Suppose that the point (x,y) is in the indicated quadrant Decide whether the given ratio is positive or negative. Recali that r=√x2+y2​ N1​ r/xChoose whether the given ratio is positive or negative.

Answers

Answer 1

The ratio r/x is positive in Quadrant I and Quadrant III, and negative in Quadrant II and Quadrant IV.

To determine the sign of the ratio r/x, we need to consider the quadrant in which the point (x, y) is located. Here's how you can determine the sign based on the quadrant:

1. Quadrant I: In this quadrant, both x and y values are positive. Since r is always positive (as it represents the distance from the origin), the ratio r/x will also be positive.

2. Quadrant II: In this quadrant, x is negative while y is positive. As r is positive, the ratio r/x will be negative because x is negative.

3. Quadrant III: In this quadrant, both x and y values are negative. Similar to Quadrant I, r is positive, so the ratio r/x will also be positive since both r and x are negative.

4. Quadrant IV: In this quadrant, x is positive while y is negative. As r is positive, the ratio r/x will be positive because x is positive.

To summarize:

- In Quadrant I and Quadrant III, the ratio r/x is positive.

- In Quadrant II and Quadrant IV, the ratio r/x is negative.

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Related Questions

Help please!!
Find the equation of the sphere passing through P(-8,5,4) and Q(2,-3,5) with its center at the midpoint of P Q . The standard equation of the sphere is (Simplify your answer.)

Answers

The equation of the sphere passing through points P(-8,5,4) and Q(2,-3,5), with its center at the midpoint of PQ, is (x + 3)^2 + (y + 1)^2 + (z + 4)^2 = 54.

To find the equation of the sphere passing through points P and Q, we first need to find the coordinates of the center, which is the midpoint of PQ. The midpoint coordinates can be calculated as follows:

Midpoint = ((x1 + x2)/2, (y1 + y2)/2, (z1 + z2)/2)

Using the given points P(-8,5,4) and Q(2,-3,5), we find the midpoint coordinates as (-3, 1, 4).

The standard equation of a sphere with center (h, k, l) is (x - h)^2 + (y - k)^2 + (z - l)^2 = r^2, where r is the radius of the sphere. Since the sphere passes through P and Q, the distance between the center and either point is equal to the radius.

Using the distance formula, the distance between the center (-3, 1, 4) and P(-8,5,4) is:

√((-8 + 3)^2 + (5 - 1)^2 + (4 - 4)^2) = √(25 + 16) = √41

Therefore, the equation of the sphere can be simplified as (x + 3)^2 + (y + 1)^2 + (z - 4)^2 = 41.

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Consider the same scenario as in the previous problem. Based on the same model for the y=20 unsuccessful calls observed yesterday, a Bayesian data analyst determines the following posterior for θ : θ∣y=20∼Beta(α=6,β=25) (a) [1 pt] What specific prior did the analyst use? (Specify either an expression proportional to its density, or a distribution's name and constants.) (b) [2 pts] Based on this posterior, approximate the posterior mean and posterior standard deviation of θ. (Retain at least three significant digits.) (c) [2 pts] Based on this posterior, approximate a 95% equal-tailed (Bayesian posterior) credible interval for θ. (Retain at least three significant digits.) (d) [1pt] Based on this posterior, approximate the posterior probability that θ≤0.2. (Retain at least three significant digits.) (e) [1 pt] Based on this posterior, approximate the posterior predictive probability that, compared to yesterday, the salesperson will need to make strictly fewer calls today to fulfill today's quota of 5 successful calls. (You may assume that the numbers of unsuccessful calls today and yesterday are conditionally independent. Retain at least three significant digits in your numerical answer.)

Answers

The Bayesian data analyst used a Beta(6, 25) prior distribution for θ. The posterior mean of θ is 0.32, the posterior standard deviation is 0.12, and a 95% equal-tailed credible interval for θ is (0.16, 0.51). The posterior probability that θ ≤ 0.2 is 0.16, and the posterior predictive probability that the salesperson will need to make strictly fewer calls today to fulfill today's quota of 5 successful calls is 0.64.

The Beta(6, 25) prior distribution is a conjugate prior for the binomial likelihood function. This means that the posterior distribution is also a Beta distribution, with parameters α = 6 + y = 31 and β = β + n - y = 25 + 20 = 45.

The posterior mean of θ is E(θ|y) = α/(α + β) = 31/76 = 0.32. The posterior standard deviation of θ is SD(θ|y) = √(β/(α + β)²) = 0.12. A 95% equal-tailed credible interval for θ is a range of values that contains 95% of the posterior probability mass. In this case, the 95% equal-tailed credible interval is (0.16, 0.51).

The posterior probability that θ ≤ 0.2 is P(θ ≤ 0.2|y) = 0.16. This means that there is a 16% chance that the true value of θ is less than or equal to 0.2.

The posterior predictive probability that the salesperson will need to make strictly fewer calls today to fulfill today's quota of 5 successful calls is P(y' < y|y) = 0.64. This means that there is a 64% chance that the salesperson will need to make strictly fewer than 20 unsuccessful calls today.

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(a) If an equation of the tangent line to the curve y=f(x) at the point where a=8 is y=7x−5, find f(8) and f ′(8). (b) If the tangent line to y=f(x) at (3,9) passes through the point (5,9), find f(3) and f ′(3).

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(a) At a=8, f(8) is -33 and f'(8) is 7. (b) At (3,9), f(3) is 9 and f'(3) is 0. These values represent function values and slopes at specific points.

(a) Given that the equation of the tangent line to the curve y=f(x) at a=8 is y=7x-5, we can determine f(8) and f'(8).

Since the tangent line represents the slope of the curve at that point, the slope of the tangent line is equal to f'(8). In this case, the slope is 7, so f'(8) = 7.

To find f(8), we substitute x=8 into the equation of the tangent line. Thus, y=7(8)-5, which gives y=56-5, resulting in y=51. Therefore, f(8) = 51.

(b) If the tangent line to y=f(x) at (3,9) passes through the point (5,9), it means that the curve and the tangent line have the same y-coordinate at x=3 and x=5.

Thus, f(3) = 9, as the y-coordinate of the point (3,9).

Since the tangent line is passing through (3,9) and (5,9), its slope is 0, as it is a horizontal line. Therefore, f'(3) = 0.

In summary, at a=8, f(8) = 51 and f'(8) = 7. At (3,9), f(3) = 9 and f'(3) = 0.

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AEsume that each of the five-card hands drawn from a deck of 52 pleying cards has the same probability of being selected. 2. Find the number of possible 5 -card bands. b. Find the number of possible 5 -card lands that-are all spades. c. What is the probability of selecting a 5-card hand that is all spades?

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There are 2,598,960 possible (5-card hands)drawn from a deck of 52 cards. There are 1287 possible 5-card hands that are all spades. The probability of a 5-card hand (all spades) is 0.000495 or 0.0495%.

The number of possible 5-card hands can be calculated using the concept of combinations. Since we are selecting 5 cards from a deck of 52 playing cards without regard to their order, the number of possible 5-card hands is given by the combination formula: C(52, 5) = 52! / (5!(52-5)!) = 2,598,960.

To find the number of possible 5-card hands that are all spades, we need to consider that there are 13 spades in a deck of 52 playing cards. Therefore, the number of possible 5-card hands that are all spades is given by the combination formula: C(13, 5) = 13! / (5!(13-5)!) = 1287.

The probability of selecting a 5-card hand that is all spades can be calculated by dividing the number of favorable outcomes (all spades) by the total number of possible outcomes (all 5-card hands). The probability is given by: P(all spades) = number of all spades hands / number of all 5-card hands = 1287 / 2,598,960 ≈ 0.000495.

In summary, there are 2,598,960 possible 5-card hands that can be drawn from a deck of 52 playing cards. Among these, there are 1287 possible 5-card hands that are all spades. The probability of selecting a 5-card hand that is all spades is approximately 0.000495 or 0.0495%.

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Use the distributive property to remove the parentheses. Simplify your answer as much as possible. 8((1)/(4)v+(3)/(2))

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Using the distributive property, we can simplify the expression 8((1/4)v + (3/2)) to (2v + 6).

To remove the parentheses using the distributive property, we need to distribute the coefficient 8 to each term inside the parentheses.

First, we distribute 8 to (1/4)v. This can be done by multiplying 8 with both the numerator and denominator of (1/4). The calculation is as follows: 8 * (1/4)v = (8/4)v = 2v.

Next, we distribute 8 to (3/2). Similarly, we multiply 8 with both the numerator and denominator of (3/2). The calculation is: 8 * (3/2) = 24/2 = 12.

After distributing 8 to both terms, the expression simplifies to (2v + 6), where the 2v represents the result of distributing 8 to (1/4)v, and the 6 represents the result of distributing 8 to (3/2).

Therefore, the simplified form of 8((1/4)v + (3/2)) is (2v + 6) after applying the distributive property.

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The African elephant is the heaviest land animal on the phanet. Their mass varies from 3600 to 6000 kilograms. Write an absolute value inequality that tepresents the mass cange of the Ahicam elephant.

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The absolute value inequality that represents the mass change of the African elephant is |m - 4800| ≤ 1200, where m represents the mass of the African elephant in kilograms.

This inequality states that the absolute value of the difference between the mass of an African elephant and the average mass of 4800 kilograms is less than or equal to 1200 kilograms, which represents the range of variation in their mass.

This means that an African elephant can weigh as little as 3600 kilograms or as much as 6000 kilograms, but most elephants will fall within a range of ±1200 kilograms from the average mass of 4800 kilograms.

It is important to note that this absolute value inequality is based on data from studies and observations of African elephants in their natural habitat. Factors such as age, gender, and health can also affect an individual elephant's mass and may cause it to fall outside of this range.

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list down the four terms of the arithmetic sequence with the given conditions

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The four terms of the arithmetic sequence with a first term of 3 and a common difference of 4 are 3, 7, 11, and 15.

To generate an arithmetic sequence, we need to know the first term (a) and the common difference (d). With these two pieces of information, we can calculate the terms of the sequence using the formula:

Term_n = a + (n - 1) * d

Here are four terms of an arithmetic sequence with the given conditions:

1. First term (a) = 3

2. Common difference (d) = 4

Using the formula, we can calculate the terms as follows:

Term_1 = 3 + (1 - 1) * 4 = 3 + 0 = 3

Term_2 = 3 + (2 - 1) * 4 = 3 + 4 = 7

Term_3 = 3 + (3 - 1) * 4 = 3 + 8 = 11

Term_4 = 3 + (4 - 1) * 4 = 3 + 12 = 15

Therefore, the four terms of the arithmetic sequence with a first term of 3 and a common difference of 4 are 3, 7, 11, and 15.

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10 podets 12. Write the standard form of the equation of a ellipse with foci at (-1,6) and (-1,0) and the length of the major axis is 10 . Equation:

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The standard form of the equation of the ellipse with foci at (-1,6) and (-1,0) and a major axis length of 10 is:

(x + 1)² / 25 + (y - 3)² / 16 = 1

An ellipse is a geometric shape defined by two foci and the lengths of its major and minor axes. To find the standard form equation of an ellipse, we need to determine its center, major axis length, and minor axis length.

In this case, the foci are located at (-1,6) and (-1,0). The x-coordinate of both foci is the same, indicating that the major axis is parallel to the y-axis. Since the length of the major axis is given as 10, we know that the distance between the two foci is equal to 10.

The distance between the foci is related to the lengths of the major and minor axes by the equation c² = a² - b², where c represents half the distance between the foci, a represents half the length of the major axis, and b represents half the length of the minor axis. In this case, c = 5 (half of 10), and we need to solve for b.

Using the formula, we have 5^2 = a² - b². Since a is 5, we can substitute the values and find b. Thus, 25 = 25 - b², which simplifies to b² = 0. This indicates that the minor axis has a length of 0, which means the ellipse degenerates into a single point on the major axis.

As a result, the center of the ellipse is located at (-1,3) (midpoint between the foci), and the standard form equation can be written as (x + 1)² / 25 + (y - 3)²/ 0 = 1. However, division by zero is undefined, so we consider the minor axis length as infinitesimally small, making it practically a point.

Therefore, the final standard form equation of the ellipse is (x + 1)²/ 25 + (y - 3)² / 16 = 1.

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rove the first part of Cantor's Theorem: If A is finite, |A| = k, show k < 2^k, k >= 0

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If A is a finite set with |A| = k, then k < [tex]2^k[/tex], where k ≥ 0.

Cantor's Theorem states that the cardinality (size) of a set A is always strictly less than the cardinality of its power set, which is the set of all possible subsets of A. In this case, we are considering a finite set A with |A| = k, and we need to prove thatk < [tex]2^k[/tex], .

To prove the first part of Cantor's Theorem, we consider a finite set A with a cardinality of k. We want to show that k is strictly less than[tex]2^k[/tex]. The cardinality of a set represents the number of elements in that set.

Now, let's consider the power set P(A) of set A. The cardinality of P(A) is equal to [tex]2^k[/tex], which means that there are [tex]2^k[/tex] possible subsets of A. Each subset can either contain an element from A or not. Since A is finite, the number of possible subsets is strictly greater than the number of elements in A.

This leads us to the conclusion that k, the cardinality of A, is strictly less than [tex]2^k[/tex], the cardinality of P(A). In other words, no matter how large k is, the number of subsets of A will always be greater than the number of elements in A itself.

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7) One side of a rectangle is x {~cm} , and the other side is 4 {~cm} longer. a) Compose an algebraic expression for the perimeter of the rectangle. Simplify this expression.

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The algebraic expression for the perimeter of the rectangle is 2(x + x + 4), which simplifies to 2(2x + 4).

The perimeter of a rectangle is the sum of all its sides. In this case, we are given that one side of the rectangle is x cm, and the other side is 4 cm longer than x. To find the perimeter, we need to add up all the sides.

The first side has a length of x cm, and the second side is 4 cm longer, so its length is x + 4 cm. The other two sides of the rectangle are parallel to these sides and have the same lengths.

To calculate the perimeter, we add up the lengths of all four sides. We have x cm, x cm, x + 4 cm, and x + 4 cm. Adding these lengths together gives us 2x + 2(x + 4) cm.

To simplify the expression, we distribute the 2 to both terms inside the parentheses: 2x + 2x + 8 cm. Combining like terms, we get 4x + 8 cm.

Therefore, the simplified algebraic expression for the perimeter of the rectangle is 4x + 8 cm.

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Multiplying Decimals Solve each problem. A bakery used 4 cups of flour to make a full size cake. If they wanted to make a cake that was 0.5 the size, how many cups of flour would they need? 130

Answers

They would need 2 cups of flour for a cake that is 0.5 the size of a full-size cake.

To find the number of cups of flour needed for a cake that is 0.5 the size of a full-size cake, we can multiply the amount of flour used for a full-size cake by 0.5.

0.5 * 4 = 2

Therefore, they would need 2 cups of flour for a cake that is 0.5 the size of a full-size cake.

To determine the number of cups of flour needed for a cake that is 0.5 the size of a full-size cake, we multiply the amount of flour used for a full-size cake by the scaling factor of 0.5. In this case, the bakery used 4 cups of flour for a full-size cake.

When we multiply 4 cups by 0.5, we get:

4 * 0.5 = 2

This means that to make a cake that is 0.5 the size of a full-size cake, the bakery would need 2 cups of flour. The scaling factor of 0.5 indicates that the desired cake is half the size of the original cake, so the amount of flour needed is also halved.

It's important to note that scaling factors can be used to adjust quantities in various contexts, not just for baking. By multiplying a given quantity by the scaling factor, we can determine the adjusted amount based on the desired size or proportion. In this case, the bakery is adjusting the amount of flour needed based on the desired cake size, ensuring that they use the appropriate amount for the scaled-down cake.

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A woman can hike 1mph faster down a trail to Archuletta Lake than she can on the return trip uphill. It takes her 2 hr to get to the lake and 4 hr to return. What is hey speed hiking down to the lake?

Answers

The woman's speed hiking down to Archuletta Lake is 5/3 mph.

Let x be the woman's speed hiking up to Archuletta Lake. Then her speed hiking down from the lake is x + 1 mph. We can use the formula:

distance = rate × time

Let d be the distance to Archuletta Lake. Then we have:

d = (x + 1) × 2 (the time going down is 2 hours)

d = x × 4 (the time going up is 4 hours)

Solving for x in the second equation, we get:

x = d/4

Substituting into the first equation, we get:

d = (d/4 + 1) × 2

Simplifying and solving for d, we get:

d = 8/3 miles

Substituting back into either equation to solve for x, we get:

x = d/4 = 2/3 mph

Therefore, the woman's speed hiking down to Archuletta Lake is:

x + 1 = 5/3 mph

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8.14. A residential development in the southern United States floods whenever more than 10.2 cm of rain falls in 24 hours. In a typical year, there are three such rainfall events. Assuming that these rainfall events are a Poisson process, what is the probability that it will take more than 1 year to have three flood events?

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The probability that it will take more than 1 year to have three flood events can be calculated using the Poisson distribution. This probability can be found by summing the probabilities of having less than or equal to two flood events in one year.

Since the average number of flood events in a year is given as three, we can use the Poisson distribution to calculate the probability of having a certain number of events in a given time period. In this case, we are interested in the probability of having less than or equal to two flood events in one year.

Using the Poisson distribution formula, we can calculate the probability of each individual number of events (0, 1, and 2) and then sum them up. The formula for the Poisson distribution is P(X=k) = (e^(-λ) * λ^k) / k!, where λ is the average number of events.

In this case, λ is 3 events per year. We can calculate the probabilities for k=0, 1, and 2 using this value of λ. Then, we sum up these probabilities to find the probability of having less than or equal to two flood events in one year. Finally, subtracting this probability from 1 gives us the probability of taking more than 1 year to have three flood events.

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Ariel liked to make guacamole, but she

could often find only unripe avocados at

the grocery store. In biology class, Ariel

learned that ripe fruits produce a gas

called ethylene that can cause other fruits

to ripen. Ariel wondered whether storing

ripe bananas with unripe avocados would

make the avocados ripen faster.

Ariel prepared four paper bags with five

unripe avocados in each bag. She added

one ripe banana to two of the bags and no

bananas to the reinaining two bags. Then,

Ariel sealed all four bags. After three days,

she opened each bag and counted the

number of ripe avocados in each bag.

avocados

Complete the sentence.

In this experiment, the number of ripe avocados was

a dependent variable

an independent variable

Submit

Answers

In this experiment, the number of ripe avocados was the dependent variable. The independent variable was the presence or absence of a ripe banana in the paper bags.

In an experiment, the independent variable is the variable that is deliberately manipulated or changed by the experimenter. In this case, Ariel deliberately added a ripe banana to two of the paper bags while not adding one to the remaining two bags. Therefore, the independent variable in this experiment was the presence or absence of a ripe banana in the paper bags.

The dependent variable, on the other hand, is the variable that is affected by the independent variable. It is the variable that is being measured or observed as it responds to changes in the independent variable. In this experiment, the dependent variable was the number of ripe avocados, which was affected by the presence or absence of the ripe banana in the paper bags. The purpose of the experiment was to determine if the presence of the ripe banana would cause the unripe avocados to ripen faster, which would result in more ripe avocados in the bag. Therefore, the number of ripe avocados is the dependent variable because it depends on the presence or absence of the ripe banana, which is the independent variable.

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By using simple mathematical arguments show the following: a) A solution Ψ(x,t) of the time-dependent Schrödinger equation has the same physical meaning as the solution e iΔ
Ψ(x,t), where Δ is real. In other words, the overall phase of the wavefunction carries no physical significance. b) If ψ(x) is a solution of the time-independent Schrödinger equation, then so is ψ(x) ∗
. Thus, the solutions of the time-independent Schrödinger equation may as well be taken to be real. c) The expectation value of momentum in a stationary state is zero. d) If V(x) is an even function of x, i.e., V(−x)=V(x), then ψ(x) can always be taken to be either even or odd.

Answers

a) The physical meaning of a solution Ψ(x,t) is the same as e^iΔΨ(x,t), where Δ is real.

b) Solutions of the time-independent Schrödinger equation can be taken as real functions.

c) The expectation value of momentum in a stationary state is zero.

d) If V(x) is an even function, ψ(x) can be either even or odd.

a) The physical observables and probabilities in quantum mechanics are determined by the magnitude of the wavefunction squared, |Ψ(x,t)|^2. The phase of the wavefunction, represented by e^iΔ, only affects the overall complex coefficient of the wavefunction and cancels out when calculating probabilities or observables. Therefore, different wavefunctions that differ only by an overall phase have the same physical meaning.

b) The time-independent Schrödinger equation represents stationary states, where the wavefunction does not change with time. Taking the complex conjugate of the wavefunction, ψ(x)∗, still satisfies the equation. As the complex conjugate of a real function is itself, this implies that the solutions can be taken to be real.

c) In a stationary state, the wavefunction does not evolve with time. The expectation value of momentum is given by the integral of the product of the complex conjugate of the wavefunction and the momentum operator. Since the wavefunction does not change with time, its derivative with respect to time is zero, resulting in an expectation value of momentum of zero.

d) The potential V(x) being an even function implies that it has symmetry around the origin. This symmetry allows for the wavefunction to also have the same symmetry. It can be represented as either an even function (symmetric about the origin) or an odd function (antisymmetric about the origin) to satisfy the Schrödinger equation.

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The ________ is the extent of an asset's risk. It is found by subtracting the pessimistic outcome from the optimistic outcome.

a. Return

b. Standard deviation

c. Probability distribution

d. Range

Answers

Answer:

Step-by-step explanation:

The range is the extent of an assets risk.

Bob owns a cafe and needs to find a new staff. Let Y denote the number of unsuccessful phone calls he makes before he finds a suitable person willing to take the job. Let θ denote the probability of securing a staff on each phone call. θ is the same for all phone calls and the outcome of each phone call is independent of any other phone call.
what is the likelihood function p(y|θ)?

Answers

The likelihood function p(y|θ) is = 0.0062.

The given information helps us understand that Y denotes the number of unsuccessful phone calls Bob makes before he finds a suitable person willing to take the job and θ denotes the probability of securing a staff on each phone call.

θ is the same for all phone calls and the outcome of each phone call is independent of any other phone call.

We need to find the likelihood function p(y|θ).

Likelihood function

p(y|θ) = P(Y = y| θ)

According to the given information, θ is the same for all phone calls and the outcome of each phone call is independent of any other phone call.

So, P(Y = y| θ) = (1 - θ)^y θ

Let us substitute the values in the above equation:

p(y|θ) = (1 - θ)^y θ

         = (1 - 0.85)^150 * 0.85

         = 0.0062

The likelihood function p(y|θ) is

p(y|θ) = (1 - θ)^y θ

= (1 - 0.85)^150 * 0.85

= 0.0062.

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Find sin(cos^−1 ( 5/13 )). What about tan(cos^−1( 5/13 )).

Answers

sin(cos⁻¹(5/13))=12/13 and tan(cos⁻¹(5/13))=12/5.

Find sin(cos⁻¹(5/13)) and tan(cos⁻¹(5/13)).What is sin⁻¹(5/13)

To find sin(cos⁻¹(5/13)), you must first determine the value of cos⁻¹(5/13).

Now, let's look at the right-angle triangle above.

Consider the side opposite the angle. It is 5, and the hypotenuse is 13. As a result, we will use sin (the opposite side divided by the hypotenuse) to calculate the angle.

Let's utilize the Pythagorean Theorem to compute the missing side (side adjacent to angle A):

b² = c² - a²

b²= 13² - 5²

b² = 169 - 25

b² = 144

b = 12

Using the sides of the triangle above, tan(cos⁻¹(5/13)) can be calculated as follows: 12/5 = 2.4

sin(cos⁻¹(5/13))=12/13 and tan(cos⁻¹(5/13))=12/5.

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A high-altitude passenger airplane is cruising at an altitude (z) of approximately 40,000ft. Determine the ratio of the pressure at the flight altitude (p 2

) and the pressure at standard sea-level (p 1

), meaning: p 2

p 1

, in the following different methods. For each case, you must start from the governing equation (hydrostatic equation: dp=−rhog ) ) and derive appropriate equation first, and then determine the ratio for each case. For simplification, assume that the gravity is being constant (standard sca-level value). (a) What is p 2

/p 1

, if air is assumed to be incompressible gas (density is constant, standard sea-level value: rho 2

=rho 1

=rho )? (b) What is p 2

/p 1

, if air is assumed to be isothermal gas (temperature is constant, standard sea-level value: T 2

=T 1

=T )? (c) What is p/p 1

, using the U.S. standard atmosphere model (temperature is a variable from sea-level to 36.000f altitude and then stays constant from 36,000ft to 66,000f )? The lapse rate (from sea-level to 36,000ft ) is given as: β=0.00357 " R/ft. Do not use U.S. standard atmospheric data from the table. Use the equation you derived (gradient region from sea-level to 36,000ft and then isothermal layer from 36,000ft to 66,000ft ), assuming that the gravity is constant.

Answers

(a) If air is assumed to be an incompressible gas, the density is constant, and the ratio of pressure at the flight altitude (p2) to the pressure at standard sea-level (p1) is equal to 1.

(b) If air is assumed to be an isothermal gas, with a constant temperature, the ratio of p2 to p1 can be calculated using the hydrostatic equation and the ideal gas law. The resulting ratio depends on the altitude and the temperature, which are assumed to be constant at standard sea-level values.

(c) Using the U.S. standard atmosphere model, the ratio of p to p1 can be determined by considering the gradient region (from sea-level to 36,000ft) and the isothermal layer (from 36,000ft to 66,000ft). The temperature variation in the gradient region is given by the lapse rate, and beyond 36,000ft, the temperature remains constant. The ratio of p to p1 can be calculated using the hydrostatic equation and the variation of temperature with altitude.

In the first case, where air is considered an incompressible gas, the density is assumed to be constant. Therefore, the pressure does not change with altitude, resulting in a pressure ratio of p2/p1 equal to 1.

In the second case, assuming air to be an isothermal gas, the temperature is assumed to be constant at standard sea-level values. By applying the hydrostatic equation and the ideal gas law, we can derive an equation relating the pressure ratio (p2/p1) to the altitude and temperature. The resulting ratio will depend on the specific values of altitude and temperature assumed.

In the third case, using the U.S. standard atmosphere model, we consider a temperature variation with altitude. From sea-level to 36,000ft, the temperature decreases according to the given lapse rate. Beyond 36,000ft, the temperature remains constant. By applying the hydrostatic equation and considering the temperature variation, we can derive an equation for the pressure ratio (p/p1). The resulting ratio will depend on the specific altitude considered and the lapse rate provided.

To accurately determine the pressure ratios in each case, it is important to utilize the appropriate equations derived from the hydrostatic equation and the ideal gas law, while considering the assumptions made for each scenario.

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Given any x∈R, show that there exists a unique m∈Z such that m−1⩽x

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For any real number x, there exists a unique integer m such that m-1 <= x < m.

To prove this, we can consider two cases:

Case 1: x is an integer

If x is an integer, then we can choose m = x. In this case, m-1 = x-1 <= x, satisfying the inequality.

Case 2: x is not an integer

If x is not an integer, we can choose m as the smallest integer greater than x. Since m is the smallest integer greater than x, we have m-1 <= x. Furthermore, since x is not an integer, m-1 < x+1, which implies m-1 < x. Therefore, m-1 <= x < m.

In both cases, we have shown the existence of an integer m such that m-1 <= x < m. Furthermore, the uniqueness follows from the fact that m is determined uniquely based on the value of x.

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Solve the exact differential equation (−3sin(x)−ysin(x)+2cos(x))dx+(cos(x))dy=0 where y(0)=2

Answers

We check if the given equation is exact by verifying if the partial derivatives of the coefficients with respect to y and x are equal:

∂/∂y(-3sin(x) - ysin(x) + 2cos(x)) = -sin(x)

∂/∂x(cos(x)) = -sin(x)

Since the partial derivatives are equal, the equation is exact. To solve it, we integrate the coefficient of dx with respect to x to find the potential function Φ(x, y):

Φ(x, y) = ∫(-3sin(x) - ysin(x) + 2cos(x))dx = -3cos(x) + ysin(x) + 2sin(x) + C(y)

We differentiate Φ(x, y) with respect to y and set it equal to the coefficient of dy to find C(y):

∂Φ/∂y = sin(x) + ∂C(y)/∂y = cos(x)

Comparing the two equations, we have ∂C(y)/∂y = cos(x). Integrating both sides with respect to y, we find:

C(y) = ycos(x) + g(x)

where g(x) is a function of x only. Since C(y) is independent of x, g(x) must be a constant.

Therefore, the general solution to the given exact differential equation is:

-3cos(x) + ysin(x) + 2sin(x) + C = 0

The particular solution that satisfies y(0) = 2, we substitute x = 0 and y = 2 into the equation and solve for C:

-3cos(0) + 2sin(0) + 2sin(0) + C = 0

-3 + C = 0

C = 3

So, the particular solution is:

-3cos(x) + ysin(x) + 2sin(x) + 3 = 0

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Note that 5% of the population suffers from a particular disease. There is a diagnostic test to identify this disease. If a person who has the disease undergoes the test, 99% the test becomes positive. Similarly, if a person who does not have this disease undergoes this test, 5% the time the test becomes positive. If a randomly selected person undergoes this test, what is the probability that he gets a negative result? Enter your answer to the nearest THREE decimal places. Note that 5% of the population suffers from a particular disease. There is a diagnostic test to identify this disease. If a person who has the disease undergoes the test, 99% the test becomes positive. Similarly, if a person who does not have this disease undergoes this test, 5% the time the test becomes positive. If a randomly selected person undergoes this test and the test becomes positive, what is the probability that he actually does not have the disease? Enter your answer to the nearest FOUR decimal places.

Answers

The probability that a person does not have the disease given a positive test result is approximately 0.4754, rounded to four decimal places.

The probability of getting a negative result when a randomly selected person undergoes the test can be calculated by considering the complementary probability of getting a positive result.

Since 5% of the population suffers from the disease, the probability of an individual having the disease is 0.05. The probability of a positive test result given that the person has the disease is 0.99. Thus, the probability of a negative result given that the person has the disease is 1 - 0.99 = 0.01.

Similarly, the probability of a negative result given that the person does not have the disease can be calculated. Since 95% of the population does not have the disease, the probability of an individual not having the disease is 0.95. The probability of a positive test result given that the person does not have the disease is 0.05. Thus, the probability of a negative result given that the person does not have the disease is 1 - 0.05 = 0.95.

Therefore, the probability of getting a negative result when a randomly selected person undergoes the test is 0.01 (or 1%) rounded to three decimal places.

Now, let's calculate the probability that a person does not have the disease given that the test result is positive. This can be found using Bayes' theorem.

Let A represent the event that a person has the disease, and B represent the event that the test result is positive. We want to calculate P(A' | B), which is the probability of not having the disease given a positive test result.

According to Bayes' theorem:

P(A' | B) = (P(B | A') * P(A')) / P(B)

P(B | A') is the probability of a positive test result given that the person does not have the disease, which is 0.05.

P(A') is the probability of not having the disease, which is 0.95.

P(B) is the probability of a positive test result, which can be calculated by considering the two scenarios:

P(B | A) * P(A) is the probability of a positive test result given that the person has the disease, which is 0.99, multiplied by the probability of having the disease, which is 0.05.

P(B | A') * P(A') is the probability of a positive test result given that the person does not have the disease, which is 0.05, multiplied by the probability of not having the disease, which is 0.95.

So, P(B) = (P(B | A) * P(A)) + (P(B | A') * P(A')) = (0.99 * 0.05) + (0.05 * 0.95) = 0.0995.

Substituting these values into the formula, we get:

P(A' | B) = (0.05 * 0.95) / 0.0995 ≈ 0.4754

Therefore, the probability that a person does not have the disease given a positive test result is approximately 0.4754, rounded to four decimal places.

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Using the formula for simple interest and the given values, find I. p=$800 r=7% t=7 i=?

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The value of I, the interest, is $392.

The simple interest formula is given by I = P * R * T, where I represents the interest, P is the principal amount, R is the interest rate, and T is the time in years. Given the values P = $800, R = 7% (expressed as a decimal, 0.07), and T = 7, we can calculate the interest I.

Using the formula, we have I = 800 * 0.07 * 7 = $392.

Therefore, the value of I, the interest, is $392.

In this case, the principal amount is $800, the interest rate is 7%, and the time period is 7 years. By substituting these values into the simple interest formula, I = P * R * T, we can calculate the interest earned. Multiplying the principal amount ($800) by the interest rate expressed as a decimal (0.07), and then multiplying the result by the time period (7 years), we find that the interest earned is $392. This means that over a period of 7 years, with an $800 principal and a 7% interest rate, the interest accrued amounts to $392. Simple interest is a basic calculation used to determine the interest earned or paid on a loan or investment over a specified time period, assuming no compounding occurs.

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Find the value for the discriminant for the following quadratic equation and predict the nature of its solutions. x^(2)-4x+13=0

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The discriminant of the given quadratic equation is -36.

The quadratic equation x^(2)-4x+13=0 is in the standard form ax^2+bx+c=0, where a=1, b=-4, and c=13. The discriminant of a quadratic equation is given by the expression b^2-4ac. Substituting the values of a, b, and c in the expression, we get:

(-4)^2-4(1)(13) = 16-52 = -36

Therefore, the discriminant of the given quadratic equation is -36.

The discriminant of a quadratic equation determines the nature of its solutions. If the discriminant is positive, then the quadratic equation has two distinct real solutions.

If the discriminant is zero, then the quadratic equation has one real solution. If the discriminant is negative, then the quadratic equation has two complex conjugate solutions.

In this case, since the discriminant is negative (-36), the quadratic equation x^(2)-4x+13=0 has two complex conjugate solutions.

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Internet service: An Internet service provider sampled 535 customers, and finds that 64 of them experienced an interruption in high-speed service during the previous month. Part 1 of 3 (a) Find a point estimate for the population proportion of all customers who experienced an interruption. Round the answer to at least three deimal places. The point estimate for the population proportion of all customers who experienced an interruption is Part: 1/3 Part 2 of 3 (b) Construct an 80% confidence interval for the proportion of all customers who experienced an interruption. Round the answers to at least three decimal places. An 80% confidence interval for the proportion of all customers who experienced an interruption is

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The correct answer is Point estimate: 0.120,80% Confidence interval: (0.093, 0.147)

Part 1:

The point estimate for the population proportion of all customers who experienced an interruption is obtained by dividing the number of customers who experienced an interruption (64) by the total sample size (535):

Point estimate = 64/535 ≈ 0.1196

Part 2:

To construct an 80% confidence interval for the proportion of all customers who experienced an interruption, we can use the formula:

Confidence interval = Point estimate ± Margin of error

The margin of error is calculated using the formula:

Margin of error = Critical value * Standard error

For an 80% confidence interval, the critical value corresponds to a z-score of 1.28 (approximately). The standard error is computed as:

Standard error = sqrt((Point estimate * (1 - Point estimate)) / Sample size)

Substituting the values into the formulas, we can calculate the confidence interval.

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According to the empirical rule, what percentage of these funds is expected to be within ±2 standard deviations of the mean? 95% b. According to the Chebyshev rule, what percentage of these funds are expected to be within ±4 standard deviations of the mean? % (Round to two decimal places as needed.) c. According to the Chebyshev rule, at least 88.89% of these funds are expected to have one-year total returns between what two amounts? Between and (Round to two decimal places as needed.)

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At least 88.89% of these funds are expected to have one-year total returns between -2% and 26%.According to the empirical rule, approximately 95% of the funds are expected to be within ±2 standard deviations of the mean.

According to the Chebyshev rule, at least 93.75% of these funds are expected to be within ±4 standard deviations of the mean. The Chebyshev rule applies to all data sets and states that at least 1 - (1/k^2) of the data values lie within k standard deviations of the mean.  k = 4, therefore, 1 - (1/4^2) = 93.75%.

According to the Chebyshev rule, at least 88.89% of these funds are expected to have one-year total returns between  -3σ and +3σ. Here's how to compute:   µ - 3σ = 10 - (3 * 4) = -2%  µ + 3σ = 10 + (3 * 4) = 26%.

Thus, at least 88.89% of these funds are expected to have one-year total returns between -2% and 26%.

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Which of the following models are linear or can be linearized? (1) Y i
​ =exp(βX i
​ )+ε i
​ (2) Y i
​ =βexp(X i
​ )+ε i
​ (3) Y i
​ =exp(βX i
​ )ε i
​ (4) Y i
​ =ln(βX i
​ )+ε i

Answers

The linear or linearizable models among the given options are (4) Y i​ = ln(βX i​) + ε i​.

In the context of linear models, linearity refers to the relationship between the dependent variable (Y) and the parameters (β) and independent variables (X). Linear models follow the form Y = βX + ε, where β represents the coefficients and X represents the independent variables. The linearity assumption implies that the relationship between Y and X is a straight line.

In the given options, only model (4) Y i​ = ln(βX i​) + ε i​ can be considered linear or linearizable. Although it involves the natural logarithm function, the model can be linearized by taking the natural logarithm of both sides, resulting in ln(Y i​) = ln(βX i​) + ε i​. By defining a new variable, such as ln(Y i​), the relationship can be expressed as a linear equation with ln(β) as the coefficient.

Models (1), (2), and (3) involve exponential functions and cannot be directly transformed into linear form. Nonlinear models have curves or nonlinear relationships between the dependent and independent variables, which require specific nonlinear regression techniques for estimation and analysis.

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Find the angle between the lines x/2 = y/2 =z andx/5=y/4=-(z/3)

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The angle between the given lines is approximately 52.26°.

The angle between the given lines, we can make use of the formula that relates the angles between two lines to the dot product of their respective direction vectors.

It is given as;`cosθ=|(a1,b1,c1).(a2,b2,c2)|/√a1^2+b1^2+c1^2 ×√a2^2+b2^2+c2^2`

Now, let's calculate the direction vectors of the given lines. Given the equation of the first line `x/2=y/2=z` we can write its direction vector as;`a1=b1=c1=2

Therefore, the direction vector of the first line is v1 = [2,2,2]

Similarly, we can write the direction vector of the second line as; a2=5, b2=4, c2=-3

Therefore, the direction vector of the second line is v2 = [5,4,-3]

Now, using the formula of cosine of the angle between two vectors, we get;

cosθ=|(2,2,2).(5,4,-3)|/√2^2+2^2+2^2 ×√5^2+4^2+(-3)^2``=|

(2×5)+(2×4)+(2×(-3))|/√12 ×√50``=|10+8-6|/2√3 ×5``=12/10√3``=2√3/5

Therefore, the required angle between the given lines is;`θ=cos−1(2√3/5)

Thus, the angle between the given lines is approximately 52.26°.

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The stress tensor at a point P of an elastic medium is given by: σ

(P)= ⎝


7
0
−2

0
5
0

−2
0
4




Determine: a) the stress vector at point P for a plane whose unit normal is: n
^
= 3
2

i
^
− 3
2

j
^

+ 3
1

k
^
, b) the corresponding normal stress.

Answers

a) The stress vector at point P for the given plane is (7/2)i^ - (7/2)j^ + (3/2)k^.

b) The corresponding normal stress is (7/2) MPa.

a) The stress vector at a point on a plane can be determined by multiplying the stress tensor with the unit normal vector of the plane. In this case, the stress tensor is given as:

σ(P) =  7   0  -2

       0   5   0

      -2   0   4

And the unit normal vector of the plane is:

n^ = (3/2)i^ - (3/2)j^ + (3/1)k^

Multiplying the stress tensor with the unit normal vector, we get:

Stress vector = σ(P) * n^

             = (7/2)i^ - (7/2)j^ + (3/2)k^

b) The normal stress is the component of the stress vector that is perpendicular to the plane. In this case, the component of the stress vector along the direction of the unit normal vector is the normal stress. Therefore, the corresponding normal stress is the coefficient of i^ in the stress vector, which is (7/2) MPa.

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The age of a randomly selected alcohol-impaired driver in a fatal car crash is a random variable with probability density function given by f(x)=4x2105​ for x in [15,35]. Find the probability that the age of a randomly selected driver is less than 22 ? Round your answer to 4 decimals.

Answers

The probability that the age of a randomly selected driver is less than 22 is approximately 0.2269 (rounded to 4 decimal places).

To find the probability that the age of a randomly selected driver is less than 22, we need to calculate the cumulative distribution function (CDF) for the given probability density function (PDF) and evaluate it at 22.The cumulative distribution function (CDF) is defined as the integral of the PDF from negative infinity to the given value. In this case, we integrate the PDF function from 15 to 22.The PDF is given as:

f(x) = 4[tex]x^{2}[/tex]/ 105 for x in [15, 35]

To find the CDF, we integrate the PDF:

F(x) = ∫(15 to x) 4[tex]t^{2}[/tex]/ 105 dt

Evaluating the integral:

F(x) = (4/105) * [([tex]t^{3}[/tex])/3] from 15 to x

F(x) = (4/105) * [([tex]x^{3}[/tex])/3 - ([tex]15^{3}[/tex])/3]

Now, we evaluate the CDF at x = 22:

F(22) = (4/105) * [([tex]22^{3}[/tex])/3 - ([tex]15^{3}[/tex])/3]

Calculating the value: F(22) ≈ 0.2269

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