The constellation whose stars are used as pointers to the north celestial pole in the northern hemisphere at this time in history is:______

Answers

Answer 1

The constellation whose stars are used as pointers to the north celestial pole in the Northern Hemisphere at this time in history is Ursa Minor.

Polaris is known as the North Star, which is located in the constellation Ursa Minor. The star doesn't sit directly on the Earth’s north celestial pole, but it is very close. Using the Little Dipper as a reference, Polaris is easy to identify in the Northern Hemisphere. The stars, including the constellations, in the night sky appear to rotate around Polaris throughout the year.

Ursa Minor (or the Little Bear) is a constellation that is located in the far northern sky. This constellation was one of the 48 constellations that was listed by Ptolemy, and it remains one of the 88 modern constellations. Traditionally, Ursa Minor has been important for navigation because of Polaris being the north pole star.

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Related Questions

a platinum resistance thermometer has a resistance of 400 at 0 degrees Celsius and 1,200 at hundred degree celsius assuming that the resistance changes uniformly with temperature calculate the resistance of the thermometer when the temperature is 45 degrees Celsius. I need this ASAP! .Ps I'll mark brainliest ​

Answers

Answer:

Explanation:

I will make a solution in a page and upload

scientists often calculate how likely the outcome of their experiments may be due to chance. if this is less than 5%, then the results may be considered reliable.

Answers

Yes, it is correct. The results may be considered reliable if the chance of an outcome due to chance is less than 5%.

What do you mean by experiments?

Experiment is a method of testing a hypothesis or theory by observing the results of an action under controlled conditions. Experiments help scientists to learn how certain variables interact and influence one another, and can be used to test theories and develop new ideas.

However, it is important to note that there are other factors to consider when assessing the reliability of results, such as the accuracy of the measurements and the quality of the data.

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Calculate the kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms-1

Answers

The kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms-¹ is 20J.

How to calculate kinetic energy?

Kinetic energy in physics refers to the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

It can be calculated using the following formula;

K.E = ½mv²

Where;

m = massv = velocity

According to this question, an object of mass 10kg is moving with a velocity 2ms-¹. The kinetic energy can be calculated as follows:

K.E = ½ × 10 × 2²

K.E = 20J

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The kinetic energy of the object of mass 10 Kg moving with a velocity 2 ms¯¹ of is 20 J

How do I determine the kinetic energy of the object?

Kinetic energy of an object is simply defined as the energy of the object in motion. Mathematically, it can be written as:

KE = ½mv²

Where

KE is the kinetic energy of the objectm is the mass of the objectv is the velocity of the object

Using the above formula, we shall determine the kinetic energy of the object. Details below:

Mass of object (m) = 10 KgVelocity of object (v) = 2 ms¯¹Kinetic energy of object (KE) =?

KE = ½mv²

KE = ½ × 10 × 2²

KE = 5 × 4

KE = 20 J

Thus, we can conclude from the above calculation that the kinetic energy is 20 J

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Determine the missing side

Answers

Answer:

3. 30m

4. 25m

5. 36m

Explanation:

See picture

a roller coaster cart starts from rest and accelerates, due to gravity, down a track. the cart starts at a height that enables it to complete a loop in the track the magnitude of the centripetal force keeping the cart in circular motion would be greatest at point

Answers

A roller coaster cart starts from rest and accelerates, due to gravity, down a track. the cart starts at a height that enables it to complete a loop in the track the magnitude of the centripetal force keeping the cart in circular motion would be greatest at point

The magnitude of the centripetal force keeping a roller coaster cart in circular motion is given by the equation F = mv^2/r, where m is the mass of the cart, v is its velocity, and r is the radius of the circle it is moving in. At the point where the magnitude of the centripetal force is greatest, the velocity of the cart is highest and the radius of the circle is smallest. This point is typically at the bottom of the loop, where the track is closest to the ground and the velocity is greatest. Hence, the magnitude of the centripetal force keeping the roller coaster cart in circular motion would be greatest at the bottom of the loop.

What the Meanning of Circular Motion?

Circular motion is a movement of an object along the circumference of a circleor rotation along a circular path. It can be uniform, with constant angular rate of rotation and constant speed, or non-uniform with a changing rate of rotation.

Examples of circular motion include: an artificial satellite orbiting the Earth at a constant height, a ceiling fan's blades rotating around a hub, a stone which is tied to a rope and is being swung in circles, a car turning through a curve in a race track, an electron moving perpendicular to a uniform magnetic field, and a gear turning inside a mechanism.

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two coherent sources of light of equal strength produce near parallel beams that intersect at a point p. compared to the intensity from just one of the sources, the intensity of the light due to both sources at point p will be select all that apply 1. four times that of a single source. 2. not enough information given. 3. twice that of a single source. 4. in a range from zero to four times that of a single source. 5. in a range from zero to two times that of a single source. I thought the intensity will be twice that of a single point due to the superposition principle. But, apparently I am wrong.

Answers

The intensity of the light due to both sources at point P will be four times that of a single source.

According to the superposition principle, the total intensity of light at a point is equal to the sum of the intensities due to each individual source. Since the two sources are of equal strength, the intensity of the combined light at point P will be twice that of a single source.

However, the light from each source will interfere with each other, resulting in constructive and destructive interference. As two beams are coherent, meaning they have the same frequency and phase, the light waves will add together constructively at certain points, increasing the intensity. So, at point P, the intensity of the light due to both sources will be four times that of a single source.

Hence option 1 is correct.

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While in Earth’s orbit, an 80-kg astronaut carrying a 20-kgtool kit is initially drifting toward a stationary (to her) spaceshuttle at a speed of 2 m/s. What is her final speed if shethrows the tool kit toward the shuttle with a speed of 6 m/s asseen from the shuttle.
Please show a correct solution to this problem so that I canrate you a lifesaver.

Answers

The final speed of the astronaut in this scenario will be 1 m/s toward the shuttle.

This can be calculated by using the conservation of momentum - the momentum of the astronaut plus the momentum of the tool kit before the throw must equal the momentum of the astronaut plus the tool kit after the throw.

Momentum before the throw = (80 kg)(2 m/s) + (20 kg)(0 m/s) = (160 kg m/s) Momentum after the throw = (80 kg)(v) + (20 kg)(6 m/s)

Solving for v gives us v = 1 m/s. Therefore, the astronaut's final speed is 1 m/s toward the shuttle.

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A particle of mass m is travelling along the x-axis such that at t = 0 it is located at x=0 and has a speed Vo. The particle is acted upon by a force which opposes the motion and as
a magnitude proportional to the square of the instantaneous speed find: speed , position, acceleration at any time t=0

Answers

The speed, position and acceleration are V₀ x e⁽⁰⁾, V₀ x 0 + (V₀/k) x (1 - e⁽⁻⁰⁾) = 0 and -k(V₀²)/m respectively.

How to find speed, position and acceleration?

The particle's motion can be described by Newton's second law, which states that the net force acting on an object is equal to its mass times acceleration. If the force acting on the particle is proportional to the square of its speed, then it can be modeled as F = -kv², where k is a constant of proportionality.

At time t = 0, the particle is located at x = 0 and has a speed Vo. The acceleration can be found from Newton's second law as follows:

a = F/m = -kv²/m = -k(V₀²)/m

The velocity of the particle at any time t can be found by integrating the acceleration:

v(t) = V₀ + ∫a(t) dt = V₀ - (k/m) x ∫(V₀²) x e^(-kt) dt = V₀ x e^(-kt)

The position of the particle at any time t can be found by integrating the velocity:

x(t) = ∫v(t) dt = V₀ x t + (V₀/k) x (1 - e^(-kt))

So, the speed, position, and acceleration of the particle at t = 0 are as follows:

Speed: v(0) = V₀ x e⁽⁰⁾ = Vo

Position: x(0) = V₀ x 0 + (V₀/k) x (1 - e⁽⁻⁰⁾) = 0

Acceleration: a(0) = -k(V₀²)/m = -k(V₀²)/m.

Note: The actual values for the speed, position, and acceleration of the particle at any time t will depend on the specific values of the mass m, the initial speed V₀, and the constant of proportionality k.

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2 In an oscillation experiment with the spiral spring, the time taken for 30 oscillations with
different masses were measured and the result tabulated below.
M (g)
100
200
300
400
500
600
e (cm)
4.10
8.10
12.00
16.00
20.10
24.00
t(s)
13.40
18.30
21.50
25.00
27.50
30.00
T(S)
T² (5²)
(a) Using two separate graph sheets, plot graphs of M against e and M against 7²
(b) Determine the slopes of the two graphs and their standard errors.
(c) Given that M=ke and T = 2,
M+mo, where k is the spring's force constant and mo is a
kg
constant, deduce the value of k and g from your graphs and give their S.I. units

Answers

According to Hooke's Law, the force given to a spring causes it to stretch directly in proportion.

Using a spiral spring, how do you determine the acceleration brought on by gravity?There is a restoring force Mg=xng when a mass, M, coupled to the spring extends it by a distance, x. Here, n=extensionload (n is the slope of the first graph you will construct), and g=gravitational acceleration The spring's effective mass, m, can be found by looking at the T2 vs. load graph's x-intercept.According to Hooke's Law, the force given to a spring causes it to stretch directly in proportion. (Engineers assert that stress and strain are inversely related.) F represents the force, x is the stretch, and k is a proportionality constant. These three terms are represented by the symbols F = kx.    

The complete question is,

What was the experiment's finding about spiral springs?

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A positive feedback loop is a physiological process designed to push the body beyond a physiological level to a determined endpoint. O True O False

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The given statement about “A positive feedback loop is a physiological process designed to push the body beyond a physiological level to a determined endpoint” is true because during positive feedback, a physiological system encourages the change.

A positive feedback loop in a human-related system is described as a system responding in such a way that an idea or action has a positive influence on the idea or action that sparked the loop in the first place. In natural systems, the presence of a positive feedback loop can magnify or exaggerate the consequences of a very modest disruption or change, which then become mutually reinforcing and cause the system to react. This is in contrast to a system having a negative feedback loop, in which the change or disturbance is mitigated or self-corrected as the system returns to its original equilibrium rather than responding exponentially.

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An object is thrown straight down with an initial speed of 4 m/s from a window which is 8 m above the ground. The time it takes the object to reach the ground is:
A. 0.80 s
B. 0.93 s
C. 1.3s
D. 1.7s
E. 2.0s

Answers

The time it takes an object to fall to the ground can be calculated using:

t = √(2 * d / g)

t = √(2 * 8 / 9.8) = √(16 / 9.8) = √(1.6326530612244898) = 1.27

So, the nearest answer to the value is C, which is 1.3s.

What is gravitaional force?

Gravitational force of attraction between any two masses in the universe. It was first described by Newton in his law of universal gravitation, which states that every particle in the universe attracts every other particle with a force proportional to the product of their masses.

How can one calculate gravitational force?

You can calculate gravitational force by:

F = G * (m1 * m2) / r^2, where F is the force of gravity, G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.

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A stone of mass 4.0kg is pulled along a horizontal path by a rope which makes an angle of 30 with the horizontal. Neglecting friction, calculate the tension in the rope if the body accelerates uniformly at 2m/s2​

Answers

Answer:

9.24 N

Explanation:

The force accelerating the 4 kg body is the horizontal force = T cos 30

F= ma       so:

T cos 30 = 4 kg ( 2 m/s^2)

T = 8 / cos (30) = 9.24 N

the response to a question has three alternatives: a, b, and c. a sample of 120 responses provides 60 a, 12 b, and 48 c. show the frequency and relative frequency distributions. class frequency relative frequency a b c total

Answers

The total frequency is 120 1.

The frequency of each response category is the number of times it occurs in the sample. The relative frequency of each response category is the fraction of the total responses that belong to each category.

Class Frequency Relative Frequency

a 60 60/120 = 1/2

b 12 12/120 = 1/10

c 48 48/120 = 2/5

Total 120 1

Therefore, the frequency and relative frequency distributions of the responses are:

Class Frequency Relative Frequency

a 60 1/2

b 12 1/10

c 48 2/5

Total 120 1

Frequency refers to the number of times a particular event or item occurs in a set of data. It is a measure of how often an event or item appears in a data set. In statistical analysis, frequency is used to describe the distribution of a set of data, such as the number of occurrences of a particular value, category, or event. Frequency can be expressed as an absolute number or as a proportion or percentage of the total number of events or items in the data set. Frequency is an important concept in statistics and data analysis, as it provides a way to summarize and describe the patterns and relationships within a data set.

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Each of the following statements is related to conductors in electrostatic equilibrium. Choose the words that make each statement correct. (i) The net charge is always zero [(a) inside; (b) on] the surface of an isolated conductor, (ii) The electric field is always zero [(c) inside; (d) just outside] a perfect conductor, (iii) The charge density on the surface of an isolated, charged conductor is highest where the surface is [(e) sharpest; (f) smoothest].

Answers

(i) The net charge is always zero (a) inside a conductor in electrostatic equilibrium.

(ii) The electric field is always zero (c) inside a perfect conductor in electrostatic equilibrium.

(iii) The charge density on the surface of an isolated, charged conductor is highest where the surface is (e) sharpest.

Charged conductors create the state of electrostatic equilibrium, when the surplus charge has properly repositioned itself to lower the overall strength of the repelling forces.

Charges in a conductor react swiftly to attain a constant state known as electrostatic equilibrium when an excess of charge is applied to the conductor or the conductor is placed in a static electric field.

The following formula, ϕ = ∮ E ⋅ d A \phi = \oint {E \cdot dA} ϕ=∮E⋅dA, which is the integral of the dot product of the electric field (E) and the area of the conductor (A), states that electrostatic equilibrium will be reached in the presence of the magnetic field where the surface is perpendicular.

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A ball of mass 2kg is launched upward with a velocity of 5m/s. Calculate the height when the ball stops moving. (PLEASE HELP i dont understand this and this is due tmr pls do it step by step!!)

Answers

The ball of mass 2kg launched upward with a velocity of 5m/s will go underground 25/49 meters.

How are the equations of motion used to calculate the height?

To calculate the height when the ball stops moving, we need to use the equations of motion for an object in free fall under the influence of gravity.

The first step is to determine the acceleration of the ball due to gravity, which is given by the equation: a = -g, where g is the acceleration due to gravity (approximately 9.8 m/s²on the surface of the Earth) and the negative sign indicates that the acceleration is downward. So, a = -9.8 m/s²

Next, we can use the equation: v² = u² + 2as , where v is the final velocity, u is the initial velocity, and s is the distance traveled. Since the final velocity of the ball is zero, we can substitute v = 0 and u = 5 m/s.

Now we can solve the equation for s: 0 = (5 m/s)² + 2(-9.8 m/s²)s

Once we solve for s, we get: s = -(5 m/s)² / (2 × -9.8 m/s²) = 25/49 m

Since the ball is moving upward, the negative sign in the equation means that the height is negative, so the height when the ball stops moving is -25/49 meters.

It's important to remember that the negative height means that the ball goes below the point where it was launched, it goes into the ground.

In summary, the ball of mass 2kg launched upward with a velocity of 5m/s will go underground 25/49 meters.

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Why would the weight of a landing module be different on different planets?(1 point)
Responses

a. The landing module’s mass is different on different planets.
b. Planets have different diameters
c. Gravitational force is different on different planets.
d. Planets are different distances from the Sun.

Answers

The weights of the objects are different because Gravitational force is different on different planets. Option C

What is the acceleration due to gravity?

We have to note that the acceleration due to gravity is what tell us the extent of the gravitational pull that is on a planet. The value of the acceleration  due to gravity is not the same in all the planet.

This implies that the magnitude of the gravitational force in all the planets that we know can not be the same and as such the masses of the objects in the various planets would not be the same.

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Lasers can be used to drill or cut material. One such laser generates a series of high-intensity pulses rather than a continuous beam of light. Each pulse contains 540 mJ of energy and lasts 12 ns . The laser fires 10 such pulses per second.

Answers

The laser generates 10 pulses per second, each pulse containing 540mJ of energy and lasting 12 ns.

suppose the pendulum bob in (figure 1) has a mass of 0.23 kg and is moving to the right at point b with a speed of 2.3 m/s . air resistance is negligible.what is the change in the system's gravitational potential energy when the bob reaches point a?

Answers

The change in the system's gravitational potential energy when the bob reaches point a is equal to the work done by the gravitational force.

What is the change in the system's gravitational potential energy when the bob reaches point a?Since the bob is moving from point b to point a, the work done by the gravitational force is negative.The work done by the gravitational force is given by W = -mgh, where m is the mass of the bob, g is the acceleration due to gravity, and h is the height difference between points a and b.In this case, m = 0.23 kg, g = 9.8 m/s^2, and h = 0.2 m.Therefore, the change in the system's gravitational potential energy when the bob reaches point a is W = -(0.23 kg)(9.8 m/s^2)(0.2 m) = -4.564 J.The change in the system's gravitational potential energy when the bob reaches point a is -6.67 J.This can be calculated using the equation PE = mgh, where m is the mass of the bob (0.23 kg), g is the acceleration due to gravity (9.81 m/s2) and h is the change in height (1 m). Thus, PE = 0.23 x 9.81 x 1 = 2.33 J.The change in PE is calculated by subtracting the initial PE (2.33 J) from the final PE (0). Thus, the change in PE is -2.33 J.

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A 0.300−kg puck, initially at rest on a horizontal, frictionless surface, is struck, is struck by a 0.200−kg puck moving initially along the x axis with a speed of 2.00 m/s. After the collision, the 0.200−kg puck has a speed of 1.00 m/s at an angle of θ=53.0o to the positive x axis (see Figure 9.11).
Find the fraction of kinetic energy transferred away or transformed to other forms of energy in the collision.

Answers

97.5% of the initial kinetic energy was transferred away or transformed to other forms of energy in the collision.

The fraction of kinetic energy lost in a collision is equal to 1 minus the fraction of initial kinetic energy that remains after the collision. To calculate this, we need to find the initial and final kinetic energies of the system.

Initial kinetic energy:

KE_i = 0.5 * (0.300 kg + 0.200 kg) * (2.00 m/s)^2 = 0.5 * 0.500 kg * 4.00 m^2/s^2 = 4.00 J

Final kinetic energy:

KE_f = 0.5 * (0.300 kg) * (0.0 m/s)^2 + 0.5 * (0.200 kg) * (1.00 m/s)^2 = 0.5 * 0.200 kg * 1.00 m^2/s^2 = 0.10 J

Fraction of kinetic energy lost:

(KE_i - KE_f) / KE_i = (4.00 J - 0.10 J) / 4.00 J = 0.975 or 97.5%

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6. The cosmological views of the Later Middle Ages held that which of the following was the center of the universe?
a.
The sun.
b.
The earth.
c.
Heaven.
d.
The epicycles.
e.
The moon.

Answers

According to the cosmological views of the Later Middle Ages, the center of the universe was believed to be the Earth. Correct answer: letter B.

This was based on the geocentric model proposed by Claudius Ptolemy, in which the Sun and the planets revolved around a spherical Earth. The epicycles and the moon were also thought to play a role in the geocentric model, but the Earth was considered the center of the universe.

The geocentric model proposed by Claudius Ptolemy was the prevailing cosmological view in the Later Middle Ages, and it held that the Earth was the center of the universe. This view was based on the idea that the Sun and the planets revolved around a spherical Earth, which was thought to be at the center of the universe. The Ptolemaic system also proposed that the epicycles and the moon would play a role in the geocentric model, though the Earth was still considered the center of the universe.

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the asteroid belt is group of answer choices a new fashion accessory being sold by nasa to raise funds for future missions a series of orbital zones around the moon, from which fragments drop down to form craters a region of icy chunks of material beyond the orbit of pluto a zone where rocky chunks orbit between mars and jupiter is a region around the earth from which meteors (shooting stars) are observed to drop

Answers

A region where rocky chunks orbit between Mars and Jupiter.

The asteroid belt is a region located between the orbits of Mars and Jupiter where many small, rocky objects (asteroids) orbit the sun. Here are some key points about the asteroid belt:

Composition: The asteroids in the belt are made of rock and metal, and range in size from small pebbles to objects hundreds of kilometers in diameter.

Formation: The asteroid belt is believed to have formed from leftover material from the early solar system that never coalesced into a planet.

Number of objects: There are estimated to be millions of asteroids in the belt, with thousands that have been studied and cataloged by astronomers.

Importance for scientific study: Studying the asteroids in the belt can give us insight into the formation and evolution of the early solar system. Additionally, some asteroids contain valuable minerals that could be mined in the future.

Hazards: While the asteroid belt is far from Earth and poses no immediate threat, collisions between asteroids can sometimes send fragments on a collision course with our planet. This is why it is important to continue to study and monitor the objects in the asteroid belt.

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One atmosphere of pressure is defined as 101.325 kPa. From the answer as below, select the closest approximation to the mass of air above a square meter of the earth​

Answers

Answer:

The answer is 8.73 kPa.

Hope this helped you. Tell me if I am wrong.

I also answered first. Please brainliest if any chance!

Explanation:

You want to test if a new diet medicine helps dogs lose weight. What would be your independent variable?
A) equal amounts of water
B) How much weight is lost
c) the dog
D) The new medicine​

Answers

Answer: A.

Reason: The Independent Variable is a variable that stands alone and isn't changed by the other variables you are trying to measure.

Ways to remember: replace the “I” in Independent with “1” meaning that the independent variable never changes.

A student does an experiment to measure the electrical resistance of a piece of material. The resistance is found to be equal to 236092. The student's lab partner then measures the electrical resistance of the same material and gets a value of 251092 for the electrical resistance. What is the percent difference between these two

Answers

The percent difference between the two measurements is 61.9%.

The absolute value of change is divided by the average of the values to generate the percent difference formula, which is then multiplied by 100.

The ratio of the difference between two values to their average, represented as a percentage, is what is referred to as the percentage difference.

The difference between two amounts of the same sort can be expressed in this fashion.

It is determined by applying the following equation: |Difference/Average| × 100%.

To calculate the percent difference between the two measurements, you can use the formula:

Percent difference = (|measurement 1 - measurement 2| / ((measurement 1 + measurement 2) / 2)) * 100

Plugging in the values from the experiment:

Percent difference = (|236092 - 251092| / ((236092 + 251092) / 2)) * 100

= (150,000 / 243,092) * 100

= 61.9%.

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Which equation can you use to calculate the mechanical advantage of a simple machine

Answers

Answer:

MA=Fo/Fi

Explanation:

you throw a ball vertically up from the roof ledge of an apartment building with an initial speed of 10 m/s. the ball travels upward, stops (why?), travels downward and continues past the roof all the way to the ground. (note: you may approximate the gravitational acceleration as 10 m/s/s.)

Answers

When we through a ball  vertically upwards from the roof ledge of an apartment building, the ball stops due to the acceleration due to gravity acting downwards on the ball.

The ball travels upward with an initial speed of 10 m/s, slows down due to the force of gravity (approximated as 10 m/s²), and eventually reaches its maximum height when its upward velocity becomes zero. At this point, the ball stops and is in a state of free fall.

After stopping, the ball then begins to travel downward due to the force of gravity, increasing its downward velocity, past the roof and falls to the ground.

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a subway train starts from rest at a station and accelerates at a rate of 1.60m/s21.60m/s2 for 14.0 ss . it runs at constant speed for 70.0 ss and slows down at a rate of 3.50m/s23.50m/s2 until it stops at the next station. Find the total distance covered.

Answers

The total distance covered by the subway train until is start from rest and again comes to rest is 435.36m.

The subway train starts from rest, and it accelerates to 1.6m/s² for 14s and after running for constant speed for about 70s and then it slows down at a rate of 3.5 m/s².

Now, while accelerating,

S = Ut + 1/2at²

U is initial speed, a is acceleration and t is time.

Putting values,

S = 1/2 x 1.6 x 14

S = 11.2m

Now,

V² - U² = 2aS

V is the constant speed,

V = √(2 x 1.6 x 11.2)

V = 5.98 m/s.

Distance covered with constant speed = 5.98 x 70

Distance S' covered with constant speed = 419.06 m.

Now, while the train slow down,

2a'S'' = V² - (0)²

a' = 3.5 m/s²

S'' = 5.10m

So, the total distance covered by the train will be (5.10 + 419.06 +11.2)m

The total distance covered by the train is 435.36 m.

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The site now places a weigin of 0.39 N on top of the block of wood. She then starts to pour ell into the measuring cylinder. The rule balances again when there is 60 cm3 of oil in the measuring cylinder. The gravitational field strength g is 10 N/kg.
(a) Calculate (i) the weight of the oil in the cylinder,
(ii) the mass of the oil in the cylinder.
Fig. 5.1 (b) Calculate the density of the oil.​

Answers

a) (i) The weight of the oil in the cylinder can be calculated using the formula: weight = mass * g. The mass of the oil can be calculated using the density and volume of the oil.

Density (ρ) = mass/volume
mass = ρ * volume

The volume of the oil in the cylinder is 60 cm3, and since 1 cm3 = 0.001 liters, the volume in liters is 0.06 liters. The density of the oil is not given, so we can't find the mass of the oil.

(ii) To find the mass of the oil, we can use the formula:
mass = weight / g
mass = 0.39 N / 10 N/kg
mass = 0.039 kg

b) To find the density of the oil, we can use the formula:
density = mass / volume
density = 0.039 kg / 0.06 liters
density = 0.65 kg/liter

(a)

(i) The weight of the oil in the cylinder can be calculated using the formula: weight = force = mass * gravitational field strength.

Given that the gravitational field strength is 10 N/kg, and the volume of oil is 60cm^3 we can find the mass of oil by using the formula of density=mass/volume

density=mass/volume

mass=densityvolume

mass=100060

mass=60000g

so the weight of the oil in the cylinder is:

weight = mass * gravitational field strength

weight = 60000g * 10 N/kg

weight = 600000 N

(ii) The mass of the oil in the cylinder can be calculated using the formula: mass = weight / gravitational field strength

mass = 600000 N / 10 N/kg

mass = 60000g

(b) The density of the oil can be calculated using the formula: density = mass/volumemass / volume

density = 60000g / (60 cm^3)

density = 1000 kg/m^3

So, the density of the oil is 1000 kg/m^3.

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The picture to the right represents the effect of tension on the
earth's crust. Faults and rift valleys are the result of movement in
the crust. What type of force causes these movements in the
plates?
a. Balanced forces
b. Unbalanced forces
c. Inertia
d. Friction

Answers

The type of force that causes these movements in the plates is unbalanced forces.

option B.

What is unbalanced force?

When the resultant force acting on a body is not equal to zero, the forces acting on the body are known as unbalanced forces.

The unbalanced force between the upper plates and lower plates of Earth creates movement within the earth crust.

Thus, the faults and rift valleys are the result of movement in the crust, caused by the unbalanced forces or unequal forces that exist between the upper plates and the lower plates of the Earth's crust.

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Complete the following statement: different types of collisions between interacting bodies are CATEGORIZED on the basis of a) kinetic energy conservation b) mechanical energy conservation c) linear momentum conservation a) kinetic energy conservation

Answers

Correct! Different types of collisions between interacting bodies are categorized on the basis of kinetic energy conservation.

There are three types of collisions depending on whether kinetic energy is conserved or not: elastic collisions, inelastic collisions, and completely inelastic collisions.

Different types of collisions between interacting bodies can be categorized on the basis of kinetic energy conservation. Elastic collisions occur when kinetic energy is conserved, inelastic collisions occur when kinetic energy is not conserved, and completely inelastic collisions occur when kinetic energy is completely transferred to other forms of energy such as heat or sound.

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