The breaking down of rocks into smaller pieces is called____________________________________________.
Fill in the blank

Answer:

( 80.87 i - 12.96 j ) m

Explanation:

Running back movements :

20⁰ north of east  for  10 meters,  

Runs straight east for 60 meters

runs 35⁰ east of south for 20 meters

A) show vector pointing from the starting point to the end ( where he scored )

The final vector displacement : ( 80.87 i - 12.96 j ) m

which is : 81.90 m, 9.10⁰ south of east

attached below is the required  diagram

First compute the resultant force F:

[tex]\mathbf F_1=(5.90\,\mathbf i-5.60\,\mathbf j)\,\mathrm N[/tex]

[tex]\mathbf F_2=(4.65\,\mathbf i-5.55\,\mathbf j)\,\mathrm N[/tex]

[tex]\implies\mathbf F=\mathbf F_1+\mathbf F_2=(10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N[/tex]

Then use Newton's second law to determine the acceleration vector [tex]\mathbf a[/tex] for the particle:

[tex]\mathbf F=m\mathbf a[/tex]

[tex](10.55\,\mathbf i-11.15\,\mathbf j)\,\mathrm N=(2.10\,\mathrm{kg})\mathbf a[/tex]

[tex]\mathbf a\approx(5.02\,\mathbf i-5.31\,\mathbf j)\dfrac{\rm m}{\mathrm s^2}[/tex]

Let [tex]\mathbf x(t)[/tex] and [tex]\mathbf v(t)[/tex] denote the particle's position and velocity vectors, respectively.

(a) Use the fundamental theorem of calculus. The particle starts at rest, so [tex]\mathbf v(0)=0[/tex]. Then the particle's velocity vector at t = 10.4 s is

[tex]\mathbf v(10.4\,\mathrm s)=\mathbf v(0)+\displaystyle\int_0^{10}\mathbf a(u)\,\mathrm du[/tex]

[tex]\mathbf v(10.4\,\mathrm s)=\left((5.02\,\mathbf i-5.31\,\mathbf j)u\,\dfrac{\rm m}{\mathrm s^2}\right)\bigg|_{u=0}^{u=10.4}[/tex]

[tex]\mathbf v(10.4\,\mathrm s)\approx(52.2\,\mathbf i-55.2\,\mathbf j)\dfrac{\rm m}{\rm s}[/tex]

If you don't know calculus, then just use the formula,

[tex]v_f=v_i+at[/tex]

So, for instance, the velocity vector at t = 10.4 s has x-component

[tex]v_{f,x}=0+\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)(10.4\,\mathrm s)=52.2\dfrac{\rm m}{\mathrm s^2}[/tex]

(b) Compute the angle [tex]\theta[/tex] for [tex]\mathbf v(10.4\,\mathrm s)[/tex]:

[tex]\tan\theta=\dfrac{-55.2}{52.2}\implies\theta\approx-46.6^\circ[/tex]

so that the particle is moving at an angle of about 313º counterclockwise from the positive x axis.

(c) We can find the velocity at any time t by generalizing the integral in part (a):

[tex]\mathbf v(t)=\mathbf v(0)+\displaystyle\int_0^t\mathbf a\,\mathrm du[/tex]

[tex]\implies\mathbf v(t)=\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf j[/tex]

Then using the fundamental theorem of calculus again, we have

[tex]\mathbf x(10.4\,\mathrm s)=\mathbf x(0)+\displaystyle\int_0^{10.4}\mathbf v(u)\,\mathrm du[/tex]

where [tex]\mathbf x(0)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m[/tex] is the particle's initial position. So we get

[tex]\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\displaystyle\int_0^{10.4}\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf j\right)\,\mathrm du[/tex]

[tex]\mathbf x(10.4\,\mathrm s)=(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m+\dfrac12\left(\left(5.02\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf i+\left(-5.31\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf j\right)\bigg|_{u=0}^{u=10.4}[/tex]

[tex]\mathbf x(10.4\,\mathrm s)\approx(542\,\mathbf i-570\,\mathbf j)\,\mathrm m[/tex]

So over the first 10.4 s, the particle is displaced by the vector

[tex]\mathbf x(10.4\,\mathrm s)-\mathbf x(0)\approx(270\,\mathbf i-283\,\mathbf j)\,\mathrm m-(-1.75\,\mathbf i+4.15\,\mathbf j)\,\mathrm m\approx(272\,\mathbf i-287\,\mathbf j)\,\mathrm m[/tex]

or a net distance of about 395 m away from its starting position, in the same direction as found in part (b).

(d) See part (c).

Answer:

The average speed was 800 miles/hour

Explanation:

Average Speed

If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:

[tex]\displaystyle V=\frac{d}{t}[/tex]

A plane took 3 hours and 33 minutes to travel d=2840 miles to finish its journey. We will calculate the average speed in miles per hour, thus the time needs to be expressed in hours, and it's given in a mixed unit:

t=3 hours+33 minutes

Since there are 60 minutes in an hour:

t=3 hours+33 /60 hours = 3 hours + 0.55 hours = 3.55 hours

Now calculate the average speed:

[tex]\displaystyle V=\frac{2840}{3.55}=800[/tex]

The average speed was 800 miles/hour

Answer:

I don't know sorry I hope you find what your looking

Answer:

the first one is oil and water and the second one I am between homogeneous mixture and compound

Answer:

 y = 17 m

Explanation:

For this projectile launch exercise, let's write the equation of position

          x = v₀ₓ t

          y = [tex]v_{oy}[/tex] t - ½ g t²

let's substitute

          45 = v₀ cos θ t

          10 = v₀ sin θ t - ½ 9.8 t²

the maximum height the ball can reach where the vertical velocity is zero

           v_{y} = v_{oy} - gt

           0 = v₀ sin θ - gt

           0 = v₀ sin θ - 9.8 t

Let's write our system of equations

         45 = v₀ cos θ  t

         10 = v₀ sin θ t - ½ 9.8 t²

         0 = v₀ sin θ - 9.8 t

We have a system of three equations with three unknowns for which it can be solved.

Let's use the last two

        v₀ sin θ = 9.8 t

we substitute

        10 = (9.8 t) t - ½ 9.8 t2

        10 = ½ 9.8 t2

        10 = 4.9 t2

        t = √ (10 / 4.9)

        t = 1,429 s

Now let's use the first equation and the last one

         45 = v₀ cos θ t

         0  = v₀ sin θ - 9.8 t

         9.8 t = v₀  sin θ

         45 / t = v₀ cos θ

we divide

         9.8t / (45 / t) = tan θ

          tan θ = 9.8 t² / 45

          θ = tan⁻¹ ( 9.8 t² / 45 )

          θ = tan⁻¹ (0.4447)

          θ = 24º

Now we can calculate the maximum height

         v_y² = [tex]v_{oy}^2[/tex] - 2 g y

         vy = 0

          y = v_{oy}^2 / 2g

          y = (20 sin 24)²/2 9.8

          y = 3,376 m

the other angle that gives the same result is

       θ‘= 90 - θ

       θ' = 90 -24

       θ'= 66'

for this angle the maximum height is

          y = v_{oy}^2 / 2g

          y = (20 sin 66)²/2 9.8

           y = 17 m

thisis the correct

Answer:

We study motion becuase it is the best way of determining the best method of doing the work by scrutinizing the motions made by the worker or the machine

Hope this helps :)

Answer:

D.

Explanation:

Given that your boat departs from the bank of a river that has a swift current parallel to its banks. If you want to cross this river in the shortest amount of time, you should direct your boat: so that it drifts with the current.

If the boat moves perpendicular to the current, the current flow will be the resistance to the movement of the boat. So, it's better for the boat to drifts perpendicularly with the current.

The best answer is therefore option D.

Answer:

40.2 m

Explanation:

Answer:

The answer should be WORK

(Hope this Helps)

Explanation:

work is equal to the product of force and distance.

W=F*S

W=Work

F=Force applied

S=Distance

Answer:

288 Km/h

Explanation:

72x4=288

therefore 288 is your answer

Each stage corresponds to a specific age. is the statements do not represent assumptions that stage theories share.

Any speculative construct is used to represent phases or steps in a time-based process, such as a belief that development proceeds in discontinuous phases indicated by functional changes.

Each stage corresponds to a specific age the statements do not represent assumptions that stage theories share.

The assumptions for the stage theory are as follows;

1. Every stage serves as a building block for the next.

2. The phases are followed in the same sequence by everyone.

3. Each step is distinct in terms of quality. It is a change in nature, not merely a change in amount.

Each stage corresponds to a specific age. is the statements do not represent assumptions that stage theories share.

Hence option B is the right option.

To learn more about the stage theory refer to the link;

https://brainly.com/question/9126685

Recruiting and nominating candidates.

Answer:

D

Explanation:

Answer:

Explanation:

1) Displacement of the object will be gotten using simply adding the distances since they are goinf in the same direction (positive y direction)

Displacement= 330km + 220km

Displacement = 550km North

2) For a falling body, the body will possess positive acceleration due to gravity because it is falling under the influence of gravitational force. If a body is not under the influence of gravity and is thrown up, such body wont come back down. Hence the value of acceleration due to gravity of a body falling to the ground is +9.8 m/s² (note that the unit of acceleration is m/s²)

Answer:

i

Explanation:

Answer: i think its A. Let me knows if its wrong so i can double check

Explanation:

The reading on the scale, if the 100 kg man standing inside the elevator, which is moving with a velocity of 5 m/s is 1000 Newtons, so option B is correct.

Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or points traveling straight forward. Even though the speed is constant, motion on a circle increases because of the constant change in direction.

Both effects add to the acceleration for all other types of motion. Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector.

Given:

The mass of man, m = 100 kg,

The speed of the elevator, s = 5 m/s,

The reading is higher when the person is in a standing elevator (or one moving at a steady speed).

w = mg =100*10 = 1000 N

Now:

If the elevator is going down at 5 m/s and the weight will be

W = m(g -a)

W = 100 (10 -0)

Here the acceleration of lift is zero as it is moving with constant speed,

W = 1000 N

Therefore, the reading on the scale, if the 100 kg man standing inside the elevator which is moving with a velocity of 5 m/s is 1000 Newtons.

To know more about Acceleration:

https://brainly.com/question/3046924

#SPJ2

Answer:

Option (1)

Explanation:

Relation between wavelength and frequency of a wave is,

Wavelength (λ) ∝ [tex]\frac{1}{\text{Frequency}}[/tex]

That means wavelength is inversely proportional to the frequency of a wave.

When the wavelength of the wave is decreased, frequency of the wave will increase.

Therefore, if the distance across section 1 is decreased in the given picture,

wavelength gets decreased.

As a result frequency of the wave will increase.

Option (1) will be the answer.

Answer:

8 km/h²

Explanation:

a = v-u/t

v is final velocity, u is initial velocity

a = 40-0/5

a = 8.0 km/h²

Answer:

Explanation:

Suppose you have a box filled with all sorts of molecules that won't react with each other.

Suppose further that these molecules move. What formula are they obeying? the answer is Ke = 1/2 m  v^2.

Now the mass is not going to change, but what about v, the velocity. It certainly can change.

Suppose further, that the molecules are in a closed container. Suppose that the box is heated up. What will happen? The molecules can't escape. All they can do is move faster (remember that they are trapped inside the box). Their mass won't change.

So if you put a thermometer inside a cork into a whole where the cork will seal the hole, what will the thermometer record. Those fast moving molecules will hit the thermometer and make the molecules of the thermometer move faster. The liquid inside the thermometer will measure the Ke of the molecules. So temperature is related to Ke.

The more heat, the faster the molecules are moving. The more they move, the more Ke is being transferred to the thermometer. The more heat transferred to the thermometer, the more the liqiuid in the thermometer will expand, and the higher the temperature.

So shortly temperature is the measurement of Ke inside the closed container that is filled with gas molecules.

Answer:

C. strike-slip fault

Explanation:

The scientist must have observed a strike- slip fault.

A fault is an evidence of brittle deformation of the crust in the presence of applied stress on earth materials. Here, the earth material is the rock subjected to tension.

Where a fault occurs, there must have been movement between two blocks of rocks. The direction of movement helps us to delineate the fault type.

Option A, Plateau is a table landform usually a mountain with flat peak.

Option B is a bowl shaped stratigraphic pattern in which the youngest sequence is at the core of the strata or a fold.

So, the most fitting option is C, a strike-slip fault.

Answer:

Explanation:

c