Test the series for convergence or divergence using the Alternating Series Test. n Σ(-1). n3 + 4 n = 1 Identify bn Evaluate the following limit. lim bn n n-> Since lim bn ? V O and bn + 1 ? von for all n > 2, ---Select--- n->00

Using Newton's method with an initial iterate x0 = 0.6, the next two iterates approximating a solution of the nonlinear equation are x1 ≈ 0.6316 and x2 ≈ 0.6300.

Newton's method is an iterative numerical technique used to approximate the solutions of a nonlinear equation. The method requires an initial estimate (x0) and iteratively refines the approximation using the formula:

x(n+1) = x(n) - f(x(n))/f'(x(n))

For the given equation, [tex]3x^2 - e^{(x+1)[/tex] = cos(x), we have:

f(x) = [tex]3x^2 - e^{(x+1)[/tex] - cos(x)

To apply Newton's method, we need to find the derivative of f(x):

f'(x) = [tex]6x - e^{(x+1)} + sin(x)[/tex]

We are given x0 = 0.6, and we need to calculate x1 and x2. Using the formula, we get:

x1 = x0 - f(x0)/f'(x0)
x1 = 0.6 - (3(0.6)² - [tex]e^{(0.6+1)[/tex] - cos(0.6))/(6(0.6) - [tex]e^{(0.6+1)[/tex] + sin(0.6))
x1 ≈ 0.6316 (rounded to 4 decimal places)

Now, using x1 to calculate x2:

x2 = x1 - f(x1)/f'(x1)
x2 = 0.6316 - (3(0.6316)² - [tex]e^{(0.6316+1)[/tex] - cos(0.6316))/(6(0.6316) - [tex]e^{(0.6316+1)[/tex] + sin(0.6316))
x2 ≈ 0.6300 (rounded to 4 decimal places)

Thus, using Newton's method with an initial iterate x0 = 0.6, the next iterates of the nonlinear equation are x1 ≈ 0.6316 and x2 ≈ 0.6300.

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Answer:

午後5時37分ちょうどにあなたの家に来て、あなたが椅子に縛られている間にあなたの両親を殺します.私は武装し、あなたを縛ります。急な動きをしたら、ロケットランチャーかショットガンで頭を吹き飛ばします。あなたの選択！

type that into translate, okay?

The partial derivatives are:

∂ z / ∂ x = − [ 5x⁴z⁶ ] / [ 6x⁵z⁵ + 6z⁵y⁴cos ( y⁴z⁶ )]

∂ z / ∂ y  = − [ 4y³z⁶ cos ( y⁴ z⁶ ) ] / [ 6x⁵z⁵ + 6z⁵y⁴cos ( y⁴z⁶ )]

We have,

f(x, y, z) = x⁵z⁶ + sin (y⁴z⁶) + 2 = 0

Now, partially differentiating we get

∂ z / ∂ x

= - [ ∂ F / ∂ x ] /  [ ∂ F / ∂ z  ]

= − [ 5x⁴z⁶ ] / [ 6x⁵z⁵ + 6z⁵y⁴cos ( y⁴z⁶ )]

and,

∂ z / ∂ y

= - [ ∂ F / ∂ y ] / [ ∂ F / ∂ z ]

= − [ 4y³z⁶ cos ( y⁴ z⁶ ) ] / [ 6x⁵z⁵ + 6z⁵y⁴cos ( y⁴z⁶ )]

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The interval of t-values that corresponds to the line segment connecting the points (0, -7) and (6, 5) is t ∈ [0, 1].

Let's find the vector equation of the line segment that connects the points (0, -7) and (6, 5). The direction vector of the line segment is:

d = (6, 5) - (0, -7) = (6, 12)

A vector equation for the line segment is:

r(t) = (0, -7) + t(6, 12) = (6t, -7 + 12t)

We want to find the values of t that correspond to the point on the line segment given by the parameterization (2t+4, -5t+1).

So, we can set the x-coordinates and y-coordinates of the two parameterizations equal to each other:

6t = 2t + 4

-7 + 12t = -5t + 1

Solving these equations, we get:

t = 1

Substituting t = 1 into the vector equation of the line segment, we get the point (6, 5), which is the endpoint of the line segment given by the parameterization.

Therefore, the interval of t-values that corresponds to the line segment connecting the points (0, -7) and (6, 5) is t ∈ [0, 1].

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There are exactly 18 red apples and 8 yellow apples in the bag. Then the correct option is C.

Given that:

Ratio, Red : Yellow = 9 : 4

The utilization of two or more additional numbers that compares is known as the ratio.

The ratio can be written as,

Red : Yellow = 9 : 4

Red : Yellow = 9 x 2 : 4 x 2

Red : Yellow = 18 : 8

There are exactly 18 red apples and 8 yellow apples in the bag. Then the correct option is C.

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To put the scores in order using minimum, maximum, and range, we first need to determine the values of each. The minimum score is 9, the maximum score is 24, and the range is 15.

Therefore, we can arrange the scores in ascending order as follows:

9, 14, 15, 17, 17, 21, 22, 23, 24

The minimum score of 9 represents the lowest score that Dawn received during the game. The maximum score of 24 represents the highest score that she received. The range of 15 represents the difference between the highest and lowest scores.

Knowing the minimum, maximum, and range can provide valuable information about a data set, as it allows us to see the spread of the scores and the range of values that the data encompasses.

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The arclength of the curve (e* +e-*) from -1 to 1 is 2(2 arccosh(2) - √3).

The problem requires finding the arclength of the curve (e* +e-*) from -1 to 1.

The arclength of the curve is given by the formula:

L = ∫√(1+(dy/dx)²) dx

To find dy/dx, we differentiate the curve (e* +e-*) with respect to x:

dy/dx = d/dx(e* +e-*) = e^x - e^(-x)

Now, we substitute this into the arclength formula and integrate from -1 to 1:

L = ∫(-1)^1 √(1+(e^x - e^(-x))²) dx

We can simplify the integrand using the identity (a-b)² = a² - 2ab + b²:

L = ∫(-1)^1 √(2 + 2e^(2x) - 2e^(-2x)) dx

= ∫(-1)^1 √(4(e^(2x) + e^(-2x)) - 4) dx

= 2 ∫0^1 √(e^(2x) + e^(-2x) - 1) dx

Next, we make the substitution u = e^x + e^(-x), du/dx = e^x - e^(-x), and simplify:

L = 2 ∫2^2 √(u² - 1) du/u

= 2 ∫arccosh(u) du

= 2(u arccosh(u) - √(u² - 1))|2^2

= 2(2 arccosh(2) - √3)

Therefore, the arclength of the curve (e* +e-*) from -1 to 1 is 2(2 arccosh(2) - √3).

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Answer: x=-150

Step-by-step explanation:

If 1.4 g of chemical A is used, the amount of chemical B needed to balance the chemical reaction is 1.6 g.

The mass of chemical B needed is calculated by reading off their corresponding values from the graph as shown below;

If 1.4 g of chemical A is used, the amount of chemical B needed to balance the chemical reaction must be taken from the graphed values by tracing the value of chemical A from the horizontal axis to the corresponding value of chemical B on vertical axis.

Chemical A = 1.4 g

Chemical B = 1.6 g (this value is obtained by tracing the intersection of 1.4 g on the curve to the y-axis).

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Answer:

33

Step-by-step explanation:

30+9÷(3)

30+3

33

please like and rate and follow

The expected standard deviation for a sample of size 14 with a percentage of success of 25%, assuming data follows a binomial distribution, is approximately 1.62 (option b).

To calculate the expected standard deviation, we can use the formula for the standard deviation of a binomial distribution:

SD = sqrt(npq)

where n is the sample size, p is the percentage of success, and q is the percentage of failure (q = 1 - p).

Substituting the values given, we get:

SD = sqrt(14 x 0.25 x 0.75)

SD = sqrt(2.625)

SD ≈ 1.62

Therefore, the expected standard deviation for a sample of size 14 with a percentage of success of 25%, assuming data follows a binomial distribution, is approximately 1.62. This means that the actual values of success in the sample are likely to vary from the expected value of 3.5 (14 x 0.25) by about 1.62 units.

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from the figure above, we can say that △ABC ~ △DEC by "AA", so then we can say

[tex]\cfrac{(x+7)+34}{34}=\cfrac{15+3x}{3x}\implies \cfrac{x+41}{34}=\cfrac{15+3x}{3x} \\\\\\ 3x^2+123x=510+102x\implies 3x^2+21x-510=0 \\\\\\ 3(x^2+7x-170)=0\implies x^2+7x-170=0 \implies (x-10)(x+17)=0 \\\\\\ x= \begin{cases} ~~ 10 ~~ \checkmark\\ -17 \end{cases}\hspace{5em}\stackrel{\textit{\LARGE AB}}{15+3(10)}\implies 45[/tex]

The trigonometric substitution to integrate / V2 - 4x2 dx is f(x) = (2c + 9)/(x - 2) + (-2c - 2.7)/10.9 Σn=0 (-1/32.7)^n (3x + 4.3)^n.

To use partial fractions, we first factor the denominator of f(x) as:

3x^2 - 23.3x - 8 = (x - 2)(3x + 4.3)

Therefore, we can write f(x) as:

f(x) = (2c + 9)/(x - 2) + A/(3x + 4.3)

where A is a constant to be determined. Multiplying both sides by the denominator (x - 2)(3x + 4.3), we get:

2c + 9 = A(x - 2) + (2c + 9)(3x + 4.3)

Simplifying and solving for A, we get:

A = (-2c - 2.7)/(3(2) + 4.3) = (-2c - 2.7)/10.9

Therefore, we can write:

f(x) = (2c + 9)/(x - 2) - (-2c - 2.7)/(10.9(3x + 4.3))

We can now use the formula for the geometric series to express the second term as a power series:

1/(1 - t) = Σn=0 tn

where t = (-1/32.7)(3x + 4.3) and the series converges if |t| < 1.

Substituting, we get:

f(x) = (2c + 9)/(x - 2) + (-2c - 2.7)/10.9 Σn=0 (-1/32.7)^n (3x + 4.3)^n

Simplifying, we get:

f(x) = (2c + 9)/(x - 2) - (2c + 2.7)/10.9 Σn=0 (-3/32.7)^n (x + 1.43/3)^n

This is the power series expansion of f(x) centered at x = 0. The open interval of convergence is determined by the convergence of the geometric series, so we have:

|(-3/32.7)(x + 1.43/3)| < 1

Simplifying, we get:

|x + 1.43/3| < 10.9/3

Therefore, the open interval of convergence is (-13.7/3, 8.47/3) or approximately (-4.57, 2.82).

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The absolute extrema of the following functions on the given interval: (a)   f(x) on the interval [-2, 2] are: Absolute maximum: f(-2) = -2, (b) the absolute extrema of f(x) on the interval [-π/6, π/2] are:  f(π/4) = f(3π/4) = 1/2.

(a) The function f(x) = 3x-4/x^2+2 is continuous on the interval [-2, 2] and has no vertical asymptotes or holes in the domain. To find the absolute extrema of the function, we need to check the critical points and endpoints of the interval. First, we find the derivative of f(x) using the quotient rule:

f'(x) = [3(x²+2) - 2x(3x-4)] / (x²+2)² = (10 - 3x²) / (x²+2)²

Setting f'(x) = 0, we find that the critical points occur when 3x^2 = 10, which gives x = ±√(10/3). We can also see that f'(x) is negative for x < -√(10/3) and positive for x > √(10/3), indicating that f(x) is decreasing on the interval (-∞, -√(10/3)) and increasing on the interval (√(10/3), ∞).

Now we check the endpoints of the interval, f(-2) = -2 and f(2) = 2. Since f(x) is decreasing on the interval [-2, √(10/3)] and increasing on the interval [√(10/3), 2], the absolute minimum occurs at x = √(10/3) and the absolute maximum occurs at x = -2.

Therefore, the absolute extrema of f(x) on the interval [-2, 2] are: Absolute minimum: f(√(10/3)) = -4√(3/10), Absolute maximum: f(-2) = -2

(b) The function f(x) = sin(x)cos(x) is also continuous on the interval [-π/6, π/2]. To find the absolute extrema, we take the derivative: f'(x) = cos²(x) - sin²(x) = cos(2x) Setting f'(x) = 0, we find critical points when 2x = π/2 + kπ, where k is an integer. Solving for x gives x = (π/4) + (kπ/2). Now we check the endpoints of the interval: f(-π/6) = -1/4√3 and f(π/2) = 0.

The critical points occur at x = -5π/4, -3π/4, -π/4, π/4, and 3π/4. We evaluate f(x) at these critical points and the endpoints of the interval and find that the absolute extrema of f(x) on the interval [-π/6, π/2] are: Absolute minimum: f(-5π/4) = f(-3π/4) = -1/2, Absolute maximum: f(π/4) = f(3π/4) = 1/2

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Complete question:

Find the absolute extrema of the following functions on the given interval. 3.2 - 4

(a) f(x) = 3x-4/x²+2 on [-2, 2]

(b) f(x) = sin(x) cos(x), - on [-π /6,  π/2]

The calculated value of the area of the figure is 464  sq units

From the question, we have the following parameters that can be used in our computation:

Composite figure

The shapes in the composite figure are

This means that

Area = Squares + Rectangles

Using the area formulas on the dimensions of the individual figures, we have

Area = 16 * 16 + 24 * 4 + 4  * (24 - 12) + 8 * 8

Evaluate

Area = 464

Hence, the area of the figure  is 464 sq units

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The sp for the set of numbers 0 2 1 4 4 5 3 3 7 6 1 is 1.91. The definitional formula works well in this case because both the mean and the sp are whole numbers.

To calculate sp for the given set of numbers: 0 2 1 4 4 5 3 3 7 6 1, we first need to find the mean or average of the set.

To do this, we add up all the numbers and divide by the total count:

0 + 2 + 1 + 4 + 4 + 5 + 3 + 3 + 7 + 6 + 1 = 36

There are 11 numbers in the set, so:

36 / 11 = 3.27

Next, we need to find the deviation of each number from the mean.

To do this, we subtract the mean from each number:

0 - 3.27 = -3.27

2 - 3.27 = -1.27

1 - 3.27 = -2.27

4 - 3.27 = 0.73

4 - 3.27 = 0.73

5 - 3.27 = 1.73

3 - 3.27 = -0.27

3 - 3.27 = -0.27

7 - 3.27 = 3.73

6 - 3.27 = 2.73

1 - 3.27 = -2.27

Now we need to square each deviation:

(-3.27)^2 = 10.68

(-1.27)^2 = 1.61

(-2.27)^2 = 5.16

(0.73)^2 = 0.53

(0.73)^2 = 0.53

(1.73)^2 = 2.99

(-0.27)^2 = 0.07

(-0.27)^2 = 0.07

(3.73)^2 = 13.94

(2.73)^2 = 7.44

(-2.27)^2 = 5.16

Add up all the squared deviations:

10.68 + 1.61 + 5.16 + 0.53 + 0.53 + 2.99 + 0.07 + 0.07 + 13.94 + 7.44 + 5.16 = 48.18

Finally, we divide the sum of squared deviations by the total count minus 1, and take the square root of the result:

sqrt(48.18 / (11 - 1)) = 1.91

So the sp for the set of numbers 0 2 1 4 4 5 3 3 7 6 1 is 1.91.

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The height of the jar is 20 centimeters when the radius is 4 centimeters.

Let V be the total volume of the jar. Since the jar is one-fourth full, we know that the remaining three-fourths are empty.

Thus, we can write:

V = (4/3)πr²h

We can also write the volume of the baby food as:

20π = (1/4)πr²h

Simplifying this equation, we get:

80 = r²h

Now, we can substitute this value of r²h in the equation for the total volume of the jar:

V = (4/3)πr²h

V = (4/3)πr²(80/r²)

V = (4/3)π(80)

V = 320π

Therefore, the total volume of the jar is 320π cubic centimeters.

Now, we can use the formula for the volume of a cylinder to find the height of the jar:

320π = πr²h

320 = 16h

h = 20

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Answer: 1750

Step-by-step explanation:

100+500+1000+5000+6000= 12600x10= 126000

126000 divided 74 = 1750

Therefore, the probability that a randomly selected value is between 215.2 and 241 is approximately 0.1366.

To solve this problem, we need to standardize the values using the z-score formula:

z = (x - μ) / σ

where x is the value of interest, μ is the mean, and σ is the standard deviation.

For the value of 215.2:

z1 = (215.2 - 193.6) / 43.1 = 0.4995 (rounded to 4 decimal places)

For the value of 241:

z2 = (241 - 193.6) / 43.1 = 1.0912 (rounded to 4 decimal places)

Now we can use a standard normal table or calculator to find the area under the standard normal curve between these two z-scores:

P(0.4995 < Z < 1.0912) = 0.1366

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The equation of the line is expressed in slope-intercept form as:

y = -5/6x - 7.

The equation of a line can be written in slope-intercept form as y = mx + b, where we have:

m = the slope

b = the y-intercept.

Find the slope (m):

Slope (m) = rise/run = -5/6

The y-intercept (b) is -7.

Substitute m = -5/6 and b = -7 into y = mx + b:

y = -5/6x - 7

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To find a formula for h'(x), the derivative of h(x), we need to consider the two parts of the piece-wise function separately.

1. For x > 2:

In this case, h(x) = (x - 2) + x - 5.

To find h'(x), we can differentiate each term separately:

h'(x) = (d/dx)(x - 2) + (d/dx)(x - 5)

Since the derivative of a constant is zero, we have:

h'(x) = 1 + 1 = 2

So, for x > 2, h'(x) = 2.

2. For x < 2:

In this case, h(x) = |x| = -x.

The derivative of -x is simply -1:

h'(x) = -1

So, for x < 2, h'(x) = -1.

Note: At x = 2, the function h(x) has a corner or "kink" due to the absolute value function. The left and right derivatives are not equal, so h(a) is not differentiable at x = 2. Therefore, we cannot find a formula for h'(x) at x = 2.

In summary, the formula for h'(x) is:

h'(x) =

 2    if x > 2

-1    if x < 2

At x = 2, h(a) is not differentiable.

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Answer:

if u trying to find the white blank answer is 18

but if u trying to find the color spot with no white

Answer:

Step-by-step explanation:

lets break this down into 3 rectangles. Following a=base*height

6*4 =24

6*3=18

10*2=20 (difference of 8 and 6 = 2)

tot=62ft^2

Answer:

A

Step-by-step explanation:

a recursive formula allows a term in the sequence to be found from the preceding term.

here the pattern of squares is

1, 4, 16

each term is 4 times the preceding term

then recursive formula is

[tex]a_{n}[/tex] = 4[tex]a_{n-1}[/tex] : a₁ = 1

a) The derivative is (1/4)x^(-3/4). b) The derivative is (1 + ln(x)) / x^2.

a) f(x) = x^(1/4)

To find the derivative, use the power rule: f'(x) = nx^(n-1), where n is the current exponent of x.
f'(x) = (1/4)x^((1/4)-1) = (1/4)x^(-3/4)

b) g(x) = -ln(x)/x

Use the quotient rule: (u/v)' = (u'v - uv')/v^2, where u = -ln(x) and v = x.
u' = -1/x, v' = 1

g'(x) = ((-1/x)*x - (-ln(x))*1) / x^2 = (1 + ln(x)) / x^2

c) h(x) = (2x^2 + x)

Use the power rule for each term:
h'(x) = (4x + 1)

d) g(x) = sin(x)

The derivative of sin(x) is cos(x):
g'(x) = cos(x)

e) h(x) = ln(x)sin(x)

Use the product rule: (uv)' = u'v + uv', where u = ln(x) and v = sin(x).
u' = 1/x, v' = cos(x)

h'(x) = (1/x)sin(x) + ln(x)cos(x)

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Since ab > 0, it is clear that the discriminant D > 0. Therefore, the equation ax^2 + bx + c = 0 has two distinct real roots.

Since 4a + 2b + c = 0, we can rewrite c as c = -4a - 2b. Substituting this into the quadratic equation ax^2 + bx + c = 0 gives ax^2 + bx - 4a - 2b = 0. Factoring out an 'a' gives a(x^2 + (b/a)x - 4) - 2b = 0.

Since ab > 0, we know that a and b must have the same sign. This means that either both a and b are positive or both a and b are negative. In either case, (b/a) is negative. So we can rewrite the equation as a(x^2 - |(b/a)|x - 4) - 2b = 0.

To solve for the roots of the equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Plugging in the coefficients, we get x = (-b ± √(b^2 - 4a(-4a-2b))) / 2a, which simplifies to x = (-b ± √(b^2 + 16ab)) / 2a.

Since ab > 0, we know that b^2 + 16ab > 0. Therefore, the quadratic equation ax^2 + bx + c = 0 has two real roots.

Based on the information provided, let's consider the equation ax^2 + bx + c = 0, where a, b, and c are real numbers and 4a + 2b + c = 0. Since ab > 0, both a and b have the same sign (either both positive or both negative).

The given equation can be rewritten as a quadratic equation in the standard form:

ax^2 + bx + c = 0

Using the discriminant formula, D = b^2 - 4ac, we can analyze the nature of the roots of the quadratic equation. Given that 4a + 2b + c = 0, we can express c as:

c = -4a - 2b

Now, let's plug this value of c into the discriminant formula:

D = b^2 - 4a(-4a - 2b)

D = b^2 + 16a^2 + 8ab

Since ab > 0, it is clear that the discriminant D > 0. Therefore, the equation ax^2 + bx + c = 0 has two distinct real roots.

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So, by definition, a primary key must be unique and must have a value that is not null.

A primary key is a column or set of columns in a relational database table that uniquely identifies each row or record in that table.

By definition, a primary key must be unique, which means that no two rows in the table can have the same value in the primary key column(s).

This uniqueness constraint is enforced by the database management system (DBMS) when inserting, updating, or deleting data in the table.

In addition to being unique, a primary key must also have a value that is not null, which means that every row in the table must have a value in the primary key column(s).

This ensures that each row can be uniquely identified and accessed.

The primary key is used as a reference by other tables in the database, which may have relationships with the primary key column(s) in the table.

For example, a foreign key is a column in one table that references the primary key column(s) in another table.

This allows the DBMS to enforce referential integrity between the tables, which means that data in the database is consistent and accurate.

In summary, a primary key is a fundamental concept in relational database design, and it plays a critical role in ensuring data integrity and consistency.

By definition, a primary key must be unique and must have a value that is not null, which allows each row in the table to be uniquely identified and accessed.

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The ratio, 71 : 53 of the form n:1 is 1.34 : 1.

How to find ratios?

The ratio of black cars to green cars in a car park is 71 : 53.

Therefore, let's represent the ratio of the form n : 1.

Ratio, is a term that is used to compare two or more numbers. In simper term, ratios compare two or more values.

Hence, let's divide the ratio by 53.

Therefore,

71 : 53

71 / 53 : 53 / 53

1.33962264151 : 1

1.34 : 1

where

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To determine which interval has the most confidence in capturing the population mean, we need to look at the confidence level associated with each interval. A confidence interval is a range of values that we believe contains the true population parameter.

If we have three intervals with different confidence levels, the interval with the highest confidence level would be the one with the most confidence in capturing the population mean. For example, if Interval A has a confidence level of 90%, Interval B has a confidence level of 95%, and Interval C has a confidence level of 99%, then Interval C would have the most confidence in capturing the population mean.

It's important to note that the level of confidence we choose affects the width of the interval. The higher the confidence level, the wider the interval will be. Therefore, we need to balance the desire for a high level of confidence with the need for a narrow interval.

In summary, the interval with the highest confidence level is the one with the most confidence in capturing the population mean. Confidence intervals are a powerful tool in statistics that allows us to estimate population parameters from a sample with a known degree of uncertainty.

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Answer: Missing the statments

Step-by-step explanation:

To determine if two pools are similar, the pool company needs to check if the corresponding sides are proportional and the corresponding angles are equal. If these conditions are met, then the two pools are considered similar in geometry.

In mathematics, specifically in geometry, similar figures are figures that have the same shape but may differ in size. To determine if pool ABCD is similar to pool EFGH, the pool company needs to check the proportionality of corresponding sides and the equality of corresponding angles.

For instance, if the length and width of pool ABCD is twice that of pool EFGH, and all the corresponding angles are equal, then the two pools are similar. It's crucial to note that all corresponding sides should be in proportion and all corresponding angles should be equal for the figures to be considered similar.

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The number of blocks that Tommy travels is given as follows:

26 blocks.

Suppose that we have two points of the coordinate plane, and the ordered pairs have coordinates [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex].

The shortest distance between them is given by the equation presented as follows, derived from the Pythagorean Theorem:

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Then the distances are given as follows:

Then the total number of blocks is given as follows:

2 x (8 + 5) = 26 blocks.

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