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Find the 3 smallest positive x-intercepts of the graph of
y = cos(12x) + cos(16x) and list them in increasing order.

Please give your answers as a list of x-coordinates from least to greatest.

Answers

Answer 1

Recall that [tex]\cos(x)+\cos(y)=2\cos \left(\frac{x+y}{2} \right)\cos \left(\frac{x-y}{2} \right)[/tex].

[tex]\cos(12x)+\cos(16x)=0 \\ \\ 2\cos(2x)\cos(14x)=0 \\ \\ \cos(2x)\cos(14x)=0[/tex]

If [tex]\cos(2x)=0[/tex], then [tex]x=\frac{\pi}{4}, \frac{3\pi}{4}, \frac{5\pi}{4}, \cdots[/tex].

If [tex]\cos(14x)=0[/tex], then [tex]x=\frac{\pi}{28}, \frac{3\pi}{28}, \frac{5\pi}{28}, \cdots[/tex].

So, the three smallest positive [tex]x[/tex] intercepts are [tex]\frac{\pi}{28}, \frac{3\pi}{28}, \frac{5\pi}{28}[/tex].


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