The "break-even" interest rate for year n that equates the return on an n-period zero-coupon bond to that of an n - 1 - period zero-coupon bond rolled over into a one-year bond in year n is defined as:_________

Answers

Answer 1

The "break-even" interest rate for year n that equates the return on an n-period zero-coupon bond to that of an n - 1 - period zero-coupon bond rolled over into a one-year bond in year n is defined as the forward rate.

A forward rate is a specified price agreed by all parties involved for the delivery of a good at a specific date in the future. The use of forward rates can be speculative if a buyer believes the future price of a good will be greater than the current forward rate. Alternatively, sellers use forward rates to mitigate the risk that the future price of a good materially decreases.

Regardless of the prevailing spot rate at the time the forward rate meets maturity, the agreed-upon contract is executed at the forward rate. For example, on January 1st, the spot rate of a case of iceberg lettuce is $50. The restaurant and the farmer agree to the delivery of 100 cases of iceberg lettuce on July 1st at a forward rate of $55 per case. On July 1st, even if the price per case has decreased to $45/case or increased to $65/case, the contract will proceed at $55/case.

To extract the forward rate, we need the zero-coupon yield curve.

We are trying to find the future interest rate [tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  

[tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2), {\displaystyle t_{1}}t_{1}[/tex]  and  [tex]{\displaystyle t_{2}}t_{2}[/tex]  expressed in years, given the rate  [tex]{\displaystyle r_{1}}r_{1}[/tex]  for

time period  [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and rate [tex]{\displaystyle r_{2}}r_{2}[/tex]  for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].  To do this, we use the property that the proceeds from investing at rate  [tex]{\displaystyle r_{1}}r_{1}[/tex] for

time period [tex]{\displaystyle (0,t_{1})}(0, t_1)[/tex]  and then reinvesting those proceeds at rate

[tex]{\displaystyle r_{1,2}}{\displaystyle r_{1,2}}[/tex]  for time period  [tex]{\displaystyle (t_{1},t_{2})}(t_1, t_2)[/tex]  is equal to the proceeds from

investing at rate [tex]{\displaystyle r_{2}}r_{2}[/tex] for time period [tex]{\displaystyle (0,t_{2})}(0, t_2)[/tex].

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Related Questions

1. There are 42 grams of sugar (C12H22O11) in a can of pop (342mL). Use this information (where necessary) to answer the following questions:

a) How many moles of sugar are there in the pop (3 marks)?

b) If a mole of sugar costs 90 cents, what is the value of the sugar in a can of pop (3 marks)?

c) How many particles of sugar are there in the pop (3 marks)?

d) What is the concentration (mol/L) of the sugar in the pop (3 marks)?

Answers

1. The mole of sugar in the pop is 0.123 mole

2. The value of the sugar in the pop is 11.07 cents

3. The number of particles of the sugar in the pop is 0.74×10²³ particles

4. The concentration of the sugar in the pop is 0.36 mol/L

1. How to determine the mole of the sugarMass of sugar (C₁₂H₂₂O₁₁) = 42 gMolar mass of sugar (C₁₂H₂₂O₁₁) = 342 g/molMole of sugar (C₁₂H₂₂O₁₁) =?

Mole = mass / molar mass

Mole of sugar (C₁₂H₂₂O₁₁) = 42 / 342

Mole of sugar (C₁₂H₂₂O₁₁) = 0.123 mole

2. How to determine the value of the sugarCost per mole = 90 centsCost of 0.123 mole of sugar =?

1 mole of sugar = 90 cents

Therefore,

0.123 mole of sugar = 0.123 × 90

0.123 mole of sugar = 11.07 cents

3. How to determine the number of particles of the sugar

From Avogadro's hypothesis,

1 mole of sugar = 6.02×10²³ particles

Therefore,

0.123 mole of sugar = 0.123 × 6.02×10²³

0.123 mole of sugar = 0.74×10²³ particles

4. How to determine the concentration of the sugarMole of sugar (C₁₂H₂₂O₁₁) = 0.123 moleVolume = 342 mL = 342 / 1000 = 0.342 L Concentration of sugar =?

Concentration = mole / Volume

Concentration of sugar = 0.123 / 0.342

Concentration of sugar = 0.36 mol/L

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A 21.496 grams sample of magnesium is burned in air to form magnesium oxide and magnesium nitride. When the products are treated with water,2.813 grams of gaseous ammonia are generated. Calculate the amounts of magnesium nitride and magnesium oxide formed?

Answers

25.898 g is the amount of magnesium nitride and magnesium oxide formed.

Step1 2Mg(s)+ O2(g)-----> 2 MgO(s)

3Mg(s)+N2(g)------> Mg3N2(s)

Mg3N2(s)+ 6 H2O(l)---> 3Mg(OH)2 + 2 NH3(g)

Step2 Moles of NH3 = (2.813/17)

Moles of Mg3N2= (1/2) Moles of NH3 = (2.813/2x17)= 2.813/34

Mass of Mg3N2 = (2.813/34) x100 =8.274g (Molar mass of Mg3N2=100)

Step3 Mass of Mg in Mg3N2 =(72/100) x8.274 =5.957g

Mass of Mg converted in MgO= 21.496-5.957=15.539

Moles of MgO= Moles of Mg = 15.539/24

Mass of MgO = 15.539x40/24 =25.898 g.

Magnesium is a cofactor for over 300 enzymatic systems that regulate various biochemical reactions in the body, including protein synthesis, muscle and nerve function, glycemic control, and blood pressure regulation [1-3].

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HELP PLS important plsssssssssssssssss

Answers

Answer: All have something wrong with them!!!

Explanation: #1: He is using chemicals without using any goggles or protection

#2: She is unsupervised while around fire as well as no protection

#3:

#4: There are many flammable things around the fire especially since its paper it could start a major fire

#5: Again has no protection (goggles. gloves, e.t.c.) and putting chemicals close to your face is just a Don't in science

#6: They are "horseplaying" and also someone else is doing all the work

The Enthalpy profile of chemical reaction is shown at the river. On the graph, indicate the magnitude of:

Answers

Energy was given out in the process as such the reaction must be exothermic given the loss of energy.

What is a reaction profile?

The reaction profile shows the the interaction between substances. Now the vertical axes shows the energy while the horizontal axes shows the course of the reaction. The hump at the top of the profile shows the activation energy. The activation energy is the maximum energy that is required for reactants to cross the barrier and become products.

Now we know that the endothermic reaction is one in which energy is taken in while an exothermic reaction is one in which energy is given out.

As such we can see from the graph that the energy of the reactants is greater than that of the products. This implies that energy was given out in the process as such the reaction must be exothermic given the loss of energy.

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What is the molality of phosphoric acid, h3po4, in a solution prepared from 376 g of phosphoric acid and 1. 70×103 g of ethylene glycol, c2h4(oh)2?

Answers

The molality of phosphoric acid, h3po4, in a solution prepared from 376 g of phosphoric acid and 1. 70×103 g of ethylene glycol, c2h4(oh)2 is 2.25m.

Ethylene Glycol is known as C2H4 (OH)2.

It is used to prepare Antifreeze solution by adding water in it.

Given,

Mass of phosphoric acid = 376g

Mass of ethylene acid = 1.7 × 10 3g

Since ethylene glycol is in excess. So it is acts as a solvent and phosphoric acid acts as solute

As we know that,

Molar mass of phosphoric acid = 98g

Moles of phosphoric acid

= Given mass / Molar mass

=376 / 98

= 3.83

Molality is defined as the ratio of moles of solute to the mass of solvent.

Molality = Moles of solute / Mass of solvent

= 3.83 / 1.7 kg

= 2.25m.

Thus, we found that the molality of phosphoric acid is 2.25m.

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Be sure to answer all parts. what are the concentrations of hso4−, so42−, and h in a 0. 31 m khso4 solution? (hint: h2so4 is a strong acid; ka for hso4− = 1. 3 × 10−2. ) [hso4−] = m [so42−] = m [h ] = m

Answers

At equilibrium the concentrations of:

[HSO₄⁻] = 0.10 M;

[SO₄²⁻] = 0.037 M;

[H⁺] = 0.037 M;

There is initially very little H+ and no SO₄²⁻ in the solution. A salt is KHSO₄⁻. All KHSO₄⁻ will split apart into K⁺ and HSO₄⁻ ions. [HSO₄⁻] will initially be present at a concentration of 0.14 M.

HSO₄⁻ will not gain H⁺ to produce H₂SO₄ since H₂SO₄ is a strong acid.  HSO₄⁻ may act as an acid and lose H⁺ to form SO₄²⁻. Let the final H⁺ concentration be x M. Construct a RICE table for the dissociation of HSO₄²⁻.

R   [tex]HSO_4^-[/tex]    ⇄  [tex]H^+ + SO_4^2^-[/tex]

I    [tex]0.14[/tex]

C   [tex]- x[/tex]               [tex]+x[/tex]       [tex]+x[/tex]

E   [tex]0.14-x[/tex]        [tex]x[/tex]         [tex]x[/tex]

[tex]K_a = 1.3[/tex] × [tex]10^-^2[/tex] for [tex]HSO^-_4[/tex] . As a result,

[tex]\frac{[H^+]. [SO_4^2^-]}{HSO_4^-} = K_a[/tex]

[tex]K_a[/tex] is large. It is no longer valid to approximate that [tex][HSO^-_4][/tex] at equilibrium is the same as its initial value.

[tex]\frac{x^2}{0.14-y} = 1.3 * 10^-^2[/tex]

[tex]x^2+1.3*10^-^2x - 0.14[/tex] × [tex]1.3[/tex] × [tex]10^-^2= 0[/tex]

Solving the quadratic equation for [tex]x , x \geq 0[/tex] since [tex]x[/tex] represents a concentration;

                             [tex]x=0.0366538[/tex]

Then, round the results to 2 significant figure;

[tex][SO_4^2^-] = x = 0.037 mol. L ^-^1[/tex][tex][H^+] = x = 0.037 mol. L ^-^1[/tex][tex][HSO_4^-] = 0.14 - x = 0.10 mol. L ^-^1[/tex]

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A toy truck has a speed of 10 m/s and kinetic energy of 50 J. What is its mass?

A. 5 kg
B. 4 kg
C. 1 kg
D. 3 kg

Answers

Answer: 5kg

Explanation: formula K=1/2mv^2

50=10m

Answer:

C

Explanation:

KE = 1/2 m v^2

KE *2 / v^2   = m

50 (2)/ 10^2   = m =  1 kg

Which compound contains a chiral carbon atom? 3-chloropentane 2-bromopropane 3-bromopentane 2-bromopentane

Answers

The compound  2-bromopentane contains a chiral carbon atom.

So , option D is correct one.

The carbon which is bonded with four different substituent or four valency of carbon is satisfy by the four different substituent is called chiral carbon and the molecule contain such chiral carbon is called chiral molecule. The molecule contain chiral carbon rotates plane polarized light.

Example: The compound  2-bromopentane contains chiral carbon at second carbon and four different substituent at second carbon is methyl , bromine , propyl and hydrogen.

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What will be the ph of a buffer solution with an acid (pka6. 1) that is exactly half as concentrated as its conjugate base?

Answers

The pH of a buffer solution with acid that (PKA 6. 1) is exactly half as concentrated as its conjugate base is 6.4.

What is a buffer solution?

A buffer solution is a solution that has a maintained pH, not basic or not acidic. Its pH changes when acid or base is added to the solution.

We had to figure out the acid's concentration, which is exactly half that of its potential base.

We know that pH = pH_log

We have less than 6.1 pH so this is a conjugated base.

This will equal to 6.1 + log2 = 6.4

Thus, the pH of a buffer solution with acid is 6.4.

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In a titration experiment, 31. 4 ml of 1. 120 m hcooh is neutralized by 16. 3 ml of ba(oh)2. what is the concentration of the ba(oh)2 solution?

Answers

In a titration experiment, 31. 4 ml of 1. 120 M HCOOH is neutralized by 16. 3 ml of [tex]Ba(OH)_{2}[/tex]. So, the concentration of the [tex]Ba(OH)_{2}[/tex]  solution is 23.16 M

Calculation,

The formula for the dilution of a solution is given as:

[tex]M_{1} V_{1}[/tex] = [tex]M_{2} V_{2}[/tex]

Where M is molarity and V is the volume of the solution in liters ( L ).

Given data,

[tex]M_{1}[/tex] =  120  M

[tex]V_{1}[/tex] =31. 4 ml

[tex]M_{2}[/tex] = ?

[tex]V_{2}[/tex] = 16. 3 ml

120  M ×31. 4 ml  =  [tex]M_{2}[/tex]  ×  16. 3 ml

[tex]M_{2}[/tex]  = 120  M ×31. 4 ml / 16. 3 ml =23.16 M

In a titration experiment, the concentration of the [tex]Ba(OH)_{2}[/tex]  solution is 23.16 M

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What is the specific heat of a substance that requires 7.5 kj of heat to raise the temperature of a 2.0 kg sample by 5 degrees c

Answers

Answer:

.75 J / g-°C

Explanation:

Specific heat =   J / gm-C

                   = 7500 J /( 2000 gm * 5 c) =   .75 J / g-°C

How many grams of calcium chloride are needed to produce 10. 0 g of potassium chloride?

cacl2( aq) k2co3( aq) → 2kcl( aq) caco3( aq)

Answers

Answer:

7.44 grams CaCl2 will produce 10.0 grams KCl.

Explanation:

The equation is balanced:

I've repeated it here, with the elements corrected for their initial capital letter.

CaCl2( aq) K2CO3( aq) → 2KCl( aq) CaCO3( aq)

This equation tells us that 1 mole of CaCl2 will produce 2 moles of KCl.

If we want 10.0g of KCl, we need to convert that mass into moles KCl by dividing by the molar mass of KCl, which is 74.55 grams/mole.

 (10.0 grams KCl)/(74.55 grams/mole) = 0.1341 moles of KCl.

We know that we'll need half that amount of moles CaCl2, since the balanced equation says we'll get twice the moles KCl for every one mole CaCl2.

So we'll need (0.1341 moles KCl)*(1 mole CaCl2/2moles KCl) = 0.0671 moles CaCl2.

The molar mass of CaCl2 is 110.98 grams/mole.

(0.0671 moles CaCl2)*(110.98 grams/mole) = 7.44 grams CaCl2

7.44 grams CaCl2 will produce 10.0 grams KCl.

In a particular redox reaction, no−2no2− is oxidized to no−3no3− and fe3 fe3 is reduced to fe2 fe2. complete and balance the equation for this reaction in acidic solution. phases are optional

Answers

Balanced chemical equation is  -  3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

Fe2+ + NO3- + H+ → Fe3+ + NO3- + NO + H2O

Fe+22+ + N+5O-23- + H+1+ → Fe+33+ + N+5O-23- + N+2O-2 + H+12O

3Fe2+ + NO3- + 4H+ → 3Fe3+ + NO + 2H2O

A balanced chemical equation specifies the quantities of reactants and products required to meet the Law of Conservation of Mass. This signifies that there is the same number of each sort of atom on the left side of the equation as there are on the right side. The rule of a balanced chemical equation is used to determine if two weights put on opposing sides of the fulcrum will balance each other.

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[?] describes how small molecules can be selectively removed from a colloidal suspension while retaining large molecules.
A) Dialysis
B) The Tyndall effect​

Answers

Dialysis is correct……………

Answer:

using a centrifuge

Explanation:

Centrifugation will make the large molecules to settle at the bottom.

The Most suitable answer is tyndall effect

Starting with 1.5 mL of isopentyl alcohol, 2.0 mL of concentrated acetic acid, and 0.4 mL of concentrated phosphoric acid, what is the theoretical yield (in g) of isopentyl acetate

Answers

The theoretical yield isopentyl acetate is of the 1.82 g

What is the theoretical yield (in g) of isopentyl acetate?

Now the theoretical yield is the yield of the product as obtained from the stoichiometry of the reaction. In this case, we know the reaction is 1:1.

Mass of  isopentyl alcohol = 0.810 g/mL * 1.5 mL = 1.215 g

Mass of acetic acid = 1.05 g/mL * 2 mL = 2.1 g

Number of moles of  isopentyl alcohol = 1.215 g/88 g/mol = 0.014 moles

Number of moles of acetic acid = 2.1 g /60 g/mol = 0.035 moles

Hence   isopentyl alcohol is the limiting reactant.

1 mole of   isopentyl alcohol yields 1 mole of isopentyl acetate

0.014 moles   isopentyl alcohol yields 0.014 moles of isopentyl acetate

Mass of of isopentyl acetate = 0.014 moles * 130 g/mol = 1.82 g

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When you created hypotheses to guess whether each chemical was an acid or base, what specifically did you look for in the chemical formulas?

Answers

While assigning a term for a chemical to be an acid or base we have to look for the [tex]H^{+}[/tex] ions that can be donated by a chemical formulas or [tex]OH^{-}[/tex] ions for the basic , When you created hypotheses to guess whether each chemical was an acid or base,

To determine whether a substance is an acid or base , count the hydrogen on each substance before and after the reaction . If the number of hydrogens has decreased the substance is the acid ( donates hydrogen ions ) . If the number of hydrogens has increased that substance is the base ( accepts hydrogen ion )

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Which is incorrect? multiple choice at equilibrium, ecell = 0. e > 0 for a spontaneous process. e = 0 for a spontaneous process. δg < 0 for a spontaneous process. δg = 0 at equilibrium.

Answers

The incorrect statement is e = 0 for a spontaneous reaction.

e cell = 0

The cell potential is 0 at equilibrium.

e > 0 for a spontaneous reaction

For a spontaneous reaction the value cell potential E cell is positive i.e. >0

e = 0 for a spontaneous reaction

This statement is incorrect because the potential of a cell is positive if the reaction is spontaneous. Hence it cannot be zero.

δ g < 0 for a spontaneous reaction

For a spontaneous reaction gibbs free energy δ g value is negative i.e. < 0

δg = 0 at equilibrium.

At equilibrium the value of gibbs free energy is zero i.e. δg = 0

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Help me, place the element symbol in its location on the chart.

Answers

The elements that suits each given property for each of the empty boxes is as described below.

How to interpret the properties of Periodic Tables?

For the first box, the property is that it is a conductor and that it has 2 energy levels. The only possible options here will be Lithium (Li) and Beryllium because they are both conductors and have 2 energy levels. However, among the given elements, only Li is given and as such we will select that.

For the second box, the property is that it is a conductor, it has 3 energy levels and has 2 valence electrons. The only element that falls into this category is Magnesium (Mg).

For the third box, the property is that it is a conductor, it has 3 energy levels and has 1 valence electron. The only element that falls into this category is Sodium (Na).

For the fourth box, the property is that it is not a conductor and has 3 energy levels. The only elements that falls into this category are Silicon(Si), Phosphorus(P), Sulphur(S), Argon(Ar). The only given option is Sulphur(S) and we will pick that.

For the fifth box, the property is that it is not a conductor and has 4 energy levels and 7 valence electrons. The only element that falls into this category is Bromine(Br).

For the sixth box, the property is that it is not a conductor and has 4 energy levels and 5 valence electrons. The only element that falls into this category is Arsenic (As).

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Enough of a monoprotic acid is dissolved in water to produce a 1. 50 m solution. the ph of the resulting solution is 2. 83. calculate the ka for the acid

Answers

1.4406 × 10⁻⁶ is the Ka(dissociation constant) for the acid.

The equilibrium constant for the reaction of an acid with water is the acid dissociation constant, where the acid, HA separates into H⁺ and A⁻ ions.

The acid dissociation constant is represented by (Ka).

So let's first imagine that the given monoprotic acid is HA.

HA will dissociate into H⁺ and A⁻ ions.

HA ⇒ H⁺ and A⁻

The formula used for Ka is

Ka = [H⁺] [A⁻] / [HA]

Given

pH = 2.83

[HA] = 1.50 M

From the given pH, we can calculate [H⁺] and [A⁻]

[H⁺] = [A⁻] = 1 × [tex]10^{-2.83}[/tex] =  1.47 × 10⁻³ M

Ka = 1.47 × 10⁻³ × 1.47 × 10⁻³ / 1.50

Ka = 1.4406 × 10⁻⁶

Hence, 1.4406 × 10⁻⁶ is the Ka for the acid.

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Which of the following statements statements expresses the following chemical equation with words?
2 K(s) + Cl₂(g) →> 2 KCI(S)
->
Select one:
O a. Four atoms of krypton react with two molecules of Cl₂
O b. Two atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride.
O c. One atom of chromium reacts with 1 molecule of calcium to produce 1 molecule of chromium calcide.
O d. Two atoms of potassium react with potassium chloride to produce chlorine gas.

Answers

Answer:

option b is the answer of given statementtwo atoms of potassium react with one molecule of chlorine to produce two molecules of potassium chloride

another student collected boiling point data of 10 different substances. Should he display his results in a line graph or a bar chart.​

Answers

Answer:

Bar chart

Explanation:

Because if he displays his or her result in a line graph the Boling data of 10 different substances will be incorrect.

Hope it helps you

what is the pH value of Potassium hydroxide

Answers

Answer:

from 10-14

Explanation:

the pH of potassium hydroxide is extremely high and is a strong base although the exact value depends on the concentration of the base in water.

10-14 is the ph value of potassium hydroxide

) a student makes up a 0. 6 m solution of acetic acid. (note: the pka of acetic acid is 4. 74) a) what is the poh of this solution?

Answers

A student makes up a 0. 6 M solution of acetic acid then its pOH of this solution is  13.77

Calculation ,

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

We have to find pH of the acetic acid .

[ [tex]H^{+}[/tex] ] = 0. 6

pH = -㏒[ [tex]H^{+}[/tex] ]

pH = -㏒ [  0. 6 ]

pH  = 0.22

pH + pOH = 14

pOH = 14 - pOH = 14 - 0.22 = 13.77

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A formic acid buffer solution contains 0. 20 m h c o o h hcooh and 0. 24 m h c o o − hcoox−. the pka of formic acid is 3. 75. what is the ph of the buffer?

Answers

A buffer solution contains an equivalent amount of acid and base. The pH of the solution with an acid dissociation constant (pKa) value of 3.75 is 3.82.

What is pH?

The amount of hydrogen or the proton ion in the solution is expressed by the pH. It is given by the sum of pKa and the log of the concentration of acid and bases.

Given,

Concentration of salt [HCOO⁻] = 0.24 M

Concentration of acid [HCOOH] = 0.20 M

The acid dissociation constant (pKa) = 3.75

pH is calculated from the Hendersons equation as,

pH = pKa + log [salt] ÷ [acid]

pH = 3.75 + log [0.24] ÷ [0.20]

= 3.75 + log (1.2)

= 3.75 + 0.079

= 3.82

Therefore, 3.82 is the pH of the buffer.

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550. ml of a 0. 40m solution of naoh is titrated with 0. 25 m hcl. calculate the ph of the solution after 650. ml of the hcl has been added

Answers

Titration is the determination of quantity by a known amount. The pH of the solution after the solution was added with 650 mL of hydrochloric acid is 13.4.

What is pH?

pH is the calculation of the hydrogen ion concentration in the solution and can be used to determine the acidity or the basicity of the solution.

Given,

M₁ = 0.40 M

V₁ = 550 mL

M₂ = 0.25 M

V₂ =?

Volume at 0.25 M is calculated as,

M₁V₁ = M₂V₂

0.40 × 550.0 =0.25 × V2

V2 = 880 ml

880 mL of HCl is required for the neutralization reaction.

The final molar concentration of NaOH is,

550 × M₁ = 0.25 × 650

M₁ = 0.295 M

pH is calculated as:

pOH = -log [OH⁻]

= -log [0.295]

= 0.529

Solving further,

pH+ pOH = 14

pH = 14 - pOH

= 14 - 0.529

= 13.4

Therefore, 13.4 is the pH of the solution.

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If 0.0309 mol CaCl2 is dissolved in water to make a 0.730 M solution, what is the volume of the solution

Answers

Answer:

0.0423 L

Explanation:

Molarity can be represented by the following ratio:

Molarity = moles / volume (L)

You can plug the given values into the equation and simplify to find the volume.

Molarity = moles / volume

0.730 M = 0.0309 moles / volume

(0.730 M) x volume = 0.0309 moles

volume = 0.0423 L

1. Fill in the blanks.
a. Breathing is a combined form of______and_______.
b. Oxygen is absorbed by diffusion from______of the lungs.
c. Plants take______gas for respiration. d. Plants have______and______for respiration.
e. Plants have_______and_______for transportation.​

Answers

Respiration deals with the gaseous exchange that occur between the individuals and the environment.

What is respiration?

The term respiration deals with the gaseous exchange that occur between the individuals and the environment. The individuals take in a gas from the environment and pass out a gas to the environment. This is the way in which the balance of the universe is maintained.

Now, plants take in carbon dioxide and give out oxygen whereas animals take in oxygen and give out carbon dioxide. By so doing, the delicate carbon - oxygen balance in nature is maintained unless it is upturned by anthropogenic activities.

The following fill in the blanks as requested in the question;

a) Inhalation and exhalation'

b) trachea

c) carbon dioxide

d) leaves and stomata

e) xylem and phloem

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Answer:

a) inhalation and exhalation

b) trachea

c) carbon dioxide

d) leaves and stomata

e) xylem and phloem

What type of bond will typically form between boron and hydrogen based on their electronegativity?

Answers

The type of bond will typically form between boron and hydrogen based  is boron-hydrogen-boron bridge bond also known as 3 centered two electron bond on the basis of their electronegativity.

What is electronegativity?

Electronegativity is a tendency or chances of an element to accepts the single electron from any atom not only the lone pair of electrons.

Fluorine is smallest and the highly  electronegative element of the periodic table after that oxygen is also an electronegative element after that nitrogen.

Therefore, it is  known as 3 centered two electron bond on the basis of their electronegativity.

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How does the mass per nucleon of an element change as the atomic number increases?

Answers

Answer:

Explanation: So, the atomic number is the number of protons present in an atom. For example, Helium's atomic number is 2, meaning it only has 2 protons. In most cases, the number of nuetrons and protons are equal, so Helium (usually) has 2 protons and 2 nuetrons - this is the nucleus. The atomic mass, or mass per nucleon is the proton and nuetron added together, so the atomic mass of Helium is about 4. Therefore, on the periodic table, as the atomic number increases by 1, the atomic mass increases by about 2 (the atomic mass is an average so it's not exact).

Now, using your periodic table as a reference, type the symbols for the known elements into their appropriate groups and periods in the modified table below. Note that we’re using the international group numbers (1-18), followed by the American scheme for the A-group elements in parentheses.

Answers

The symbols for some known elements using the periodic table are given below

Groups/Period

H

He

Li

Be

B

C

N

O

F

Ne

Na

Mg

Al

SI

P

S

Cl

Ar

K

CA

What is an element?

An element is a substance which cannot be split into simpler units by any ordinary chemical process

So therefore, the elements in the periodic table are classified based on their increasing atomic numbers.

The group is vertical representation of the elements

The periods is horizontal arrangements of elements in the periodic table

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Answer:

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Explanation:

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