Task
In the picture below & and k are parallel:
m
Show that the four angles marked in the picture are congruent.




Help please I’m stuck

Answer: $13

Step-by-step explanation:

Let x be the price of each ticket (to the aquatic show and fireworks display).

Then, we know that:

$48 = $22 + 2x

Simplifying this equation, we get:

$48 - $22 = 2x

$26 = 2x

x = $13

Therefore, the price of each ticket is $13.

The measure you're referring to is called "Cohen's d." It expresses the difference between the experimental and control group in standard deviation units, providing an indicator of effect size and meaningfulness in a study.

The measure of meaningfulness that expresses the difference between the experimental and control group in standard deviation units is the effect size. Effect size is typically calculated by dividing the difference between the means of the two groups by the standard deviation of the control group. It is a useful tool for comparing the effectiveness of different interventions or treatments, as it allows researchers to assess the magnitude of the difference between the groups beyond just statistical significance.

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The null hypothesis (H0) is that the average delivery time for U.S. packages during December is 2 days, while the alternative hypothesis (Ha) is that the average delivery time is longer than 2 days.

Based on your question, you want to test if the average delivery time for U.S. packages in December is longer than 2 days. In this hypothesis test, you would have the following hypotheses:

Null Hypothesis (H0): The average delivery time for U.S. packages in December is 2 days.
Alternative Hypothesis (H1): The average delivery time for U.S. packages in December is greater than 2 days.

Thus, H0: μ ≤ 2 (where μ is the population mean delivery time)
Ha: μ > 2

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The student is not correct because there are intervals of 4 and the histogram is relatively symmetric.

The histogram is not skewed right, but instead appears to be faintly symmetrical; the frequency of points commence from a count of 0, proceeding to pulsate up to 4 and then progressively meander downward from there to 3.

No apparent outlier can be seen in the provided histogram data; this refers to any data point that disagreeably differs from the remainder of datasets. In this occurrence, no numbers stand out significantly deviantly from the rest.

The intervals used in the histogram are not five units wide, but four units wide instead.

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The equation of the line is written as y = (2/3)x + (14/3).

The equation of a line is a mathematical representation of the relationship between each point's x and y coordinates along a straight line.

Y = mx + b, where m is the line's slope and b is its y-intercept, is its mathematical formula (the point where the line intersects the y-axis). This equation allows us to rapidly calculate the y-coordinate of a point given its x-coordinate.

The equation of the line can be written as,

y = mx + c

The slope of the line is,

m = ( y₂ - y₁) / (x₂ - x₁)

m = ( 6 - 2 ) / ( 9-3 )

m = 2/3

The y-intercept is calculated as,

y = 2/3x + c

6 = (2/3) x 2 + c

c = 14/3

The equation of the line is,

y = 2/3x + 14/3

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Answer:

The answer is 29/35

Step-by-step explanation:

2/5+3/7

find the LCM of 5 and 7

[7(2)+5(3)]/35

14+15/35=29/35

Step-by-step explanation:

For a right triangle

tan Φ = opposite leg / adjacent leg

tan Φ = 40 / 630

Φ = arctan (40/630) = 3.6 degrees  

Thus, the proportion of values between negative infinity and 1 z-score in the standard normal distribution is about 84.13%.

In the standard normal distribution, the proportion of values between negative infinity and 1 z-score can be determined using the cumulative distribution function (CDF) of the normal distribution.

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Answer:

Side = 6.3245 inches

Step-by-step explanation:

Area of square = side²

40 in² = side²

√(40 in²) = √(side²)

6.3245 in = side

A graph of the given quadratic equation is shown below.

The axis of symmetry is equal to 3.

The vertex is equal to (3, -1).

In Mathematics and Geometry, the graph of a quadratic function would always form a parabolic curve because it is a u-shaped. Based on the graph of this quadratic function, we can logically deduce that the graph is an upward parabola because the coefficient of x² is positive and the value of "a" is greater than zero (0).

Since the leading coefficient (value of a) in the given quadratic function y = x² - 6x + 8 is positive 1, we can logically deduce that the parabola would open upward and the solution would be on the x-intercepts. Also, the value of the quadratic function f(x) would be minimum at -1.

In conclusion, the axis of symmetry is 3 while the vertex is given by the ordered pair (3, -1).

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Answer:

Step-by-step explanation:

You want two numbers such that ...

Let x and y represent the first and second numbers, respectively. Then the given relations can be written as the equations ...

  x +2y = 8

  2x +y = 34

Solving the first equation for x gives ...

  x = 8 -2y

Using that in the second equation, we have ...

  2(8 -2y) +y = 34

  16 -3y = 34 . . . . . . eliminate parentheses

  -18 = 3y . . . . . . . . add 3y-34

  -6 = y . . . . . . . . divide by 3

  x = 8 -2(-6) = 8 +12 = 20

The first number is 20, and the second number is -6.

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The volume of the Pentagonal pyramid is 8.25 units² and surface area is 12.2 units²

A Pyramid is a three-dimensional shape. A pyramid has a polygonal base and flat triangular faces.

The volume of of a pyramid is expressed as;

V = 1/3 b × h

where b is the area of the base

Area of the base = 1/2 nsa

where s is the side length and n is the number of sides and a is the apothem.

side length = apothem × 2tan(180/n)

= √3/2 × 2tan36

= √3 × tan36

= 1.26m

Therefore,

A = 1/2( 5 × 1.26 × √3/2)

A = 1/2 ( 5.5)

A = 2.75 units²

Volume of the pyramid = 2.75 × 3

= 8.25 units²

Area of a face = 1/2bh

= 1/2 × 1.26 × 3

= 3.78/2

= 1.88 units²

Total surface area = 1.88 × 5

= 9.45 units² + 2.75units²

= 12.2 units²

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Answer:

x = 1/3

Step-by-step explanation:

To solve this equation for x, divide each side by 33.

33x/33 = 11/33

x = 1/3

Answer:

x=3

Step-by-step explanation:

The value of x that makes the equation true is 3.

What is an equation?

An equation is a statement that equates to two expressions.

The given equation is:

Divide both sides by 11

So, the required value of x=3.

The monthly payments after the down payment are $186.58 per month.

We will first calculate amount of the down payment which is:

= 10% * 6,250.

= $625.

So, the financed amount for the purchase will be:

= $6,250 - $625

= $5,625.

We will now calculate the amount of sales tax where tax rate is 8.25%, this give us:

= $6,250 * 8.25%

= $515.63.

The total amount financed including sales tax is:

= $5,625 + $515.63

= $6,140.63.

To calculate the monthly payments, we can use the formula M = P [ i(1 + i)^n ] / [ (1 + i)^n – 1 ]

M = $6,140.63*  [ 0.005(1 + 0.005)^36 ] / [ (1 + 0.005)^36 – 1 ]

M = $6,140.63* 0.03042193745

M = $186.58

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The graph of the data set is in the image at the end, and it can be modeled by the quadratic:

y = 2*(x + 1)² - 3

Here we have the table:

x            y

-2,         -1

-1,          -3

0,           -1

1,             2

2,            7

The graph of it can be seen in the image at the end, there we can see that this seems to be a quadratic function

At the graph we also can see that (-1, -3) is te vertex, then if the leading coefficient is a, we can write the quadratic equation as:

y = a*(x + 1)² - 3

And we know that the equation passes throug (0, -1), replacing that we will get.

-1 = a*(0 + 1)² - 3

-1 = a - 3

-1 + 3 = a

2 = a

The function is:

y = 2*(x + 1)² - 3

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Answer:

c = 6.

Step-by-step explanation:

x^2+cx+9 = (x + b)^2     where b is a constant

x^2 + cx + 9 = x^1 + 2bx + b^2

so 2b = c

and b^2 = 9

So b = 3

and c = 2*b = 6

To solve this problem, we will use the fact that the square of a binomial (a+b)^2 is equal to a^2 + 2ab + b^2.

Let's start by assuming that x^2 + cx + 9c is the square of a binomial (a+b)^2. Expanding (a+b)^2 using the formula above, we get:

(a+b)^2 = a^2 + 2ab + b^2

If we compare this to x^2 + cx + 9c, we see that:

a^2 = x^2      (1)
2ab = cx       (2)
b^2 = 9c        (3)

From (1), we get a = ±√x^2 = ±x.

Substituting a = ±x into (2), we get:

2(±x)b = cx

Simplifying this equation, we get:

b = ±(c/2)

Substituting a = ±x and b = ±(c/2) into (3), we get:

x^2 + (c/2)^2 = 9c

Multiplying both sides by 4, we get:

4x^2 + c^2 = 36c

Rearranging this equation, we get:

4x^2 - 36c + c^2 = 0

This is a quadratic equation in c. Using the quadratic formula, we get:

c = (36 ± √(36^2 - 4(4)(c^2))) / (2(4))

Simplifying this equation, we get:

c = (9 ± √(81 - c^2)) / 2

Since c is nonzero, we can ignore the solution c = 0. Therefore, we have:

c = (9 + √(81 - c^2)) / 2   or   c = (9 - √(81 - c^2)) / 2

We can check that both solutions satisfy the original condition that x^2 + cx + 9c is the square of a binomial.

However, we need to ensure that the square root in each solution is real, which means that 81 - c^2 ≥ 0.

For the first solution, we have:

81 - c^2 ≥ 0

c^2 ≤ 81

|c| ≤ 9

Therefore, the first solution is valid for c such that -9 ≤ c ≤ 9.

For the second solution, we have:

81 - c^2 ≥ 0

c^2 ≤ 81

|c| ≥ 9

However, we already know that c is nonzero, so |c| > 0. Therefore, the second solution is not valid for any value of c.

Therefore, the only valid solution is:

c = (9 + √(81 - c^2)) / 2,   for -9 ≤ c ≤ 9.

I hope this helps! Let me know if you have any questions.
If x^2 + cx + 9c is equal to the square of a binomial, then it can be written in the form (x + A)^2, where A is a constant. Expanding the square of the binomial, we get:

(x + A)^2 = x^2 + 2Ax + A^2

Comparing this with the given expression, x^2 + cx + 9c, we can deduce the following:

2A = c and A^2 = 9c

We are asked to find the value of c. Using the first equation (2A = c), we can substitute c in the second equation:

A^2 = 9(2A)
A^2 = 18A

Since A is nonzero, we can divide both sides by A:

A = 18

Now, using the first equation, we can find the value of c:

c = 2A
c = 2(18)
c = 36

Therefore, the value of c is 36.

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The sum of the areas of the two squares = 104

The perimeter of the triangle is 27.67

1. We have 5x)² - x²  = 96

next wer have to solve for x

25x²  - x²  = 96

x = 2

x²  = 2²  = 4

5x)² = 10²  = 100

sum of the areas = 4 + 100 = 104

2. b = a + 4

c = b + 5

ac + bc = 2a^2 + 124

substitute b and c from the relationships:

When we simplify we have 18a = 88

a = 44/9

b = a + 4 = 44/9 + 4 = 80/9

c = b + 5 = 80/9 + 5 = 125/9

perimeter = a + b + c:

= 44/9 + 80/9 + 125/9

= 249/9 = 27.67

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There are 77,910 ways to distribute the seven distinct apples and six distinct pears to three distinct people such that each person has at least one pear.

We can use the principle of inclusion-exclusion to solve this problem. Let A be the set of all possible ways to distribute the apples and pears without any restrictions, and let B, C, and D be the sets of ways to distribute the apples and pears such that person 1, person 2, and person 3, respectively, does not receive a pear.

We can compute |A|, the total number of ways to distribute the apples and pears, as follows:

|A| = (7 + 6) choose 3 = 78 choose 3 = 82,251

To compute |B|, we can first choose 6 pears to give to persons 2 and 3 (since person 1 cannot receive a pear). This can be done in (6 choose 2) = 15 ways. Then, we can distribute the remaining 7 apples and 1 pear to the three people in any way, which can be done in (8 choose 1) * (6 choose 2) = 84 ways. Therefore, |B| = 15 * 84 = 1,260.

Similarly, |C| = |B| and |D| = |B|, since the problem is symmetric with respect to the three people.

To compute |B intersection C|, we can choose 6 pears to give to person 3 (since persons 1 and 2 cannot receive a pear). This can be done in (6 choose 1) = 6 ways. Then, we can distribute the remaining 7 apples and 2 pears to persons 1 and 2 in any way, which can be done in (9 choose 2) = 36 ways. Therefore, |B intersection C| = 6 * 36 = 216.

Similarly, |B intersection D| = |C intersection D| = |B intersection C|, since the problem is symmetric with respect to the three people.

To compute |B intersection C intersection D|, we can simply distribute the 7 apples and 3 pears among the three people in any way, which can be done in (13 choose 3) = 286 ways.

Therefore, by the principle of inclusion-exclusion, the number of ways to distribute the apples and pears such that each person has at least one pear is:

|A intersection complement(B union C union D)| = |A| - |B union C union D| = |A| - (|B| + |C| + |D| - |B intersection C| - |B intersection D| - |C intersection D| + |B intersection C intersection D|) = 82,251 - (3 * 1,260 - 3 * 216 + 286) = 77,910.

Therefore, there are 77,910 ways to distribute the seven distinct apples and six distinct pears to three distinct people such that each person has at least one pear.

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The point which is a solution to the system y = x + 7 and y = 11 - x is: 2. (2, 9).

The value of b in the second equation must be: 1. 10.

The x-coordinate of the solution to the system is: 4. x = -2.

The y-coordinate of the solution is: 4. y = 4.

The point (2, 5) would not be a solution to this equation: 4. 2x + 4y = 12

In this scenario and exercise, you are required to determine the solution to the given system of equations as follows;

y = x + 7

y = 11 - x

By using the substitution method, we have the following:

x + 7 = 11 - x

2x = 4

x = 4/2 = 2.

y = x + 7 = 2 + 7 = 9.

Next, we would determine the value of b as follows;

x = 1

y = 3x + 5 = 3(1) + 5 = 8

y = -2x + b

b = y + 2x = 8 + 2(1) = 10.

For the x-coordinate of the solution to the system, we have:

y = 4x + 7

x + y = -3

-3 - x = 4x + 7

5x = -10

x = -10/5 = -2.

For the y-coordinate of the solution, we have:

x + 3 = -2x + 6

3x = 3

x = 1

y = x + 3 = 1 + 3 = 4

2x + 4y = 12

2(2) + 4(5) = 12

4 + 20 = 12

24 = 12 (False).

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Answer:

We can rewrite the given expressions as:

(3x² - y² - 2yz - z²) and (y² - z² - 2zx - x²)

To find the H.C.F., we can use the Euclidean algorithm. We start by dividing the first expression by the second expression:

(3x² - y² - 2yz - z²) ÷ (y² - z² - 2zx - x²)

Using long division or synthetic division, we get:

(3x² - y² - 2yz - z²) = (3x + y + z)(x - y + z) + 2y(x - z)

Therefore, the remainder is 2y(x - z). We can now divide the second expression by this remainder:

(y² - z² - 2zx - x²) ÷ 2y(x - z)

Using long division or synthetic division, we get:

(y² - z² - 2zx - x²) = -x(x - y + z) + z(x - y + z)

Therefore, the remainder is z(x - y + z).

Since the second remainder is not zero, we need to continue with the algorithm. Now we divide the remainder 2y(x - z) by the remainder z(x - y + z):

2y(x - z) ÷ z(x - y + z)

Using long division or synthetic division, we get:

2y(x - z) = 2y(x - y + z) - 2y²

Therefore, the remainder is -2y². Now we divide the previous remainder z(x - y + z) by this new remainder:

z(x - y + z) ÷ (-2y²)

Using long division or synthetic division, we get:

z(x - y + z) = -1(-2y²) + z²

Therefore, the H.C.F. of the original expressions is the absolute value of the last remainder, which is |-2y²| = 2y².

Therefore, the H.C.F. of (3x² - y² - 2yz - z²) and (y² - z² - 2zx - x²) is 2y².

The expected value 'w' for the total raffle tickets sold for $1.00 with other conditions is equal to $0.784.

Number of raffle tickets sold for $1.00 = 2000

Expected value of w is ,

= Expected value of the prize won - cost of a single ticket $1.00

The probability of winning a $25 prize is

=  20/2000

= 0.01.

The expected value of winning this prize is equal to

= (25 - 1) × 0.01

= 0.24

The probability of winning a $50 prize is

= 10/2000

= 0.005.

The expected value of winning this prize is equal to

=  (50 - 1) × 0.005

= 0.245

The probability of winning a $300 prize is

= 2/2000

= 0.001.

The expected value of winning this prize is,

= (300 - 1) × 0.001

= 0.299

This implies,

The expected value of w is equal to

= 0.24 + 0.245 + 0.299

= 0.784

Therefore, the expected value of winning a prize minus the cost of the ticket is $0.784.

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The least amount of ratings the particular company can receive is 3 on the seventh survey and still be eligible to have an average of at least 8 for the first 10 surveys.

Here we have to implement basic algebraic application
Let us consider x as the  the least rating the company can get on the seventh survey.
The average of the first six surveys is 7.7, so their total score is 6 × 7.7 = 46.2.

The average of at least 8 for the first ten surveys, their total score should be at least 80.
So for the first ten surveys, their total score should be
80 = (46.2 + x + y)/10
Here
y = score for survey 8 and survey 9.

Evaluating for y
y = (80 - 46.2 - x × 2)/2
= (33.8 - x)/2.

As  each survey rating is an integer between 0 and 10 inclusive, we need to find the smallest integer value of x that makes y ≥ 0

Then, (33.8 - x)/2 >= 0.
Multiplying both sides by 2
33.8 - x >= 0
Subtracting 33.8 from both sides
-x >= -33.8
Multiplying both sides by -1
x <= 33.8
Hence, the smallest integer value of x that makes y ≥0 is x = 3.

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Answer:

Above picture is,

the explanation.

4(x−3) = 96

x=27

-12 + 12 + 4x = 96 + 12

Combine like terms: -12 + 12 = 0 0 + 4x = 96 + 12

4x = 96 + 12

Combine like terms: 96 + 12 = 108

4x = 108

Divide each side by '4'.

x = 27

The equation "14 + 5x -11 = 7x + 3 - 2x" has infinitely many solutions, so any value of "x" will satisfy the equation.

In order to solve for "x" in the equation "14 + 5x - 11 = 7x + 3 - 2x", we need to simplify the expression by combining like terms:

14 + 5x - 11 = 7x + 3 - 2x

Simplifying the LHS,

We get,

3 + 5x = 7x + 3 - 2x

Simplifying the RHS,

We get,

3 + 5x = 5x + 3

Subtracting 5x from both sides,

We get,

3 = 3

The equation simplifies to 3 = 3, which is always true.

This means that the equation has infinitely many solutions and that any value of "x" will satisfy the equation.

Therefore, there is no unique value of "x" that can be found from the equation.

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The given question is incomplete, the complete question is

Find the value of "x" in the expression "14+5x -11= 7x+3-2x".

The expression that represents the area of shaded region is expressed as:

The area of the shaded region = area of larger rectangle - area of smaller rectangle.

Area of a rectangle = length * width

Area of shaded region = [(3x + 7)(3x - 1)] - [(2x + 5)(x)]

Area of shaded region = (9x² + 18x - 7) - (2x² + 5x)

Open the bracket:

9x² + 18x - 7 - 2x² - 5x

Combine like terms:

9x² - 2x² + 18x - 5x - 7

Area of shaded region = 7x² + 13x - 7

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The ordering of the topics from broader to narrowest are given as follows:

Broad topics are topics that affect a larger amount of the population than narrower topics affect.

In the context of this problem, we have that the television is a subset of the popular media, hence the popular media is broader than the television.

Televised debates are one program on the television, that is, it is a subset of the television, hence television programs are broader than television debated.

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To decrease the type II error in a hypothesis test while maintaining the type I error at its current level, we need to increase the sample size.

Type I error shows when we reject a null hypothesis which is actually true. Type II error shows when we fail to reject a null hypothesis which is actually false.

Increasing the sample size can decrease the probability of making a Type II error, as it increases the power of the hypothesis test. Probability of correctly rejecting a false null hypothesis is called power.

By increasing the sample size, we can increase the power of the test while maintaining the significance level (and thus the type I error) at its current level.

This means that we will be less likely to miss a true effect (i.e., lower the probability of making a Type II error) while still controlling the probability of false positives (i.e., Type I error) at the desired level.

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