force is shifted from A to D, it does not produce any work.
D) The values will be zero, negative, and zero if the particle is transferred from B to C.
comprehension of the potential energy idea.The total energy resulting because of all the charges present in the system determines the total potential energy for moving a charge from one location to another. Therefore, total potential energy is positive for two positive charges.
recognizing the idea of completed work.or work done, we just take into account the polarity of charges. The effort completed for equal polarity is found to have a positive regardless of its value. Our force's course determines the job that is accomplished by our force. The work done will be negative for the opposing path and force direction.
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The complete question is -
The figure shows a system of three charged particles. If you move the particle of charge from point A to point D, are the following quantities positive, negative, or zero: (a) the change in the electric potential energy of the three-particle system, (b) the work done by the net electric force on the particle you moved (that is, the net force due to the other two particles), and (c) the work done by your force? (d) What are the answers to (a) through (c) if, instead, the particle is moved from B to C?
A 50 g rock is launched vertically in the air by a slingshot. The slingshot exerts an average force of 53 N on the rock over a distance of 0.750 m.
The work done by the average force is 39.75 J.
What is the work done by the average force?The work done by the average force of the slingshot is calculated by applying the following equation as shown below.
Mathematically, the formula for work done is given as;
W = Fd
where;
F is the average forced is the displacement of the rockThe given parameters include;
average force, f = 53 Ndisplacement, d = 0.75 mThe work done by the average force is calculated as follows;
W = 53 N x 0.75 m
W = 39.75 J
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part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures. a
The particle's maximum displacement from its mean position is measured by its amplitude, which in the graph equals 6 cm. The wavelength is 1.20 nm, and the frequency is 1.67 hz.
A periodic wave's wavelength, or the distance over which the wave's shape repeats, is its spatial period. It is the separation between adjacent spots on a wave that correspond to the same phase. Displacement refers to the idea that something has moved or been shifted. The term "displacement" refers to a shift in an object's position. The following equation serves as a mathematical definition of it: is used to describe the final position's value.
f = 1/T f = 1/0.6 f = 1.67 mHz is the frequency.
Wavelength and frequency are combined to form the wave's speed.
v = f (lamda) lamda = v/f
lamda = v/f
lamda = 2/1.67
lamda = 1.20m
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The complete question is -
part a part complete what is the amplitude of this wave? express your answer in centimeters to two significant figures.
A) What is the amplitude of this wave?
B) What is the frequency of this wave? Express your answer to three significant figures and include the appropriate units.
C) What is the wavelength of this wave?
If m1 is 50 kg and has a velocity of 4 m/s, and m2 is 75 kg and has a velocity of -1 m/s, then what would be the final velocity of object 2 if the two objects collide and bounce off of each other and object 1 has a final velocity of -2 m/s?
The final velocity of object 2 is: 3 m/sec
What is the conservation of mass?According to the rule of conservation of mass, no atoms are created or destroyed during a chemical process. Instead, the atoms combine in a variety of ways to create goods. This explains why each element has the equal amount of atoms on both sides of an equation with balanced symbols.
According to conservation of mass,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Given that,
m₁ = 50 kg
m₂ = 75 kg
u₁ = 4 m/s
u₂ = -1 m/s
v₁ = -2 m/s
v₂ = ?
Now, putting the values,
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
(50 × 4) + [75 × (-1)] = [50 × (-2)] + (75 × v₂)
or, 125 = -100 + 75 v₂
or, 75 v₂ = 225
or, v₂ = 3 m/sec.
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which of the following statements about a mercury barometer are correct? select all that apply. multiple select question. the atmospheric pressure is proportional to the height of the mercury in the tube. the space above the mercury in the inverted tube contains air at atmospheric pressure. the mercury tube is sealed at the top. the barometer contains a tube filled with mercury that is inverted in a container of mercury.
The mercury tube is sealed at the top, and ambient pressure is inversely proportional to the height of the mercury within.
On Mercury, are people still alive?Living on Mercury wouldn't be simple, but it might not be impossible. Remember that you wouldn't last very long without a space suit because there isn't any atmosphere up there. On top of all of this, Mercury experiences one of the Solar System's biggest temperature variations.
What makes Mercury so valuable?Mercury is frequently utilized in numerous devices, including switches and batteries, since it is an effective electrical conductor. In small-scale mining operations, it is utilized to amalgamate gold and silver because it easily joins with other metals.
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(figure 1) shows five identical light bulbs a-e connected to a battery. initially, some of the bulbs light up because the two terminals of each bulb are connected to opposite terminals of the battery. if any wire in the circuit is cut, some bulbs may go out. figure1 of 1 part a part complete which bulbs, if any, go out when a single cut is made at location a? check all that apply. a b c d e none previous answers correct part b which bulbs, if any, go out when a single cut is made at location b? check all that apply. which bulbs, if any, go out when a single cut is made at location ?check all that apply. a b c d e none request answer part c which bulbs, if any, go out when a single cut is made at location c? check all that apply.
Figure shows five identical light bulbs a-e connected to a battery.
Part A: The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B: If a cut is made at point b, then no bulb will go out because C is already fused.
Part C: If a cut is made on C, then no bulb will go out because D and E were already fused.
What is the potential difference?When two places in a circuit contain different amounts of charge carriers' energy, this is referred to as a potential difference.
Part A:
Use the concept of potential difference to understand this question.
The bulb will only be lit when there is some potential difference. If the potential difference is zero, then the bulb will not light.
First, redraw the diagram and shown it below:
The potential at points 1 and 3 is different because of the internal resistance of B, so B is already glowing.
Part B
The potential at points 3 and 4 is the same because there is no resistance between them and the potential across C is 3 and 4. So, the potential difference is zero across C and it was already fused.
So, if a cut is made at point b, then no bulb will go out because C is already fused.
Part C
The potential at points 2, 4, 5, and 6 is the same. The potential across D and E is 5 and 6. The potential difference is zero across them, so they were already fused.
If a cut is made on C, then no bulb will go out because D and E were already fused.
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The complete question is as follows:
A pressure vessel support bracket is to be designed so that it can withstand a tensile loading cycle of 0-500 MN/m2 once every day for 25 years. Which of the following steels would have the greater tolerance to intrinsic defects in this application: (i) a maraging steel (Ke-82 MNm-, C= 0.15 × 10-11, m-41), or (ii) a medium-strength steel (Kic 50 MN m1, C0.24x 10-", m 3.3)? For the loading situation a geometry factor of 1.12 may be assumed.
Ao for a maraging steel (82 M Nm-, C= 0.15 10-11, m-41) is equal to 58.2*10^-6m, and for a medium-strength steel, it is 40.6*10^-6m (50 MN m1, C0.24x 10-", m 3.3). The second case can be more tolerant.
Ultra-high-strength steel alloys, or maraging steels, are a unique class of low-carbon steel that have comparable ductility while being stronger and tougher than most other steels. A structure's capacity to safely withstand until repair can be made is known as damage tolerance. Based on the presumption that defects can exist in any building and that these problems spread with use, the approach to engineering design that takes damage tolerance into account.
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - A)
Ao = 58.2*10^-6m
9125 is equal to 2/c(1/stress)*pi1/2(2-m) (Afinal - Ao)
comparable to case two
Ao = 40.6*10^-6m
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Q1) Give reasons for the following:-
a. a leaf appears green;
____________________________
b. milk appears white;
____________________________
c. the words on a page appear black;
____________________________
Answer:
Explanation:
A leaf appears green becuase of photosyithesis
Milk appears white because all the corols are being aborseb
words on the page are black because all colors are being refcted.
if the samples are 10 cm from the axis if the rotor and the ultracentrifuge spins at 6.6×104 rpm , what is the magnitude of the net force on the rotor due to the unbalanced samples?
The magnitude of the net force on the rotor due to the unbalanced samples is 64.4 N.
What is magnitude of a force?The total amount of forces exerted on an object is referred to as the magnitude of force. The strength of the force increases when all the forces are pulling in the same direction. When forces are exerted on an item from different angles, the force's strength reduces.
If the net force acting on an object is zero, then the object is not accelerating and is in a state that we refer to as equilibrium. The magnitude of the net force acting on an object is equal to the mass of the object multiplied by the acceleration of the object.
radius r = 12 cm = 12 x 10-2 m
Mass : 10 mg = 10 x 10 -6 kg
angular speed ω = 70,000 rpm = 7330.4 rad/sec
The net force is given by :
F = m ω 2r
Substitute the given values in equation
F = (10 * 10[tex](10 * 10^{-6} kg ) * (7330.4rad / s )^{2} * (12 * 10^{-2} m)[/tex]
F = 64.4 N
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An electron is released from rest in a uniform electric field. If the electric field is 1.25 kN/C, at the end of 20 ns
the electron's velocity will be approximately
At the end of 20 ns, the electron's velocity will be approximately 5.2 × 10⁶ m/s.
What is electric field?The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.
Electric charge or magnetic fields with variable amplitudes can produce an electric field. The attraction forces that keep together atomic nuclei and electrons at the atomic scale are brought on by the electric field.
Given that:
the electric field is 1.25 kN/C
So, acceleration of the electron: a = eE/m
= (1.6 × 10⁻¹⁹×1.25×10³)/(9.1×10⁻³¹) m/s²
= 2.6 × 10¹⁴ m/s².
Hence, after the end of 20 ns the electron's velocity will be = at
= 2.6 × 10¹⁴ × 20 × 10⁻⁹ second
= 5.2 × 10⁶ m/s.
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define the principal focus of a concave mirror
The principal focus of a concave mirror is a point on the axis of the mirror at which parallel rays of light are brought to focus after being reflected by the mirror. A concave mirror is a mirror with a curved surface that is shaped like the inside of a bowl, with the center of the curve facing outward. When light rays are reflected by a concave mirror, they are brought to a focus at the principal focus of the mirror. The distance from the center of the mirror to the principal focus is known as the focal length of the mirror. The principal focus of a concave mirror is an important concept in optics and is used in the design and operation of various optical instruments, such as telescopes and cameras.
b(4+a) ;where a = 6 and b - 2
= 2(4+6)
= 2×10
= 20
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Two ball bearings from different manufacturers are being considered for a certain application Bearing A has a catalog rating of 2.0 kN based on a catalog rating system of 3000 hours at 500 rev/min. Bearing B has a catalog rating of 7.0 kN based on a catalog that rates at 10^{6 cycles. For a given application, determine which bearing can carry the larger load.
CB =7 KN , Since CA > Cg bearing A can carry the larger load.
In order to compare the bearings, both bearings need to be rated in
terms of same catalog rating.
Calculation :
Calculate basic load rating for bearing A for one million
revolutions.
CA = FA[tex](\frac{LA}{LR} )^{1/a}[/tex]
= [tex]2(\frac{3000*500*60}{10^{6} } )^{1/3}[/tex]
= 8.96kN
Bearing B already is rated at one million revolutions, CB =7 KN
Since CA > Cg bearing A can carry the larger load.
Bearings are mechanical elements that limit relative motion to a desired degree and reduce friction between moving parts. The bearing design can, for example, provide free linear motion of the moving part or free rotation about a fixed axis. Alternatively, movement can be prevented by controlling the normal force vector acting on the moving part. Most bearings facilitate the necessary movement by minimizing friction. Bearings are broadly classified according to the type of motion, permissible motion, and the direction of load (force) applied to parts.
Slewing bearings support rotating components such as shafts and axles in mechanical systems, transferring axial and radial loads from the load source to the supporting structure. Plain bearings, the simplest type of bearing, consist of a shaft that rotates in a bore.
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when you calculate for the heat necessary for a phase change such from water to steam, you don't need a temperature in your calculation. t/f
Yes, the statement is true, that when we calculate for the heat necessary for a phase change we do not need a temperature in a calculation.
The heat required for the state change of a material is given by the formula,
Q = mL
Where Q is the heat required M is the mass of the material and l is the latent heat of the material.
As we can see from the above formula there is no requirement of the change in temperature of the material in order to calculate the necessary heat for the phase change such as water to steam.
It has to be noted here that when we calculate the heat required during the same phase of the material requires the knowledge of change of temperature.
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What is the distance between Earth and sun if light travels at 300000 km/s and takes 8 mins to reach Earth?; How long can light travel in 300000 km?; Does light travel 300000 km per second?; What is the distance of the sun from the Earth * 7 light minutes 8 light minutes 9 light minutes 10 light minutes?
On average, the Sun is located around 93,000,000 miles (150 million kilometers) from Earth. It is so far away that it takes roughly 8 minutes for the Sun's light, which is moving at a speed of 186,000 miles per second (300,000 kilometers per second), to reach us.
If sunlight needs 8.3 minutes to reach Earth, how far away is Earth from the Sun?The Sun is only 8.3 light minutes away from Earth, or 1.5781e-5 light years, since light travels from the photosphere of the Sun to the Earth in only 8.3 minutes.
In 300000 kilometers, how far can light travel?The distance light travels in a year is measured in light-years. Light travels 5.88 trillion miles and 186,000 miles per second through interstellar space.
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The depth of snow after n hours of a snowstorm is
The depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.
A polynomial function exists as a function that examines only non-negative integer powers or only positive integer exponents of a variable in a formula like the quadratic equation, cubic equation, etc.
Given, depth of the snow after n hours of a snowstorm exists represented by the function f(n+1) = f(n) + 0.8 where, f(0) = 2.5
To find, which statement explains the sequence of numbers rendered by the function.
Given function f(n + 1) = f(n) + 0.8 where f(0) = 2.5
Hence, the depth of snow was 0.8 inches when the storm began and 2.5 inches after the first hour of the storm describes the sequence of numbers generated by the function.
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How do you calculate the rotation speed for a rotating living quarters on a spaceship for 1 g?
To produce the equal of 1 G, you would require a superstructure with a diameter of around 900m and a leisurely 1rpm.
For artificial gravity, how so many rotations per minute are required?Solution:The orbiter must rotate at a rate of 0.04 revolutions per second, or 2.4 revolutions per minute, to imitate Earth's gravity.
How do you determine the g-force in a turn?Just use following formula to translate rotations per minute (RPM) into relative centrifugal (RCF), also known as g force:RCF = (RPM)2 × 1.118 × 10-5 × r.The length of the particle from the rotating center and the rotational speed, measured in RPM, both affect the relative centrifugal force.
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Two identical flasks contain O2 and H2 gas, respectively, at the same temperature and pressure. In comparing the two flasks, which of the following is not a true statement.(a) the average kinetic energy of H2 is greater than that of 02(b) the average speed of a H2 molecule is greater than that of an O2 (c) the number of impacts/(unit area)/(unit tim) are different for the two gases(d) the number of moles is the same e) total mass of each gas is different
Statement a is not True as Kinetic theory of gas clearly suggest that the average Kinetic Energy of gas particles is proportional to Absolute temperature and all gases a the same temperature have the same Average kinetic Energy.
What is kinetic energy ?
The energy an item has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body keeps the kinetic energy it acquired throughout its acceleration unless its speed changes.
A) Flask B is at a higher pressure than flask A.
B) The densities of both gases are the same.
C) Both flasks have the same amount of gas molecules.
D) The pressures of the flasks are the same.
E) Flask B contains more moles of gas than flask A.
F) Both flasks have molecules with the same average kinetic energy.
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A 2.50-kg solid, uniform disk rolls without slipping across a level surface, translating at 3.75 m/s. If the disk’s radius is 0.100 m, find its (a) translational kinetic energy and (b) rotational kinetic energy.
The translational & rotational kinetic energy is :
a) The translational kinetic energy of the disk across the level surface is 17.58J.
b) The rotational kinetic energy of the disk is 8.79J.
How do you find total kinetic energy with translational and rotational?The combined translational and rotational kinetic energies of an item in motion determine its total kinetic energy. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. Total kinetic energy is 12mvCM2 plus 12I2.Ek=12mv2, where m is the mass (mass of the molecule, atom, or ion) and v is the velocity of its Centre of mass, is the energy associated with the movement of a chemical entity.There is just one distinction between rotational and translational kinetic energy: translational energy moves in a straight path, but rotational energy does not. When a bicycle is being ridden down a bike path, its tyre provides an illustration of both kinetic and translational kinetic energy.Learn more about translational & rotational kinetic energy refer to :
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A steel ball of mass 0.500 kg is fastened to a cord that is 70.0 cm long and fixed at the far end. The ball is then released when the cord is horizontal (Fig 9-65). At the bottom of its path, the ball strikes a 2.50 kg steel block initially at rest on a frictionless surface The collision is elastic. Find
(a)the speed of the ball and (b) the speed of the block, both just after the collision.
(a) ball velocity = - 2.47 m/s
(b) block velocity = 1.236 m/s
What is collision?Two items collide when they briefly come into touch with one another. To put it another way, a collision is a brief reciprocal encounter between two masses in which the momentum and energy of the masses change.
For ball as it is at initially at height of 70.0 cm = 0.7 m
so by energy conservation,
K.E.(i) P.E.(i) + K.E.(f)+P.E.(f)
0 + mg×(0.7) = 1/2 mv² + 0
v = 3.71 m/s
now, collision b/w ball and block
as the block is in rest initially and there is no external force b/w them
so by momentum conservation,
m₁u₁+ m₂u₂ = m₁v₁+ m₂v₂
or, (0.5 x 3.71) + 0 = (0.5x v₁) + (2.5 x v₂)
3.71 = v₁ + 5v₂ .........(1)
as elastic collision so energy conservation
or, 1/2 m₁ u₁² + 1/2 m₂ u₂² = 1/2 m₁ v₁² + 1/2 m₂ v₂²
or, (1/2 x 0.5 x 3.712) + 0 = (1/2 x 0.5 x v₁²) + (1/2 x 2.5 x v₂²)
or, 3.433 = 0.25xv₁² + 1.25 v₂² ...............(2)
from eq. 1 and eq. 2
or, 3.433 = 0.25 x (3.71 - 5 v₂)² + 1.25v₂²
or, v² = 1.236 m/s
and v₁ = 3.71 - 5v₂
or, v₁ = - 2.47 m/s
so after collision
ball velocity = - 2.47 m/s [(-)ve x direction]
block velocity = 1.236 m/s [(+)ve x direction]
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A runner can jog at 5m\s how many laps or a 400m track could she complete in 4 minutrs?
Answer:
3 laps
Explanation:
1 minute = 60 seconds.
4 minutes * 60 seconds/ 1 minute = ==> use seconds-minutes conversion
factor to solve for the number of
seconds in 4 minutes
4 * 60 seconds/1 = ==> cancel the minutes unit
4 * 60 seconds = 240 seconds in 4 minutes
Now solve for the number of meters completed in 240 seconds by using the meters-seconds conversion
240 seconds * 5 meters/1 second=
240 * 5 meters/1= ==> cancel the seconds unit
240*5 meters = 1200 meters
Now solve for the number of laps equivalent to 1200 meters by using the laps-meters conversion
1200 meters * 1 lap/400 meters =
1200 * 1 lap/400 = ==> cancel the meters unit
1200 laps/400 =
1200/400 laps = 3 laps
A 2.10 mH toroidal solenoid has an average radius of 5.80 cm and a cross-sectional area of 2.20 cm^2 .A.How many coils does it have? In calculating the flux, assume that B is uniform across a cross section, neglect the variation of B with distance from the toroidal axisB.At what rate must the current through it change so that a potential difference of 2.40 V is developed across its ends?
A toroidal solenoid has 1664 turns.
The rate of current is across it is 1142.86 A/s.
What is a solenoid?
A solenoid is a machine made of a casing, a coil of wire, and a moving plunger (armature). A magnetic field that generates around the coil when an electrical current is applied pulls the plunger in. A solenoid, to put it simply, transforms electrical energy into mechanical work.
Given,
Length L = 2[tex]\pi[/tex]r
= 2[tex]\pi[/tex]×0.058 = 0.3644 m
L = [tex]u_{o}[/tex][tex]N^{2}[/tex]A/l
N= [tex]\sqrt{LXl/u_{oA} }[/tex]
N = [tex]\sqrt{2.1X10^{-3}X0.3644/4\pi X10^{-7}X2.2X10^{-4}}[/tex]
N= 1664 turns
B) V = L [tex]\frac{dl}{dt}[/tex]
[tex]\frac{dl}{dt}[/tex] = [tex]\frac{V}{L}[/tex] = [tex]\frac{2.4}{2.1X10^{-3} }[/tex]
[tex]\frac{dl}{dt}[/tex] = 1142.86 A/s
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A planet travels in an elliptical orbit around its star, as shown above. Which arrow best shows the direction of the net force exerted on the planet?
The arrow that best shows the direction of the net force exerted on the planet is arrow B.
What is the net force exerted on a planet orbiting the sun?
The net force exerted on an object travelling round the sun is known as gravitational force.
According Newton's law of universal gravitation, every two objects in the universe attract each other with a force that is directly proportional to the product of masses of the objects and inversely proportional to the square of the distance between them.
Fg = Gm₁m₂/R²
where;
m₁ is the mass of the first object (planet)m₂ is the mass of the second object (planet)R is the distance between the two objectsThus, gravity is the primary force that controls the orbit of the planets around the sun and it is directed towards the sun.
Each planet has its own gravity based on the size of the planet and the speed at which it travels round the sun.
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all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to all points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion translation rotation about a fixed axis none of the above
All points in a rigid body move with the same velocity and acceleration if the rigid body is subjected to general plane motion.
The general plane motion refers to the movement of a rigid body in two dimensions, where the body can translate (move in a straight line) and rotate about a fixed axis. When a rigid body is subjected to general plane motion, all points on the body will move with the same velocity and acceleration, as the body is rigid and does not deform.
This is in contrast to translation, which refers to movement in a straight line, and rotation about a fixed axis, which refers to rotation around a fixed point. In these cases, the points on the body will not necessarily move with the same velocity and acceleration, as the body is able to deform and rotate.
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