The average high temperatures in degrees for a city are listed.

58, 61, 71, 77, 91, 100, 105, 102, 95, 82, 66, 57

If a value of 101° is added to the data, how does the mean change?
The mean decreases by 1.6°.
The mean increases by 1.6°.
The mean decreases by 8.4°.
The mean increases by 8.4°.

When a=6, the value of b is equals to -43.

What is Algebraic expression ?

Algebraic expression can be defined as combination of variables and constants.

An algebraic expression is a combination of variables, constants, and mathematical operations such as addition, subtraction, multiplication, and division, which can be simplified and evaluated.

In other words, an algebraic expression is a collection of terms and coefficients that are connected by mathematical operators.

Substitute the value of a=6 into the expression for b:

b = -1 - 7a

b = -1 - 7(6)

b = -1 - 42

b = -43

Therefore, when a=6, the value of b is -43.

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Minimum - 2

First Quartile - 4

Median - 8

Third Quartile - 13

Maximum - 15

Other fractions could represent the part of the beads on the bracelet that will be green are : 1/3, 2/6, 3/9, 4/12.

A fraction represents a part of a whole or, more generally, any number of equal parts. When spoken in everyday English, a fraction describes how many parts of a certain size there are, for example, one-half, eight-fifths, three-quarters.

here, we have,

The maximum number of beads the bracelet can have  = 12 beads

The fraction of green beads in the bracelet = 1/3

⇒ 1 bead in every 3 bead is GREEN.

⇒The minimum number of total beads = Number of (green+ Other) bead                                                           = 2 + 1  = 3

Now, the possible number of total beads the bracelet can have is

3, 4, 5 , 6, 7, 8, 9 ,10, 11 and 12.

If there are total 3 beads, the fraction representing the green bead  = 1/3

If there are total 6( =3 +3) beads, the fraction representing the green bead  

= 1 green bead in first 3 beads +  1  green bead in next 3 beads

=   2 green beads in total 6 beads

=   2/6

If there are total 9( = 3 +3 +3) beads, the fraction representing the green bead  = 3/9

If there are total 12( = 3 +  3 +3 +3) beads, the fraction representing the green bead  = 4/12

Hence, other fractions could represent the part of the beads on the bracelet that will be green are :1/3, 2/6, 3/9, 4/12.

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Answer:

he walks 300 meters

Step-by-step explanation:

nbsjdjsj d f f f f f f f. f f f f f f f f f f

The length of the top of the workbench is 13m and the width is 7m.

To find the length and the width, we can use the formula for the area of a rectangle, which is A = L x W, where A is the area, L is the length, and W is the width. We can plug in the given values and solve for the unknowns.

Let's start by assigning variables to the length and the width. Let's call the width x and the length x + 6 (since the length is 6m greater than the width).

Now we can plug these values into the formula:

A = L x W

91 = (x + 6) x x

91 = x2 + 6x

Now we can rearrange the equation to solve for x:

x2 + 6x - 91 = 0

We can use the quadratic formula to solve for x:

x = (-6 ± √(62 - 4(1)(-91))) / (2(1))

x = (-6 ± √(36 + 364)) / 2

x = (-6 ± √400) / 2

x = (-6 ± 20) / 2

The two possible solutions are:

x = (-6 + 20) / 2 = 7

x = (-6 - 20) / 2 = -13

Since the width cannot be negative, the only valid solution is x = 7. This means that the width is 7m and the length is x + 6 = 7 + 6 = 13m.

So the length of the top of the workbench is 13m and the width is 7m.

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Larry will need an annual rate of return of approximately 1.35% (rounded to two decimal places) to reach his goal of $3,500 in 20 years, if interest is compounded continuously.

The formula for continuous compounding is [tex]A = Pe^{rt}[/tex], where A is the amount of money at the end of the investment period, P is the initial principal, e is Euler's number (approximately 2.71828), r is the annual interest rate, and t is the time in years.

In this case, Larry has P = $3,000 and needs A = $3,500 in t = 20 years. We can solve for r by rearranging the formula:

[tex]r = ln(A/P)/(t)[/tex]

Plugging in the values, we get:

[tex]r = ln(3500/3000)/(20) = 0.0135[/tex] or 1.35%

Therefore, Larry will need an annual rate of return of approximately 1.35% (rounded to two decimal places) to reach his goal of $3,500 in 20 years, if interest is compounded continuously.

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The equation which represents the total length of the siding is given by A , where A = 50 x 4 = 200 meters

Equations are statements in mathematics that have two algebraic expressions on either side of the equals (=) sign.

It displays the similarity of the connections between the phrases on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are examples of the parts of an equation. When creating an equation, the "=" symbol and terms on both sides are necessary.

Given data ,

Let the total length of the siding be represented as A

Now , the value of A is

Let the number of pieces be n = 48 pieces

Let the length of each piece be l = 3.7 meters

Now , total length of the siding A = number of pieces x length of each piece

On simplifying the equations , we get

The total length of siding A = 48 x 3.7 = 177.6 meters

Now , n ≈ 50 pieces

l ≈ 4 meters

So , total length of siding A = 50 x 4 = 200 meters

Hence , the equation is A = 50 x 4 = 200 meters

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The solution to the given proportion is 7 / 8. The solution has been obtained by using the cross multiplication method.

The cross multiplication approach involves multiplying the denominator of the first phrase by the numerator of the second fraction, and vice versa.

We are given a proportion as

2 / (3b - 3) = 4 / (1 - 2b)

Now, by using cross multiplication method, we get

⇒2 (1 - 2b) = 4 (3b - 3)

⇒2 - 4b = 12b - 12

⇒-16b = -14

⇒16b = 14

⇒b = 14 / 16

⇒b = 7 / 8

Hence, the solution to the given proportion is 7 / 8.

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A store scanner has a red laser wavelength of 650 nm. While a green laser pointer has a wavelength of 502 μm. The ratio of green to red wavelengths is 0.77.

To find this ratio, we need to divide the wavelength of the green laser by the wavelength of the red laser:

502 μm / 650 nm = 0.77

Note that we need to convert the units of the green laser wavelength from micrometers (μm) to nanometers (nm) in order to divide it by the red laser wavelength, which is already in nanometers. To do this, we multiply the green laser wavelength by 1000:

502 μm * 1000 = 502000 nm

So the ratio of green to red wavelengths is 502000 nm / 650 nm = 0.77.

This ratio indicates that the green laser has a shorter wavelength than the red laser. Generally, shorter wavelengths correspond to higher energy and higher frequency light. In the case of lasers, this means that the green laser is capable of producing a more intense and focused beam of light than the red laser.

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a. The expected number of applications rejected is 3  

b. The probability that among the next 15 applications, none will be rejected is 0.042

c. The probability that among the next ten applications, seven will be rejected is 0.48

d. The probability that among the next ten applications, between 1 and 8 applications is 0.95

The binomial distribution formula is used to calculate the probability of getting a certain number of successes (x) in a fixed number of independent trials (n) with a known probability of success (p) for each trial. The formula is:

Here we have

30% of the applications received for a position in a graduate school are rejected.

a) The number of rejected applications among the next 10 applications follows a binomial distribution with parameters n = 10 and p = 0.3.

The expected number of rejected applications is:

E(X) = np = 10 * 0.3 = 3

Hence, the expected number of applications rejected is 3

b) The probability of being rejected is 0.3

The probability that none of the next 15 applications will be rejected is:

P(X = 0) = (1 - p)ⁿ = (1 - 0.3)¹⁵= 0.042

Therefore, the probability that none of the next 15 applications will be rejected is 0.042 or approximately 4.2%.

c) The probability that 7 of the next ten applications will be rejected is:

By using the binomial distribution formula

P(X = 7) = (10, 7) × 0.3⁷ × 0.7³ =  

=  6435 × 0.0002187 × 0.343 = 0.48

Therefore, the probability that 7 of the next 10 applications will be rejected is 0.48 or approximately 48%.

d) The probability that between 1 and 8 (inclusive) of the next ten applications will be rejected is:

P(1 ≤ X ≤ 8) = P(X ≤ 8) - P(X ≤ 0) = Σ P(X = i) for i = 1 to 8

We can use the complement rule and calculate the probability of having 0 or 9 rejected applications, and subtract that from 1:

=> P(1 ≤ X ≤ 8) = 1 - [P(X = 0) + P(X = 9) + P(X = 10)]

= 1 - [(1 - p)ⁿ + (n, 1) × p¹ × (1 - p)⁽ⁿ⁻¹⁾ + (n, 0) × p⁰ × (1 - p)ⁿ]

= 1 - [(0.7)¹⁰ + ((10,1) × 0.3 × 0.7⁹) + (10, 0) (0.3)¹⁰]

= 1 - [ 0.02824 + 0.01210 + 0.000006]

= 1 - [ 0.040346]

= 0.95

Hence, The probability that between 1 and 8 (inclusive) of the next ten applications will be rejected is 0.95 or approximately 95%  

Therefore,

a. The expected number of applications rejected is 3  

b. The probability that among the next 15 applications, none will be rejected is 0.042

c. The probability that among the next ten applications, seven will be rejected is 0.48

d. The probability that among the next ten applications, between 1 and 8 applications is 0.95

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Answer:

The two points given are (-2, -8) and (8, -8), which lie on a horizontal line. Since the line is horizontal, the slope is zero.

To see this, we can use the formula for the slope of a line between two points:

slope = (y2 - y1)/(x2 - x1)

Substituting the coordinates of the two given points, we get:

slope = (-8 - (-8))/(8 - (-2)) = 0

Therefore, the slope of the line through the points (-2, -8) and (8, -8) is 0.

Step-by-step explanation:

Answer:  d = √(Δy2 + Δx2) = √(02 + 102) = √100 = 10

Step-by-step explanation:

The exact values of the trigonometric functions are

To find the exact value of the trigonometric functions, we will use the reference angle and the quadrant in which the terminal side of each angle is located.

For cos 17π/6, the reference angle is π/6 and the terminal side is in the fourth quadrant. The point on the unit circle in this quadrant with a reference angle of π/6 is (√3/2, -1/2). Therefore, the exact value of cos 17π/6 is √3/2.

For sin 20π/3, the reference angle is π/3 and the terminal side is in the first quadrant. The point on the unit circle in this quadrant with a reference angle of π/3 is (1/2, √3/2). Therefore, the exact value of sin 20π/3 is √3/2.

For tan 15π/4, the reference angle is π/4 and the terminal side is in the third quadrant. The point on the unit circle in this quadrant with a reference angle of π/4 is (-√2/2, -√2/2). Therefore, the exact value of tan 15π/4 is 1.

In summary, the exact values of the trigonometric functions are:
cos 17π/6 = √3/2
sin 20π/3 = √3/2
tan 15π/4 = 1

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Answer: ur mom anyways jk

Step-by-step explanation:

6hrs and 7mins pls dont trust me on this answer and if u get it wrong im  sorry

The answer of -x+3y=20; 7y=x will be x = -[tex]\frac{7}{2\\}[/tex] and y = - [tex]\frac{1}{2}[/tex].

Given,

-x+3y=20 .... (1)

7y=x .... (2)

By using the method of substitution.

We will use equation (2) as

7y=x

=>y= [tex]\frac{x}{7}[/tex] ....(3)

Putting equation (3) in (1)

We have, -x+3([tex]\frac{x}{7}[/tex])=20

Taking L.CM.

[tex]\frac{-7x+3x}{7}[/tex] = 20

-7x +3x = 140

-4x = 140

0r, x = - [tex]\frac{140}{4}[/tex]

x = - [tex]\frac{7}{2}[/tex]

Now by putting value of x in equation (2),  we get

7y = x

7y = -[tex]\frac{7}{2}[/tex]

0r, y = -[tex]\frac{1}{2}[/tex]

Thus, x = -[tex]\frac{7}{2\\}[/tex] and y = - [tex]\frac{1}{2}[/tex]

This means that there exists an element a of the ideal I, such that all other elements in the ideal can be written as a multiple of a. In other words, the ideal I can be written as I = (a) = {ar : r ∈ I}, where r is any element of the ideal I.

A principle ideal is an ideal that is generated by a single element. This means that there exists an element a of the ideal I, such that all other elements in the ideal can be written as a multiple of a. In other words, the ideal I can be written as I = (a) = {ar : r ∈ I}, where r is any element of the ideal I. This is an important concept in the study of rings and algebraic structures, as it allows us to understand how ideals are generated and how they relate to other ideals in the same ring.

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The value of (x-y)² is m^2-4n.

To find the value of (x-y)², we can use the formula for the difference of squares:
(x-y)² = (x+y)² - 4xy

We are given that x+y = m and xy = n, so we can substitute these values into the formula:
(x-y)² = m² - 4n

Therefore, the value of (x-y)² is m²-4n.

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The linear functions of the scenario are y = 12x and y = 24/2x

From the question, we have the following parameters that can be used in our computation:

(1, 12) and (2,24)

From the question, we understand that the function is a linear function

A linear function is represented as

y = mx + c

Using the above as a guide, we have the following equations

m + c = 12

2m + c = 24

Subtract the equations

m = 12

Substitute 12 for m in m + c = 12

12 + c = 12

Evaluate

c =0

So, the equation is y = 12x

An equivalent equation is y = 24x/2

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The solution of the exponential equation is x = 0.35

An exponential equation is an equation that contains exponents.

Since we have the exponential equation

4ˣ = 8ˣ - 1

We proceed to solve as follows

4ˣ = 8ˣ - 1

(2²)ˣ = (2⁴)ˣ - 1

(2ˣ)² = (2ˣ)⁴ - 1

Let 2ˣ = y

So, we have that

y² = y⁴ - 1

Re- arranging, we have that

y⁴ - y² - 1 = 0

Also, let y² = p. So, we have that

p² - p - 1 = 0

Now, we find p using the quadratic formula.

[tex]p = \frac{-b +/-\sqrt{b^{2} - 4ac} }{2a}[/tex]

where a = 1 b = -1 and c = -1

So, [tex]p = \frac{-(-1) +/-\sqrt{(-1)^{2} - 4(1)(-1)} }{2(1)}\\= \frac{1 +/-\sqrt{1 + 4} }{2}\\= \frac{1 +/-\sqrt{5} }{2}\\p = \frac{1 + 2.24 }{2} or p = \frac{1 - 2.24 }{2}\\p = \frac{3.24 }{2} or p = \frac{-1.24 }{2}\\p = 1.62 or p = -0.62[/tex]

We ignore the negative value.

So, p = 1.62

y² = 1.62

y = ±√1.62

y = ±1.273

Since y = 2ˣ, we have that

2ˣ = ±1.273

We ignore the negative value since the value of y cannot be negative.

So, 2ˣ = 1.273

Taking natural logarithm of both sides, we have that

㏑2ˣ = ㏑1.273

x㏑2 = ㏑1.273

x = ㏑1.273/㏑2

= 0.2412/0.693

= 0.348

≅ 0.35

So, x = 0.35

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The equation of the parabola can be written as

y=-0.16(x+2.0)(x-4.6)

A parabola is a curve made from the conic section whose eccentricity is 1 and is defined by the linear equation,

y=a(x-h)²+k, where a is an arbitrary constant and (h,k) denotes the vertex of the parabola.

According to the Intercept form of a parabola, if two x-intercepts (h1, 0), (h2, 0) are given, then the equation of parabola can be written as,

y=a(x+h1)(x-h2)

In this question,

h1 = 2.0

h2 = 4.6

So, the equation of the parabola would be,

y=a(x+2.0)(x-4.6)

Now, to find the value of the arbitrary constant "a", we can plug the point (0, 1.5) in this equation,

1.5 = a(0+2.0)(0-4.6)

1.5 =  a(-9.2)

a = -0.16

So, the equation of the parabola can be written as,

y=-0.16(x+2.0)(x-4.6)

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Both products finish at the same time, which is D) 42 hours later.

The factory produces Product A every 6 hours and Product B every 21 hours.

If they started at the same time, they will finish at the same time after the lowest common multiple of the two intervals, which is 42 hours.

Therefore, the answer is D. 42 hours.

LCM is the short form for “Least Common Multiple.” The least common multiple is defined as the smallest multiple that two or more numbers have in common.

For example: Take two integers, 2 and 3.

Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20….

Multiples of 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30 ….

6, 12, and 18 are common multiples of 2 and 3. The number 6 is the smallest. Therefore, 6 is the least common multiple of 2 and 3.

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The standard form of the equation of a quadratic function with roots of 4 and −1 that passes through (1, −9) is [tex]y = 1.5x^{2} - 4.5x - 6[/tex]

What is the quadratic function?

A quadratic function is a type of function that can be written in the form:

[tex]f(x) = ax^2 + bx + c[/tex]

where a, b, and c are constants, and x is the variable. This function is a second-degree polynomial function, which means that the highest power of the variable x is 2.

Quadratic functions can be graphed as a U-shaped curve called a parabola. The sign of the coefficient a determines whether the parabola opens up or down. If a > 0, the parabola opens up, and if a < 0, the parabola opens down. The vertex of the parabola is the minimum or maximum point of the function, depending on whether the parabola opens up or down.

Quadratic functions are used in many areas of mathematics, science, and engineering to model various phenomena such as projectile motion, population growth, and optimization problems.

To write the standard form of the equation of a quadratic function, we need to use the roots of the function and another point on the curve. The standard form of the quadratic function is:

y = a(x - r1)(x - r2)

where r1 and r2 are the roots of the quadratic function, and a is a constant.

Given that the roots of the quadratic function are 4 and -1, we can write:

y = a(x - 4)(x + 1)

To find the value of a, we can use the point (1, -9) that the function passes through:

-9 = a(1 - 4)(1 + 1)

-9 = -6a

a = 3/2

Substituting this value of a in the equation, we get:

[tex]y = 1.5(x - 4)(x + 1)[/tex]

Expanding this equation, we get:

[tex]y = 1.5x^{2} - 4.5x - 6[/tex]

Therefore, the standard form of the equation of the quadratic function with roots of 4 and −1 that passes through (1, −9) is [tex]y = 1.5x^{2} - 4.5x - 6[/tex]

So, the correct answer is: [tex]y = 1.5x^{2} - 4.5x - 6[/tex]

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Both the limits are equal to -1, which means the function is continuous at x=1. Therefore, there is no discontinuity at x=1. So, The function is continuous at x=1.

To determine if the function is continuous at x=1, we need to evaluate the left and right limits of the function at x=1 and see if they are equal.

Left limit as x approaches 1:

\lim_{x\to 1^-}\frac{2x^2-5x+3}{x-1} = \frac{2(1)^2-5(1)+3}{1-1} = \frac{0}{0}

Right limit as x approaches 1:

\lim_{x\to 1^+}\frac{2x^2-5x+3}{x-1} = \frac{2(1)^2-5(1)+3}{1-1} = \frac{0}{0}

Since both limits are indeterminate forms of 0/0, we can use L'Hopital's Rule to evaluate them.

Taking the derivative of the numerator and denominator of the original function, we get:

\lim_{x\to 1^-}\frac{4x-5}{1} = -1

\lim_{x\to 1^+}\frac{4x-5}{1} = -1

Both limits are equal to -1, which means the function is continuous at x=1. Therefore, there is no discontinuity at x=1.

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Answer:

80%

Step-by-step explanation:

96.3 - 53.5 = 42.8

42.8 / 53.5 = 0.8

0.8 × 100 = 80%

The given indicates that the decimal of growth or decay is 0.69 for this problem. Decimal of growth or decay can be determined using the formula A = P(1+r)ⁿ.

Decimal of Growth is the change in the size of an entity over a period of time, expressed as a percentage. It is a measure of the rate at which something grows or shrinks.

Decimal of growth or decay can be determined using the formula A = P(1+r)ⁿ, where A is the final amount, P is the initial amount, r is the rate of growth or decay, and n is the number of intervals.

In this case, A=7,545, P=7,545, r=0.96, and n=5. Plugging these values into the formula, we get 7,545=(7,545)(1+0.96)⁵.

Using a calculator, we can determine that (1+0.96)⁵=0.69, resulting in A=7,545(0.69)=5,203. This indicates that the decimal of growth or decay is 0.69 for this problem.

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[tex](x^{3/2} )^{6/5}[/tex]

= [tex]x^{9/5}[/tex]

The value of a after solving through exponents = 9/5

The way of representing huge numbers in terms of powers is known as an exponent. The number of times a number has been multiplied by itself is the exponent, so to speak.

For instance, the result of multiplying the number 6 by itself four times is:

6 × 6 × 6 × 6. You can write this as

Now here,

[tex](x^{3/2} )^{6/5}[/tex]

= [tex]x^{9/5}[/tex]

Therefore, the value of a = 9/5.

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\( \operatorname{det}\left(2 A^{-1} B^{2}\right) = \frac{18}{12} = \frac{3}{2} \)Explanation: We are given that \( \operatorname{det} A=12 \) and \( \operatorname{det} B=3 \). We need to find the determinant of \( 2 A^{-1} B^{2} \). We can use the properties of determinants to simplify the expression. Recall that \( \operatorname{det}(cA) = c^n \operatorname{det}(A) \) for an \( n \times n \) matrix \( A \) and a scalar \( c \), and that \( \operatorname{det}(AB) = \operatorname{det}(A)\operatorname{det}(B) \). Using these properties, we can write:\( \operatorname{det}\left(2 A^{-1} B^{2}\right) = \operatorname{det}(2) \operatorname{det}(A^{-1}) \operatorname{det}(B^{2}) \)\( = 2^3 \operatorname{det}(A^{-1}) \operatorname{det}(B)^2 \)\( = 8 \cdot \frac{1}{\operatorname{det}(A)} \cdot (\operatorname{det}(B))^2 \)\( = 8 \cdot \frac{1}{12} \cdot (3)^2 \)\( = \frac{18}{12} = \frac{3}{2} \)Therefore, \( \operatorname{det}\left(2 A^{-1} B^{2}\right) = \frac{3}{2} \).

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Yes, the fraction 4/9 will make each equation true.

Fraction is an element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

To see why, we can simplify the fraction 4/9 as follows:

4/9 = (4 x 7)/(9 x 7) = 28/63

Now, we can substitute 4/9 with 28/63 in each equation to see that they are all true:

63 x 28/63 = 28

18 x 28/63 = 8

96 x 28/63 = 42

36 x 28/63 = 16

We can also write it as:

63 × (4/9) = 28

18 × (4/9) = 8

96 × (4/9) = 42

36 × (4/9) = 16

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We fοund the inequality tο be  14 -0.6x ≤ 1.5 and sοlving this we fοund that the warning lights cοme οn after using fοr apprοximately 21 days.

In mathematics, inequalities specify the cοnnectiοn between twο nοn-equal numbers. Equal dοes nοt imply inequality. Typically, we use the "nοt equal sign" tο indicate that twο values are nοt equal. Hοwever several inequalities are utilised tο cοmpare the numbers, whether it is less than οr higher than. An inequality symbοl has nοn-equal expressiοns οn bοth sides. It indicates that the expressiοn οn the left shοuld be bigger οr smaller than the expressiοn οn the right, οr vice versa. Literal inequalities are relatiοnships between twο algebraic expressiοns that are expressed using inequality symbοls.

Given,

 The gallοns οf fuel that the car hοlds = 14 gallοns

Amοunt οf fuel used each day = 0.6 gallοns

When the remaining fuel is 1.5 gallοns οr less, warning lights cοme οn.

We can write an inequality fοr this situatiοn.

If x is the number οf days the car is used, then the warning lights cοme οn when,

 14 - 0.6x ≤ 1.5

This is the inequality expressiοn.

Sοlving,

12.5 ≤ 0.6x

x ≥ 12.5/0.6

x ≥ 20.8

Therefοre we fοund the inequality tο be 14 -0.6x ≤ 1.5 and sοlving this we fοund that the warning lights cοme οn after using fοr apprοximately 21 days.

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The zeros of P(x)=x^(4)+2x^(3)-7x-14 are 1, -2, and 2.

To find the rational zeros, we need to use the rational zero theorem. This theorem states that any rational zeros of a polynomial must be a factor of the constant term (in this case, -14) divided by a factor of the leading coefficient (in this case, 1).

So, the possible rational zeros of this polynomial are ±1, ±2, ±7, and ±14.

To confirm if these are indeed the zeros of the polynomial, we can plug each of these numbers into the polynomial and determine if the result is 0.

For example, when x=7, P(7) = 7^(4)+2(7^(3))-7(7)-14 = 2401+882-49-14 = 1720. Since the result is not 0, 7 is not a zero of the polynomial.

So when x=2,

P(2) = 2^(4)+2(2^(3))-7(2)-14

       = 16+16-14-14 = 0.

Therefore, 2 is a zero of the polynomial.

By repeating this process for all possible rational zeros, we can determine that the zeros of this polynomial are 1, -2, and 2.

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