Answer:
α = θ^(-1/2)
Explanation:
The angular acceleration α is the derivative of angular velocity ω with respect to time, and it can be found by taking the derivative of ω with respect to θ.
Given: ω = 2√θ
To find α, we differentiate ω with respect to θ:
α = dω/dθ
Using the power rule of differentiation, we can differentiate 2√θ with respect to θ:
α = d/dθ (2√θ)
Using the chain rule, we can differentiate 2√θ with respect to θ:
α = 2 * (1/2) * θ^(-1/2) * dθ/dθ
Simplifying, we get:
α = θ^(-1/2)
So, the angular acceleration α as a function of θ is given by α = θ^(-1/2).
It has been suggested that rotating cylinders about 13.0 mi long and 6.50 mi in diameter be placed in space and used as colonies. What angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth?
The centripetal acceleration at the surface of the cylinder must rotate at an angular rate of about 0.139 radians/s to match the acceleration of free fall on Earth.
How can centripetal acceleration be used to calculate angular speed?Revolutions per minute are referred to as rev/min. Since r is known, we can get the centripetal acceleration using the second expression in the equation ac=v2r;ac=r2.
Finding the centripetal acceleration at the cylinder's surface is a good place to start. What determines the centripetal acceleration is:
a = v^2 / r
A centrifugal force equal to and opposing the centripetal force exists because the cylinder is rotating. The sources of the centrifugal force are:
Fc = m * a
Since we want the centripetal acceleration to match the acceleration of free fall on Earth, we can set:
a = 9.81 m/s^2
We also know that the cylinder's radius is equal to half its diameter, therefore, r = 6.50 mi / 2 = 3.25 mi
To utilise metric units for the acceleration, we must convert the cylinder's length and radius to metres:
r = 3.25 mi * 1609.34 m/mi = 5220.61 m
L = 13.0 mi * 1609.34 m/mi = 20921.4 m
We can now determine the linear velocity, v. When we rearrange the centripetal acceleration formula, we obtain: v = sqrt(a * r)
When we replace the values we discovered earlier, we obtain:
v = sqrt(9.81 m/s^2 * 5220.61 m) = 725.44 m/s
Using the equation w = v / r, we can finally determine the angular speed w of the cylinder.
When we replace the values we discovered earlier, we obtain:
w = 725.44 m/s / 5220.61 m = 0.139 radians/s
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When its 80 kW engine is generating full power, a small single-engine airplane with mass 700 kg gains altitude at a rate of 2.5 m/s.
What fraction of the engine power is being used to make the airplane climb? (The remainder is used to overcome the effects of air resistance and of inefficiencies in the propeller and engine.)
Express your answer as a percentage to two significant figures.
Around 21.49% of the engine power, or 21.5% rounded to two significant figures, is being used to propel the aircraft upward.
What is the work-energy theorem?There is always a change in the kinetic energy of an object when a net force acts on it. This happens as a result of the object experiencing an acceleration, which changes its velocity. As a result, we arrive at the work-energy theorem. The work-energy theorem is applicable to forces that are both constant and variable.
Power = (mass) x (gravity) x (vertical speed)
where the mass is 700 kg, gravity is 9.81 m/s², and the vertical speed is 2.5 m/s.
Power = (700 kg) x (9.81 m/s²) x (2.5 m/s)
Power = 17,192.5 W
To find the fraction of the engine power that is being used to make the airplane climb, we need to divide the power used for climbing by the total engine power, which is 80,000 W:
Fraction of engine power = (Power for climbing / Total engine power) x 100%
Fraction of engine power = (17,192.5 W / 80,000 W) x 100%
Fraction of engine power = 21.49%
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A 1.0 mL sample of seawater is determined to contain 2.5 × 10–14 moles of dissolved gold.
The setup below will determine how many grams of gold are in 1.0 L of seawater.
Two balls of equal mass are moving towards each other with equal velocities. If they collide in a totally elastic
collision, what will happen?
A They'll bounce off each other
B They'll stick together and move right.
C They'll stick together and move left.
13
Save
15 >
Sa
Answer:
A. They'll bounce off each other
Explanation:
Nothing sticks together in a totally elastic collision.
your answer with an example. A farmer moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 2 seconds from his initial position
pls answer this question
Explanation:
Question is poorly written, but I will assume he moves at speed of 10m/40 s= 1/4 m/s
2 min 2 s = 122 s
1/4 m/s * 122 s = 30.5 meters
this is three sides of the square + 1/2 meter of the 4th side
so he will be displaced 9 1/2 m form starting point
Farmer moves along the boundary in 40 seconds. As a result, the farmer will arrive at field point C after 3.5 rounds. Hence, after 2 minutes and 20 seconds, the farmer will have moved 14.14 metres north of where they were before.
How can you determine a square field's displacement?The square's perimeter is 40 metres (4 by 4 by 10). It is assumed that the farmer circles this square field once in 40 seconds. Because of this, the farmer covered 40m in 40 seconds. We are aware that speed is equal to distance times time.
What is the displace displacement formula?Displacement is defined as the final position minus the starting position.
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Mass
7. If the mass of the diver is 75 kg. What is the height he jumped
from?
Answer:
The height from which the diver jumped can be calculated using the laws of motion and the principle of conservation of energy.
Let's assume that the diver jumped from a platform with an initial velocity of zero. The potential energy (PE) of the diver at the top of the platform is given by:
PE = mgh
Where m is the mass of the diver, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the diver jumped.
When the diver jumps, the potential energy is converted into kinetic energy (KE) as the diver moves downwards. The kinetic energy of the diver just before hitting the water is given by:
KE = (1/2)mv^2
Where v is the velocity of the diver just before hitting the water.
According to the principle of conservation of energy, the potential energy at the top of the platform is equal to the kinetic energy just before hitting the water. Therefore, we can equate the two equations above and solve for h:
mgh = (1/2)mv^2
h = (1/2)v^2/g
We need to find the value of v to calculate h. We can use the kinematic equation:
v^2 = u^2 + 2as
Where u is the initial velocity (which is zero in this case), a is the acceleration due to gravity (9.8 m/s^2), and s is the distance travelled by the diver (which is equal to h).
Substituting the values, we get:
v^2 = 2gh
v^2 = 2 * 9.8 * h
v^2 = 19.6h
Therefore:
h = v^2/(19.6)
Now, let's assume that the velocity of the diver just before hitting the water was 10 m/s (a reasonable value for a diving competition). Then:
h = (10^2)/(2*9.8) = 51 meters
Therefore, the height from which the diver jumped is approximately 51 meters.
Rita raises a 10kg package to a height of 2.5 m in 2.0 s.
(a) How much work did she do on the package?
(b) How much power was expended on the package?
(c) It she were to raise the package in 1.0 s rather than 2.0 s, how do the work and power change?
Answer:
A) W =250J B) Power = 125 J/s C) Work = 250 J Power = 250 J/s
Explanation:
Work = Force*distance
A:
[tex]W = 10kg*10m/s^2*2.5m\\W = 250 J\\[/tex]
B:
Power is J/s
Power = 250J/2.0s = 125 J/s
C:
Work stays the same
Power increases to 250 J/s
A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 33.1 ◦C . In an attempt to cool the liquid, which has a mass of 185 g , 90.3 g of ice at 0.0 ◦C is added. At the time at which the temperature of the tea is 26.3 ◦C , find the mass of the remaining ice in the jar. The specific heat of water is 4186 J/kg · ◦ C . Assume the specific heat capacity of the tea to be that of pure liquid water. Answer in units of g.(2 significant digits pls)
According to the question the mass of remaining ice in the jar is 90.3 g.
What is mass?Mass is a fundamental physical property of matter that is measured in kilograms (kg). It is the amount of matter an object contains and is often used to measure the weight of an object. Mass is different from weight, which is a measure of the force of gravity acting on an object. Mass is the same no matter where it is located, while weight is different due to the varying gravitational forces in different locations. Mass is an inherent property of matter and is conserved, meaning it cannot be created or destroyed, it can only be changed from one form to another. Mass is an important concept in physics and is used in a variety of calculations.
The equation for heat transfer can be written as
Q = mcΔT
Where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
We can use this equation to solve for the remaining mass of ice:
Q = mcΔT
m = Q / (cΔT)
m = (185 x 4186 x (33.1-26.3)) / (4186 x (0 - 26.3))
m = 90.3 g
Therefore, the mass of remaining ice in the jar is 90.3 g.
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Consider a series RLC circuit where =855 Ω and =7.25 F.
However, the inductance of the inductor is unknown. To find its value, Anindya decides to perform some simple measurements. He applies an AC voltage that peaks at 84.0 V and observes that the resonance angular frequency occurs at 39700 rad/s. What is the inductance of the inductor in millihenrys?
The inductance of the inductor is calculated as to be approximately 32.8 mH.
What do you understand by the term inductance?Property of an electrical circuit that opposes any change in the flow of electric current is known as inductance .
As ω = 1/√(LC)
ω is resonance angular frequency, L is inductance, and C is capacitance.
Given ω = 39700 rad/s, R = 855 Ω, and C = 7.25 F.
ω = 1/√(LC) ; ω² = 1/LC
L = 1/(ω²C)
L = 1/((39700 )² * 7.25 F)
L ≈ 0.0328 H = 32.8 mH
Therefore, the inductance of the inductor is approximately 32.8 mH.
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count rate= State two of the social, economic or environmental issues involved in the storage of radioactive materials with very long half-lives.
The two social, economic, or environmental issues are Safety and security concerns and the Cost of storage and disposal.
What are two environmental and social issues?People all across the world are impacted by global environmental changes, such as pollution, climate change, biodiversity loss, and freshwater decrease, which have social and economic effects in addition to physical ones. The continuity of families and communities, social ties, health, and occasionally survival are all impacted by these changes.
Which 3 environmental issues are there?There are many environmental problems, but there are three main ones that influence most of them in general: the loss of biodiversity, water pollution, ocean acidification, and climate change.
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the force constant of spring is 100n/m neglecting friction what is the speed of a 50g attached to the spring with Masses through the equilibrium position after stretched by 4cm
Answer: 2.53 m/s
Explanation: The first step in solving this problem is to use Hooke's law to find the force exerted by the spring on the mass when it is stretched by 4 cm. Hooke's law states that the force exerted by a spring is proportional to the amount it is stretched or compressed. The formula for Hooke's law is:
F = -kx
where F is the force exerted by the spring, k is the force constant of the spring, and x is the amount the spring is stretched or compressed from its equilibrium position.
In this case, the force exerted by the spring can be found as follows:
F = -kx
F = -100 N/m * 0.04 m
F = -4 N
The negative sign indicates that the force is in the opposite direction to the displacement of the mass from its equilibrium position.
Next, we can use the work-energy principle to find the speed of the mass as it passes through its equilibrium position. The work-energy principle states that the work done on an object is equal to its change in kinetic energy. In this case, the work done on the mass is the work done by the spring, which is:
W = (1/2)kx^2
where W is the work done by the spring and x is the displacement of the mass from its equilibrium position.
The work done by the spring can be found as follows:
W = (1/2)kx^2
W = (1/2)(100 N/m)(0.04 m)^2
W = 0.008 J
This work done by the spring is equal to the change in kinetic energy of the mass, which is:
ΔK = (1/2)mv^2 - 0
where ΔK is the change in kinetic energy of the mass, m is the mass of the mass, and v is its speed.
We can solve for v as follows:
ΔK = (1/2)mv^2 - 0
ΔK = (1/2)mv^2
v^2 = 2ΔK/m
v = sqrt(2ΔK/m)
Substituting the values we have found, we get:
v = sqrt(2(0.008 J)/(0.05 kg))
v = sqrt(0.32 m^2/s^2 / 0.05 kg)
v = sqrt(6.4 m^2/s^2)
v = 2.53 m/s
Therefore, the speed of the mass when it passes through its equilibrium position is 2.53 m/s.
A swimmer runs horizontally off a diving board with a speed of 3.04 m/s and hits the water a horizontal distance of 1.68 m from the end of the board.
With a horizontal velocity of 3.04 m/s and a horizontal displacement of 1.68 m from the end of the diving board, the swimmer enters the water 1.70 metres below the diving board.
What is velocity, for instance?The rate at which something moves in a certain direction is referred to as its velocity. as quickly as a car travelling north on a highway or a rocket taking flight.
We can use the kinematic equations of motion to solve this issue.
Use the swimmer's horizontal travel distance as the displacement in the x-direction. Given that the swimmer enters the water 1.68 metres from the board's end, the following is the answer:
x=1.68 m and v0x=3.04 m/s
Δx = v0x * t
calculating t:
t = 1.68 m / 3.04 m/s because x / v0x.
t = 0.5526 s
Thus, the swimmer enters the water in 0.5526 seconds.
"y" equals "v0y*t" plus "(1/2)*a*t2"
replacing the values with:
Δy = 0 + (1/2) * (-9.81 m/s²) * (0.5526 s)²
Δy = -1.70 m
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object has a mass of 900 kg. If its momentum is 18,000 kg-m/s, then how fast is it moving?
20 m/s
B 0.05 m/s
18,900 m/s
16,200,000 m/s
Answer: 20m/s
Explanation:The momentum (p) of an object is given by the product of its mass (m) and velocity (v), i.e., p = mv. We can rearrange this equation to solve for velocity (v), which gives v = p/m.
Substituting the given values, we have:
v = p/m = 18,000 kg-m/s / 900 kg = 20 m/s
Therefore, the object is moving at a speed of 20 meters per second.
Which body part is included in the circulatory system?
A.
nose
B.
blood vessels
C.
diaphragm
D.
trachea
Answer:
B. blood vessels.
The circulatory system is made up of the heart, blood vessels, and blood. Its main function is to transport oxygen and nutrients to the body's tissues and organs, while also removing waste products.
The nose and trachea are part of the respiratory system, which is responsible for breathing and gas exchange. The diaphragm is a muscle that helps with breathing, but it is not part of the circulatory or respiratory system.
Blood vessels, on the other hand, are a key component of the circulatory system. They include arteries, veins, and capillaries, which transport blood throughout the body.
Answer:
Explanation:
B . blood vessels
If a wave has a frequency of 20 Hz, and you watch it for 5 seconds, how many wave pulses would you observe?
A frequency of 20 Hz means that a wave pulse passes a certain point every 0.05 seconds. Therefore, over the course of 5 seconds, you would observe 100 wave pulses.
What is frequency?Frequency is a measure of how often something occurs in a given period of time. It is typically expressed as the number of occurrences per unit of time, such as hertz (Hz) for sound and cycles per second (cps) for electrical signals. Frequency is an important parameter in many fields, including physics, engineering, and communications. Frequency can also be used to describe the rate of change in a system, such as in a wave or oscillation. Frequency is inversely proportional to the period, which is the time it takes for a single cycle to complete.
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sound waves, light waves, UV waves, IR waves. We use these waves all of the time to listen to the radio, use Bluetooth in our cars, make phone calls, etc.
In a well-organized structure, write a 3-5 paragraph length essay discussing the physics of waves and how they play a major role in your daily life. Be sure to discuss their properties as well: transverse/longitudinal, frequencies, amplitudes, etc.
Waves are an essential part of the physical world, and they play a crucial role in our daily lives. Waves can be broadly categorized into two types: mechanical waves and electromagnetic waves. Mechanical waves require a medium to travel, such as sound waves, while electromagnetic waves do not need a medium and can travel through space, such as light waves. Both types of waves exhibit unique properties, including amplitude, frequency, wavelength, and speed.
Sound waves are mechanical waves that require a medium to travel, such as air or water. These waves are longitudinal, meaning they move in the same direction as the wave. They have properties such as amplitude, which is the magnitude of the wave, and frequency, which is the number of waves that pass through a point in a given amount of time. Sound waves have a wide range of frequencies, from low-frequency waves, such as the sound of a bass guitar, to high-frequency waves, such as a dog whistle.
Electromagnetic waves, on the other hand, do not require a medium to travel and can travel through a vacuum, such as space. These waves are transverse, meaning they move perpendicular to the wave. They also have properties such as frequency and amplitude. Electromagnetic waves have a wide range of frequencies, from radio waves used to transmit music to gamma rays used to treat cancer.
In our daily lives, waves play a significant role. For example, we use radio waves to listen to the radio, watch television, and make phone calls. We use microwaves to heat food quickly, and we use infrared waves to sense heat and motion in security systems. We also use visible light waves to see the world around us, and ultraviolet waves to help our bodies produce vitamin D.
In conclusion, waves are a fundamental aspect of the physical world and play a significant role in our daily lives. Whether it's listening to the radio, using Bluetooth in our cars, or making phone calls, waves are involved in almost everything we do. Understanding the properties of waves, including frequency, amplitude, and wavelength, is crucial in understanding how waves function and how they affect our daily lives.
A 2000kg vehicle travelling 30m/s takes 10s to stop. what force did the vehicle experience? show your work.
Explanation:
The WORK required to stop the truck is equal to the initial Kinetic Energy of the truck ( 1/2 m v^2)
1/2 mv^2 = 1/2 * 2000 * 30^2 = 900 000 J
Distance travelled in 10 seconds is
d = vot - 1/2 at^2 where a = 30 m/s / 10 s = 3 m/s^2
= 30 (10) - 1/2 ( 3)(10^2) = 150 meters
Work = F * d
900 000 = F * 150
F = 6000 N
Patricia is in a waiting room at her physicians office. She’s anxiously clicking a pen as she waits. She suddenly realizes it’s probably a bit annoying to everyone else who is also waiting.
Self-management entails utilising what you know about your emotions to regulate them so that you may have pleasant connections with others and motivate yourself in all situations.
What distinguishes a high level of emotional intelligence?Those with a high EQ are acutely aware of their own emotions as well as the emotions of those around them. They can recognise and comprehend the varied sentiments that wash over them and control them correctly.
The capacity to properly observe the emotions of people and "read" circumstances effectively is referred to as social awareness. It is about perceiving what other people are thinking and feeling in order to take their point of view utilising your empathy.
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a cylindrical solid object of mass 400g and radius of 20cm is rolling down as inclined plane at speed of 3m/s. calculate the kinetic energy of the given object.
Answer:2.7 joules
Explanation:
Rolling Cylinder Kinetic Energy.
A cylindrical solid object of mass 400g and radius of 20cm is rolling down as inclined plane at speed of 3m/s. calculate the kinetic energy of the given object.
To calculate the kinetic energy of a rolling cylinder, we need to use the formula for rotational kinetic energy, which is:
K_rotational = (1/2) * I * ω^2
where I is the moment of inertia and ω is the angular velocity.
For a cylinder rolling without slipping down an inclined plane, the total kinetic energy is the sum of translational kinetic energy and rotational kinetic energy, which is:
K_total = K_translational + K_rotational
where K_translational is given by:
K_translational = (1/2) * m * v^2
where m is the mass of the cylinder, and v is its linear velocity.
First, let's find the moment of inertia of the cylinder. For a solid cylinder, the moment of inertia is given by:
I = (1/2) * m * r^2
where r is the radius of the cylinder. Substituting the given values, we get:
I = (1/2) * 0.4 kg * (0.2 m)^2 = 0.008 kg·m^2
Next, let's find the linear velocity of the cylinder. The speed of the cylinder is given as 3 m/s, so the linear velocity is:
v = 3 m/s
Now we can calculate the translational kinetic energy:
K_translational = (1/2) * m * v^2 = (1/2) * 0.4 kg * (3 m/s)^2 = 0.9 J
Finally, we can calculate the rotational kinetic energy:
K_rotational = (1/2) * I * ω^2
Since the cylinder is rolling without slipping, the linear velocity is related to the angular velocity as:
v = ω * r
Rearranging this equation, we get:
ω = v / r = 3 m/s / 0.2 m = 15 rad/s
Substituting the values, we get:
K_rotational = (1/2) * 0.008 kg·m^2 * (15 rad/s)^2 = 1.8 J
Therefore, the total kinetic energy of the cylinder is:
K_total = K_translational + K_rotational = 0.9 J + 1.8 J = 2.7 J
Therefore, the kinetic energy of the given object is 2.7 Joules.
What is the momentum of an object with a mass of 750 kg and a velocity of 15 m/s?
A 50 kg-m/s
B
0.02 kg-m/s
C
765 kg-m/s
D 11,250 kg.m/s
Answer:D
The momentum of an object is defined as the product of its mass and velocity. So, to calculate the momentum of an object with a mass of 750 kg and a velocity of 15 m/s, we can use the following formula:
Momentum = mass x velocity
Momentum = 750 kg x 15 m/s
Momentum = 11,250 kg m/s
Therefore, the momentum of the object is 11,250 kg m/s.
Calculate the value of two equal charges if they repel one another with a force of 1kgf when separated by a distance of 1cm in air. Now if the charges are situated in an insulating liquid having permittivity 8 times that of air then what would be the magnitude of the charges if they exert the same force on each other.
Answer:
Explanation:
First, let's convert the force to SI units, since we'll need to use them in our calculation:
1 kgf = 9.81 N
The force between the charges is given by Coulomb's law:
F = k * q^2 / r^2
where F is the force, q is the charge, r is the distance between the charges, and k is Coulomb's constant:
k = 1 / (4πε0) = 8.99 x 10^9 N·m^2/C^2
where ε0 is the permittivity of free space.
We can use the given force and distance to solve for the value of q:
9.81 N = 8.99 x 10^9 N·m^2/C^2 * q^2 / (0.01 m)^2
Solving for q, we get:
q = ± 3.0 x 10^-6 C
The charges must have the same magnitude, so we take the positive value:
q = 3.0 x 10^-6 C
Now, if the charges are placed in a liquid with permittivity ε = 8ε0, the force between them will be:
F' = k * q^2 / (ε * r^2)
We want this force to be the same as before, so we can set it equal to 9.81 N and solve for q:
9.81 N = 8.99 x 10^9 N·m^2/C^2 * q^2 / (8ε0 * 0.01 m)^2
Solving for q, we get:
q = ± 6.0 x 10^-6 C
Again, we take the positive value since the charges have the same magnitude:
q = 6.0 x 10^-6 C
So the magnitude of the charges in the liquid is twice that in air.
Find the tension in each of the two ropes supporting a hammock if one is at an angle of θ1= 16 degrees above the horizontal and the other is at an angle of θ2= 38 degrees above the horizontal. The person sleeping in the hammock (unconcerned about tensions and ropes) has a mass of 70 kg
T1=
T2=
The rope is under about 411.8 N of stress at point 1, and around 532.6 N of tension at point 2.
Calculation-/|
/ |
T1 / | θ1
/ |
/ θ1|
/ |
/_____|
\ |
\ | θ2
\ |
T2 \ |
\ |
\|
The forces in the x and y axes must balance since the hammock is at rest. Consequently, we may write:
ΣF_x = T1 cosθ1 - T2 cosθ2 = 0
ΣF_y = T1 sinθ1 + T2 sinθ2 - mg = 0
Let's change the equations such that we can solve for T1 and T2:
T1 = T2 cosθ2 / cosθ1
T2 = (m g) / (sinθ2 - sinθ1)
T1 = T2 cos(38°) / cos(16°) = 0.773 T2
T2 = (70 kg)(9.81 m/s^2) / (sin 38° - sin 16°) = 532.6 N
Therefore, we can find T1:
T1 = 0.773 T2 = 0.773(532.6 N) = 411.8 N
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a particle describes a circular path of radius 0.45m at the rate of 1200rev/min. Determine its acceleration?
The acceleration of the particle is 6.42 x 10⁵m/min², directed toward the center of the circular path.
To determine the acceleration of the particle moving in a circular path of radius 0.45m at a rate of 1200 rev/min, we can use the formula for centripetal acceleration:
a = (v²) / r
where v is the linear velocity of the particle and r is the radius of the circular path.
First, we need to convert the rate of 1200 rev/min to the linear velocity of the particle. One revolution corresponds to the circumference of the circle, which is given by:
C = 2πr
So, the linear velocity of the particle is:
v = (1200 rev/min) x (2πr) = (1200 rev/min) x (2π x 0.45m) = 1696.4 m/min
Next, we can substitute the values of v and r into the formula for centripetal acceleration:
a = (1696.4 m/min)² / 0.45m = 6.42 x 10⁵ m/min²
Therefore, the acceleration of the particle is 6.42 x 10⁵ m/min², directed toward the center of the circular path.
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A 21 g block of ice is cooled to −77 ◦C. It is added to 593 g of water in an 92 g copper calorimeter at a temperature of 28◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg · ◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C. ( 2 significant digits pls)
T = 16.7 Degree C
Ice at −20∘C is added to 50g of water at 40∘C . When the temperature of the mixture reaches 0∘C , it is found that 20g of ice is still unmelted. The amount of ice added to the water was close to (specific heat of water 4.2J/g/∘C ) Specific heat of Ice 2.1J/g/∘C Heat of fusion of water at 0∘C=334J/g.
A reducing agent ____
accepts electrons
donates electrons
is reduced
neutralizes
Answer:
A reducing agent accepts electrons
Find the magnetic field a distance r from the center of a long wire that has radius a and carries a uniform current per unit area j in the positive z direction.
First find the magnetic field outside the wire (i.e., when the distance r is greater than a).
Now find the magnetic field inside the wire (i.e., when the distance r is less than a).
Answer: See attached image.
(a) Find the frequency ratio between the two frequencies f1 = 320 Hz and
½2 = 576 Hz.
S) If we go down from / by an interval of a fourth, find the frequency ratio filfi.
(c) Find the frequency of f3.
The frequency ratio between two frequencies f1 and f2 is given by:
frequency ratio = f2 / f1
Substituting the given values, we get:
frequency ratio = 576 Hz / 320 Hz = 1.8
Therefore, the frequency ratio between the two frequencies f1 = 320 Hz and f2 = 576 Hz is 1.8.
What is the frequency of f3?(b) If we go down from f1 by an interval of a fourth, we get a frequency that is 5 semitones lower. The frequency ratio for a single semitone is given by:
2^(1/12) ≈ 1.05946
Going down by 5 semitones, we get a frequency ratio of:
1 / (2^(5/12)) ≈ 0.84090
Therefore, the frequency ratio between f1 and the frequency that is a fourth below it is approximately 0.84090.
(c) To find the frequency of f3, we need to know the interval between f1 and f3. Let's assume that f3 is a fifth above f2. The frequency ratio for a fifth is given by:
2^(7/12) ≈ 1.49831
Therefore, the frequency of f3 is:
f3 = f1 * (2^(7/12)) * (2^(7/12)) = 320 Hz * 1.49831 * 1.49831 ≈ 716 Hz
Therefore, the frequency of f3 is approximately 716 Hz.
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Why is it a bad idea to drink hot cocoa out of a tin cup? Explain the energy transfers on the atomic level.
It is not a good idea to drink hot cocoa out of a tin cup since metal is a good conductor of heat and the hot cocoa's high temperature will cause the metal cup to quickly transfer heat to your hand and mouth, perhaps resulting in burns or pain.
What is the name for the energy that is transferred when hot cocoa is put into a cold mug?When particles of warmer matter collide with particles of cooler matter, some of the thermal energy from the warmer particles is transferred to the cooler particles. Certain solids and liquids typically conduct electricity more quickly than gases do.
How does sipping a cup of hot chocolate transmit heat?Conduction is the mechanism by which the hot chocolate transmits heat to the mug. As the molecules of the hot chocolate clash with those of the mug, energy is transferred to both of them as well as to the surrounding air.
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Draw a free body diagram showing all forces acting on the air cart, including the extra
force that may be causing a discrepancy between your numbers.
A free body diagram is a visual representation of all the forces acting on an object.
What is a free body diagram?A free body diagram is a visual representation of all the forces acting on an object. It is a tool commonly used in physics to help analyze the motion of an object.
What are the forces acting?In the case of an air cart, the forces acting on the cart might include the force of gravity pulling the cart downward, the normal force of the surface supporting the cart pushing upward, and the force of air resistance acting against the cart as it moves through the air. There may also be other forces at play, depending on the specific situation, such as an applied force from a fan or a motor driving the cart forward.
If there is an extra force causing a discrepancy between your numbers, you would also include this force on the free body diagram, with an arrow representing the magnitude and direction of the force
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2. A) How much torque of is exerted on the pivot point P by a 51.2 N force F exerted a rod that is 33.3 cm in length.
B) How much torque of is exerted on the pivot point P if the 51.2 N force is applied at an angle of 56.3 degrees above the radial line?
A) Torque exerted on the pivot point P by force F is: 17.02 Nm B) torque exerted on the pivot point P by force F at an angle of 56.3 degrees above the radial line is: 13.83 Nm.
What is torque?Torque is a measure of the rotational force on any object around an axis or pivot point.
A) Torque = Force x Lever arm
Given force F is 51.2 N and the lever arm is 33.3 cm.
Lever arm = 33.3 cm = 0.333 m
Therefore, torque exerted on the pivot point P by the force F is:
Torque = 51.2 N x 0.333 m = 17.02 Nm
B) If the force F is applied at an angle of 56.3 degrees above the radial line, Perpendicular force = Force x sin(angle)
Perpendicular force = 51.2 N x sin(56.3°) = 41.48 N
The lever arm is still 0.333 m. Therefore, torque exerted on the pivot point P by force F at an angle of 56.3 degrees above the radial line is:
Torque = Perpendicular force x Lever arm = 41.48 N x 0.333 m = 13.83 Nm.
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