The electron in the ground-state of H atom absorbs the photon of the wavelength of 93.78 nm. The energy level of the electron move is n₂ = 5.
The energy of the photons is expressed as :
E = hc / λ
Where,
The E is the energy = ?
The h is the Planck's constant = 6.63 × 10⁻³⁴J.s
The c is the speed of the light = 3 × 10⁸ m/s
The λ is the wavelength of the photon = 93.78 nm
The energy is expressed as the :
E= ( 6.63 × 10⁻³⁴J.s × 3 × 10⁸ m/s ) / 93.78 nm
E = 2.1 × 10⁻¹⁸ J
Therefore, the energy of the photons is 2.1 × 10²⁵ J.
Transition energy for the hydrogen atom is :
ΔE = - R ( 1/ n₂² - 1 / n₁²)
Where,
R = 13.6eV
n₁= 1
n₂ = ?
2.1 × 10⁻¹⁸ = - 2.8 × 10⁻¹⁸ ( 1/ n₂² - 1 / 1²)
n₂ = 5
The energy level is n₂ = 5.
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please help!!! what does decreasing particle size do to a solvent’s solubility :)
In the event a particle's size of a solute is decreased, the surface area of the solute gradually increases. This proceeds to an optimum increase in the rate of solution and results in an increase in solubility.
Therefore, this effect is very important when the size goes down to the nanometric range . In many cases, a low dissolution rate is correlated with low solubility.
Solubility is claimed as the ability of a substance, the solute, to create a solution with another substance, the solvent . It is projected as the maximum quantity of a substance that could be dissolved in another . The maximum amount of solute that can be dissolved in a solvent at equilibrium produces a saturated solution .
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6.500 l of 0.00080 m k2so4 is mixed with 350 ml of 0.0025 m sr(no3)2. how many moles of solid srso4 will precipitate?
The number of moles of SrSO4 that will precipitate is equal to the number of moles of Sr(NO₃)²: 0.000875 mol SrSO4 will precipitate.
To find the moles of solid SrSO₄ that will precipitate, we need to first determine the limiting reagent in the reaction between K₂SO₄ and Sr(NO₃)².
Using the formula [tex]C = n/V[/tex], we can find the number of moles of each solution:
For K₂SO₄:
C = 0.00080 mol/L
V = 6.500 L
n = C x V = 0.00080 mol/L x 6.500 L = 0.0052 mol
For Sr(NO₃)²:
C = 0.0025 mol/L
V = 0.350 L
n = C x V = 0.0025 mol/L x 0.350 L = 0.000875 mol
Now we need to compare the moles of K₂SO₄ and Sr(NO₃)²to see which is the limiting reagent.
From the balanced equation:
K₂SO₄ + Sr(NO₃)² → 2KNO + SrSO₄
We can see that the stoichiometric ratio of K2SO4 to Sr(NO₃)² is 1:1. Therefore, we can compare the number of moles of each reagent directly.
0.0052 mol K₂SO₄ : 0.000875 mol Sr(NO₃)²
Since there are fewer moles of Sr(NO₃)², it is the limiting reagent.
Using stoichiometry, we can calculate the number of moles of SrSO₄ that will precipitate. From the balanced equation, we know that 1 mole of Sr(NO₃)² reacts with 1 mole of K₂SO₄ to form 1 mole of SrSO₄.
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what is the density of a sample of argon gas at 58 ∘c and 861 mmhg ?
The density of the argon gas at 58 °C and 861 mmHg is approximately 1.71 g/L.
To solve this problem, we can use the ideal gas law, which relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a gas:
PV = nRT
where R is the universal gas constant.
To solve for the density of the gas, we can rearrange this equation to solve for n/V (which is the molar density or the number of moles per unit volume):
n/V = P / (RT)
The density (ρ) of the gas is then given by:
ρ = (n/V) × M
where M is the molar mass of the gas.
We are given the temperature T = 58 °C = 331 K and the pressure P = 861 mmHg. We can convert the pressure to atm by dividing by 760 mmHg/atm:
P = 861 mmHg / 760 mmHg/atm = 1.13 atm
We can also look up the molar mass of argon, which is approximately 39.95 g/mol.
To use the ideal gas law, we need to convert the temperature to Kelvin:
T = 58 °C + 273.15 = 331.15 K
Now we can substitute these values into the equation for n/V:
n/V = P / (RT) = (1.13 atm) / [(0.08206 L·atm/(mol·K)) × (331.15 K)] ≈ 0.0427 mol/L
Finally, we can calculate the density of the gas using:
ρ = (n/V) × M = (0.0427 mol/L) × (39.95 g/mol) = 1.71 g/L
Therefore, the density of the argon gas at 58 °C and 861 mmHg is approximately 1.71 g/L.
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what is the oxidation number of the central metal ion in each of the following complexes or compounds? [nicl3f]2− [fe(h2o)4(nh3)2]3 na[au(cn)2]
The oxidation number of the central metal ion in each of the given complexes or compounds can be determined by assigning oxidation numbers to the ligands and balancing the overall charge of the complex.
1. [NiCl3F]2-: The overall charge of the complex is -2. Chlorine has an oxidation state of -1, fluorine has an oxidation state of -1, and the oxidation state of nickel is x. Therefore, (-1 x 3) + (-1) + x = -2. Solving for x, we get the oxidation state of nickel as +2.
2. [Fe(H2O)4(NH3)2]3+: The overall charge of the complex is +3. Oxygen in water has an oxidation state of -2, nitrogen in ammonia has an oxidation state of -3, and the oxidation state of iron is x. Therefore, (-2 x 4) + (-3 x 2) + x = +3. Solving for x, we get the oxidation state of iron as +3.
3. Na[Au(CN)2]: The overall charge of the complex is 0 (since Na has a charge of +1 and [Au(CN)2] has a charge of -1). Cyanide has an oxidation state of -1, and the oxidation state of gold is x. Therefore, (-1 x 2) + x = 0. Solving for x, we get the oxidation state of gold as +1.
In summary, the oxidation number of the central metal ion in [NiCl3F]2- is +2, in [Fe(H2O)4(NH3)2]3+ is +3, and in Na[Au(CN)2] is +1.
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Which of the following processes shows a decrease in entropy of the system?
A) 2NO (g) + O
2
(g) →
2
N
O
2
(g)
B) C
O
C
l
2
(g) →
CO(g) + C
l
2
(g)
C) C
H
3
O
H
(
l
)
→
CO(g) + 2
H
2
(g)
D) N
a
C
l
O
3
(s) →
N
a
+
(aq)+
C
l
O
−
3
(aq)
E) None of the above will show a decrease in entropy.
Entropy is a measure of the disorder or randomness of a system, and it tends to increase over time. The correct answer is E) None of the above will show a decrease in entropy.
In general, processes that increase the number of particles, increase the volume, or increase the temperature tend to increase entropy, while processes that decrease the number of particles, decrease the volume, or decrease the temperature tend to decrease entropy. In option A, the number of particles increases from 3 to 4, so entropy increases. In option B, the number of particles stays the same, but the volume increases, so entropy increases. In option C, the number of particles increases from 1 to 3, so entropy increases. In option D, the solid [tex]NaClO_{3}[/tex] dissociates into two aqueous ions, so the number of particles increases and entropy increases.Therefore, option E is the correct answer since none of the given processes show a decrease in entropy.
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what is the energy change of a hydrogen atom when its electron transitions from n=2 to n=5
The energy change of a hydrogen atom when its electron transitions from n=2 to n=5 is 4.092 × 10^-19 J.
The energy change of a hydrogen atom when its electron transitions from n=2 to n=5 can be calculated using the Rydberg formula:
1/λ = R*(1/n1^2 - 1/n2^2)
where λ is the wavelength of the emitted or absorbed photon, R is the Rydberg constant (1.097 × 10^7 m^-1), and n1 and n2 are the initial and final energy levels, respectively.
For the transition from n=2 to n=5, we have:
n1 = 2
n2 = 5
1/λ = R*(1/2^2 - 1/5^2)
Solving for λ, we get:
λ = 434 nm
The energy of a photon with a wavelength of 434 nm can be calculated using the formula:
E = hc/λ
where E is the energy of the photon, h is Planck's constant (6.626 × 10^-34 J s), and c is the speed of light (2.998 × 10^8 m/s).
Plugging in the values, we get:
E = (6.626 × 10^-34 J s)(2.998 × 10^8 m/s)/(434 nm)
E = 4.092 × 10^-19 J
Therefore, the energy change of a hydrogen atom when its electron transitions from n=2 to n=5 is 4.092 × 10^-19 J.
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test strips that check for the presence of ghb, rohypnol, or ketamine will not be effective if the drink contains what product?
The test strips that check for the presence of GHB, Rohypnol, or ketamine will not be effective if the drink contains dairy products.
Generally test strips are used to detect the pathological changes, that is especially present in urine. Basically the test strips indicates the acidity of urine by changing of the color on contact with it. Test strips react to acid in urine and determine its pH by color change, which is a good indicator of whole body pH.
Strip Testing basically refers to the process wherein semiconductor devices are electrically tested while they are still in their lead frame strips, i.e., before they are singulated into many individual units.
Hence, the test strips that check for the presence of GHB, Rohypnol, or ketamine will not be effective if the drink contains dairy products.
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Draw the structure of propyl (5E)-8-hydroxyoct-5-enoate. Select Draw Rings More С H o
The structure of propyl (5E)-8-hydroxy oct-5-enoate can be described as follows:
The main chain consists of eight carbon atoms, forming an octane backbone.
The double bond is located between the fifth and sixth carbon atoms, denoted as 5E. It indicates that the double bond has a trans configuration.
A hydroxyl group (-OH) is attached to the eighth carbon atom, indicating the presence of an alcohol functional group.
An ester group is present, represented by -COO-. It is formed by the linkage of the carbonyl group (C=O) from the carboxylic acid and an alcohol group (-OH) from another molecule.
The propyl group (C3H7) is attached to one end of the molecule, specifically the first carbon atom.
Please note that without a visual representation, it might be challenging to fully grasp the exact arrangement and orientation of the atoms in the molecule. Consider using chemical drawing software or consulting a reliable chemical structure database to obtain an accurate visual representation of propyl (5E)-8-hydroxyoct-5-enoate.
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cast iron skillet is used to fry bacon. for optimal frying, the pan must be heated to about 178 oc from a room temperature of 22.0 oc. it is known that 1.58 x 105 j of heat energy are absorbed by the pan to reach the desired temperature and the specific heat of iron is 0.450 j/g oc. what must the mass of the skillet be
The mass of the cast iron skillet must be approximately 2341.2 grams for optimal bacon frying.
To solve this problem, we can use the formula:
Q = m * c * ΔT
where Q is the heat energy absorbed by the skillet, m is the mass of the skillet, c is the specific heat of iron, and ΔT is the change in temperature.
We know that Q = 1.58 x 105 J, c = 0.450 J/g°C, ΔT = (178 - 22) = 156°C. We can plug these values into the formula and solve for m:
1.58 x 105 J = m * 0.450 J/g°C * 156°C
m = 1.58 x 105 J / (0.450 J/g°C * 156°C)
m = 717 g
Therefore, the mass of the skillet must be approximately 717 g for optimal frying of bacon.
To determine the mass of the cast iron skillet, we can use the heat energy equation: Q = mcΔT, where Q is the heat energy absorbed, m is the mass, c is the specific heat capacity of the material, and ΔT is the change in temperature.
Given:
Q = 1.58 x 10^5 J
c (specific heat of iron) = 0.450 J/g°C
Initial temperature (T1) = 22.0°C
Final temperature (T2) = 178°C
First, we need to find the change in temperature (ΔT):
ΔT = T2 - T1 = 178°C - 22.0°C = 156°C
Now we can plug the values into the heat energy equation:
1.58 x 10^5 J = m * (0.450 J/g°C) * (156°C)
Next, we can solve for the mass (m):
m = (1.58 x 10^5 J) / (0.450 J/g°C * 156°C) ≈ 2341.2 g
Therefore, the mass of the cast iron skillet must be approximately 2341.2 grams for optimal bacon frying.
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once all of the valence electrons have been placed on a lewis structure:
Once all the valence electrons have been placed on a Lewis structure, the next step is to check if the octet rule has been satisfied for all the atoms except hydrogen.
The octet rule states that atoms tend to gain, lose, or share electrons to achieve a full outer shell of eight electrons, which is the same electron configuration as the nearest noble gas. However, some elements such as boron, aluminum, and beryllium can have fewer than eight electrons in their valence shell and still be stable.
If any of the atoms in the Lewis structure do not satisfy the octet rule, then double or triple bonds may be used to share additional electrons between the atoms. The goal is to distribute electrons so that each atom has a full outer shell, or as close as possible to it.
Additionally, the Lewis structure should also obey formal charge rules, where the sum of the formal charges on all atoms in the molecule or ion should equal the overall charge of the species. The formal charge is calculated by subtracting the number of non-bonding electrons and half of the bonding electrons from the total valence electrons for each atom. A Lewis structure with the lowest formal charges on the individual atoms is considered the most stable.
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Which is NOT considered hazardous waste?
a
auto fluids
b
clothes
c
electronic devices
d
Battery
Clothes are not hazardous waste as they are made from natural and synthetic materials. They are neither toxic nor flammable, making them safe to dispose of in regular trash. Furthermore, clothing items can often be reused, recycled, or donated, reducing environmental impact and preventing hazardous waste.
Hope this helped! Have a great day. :)the molar solubility for magnesium hydroxide, mg(oh)2, is 1.6x 104. calculate its ksp.
The Ksp of magnesium hydroxide is 4.096x10^12.
he Ksp (solubility product constant) of magnesium hydroxide (Mg(OH)2) can be calculated using the molar solubility value given.
The balanced equation for the dissociation of magnesium hydroxide is:
Mg(OH)2(s) ⇌ Mg2+(aq) + 2OH-(aq)
The molar solubility of Mg(OH)2 is given as 1.6x10^4. Since Mg(OH)2 dissociates into one Mg2+ ion and two OH- ions, the equilibrium concentrations can be expressed as follows:
[Mg2+] = x
[OH-] = 2x
The Ksp expression for Mg(OH)2 is then:
Ksp = [Mg2+][OH-]^2 = x * (2x)^2 = 4x^3
Substituting the molar solubility value into the expression:
Ksp = 4(1.6x10^4)^3 = 4.096x10^12
Therefore, the Ksp of magnesium hydroxide is 4.096x10^12.
The Ksp value represents the equilibrium constant for the dissociation of a sparingly soluble salt. It indicates the extent to which the salt dissociates into its constituent ions in a saturated solution at equilibrium. In the case of magnesium hydroxide, a high Ksp value suggests that it has a significant degree of dissociation and is relatively soluble in water.
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which of the following are advantages of using coal as an energy source? multiple select question. coal can be fairly easily transported. coal is plentiful. coal has the least amount of impact on the environment when burned. coal is widely distributed in the united states.
Two of the advantages of using coal as an energy source are that it is plentiful and widely distributed in the United States. So, correct options are B and D.
These characteristics make it easier and more cost-effective to obtain and transport than some other energy sources.
However, it is not true that coal has the least amount of impact on the environment when burned. Coal is a fossil fuel, and burning it releases carbon dioxide, sulfur dioxide, nitrogen oxides, and other pollutants into the air, which can have negative impacts on air quality, climate change, and human health.
Furthermore, the transportation and mining of coal can also have negative impacts on the environment, including water pollution, land degradation, and habitat destruction.
Therefore, while coal may have some advantages as an energy source, it is important to consider the full range of environmental and health impacts associated with its use.
So, correct options are B and D.
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is water molecules were linear instead of bent, would the heat of vaporization be higher or lower
If water molecules were linear instead of bent, the heat of vaporization would be lower. This is because the bent shape of water molecules allows them to form hydrogen bonds with each other, which gives water a high heat of vaporization. If the molecules were linear, they would not be able to form these bonds as effectively, resulting in a lower heat of vaporization.
Water is an inorganic compound with the chemical formula H2O. It is a transparent, tasteless, odorless,[a] and nearly colorless chemical substance, and it is the main constituent of Earth's hydrosphere and the fluids of all known living organisms (in which it acts as a solvent. It is vital for all known forms of life, despite not providing food, energy or organic micronutrients. Its chemical formula, H2O, indicates that each of its molecules contains one oxygen and two hydrogen atoms, connected by covalent bonds.
so, If the molecules were linear, they would not be able to form these bonds as effectively, resulting in a lower heat of vaporization.
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find the ph of a buffer that consists of 0.33 m nh3 and 0.16 m nh4cl (pkb of nh3 = 4.75).
The pH of the buffer solution consisting of 0.33 M NH3 and 0.16 M NH4Cl is approximately 9.93.
To find the pH of a buffer consisting of 0.33 M NH3 and 0.16 M NH4Cl, we can use the Henderson-Hasselbalch equation for buffers:
pH = pKa + log ([A-]/[HA])
First, we need to determine the pKa from the given pKb of NH3 (4.75). We know that pKa + pKb = 14, so:
pKa = 14 - pKb
= 14 - 4.75
= 9.25
Next, we need to identify the concentrations of the acid ([HA]) and base ([A-]) components of the buffer.
In this case, the acid is NH4+ and the base is NH3:
[HA] = 0.16 M (NH4Cl)
[A-] = 0.33 M (NH3)
Now we can plug these values into the Henderson-Hasselbalch equation:
pH = 9.25 + log (0.33/0.16)
pH ≈ 9.25 + 0.68
pH ≈ 9.93
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which molecile shoe has a carboyl functional group in the form of an aldehyde
An aldehyde is an organic compound that contains a carbonyl group (C=O) bonded to a hydrogen atom (H) and an alkyl group or an aromatic group (R). In general, aldehydes can be represented by the formula R-CHO.
The molecule that fits the description of having a carbonyl functional group in the form of an aldehyde is formaldehyde, which has the chemical formula CH2O. In formaldehyde, the carbonyl group (-C=O) is located at the end of the molecule, making it an aldehyde.
Formaldehyde is a colorless gas with a pungent odor that is widely used in industry and as a disinfectant and preservative. It is also an important intermediate in organic synthesis and is used to make a variety of chemicals and products, including plastics, resins, and textiles.
The presence of the carbonyl group in formaldehyde makes it a highly reactive molecule that can participate in a variety of chemical reactions, including nucleophilic addition and condensation reactions. Its ability to react readily with other compounds makes it a valuable reagent in organic chemistry and an important industrial chemical.
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For ammonia, Kb is 1.8 x 10-5. to make a buffered solution of pH 10.0, the ratio of NH4Cl to NH3 must be: a) 1.8 : 1 b) 1 : 1.8 c) 0.18 : 1 d) 1 : 0.18 e) none of these
To make a buffered solution of pH 10.0 using ammonia (NH3) and its conjugate acid ammonium chloride (NH4Cl), the ratio of NH4Cl to NH3 should be 1 : 0.18 (option d).
In a buffered solution, the Henderson-Hasselbalch equation relates the pH, pKa (the negative logarithm of the acid dissociation constant), and the ratio of the concentrations of the conjugate acid and base. For ammonia, the pKa is related to the Kb (base dissociation constant) through the equation pKa + pKb = 14.
Given that Kb for ammonia is 1.8 x 10^-5, we can calculate the pKb as follows:
pKb = -log10(Kb) = -log10(1.8 x 10^-5) = 4.74
To achieve a pH of 10.0, we can use the Henderson-Hasselbalch equation:
pH = pKa + log10([NH4+]/[NH3])
Substituting the values, we have:
10.0 = 4.74 + log10([NH4+]/[NH3])
Rearranging the equation:
log10([NH4+]/[NH3]) = 10.0 - 4.74
log10([NH4+]/[NH3]) = 5.26
Taking the antilog of both sides:
[NH4+]/[NH3] = 10^5.26
[NH4+]/[NH3] ≈ 0.18
Therefore, the ratio of NH4Cl to NH3 in the buffered solution should be 1 : 0.18.
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How many degrees will 340 J raise the temperature of 6. 8 g of water? (Refer
to table of constants for water. )
O A. 12°C
OB. 81°C
O
C. 50°C
O
O
D. 28°C
The number of degrees that 340 J will raise temperature of 6. 8 g of water is 12°C.
So the answer is option A.
The specific heat capacity of water is 4.184 J/g·°C, so to determine how many degrees 340 J will raise the temperature of 6.8 g of water, you can use the formula:
ΔT = Q / (m × c)
where:
ΔT = change in temperature
Q = heat energy
m = mass of the substance
c = specific heat capacity of the substance
Plugging in the given values:
Q = 340 J
m = 6.8 g
c = 4.184 J/g·°C
ΔT = 340 J / (6.8 g × 4.184 J/g·°C)
ΔT ≈ 12.16°C
Hence, the answer is A. 12°C.
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how is natural gas similar to solar energy?
Natural gas and solar energy, both are obtained by nature. Solar energy is much more ecofriendly as compared to natural gas.
Like oil and coal, natural gas represents a fossil fuel which was created when extinct animals and plants from the past were gradually buried behind layers of rock. On the contrary hand, solar energy is generated by the sun, which is unbounded. Biomass, geothermal, hydroelectricity, solar, wind, and other alternative energy resources are some of the most prevalent types. Natural gas and solar energy, both are obtained by nature. Solar energy is much more ecofriendly as compared to natural gas.
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which one of the following conditions is always true for a titration of a weak acid with a strong base? the equivalence point occurs at a ph equal to 7. if a colored indicator is used, it must change color rapidly in the weak acid's buffer region. a colored indicator with a pka less than 7 should be used. equal volumes of weak acid and strong base are required to reach the equivalence point. the equivalence point occurs at a ph greater than 7.
The correct option is D, The equivalence point occurs at a pH greater than 7 for a titration of a weak acid with a strong base. This is because the strong base will react with the weak acid to form a salt and water.
Titration is a commonly used analytical technique in chemistry for determining the concentration of an unknown solution by adding a known amount of a standardized solution of known concentration. The process involves slowly adding the standardized solution to the unknown solution until the chemical reaction between the two is complete. The point at which the reaction is complete is known as the equivalence point and can be detected using various indicators that change color or other properties at this point.
The main aim of titration is to accurately measure the concentration of a particular substance in a solution. For example, an acid-base titration can be used to determine the concentration of an acid in a solution by adding a known amount of a strong base until the equivalence point is reached. Similarly, a redox titration can be used to determine the concentration of a reducing or oxidizing agent in a solution.
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which of the following does not have trigonal planar electron-pair geometry?select the correct answer below:bf3alcl3pcl3bh3
The electron-pair geometry of a molecule refers to the spatial arrangement of its electron pairs around the central atom. A molecule with a trigonal planar electron-pair geometry has a central atom with three bonding pairs and no lone pairs.
Therefore, the molecule will have a flat, triangular shape. Out of the given options, BH3 does not have a trigonal planar electron-pair geometry. It has only three bonding pairs and no lone pairs, but its electron geometry is trigonal planar due to the repulsion between the electron pairs. However, BH3 is an exception as it has an incomplete octet, making it an exception to the octet rule. Therefore, BH3 has a trigonal planar molecular geometry with a bond angle of 120 degrees. In contrast, BF3, AlCl3, and PCl3 all have trigonal planar electron-pair geometry with bond angles of 120 degrees, making them flat, triangular molecules.
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a sample of gas occupies a volume of 10.81 L at -25 what will be the new temperature needed for the gas to increase its volume to 30.5 L at a constant pressure what law will you use
700.4 K is the e new temperature needed for the gas to increase its volume to 30.5 L at a constant pressure which is determined using Charle's law.
The initial volume of gas = 10.81 L
Temperature -25°C
The final volume of gas = 30.5 L
Here we can use Charle's law because of changes in the volume and temperature of a gas at constant pressure.
The relation between volume and temperature is written as:
V1/T1 = V2/T2
We need to convert the temperature from the Celsius scale to the Kelvin scale.
T1 = -25°C + 273.15
T1 = 248.15 K
Substituting the values, we get:
V1/T1 = V2/T2
T2 = (V2 * T1) / V1
T2 = (30.5 L * 248.15 K) / 10.81 L
T2 = 700.4 K
Therefore, we can infer that the new temperature needed is 700.4 K.
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Write and balance the following single
replacement reaction.
f) Cr + H₂PO4
(HINT: Use Cr³+)
This reaction involves the displacement of H from H₂PO₄ by Cr. It is an example of a redox reaction, where oxidation and reduction occur simultaneously.
The single replacement reaction between Cr and H₂PO₄ can be represented as follows:
Cr + H₂PO₄ → CrPO₄ + H₂
In this reaction, Cr is oxidized from its elemental form to Cr³+ ion, while H₂PO₄ is reduced to H₂ gas and PO₄³⁻ ions combine with Cr³+ to form CrPO₄.
To balance the reaction, we need to make sure that the number of atoms of each element is equal on both sides of the reaction. In this case, there is one Cr atom and one H₂PO₄ molecule on the left side, and one CrPO₄ molecule and one H₂ molecule on the right side. Therefore, the balanced equation is:
Cr + H₂PO₄ → CrPO₄ + H₂
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How do acids feel?
The properties of acids are _______ by a base.
Please help!!!!
Answer:
neutralized
Explanation:
The properties of acids are neutralized by a base.
what concentration of acetic acid and acetate would you need to make 200.0 ml of a 0.200 m buffer with a ph of 5.00? the pka of acetic acid is 4.76
To create a 200.0 ml buffer solution with a pH of 5.00, you would require roughly 0.0774 M of acetic acid (CH₃COOH) and approximately 0.1226 M of acetate (CH₃COO-), which is the remaining concentration after subtracting the acetic acid concentration from 0.200 M.
How to make 0.200 M acetic acid and acetate buffer with pH 5.00 using 200.0 mL?To calculate the concentrations of acetic acid (CH₃COOH) and acetate (CH₃COO-) required to make a 200.0 ml buffer with a pH of 5.00, we can use the Henderson-Hasselbalch equation:
pH = pKa + log([A-]/[HA])
Given:
pH = 5.00
pKa = 4.76
Volume (V) = 200.0 ml
Buffer concentration ([HA] + [A-]) = 0.200 M
Let's assume the concentration of acetic acid ([HA]) is x M. Therefore, the concentration of acetate ([A-]) would be (0.200 - x) M.
Using the Henderson-Hasselbalch equation, we can write:
5.00 = 4.76 + log([(0.200 - x) / x])
To solve for x, we can rewrite the equation as:
0.24 = log([(0.200 - x) / x])
Taking the antilog of both sides, we get:
10^0.24 = (0.200 - x) / x
Simplifying:
1.5849 = (0.200 - x) / x
Now, we can cross-multiply:
1.5849x = 0.200 - x
2.5849x = 0.200
Solving for x:
x = 0.200 / 2.5849
x ≈ 0.0774 M
Therefore, to make a 200.0 ml buffer solution with a pH of 5.00, you would need approximately 0.0774 M acetic acid (CH₃COOH) and (0.200 - 0.0774) ≈ 0.1226 M acetate (CH₃COO-).
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which line segment represents the activation energy for the reaction between c and d to form a and b
The activation energy for the reaction between C and D to create segments A and B is shown in Segment 3. Here option C is the correct answer.
Activation energy is the minimum amount of energy required to start a chemical reaction. Typically, activation energy is represented graphically as the energy barrier between the reactants and the products in a chemical reaction. However, in general, the activation energy would be represented by the line segment that shows the energy required for the reaction to occur.
The activation energy is often illustrated as a hump on the reaction energy diagram, with the energy required to initiate the reaction being the peak of the hump. Therefore, the line segment that represents the activation energy would be the one that shows the energy required for the reaction to occur.
If the graph shows the energy of the reactants and products over time, then the activation energy would be the difference in energy between the reactants and the highest point on the graph. It's important to note that activation energy is not dependent on the rate of reaction, but rather on the energy needed to start the reaction.
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Complete question:
Which of the following line segments represents the activation energy for the reaction between c and d to form a and b?
A) Line segment 1
B) Line segment 2
C) Line segment 3
D) Line segment 4
What is the molar solubility of Ca(OH)2 in pure water (Ksp - 5.02 x 106)? O 1.36 x 10-2 M O 5.16 x 10-6 M O 1.22 x 10-5 M 1.12 x 10-3M 01.08 x 10-2M
The main answer to the question is 5.16 x 10-6 M.
The molar solubility of Ca(OH)2 in pure water can be determined using the Ksp (solubility product constant) value of 5.02 x 106. The equation for the dissociation of Ca(OH)2 is Ca(OH)2 ⇌ Ca2+ + 2OH-.
Using the Ksp expression, Ksp = [Ca2+][OH-]2, and assuming that the concentration of Ca2+ is equal to the molar solubility (S), we can substitute S for [Ca2+] and get: Ksp = S*(2S)2 = 4S3.
Substituting the Ksp value of 5.02 x 106 into the equation, we get: 5.02 x 106 = 4S3, which can be rearranged to solve for S: S = (5.02 x 106 / 4)1/3 = 5.16 x 10-6 M.
Summary:
The molar solubility of Ca(OH)2 in pure water is 5.16 x 10-6 M, which is calculated using the Ksp value of 5.02 x 106 and the dissociation equation for Ca(OH)2.
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What is the molarity of a solution that contains 80 g of NaOH in 4.0 liters of solution?
To find the molarity of a solution, you need to know the number of moles of solute (NaOH) and the volume of the solution.
First, you need to calculate the number of moles of NaOH:
Molar mass of NaOH = 22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 39.99 g/mol
Number of moles of NaOH = mass of NaOH / molar mass of NaOH
= 80 g / 39.99 g/mol
= 2.001 mol (rounded to three decimal places)
Next, calculate the molarity of the solution:
Molarity (M) = moles of solute / volume of solution (in liters)
= 2.001 mol / 4.0 L
= 0.50025 M (rounded to five decimal places)
Therefore, the molarity of the solution is approximately 0.50025 M.
Answer:
0.50 M
Explanation:
The first step is to calculate the number of moles of NaOH in the solution using the formula:
[tex]\boxed{\bold{moles = \frac{mass}{molar \:mass}}}[/tex]
The molar mass of NaOH is 40.00 g/mol (sodium: 22.99 g/mol, oxygen: 15.99 g/mol, hydrogen: 1.01 g/mol). So, the number of moles of NaOH in the solution is:
moles =[tex]\bold{ \frac{80 g}{40.00 g/mol }}[/tex]= 2.00 mol
The next step is to calculate the molarity of the solution using the formula:
[tex]\boxed{\bold{molarity = \frac{moles\: of \:solute}{volume \:of\: solution \:in\: liters}}}[/tex]
In this case, the moles of solute (NaOH) is 2.00 mol and the volume of solution is 4.0 liters. So, the molarity of the solution is:
molarity = [tex]\frac{2.00 mol}{4.0 L }[/tex]= 0.50 M
Therefore, the molarity of the solution that contains 80 g of NaOH in 4.0 liters of solution is 0.50 M.
which is more stable: 16 protons, 20 neutrons, and 16 electrons when they are combined as two 18 o atoms or as one 36 s atom?
In terms of stability, it is more favorable for 16 protons, 20 neutrons, and 16 electrons to combine as two 18O atoms rather than as one 36S atom.
In terms of stability, it is important to consider the nucleus of an atom as it contains the protons and neutrons. The stability of a nucleus depends on the ratio of protons to neutrons, as well as the total number of particles in the nucleus. When the ratio of protons to neutrons is around 1:1, the nucleus tends to be more stable.
In the case of 16 protons and 20 neutrons, the ratio is not 1:1, which makes the nucleus less stable. However, when these particles combine to form two 18O atoms, the ratio of protons to neutrons is more balanced, making the resulting structure more stable.
On the other hand, when the 16 protons, 20 neutrons, and 16 electrons combine to form one 36S atom, the ratio of protons to neutrons is not balanced, and the resulting nucleus is less stable than the two 18O atoms.
Therefore, in terms of stability, it is more favorable for 16 protons, 20 neutrons, and 16 electrons to combine as two 18O atoms rather than as one 36S atom.
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write the structure of all possible peptides containing these amino acids: arg, lys,phe
There are several possible peptides containing the amino acids arginine (arg), lysine (lysine), and phenylalanine (phe). Here are some examples:
Arg-Lys-Phe: This is a tripeptide with arginine at the amino-terminal end, phenylalanine at the carboxy-terminal end, and lysine in the middle. The structure is NH2-Arg-Lys-Phe-COOH.
Lys-Arg-Phe: This is another tripeptide with lysine at the amino-terminal end, phenylalanine at the carboxy-terminal end, and arginine in the middle. The structure is NH2-Lys-Arg-Phe-COOH.
Arg-Phe-Lys: This is a tripeptide with arginine at the amino-terminal end, lysine at the carboxy-terminal end, and phenylalanine in the middle. The structure is NH2-Arg-Phe-Lys-COOH.
Lys-Phe-Arg: This is a tripeptide with lysine at the amino-terminal end, arginine at the carboxy-terminal end, and phenylalanine in the middle. The structure is NH2-Lys-Phe-Arg-COOH.
Phe-Arg-Lys: This is a tripeptide with phenylalanine at the amino-terminal end, lysine at the carboxy-terminal end, and arginine in the middle. The structure is NH2-Phe-Arg-Lys-COOH.
Phe-Lys-Arg: This is a tripeptide with phenylalanine at the amino-terminal end, arginine at the carboxy-terminal end, and lysine in the middle. The structure is NH2-Phe-Lys-Arg-COOH.
Note that the amino acids can be arranged in different orders to form different peptides, but the peptide bond is always between the carboxyl group of one amino acid and the amino group of the next.
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