Suppose that on the average, 7 students enrolled in a small liberal arts college have their automobiles stolen during the semester. What is the probability that less than 1 student will have his automobile stolen during the current semester

Given that exp(2x) is a solution, we assume another solution of the form

y(x) = v(x) exp(2x) = v exp(2x)

with derivatives

y' = v' exp(2x) + 2v exp(2x)

y'' = v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)

Substitute these into the equation:

(2x + 5) (v'' exp(2x) + 4v' exp(2x) + 4v exp(2x)) - 4 (x + 3) (v' exp(2x) + 2v exp(2x)) + 4v exp(2x) = 0

Each term contains a factor of exp(2x) that can be divided out:

(2x + 5) (v'' + 4v' + 4v) - 4 (x + 3) (v' + 2v) + 4v = 0

Expanding and simplifying eliminates the v term:

(2x + 5) v'' + (4x + 8) v' = 0

Substitute w(x) = v'(x) to reduce the order of the equation, and you're left with a linear ODE:

(2x + 5) w' + (4x + 8) w = 0

w' + (4x + 8)/(2x + 5) w = 0

I'll use the integrating factor method. The IF is

µ(x) = exp( ∫ (4x + 8)/(2x + 5) dx ) = exp(2x - log|2x + 5|) = exp(2x)/(2x + 5)

Multiply through the ODE in w by µ :

µw' + µ (4x + 8)/(2x + 5) w = 0

The left side is the derivative of a product:

[µw]' = 0

Integrate both sides:

∫ [µw]' dx = ∫ 0 dx

µw = C

Replace w with v', then integrate to solve for v :

exp(2x)/(2x + 5) v' = C

v' = C (2x + 5) exp(-2x)

∫ v' dx = ∫ C (2x + 5) exp(-2x) dx

v = C₁ (x + 3) exp(-2x) + C₂

Replace v with y exp(-2x) and solve for y :

y exp(-2x) = C₁ (x + 3) exp(-2x) + C₂

y = C₁ (x + 3) + C₂ exp(2x)

It follows that the second fundamental solution is y = x + 3. (The exp(2x) here is already accounted for as the first solution.)

9514 1404 393

Answer:

Step-by-step explanation:

Of the items sold, sodas were 2/(2+1) = 2/3 of the total.

  (2/3)(228) = 152 . . . sodas were sold

  152/2 = 76 . . . . hot dogs were sold

Answer:

8x-7y=6

or, -7y=-8x+6

or, y=8x/7-6/7

so the slope is 8/7

8x-y=-8

or, -y=-8x-8

or, y=8x+8

So the slope is 8

Both has different slope and they don't satisfy the property of being perpendicular to each others, so they're neither parallel nor perpendicular.

Answered by GAUTHMATH

Answer:

$36.5 money ms.weaver spent for the items

Answer:

x = 4

y = 3

Step-by-step explanation:

Given equations :-

Second equation can be written as ,

Adding them :-

Put this in (ii) :-

Answer:

(a) 20226 units

(b) Marginal productivities

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]

(c) Evaluation of the marginal productivities

[tex]P_x =803[/tex]

[tex]P_y = 15[/tex]

Step-by-step explanation:

Given

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex]

Solving (a): P(x,y) when x = 26 and y = 1333

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P(26,1333) = 2500*26^\frac{1}{5}*1333^\frac{1}{5}[/tex]

[tex]P(26,1333) = 20226[/tex] --- approximated

Solving (b): The marginal productivities

To do this, we simply calculate Px and Py

Differentiate x to give Px, so we have:

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P_x =2500 * x^{\frac{1}{5}-1} & y^\frac{1}{5}[/tex]

[tex]P_x =2500 * x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex]

Differentiate y to give Py, so we have:

[tex]P(x,y) = 2500x^\frac{1}{5}y^\frac{1}{5}[/tex] becomes

[tex]P_y =2500 * x^\frac{1}{5} & y^{\frac{1}{5}-1}[/tex]

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex]

Solving (c): Px and Py when x = 25 and y = 1333

[tex]P_x =2500x^{-\frac{4}{5}} & y^\frac{1}{5}[/tex] becomes

[tex]P_x =2500 * 25^{-\frac{4}{5}} * 1333^\frac{1}{5}[/tex]

[tex]P_x =803[/tex] --- approximated

[tex]P_y =2500 x^\frac{1}{5} y^{-\frac{4}{5}}[/tex] becomes

[tex]P_y =2500 * 25^\frac{1}{5} * 1333^\frac{-4}{5}[/tex]

[tex]P_y = 15[/tex]

Answer:

The confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.99}{2} = 0.005[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a pvalue of [tex]1 - 0.005 = 0.995[/tex], so Z = 2.575.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

In this question:

[tex]M = 1.99\frac{\sigma}{\sqrt{35}}[/tex]

The lower end of the interval is the sample mean subtracted by M, while upper end of the interval is the sample mean added to M. Thus, the confidence interval is [tex](\overline{x} - 1.99\frac{\sigma}{\sqrt{35}}, \overline{x} + 1.99\frac{\sigma}{\sqrt{35}})[/tex], in which [tex]\overline{x}[/tex] is the sample mean and [tex]\sigma[/tex] is the standard deviation for the population.

Answer:

m∠GHI = 160

Step-by-step explanation:

From the question given above, the following data were obtained:

m∠GHI = 14x + 6

m∠QHI = 130°

m∠GHQ = 3x – 3

m∠GHI =?

Next, we shall determine the value of x. This can be obtained as follow:

m∠GHI = m∠QHI + m∠GHQ

14x + 6 = 130 + (3x – 3)

14x + 6 = 130 + 3x – 3

Collect like terms

14x – 3x = 130 – 3 – 6

11x = 121

Divide both side by 11

x = 121 / 11

x = 11

Finally, we shall determine the value m∠GHI. This can be obtained as follow:

m∠GHI = 14x + 6

x = 11

m∠GHI = 14(11) + 6

m∠GHI = 154 + 6

m∠GHI = 160

Answer:

See Explanation

Step-by-step explanation:

According to the Question,

(a) The sample is from all computer chips manufactured at the factory during the week of production. We might be tempted to generalize the population to represent all weeks, but we should exercise caution here since the rate of defects may change over time.

(b) The fraction of computer chips manufactured at the factory during the week of production that had defects.

(c) Estimate the parameter using the data: phat = 27/212 = 0.127.

(d) Standard error (or SE).

(e) Compute the SE using phat = 0.127 in place of p:

SE ≈ √(phat(1−phat)/n) = 0.023.

(f) The standard error is the standard deviation of phat. A value of 0.10 would be about one standard error away from the observed value, which would not represent a very uncommon deviation. (Usually beyond about 2 standard errors is a good rule of thumb.) The engineer should not be surprised.

(g) Recomputed standard error using p = 0.1: SE = 0.021. This value isn't very different, which is typical when the standard error is computed using relatively similar proportions (and even sometimes when those proportions are quite different!).

9514 1404 393

Answer:

Step-by-step explanation:

There are a couple of relations that are applicable to these questions.

__

The segment lengths relation tells us ...

  10x = 8×7 . . . . . . products of segment lengths are equal

  x = 56/10 = 5.6 . . . . divide by 10

__

The value of y° is the average of the intercepted arcs:

  y° = (85° +45°)/2 = 65°

_____

Additional comment

This diagram does not have enough information to allow computation of z. We would need to know the intercepted arc, or the length of the secant that meets tangent z.

Answer:

<LKJ = 115°

Step-by-step explanation:

<LKJ = <LKD + <DKJ

<LKJ = 60°+55°

<LKJ = 115°

Answered by GAUTHMATH

Answer:

[tex] \large{ \tt{✺ \: m \: \angle \: LKJ= m \: \angle} \: LKD \: + \: m \: \angle \: dKJ}[/tex]

[tex] \large{ \tt{⟶ \: m \: \angle \: LKJ= 60 \degree + 55 \degree}}[/tex]

[tex] \large{ \boxed{ \tt{⟶ \: m \: \angle \: LKJ = 115 \degree}}}[/tex]

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

Iam going to do question 21

Step-by-step explanation:

1/7*x=2

1/7x=2

x=2:1/7

x=2*7/1

x=14

Answer: 1, 4

Step-by-step explanation:

[tex]\frac{1}{4} x+x=5\\\\\frac{1}{4} x+\frac{4}{4} x=5\\\\\frac{5}{4} x=5\\\\5x=4*5\\5x=20\\x=4[/tex]

Answer:

x=40

Step-by-step explanation:

In the picture, it seems that angles BHC, CHD, and DHE form a line, 180 degrees. So to solve, set up an equation:

[tex](2x+5)+55+40=180[/tex]

Take off the parentheses and solve.

Subtract 5, 55 and 40 from both sides, or add them together, then subtract.

5+55+40=100

You get:

[tex]2x=80[/tex]

Divide both sides by 2

You get:

I hope this helps!

Answer:2x + 50 > 68

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

because is you skip count on two you will count on to 68 so that is why the answer is 7.

I'll use the integrating factor method for the first DE, and undetermined coefficients for the second one.

(a) Multiply both sides by exp(7t ):

exp(7t ) dx/dt + 7 exp(7t ) x = 5 exp(7t ) cos(2t )

The left side is now the derivative of a product:

d/dt [exp(7t ) x] = 5 exp(7t ) cos(2t )

Integrate both sides:

exp(7t ) x = 10/53 exp(7t ) sin(2t ) + 35/53 exp(7t ) cos(2t ) + C

Solve for x :

x = 10/53 sin(2t ) + 35/53 cos(2t ) + C exp(-7t )

(b) Solve the corresonding homogeneous DE:

d²x/dt ² + 6 dx/dt + 8x = 0

has characteristic equation

r ² + 6r + 8 = (r + 4) (r + 2) = 0

with roots at r = -4 and r = -2. So the characteristic solution is

x (char.) = C₁ exp(-4t ) + C₂ exp(-2t )

For the particular solution, assume an ansatz of the form

x (part.) = a cos(3t ) + b sin(3t )

with derivatives

dx/dt = -3a sin(3t ) + 3b cos(3t )

d²x/dt ² = -9a cos(3t ) - 9b sin(3t )

Substitute these into the non-homogeneous DE and solve for the coefficients:

(-9a cos(3t ) - 9b sin(3t ))

… + 6 (-3a sin(3t ) + 3b cos(3t ))

… + 8 (a cos(3t ) + b sin(3t ))

= (-a + 18b) cos(3t ) + (-18a - b) sin(3t ) = 5 sin(3t )

So we have

-a + 18b = 0

-18a - b = 5

==>   a = -18/65 and b = -1/65

so that the particular solution is

x (part.) = -18/65 cos(3t ) - 1/65 sin(3t )

and thus the general solution is

x (gen.) = x (char.) + x (part.)

x = C₁ exp(-4t ) + C₂ exp(-2t ) - 18/65 cos(3t ) - 1/65 sin(3t )

Answer:

False

Step-by-step explanation:

A field book is a private notepad used by a surveyor to record measurements and notes.

Basically, the size of a field book is 200 millimeters × 120 millimeters (20 centimeters × 12 centimeters) and it's typically opened lengthwise. There are two (2) main types of field book and these includes;

I. Double-line field book.

II. Single-line field book.

As a general rule, it's best that all findings, entries (notes) and observations are recorded or made into a field book after each and every measurement have been taken by a surveyor.

In conclusion, a field book is considered to be a legal document used by surveyors to keep records of accomplished field work or work done in the field. Thus, it's not a private notepad used by a surveyor to transcribe notes.

Answer:

False

Step-by-step explanation:

A field book is a private notepad used by a surveyor to transcribe notes and is not considered a legal document is False.

Total outcomes=6 i.e{1,2,3,4,5,6 }

No.of favourable outcomes = 3 i.e {I, 3,5}

P(odd)=3/6=1/2

Answer:

1/ 2

Step-by-step explanation:

[tex]probability \: of \:an \:event\: = \frac{number \: of \: favorable outcomes}{total \: number \: of \: outcomes} [/tex]

favorable outcomes = odd numbers

=1, 3, 5

number of favorable outcomes = 3

total outcomes

= 1, 2, 3, 4, 5, 6

total number of outcomes = 6

probability = 3/ 6

= 1/ 2

Answer:

W and X

Y and Z arent functions because some of their domains (x value) have different inputs. Each domain can only have one input.

Answer:

you mean the mean not the meaning right?

The mean proportional of 3 and 27 = +√3×27 = +√81 = 9.

Answer:

A. 754 cm²

Step-by-step explanation:

Amount of cardboard needed = surface area of the cone

Curved surface area of the cone = πrl

Where,

π = 3.14

r = ½(20) = 10 cm

l = 24 cm

Plug in the values into the formula

Curved surface area = 3.14 × 10 × 24 = 753.6 ≈ 754 cm²

Answer:

C. y=7/9x+17/9

Step-by-step explanation:

Take the slope. slope= m = y2-y1/x2-x1

=5-(-2)/4-(-5)

=7/9

Then put it into point-slope form.

y-y1=m(x-x1)

=y-5=7/9(x-4)

Simplify.

y=7/9x-28/9+5

y=7/9x+17/9

Answer:

C

Step-by-step explanation:

First find the slope (change in y/ change in x) which is positive 7/9.

Then use y=mx+b and plug in the slope, and one of the given points to solve for b.

5= 7/9*4+b

5=28/9+b

5-28/9=b

45/9-28/9=b

17/9=b

Then with the slope and y intercept(b) you get the equation shown in answer c.

Hope that helps!

Answer:

62.5%

Step-by-step explanation:

Given that :

20 cup bowl of punch = 75% Juice

We can infer that :

The number of cups of JUICE is :

75% * 20 = 0.75 * 20 = 15 cups

Adding 4 cups of water to the 20 cups, we have = 24 cups

With 15 cups of JUICE ;

The percentage of the new punch that is juice will be x

x% of 24 cups = 15 cups

x/100 * 24 = 15

0.01x * 24 = 15

0.24x = 15

x = 15 / 0.24

x = 62.5

x = 62.5%

Answer:

It's C

62.5% btw

Step-by-step explanation:

Did the quiz lol

Answer:

42 and 39

Step-by-step explanation:

The best method in my opinion is to guess and check. So, you would start off by dividing 1638 by any number you see fit (I started with 34), and keep increasing or decreasing until you get whole numbers that are three integers apart. I understand that this is a little tedious but I'm not aware of a better solution as of right now, so that's the best that I've got! Please let me know if you need more help and I will be happy to help!

Answer:

(-2,-1)

Step-by-step explanation:

let the number=x

its reciprocal=1/x

x+2(1/x)=-3

x+2/x=-3

x²+2=-3x

x²+3x+2=0

(x+2)(x+1)=0

x=-2,-1

Answer:

a) Figure B and Figure C

b) Figure C

c) Figure A, Figure B, and Figure C

Step-by-step explanation:

a) Rectangles are shapes that have four sides, and four right angels. Right angles are angles that are 90 degrees.

The only shapes with four sides AND four right angles are Figure C and Figure B.

b) Squares are shapes with four EQUAL sides and four right angles. The only shape with four equal sides and four right angles is Figure C.

c) Parallelograms are any shapes with four sides. All of these shapes have four sides.

Hope this helps!

Answer:

O 4x+2y=8.

Hope this helps you

Answer:

A dot product is the product of the magnitude of the vectors and the cos of the angle between them. A cross product is the product of the magnitude of the vectors and the sine of the angle that they subtend on each other.

Step-by-step explanation: