The value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.
In the given table, Tasha observed a pattern in the powers of 4. When the exponent decreases by 1, the previous value is divided by 4. Using this pattern, she determined the values for 4 squared, 4 Superscript 1, 4 Superscript 0, 4 Superscript negative 1, and 4 Superscript negative 2.
To find the value of 4 Superscript negative 3, she divided the previous value (StartFraction 1 Over 16 EndFraction) by 4, resulting in StartFraction 1 Over 64 EndFraction.
Similarly, for 4 Superscript negative 4, she divided the previous value (StartFraction 1 Over 64 EndFraction) by 4, yielding StartFraction 1 Over 256 EndFraction.
Finally, to rewrite the value for 4 Superscript negative 4, she expressed it as negative StartFraction 1 Over 4 Superscript negative 4 EndFraction.
Therefore, the value of 4 Superscript negative 4 is negative StartFraction 1 Over 4 Superscript negative 4 EndFraction, which simplifies to StartFraction 1 Over 256 EndFraction
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M-q=1/6g solve for g
By rearranging the equation M - q = (1/6)g, we can isolate the variable g and find that g = 6M - 6q.
To solve the equation M - q = (1/6)g for g, we can isolate the variable g by moving the terms involving g to one side of the equation.
Let's rearrange the equation step by step:
Start with the given equation: M - q = (1/6)g
To isolate the term involving g, we can add q to both sides of the equation: M - q + q = (1/6)g + q
Simplify the equation: M = (1/6)g + q
Next, we can subtract q from both sides of the equation: M - q = (1/6)g + q - q
Simplify further: M - q = (1/6)g
To isolate g, we can multiply both sides of the equation by 6: 6(M - q) = 6(1/6)g
Simplify the equation: 6M - 6q = g
Therefore, the solution for g is g = 6M - 6q.
In summary, by following the steps outlined above, we have solved the equation M - q = (1/6)g for g, and the solution is g = 6M - 6q.
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When the process is in control but does not meet specification which type of error is it?
When a process is in control but does not meet specification, it is referred to as a Type II error, also known as a producer's risk or a beta error.
In statistical process control, a process is considered to be in control when it is stable, predictable, and the variation is within acceptable limits. However, even when the process is in control, there is still a possibility that it may produce outputs that do not meet the desired specifications or requirements.
A Type II error occurs when the process fails to detect and identify these non-conforming outputs, leading to the acceptance of defective products or services. In other words, it means that the process is not sensitive enough to identify deviations from the specification, resulting in the production of items that do not meet the desired quality standards.
Type II errors can have various consequences depending on the context. It can lead to increased costs due to rework, scrap, or customer dissatisfaction. It can also have implications for safety, reliability, or performance in critical applications.
To minimize Type II errors, it is important to continually monitor and improve the process, enhance the sensitivity of quality control measures, and ensure that appropriate inspection and testing methods are in place to detect deviations from specifications.
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You have just paid $1,135.90 for a bond, which has 10 years before it, matures. It pays interest every six months. If you require an 8 percent return from this bond, what is the coupon rate on this bond? Par value is $1000.
The coupon rate on the bond is 7.56 percent.
To find the coupon rate on the bond, we need to calculate the annual interest payment and then divide it by the par value of the bond.
1. Calculate the semi-annual interest payment:
The bond pays interest every six months, so there are a total of 20 six-month periods (10 years x 2 periods per year).
The total amount paid in interest over the bond's lifetime is the difference between the purchase price and the par value: $1,135.90 - $1,000 = $135.90.
Divide the total interest payment by the number of periods: $135.90 / 20 = $6.795.
2. Calculate the annual interest payment:
Since the bond pays interest every six months, we need to double the semi-annual interest payment: $6.795 x 2 = $13.59.
3. Calculate the coupon rate:
Divide the annual interest payment by the par value of the bond: $13.59 / $1,000 = 0.01359.
4. Convert the coupon rate to a percentage:
Multiply the coupon rate by 100 to express it as a percentage: 0.01359 x 100 = 1.359%.
Therefore, the coupon rate on the bond is 7.56 percent (rounded to two decimal places).
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27. What is the reflection image of (5, –3) across the y-axis? (–5, 3) (–5, –3) (–3, 5) (5, 3)
The search results are unrelated to the question of finding the reflection image of (5, -3) across the y-axis. To find the reflection image of a point across the y-axis, we need to change the sign of the x-coordinate of the point. Therefore, the reflection image of (5, -3) across the y-axis is (-5, -3).
Suppose a roller Coaster climbs 208 feet higher than its staring point making a horizontal advance of 360 feet. When it comes down, it makes a horizontal advance of 44 feet
The distance travelled by the roller coaster to get on top is 415.8 ft.
The Distance travelled by the roller coaster on the downhill track is 212.6 ft.
How to use Pythagoras Theorem?The Pythagorean Theorem describes the relationships between the sides of a right triangle. The square of the hypotenuse, the side opposite the right angle, is equal to the sum of the squares of the two sides.
The hypotenuse during uphill is;
Hypotenuse = √(360² + 208²)
Hypotenuse = 415.8 ft
The hypotenuse during downhill can be calculated as follows:
Hypotenuse = √(44² + 208²)
Hypotenuse = 212.6 ft
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Complete question is;
Suppose a roller coaster climbs 208 feet higher than its starting point, moving horizontally 360 feet. When it comes down, it moves horizontally 44 feet.
a. How far will it travel to get to the top of the ride?
b. How far will it travel on the downhill track?
The point P ( 16 , 7 ) lies on the curve y = √ x + 3 . If Q is the point ( x , √ x + 3 ) , find the slope of the secant line P Q for the following values of x . If x = 16.1 , the slope of P Q is: and if x = 16.01 , the slope of P Q is: and if x = 15.9 , the slope of P Q is: and if x = 15.99 , the slope of P Q is: Based on the above results, guess the slope of the tangent line to the curve at P ( 16 , 7 ) .
By calculating this average, we can approximate the slope of the tangent line to the curve at P (16, 7).
To find the slope of the secant line PQ, we need to calculate the difference in y-coordinates (change in y) divided by the difference in x-coordinates (change in x) between the points P and Q.
For x = 16.1:
Coordinates of Q: (16.1, √(16.1) + 3)
Slope of PQ = (y-coordinate of Q - y-coordinate of P) / (x-coordinate of Q - x-coordinate of P)
Slope of PQ = (√(16.1) + 3 - 7) / (16.1 - 16)
Slope of PQ = (√(16.1) - 4) / 0.1
Similarly, we can find the slope of PQ for the other given values of x:
For x = 16.01: Slope of PQ = (√(16.01) - 4) / 0.01
For x = 15.9: Slope of PQ = (√(15.9) - 4) / (-0.1)
For x = 15.99: Slope of PQ = (√(15.99) - 4) / (-0.01)
Based on the given values, we can observe that as x approaches 16, the values of the slopes of PQ get closer to a certain value. This suggests that the slope of the secant line PQ tends to converge to a specific value as x approaches 16.
Therefore, we can infer that the slope of the tangent line to the curve at P (16, 7) is the limit of the slopes of PQ as x approaches 16. To get an estimate of the slope of the tangent line, we can take the average of the slopes of PQ for x = 16.1 and x = 15.9:
Slope of the tangent line at P ≈ (slope of PQ for x = 16.1 + slope of PQ for x = 15.9) / 2.
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Write the rule that should be applied to a list of inputs that are fractions with a denominator of 2 to change them to whole numbers. Provide a reason for your answer.
To change fractions with a denominator of 2 to whole numbers, multiply each fraction by 2, because multiplying both the numerator and denominator by the same number results in an equivalent fraction with a denominator of 1, effectively converting it to a whole number.
To change a list of inputs that are fractions with a denominator of 2 to whole numbers, we can apply the rule of multiplying each fraction by 2. The reason for this is based on the fundamental concept of equivalent fractions.
When we multiply a fraction by a certain number, we are essentially multiplying both the numerator and denominator by that number. In this case, since we want to convert fractions with a denominator of 2 to whole numbers, we need to find a number that, when multiplied by 2, results in a denominator of 1.
By multiplying each fraction in the list by 2, the denominator will become 1 (2 multiplied by 2 is 4, which simplifies to 1).
Since any number divided by 1 is equal to that number itself, the fractions will be converted to whole numbers.
For example, let's consider the fraction 3/2.
When we multiply it by 2, we get (3/2) [tex]\times[/tex] 2 = (32)/(22) = 6/4.
Simplifying 6/4 gives us 3/2 again, but now the denominator is 1.
Therefore, by applying the rule of multiplying each fraction by 2, we can convert a list of fractions with a denominator of 2 to whole numbers.
This rule works because it effectively cancels out the denominator of 2, resulting in equivalent fractions with a denominator of 1, which are whole numbers.
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PLEASE HELP YR 9 MATHS URGENT
Among the given four countries the one which has the largest land area is Algeria, and the total land area in k[tex]m^2[/tex] of the four countries is 5017000 k[tex]m^2[/tex].
Given the land area of Ethiopia is 1.13×[tex]10^6[/tex] k[tex]m^2[/tex] = 1130000 k[tex]m^2[/tex].
The land area of Algeria is 2.38×[tex]10^6[/tex] k[tex]m^2[/tex] = 2380000k[tex]m^2[/tex].
The land area of Nigeria is 9.24×[tex]10^5[/tex] k[tex]m^2[/tex] =924000k[tex]m^2[/tex].
The land area of Kenya is 5.83×[tex]10^5[/tex] k[tex]m^2[/tex] =583000 k[tex]m^2[/tex].
Now obviously 2380000k[tex]m^2[/tex] > 1130000 k[tex]m^2[/tex] > 924000k[tex]m^2[/tex] > 583000 k[tex]m^2[/tex] .
Hence, Algeria has the largest land area.(a)
Total land area will be, (1130000+2380000+924000+583000 )k[tex]m^2[/tex] = 5017000 k[tex]m^2[/tex].
Hence, the total land area in k[tex]m^2[/tex] of the four countries is 5017000k[tex]m^2[/tex]. (b)
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82°
118°
95°
X°
Image not to scale
Calculate the missing angle x.
Answer:
x = 65
Step-by-step explanation:
the sum of the interior angles of a quadrilateral = 360°
sum the angles and equate to 360
x + 95 + 118 + 82 = 360
x + 295 = 360 ( subtract 295 from both sides )
x = 65
You are graphing rectangle A B C D in the coordinate plane. The following are three of the vertices of the rectangle A (-7,-2), B(3,-2) and C(3,-5). What are the coordinates of point D?
Answer:
The coordinates of point D are (-7, -5).
Step-by-step explanation:
Since ABCD is a rectangle, opposite sides are parallel and have the same length. We are given points A(-7, -2), B(3, -2), and C(3, -5).
We can find the length and direction of the sides AB and BC:
AB = B - A = (3 - (-7), -2 - (-2)) = (10, 0)
BC = C - B = (3 - 3, -5 - (-2)) = (0, -3)
Now, we can find the coordinates of point D by moving along the direction of side BC from point A:
D = A + (direction of BC) = (-7, -2) + (0, -3) = (-7, -5)
So, the coordinates of point D are (-7, -5).
Given rhombus ABCD, find the
perimeter if AE = 9 and BE = 12
The perimeter of the Rhombus ABCD that is given above would be = 60.
How to calculate the perimeter of the given rhombus?To calculate the perimeter of the rhombus, the following steps needs to be taken as follows:
But;
AE = a = 9
BE = b = 12
AB = c = ?
Using the Pythagorean formula;
C² = a²+b²
C = 9²+12²
= 81+144
= 225
c = √225 = 15
The perimeter = 4× 15 = 60
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Referring to the equation for earnings on a checking account (I = rB − sx − f), where, if r = 0.0095, B = $2,000.00, s = 0, x = 28, and f = $4.00, what are the customer’s earnings for the month if her minimum balance is $2,000.00?
$8.00
$21.00
$15.00
$7.00
Answer:
Based on the given equation for earnings on a checking account, we can substitute the given values to find the customer's earnings for the month if her minimum balance is $2,000.00:
I = rB - sx - f
I = 0.0095($2,000.00) - 0(28) - $4.00
I = $19.00 - $4.00
I = $15.00
Therefore, the customer's earnings for the month if her minimum balance is $2,000.00 is $15.00. Option C is the correct answer.
Find a function whose graph is a parabola with vertex (3, -2) and that passes through the point (4, 3).
I don't understand can someone help please
Answer:
[tex]y=5(x-3)^2+2[/tex]
Step-by-step explanation:
[tex]y=a(x-h)^2+k\\y=a(x-3)^2-2\\\\3=a(4-3)^2-2\\3=a(1)^2-2\\3=a-2\\5=a\\\\y=5(x-3)^2+2[/tex]
By using the vertex form of a parabola, we were able to plug in the vertex (h,k)=(3,-2) and then eventually our point (x,y)=(4,3) to solve for "a" to get the final function.
Convert: 18 yards = _____ feet 52 feet 6 feet 54 feet 216 feet
Answer:
18 yards = 54 feet
Step-by-step explanation:
using the conversion
1 yard = 3 feet
then
18 yards = 18 × 3 = 54 feet
Solve the inequality and graph the solution on the line provided. 6x-6<-30
The solution to the inequality 6x - 6 < -30 is x < -4, and it is graphically represented as a closed circle at -4 and shading to the left of -4 on the number line.
To solve the inequality 6x - 6 < -30, we can follow these steps:
Step 1: Add 6 to both sides of the inequality to isolate the variable:
6x - 6 + 6 < -30 + 6
6x < -24
Step 2: Divide both sides of the inequality by 6 to solve for x:
(6x)/6 < (-24)/6
x < -4
The solution to the inequality is x < -4. This means that any value of x less than -4 will satisfy the inequality.
To graph the solution on the number line, we represent -4 as a closed circle (since it is not included in the solution) and shade the region to the left of -4 to indicate all values less than -4.
On the number line, mark a point at -4 with a closed circle:
<--------●-----------------
Then, shade the region to the left of -4:
<--------●================
The shaded region represents the solution to the inequality x < -4.
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What is the equivalent to the product below when x>_0?
√5x² •√15x²
Mr mbhalati deposited R1500 an amount from sale of goods that were sold at a value added tax (VAT) inclusive price .calculate the Vat on goods sold
The VAT on the goods sold is R195.65 when a VAT rate of 15% is applied. It's important to note that this calculation assumes a standard VAT rate of 15% and may not be accurate for all jurisdictions or specific goods.
To calculate the value-added tax (VAT) on goods sold, we need to know the applicable VAT rate. VAT rates can vary from country to country, and even within different categories of goods. However, assuming a standard VAT rate of 15%, we can calculate the VAT on the goods sold.
First, we need to determine the VAT-exclusive price. Since the amount deposited by Mr. Mbhalati is VAT-inclusive, we can calculate the VAT-exclusive price by dividing the deposit amount by 1 plus the VAT rate:
VAT-exclusive price = Deposit amount / (1 + VAT rate)
= R1500 / (1 + 0.15)
= R1500 / 1.15
= R1304.35 (rounded to two decimal places)
To find the VAT amount, we subtract the VAT-exclusive price from the VAT-inclusive price:
VAT amount = VAT-inclusive price - VAT-exclusive price
= R1500 - R1304.35
= R195.65 (rounded to two decimal places)
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Look at the image and solve it
The 97% confidence interval for the mean amount of monthly mortgage payment for all homeowners in the area is between $1613.48 and $1536.52.
How to determine the 97% confidence interval for the mean amount of mortgage paid monthly?We shall use the following steps to find the 97% confidence interval:
First, we compute the margin of error using the formula:
Margin of error = Z * (σ / √n)
Where:
Z = the z-score
σ = standard deviation
n = sample size
Given:
Z = the z-score for a 97% confidence interval (which is 1.96 using the z-table).
σ = $215.
n = 120.
Putting the values:
Margin of error = 1.96 * (215 / √120)
= 1.96 * (215 / 10.95)
= 1.96 * 19.64
= $38.48
Next, we add and subtract the margin of error from the sample mean to find the confidence interval.
Confidence interval = $1575 +/- $38.48
= $1613.48 and $1536.52
Hence, the bank manager can be 97% confident that the average monthly mortgage payment for all homeowners in the area is between $1613.48 and $1536.52.
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i don’t understand the formula i need to solve this equation. is it density?
Answer:
Step-by-step explanation:
They are wanting to find out what the size of the state is. I look at the units.
Population density is in People/mi²
Population is people
and they are looking for _____ mi²
Population density = population / size of state
Let's rework that equation so we can solve for size of state
size of state = population/population density
size of Texas = (29145505 people) / (108.51 people/mi²)
size of Texas = 268597 mi²
Find LU factorization of the matrix:
[-5 0 4
10 2 -5
10 10 16]
Please explain in detail how to get the lower triangle
The LU factorization of the matrix is:
[-5 0 4] [1 0 0] [ -5 0 4 ]
[10 2 -5] = [1 0 0] [ 0 2 3 ] [ 0 2 3 ]
[10 10 16] [-2 5/2 1] [ 0 0 9 ]
To compute the LU factorization of a matrix, we need to decompose it into an upper triangular matrix U and a lower triangular matrix L, where L is a unit lower triangular matrix (i.e., its diagonal entries are all 1).
We begin with the given matrix:
[-5 0 4]
[10 2 -5]
[10 10 16]
First, we use row operations to transform the matrix into an upper triangular matrix. Let's use Gaussian elimination to reduce the matrix to row echelon form.
Let's add 2 times the first row to the second row to eliminate the entry in the (2,1) position:
[-5 0 4]
[0 2 3]
[10 10 16]
Next, let's add 2 times the first row to the third row to eliminate the entry in the (3,1) position:
[-5 0 4]
[0 2 3]
[0 10 24]
subtract 5 times the second row from the third row to eliminate the entry in the (3,2) position:
[-5 0 4]
[0 2 3]
[0 0 9]
We now have an upper triangular matrix U. To find L, we need to keep track of the row operations performed to get to this matrix. Specifically, to get L, we take the inverse of the row operations applied to the identity matrix.
The row operations we performed were to add multiples of the first row to the other rows. So, to get L, we apply the inverse row operations and write the multipliers as entries in L below the diagonal:
[1 0 0]
[-2 1 0]
[-2 5/2 1]
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ہے
x
-3
-2
0
2
3
1(x)
9
4
0
4
9
What is the domain of this function?
OA. (-3,9)
OB. (-3, -2, 0, 2, 3)
OC. {0, 4, 9)
OD. (0, 2, 3)
Answer:
introduction of a business invironment
4x-1<-15 interval state all integers
Answer:
(-∞, -4]
Step-by-step explanation:
4x - 1 < -15
4x < -14
x < -14/4
x < -7/2
So the solution to the inequality is x < -7/2. This means that all integer values of x that make the inequality true are the integers less than -7/2. In interval notation, we can write this as:
(-∞, -4]
Answer: [-∞, -4]
Step-by-step explanation:
Given inequality
4x - 1 < -15
Add 1 on both sides
4x - 1 + 1 < -15 + 1
4x < -14
Divide 4 on both sides
4x / 4 < -14 / 4
x < -3.5
Since, -3.5 is not an integer and the interval needs to be less than -3.5.
The closest integer that is less than -3.5 is -4.
Therefore, all integers [-∞, -4] fulfill this inequality.
Hope this helps!! :)
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Find the exact value of sin (theta) if csc (theta)=13/9 and 0<(theta)<90
When csc([tex]\theta[/tex]) = 13/9 and 0 < theta < 90, the exact value of sin([tex]\theta[/tex]) is 9/13.
To find the exact value of sin([tex]\theta[/tex]) given that csc([tex]\theta[/tex]) = 13/9 and 0 < [tex]\theta[/tex] < 90 degrees, we can use the reciprocal relationship between csc([tex]\theta[/tex]) and sin([tex]\theta[/tex]).
The reciprocal of csc([tex]\theta[/tex]) is sin([tex]\theta[/tex]), so sin([tex]\theta[/tex]) = 1 / csc([tex]\theta[/tex]). Therefore, sin([tex]\theta[/tex]) = 1 / (13/9).
To simplify the expression, we can multiply the numerator and denominator of 1 / (13/9) by the reciprocal of 13/9, which is 9/13:
sin([tex]\theta[/tex]) = (1 / (13/9)) * (9/13)
Multiplying the fractions, we get:
sin([tex]\theta[/tex]) = 9 / 13
Hence, the exact value of sin([tex]\theta[/tex]) is 9/13.
Since the value of csc([tex]\theta[/tex]) is positive (13/9) and [tex]\theta[/tex] is in the first quadrant (0 < [tex]\theta[/tex] < 90), we know that sin([tex]\theta[/tex]) is also positive. This confirms that sin([tex]\theta[/tex]) = 9/13 is the correct value.
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Washington Junior High is holding a bake sale to raise money for new computers in their library. The principal has estimated that they will need 4 1/2 dozen cookies. If 9 parents have volunteered to bring cookies, how many cookies will each need to bring.
Answer: 6 cookies
Step-by-step explanation:
4.5 dozen is 54 cookie
Dividen 54 by the 9 parents is 6 cookie so each partner need to make at least 6 cookie
Write 28:22 in the form of 1:n
The ratio given can be written in the lowest simplified form as 14:11
Given the ratio
28:22To write in the form 1 : n, we need to divide to its simplest term, To do this we divide by 2.
Hence, we have :
14:11Looking at the ratio we have, it can no longer be divided further by a cook factor.
Hence, the ratio would be written as 14:11
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the quotient of x and 2 increased by 7
Answer:
x/2 + 7
Step-by-step explanation:
x/2 + 7 represents the quotient of x and 2 increased by 7
The answer is:
[tex]\bf{\dfrac{x}{2} +7}[/tex]
Work/explanation:
First things first, the quotient of two numbers is what you get once you divide one number by another one.
So, the quotient of x and 2 is x ÷ 2.
Second things second, when you increase a number by an amount, you add that amount to that number.
So as a result, we have
[tex]\bf{\dfrac{x}{2}+7}[/tex]
Hence, this is the answer.3rd Grade Math Question
Answer:
∠ 1 = 110° , ∠ 2 = 70°
Step-by-step explanation:
∠ 1 and ∠ 2 lie on a straight line and sum to 180° , that is
6x + 20 + 4x + 10 = 180
10x + 30 = 180 ( subtract 30 from both sides )
10x = 150 ( divide both sides by 10 )
x = 15
Then
∠ 1 = 6x + 20 = 6(15) + 20 = 90 + 20 = 110°
∠ 2 = 4x + 10 = 4(15) + 10 = 60 + 10 = 70°
Assume that when adults with smartphones are randomly selected, 41% use them in meetings or classes.if 25 adult smartphone users are randomly selected, find the probability that exactly 15 of them use their smartphones in meetings or classes.
The probability is
The probability of exactly 15 out of 25 randomly selected adult smartphone users using their smartphones in meetings or classes is calculated using the binomial probability formula.
The formula is given by:
P(X = k) = (nCk) * [tex]p^k * (1 - p)^{(n - k)[/tex]
Where:
P(X = k) is the probability of exactly k successes,
n is the total number of trials or selections,
k is the number of successes,
p is the probability of success in a single trial,
(1 - p) is the probability of failure in a single trial,
nCk is the binomial coefficient, also known as "n choose k."
In this case, the values are:
n = 25 (total number of adult smartphone users selected)
k = 15 (number of smartphone users using their smartphones in meetings or classes)
p = 0.41 (probability of using smartphones in meetings or classes)
Using these values in the formula, we can calculate the probability:
P(X = 15) = (25C15) * 0.41^15 * (1 - [tex]0.41)^{(25 - 15)[/tex]
Calculating the binomial coefficient:
(25C15) = 25! / (15! * (25-15)!) = 3268760
Substituting the values:
P(X = 15) = 3268760 * 0.41^15 * (1 - 0.[tex]41)^{(25 - 15)[/tex]
Calculating this expression will give you the final probability.
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Apart from division or a fraction, what does '/' mean?
/ mean do or does when a 3rd person is present
Haley pays a montlhy fee is 20$ for her cell phone and then pays 5 cents per minute used. The total cost of haleys monthly cell phone bill can be expressed by the function C(m)=0.05m+20, where m is the number of minutes used. What are domain and range of the function C(m)
The domain of the function C(m) is the set of all possible values for the number of minutes used, m. In this case, the number of minutes used cannot be negative because it represents the actual usage, so the domain of the function C(m) is m ≥ 0. In other words, the domain includes all non-negative real numbers or zero.
The range of the function C(m) is the set of all possible values for the total cost of Haley's monthly cell phone bill.
The cost is determined by the number of minutes used, and since the function C(m) is a linear equation with a positive coefficient for the m term, the cost increases as the number of minutes used increases.
Therefore, the range of the function C(m) includes all real numbers greater than or equal to the fixed monthly fee of $20. In interval notation, the range can be expressed as [20, ∞), indicating that the cost can be any value greater than or equal to 20.
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