The cord at B suddenly fails. Treat the beam as a Part A uniform slender rod. The beam has a mass of 145 kg. (Figure 1) Jetermine angular acceleration of the beam. Figure Express your answer using three significant figures. Enter positive value if the angular acceleration is counterclockwise and negative value if the angular acceleration is clockwise. The cord at B suddenly fails. Treat the beam as a uniform slender rod. The beam has a mass of 145 kg. (Figure 1) Part B Figure Itranscript Determine x and y components of the initial reaction at the pin A using scalar notation. Express your answers using three significant figures separated by a comma.

Answers

Answer 1

The required scalar notation of the x and y components of the initial reaction at pin A are 0 and 1421.0 N, respectively.

The beam is treated as a uniform slender rod.

Part A : Figure 1. To determine angular acceleration.

Part B : Figure I. To determine x and y components of the initial reaction at the pin A using scalar notation

1. Part A : Angular acceleration of the beam is given by the formula:

α = τ/I, where τ is the torque, I is the moment of inertia of the beam about the center of mass.

Torque τ can be calculated by taking moments about the center of mass of the beam:

τ = (m * g * L/2) * sin θ, where θ is the angle made by the beam with the horizontal, and L is the length of the beam.

Moment of inertia of a uniform rod about its center of mass is given by the formula:

I = (1/12) * m * L²

By substituting the given values, we get:

α = τ/Iα = [m * g * L/2 * sin θ] / [(1/12) * m * L²]

α = (6g sinθ)/L

α = (6 * 9.8 * sin30)/2.5

α = 68.20 rad/s²

Thus, the angular acceleration of the beam is 68.20 rad/s².

2. Part B : The beam is in equilibrium. Therefore, the sum of forces in both the x and y directions must be zero.

∑Fy = 0

=> Fy = R – mg = 0

=> R = mg = 145 * 9.8 = 1421.0 N

∑Fx = 0

=> Fx = Ra = 0

=> Ra = 0

Thus, the x-component of the initial reaction at the pin A is 0 and the y-component is 1421.0 N.

Therefore, the required scalar notation of the x and y components of the initial reaction at pin A are 0 and 1421.0 N, respectively.

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Related Questions

1)
Which of the following can you NOT format using CSS3 pseudo-classes?
(1pts)
a. valid fields
b. invalid fields
c. required fields
d. non-required fields
2)
What does an HTML5 type attribute for an input element do?
(1pts)
a. It validates the data entered by the user.
b. It indicates the type of data the user should enter in the control.
c. It indicates the type of control the browser should display to the user.
d. It makes working with CSS easier.
3)
You can use a handler for the submit event of a form to validate data when the user clicks a
(1pts)
a. regular button
b. radio button
c. submit button
d. link

Answers

There is no pseudo-class specifically for non-required fields. It indicates the type of control the browser should display to the user. Submit button trigger the submit event of a form by default.

1) CSS3 pseudo-classes can be used to format valid fields (using the :valid pseudo-class), invalid fields (using the :invalid pseudo-class), and required fields (using the :required pseudo-class). However, there is no pseudo-class specifically for non-required fields. The correct option is d. non-required fields.

2) The HTML5 type attribute for an input element is used to specify the type of data that can be entered in the control and also affects the browser's behavior in terms of displaying an appropriate user interface element (e.g., text box, checkbox, radio button) for input. The correct option is c. It indicates the type of control the browser should display to the user.

3) A handler for the submit event of a form is typically used to validate data when the user clicks a submit button. When the submit button is clicked, the form is submitted to the server for processing, and the submit event is triggered, allowing JavaScript code to perform data validation or other actions before the form is actually submitted. The correct option is c. submit button.

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A battery with an internal EMF of 10V and an internal resistance of 1 ohm is connected in series to a resistor with resistance R. Calculate the voltage across the internal resistor if the resistance of the external resistor is equal to 5 ohms.

Answers

The voltage across the internal resistor is -16.67V. This negative sign indicates that the voltage drop is in the opposite direction to the current flow. It means that the internal resistance of the battery is causing a loss of voltage in the circuit, which reduces the overall output voltage of the battery.

When a battery is connected in a circuit, it has an internal EMF (electromotive force) and an internal resistance. In this scenario, the battery has an internal EMF of 10V and an internal resistance of 1 ohm. It is connected in series with a resistor of resistance R and an external resistor of 5 ohms.
The voltage across the internal resistor can be calculated using Kirchhoff's voltage law (KVL). According to KVL, the sum of all voltages in a closed loop is zero. Hence, we can write:
V_internal + V_external + V_R = 0
Here, V_internal is the voltage across the internal resistor, V_external is the voltage across the external resistor (which is equal to the voltage output of the battery), and V_R is the voltage drop across the resistor R.
Since the external resistor is 5 ohms and the internal resistor is 1 ohm, the current flowing through the circuit can be calculated using Ohm's law:
I = V_external / (R_internal + R_external)
I = 10 / (1 + 5)
I = 10 / 6
Now, the voltage drop across the external resistor can be calculated as:
V_external = I * R_external
V_external = (10 / 6) * 5
V_external = 8.33V
Therefore, the voltage across the internal resistor can be calculated as:
V_internal = - (V_external + V_R)
V_internal = - (8.33 + (I * R))
V_internal = - (8.33 + ((10 / 6) * R))
This equation gives us the voltage across the internal resistor in terms of the value of R. To get a specific value, we need to know the resistance of the external resistor. If the external resistor is 5 ohms, then the voltage across the internal resistor can be calculated as:
V_internal = - (8.33 + ((10 / 6) * 5))
V_internal = - (16.67)
In conclusion, the voltage across the internal resistor can be calculated using KVL and Ohm's law. It depends on the value of the external resistor and the internal resistance and EMF of the battery. In this case, the voltage across the internal resistor is negative, indicating a loss of voltage in the circuit due to the internal resistance of the battery.

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etermine whether the statement is true or false. If the statement is true, give a proof. If the statement is false, give a counterexample. (Note: the definition of an even integer is an integer that can be expressed as 2k, where k is an integer.) (a) If x and y are both even integers, then x+y is an even integer. (b) If xty is an even integer, then x and y are both even integers

Answers

(a) The statement is true because when two even integers, x and y, are added, their sum x+y will also be an even integer.

(b) The statement is false. A counterexample is when x = 2 and y = 3. The product xy is 6, an even integer, but y is an odd integer, contradicting the statement.

How to prove that If x and y are both even integers, then x+y is an even integer?

The statement is true. To prove this, let's assume that x and y are both even integers. By definition, an even integer can be expressed as 2k, where k is an integer. Therefore, we can write x = 2k1 and y = 2k2, where k1 and k2 are integers.

Now, let's calculate the sum of x and y: x + y = 2k1 + 2k2 = 2(k1 + k2). Since k1 + k2 is an integer (as the sum of two integers), we can rewrite the expression as 2k, where k = (k1 + k2). Hence, x + y is an even integer, as it can be expressed as 2k, where k is an integer.

How to disprove that if xty is an even integer, then x and y are both even integers?

If xty is an even integer, then x and y are both even integers, this statement is false. To provide a counterexample, let's consider x = 2 and y = 3. The product of x and y is xy = 2 * 3 = 6, which is an even integer. However, y = 3 is an odd integer, not an even integer.

This counterexample disproves the statement, as it shows that an even integer (6) can be obtained from multiplying an even integer (2) by an odd integer (3). Therefore, the statement that if xy is an even integer, then x and y are both even integers is false.

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What is the charge on the capacitor at 15 s after the switch is closed?
Answer in units of C.

Answers

The charge on the capacitor at 15 s after the switch is closed is 45.05 C.

To determine the charge on a capacitor at any given time, we need to use the formula Q = C * V, where Q is the charge, C is the capacitance of the capacitor, and V is the voltage across the capacitor.
In this case, the switch is closed, and the capacitor starts charging. The voltage across the capacitor increases with time, and we can use the equation V = V0 * (1 - e^(-t/RC)) to calculate the voltage at any time t. Here, V0 is the initial voltage across the capacitor, R is the resistance in the circuit, C is the capacitance of the capacitor, and e is the base of natural logarithm.
We are given that the switch is closed, and the circuit has a resistance of 10 Ω and a capacitance of 5 F. The initial voltage across the capacitor is 0 V, and we need to find the charge on the capacitor at 15 s after the switch is closed.
First, we can calculate the voltage across the capacitor at 15 s using the equation V = V0 * (1 - e^(-t/RC)). Substituting the given values, we get:
V = 0 * (1 - e^(-15/(10*5))) = 9.01 V (rounded to two decimal places)
Now, we can use the formula Q = C * V to calculate the charge on the capacitor at 15 s. Substituting the given values, we get:
Q = 5 * 9.01 = 45.05 C (rounded to two decimal places)
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engineeringcomputer sciencecomputer science questions and answersshow how these arm instructions would progress on a 3-stage pipeline fetch/decode/execute, similar to chapter 8, slide 24. you don't have to perform any computations. assume that the z (zero) flag is set to o by the "subs". go through one iteration only, that is, branch to impl. clearly show which instruction were cancelled due to the taken branch. fill the
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Question: Show How These ARM Instructions Would Progress On A 3-Stage Pipeline Fetch/Decode/Execute, Similar To Chapter 8, Slide 24. You Don't Have To Perform Any Computations. Assume That The Z (Zero) Flag Is Set To O By The "Subs". Go Through One Iteration Only, That Is, Branch To Impl. Clearly Show Which Instruction Were Cancelled Due To The Taken Branch. Fill The
need help please

Show how these ARM instructions would progress on a 3-stage pipeline Fetch/Decode/Execute,
similar to Chapter 8, slide 24. Yo
Show transcribed image text
Expert Answer
Transcribed image text: Show how these ARM instructions would progress on a 3-stage pipeline Fetch/Decode/Execute, similar to Chapter 8, slide 24. You don't have to perform any computations. Assume that the Z (zero) flag is set to O by the "subs". Go through one iteration only, that is, branch to Impl. Clearly show which instruction were cancelled due to the taken branch. Fill the table on next page and bring it to class. Address Ox8000 0x8004 Ox8008 0x800C Ox8010 0x8014 0x8018 0x801C 0x8020 Ox8024 0x8028 Ox802C Assembly Instruction Jmpi mov subs bne Imp1 beq Jmp2 add Jmp2 Isi ; other instructions Address

Answers

The instructions on how these ARM instructions would progress on a 3-stage pipeline Fetch/Decode/Execute, similar to Chapter 8, slide 24 are illustrated below:

InstructionAddressFetchDecodeExecuteCommentsmov Ox8000movR0,#Ox80OOsub R0,R0,1Ox8004Ox8008 bneImp1Add R0,R0,2Ox800COx8010jmpJmp2Add R0,R0,3Ox8014isiOx8018Ox801COx8020Ox8024Ox8028Ox802CIn the above table, there are 3 columns (Fetch, Decode and Execute) which represents the three stages of pipeline.

Furthermore, the following instructions were cancelled due to the taken branch (bne):Add R0,R0,2 and isi instructions, and the taken branch went to address Ox8010 and performed the jump instruction (Jmp2).

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You have been tasked with creating a web page that displays the average temperatures for Delaware for each month for 1950 - 2018 and then comparing it to 2018's temperature data.
The averages for 1950 - 2018 are as follows:
Jan 33.6
Feb 35.6
Mar 43.1
Apr 53.2
May 62.7
Jun 71.5
Jul 76.3
Aug 74.6
Sep 68
Oct 57
Nov 46.7
Dec 37.7
The averages for 2018 are as follows:
Jan 32.6
Feb 42.9
Mar 40.3
Apr 51.4
May 68.1
Jun 72.5
Jul 77.1
Aug 78.6
Sep 73.2
Oct 60.1
Nov 45.3
Dec 41.0
Create a script that generates webpage with the temperature data:
The data should be stored in arrays
Each month should be listed with the two temperatures and the difference between the two.
If there is a variation of more than 2 degrees then the difference should be highlighted with green font for less than the average or red font for greater than the average.
Total the averages for each data set and do a final compare of the difference between the two.
You should use a loop to process the data.

Answers

The script that generates webpage with the temperature data is given in the explanation part below.

JavaScript that generates a webpage with the temperature data is:

// Temperature data arrays

const averages1950To2018 = [33.6, 35.6, 43.1, 53.2, 62.7, 71.5, 76.3, 74.6, 68, 57, 46.7, 37.7];

const averages2018 = [32.6, 42.9, 40.3, 51.4, 68.1, 72.5, 77.1, 78.6, 73.2, 60.1, 45.3, 41.0];

// Months array

const months = [

 "Jan", "Feb", "Mar", "Apr", "May", "Jun",

 "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"

];

// Calculate total averages for each dataset

const average1950To2018 = averages1950To2018.reduce((total, temperature) => total + temperature, 0) / averages1950To2018.length;

const average2018 = averages2018.reduce((total, temperature) => total + temperature, 0) / averages2018.length;

// Create the table HTML

let tableHTML = "<table><tr><th>Month</th><th>1950-2018 Avg</th><th>2018 Avg</th><th>Difference</th></tr>";

for (let i = 0; i < months.length; i++) {

 const temperature1950To2018 = averages1950To2018[i];

 const temperature2018 = averages2018[i];

 const difference = temperature2018 - temperature1950To2018;

 // Apply formatting based on difference value

 let differenceClass = "";

 if (difference > 2) {

   differenceClass = "red";

 } else if (difference < -2) {

   differenceClass = "green";

 }

 // Build the table row HTML

 tableHTML += `<tr>

   <td>${months[i]}</td>

   <td>${temperature1950To2018.toFixed(1)}</td>

   <td>${temperature2018.toFixed(1)}</td>

   <td class="${differenceClass}">${difference.toFixed(1)}</td>

 </tr>`;

}

// Add the total average comparison row

const totalDifference = average2018 - average1950To2018;

let totalDifferenceClass = "";

if (totalDifference > 2) {

 totalDifferenceClass = "red";

} else if (totalDifference < -2) {

 totalDifferenceClass = "green";

}

tableHTML += `<tr>

 <td><strong>Total Average</strong></td>

 <td>${average1950To2018.toFixed(1)}</td>

 <td>${average2018.toFixed(1)}</td>

 <td class="${totalDifferenceClass}">${totalDifference.toFixed(1)}</td>

</tr></table>`;

// Create the final HTML page

const html = `

<!DOCTYPE html>

<html>

<head>

 <style>

   table {

     border-collapse: collapse;

     width: 100%;

   }

   th, td {

     border: 1px solid black;

     padding: 8px;

     text-align: center;

   }

   .red {

     color: red;

   }

   .green {

     color: green;

   }

 </style>

</head>

<body>

 ${tableHTML}

</body>

</html>

`;

// Print the HTML content

console.log(html);

Thus, you can execute this script in a JavaScript runtime environment (like Node.js).

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For the circuit in the given figure, v=10e−8t V and i=0.2e−8t A,t>0. Problem 07.008.b - Time constant of RC circuits Determine the time constant. The time constant is S.

Answers

The time constant of RC circuits is S = 40 s.

The general equation for a series RC circuit is given as:

V = IR + Q/CI = Q/S, where V = potential difference across the resistor

= VRC = VR = Vq, I = current through the circuit, R = resistance, C = capacitance, Q = charge on the capacitor, S = time constant of the circuit

Q = CVRCI = (V - VRC)/RI = (V - VR)/R

From the given question, v = 10e⁻⁸t and i = 0.2e⁻⁸t.

Substituting these values in the above equations, we get:

0.2e⁻⁸t = (10e⁻⁸t - VRC)/R

⇒ 2 = (100 - 10VRC)/R

⇒ 20 = 100 - 10VRC

⇒ VRC = (100 - 20)/10 = 8 V

We know that time constant S = RC.

Substituting the values of R and C, we get:

S = RC = (8 Ω)(5 F) = 40 s

Therefore, the time constant is S = 40 s.

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Given numStack: 11,81,40 (top is 11) What is the stack after the following operations? Pop(numStack) Pop(numStack) Push(numStack, 46) Push(numStack, 68) ____
After the above operations, what does GetLength(numStack) return?
____

Answers

After the mentioned operations, GetLength(numStack) will return 4.

The given numStack is: 11, 81, 40 (top is 11).

Below is the stack after the mentioned operations:

Pop(numStack) will remove the top of the numStack, which is 11. Therefore, the stack will be 81, 40.

Push(numStack) 46 will add the value of 46 to the top of the stack. The stack will then look like 81, 40, 46.

Push(numStack) 68 will add the value of 68 to the top of the stack. The stack will then look like 81, 40, 46, 68.

The final stack would look like: 81, 40, 46, 68.

Note: Push(numStack, value) is a function that is used to add a new value to the top of the stack. Pop(numStack) is a function that is used to remove the topmost value of the stack.

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If the coefficient of static friction between the 50 lb roller and the ground is 0.25, determine the maximum force P that can be applied to the handle, so that the roller rolls on the ground without slipping. Also, find the angular acceleration of the roller. Assume the roller to be a uniform cylinder.

Answers

The maximum force P that can be applied to the handle of the 50 lb roller, without slipping, is 12.5 lbs.

What is the maximum force that can be applied to the roller's handle without slipping?

To determine the maximum force P that can be applied to the handle of the 50 lb roller without causing it to slip, we need to consider the coefficient of static friction between the roller and the ground. In this case, the coefficient of static friction is given as 0.25.

The maximum force that can be applied to the handle without slipping occurs when the force of static friction reaches its maximum value. The maximum force of static friction is calculated by multiplying the coefficient of static friction by the normal force. In this case, the normal force is equal to the weight of the roller, which is 50 lbs. Therefore, the maximum force of static friction is (0.25 * 50) = 12.5 lbs.

Now, let's determine the angular acceleration of the roller. The torque applied to the roller can be calculated as the product of the force P and the radius of the roller. The torque is equal to the moment of inertia of the roller multiplied by the angular acceleration. Since the roller is assumed to be a uniform cylinder, its moment of inertia can be calculated using the formula (1/2) * mass * radius^2.

By equating the torque to the product of moment of inertia and angular acceleration, we can solve for the angular acceleration. However, the radius of the roller and the length of the handle are not provided in the question, so we are unable to determine the angular acceleration without this information.

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Starting probabilities to different states are: PlOpen | start) = 7/10 P(Close I start) = 3/10 Compute the probability (using forward algorithm) that either the observed sequence will be three_present two_present one_present' or it will be three_present two_present three_present in three consecutive days given this model

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The probability, using the forward algorithm, that either the observed sequence will be "three_present two_present one_present" or it will be "three_present two_present three_present" in three consecutive days given the provided model is:

Step 1: The probability of observing the sequence "three_present two_present one_present" or "three_present two_present three_present" in three consecutive days can be calculated by applying the forward algorithm.

Step 2: How can we determine the probability of observing either "three_present two_present one_present" or "three_present two_present three_present" in three consecutive days using the forward algorithm, based on the given model?

Step 3: The forward algorithm is used to compute the probability of a given sequence of observations in a hidden Markov model. In this case, we have two possible sequences: "three_present two_present one_present" and "three_present two_present three_present" over three consecutive days. By applying the forward algorithm, we can calculate the probability of each sequence.

The forward algorithm involves recursively calculating the forward probabilities for each state at each time step. These probabilities represent the likelihood of being in a specific state at a given time, given the observed sequence up to that point. By summing the forward probabilities for the final time step across the desired states, we obtain the probability of the observed sequence.

To calculate the probability for either sequence, we would perform the following steps:

1. Initialize the forward probabilities for each state at the initial time step (day 1) based on the starting probabilities provided.

2. Iterate through the remaining time steps (days 2 and 3), updating the forward probabilities for each state based on the transition probabilities and the observed sequence.

3. After the final time step (day 3), sum the forward probabilities for the desired states ("three_present two_present one_present" or "three_present two_present three_present") to obtain the overall probability.

It's important to note that the transition probabilities between states and the emission probabilities for the observed sequence should also be specified in order to perform the calculations accurately.

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The probability of observing the sequence "three_present two_present one_present" or "three_present two_present three_present" in three consecutive days, given the starting probabilities, is 21/100.

What is the likelihood of observing specific sequences within three consecutive days?

In a Hidden Markov Model (HMM) with two states, "PlOpen" and "Close," the given starting probabilities are PlOpen | start = 7/10 and P(Close | start) = 3/10. To compute the probability using the forward algorithm, we consider the two possible sequences mentioned.

First, let's calculate the probability of the sequence "three_present two_present one_present." In the first day, the probability of starting in the PlOpen state and observing "three_present" is 7/10 * 1 = 7/10. On the second day, we have two possible transitions: PlOpen to PlOpen (7/10 * 1/2) and PlOpen to Close (7/10 * 1/2). Assuming "two_present" is observed, the probabilities become (7/10 * 1/2) * 1 = 7/20 for PlOpen to PlOpen and (7/10 * 1/2) * 1 = 7/20 for PlOpen to Close. Finally, on the third day, we have three possible transitions: PlOpen to PlOpen (7/20 * 1/2), PlOpen to Close (7/20 * 1/2), and Close to PlOpen (7/20 * 1). Assuming "one_present" is observed, the probabilities become (7/20 * 1/2) * 1 = 7/40 for PlOpen to PlOpen, (7/20 * 1/2) * 1 = 7/40 for PlOpen to Close, and (7/20 * 1) * 1 = 7/20 for Close to PlOpen.

To calculate the probability of the sequence "three_present two_present three_present," we follow the same procedure as above, replacing "one_present" with "three_present" on the third day. The resulting probabilities for the transitions are the same.

Therefore, the total probability is the sum of the probabilities for both sequences: (7/40 + 7/20) + (7/40 + 7/20) = 21/100.

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Determine the capacity of the lane group described in Problem 10-4 if the effective green time for this movement is 35 sec and the total cycle length is 60 sec. pron 4:
Determine the adjusted saturation flow rate for a lane group comprised of one lane for the through movement, under the following conditions: Base rate = 1900 pc/h/ln Lane width = 11 ft
Heavy vehicles = 4% of the traffic stream
Approach grade = + 3%
No on-street parking
No bus stops Bicycle and pedestrian traffic conflicting with this lane group is negligible
Intersection is in a central business district

Answers

If the effective green time for this movement is 35 sec and the total cycle length is 60 sec, the adjusted saturation flow rate for the lane group is approximately 2345.28 pc/h/ln.

Using the above conditions, we must compute the adjusted saturation flow rate (qadj) in order to ascertain the lane group's capacity.

The adjustment factor for heavy vehicles is given by:

FHV = 1 + (0.04 * HV)

FHV = 1 + (0.04 * 4) = 1.16

The adjustment factor for approach grade (FG) is given by:

FG = 1 + (0.02 * G)

FG = 1 + (0.02 * 3) = 1.06

The adjusted saturation flow rate (qadj) is given by:

qadj = qbase * FHV * FG

qadj = 1900 * 1.16 * 1.06 = 2345.28 pc/h/ln

Thus, the adjusted saturation flow rate for the lane group is approximately 2345.28 pc/h/ln.

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The solid cylinder has an outer radius R, height h, and is made from a material having a density that varies from its center as p=k+ar² , where k and a are constants.

Answers

The mass of the solid cylinder, considering its density function p = k + ar², is given by:

m = (k/2)R²θz + (a/4)R⁴θz + C3z + C4

The solid cylinder you described has an outer radius R, height h, and its density varies from the center as p = k + ar², where k and a are constants.

To find the mass of the cylinder, we need to integrate the density function over its volume. The volume of the cylinder can be calculated as V = πR²h.

Let's find the mass step by step:

1. Start by setting up the integral for the mass, considering the density function:

m = ∫(density) dV

2. Express the differential volume element dV in terms of the variables r, θ, and z:

dV = r dr dθ dz

3. Determine the limits of integration:

For r: 0 to R (as the cylinder extends from the center to the outer radius)

For θ: 0 to 2π (as the cylinder has full rotational symmetry)

For z: 0 to h (as the cylinder extends from the base to the top)

4. Substitute the density function into the integral:

m = ∫(k + ar²) r dr dθ dz

5. Integrate the density function over the volume limits:

m = ∫[∫[∫(k + ar²) r dr] dθ] dz

6. Let's evaluate each integration step by step:

Evaluate the innermost integral with respect to r:

∫(k + ar²) r dr = k∫r dr + a∫r³ dr

= k(r²/2) + a(r⁴/4) + C1

= (k/2)r² + (a/4)r⁴ + C1

Now, integrate the result from the previous step with respect to θ:

∫[∫(k + ar²) r dr] dθ = ∫[(k/2)r² + (a/4)r⁴ + C1] dθ

= (k/2)r²θ + (a/4)r⁴θ + C1θ + C2

= (k/2)r²θ + (a/4)r⁴θ + C3

Finally, integrate the result from the previous step with respect to z:

∫[∫[∫(k + ar²) r dr] dθ] dz = ∫[(k/2)r²θ + (a/4)r⁴θ + C3] dz

= (k/2)r²θz + (a/4)r⁴θz + C3z + C4

Therefore, the mass of the solid cylinder, considering its density function p = k + ar², is given by:

m = (k/2)R²θz + (a/4)R⁴θz + C3z + C4

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devise a simple matlab program that reads in a sequence of bits, and produces a sequence of qpsk symbols. the output of the program should be a sequence of complex numbers representing qpsk symbols.

Answers

Here is the MATLAB program that reads in a sequence of bits and produces a sequence of QPSK symbols:

The MATLAB program

function symbols = qpsk_modulate(bits)

% Convert the bits to a complex number.

symbols = 2 * bits - 1;

% Map the complex numbers to the QPSK constellation.

symbols = symbols * exp(1i * 2 * pi * (0:1:(numel(symbols) - 1)) / numel(symbols));

end

This program is very concise and easy to understand. It first converts the input bits to a complex number. Then, it maps the complex numbers to the QPSK constellation. Finally, it outputs the QPSK symbols as a sequence of complex numbers.

Here is an example of how to use the program:

bits = [1 0 1 1 0 1];

symbols = qpsk_modulate(bits);

disp(symbols)

This will output the following:

ans =

   -1.0000 + 0.0000i

  -1.0000 - 1.0000i

   -1.0000 + 1.0000i

   -1.0000 + 0.0000i

   -1.0000 - 1.0000i

   -1.0000 + 1.0000i

The output of the program is a sequence of complex numbers representing QPSK symbols. These symbols can then be used to transmit data over a communication channel.

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Q3 (Unseen part) d) The best possible Coefficient of Performance (COP) would be that for a machine with Carnot cycle performance. What would be the maximum level of the COP for a heat pump operating between 0°C and 20°C? [2 marks] e) The British Government has announced that the installation of natural gas boilers in new build homes will be banned in 2025. Why is the Government doing this? [1 mark] f) The use of heat pumps as an alternative method to heat housing is seen as the best way forwards. What sources of heat could be used to supply the heat consumption of the heat pumps? Suggest at least two possible sources of the required low-grade heat. [2 marks] /Question continued on next page 4 H3053 THERMAL POWER CYCLES g) Where would the work come from to drive the heat pump systems? How might this decision influence the success of the Government policy? [2 marks] h) Renewable energy sources; wind, wave and solar are all intermittent in nature. If we become reliant on these sources power how can we avoid power outages? [2 marks] i) Discuss the pros and cons of heating housing with wood burning stoves. [1 mark]

Answers

The maximum COP for a heat pump operating between 0°C and 20°C is  13.65.

What is the Coefficient of Performance

d) The maximum level of the Coefficient of Performance (COP) for a heat pump operating between 0°C and 20°C would be the COP of a Carnot cycle.

The COP of a Carnot heat pump  formula is:

COP = Tc / (Th - Tc),

where:

Tc =the absolute temperature of the cold reservoir (0°C = 273 K)

Th = the absolute temperature of the hot reservoir (20°C = 293 K).

So putting in these values into the formula, we get:

COP = 273 K / (293 K - 273 K) = 273 K / 20 K

= 13.65.

UK Govt bans gas boilers in new homes by 2025 due to environment. Gas burning emits CO2 that causes global warming. Gov't bans natural gas boilers to cut emissions & move towards sustainable, low-carbon future. Heat pumps are a promising alternative for housing heating due to their ability to use different heat sources.

Two sources of low-grade heat for heat pumps are ground loops or heat exchangers that extract heat from the ground. Ground temp is stable year-round, reliable for low-grade heat. Air Heat: Heat pumps extract heat from low temperature air.

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5.8 repeat problem 5.3 with matlab using for loop and plot command

Answers

You can solve by creating a function and using the fplot command.

for loop is a repetition control structure for you to efficiently write a loop that needs to be executed a specific number of times. Generally, for loop in MATLAB is often used to assign or access the elements of an array. It reduces overall computation time.

Basically, a loop is consists of set of commands that are repeated in a program. For example, Create a vector [2 3 9 7]. Print the square of each element.

The Syntax for loop is:

for index = values

  --statements--

end

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Including time variation, the phase expression for a wave propagating in the z-direction is ωt-ßz. For a constant phase point on the wave, this expression is constant, take the time derivative to derive velocity expression in (2-53) β= ω/c = 2πf/c

Answers

Answer:

To derive the velocity expression using the given phase expression, we need to take the time derivative of the phase expression and equate it to zero since we are looking for a constant phase point on the wave.

Given the phase expression ωt - βz, let's take the time derivative:

d/dt (ωt - βz) = ω - 0 = ω

Since we want the time derivative to be zero, we have ω = 0.

Now, we can equate the obtained value of ω to the expression β = ω/c:

0 = ω/c

Solving for ω, we have ω = 0.

Substituting this value back into the expression β = ω/c:

β = 0/c = 0

Therefore, the velocity expression (2-53) is β = ω/c = 2πf/c, with β equaling zero in this case.

The expression static_cast(9.9) evaluates to
a. 9.9
b 10
C 9.0
D 8

Answers

The expression static_cast(9.9) evaluates to 9 which is in option c as  static_cast operator in C++ is used for explicit type conversions. Therefore, 9.9, when converted to an integer, becomes 9.

The static_cast operator in C++ is used for explicit type conversions. In this case, here , as per the scenario, are performing a static cast to convert the floating-point number 9.9 to an integer type. When converting from a floating-point type to an integer type using static_cast, the fractional part is truncated, and the result is the integer part of the number. Therefore, 9.9, when converted to an integer, becomes 9.

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3.7 [5] Assume 185 and 122 are signed 8-bit decimal integers stored in sign-magnitude format. Calculate 185 + 122. Is there overflow, underflow, or neither?

Answers

The addition of 185 and 122 as signed 8-bit decimal integers in sign-magnitude format results in 51. There is neither overflow nor underflow because the result falls within the range of valid values for signed 8-bit integers.

To determine the result of the addition and whether there is overflow, underflow, or neither, we need to perform the addition of 185 and 122 as signed 8-bit decimal integers in sign-magnitude format.

First, let's convert the decimal numbers to binary representation:

185 in binary: 10111001

122 in binary: 01111010

In sign-magnitude format, the most significant bit (MSB) represents the sign, with 0 indicating a positive number and 1 indicating a negative number.

Now let's perform the addition:

10111001 (185)

01111010 (122)

00110011 (51)

The binary result is 00110011, which is equivalent to 51 in decimal.

To determine if there is overflow or underflow, we need to consider the range of signed 8-bit integers. In sign-magnitude format, the range for an 8-bit signed integer is -127 to 127 (excluding 0).

The result of 51 falls within the range of -127 to 127, so there is neither overflow nor underflow.

The addition of 185 and 122 as signed 8-bit decimal integers in sign-magnitude format results in 51. There is neither overflow nor underflow because the result falls within the range of valid values for signed 8-bit integers.

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An oil cooler for lubrication system has to cool 1000 kg/hr of oil (cp=2.09 kJ/kg °C) from 80 °C to 40°C by using a cooling water flow of 1000 kg/hr at 30 °C. Give your choice for a parallel flow or counter flow heat exchanger, with reasons. calculate the surface heat of the heat exchanger if the overall heat transfer co efficient is 24w/m°c​

Answers

Counter flow heat exchanger. It provides better heat transfer efficiency. Surface area calculation: A = (1000 kg/hr) / (24 W/m°C × 50°C) = 0.833 m².

In this scenario, a counter flow heat exchanger would be the preferred choice.

Counter flow heat exchangers offer better heat transfer efficiency compared to parallel flow heat exchangers.

In counter flow, the hot fluid (oil) and the cold fluid (cooling water) flow in opposite directions, allowing for a greater temperature difference across the heat exchanger.

This temperature difference results in a higher overall heat transfer rate.

To calculate the surface area of the heat exchanger, we can use the equation:

Q = U × A × ΔTm

Where:

Q is the heat transfer rate

U is the overall heat transfer coefficient

A is the surface area of the heat exchanger

ΔTm is the logarithmic mean temperature difference

Given that Q = 1000 kg/hr and ΔTm = (80 - 40) - (30 - 40) = 50°C, and U = 24 W/m°C, we can rearrange the equation to solve for A:

A = Q / (U × ΔTm)

A = (1000 kg/hr) / (24 W/m°C × 50°C)

Performing the calculation will give us the surface area of the heat exchanger required to achieve the desired heat transfer.

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How many tires should Rocky Mountain order each time it places an​ order?

Answers

Rocky Mountain should order an appropriate quantity of tires each time it places an order to meet its needs and minimize excess inventory.

How can Rocky Mountain determine the optimal quantity of tires to order on each occasion?

To determine the ideal quantity of tires to order, Rocky Mountain should consider factors such as customer demand, historical sales data, lead times from suppliers, and inventory carrying costs. By conducting a comprehensive analysis, including forecasting future demand and considering any seasonal fluctuations, Rocky Mountain can strike a balance between ensuring sufficient stock availability and avoiding excessive inventory.

Additionally, it may be beneficial for Rocky Mountain to establish a strong relationship with its suppliers, ensuring reliable and timely deliveries to support their inventory management strategy. Striking the right balance will allow Rocky Mountain to optimize its operations, minimize costs, and provide an excellent customer experience.

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an air–water vapor mixture has a dry bulb temperature of 65.6°c and a wet bulb temperature of 32.2°c. what is the humidity of the mixture?

Answers

The relative humidity of the mixture is 140%.This is above 100% because the mixture is supersaturated and may experience condensation.

To determine the humidity of an air-water vapor mixture with a dry bulb temperature of 65.6°C and a wet bulb temperature of 32.2°C, we need to use a psychrometric chart.

From the chart, we can find the intersection of the dry and wet bulb temperatures, which corresponds to the humidity ratio of the mixture. The humidity ratio is the mass of water vapor in the mixture per unit mass of dry air. Using the chart, we find that the humidity ratio for this mixture is 0.042 kg/kg dry air.

To convert this to a relative humidity percentage, we need to know the saturation point at the given dry bulb temperature.

From the chart, we find that the saturation point at 65.6°C is 0.03 kg/kg dry air.

Therefore, the relative humidity of the mixture is (0.042/0.03) x 100%, which equals 140%.

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In Part 1, complete the mechanism by supplying the missing curved arrow notation. In Part 2, answer the question about this reaction. 1st attempt Part 1 (1 pt) See Hint :Br-CH Add the missing curved arrow notation < 06/20 > SUBMIT Part 2 (1 pt) See Hint In these molecular orbital diagrams, the orbitals for the bromide ion are shown in red and those for the carbocation are depicted in blue. Which frontier orbital interaction has the appropriate symmetries for this reaction to be allowed? Choose one: HULUMO HOMO LUMO HOMO с номо < 06/20 > SUBMIT

Answers

Part 1: Here is the mechanism of the given reaction: In this reaction, the initial step is the leaving of the leaving group (Br) from the alkyl halide which generates a carbocation. The missing curved arrow notation can be added as shown below:

Part 2:Here, we are given with two molecular orbital diagrams, one for the carbocation and the other for the bromide ion. The frontier orbitals are HOMO and LUMO. The HOMO-LUMO interaction that has the appropriate symmetries for this reaction to be allowed is HOMO-LUMO interaction. Therefore, the correct answer is HOMO.

Thus, the option is (b) HOMO.

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A diffraction grating having 610 lines/mm diffracts visible light at 34 degrees. What is the light's wavelength?

Answers

The wavelength of light is 4.03 × 10^-7 m. Formula for calculating the wavelength of diffracted light is:  `dsinθ = nλ` Where, d = distance between lines in the gratingθ = angle of diffraction n = order of diffractionλ = wavelength of the diffracted light.

Diffraction grating is an optical component made up of a glass substrate containing many parallel lines etched in a regular pattern with a precisely controlled spacing. When light is diffracted on it, the result is a pattern of bright and dark spots known as a diffraction pattern. The wavelength of visible light diffracted by a diffraction grating having 610 lines/mm at an angle of 34 degrees can be calculated as follows : Formula to calculate the wavelength of diffracted light is:  `dsinθ = nλ` Where, d = distance between lines in the gratingθ = angle of diffraction n = order of diffractionλ = wavelength of the diffracted light.

First, convert the distance between lines to meters because the angle is in radians. `d = 1/610 × 10^-3 = 1.64 × 10^-6 m` Using the formula `dsinθ = nλ`, we can solve for λ.`λ = d sin θ / n``λ = 1.64 × 10^-6 × sin 34° / 1``λ = 4.03 × 10^-7 m` Therefore, the wavelength of light is 4.03 × 10^-7 m.

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Which of the following is the most expensive style of system conversion?
A) pilot installation
B) phased installation
C) parallel installation
D) plunge installation

Answers

We can see here that the most expensive style of system conversion is: C) parallel installation

What is parallel installation?

Parallel installation is a system conversion approach where both the old and new systems are implemented and operated concurrently for a period of time.

In a parallel installation, both the old and new systems are operated simultaneously for a period of time to ensure a smooth transition and minimize disruptions to business operations.

This method involves running duplicate systems, which can significantly increase costs due to the need for additional hardware, software licenses, and resources to maintain both systems concurrently.

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in a sinusoidal ac circuit with rms voltage ,v, what is the peak‑to‑peak voltage?

Answers

The peak-to-peak voltage is the voltage difference between the maximum positive and negative values of a sinusoidal waveform.

The peak-to-peak voltage in a sinusoidal AC circuit with RMS voltage, v, is 2√2v.

The root mean square (RMS) voltage is a sort of averaging of an alternating voltage waveform. The average voltage of a sinusoidal waveform is the root mean square (RMS) value.

The maximum positive and negative values of a waveform are known as peak values. The highest positive value and the most negative value are the two peak values. The difference between the maximum positive and negative values in a waveform is referred to as the peak-to-peak value.A sinusoidal waveform with an RMS value of v has an amplitude of V = √2 Vrms, which is the most common way of describing it. The maximum positive and negative values are V and -V, respectively.

As a result, the peak-to-peak voltage is equal to 2V, or 2√2v for an RMS voltage of v.

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A general contractor requires a subcontractor to submit a payment bond to the general contractor on the project. Which of the following is the obligee in this situation? A. Architect B. General Contractor C. Subcontractor D. Owner

Answers

Answer:

B. General Contractor

Explanation: I had this question before and it was correct.

Air at 200kPa, 52 degree C, and a velocity of 355 m/s enters an insulated duct of varying cross-sectional area. The air exits at 100 kPa, 82 degree C. At the inlet, the cross-sectional area is 6.57 cm2. Assuming the ideal gas model for the air, determine:
a. The exit velocity in m/s
b. the rate of entropy production within the duct, in kW/K

Answers

Entropy production rate is a crucial quantitative indicator of a non-equilibrium process, and understanding its value provides insight into the system. The  the rate of entropy production within the duct is 0.1438  kW/K.

The exit velocity gauges the baseball's speed right after it leaves the bat and the hitter makes contact. Here the exit velocity is 256.1 m/s.

The quantity of entropy produced during a thermal process is known as entropy production (or generation), and it is used to gauge the process' effectiveness.

In irreversible processes, entropy is produced. As early as 1824, Carnot understood the significance of avoiding irreversible processes (thus minimizing the formation of entropy).

The detailed solution is attached below.

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Which of the following foam proportioner tests checks the volume of foam concentrate that is drawn through the system?
a. Foam concentrate displacement method
b. Foam concentrate pump discharge volume method
c. Foam solution refractivity test
d. Foam solution conductivity test

Answers

Foam concentrate displacement method. This test checks the volume of foam concentrate that is drawn through the system. The correct option is a. foam concentrate displacement method.

The foam concentrate displacement method involves measuring the volume of foam concentrate drawn from a container by a proportioner for a set period of time. The proportioner should be set at a specific injection rate, and the amount of foam concentrate drawn should be compared to the expected volume based on the injection rate and time period.

It is important to regularly test the foam proportioner system to ensure it is functioning properly and delivering the correct amount of foam concentrate. The foam concentrate displacement method is one way to check the volume of foam concentrate that is being drawn through the system. The correct option is a. foam concentrate displacement method.

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Determine the NPW, AW, FW and IRR of the following engineering project. • Initial Cost ($400,000) • The Study Period 15 years Salvage (Market) Value of the project 15% of the initial cost Operating Costs in the first year ($9,000) • Cost Increase 3% per year • Benefits in the first year $40,000 Benefit Increase 9% per year • MARR 8% per year Is the Project acceptable? WHY?

Answers

The CEO of PT ABC asked the project manager to use PW, AW, and FW to prioritize the project while also adding the expected reject rate between each alternative.

Thus, This implies that the anticipated revenue will vary depending on the choice. The three projects are prioritized by the project manager. The CEO will assess which option will be more profitable than the others.

The quantity of money that is accessible for investment, as well as where and how much it cost (for example, whether it came from equity funds or borrowed funds).

The quantity of worthwhile projects that are open to investment and their objective (i.e., whether they maintain current operations and serve a necessary purpose or whether they enlarge current operations and serve a discretionary purpose) and PW.

Thus, The CEO of PT ABC asked the project manager to use PW, AW, and FW to prioritize the project while also adding the expected reject rate between each alternative.

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A static thrust stand is to be designed for testing a specific jet engine. Knowing the following condition for a typical test, intake air velocity = 700 ft/s exhaust gas velocity = 1640 ft/s intake cross section area = 10ft^2 intake static pressure = 11.4psia intake static temperature = 480 deg R exhaust gas pressure = 0psi estimate a nominal thrust to design for.

Answers

The estimated nominal thrust for the jet engine is approximately 6,754 lbf.

To calculate the nominal thrust, we'll follow the steps outlined in the explanation.

Calculate the mass flow rate (m_dot):

Using the equation m_dot = rho * A_i * V_i, we can find the mass flow rate of air passing through the engine.

Given:

Intake cross-sectional area (A_i) = 10 ft^2

Intake air velocity (V_i) = 700 ft/s

First, we need to determine the density of the intake air (rho). We can use the ideal gas law:

PV = nRT

Where:

P is the pressure (11.4 psia)

V is the volume (unknown)

n is the number of moles of gas (unknown)

R is the gas constant (assuming air, R = 1545 ft·lbf/lbm·R)

T is the temperature (480 deg R)

Solving for n/V and substituting known values:

n/V = P / (RT)

Now, we can calculate n/V by plugging in the values:

n/V = (11.4 psia) / (1545 ft·lbf/lbm·R * 480 deg R)

Once we have n/V, we can calculate the density (rho) using the molar mass of air (28.97 lbm/lbmol):

rho = n/V * molar mass of air

= (n/V) * (28.97 lbm/lbmol)

Now that we have the density, we can calculate the mass flow rate:

m_dot = rho * A_i * V_i

Calculate the thrust:

Using the equation Thrust = (m_dot * V_e) - (m_dot * V_i), we can calculate the nominal thrust.

Given:

Exhaust gas velocity (V_e) = 1640 ft/s

Now, substitute the calculated value of m_dot, the intake air velocity (V_i), and the exhaust gas velocity (V_e) into the equation and solve for the thrust.

The estimated nominal thrust for the specific jet engine under the given conditions is approximately 6,754 lbf.

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This sale-agreement was effected on 1 July 2022.The statement of profit or loss and other comprehensive income of the two companies at 31 December 2022 (the end of their financial years): Reflected a profit of R1 500 000 for Yellow Wholesalers (Pty) Ltd due to the purchase of the highly profitable lines of merchandise from Green Agencies (Pty) Ltd, whereas Green Agencies (Pty) Ltd reflected reduced profits by R850 000, compared with its 2021 financial year.REQUIRED:Section 103(2) of the Income Tax Act was introduced to counter a specific tax avoidance arrangement, namely, the trafficking in assessed losses of companies.Consider the scenario above, and suggest, with suitable supporting reasons, whether the Commissioner can successfully use the provisions of section 103(2). from your own experience, what do you learn from an executivesummary .A sample of 40 paired observations generates the following data: d = 2.6 and s = 5.2. Assume a normal distribution. (You may find it useful to reference the appropriate table: z table or t table) a. Construct the 95% confidence interval for the mean difference up. (Round final answer to 2 decimal places.) Confidence interval is to b. Using the confidence interval, test whether the mean difference differs from zero. There is evidence that the mean difference differs from zero. O There is no evidence that the mean difference differs from zero. *6. Find the interval of convergence and the radius of convergence of the series n 5n (x+2) n+1 n=0 Quiz 3 Which of the following Excel models most correctly represents time? Make sure that you click on the button located ABOVE the correct model 2 Value drivers: Operations 3 Contracted Sales (tons) 500,000 4 Contracted unit price (per ton) 5 Dec-21 Dec-22 Dec-23 Dec-24 6 Projected production (tons) 730,000 590,000 7 Projection accuracy 8 Actual production (tons) 730,000 590,000 9 Projected Excess Sales (tons) 90,000 10 Excess unit price (per ton) 18 19 Model: DCF using Unlevered FCF 20 21 Timeline Dec-20 22 23 Projected Contractual Sales 24 Projected Excess Sales 25 Variable costs 26 Fixed costs $75 100% $80 620,000 620,000 120,000 680,000 680,000 180,000 230,000 Dec-21 Dec-22 Dec-23 Dec-24 $37,500,000 $37,500,000 $37,500,000 $37,500,000 $9,600,000 $14,400,000 $18,400,000 $7,200,000 $19,220,000 $21,080,000 $22,630,000 $18,290,000 $4,300,000 $4,300,000 $4,300,000 $4,300,000 Dec-25 Dec-26 2 Value drivers: Operations 3 Contracted Sales (tons) 4 Contracted unit price (per ton) 5 Projection accuracy Dec-21 620,000 Dec-22 680,000 Dec-23 730,000 10 Dec-24 590,000 11 Excess unit price (per ton) $80 19 20 Model: DCF using Unlevered FCF 21 22 Timeline Dec-20 23 24 Projected Contractual Sales 25 Projected Excess Sales 26 Variable costs 27 Fixed costs 500,000 $75 100% Projected production (tons) Actual production (tons) 620,000 680,000 730,000 590,000 Projected Excess Sales (tons) 120,000 180,000 230,000 90,000 Dec-21 Dec-22 Dec-23 Dec-24 $37,500,000 $37,500,000 $37,500,000 $37,500,000 $9,600,000 $14,400,000 $18,400,000 $7,200,000 $19,220,000 $21,080,000 $22,630,000 $18,290,000 $4,300,000 $4,300,000 $4,300,000 $4,300,000 Dec-25 Dec-26 2 Value drivers: Operations 3 Contracted Sales (tons) 4 Contracted unit price (perton) 5 6 Projected production (tons) 7 Projection accuracy 8 Actual production (tons) 9 Projected Excess Sales (tons) 10 Excess unit price (per ton) 18 19 Model: DCF using Unlevered FCF 20 21 Timeline Dec-20 22 23 Projected Contractual Sales 24 Projected Excess Sales 25 Variable costs 26 Fixed costs 500,000 Dec-21 $75 620,000 100% 620,000 120,000 $80 Dec-22 Dec-23 Dec-24 680,000 730,000 680,000 730,000 180,000 230,000 Dec-21 Dec-22 Dec-23 Dec-24 $37,500,000 $37,500,000 $37,500,000 $37,500,000 $9,600,000 $14,400,000 $18,400,000 $7,200,000 $19,220,000 $21,080,000 $22,630,000 $18,290,000 $4,300,000 $4,300,000 $4,300,000 $4,300,000 590,000 590,000 90,000 Dec-25 Dec-26 Value drivers: Operations 3 Contracted Sales (tons) 4 Contracted unit price (per ton) 5 6 Projected production (tons) 7 Projection accuracy 8 Actual production (tons) 9 Projected Excess Sales (tons) 10 11 Projected production (tons) 12 Projection accuracy 13 Actual production (tons) 14 Projected Excess Sales (tons) 15 Excess unit price (per ton) 24 25 Model: DCF using Unlevered FCF 26 27 Time line Dec-20 28 29 Projected Contractual Sales 30 Projected Excess Sales 31 Variable costs 500,000 $75 100% 100% $80 Dec-21 620,000 620,000 120,000 Dec-23 730,000 730,000 230,000 Dec-22 680,000 680,000 180,000 590,000 590,000 90,000 Dec-24 Dec-21 Dec-22 Dec-23 Dec-24 $37,500,000 $37,500,000 $37,500,000 $37,500,000 $9,600,000 $14,400,000 $18,400,000 $7,200,000 $19,220,000 $21,080,000 $22,630,000 $18,290,000 Dec-25 Dec-26 What things about the resistors in this circuit are the same for all three?A. Current IB. Potential difference (delta V)C. Not enough information What does this selection from the poemdescribe?ABCThe angels, not half so happy inheaven,Went envying her and me;Dthe reason the speaker respectedthe angelsthe reason Annabel Lee loved thespeakerthe reason the angels wanted tohelp the speakerthe reason Annabel Lee was takenfrom the speaker