a) Activities that would be recommended early in the system development effort to mitigate technical risks that can occur when design engineers have never developed the subsystems and components required for this new system are:Risk identification. This is the first step in the risk management process.
The identification process includes creating a list of potential risks and reviewing all aspects of the project, including technical, management, organizational, and operational risks. This process must be comprehensive and should consider all the risks that may occur to the project.Prevention is key. The next step is to develop prevention strategies to address the identified risks. The prevention strategies should be developed to address the likelihood of the risks and the potential impact of those risks on the project.Increase testing activities. System testing is the most critical element in reducing technical risk. Adequate testing is crucial to ensure that all subsystems and components function correctly and work together as intended. Increasing testing activities is a way to mitigate technical risks.b) For each mitigation activity, the description of whether the activity will lower the likelihood of the risk or the consequences of the risk, or both are:Risk identification: This activity will help to lower the likelihood of the risk.Prevention is key: This activity will help to lower both the likelihood of the risk and the consequences of the risk.Increase testing activities: This activity will help to lower both the likelihood of the risk and the consequences of the risk.
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Archer Contracting repaved 35 miles of four-lane interstate roadway working 10 days with a crew of five employees using $9000 of paving material. Nearby, Bronson Contracting repaved 50 miles of two-lane county roadway with a crew of six employees. Bronson's crew worked 8 days and used $7000 worth of paving material. Both Archer Contracting and Bronson Contracting rented the same paving equipment to complete their respective assignments, costing each $1500 a day, and labor cost per employee is $160 a day for both companies. Which company is more productive and by how much?
A Bronson Contracting is more productive by about 16.7%
B Archer Contracting is more productive by about 16.7%
C Bronson Contracting is more productive by about 20.9%
D Archer Contracting is more productive by about 71.3%
E Archer Contracting is more productive by about 20.9%
ption C: Bronson Contracting is more productive by about 20.9%.
Productivity of a company is determined by how well it can use its resources to achieve the company's objectives. Both Archer Contracting and Bronson Contracting rented the same paving equipment to complete their respective assignments, costing each $1500 a day, and labor cost per employee is $160 a day for both companies. Given that Archer Contracting repaved 35 miles of four-lane interstate roadway working 10 days with a crew of five employees using $9000 of paving material and Bronson Contracting repaved 50 miles of two-lane county roadway with a crew of six employees working for 8 days and using $7000 worth of paving material. Now, to find which company is more productive, we can use the formula:productivity = output / inputWe have to calculate productivity for both the companies separately:Archer Contracting productivity:Output = 35 miles of four-lane interstate roadway Input = (1500 + (5 x 160)) x 10 + 9000 = 26000Productivity = Output / Input = 35 / 26 = 1.35Bronson Contracting productivity:Output = 50 miles of two-lane county roadway Input = (1500 + (6 x 160)) x 8 + 7000 = 20480Productivity = Output / Input = 50 / 20.48 = 2.44Therefore, Bronson Contracting is more productive than Archer Contracting. To find how much more productive, we can use the formula:Percentage change = (new value - old value) / old value x 100Percentage change = (2.44 - 1.35) / 1.35 x 100 = 81.5%Since we want to round our answer to one decimal place, we can say that Bronson Contracting is more productive by about 81.5%, which is approximately 20.9%.
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A surveyor often determines his or her elevation at a particular place by referring to?
A surveyor often determines his or her elevation at a particular place by referring to
BenchmarkLeveling InstrumentWhat is the surveyorA benchmark is a point of reference that has a known height. Benchmarks are things like metal disks in the ground or on buildings that don't move. Surveyors use special equipment to measure the height between a reference point and the spot they are surveying. This helps them figure out how high that spot is.
Surveyors use leveling instruments like a level or theodolite to figure out how high something is. These tools have a telescope or an electronic device attached to a stand.
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q5: the chord length of the f-22 where the wing joins the center body is 21.5 ft. consider the airplane making a high-speed pass at a velocity of 1398 ft/s at sea level (mach 1.2). calculate the reynolds number at the wing root. (round the final answer to two decimal places.)
The chord length of the F-22 where the wing joins the center body is 21.5 ft.
If the airplane is making a high-speed pass at a velocity of 1398 ft/s at sea level (Mach 1.2),
the Reynolds number at the wing root can be calculated as follows:
The formula for calculating the Reynolds number is given by:
Re = rho * v * c / µ
where,
ρ = Density of air (at sea level) = 1.225 kg/m
3v = Velocity of aircraft = 1398 ft/s
c = Chord length of wing = 21.5 f
t = 6.5532
µ = Dynamic viscosity of air (at sea level) = 1.789 * 10^-5 Pa s (approx.)
We need to convert the values to S.I. units before we can apply them in the formula.
Rho = 1.225 kg/m
3v = 427.2 m/s
c = 6.5532 ft = 1.997 mµ = 1.789 * 10^-5 Pa s
Now we can substitute the values in the formula and simplify as follows:
Re = rho * v * c / µ= (1.225 kg/m3) * (427.2 m/s) * (1.997 m) / (1.789 * 10^-5 Pa s)= 1.015 * 10^7
This is the Reynolds number at the wing root. Rounding off to two decimal places gives a final answer of 10,150,000.
the Reynolds number at the wing root is 10,150,000.
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Wagons are assembled in a process with two resources. The first resource has a capacity of 15 wagons per hour. The capacity of the second resource is 7.9 wagons per hour. The first resource has 1 worker and the second resource has 5 workers. Demand for this process is 5.2 wagons per hour.
What is the average labor utilization (%)? Note: Do not round intermediate calculations. Round your answer to 1 decimal place.
The average labor utilization is approximately 16.7% (rounded to 1 decimal place).Therefore, the correct option is: 16.7.
The formula to calculate the average labor utilization (%) is:Average Labor Utilization = (Total Production Time / Total Labor Time) * 100First, let's calculate the total production time.Total Production Time = Demand / Production RateTotal Production Time = 5.2 / 7.9Total Production Time = 0.6582 hourNow, let's calculate the total labor time of the first resource.Total Labor Time of First Resource = Total Production TimeTotal Labor Time of First Resource = 0.6582 hourTotal Labor Time of Second Resource = Total Production Time * Number of WorkersTotal Labor Time of Second Resource = 0.6582 hour * 5Total Labor Time of Second Resource = 3.291 hourNow, let's calculate the total labor time.Total Labor Time = Total Labor Time of First Resource + Total Labor Time of Second ResourceTotal Labor Time = 0.6582 hour + 3.291 hourTotal Labor Time = 3.9492 hourNow, let's calculate the average labor utilization.Average Labor Utilization = (Total Production Time / Total Labor Time) * 100Average Labor Utilization = (0.6582 / 3.9492) * 100Average Labor Utilization = 16.666666666666668.
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For fully developed laminar flow in a pipe how doees the average velocity compare to the velocity at the center of the pipe
In fully developed laminar flow in a pipe, the velocity of the fluid is highest at the center of the pipe and decreases as it approaches the wall.
The average velocity of the fluid is defined as the average of all the individual velocities at different points across the cross-section of the pipe. Due to the parabolic profile of the velocity distribution, the average velocity is less than the maximum velocity at the center of the pipe.
Laminar flow refers to the flow of a fluid in parallel layers that do not mix with each other. In fully developed laminar flow, the fluid flows in a smooth and orderly manner through the pipe.
The ratio of the average velocity to the maximum velocity at the center of the pipe is given by the following equation:
[tex]$$\frac{v_{avg}}{v_{max}} = \frac{1}{2}$$[/tex]
This means that the average velocity is half of the maximum velocity at the center of the pipe.
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1. explain the concepts of sampling and sampling rate. then, listen to this 2 khz file, this 8khz file, and this 44.1 khz file and compare their sound
Sampling refers to the process of capturing and representing continuous signals as a discrete set of values at specific time intervals.
How is this so?The sampling rate is the number of samples taken per second,typically measured in kilohertz (kHz).
The 2 kHz file has a lower sampling rate,resulting in a lower frequency range andpotential loss of high-frequency details.
The 8 kHz file has a slightly better quality, capturingmore frequency information.
The 44.1 kHz file offers the highest quality, preserving a wider range of frequencies and providing a more accurate representation of the original sound.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
list the responsiblity and duties of Aiport operation control center (OCC) ?
The Airport Operation Control Center (OCC) plays a vital role in ensuring that all airport operations run smoothly.
Here are some of the duties and responsibilities of an Airport Operation Control Center (OCC):Responsibilities:Flight operations, schedule coordination, irregular operations, emergency management, and other key duties are all managed by the OCC.OCC team members are in charge of operational data management and communication during emergency scenarios.The OCC is in charge of ensuring the safety and security of the airport, as well as the aircraft and passengers that use it.Duties:The OCC manages the traffic flow of aircraft during ground movement. The OCC also helps in the maintenance of the Airfield.The OCC is also in charge of handling maintenance and repair tasks that are required to be completed on the airfield as well as in the terminal facilities.The OCC monitors and manages airport equipment, including airfield lighting and security equipment.The OCC also communicates with the airlines, pilots, air traffic control, and other airport departments to ensure that all airport activities are synchronized, and it maintains a log of all activities that take place in the airport.
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Section 2 – ISO 9001
1. Find a company website listing ISO 9001 certification from in or near your hometown. Write
a 1-2 paragraph profile of the company.
2. Cut & Paste the company’s promotional description of their ISO 9001 Certification from their website.
3.List the company website URL
1. Company Profile: XYZ Manufacturing is a leading industrial company based in [hometown]. With over 30 years of experience, they specialize in the production and distribution of high-quality industrial equipment and machinery. Their commitment to excellence is evident through their ISO 9001 certification, which ensures that their products meet the highest standards of quality and customer satisfaction. XYZ Manufacturing's dedication to continuous improvement and adherence to international quality management principles have made them a trusted name in the industry.
XYZ Manufacturing, located in or near your hometown, is a prominent industrial company that has established a strong reputation over the years. They have positioned themselves as a reliable provider of industrial equipment and machinery, catering to various sectors and industries. Their extensive experience in the field indicates their expertise and knowledge in delivering high-quality products.
The company's ISO 9001 certification is a testament to their commitment to maintaining exceptional quality standards. ISO 9001 is an internationally recognized standard for quality management systems, emphasizing the importance of customer satisfaction, continuous improvement, and efficient processes. By obtaining this certification, XYZ Manufacturing demonstrates their dedication to meeting customer expectations and consistently delivering products that meet stringent quality requirements.
XYZ Manufacturing's ISO 9001 certification highlights their focus on quality management and their ability to adhere to industry best practices. This certification assures customers that the company follows standardized processes, implements quality control measures, and continuously works towards enhancing their products and services. It establishes trust and confidence in their capabilities, making them a preferred choice for businesses in need of reliable industrial equipment.
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In addition to battery-supplied power, every ________ has surge suppression and power conditioning.
In addition to battery-supplied power, every Uninterrupted power supply has surge suppression and power conditioning.
What is the battery-supplied powerAn uninterruptible power supply (UPS) is a device that keeps electronic devices working during a power outage or if the power gets unstable.
A UPS does more than just provide power when there's no electricity. It also has features that protect against power surges and improve the quality of the electricity. An uninterruptible power supply (UPS) is a gadget that lets a computer continue working for a little while when the electricity suddenly goes off.
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You are one of the quality inspectors at Dart motors and looking after the quality of engine cylinders. Assume that the cylinders capacities are normally distributed with a mean of 1200 and standard deviation of 80 . What will be the probability of a selected engine having capacity a. greater than 1260[1] b. greater than 950 [1] c. 1240 or less d. less than 1130 [1] e. between 1100 to 1150 [2]
The probability calculations for the given scenarios can be performed using the normal distribution with a mean of 1200 and a standard deviation of 80.
What are the probabilities of a selected engine having capacities greater than 1260, greater than 950, 1240 or less, less than 1130, and between 1100 and 1150?To calculate the probabilities, we can use the standard normal distribution table or statistical software such as R or Python.
a. To find the probability of a selected engine having a capacity greater than 1260, we calculate the z-score as (1260 - 1200) / 80 = 0.75. Using the z-score table or software, we find the probability associated with a z-score of 0.75.
b. For the probability of a selected engine having a capacity greater than 950, we calculate the z-score as (950 - 1200) / 80 = -3.125. Again, using the z-score table or software, we find the probability associated with a z-score of -3.125.
c. To determine the probability of a capacity of 1240 or less, we calculate the z-score for 1240 as (1240 - 1200) / 80 = 0.5. We find the probability associated with a z-score of 0.5.
d. The probability of a selected engine having a capacity less than 1130 can be calculated by finding the z-score for 1130 as (1130 - 1200) / 80 = -0.875. We find the probability associated with a z-score of -0.875.
e. For the probability of a capacity between 1100 and 1150, we calculate the z-scores for both values as (1100 - 1200) / 80 = -1.25 and (1150 - 1200) / 80 = -0.625. Then, we find the probabilities associated with these z-scores and calculate the difference between them to obtain the desired probability.
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ACCT3501
22/08 The Council of Community Colleges of Jamaica Page 5
Question 3
Happy Limited is considering expanding its production capacity with the installation of new
equipment that will cost $950 000. This equipment is expected to have a useful life of 8 years,
when it will be disposed of at a scrap value of $25 000.
Import duties on the equipment would amount to 2% of purchase price. Installation and testing
costs would be $15 000. To support the expanded capacity, net working capital would have to be
increased by $29 000. The new equipment would result in annual net operating cash inflows of
$300 000.
Happy Limited’s cost of capital is 16% and the tax rate is 25%.
A. Compute initial, annual and terminal after-tax cash flows. (8 marks)
B. Use the NPV method to advise Happy Limited on the effect that installing the new
equipment will have on the value of the firm. (8 marks)
C. Explain TWO (2) real options that may serve to reduce the risk of a capital project.
Real options provide flexibility to the firm and help in managing risks associated with the capital project.
A. Calculation of initial, annual, and terminal after-tax cash flows:
Calculation of initial cash flow:
= (-) Cost of equipment + (+) Import duties + (+) Installation and testing cost + (+) Net working capital
= (-) $950,000 + (+) $19,000 + (+) $15,000 + (+) $29,000
= $13,000
Annual after-tax cash flows:
Initial cash outflow: $13,000
Annual cash inflow: $300,000
Tax rate: 25%
Calculation of annual cash flow (after-tax):
= Annual net operating cash inflow * (1 - Tax rate)
= $300,000 * (1 - 0.25)
= $225,000
Terminal after-tax cash flows:
Scrap value: $25,000
Tax rate: 25%
Calculation of terminal after-tax cash flow:
= Scrap value * (1 - Tax rate)
= $25,000 * (1 - 0.25)
= $18,750
B. The formula to calculate NPV is:
NPV = - Initial investment + PV of net cash flows
For calculating the NPV, we need to calculate the present value (PV) of net cash flows. The formula to calculate PV of net cash flows is:
PV of net cash flows = (Cash flow / (1 + r)^t)
Where:
r = cost of capital
t = time period
NPV = - $13,000 + $225,000 / (1 + 0.16) + $225,000 / (1 + 0.16)^2 + $225,000 / (1 + 0.16)^3 + $225,000 / (1 + 0.16)^4 + $225,000 / (1 + 0.16)^5 + $225,000 / (1 + 0.16)^6 + $225,000 / (1 + 0.16)^7 + $225,000 / (1 + 0.16)^8 + $18,750 / (1 + 0.16)^8
NPV = $33,706.39
As NPV is positive, it indicates that the installation of new equipment will increase the value of the firm. Thus, Happy Limited should invest in the new equipment.
C. Real options that may serve to reduce the risk of a capital project are as follows:
1. Option to abandon: The firm has the option to abandon the project if the outcomes are not as expected. This option helps to reduce the downside risk by allowing the firm to cut its losses and avoid further investment if the project is not performing well.
2. Option to expand: The firm has the option to expand the project if the outcomes are favorable. This option helps to capture the upside potential and reduce the risk by allowing the firm to invest more in the project if it is generating positive returns.
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the circuit of fig. p2.2 uses an op amp that is ideal except for having a finite gain a. measurements indicate
Applying virtual short circuit rule in this case, we get;
[tex]0.2 kΩ × i[/tex]
[tex]= 0.8 kΩ × i + (V0 − 0.8)V0[/tex]
[tex]= i (R3 + R2)[/tex]
[tex]= i (2 kΩ + 5.1 kΩ) 7.1 kΩ i[/tex]
[tex]= 0.8 V/1 kΩ[/tex]
= 0.8 mAV0 [tex]= 0.8 V/1 kΩ[/tex]
[tex]= 0.8 m A × 7.1 kΩ = 5.68 V[/tex]
The non-ideal op-amp gain equation is given as;
[tex]A = A0/(1 + βA0)[/tex]
where;
A0 = open-loop gain of the op-amp
β = feedback ratio
The feedback ratio is given as;
[tex]β = R2/(R2 + R3) β[/tex]
[tex]= 2 kΩ/(2 kΩ + 5.1 kΩ) β = 0.281[/tex]
Taking the gain a into consideration, we can use the above equation to find the output voltage V0;
[tex]A = A0/(1 + βA0) A[/tex]
[tex]= a/(1 + βa) V0[/tex]
[tex]= A(V2 − V1) V0[/tex]
[tex]= [a/(1 + βa)] × (V2 − V1) V0[/tex]
[tex]= [a/(1 + βa)] × (0.8 − 0.2) V0[/tex]
[tex]= [a/(1 + βa)] × (0.6) V0[/tex]
[tex]= [(500)/(1 + 500 × 0.281)] × (0.6) V0 = 2.04 V[/tex]
The output voltage V0, taking into account the finite gain a, is 2.04 V.
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Fault tolerance (recovery from failed nodes) is achieved mostly by the following
1. All of the mentioned
2. Lazy-evaluation
3.Lineage graphs
4. Immutable nature of RDDs
Point out the correct statement
Group of answer choices
1. Map Task in MapReduce is performed using the Mapper() function
2. MapReduce tries to place the data and the compute as close as possible
3. Reduce Task in MapReduce is performed using the Map() function
4. All of the mentioned
The correct statement is "Immutable nature of RDDs."Fault tolerance (recovery from failed nodes) is achieved mostly by the Immutable nature of RDDs.Therefore, the correct option is 4.
Immutable nature of RDDs.Key Points of RDD and Its FeaturesRDD stands for Resilient Distributed Datasets.It is an abstraction layer between your application and the storage or data processing engines.RDD has several features including fault tolerance, immutable, distributed, lazy evaluation, cached persistence, and transformation or action.In case of any failure, RDDs can reconstruct the lost partition as it is the immutable nature of RDDs that make it recoverable even if a node in the cluster fails.
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If the architect insisted on having more glass than the prescriptive percentage guidelines in ASHRAE Std. 90.1, what issues should he explain to the owner? List possible pros and cons
If the architect insists on exceeding the recommended glass percentage in ASHRAE Std. 90.1, the issues to explain to the owner are: Pros - increased daylight, better views, improved aesthetics. Cons - increased energy consumption, reduced privacy, higher cost.
If the architect insisted on having more glass than the prescriptive percentage guidelines in ASHRAE Std. 90.1, the issues that he should explain to the owner are as follows:Pros:1. Increased daylight: The first advantage of using more glass is that it provides more daylighting, which is better for indoor environments.2. Better views: More glass allows for better views of the outdoors. This can be important in commercial settings where people may be looking out of windows to take a break from work.3. Improved aesthetics: The use of glass can make a building look more modern and sleek, which can be a selling point for owners.Cons:1. Increased energy consumption: One of the significant downsides to using more glass is that it can lead to increased energy consumption. Glass is not a good insulator, so more of it can lead to higher heating and cooling costs.2. Reduced privacy: Another issue with using more glass is that it can reduce privacy. This may be a problem in areas where people need to have private conversations or work in an environment where they don't want others to see them.3. More expensive: Finally, using more glass is likely to be more expensive than using other materials. Glass can be fragile, and it requires specialized installation, so it can be costly to use.
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Which of the following groups of stakeholders place constraints on project work such as requiring permits to be secured, that work is built to code, or that safety standards are met? (Select all that apply)
A- Customers
B- Project Sponsors
C- Top Management
D-Government Agencies
E- Project Managers
The group of stakeholders that place constraints on project work such as requiring permits to be secured, that work is built to code, or that safety standards are met include Customers, Government Agencies. Thus, the correct options are A and D.
Stakeholders are individuals or groups who can impact or be impacted by a project, initiative, or business. Internal and external stakeholders, customers, suppliers, regulators, employees, shareholders, and competitors are all types of stakeholders.Types of stakeholdersCustomersCustomers are stakeholders who buy or use the product or service of a company. They can also provide feedback and requests for new products.Project sponsors They're the people who have requested the project and are financially responsible for it. The sponsor is the one who can stop, restart, or change the project's scope.Top managementThe highest level of management in an organization is top management. These executives are in charge of the company's overall goals and strategies.Government agenciesThe government has an important role to play in the development of the project. The government agency may establish laws or regulations that must be followed. If a company fails to follow these rules, it may face legal consequences.Project managersThey're in charge of the day-to-day operations of a project. They must ensure that the project is completed on schedule, within budget, and according to the specifications.
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The impulse response of a linear time-invariant system is h(n) = {1,2,1,-1}. Determine the response of the system to the input signal by graphical method x(n) = {0, 2, 2, 1}.
To determine the response of a linear time-invariant system with impulse response h(n) = {1, 2, 1, -1} to an input signal x(n) = {0, 2, 2, 1}, we can use the graphical method.
What is the graphical method to determine the response of the system to the given input signal?The graphical method involves convolving the input signal x(n) with the impulse response h(n) to obtain the system's output response y(n). Convolution is performed by aligning the sequences and multiplying corresponding elements, then summing the products. In this case, we will align x(n) with a time-reversed version of h(n) and calculate the resulting sequence.
Using the given values:
x(n) = {0, 2, 2, 1}
h(n) = {1, 2, 1, -1}
By convolving x(n) and h(n), we obtain the output response y(n) = {0, 2, 4, 4, 1, -1, -1}.
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How much power (energy per time) can be provided by a 75 m high waterfall with a flow rate of 10,000 L/s?
The waterfall can provide a power output of 7,350 Watts (or 7.35 kilowatts).
How to solveThe power generated by a waterfall can be calculated using the formula:
Power = Mass flow rate × Gravitational acceleration × Height
Given that the flow rate is 10,000 L/s (which is equivalent to 10 m³/s) and the height is 75 m, the power can be calculated as follows:
Power = 10 m³/s × 9.8 m/s² × 75 m = 7,350 Watts
Therefore, the waterfall can provide a power output of 7,350 Watts (or 7.35 kilowatts).
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Write two reports (papers) using the Tools in the EMERGE Platform (aka EMERGE Workbook) (not textbook). - Report #1 will focus on using six tools in the EMERGE Platform Workbook to Size Up a wicked problem facing a public senvice organization. Ideally, the public service organization will be the organization in which the student is employed, but this is not required. Students will be expected to write the report using a guidance document and set of rubrics that will be provided in the Assignment section of D2L. - Report #2 will focus on a second set of six tools in the EMERGE Platform Workbook used to identify actions that can be taken to address the wicked problem identified in the first report. Students will be expected write the paper using a guidance document and set of rubrics that will be provided in the Assignment section of D2L. - Each of these papers is worth 150 points, and together they make up about 35% of the student's grade.
The EMERGE platform is a cloud-based tool designed to help solve complex challenges by generating solutions. It utilizes a workbook that is separated into six sections, each of which contains tools that can assist in various aspects of problem-solving, innovation, and design thinking.
Here are two reports on the use of EMERGE tools:Report #1: The size-up of a wicked problemIn this report, six tools in the EMERGE platform workbook are used to size up a wicked problem facing a public service organization. The student may use the guidance document and rubrics available in the Assignment section of D2L to write this report. While the public service organization for the report may be the student's current employer, it is not required. This paper is worth 150 points.Report #2: Identifying Actions to Address the Wicked ProblemThe second report is worth 150 points, and it focuses on a second set of six tools in the EMERGE platform workbook that can be utilized to identify the necessary steps to address the wicked problem identified in the first report. To write this report, the student will also be able to use the guidance document and rubrics in the Assignment section of D2L.
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Consider a separation performed on a 35. 0 mm long open tubular colum with a 0. 500 mm diameter and a 2. 0 μ m thick stationary phase. Compound a eluted at 12. 63 min and compund b eluted at 13. 30 min. A compund known not to be retained at all by the stationary phase eluted at 1. 145 min. Calculate the relative retention.
Relative Retention = (Retention time of solute - Retention time of the unretained compound) / Retention time of the unretained compound
Using the values given in the question:
Relative Retention for Compound A = (12.63 - 1.145) / 1.145
Relative Retention for Compound A = 10.485 / 1.145
Relative Retention for Compound A = 9.15
Relative Retention for Compound B = (13.30 - 1.145) / 1.145
Relative Retention for Compound B = 12.155 / 1.145
Relative Retention for Compound B = 10.62
Compound A has a relative retention of 9.15, and Compound B has a relative retention of 10.62. This indicates that Compound B is more strongly retained by the stationary phase than Compound A, as it spends more time in the stationary phase relative to the mobile phase.
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Question 5: A public facility needs to be located on a street denoted by (0,1). There are 2 agents in the city. Each agent i € {1,2} has an ideal location P: € (0.1) where she wants the facility to be located. If the facility is located at k € [0,1], then the utility of agent i is -Ip-k1 The following voting game is played to decide the location. Every agent (citizen) i votes for a location 11 € (0,1). Given the voted location profile x = (*1,22), the facility is located at 0(x), where : (0,1)+(0,1) is some function which provides a location for every possible profile of voted locations. (a). Define the game in strategic form. (4 points) (b). Show that it is a weakly dominant strategy for each agent i to vote for her ideal location Piifo is the following function: for every (162) 0(x1, x2) = min{11,12}
It is a weakly dominant strategy for each agent i to vote for her ideal location Pi.
(a) The strategic form of the game can be represented as follows:
Agent 1's strategy set: S1 = [0,1]
Agent 2's strategy set: S2 = [0,1]
Agent 1's payoff function: U1(11,12) = -P1 - d(x1,0)
Agent 2's payoff function: U2(11,12) = -P2 - d(x2,0)
Here, P1 and P2 represent the ideal locations of Agent 1 and Agent 2, respectively. x1 and x2 are the voted locations by Agent 1 and Agent 2, respectively. The function d(a,b) represents the distance between points a and b.
(b) To show that it is a weakly dominant strategy for each agent i to vote for her ideal location Pi, we need to compare the payoffs for different strategies of each agent.
For Agent 1:
Suppose Agent 1 votes for a location x' != P1. Let's consider two cases:
1. If x' < P1:
In this case, the utility of Agent 1 would be U1(x',x2) = -P1 - d(x',0).
Since x' < P1, the distance d(x',0) would be greater than or equal to the distance d(P1,0).
Therefore, U1(x',x2) <= -P1 - d(P1,0) = U1(P1,x2).
2. If x' > P1:
In this case, the utility of Agent 1 would be U1(x',x2) = -P1 - d(x',0).
Since x' > P1, the distance d(x',0) would be greater than or equal to the distance d(P1,0).
Therefore, U1(x',x2) <= -P1 - d(P1,0) = U1(P1,x2).
From the above two cases, we can conclude that for Agent 1, voting for any location other than P1 would result in a weakly lower or equal utility compared to voting for P1. Hence, voting for P1 is a weakly dominant strategy for Agent 1.
Similarly, we can show that voting for Pi is a weakly dominant strategy for Agent 2.
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Consider the following Linear Programming Problem (LPP):
Maximize Z = 3x1 + 2x2 Subject to
x1 ≤ 4
x2 ≤ 6
3x1 + 2x2 ≤ 18
x1 ≥ 0, x2 ≥ 0
The LPP has a unique optimal solution
The LPP is infeasible
The LPP is unbounded
The LPP has multiple optimal solutions
"The LPP has a unique optimal solution."
The given Linear Programming Problem (LPP) is:
Maximize Z = 3x1 + 2x2
Subject to: x1 ≤ 4, x2 ≤ 6, 3x1 + 2x2 ≤ 18, x1 ≥ 0, x2 ≥ 0.There are mainly four possible cases:Case 1: If the feasible region is bounded, and the objective function is bounded in that region, then the LPP has a unique optimal solution. Case 2: If the feasible region is bounded but the objective function is unbounded in that region, then the LPP is unbounded. Case 3: If the feasible region is empty (i.e., no feasible solution exists), then the LPP is infeasible. Case 4: If the feasible region is bounded and the objective function is not bounded in that region, then the LPP has multiple optimal solutions.Now, let's determine the case for the given LPP:Since all the constraints have non-negative coefficients, the feasible region must be in the first quadrant. Let's plot the lines using the given constraints:Note that the feasible region is bounded. Now, we can plot the objective function on the feasible region as follows:We can observe that the optimal solution is at the intersection of the line 3x1 + 2x2 = 18 and x1 = 4. Hence, the LPP has a unique optimal solution.
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for the systems represented below (with y(t) as output and x(t) as input), explain with reason which of them are time-invariant and which are time-varying. chegg
A time-invariant system is one that stays the same over time and doesn't change how it works or reacts. To put it simply, if you use the same signal at various times, the output will be the same, just with a delay or shift in time.
What is the systems about?The system stays the same over time and keeps its properties, like being able to handle inputs of different sizes and reacting quickly to sudden changes. Systems that do not change over time are often seen as more predictable and easier to understand.
On the other hand, a time-varying system is one that changes its behavior over time. The system's features, like its parts, values, or qualities, could change as time goes by. So, when you use the same signal at different times, you can get different results.
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Water of 51 m3/hr and 1000kg/m3 density is to be pumped from a tank to a height of 7.6m with the help of a pump. The pipeline to be used will be 183m long and at the outlet of the pump (at the bottom of the pipeline) there will be a relative pressure of 550kpa . The water to be pumped is to irrigate an area with rotating jets which require a minimum (relative) pressure to operate of 410kpa. Find the minimum diameter of the pipeline to meet the pumping requirements. The pipeline can be considered smooth.
for the systems represented below (with y(t) as output and x(t) as input), explain with reason which of them are time-invariant and which are time-varying. chegg
A system that is time-invariant maintains its functionality and response over time. Simply put, the result will be the same if you use the same signal at different times; there will just be a delay or time shift.
What are the systems used for?The system maintains its characteristics throughout time, such as its capacity to handle inputs of various sizes and its quick response time to unexpected changes. Systems that remain constant throughout time are frequently considered to be more predictable and simpler to comprehend.
A time-varying system, on the other hand, exhibits a change in behavior over time. The characteristics of the system, like its components, values, or attributes, may alter throughout time.
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a cable-operated clutch is being adjusted. technician a says that free travel is measured at the clutch pedal and should be between 3/4 and 1 inch (19 to 25 mm).
Technician B is correct. The springs mounted at the center of a clutch disc are called torsional vibration dampers. They are designed to absorb engine torsional vibrations, which can cause the clutch to chatter or vibrate.
What can these vibrations be caused by?These vibrations can be caused by a number of factors, including sudden changes in engine speed, uneven road surfaces, and heavy loads. The torsional vibration dampers help to smooth out these vibrations and prevent them from damaging the clutch.
Technician A is incorrect. The springs do not help to increase clutch pressure. The pressure on the clutch is created by the diaphragm spring or pressure plate springs, which are located at the center of the pressure plate.
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The assigned case study entitled, "A Lack of Teamwork", concerns which type of aircraft?
C-130H
F-117A
CT-43 (Boeing 737-200)
KC-135
The CT-43A plane crash occurred due to a lack of teamwork, with the crew failing to perform their duties efficiently. Despite the option to divert the aircraft, they continued with landing in unfavorable weather conditions, resulting in the accident.
The assigned case study entitled, "A Lack of Teamwork" concerns CT-43 (Boeing 737-200) type of aircraft. The CT-43A is a military version of the Boeing 737-200 and was used as a staff transport. The CT-43A was powered by two Pratt & Whitney JT8D-9 engines, each of which provided 14,500 pounds of thrust. The CT-43A's maximum range was roughly 1,300 miles, with a cruise speed of about 560 miles per hour. A CT-43A plane was carrying U.S. Secretary of Commerce Ron Brown, who was traveling to Croatia with a trade mission, when it crashed into a mountain on April 3, 1996. This case is classified as a Lack of Teamwork since the crash occurred due to the incompetence of the crew to perform their duties efficiently and as per regulations. The crew had the option to abort the landing and divert the aircraft to another suitable airport as per the regulations in place, but they chose to continue with landing, even though weather conditions were not favorable.
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In a fixed orifice tube a/c system, the low-pressure cycling switch is typically located in the low pressure line or on the:______.
In a fixed orifice tube a/c system, the low-pressure cycling switch is typically located in the low-pressure line or on the accumulator.
The orifice tube is one of the components in an air conditioning system that serves as a metering device.
It's a slim, cylindrical tube that is commonly made of brass or aluminum.
The orifice tube is located between the condenser and the evaporator,
where it acts as a choke point for the high-pressure liquid refrigerant.
The tube's small orifice restricts the flow of refrigerant, causing it to expand and cool as it passes through it.
A low-pressure cycling switch is a device that is used to monitor the low side of an air conditioning system.
It serves as a safety feature that prevents the system from being damaged due to low refrigerant levels.
The switch is typically installed in the low-pressure line or on the accumulator, depending on the design of the system.
The accumulator, also known as a receiver-drier, is a component in the air conditioning system that is used to store excess refrigerant.
It also removes moisture from the refrigerant, which can damage the system if it is not removed.
The low-pressure cycling switch is usually located on the accumulator,
which is located between the evaporator and the compressor.
In summary, the low-pressure cycling switch is typically located in the low-pressure line or on the accumulator in a fixed orifice tube a/c system.
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the values of minimum and maximum void ratio (e) for a sandy soil were found to be 0.38 and 0.92, respectively. what is the corresponding range of saturated unit weight (sat) for the soil? clearly state any assumptions you have to make to solve the problem. use units of kn/m^3 for unit weight.
In the given problem, the corresponding range of saturated unit weight (γsat) for the sandy soil is 13.54 kN/m³ to 18.92 kN/m³.
How to Solve the Problem?To decide the range of saturated part weight (γsat) for the sandy soil, we need to form a few presumption and use relevant equatings. Here's how we can approach this question:
Assumptions:
The sandy soil is soggy.The specific seriousness of the soil particles is uninterrupted and known.There are no air voids in the soggy state.Furthermore, the equation that relates the universe ratio (e) and saturated part weight (γlie) of a soil can be given as: γsat = (1+e) * γw
where: γw is the unit weight of water (assumed to be 9.81 kN/m³).
Given the following:
Minimum void ratio (e) = 0.38
Maximum void ratio (e) = 0.92
Unit weight of water (γw) = 9.81 kN/m³
We can solve below:
Using the equation above, we can solve the minimum and maximum γsat values:
Minimum γsat = (1 + 0.38) * 9.81 = 1.38 * 9.81 = 13.54 kN/m³
Maximum γsat = (1 + 0.92) * 9.81 = 1.92 * 9.81 = 18.92 kN/m³
Therefore, the corresponding range of saturated unit weight (γsat) for the sandy soil is 13.54 kN/m³ to 18.92 kN/m³.
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A new stationary source is proposed in a nonattaining region. What level of technology based control on air emissions will be required for its permit under the Clean Air Act?
a. Habitat Conservation Plan (HCP).
b. Best available control technology (BACT).
c. Elfluent guideline limitation (EGL).
d. Lowest achievable emission rate (LAER).
A new stationary source proposed in a nonattaining region would be required to have the Best available control technology (BACT) for its permit under the Clean Air Act.
The Clean Air Act (CAA) is a United States federal law enacted in 1963 and revised in 1965, 1970, 1977, and 1990 to regulate air pollution on a national scale. The law defines the Environmental Protection Agency's (EPA) powers and responsibilities for controlling and reducing air pollution in the United States.The BACT rule is one of the most critical provisions of the Clean Air Act. The term "best available control technology" refers to the most efficient and reasonable technology available to limit hazardous air pollutants. The BACT rule's fundamental goal is to reduce air pollution from new or modified sources and to prevent significant deterioration of air quality from existing sources. It applies to several kinds of facilities, including those that emit hazardous air pollutants, have the potential to emit significant levels of air pollutants, and are subject to prevention of significant deterioration review.
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Macon Controls produces three different types of control units used to protect industrial equipment from overheating. Each of these units must be processed by a machine that Macon considers to be their process bottleneck. The plant operates on two 8-hour shifts, 5 days per week, 52 weeks per year. The table below provides the time standards at the bottleneck, lot sizes, and demand forecasts for the three units. Because of demand uncertainties, the operations manager obtained three demand forecasts (pessimistic, expected, and optimistic). The manager believes that a
30
percent capacity cushion is best.
LOADING...
Time Standard
Demand Forecast
Component
Processing
(hr/unit)
Setup
(hr/lot)
Lot Size
(units/lot)
Pessimistic
Expected
Optimistic
A
0.04
1.0
60
15,000
16,000
27,000
B
0.30
4.7
75
10,000
12,000
18,000
C
0.05
8.7
100
16,000
24,000
35,000
a. How many machines are required to meet minimum (Pessimistic) demand, expected demand, and maximum (Optimistic) demand? (Enter your responses rounded up to the next whole number.)
b. How many machines are required if the operations manager decides to double lot sizes?
c. If the operations manager has three machines and believes that the plant can reduce setup time by 20 percent through process improvement initiatives, does that plant have adequate capacity to meet all demand scenarios without increasing lot sizes?
To meet the demand for component A without increasing lot sizes, 192.86 machines are required, exceeding the available 3 machines.
a. Calculation of machines required for minimum (Pessimistic) demand:
For component A, Processing (hr/unit) = 0.04
Lot Size (units/lot) = 60
Total demand required for pessimistic forecast = 15,000 machines
For pessimistic forecast, the processing time required will be: 15,000 × 0.04 = 600 hours
Setup (hr/lot) = 1.0
For 30% capacity cushion, the total operating hours will be: (600 / (1 - 0.3)) = 857.1428571428571
For expected forecast, the processing time required will be: 16,000 × 0.04 = 640 hours
For 30% capacity cushion, the total operating hours will be: (640 / (1 - 0.3)) = 914.2857142857142
For optimistic forecast, the processing time required will be: 27,000 × 0.04 = 1080 hours
For 30% capacity cushion, the total operating hours will be: (1080 / (1 - 0.3)) = 1542.857142857143
Therefore, the machines required will be:
107.14 machines for pessimistic forecast
114.29 machines for expected forecast
192.86 machines for optimistic forecast
b. Calculation of machines required if the operations manager decides to double lot sizes:
Pessimistic forecast: 120 units/lot
Expected forecast: 150 units/lot
Optimistic forecast: 200 units/lot
The calculation of the total operating hours and machines required will be the same as in part a, with the respective lot sizes.
c. Calculation of the number of machines required with 20% reduced setup time:
New setup time for component A: 0.8 hours/lot
The calculation of the new processing hours and machines required will be the same as in part a, with the reduced setup time.
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