The amount of potential energy, P, an object has is equal to the product of its mass, m, its height off the ground, h, and the gravitational constant, g. This can be modeled by the equation P = mgh.

What is the equivalent equation solved for h?

StartFraction StartFraction p Over m EndFraction Over g EndFraction equals h. = h
StartFraction p Over m g EndFraction equals h.= h
Pmg = h
StartFraction p Over StartFraction m Over p EndFraction EndFraction equals h. = h

Answer: -5  < x < -2 or (-5, -2)

Step-by-step explanation:

Graph- (-5, -2)

Inequality- -5  < x < -2

Answer:

A

Step-by-step explanation:

This is because the answer you picked means congruent to, however these two triangles are not the same size

Answer:

$843.67

Step-by-step explanation:

We can use a proportion to solve this problem:

12 : 100 = x : 896

x =(896 * 12)/100 = $107,52

896 - 107.52 = $788,48 (price of the computer after the discount)

7 : 100 = x : 788,48

x = (788,48 * 7)/100 = $55,1936

788.48 + 55,1936 = 843,6736 = $843.67 (final price)

Hello,

All the numbers must begin with  6.

There are still 2,3,4,5 digits :  4 possibilities.

4!=4*3*2*1=24

The first is 62345 and the last 65432.

Given:

The gradient of the line passing through A(2,3), B(k,7) is [tex]\dfrac{2}{3}[/tex].

To find:

The value of k.

Solution:

The gradient or slope of a line is:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

The gradient of the line passing through A(2,3), B(k,7) is [tex]\dfrac{2}{3}[/tex]. So,

[tex]\dfrac{2}{3}=\dfrac{7-3}{k-2}[/tex]

[tex]\dfrac{2}{3}=\dfrac{4}{k-2}[/tex]

On cross multiplication, we get

[tex]2(k-2)=4(3)[/tex]

[tex]2k-4=12[/tex]

[tex]2k=12+4[/tex]

[tex]2k=16[/tex]

Divide both sides by 2.

[tex]k=\dfrac{16}{2}[/tex]

[tex]k=8[/tex]

Therefore, the value of k is 8.

Answer:

Hope it helps

Step-by-step explanation:

Answer:

because when two negatives are together they can't add

Step-by-step explanation:

because when two negatives are together they can't add no matter if there's an addition sign

Answer:

Scale model width = 12.5 yards

Step-by-step explanation:

Given:

Actual length of field = 120 yards

Actual width of field = 50 yards

Scale model length = 30 yards

FInd:

Scale model width

Computation:

Scale model width = [Scale model length / Actual length of field] Actual width of field

Scale model width = [30/120]50

Scale model width = [1/4]50

Scale model width = 0.25 x 50

Scale model width = 12.5 yards

Answer:

Step-by-step explanation:

If a point (x, y) is reflected across y = -x, coordinates of the image point will be,

(x, y)→ (-y, -x)

Following this rule,

Vertices of the triangle will be,

(3, 1) → (-1, -3)

(3, -2) → (2, -3)

(6, -3) → (3, -6)

Therefore, image of the given triangle A will be,

(-1, -3), (2, -3) and (3, -6)

what's the whole question??

Step-by-step explanation:

For the 1st picture,

1 unit to the left and 3 units up.

Fir the 2nd picture,

We know the 90 degree counterclockwise rule is

[tex](x) \:(y) goes \: to \: ( - y)(x)[/tex]

So our new points will be

(-1,7)

(4,8)

(-2,2)

For the 3rd picture,

The new points will be

(-10,0)

(-6,2)

(-7,-1)

For the 4th picture,

A pentagon interior angles add up to 540.

We solve for x.

I cant really see the angles but just add up all the known angles and subtract them from 540 and that should get you your answer.

For 5th picture,

Exterior angles add up to 360 for every figure, a 13 sided polygon means it has 13 exterior angles. Since this is a regular polygon, the angles will all be equal.

[tex] \frac{360}{13} = 27 \frac{9}{13} [/tex]

Which equal

27.7

hope this helps you.

Answer:

Step-by-step explanation:

y = 2 - 4x

y = 2 - 4(-1)

y = 2 + 4

y = 6

hope this helps!

Answer:

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].

Step-by-step explanation:

Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:

[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].

Multiply both sides by [tex](-1)[/tex] to obtain:

[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].

[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].

If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:

[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].

However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].

Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].

Determinant of this quadratic equation about [tex]y[/tex]:

[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].

Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:

[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].

[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].

Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].

The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:

[tex]-2 \le -m^{2} \le 0[/tex].

[tex]0 \le m^{2} \le 2[/tex].

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

In other words,  solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].

Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

Answer

Number of years 1               2            3

House 1 (value in dollars) 249,000 253,980 259,059.60

House 2 (value in dollars) 249,000 256,000 263,000

House 1: exponential function

House 2: linear function

House 1: f(x) = 249,000 * (1.02)^(x-1)

→ f(3) = 249,000 * (1.02)³⁻¹ = 249,000 * (1.02)² = 259,059.60

House 2: f(x) = 249,000 + 7,000(x-1)

→ f(3) = 249,000 + 7,000(3-1) = 249,000 + 7,000(2) = 249,000 + 14,000 = 263,000

House 1:

f(45) = 249,000 * (1.02)⁴⁵⁻¹ = 249,000 * (1.02)⁴⁴ = 249,000 * 2.39 = 595,110

House 2:

f(45) = 249,000 + 7,000(45-1) = 249,000 + 7,000(44) = 249,000 + 308,000 = 557,000

House 1 will have a greater value than House 2 after 45 years.

Step-by-step explanation:

Hope this helps, if not let me know and I will fix it.

Part A

The value for house 1 follows an exponential growth function since the value is increasing by 2% each year. This is because we multiply each value by 1.02 to get the next year's value.

In contrast, house 2's value increases by the same amount each year (7000 per year)

This fixed amount it increases directly leads to house 2 having linear growth.

-----------

=================================================

Part B

The equation for house 1's value is y = 249000(1.02)^x

This is in the form y = ab^x, where a = 249000 is the starting value and b = 1.02 is the growth rate factor.

We can think of 1.02 as 1+0.02 to represent the 2% growth.

In other words, 1.02 = 1+r solves to r = 0.02 = 2%

-----------

The equation for the second home's value is y = 7000x+249000

The slope m = 7000 tells us how the value is going up per year.

The y intercept b = 249000 is the original home value (when x = 0).

-----------

=================================================

Part C

Let's plug x = 45 into each equation mentioned in part B

For home 1, we have

f(x) = 249000(1.02)^x

f(45) = 249000(1.02)^45

f(45) = 607,025.697

f(45) = 607,025.70

So that's the value of home 1 after 45 years of constant 2% growth per year

For the second home, we have,

f(x) = 7000x+249000

f(45) = 7000*45+249000

f(45) = 564,000

So there is a significant difference. This difference is 607,025.70 - 564,000 = 43,025.70 dollars.

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Answer:

oh I thought you were talk about love well dang :(

Step-by-step explanation:

Answer:

hi, it's 16 because:

[tex]ab = bc \\ ab = 8 \\ ac = 2 \times 8 = 16 \\ ac = 16[/tex]

Answer:

16

Step-by-step explanation:

Theorem: In a circle, if a radius is perpendicular to a chord, then the radius is the perpendicular bisector of the chord.

In this case, the radius containing points O and B is perpendicular to chord AC, so the radius bisects chord AC making AB = BC.

Also,

AB + BC = AC

By substitution, we have

AB + AB = AC

AC = 2AB

AC = 2(8)

AC = 16

Answer:

f(g(x)) =

[tex] {x}^{6} + 6 {x}^{4} + 8x^{2} + 2[/tex]

Step-by-step explanation:

put g(x) instead of any x in f(x)

[tex] {(x ^{2} + 2) }^{3} - 4( {x}^{2} + 2) + 2[/tex]

Answer:

[tex]y = |x+2|+1[/tex]

Step-by-step explanation:

Answer: 7 hr

Step-by-step explanation:

Given

Distance between Emily and Kylie is [tex]140\ \text{miles}[/tex]

Speed of Emily [tex]v_e=12\ mph[/tex]

Speed of Kylie [tex]v_k=8\ mph[/tex]

Distance traveled by Emily [tex]\Rightarrow d_e=12t[/tex]

Distance traveled by Kylie [tex]\Rightarrow d_k=8t[/tex]

[tex]\Rightarrow 12t+8t=140\\\Rightarrow 20t=140\\\Rightarrow t=7\ hr[/tex]

They will meet after 7 hour.

Answer:

only Y

Step-by-step explanation:

all the others have for at least 1 value of x more than one different y values defined.

but a function must be clear about the association between an x unit value and the corresponding result.

many different input values can have the same functional result. but there can be only one defined result per input value. otherwise it is not a function.

you cannot say 1+1 = 2 or 3. it is either 2 or 3, but you need to define what. you can't leave it open.

The function is given by the table Y

x = { -3 , 2 , 0 , 3 } and y = { 1 , 1 , 1 , 1 }

The function rule is the relationship between the input or domain and the output or range. A relation is a function if and only if there exists one value in the range for every domain value.

A function is a relation from a set of inputs to a set of possible outputs where each input is related to exactly one output.

Given data ,

Let the function be represented as A

Now , the value of A is

Let the x values of the function be represented as

x = { -3 , 2 , 0 , 3 }

Now , the y values of the function is

y = { 1 , 1 , 1 , 1 }

From the table , we can see that for every different values of x there are range of values of y

No two same values of ranges have the same domain

Therefore , it is a function

Hence , the function is table Y

To learn more about function rule click :

https://brainly.com/question/3760195

#SPJ7

Answer:

I'm sorry but no idea

Step-by-step explanation:

No idea

Answer:

[tex]{ \tt{length = \sqrt{ {( - 2 - 5)}^{2} + {(3 - 7)}^{2} } }} \\ = \sqrt{65} \\ = 8.06 \: units[/tex]

(I) is true, since the plot shows f'(x) is negative on (0, 2)

(II) is false, since f'(x) is negative on (1, 2), so f(x) is decreasing over this interval

(III) is false. An inflection point can only occur at a point x if f''(x) is zero or doesn't exist. But at x = 0, the tangent line to f'(x) clearly has a negative, non-zero slope.

This makes A the correct choice.

Answer:

Step-by-step explanation:

If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,

(x, y) → (x + 4. y + 1)

Therefore, vertices of the image triangle ABC will be,

A(2, 2) → A'(2+4, 2+1)

           → A'(6, 3)

B(5, -1) → B'(5+4, -1+1)

           → B'(9, 0)

C(1, -2) → C'(1+4, -2+1)

           → C'(5, -1)

Then reflected across y-axis.

Rule for the reflection across y-axis will be,

(x, y) → (-x, y)

A'(6, 3) → A"(-6, 3)

B'(9, 0) → B"(-9, 0)

C'(5, -1) → C"(-5, -1)

Answer:

A"(-6, 3)

B"(-9, 0)

C"(-5, -1)

Step-by-step explanation:

Answer:

a) 1.73

b)1.32

Step-by-step explanation:

y = f(x) = 3^x

f(1/2) = 3^1/2 = √(3) = 1.73

f(1/4) = 3^1/4 = 1/4√3 = 1.32

Answer:

Answer :

It's 3v - 9/2

Step-by-step explanation:

....

Answer:he's right

Step-by-step explanation:

Answer:

Step-by-step explanation:

The area of a sector has the formula

[tex]A_s=\frac{\theta}{360}*\pi r^2[/tex] Hopefully, this looks somewhat familiar to you. Theta is the central angle given as 75, r is the radius given as 4. Filling in:

[tex]A_s=\frac{75}{360}*(3.14)(4)^2[/tex] and simplifying that a bit to look less threatening, but not by much:

[tex]A_s=\frac{5}{24}(3.14)(16)[/tex] and

[tex]A_s=\frac{251.2}{24}=\frac{157}{15}=10.466666666...[/tex] Not sure how you're supposed to express your answer so I gave both the fraction and its decimal equivalency.

Answer:

x = 6

HI = 29

Step-by-step explanation:

✔️HI = ½(AB) => Triangle Mid-segment Theorem

HI = 5x - 1

AB = 58

Plug in the values and solve for x

5x - 1 = ½(58)

5x - 1 = 29

Add 1 to both sides

5x - 1 + 1 = 29 + 1

5x = 30

Divide both sides by 5

5x/5 = 30/5

x = 6

✔️HI = 5x - 1

Plug in the value of x

HI = 5(6) - 1

HI = 30 - 1

HI = 29