the coordinates of point are (-3,5). what are the coordinates of point B, which is a reflection of point A across the x-axis?

The upper limit is 0.79

The class interval's upper limit is its highest value. Similarly, the lower limit is the class interval's smallest value.

Given that n = 200 and standard deviation  σ = 0.025

σ = (√n/√n)  = 0.025

Now calculate p

P = defectives/total inspected

= 145/200

P = 0.72

Q= 1-p

= 1- 0.72

= 0.18

Now calculate the upper limit

UCL = p – (-3 x σ)

= 0.72 – ( -3 x 0.025)

= 0.72 – (-0.075)

= 0.72 + 0.075

= 0.795

= 0.79

Therefore the upper limit is 0.79

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Using the concepts of probability, we got that book is independent variable in the experiment in which I randomly assign one group of angelenos to read a book about the history of the Seattle supersonics, and the other to read a book about cheese.

The independent variable is the condition that you actually change in an experiment. It is the variable you control. It is known as independent because its value does not depend on the value and is not affected by the state of any other variable in the experiment.

Hence, when  i randomly assign one group of Angelenos to read a book about the history of the Seattle supersonics, and the other to read a book about cheese and  then give them a quiz about basketball history (including recent events such as the Los Angeles Lakers then  the independent variable in this experiment is the book given by me.

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An equation to determine the original price of the lawnmower discounted at 9% to $1,517.74 is B. y = 0.91x.

An equation summarizes a mathematical statement that equates two or more mathematical expressions.

Equations operate with values, numbers, and variables, using the equation symbol (=) and mathematical operands to establish the equality of values.

Discount offered = 9%

Amount paid for a lawnmower = $1,517.74

Original price = x

Discounted price, y = 0.91x

Y = 0.91x

1,517.74 = 0.91x

x = 1,667.85

Thus, the original price of the lawnmower is determined by Equation B.

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There are no pair of numbers that multiply to 36 and add up to -7

The factors of number refers to any of various numbers multiplied together to form some whole. For instance, 3 is a factor of 12, as are 2, 4 and 6.

The pairs of factors of 36 that multiply to 36 are:

From the pair of numbers above, none add up to -7

Therefore, there is no pair of numbers whose product is 36 and sum is -7

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The attendant at a parking lot compared the number of hybrid vehicles to the total number of vehicles in the lot over a weekend.

Day      hybrids    total

Fri           5             9

sat                         63

sun         40            

we need to find number of hybrids in sat and total in sun.

Number of hybrids in sat = 5*7 = 35(ratios are equal)

Total in sum = 9*8 = 72.

Day      hybrids    total

Fri           5             9

sat          35           63

sun         40           72

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[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{2}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{(-4)}}} \implies \cfrac{2 +1}{8 +4} \implies \cfrac{ 3 }{ 12 } \implies \cfrac{1 }{ 4 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{ \cfrac{1 }{ 4 }}(x-\stackrel{x_1}{(-4)}) \implies y +1 = \cfrac{1 }{ 4 } ( x +4) \\\\\\ y+1=\cfrac{1 }{ 4 }x+1\implies {\Large \begin{array}{llll} y=\cfrac{1 }{ 4 }x \end{array}}[/tex]

The likelihood that the sample mean time required to finish the exam will be less than 47.5 minutes is 0.566.

Given;

The average amount of time needed to finish an exam is 45 minutes, with a standard deviation of 15 minutes. The average amount of time required for 100 randomly chosen pupils is calculated.

Mean (μ) = 45

Standard deviation (σ) = 15

Here, σ/√n = 15/√100

                   = 1.5

To get the probability the sample mean time necessary to complete the examination is less than 47.5 minutes, we need;

P (x < 47.5) = P(z < (x-μ /σ/√n ) )

                  = P(z < 47.5 - 45/1.5)

                  = P(z < 17.5)

                  = 0.566

The probability the sample mean time necessary to complete the examination is less than 47.5 minutes is 0.566

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The ratio 120/150 represented in the simplest form is 4 : 5 .

The given ratio is 120 /150 .

Now if we write the expression in the form of the simplest ratio we have to divide the ratio by the highest common factor.

The HCF of the number is 30. Hence the ratio in simplest form will be

120÷30 : 150÷30 = 4 : 5 .

By comparing two amounts of the same unit and establishing the ratio, we can work out how much of one quantity is contained in the other. Two categories of ratios exist.

Ratio can be thought of as an ordered pair of integers, a fraction with the first number in the numerator and the second in the denominator, or as the value that this fraction represents.

Ratios of counts are rational numbers that can also be rational numbers and are occasionally expressed by (non-zero) natural numbers.

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The simplest radical form of  √(11/(x + 4)) when x is 16 is; ¹/₁₀√55

Surds are actually the expressions of the number, and often use radicals. Meanwhile, the radical is just the symbol used to express the square root.

We are given the expression of the surd as;

√(11/(x + 4))

We want to solve this for when x = 16. Thus, we plug in 16 for x in the surd to get;

√(11/(16 + 4))

= √(11/20)

Now, we can rewrite the fraction in the bracket to have the denominator as a perfect square by multiplying both numerator and denominator by 5 to get;

√(55/100)

Square root of 100 is 10 and as such we now have;

√(55/100) = ¹/₁₀√55

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The amount of honey that Bert’s new beehive hold would be; 200.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Given data that the Number of frame beehive = 6

The Pound of honey = 40

The Current Frame beehive = 30

First step is to formulate an equation and then use the formulated equation;

40 × 30 ÷ 6

Hence, 40 × 5

= 200 honey

Therefore, the number of honey would be; 200.

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Answer:

Prime

Step-by-step explanation:

Because this number is only divisible by itself and no other number.

Problem 13

Reason:

If a > 0, then the statement would always be true. However, if 'a' was negative, then the statement is false.

For example, if a = -2 then:

[tex]a^{-1} = (-2)^{-1} = \frac{1}{(-2)^1} = -\frac{1}{2} = -0.5[/tex]

In short,

[tex]a^{-1} = -0.5 \ \ \text{ when } a = -2[/tex]

This is one of infinitely many counter-examples to prove the original statement isn't always true.

===================================================

Problem 14

Reason:

The rule to use here is [tex]a^b*a^c = a^{b+c}[/tex]

We add exponents b and c, while the base 'a' stays the same the whole time.

In this problem we have: [tex]3^n*3^{-n} = 3^{n+(-n)} = 3^{n-n} = 3^0 = 1[/tex]

Therefore [tex]3^n*3^{-n} = 1[/tex] is always true regardless of what you replace n with. The variable n doesn't have to be an integer.

===================================================

Problem 15

Reason:

Let's say p = -1 is plugged into the expression

[tex]6^p = 6^{-1} = \frac{1}{6^1} = \frac{1}{6} \approx 0.1667[/tex]

which is a positive outcome showing that [tex]6^p > 0[/tex] doesn't automatically guarantee that p > 0. Feel free to try other negative values as counter-examples. Also p = 0 works as well. It turns out that [tex]6^p[/tex] is always positive regardless of what real number you use for p.

===================================================

Problem 16

Reason:

The rule used here is [tex]a^{-b} = \frac{1}{a^b}[/tex]

An equivalent rule is [tex]\left(\frac{a}{b}\right)^{-c} = \left(\frac{b}{a}\right)^c[/tex]

The idea is to flip the fraction to turn the exponent positive.

Examples: [tex]2^{-5} = \frac{1}{2^5} \ \ \text{ and } \ \ \left(\frac{7}{9}\right)^{-3} = \left(\frac{9}{7}\right)^{3}[/tex]

===================================================

Problem 17

Reason:

This is similar to problem 15 in that [tex]2^m[/tex] is always positive regardless if m is negative, zero, or positive. It might help to graph out [tex]y = 2^x[/tex] and see that the curve never dips below the x axis.

-x/y is equivalent to x/-y according to the division rule a/b*d/c=a/b*c/d.

In division, a number is divided, which is an easy operation. In mathematics, division is the division of a sum into equal parts. A group of 20 people, for instance, could be divided into four groups of 5, five groups of 4, and so on. Division's opposite is multiplication. If 3 groups of 4 add up to 12, then 4 are in each group when 12 is divided into 3 equal groups.

According to the division rule a/b/c/d=a/b*d/c, 

=1/(y/-x)

=1*-x/y

=-x/y

-x/y is equivalent to x/-y according to the division rule a/b÷c/d=a/b*d/c.

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The area of a bull's eye is equal to: B. 452.39 mm².

The area of a circle simply refers to the region enclosed or space occupied by a circle within its boundary, and in a two-dimensional plane.

Mathematically, the area of a bull's eye can be calculated by using this formula:

Area of bull's eye = πr²

Where:

r is the radius of a circle.

Note: The radius of the bull's eye is equal to 12 mm and π = 3.14159.

Substituting the given parameters into the formula, we have;

Area of bull's eye = π × (12)²

Area of bull's eye = 3.14159 × 144

Area of bull's eye = 452.39 mm².

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Answer:

answer. {-2187x}/{625}

Answer: 8

Step-by-step explanation:

7.69 to the nearest whole number is 8

It is false that " finding a random sample with a mean this low in a population with mean 7 and standard deviation 2 is very unlikely".

The term "standard deviation" (or "") refers to a measurement of the data's dispersion from the mean. A low standard deviation indicates that the data are grouped around the mean, whereas a high standard deviation shows that the data are more dispersed. The average degree of variability in your data set is represented by the standard deviation. It reveals the average deviation of each score from the mean. The standard deviation gauges how widely the data deviates from the mean. When comparing data sets that may have the same mean but a different range, it is helpful. The mean of the two numbers 15, 15, 15, 14, 16 and 2, 7, 14, 22, 30 for instance, is the same. The second, however, is obviously more dispersed.

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The value of x is 22.5528.

Let ABC be the triangle , <A = 70, <B = 30 ,<C = 80.

Sum of angles in a triangle is 180.

70 + 30 + <C = 180

<C = 180 - 100

<C = 80.

Let sides be a = x , b = 12 and c = ?

According to sines law,

a/sin A = b/sin B = c/sin C

substitute a ,b,A,B values

a/sin A = b/sin B

x/sin 70 = 12/sin 30

x = 0.9397*12/1/2

= 11.2764*2/1

x = 22.5528.

Therefore the value of x is 22.5528.

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Answer:

2:1

Step-by-step explanation:

.5 kg : 250g

the units must be same at both sides

500g : 250g

{as 1 kg = 1000g}

by simplifying both sides

10g : 5g

2g : 1g

2:1

Answer:

a) y = 0

Step-by-step explanation:

Given equation,

→ 3y - 7(y + 5) = y - 35

Now the value of y will be,

→ 3y - 7(y + 5) = y - 35

→ 3y - 7y - 35 = y - 35

→ -4y - y = -35 + 35

→ -5y = 0

→ y = 0/-5

→ [ y = 0 ]

Hence, the value of y is 0.

Answer:

Step-by-step explanation: The constant growth for Plant A is two cm a month and the growth of Plant B is also two cm a month.

In relation, Plant B will also be 3cm taller than Plant A on any month so when Plant A is 49cm, Plant B is 52.

When Piece A's height is 49 cm then the Piece B's height will be 52 cm.

Statistics is the discipline that concerns the collection, organization, analysis, interpretation, and presentation of data.

We can see that Piece A's height increases by 2 cm each month and Piece B's height increases by 2 cm each month as well.

To find out what Piece B's height will be when Piece A's height is 49 cm, we need to find how many months it will take for Piece A to reach 49 cm.

From Month 1 to Month 2, Piece A's height increased by 2 cm, and from Month 2 to Month 3, Piece A's height increased by another 2 cm. Therefore, Piece A's height increases by 2 cm per month.

To go from 28 cm (Piece A's height in Month 3) to 49 cm, it takes 21 cm ÷ 2 cm/month = 10.5 months.

So 10.5 months after Month 3 is Month 13.5.

In Month 13.5, Piece A's height will be 49 cm and Piece B's height will be:

Piece B's height in Month 3 + 2 cm/month × (13.5 - 3 months)

= 31 cm + 2 cm/month × 10.5 months

= 52 cm

Therefore, when Piece A's height is 49 cm, Piece B's height will be 52 cm.

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Function g(x) have 3 x intercepts.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The function f(x) = (x + 5)(x-3) is dilated by x to produce the function

the function g(x) = x f(x).

A dilation is a transformation which preserves the shape and orientation of the figure, but changes its size

g(x)=x(x + 5)(x-3)

=x(x²-3x+5x-15)

=x(x²+2x-15)

x=0, x=-5 and x=3

The function g(x) have 3 x intercepts.

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Answer:

x = -12

Step-by-step explanation:

Get X all on one side

7x - 8x = 8x - 8x + 12

-x = 12

x = -12

Answer:

x = -12

Step-by-step explanation:

To solve this, you will need to get all of the variables on one side, and the 12 on the other. You will subtract 8x from both sides to get the equation -x = 12. You can then divide both sides by -1 to get the x alone, and thus you get x = -12.

Answer:

x^5

Step-by-step explanation:

Answer:

Step-by-step explanation:

15 ile 25 arasında toplam 10 tam sayı var,
buna 25-15=10 şeklinde ulaşabiliriz. Ardından tek sayılar sorulduğu için ve bu 10 tam sayı içerisinde hem tek hemde çift olduğu için sayıyı ikiye böleriz
10/2=5 ve ardından en sonda bulunan 25 sayısını çıkarırız yani, 5-1=4

cevaplar: 17, 19,21,23

Answer:

Step-by-step explanation:

the answer is 86

hope it helps!

(-_-)

[tex]\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{"y" varies with "x"}}{y=kx}\hspace{5em}\textit{we know that} \begin{cases} y=-4\\ x=10 \end{cases}\implies -4=k(10) \\\\\\ \cfrac{-4}{10}=k\implies -\cfrac{2}{5}=k\hspace{10em}\boxed{y=-\cfrac{2}{5}x} \\\\\\ \textit{when x = 2, what is "y"?}\qquad y=-\cfrac{2}{5}(2)\implies y=-\cfrac{4}{5}[/tex]