The empirical formula of a compound with molecules containing 12 carbon atoms, 14 hydrogen atoms, and 6 oxygen atoms is __________.
Select one:
a. C2H4O
b. CH2O
c. C6H7O3
d. C12H14O6
e. CHO

6.5 g of CO2 occupy 3614.26 ml at STP .

Ideal gas equation

PV = nRT

 Given

   P = 1 atm (at STP)

   V = ?

   n = Mass / Molar mass

       = 6.5 g/ 44g/mol

       = 0.147 moles

   R = 0.0821 L.atm/mol.K

   T = 298 K ( at STP)

 Substitute these values

 V = nRT/P

     = (0.147 )(0.0821)(298)/1

     = 3.61 L

 We know that

 1000 ml = 1L

 so 3.61 L = 3614.26 ml

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To find out how many grams are in 25 moles of Na3N, we need to first determine the molar mass of Na3N and then multiply it by the number of moles.

Step 1: Determine the molar mass of Na3N.
The molar mass of Na (Sodium) is 22.99 g/mol, and the molar mass of N (Nitrogen) is 14.01 g/mol. The formula for Na3N has 3 Sodium atoms and 1 Nitrogen atom. So, we calculate the molar mass as follows:
(3 × 22.99) + (1 × 14.01) = 68.97 + 14.01 = 82.98 g/mol

Step 2: Multiply the molar mass by the number of moles.
Now we multiply the molar mass (82.98 g/mol) by the number of moles (25 moles) to get the total mass in grams:
82.98 g/mol × 25 moles = 2,074.5 grams

So, there are 2,074.5 grams in 25 moles of Na3N. The correct answer is:
a. 2,074.5 grams

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A catalyst is a substance that increases the rate of a chemical reaction by lowering the activation energy required for the reaction to occur.

A catalyst itself does not participate in the reaction and is not consumed stoichiometrically or nonstoichiometrically. Instead, it speeds up the reaction by providing an alternative reaction pathway with a lower activation energy.

Therefore, a catalyst does not get consumed at all during a reaction. It can be used repeatedly in the same reaction or in different reactions, making it a cost-effective way to accelerate chemical reactions.

The use of catalysts is a common technique in many chemical processes, including the production of fuels, pharmaceuticals, and plastics.

Catalysts can also improve the efficiency and selectivity of reactions, leading to higher yields and reduced waste.

In addition, catalysts can be used to modify the properties of materials, such as their strength or durability, through catalytic reactions on their surfaces. Overall, catalysts play a crucial role in the modern chemical industry and research.

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The hydronium ion concentration of the acid rain sample with a pH of 3.25 is approximately 5.62 × 10^-4 M. The correct answer is option B.

To find the hydronium ion concentration of an acid rain sample with a pH of 3.25, you need to use the pH formula:

pH = -log10[H₃O+]

where pH is 3.25 and [H₃O+] represents the hydronium ion concentration. To solve for [H₃O+], follow these steps:

1. Rewrite the formula as: [H₃O+] = 10^(-pH)
2. Substitute the pH value: [H₃O+] = 10^(-3.25)
3. Calculate the hydronium ion concentration: [H₃O+] ≈ 5.62 × 10^-4 M

So, the hydronium ion concentration of the acid rain sample with a pH of 3.25 is approximately 5.62 × 10^-4 M. The correct answer is option B.

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Yes, it affects the results as the concentration of the standard solutions is a crucial factor in the experiment since it has an impact on the reaction's stoichiometry and the quantity of precipitate produced.

The amount of precipitate created would differ if the concentration of the standard solutions was different from the anticipated value, which would result in mistakes in the computed values of the unknown concentrations.

In this instance, more precipitate would have formed if the AgNO₃standard solution concentration had been 0.0024 M instead of 0.0020 M. This is because more Ag+ ions would have been accessible for the reaction.

In order to acquire accurate and consistent results from the experiment, it is crucial to make sure that the standard solutions are produced correctly and that their concentrations are confirmed.

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The element which makes up the framework of organic compounds and which cycles through all ecosystems is  carbon.

Carbon is a fundamental element of organic compounds, including proteins, carbohydrates, lipids, and nucleic acids, which are essential building blocks of all living organisms. Carbon cycles through all ecosystems through processes such as photosynthesis, respiration, decomposition, and combustion. Carbon is also involved in the formation of fossil fuels, which are a major source of energy for human societies.

It is essential for life as it is found in all living organisms, and it cycles through ecosystems . This cycling of carbon is known as the carbon cycle.

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To find the hydroxide ion concentration, we first need to calculate the concentration of hydrogen ions (H+) using the pH value. The pH formula is pH = -log[H+]. Rearranging this formula, we get [H+] = 10^-pH.

So, [H+] = 10^-9.20 = 6.31 × 10^-10 M

Since lye is a strong base, it completely dissociates in water to produce hydroxide ions (OH-). The concentration of hydroxide ions is equal to the concentration of the lye solution.

Therefore, the hydroxide ion concentration of the lye solution with a pH of 9.20 is A) 6.31 × 10^-10 M.

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To find the molecular formula of the compound, we need to first calculate its empirical formula mass. The empirical formula mass can be found by adding the atomic masses of the elements in the empirical formula:

C4H9: (4 x 12.01 g/mol) + (9 x 1.01 g/mol) = 57.09 g/mol

Next, we need to determine the ratio between the empirical formula mass and the molar mass of the compound:

114.26 g/mol / 57.09 g/mol = 2

This means that the molecular formula of the compound is two times the empirical formula. To find the molecular formula, we simply multiply the empirical formula by 2:

C4H9 x 2 = C8H18

Therefore, the compound's molecular formula is C8H18.

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To perform Jones oxidation when converting primary alcohols to carboxylic acids or secondary alcohols to ketones, you will need the following three things:

1. The alcohol: The starting material, either a primary alcohol for conversion to a carboxylic acid or a secondary alcohol for conversion to a ketone.

2. Chromium trioxide (CrO3): This is the oxidizing agent used in Jones oxidation. It is responsible for oxidizing the alcohol to the desired product.

3. Sulfuric acid (H2SO4): This is the acidic catalyst required for the reaction to take place. It helps in the formation of the reactive intermediate needed for the oxidation process.

In summary, to convert alcohols to carboxylic acids or secondary alcohols to ketones using Jones oxidation, you will need the alcohol, chromium trioxide (CrO3), and sulfuric acid (H2SO4).

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The error is the there are the planets in the solar system which do not have the moons as the every planet that in the solar system that has at least on moon.

Planet is the celestial body which is the orbit around the Sun. The planet which has the sufficient mass for the gravity to be overcome with the rigid body the forces acts and so that the hydrostatic equilibrium that  is nearly round in the shape, and it also has the cleared and the neighborhood around the orbit.

The planet have the enough to have the gravity of force it into the spherical shape. The planet are big enough which the gravity cleared the away of any other objects which is similar to size and the shape near the orbit and around the Sun.

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The reaction 4Al (s) + 3 O2(g) → 2 Al2O3(s) with ∆H = -3351 kJ is exothermic, and therefore heat is released by the reaction. The answer is D) exothermic, released.

An exothermic reaction is a chemical reaction that releases heat into the surroundings, and it has a negative ∆H value. In this case, the ∆H is -3351 kJ, which indicates that the reaction is exothermic. As a result, heat is released during the reaction, making the surroundings warmer. This is in contrast to an endothermic reaction, where heat is absorbed from the surroundings, resulting in a positive ∆H value and a decrease in the surrounding temperature. Thus, the answer is D) exothermic, released.

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Ethane gas reacts with oxygen gas to produce carbon dioxide gas and water vapor gas.

[tex]C2H6 (g) + O2 (g) → CO2 (g) + H2O (g)[/tex]

Ethane gas is a hydrocarbon with the chemical formula C2H6. It is a colorless and odorless gas that is present in natural gas and is also produced through the refining of petroleum. Ethane is a member of the alkane family, which are hydrocarbons that have only single bonds between carbon atoms. The molecule consists of two carbon atoms and six hydrogen atoms.

Ethane has a boiling point of -88.6°C and a melting point of -182.8°C. It is highly flammable and can form explosive mixtures with air. Ethane is used primarily as a fuel for heating and cooking, as well as a feedstock for the production of other chemicals.

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Answer:

By 335.2 degrees Celsius

Explanation:

-18.1 KJ * 1000 = -18100 J

J = mass * specific heat * Change of Temp

-18100 = 60 * .9 * x

x = -335.2

Answer:

261.52 grams of zinc to react fully with 8.0 moles of silver nitrate.

Explanation:

To solve this problem, we need to use the balanced chemical equation for the reaction between zinc and silver nitrate:

Zn + 2AgNO3 → Zn(NO3)2 + 2Ag

From the equation, we can see that 1 mole of zinc reacts with 2 moles of silver nitrate to produce 2 moles of silver. Therefore, if we have 8.0 moles of silver nitrate, we will need 4.0 moles of zinc to react with all of the silver nitrate.

To convert moles of zinc to grams, we need to use the molar mass of zinc, which is 65.38 g/mol.

Mass of zinc = number of moles of zinc x molar mass of zinc

Mass of zinc = 4.0 mol x 65.38 g/mol

Mass of zinc = 261.52 g

Therefore, we need 261.52 grams of zinc to react fully with 8.0 moles of silver nitrate.

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The amount in grams of zinc are needed to react fully with 8.0 moles of silver nitrate is 261.52 grams.

To determine the grams of zinc needed to react fully with 8.0 moles of silver nitrate, we first need to establish the balanced chemical equation for the reaction. This is a single displacement reaction:

Zn + 2AgNO₃ → Zn(NO₃)₂ + 2Ag

From the balanced equation, we can see that 1 mole of zinc reacts with 2 moles of silver nitrate. To find out how many moles of zinc are needed for 8.0 moles of silver nitrate, we can use the stoichiometry:

(1 mole Zn / 2 moles AgNO₃) × 8.0 moles AgNO₃ = 4.0 moles Zn

Now, we can convert the moles of zinc into grams using the molar mass of zinc (65.38 g/mol):

4.0 moles Zn × 65.38 g/mol = 261.52 g

So, 261.52 grams of zinc are needed to react fully with 8.0 moles of silver nitrate.

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To find the hydronium ion concentration of a 0.150 M hypochlorous acid solution with Ka = 3.5 x 10^-8, follow these steps:

1. Write the Ka expression for the dissociation of hypochlorous acid: Ka = [H3O+][OCl-] / [HOCl].

2. Set up an ICE table to track the changes in concentrations during the reaction:

   Initial: [HOCl] = 0.150 M, [H3O+] = 0 M, [OCl-] = 0 M
   Change: [HOCl] = -x, [H3O+] = +x, [OCl-] = +x
   Equilibrium: [HOCl] = 0.150-x, [H3O+] = x, [OCl-] = x

3. Substitute the equilibrium concentrations into the Ka expression: 3.5 x 10^-8 = (x)(x) / (0.150-x)

4. Since Ka is very small, the x value is much smaller than 0.150. Therefore, we can approximate 0.150-x as 0.150: 3.5 x 10^-8 = (x)(x) / 0.150

5. Solve for x, which represents the hydronium ion concentration: x = √(3.5 x 10^-8 * 0.150) = 7.2 × 10^-5 M

The hydronium ion concentration of the 0.150 M hypochlorous acid solution is 7.2 × 10^-5 M (Option D).

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Answer:

correct answer is (A) AgNO3 (aq).

Explanation:

Metal Plating in Solutions

Nehal Kafle

A 2.0 A current is applied to beakers containing identical volumes of each of the following 1.0 M solutions. In beaker will the greatest mass of metal plate out? (A) AgNO3 (aq) (B) CuSO4 (aq) (C) FeCl2 (aq) (D) AlBr3 (aq)

The metal that plates out will be the one that has the highest reduction potential among the metals present in the solution. We can determine this by consulting a table of standard reduction potentials. Here are the reduction half-reactions for the four metal ions:

(A) Ag+ + e- → Ag E° = +0.80 V

(B) Cu2+ + 2e- → Cu E° = +0.34 V

(C) Fe2+ + 2e- → Fe E° = -0.44 V

(D) Al3+ + 3e- → Al E° = -1.66 V

The greater the reduction potential, the easier it is for the metal to gain electrons and be reduced to its elemental form. Thus, the metal with the highest reduction potential will plate out first.

Comparing the reduction potentials of the four metals, we see that Ag+ has the highest reduction potential (+0.80 V), followed by Cu2+ (+0.34 V), Fe2+ (-0.44 V), and Al3+ (-1.66 V). Therefore, the solution with AgNO3 will have the greatest mass of metal plating out.

Therefore, the correct answer is (A) AgNO3 (aq).

During a chemical reaction, the concentrations of the reactants and products reach a constant level when the reaction reaches equilibrium.

At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, meaning that the concentrations of both the reactants and products remain constant. The equilibrium concentration of each product and reactant is determined by the reaction's equilibrium constant, which is unique for each reaction.
Hi! During a chemical reaction, the point at which the concentrations of the reactants and products reach a constant level is defined as "equilibrium." At equilibrium, the rate of the forward reaction (formation of products) is equal to the rate of the reverse reaction (formation of reactants), resulting in constant concentrations of both reactants and products.

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For a chemical reaction present in above figure,

a) The limiting reagent is Alkene.

b) The theoretical yield of product is 3.32 g.

c) The percentage yield is about 92%, when the actual yield is 3.05 g.

We have a reaction starting with 1.50 g of the alkene substrate, 3.75 g of pyridinium tribromide, and 20.0 ml of acetic acid and produce a single product is obtained. See the above figure 2.

Molecular mass of reactant = 10× 12 + 12×1 = 132 g

Molecular mass of product = 10× 12 + 2× 80 + 12 × 12 =292 g

a) The limiting reagent is alkene in this reaction.

According to reaction, 132g reactant -> 292 g product

so, 1g reactant --> 292/132 g product

1.50 g reactant ->1.50( 292/132)g product

= 3.32 g product

b) The theoretical yield of product is 3.32 g in this reaction.

c) Percent Yield is calculated as the actual yield divided by the theoretical yield then multiply the resultant with 100.

Now, 3.05 g of pure product, that is actual yield of product= 3.05 g

Percentage of yield= ( 3.05 /3.32 )× 100

= 91.86% ~ 92%

Hence, required value is 92%.

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Complete question:

The above figure complete the question

a researcher performs the above reaction starting with 1.50 g of the alkene substrate, 3.75 g of pyridinium tribromide, and 20.0 ml of acetic acid. only one product is observed. 2. what is the limiting reagent? b. what is the theoretical yield? c. if the researcher obtains 3.05 g of pure product, what is the percent yield?

Water's unique structural property that contributes to its high specific heat and high heat capacity is its hydrogen bonding. Hydrogen bonding occurs between the positively charged hydrogen atoms in water molecules and the negatively charged oxygen atoms in neighboring water molecules.

Hydrogen bonding allows water to absorb and store large amounts of heat energy without a significant increase in temperature, making it an excellent insulator.  Water has a unique structural property known as hydrogen bonding. Hydrogen bonding occurs between the positively charged hydrogen atoms in water molecules and the negatively charged oxygen atoms in neighboring water molecules. This bonding allows water to absorb and store large amounts of heat energy without a significant increase in temperature. As a result, water has high specific heat and high heat capacity, making it an excellent insulator.

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The molarity of the strong biprotic acid is 1.00 M. The molarity of the acid can be calculated using the equation MaVa = MbVb, where Ma is the molarity of NaOH and Mb is the molarity of the acid.

In this corrosive base balance response, 100 mL of 0.5 M NaOH responds with 25 mL of a solid biprotic corrosive. We can utilize the decent compound condition to decide the molarity of the corrosive.

[tex]2 NaOH + H_{2} A[/tex] → [tex]Na_{2 }A + 2 H_{2} O[/tex]

The stoichiometric proportion among NaOH and [tex]H_{2} A[/tex] is 2:1. Subsequently, we can compose:

Molarity of NaOH x Volume of NaOH = Molarity of [tex]H_{2} A[/tex] x Volume of [tex]H_{2} A[/tex] x 2

Subbing the given qualities:

0.5 M x 100 mL = Molarity of [tex]H_{2} A[/tex] x 25 mL x 2

Molarity of [tex]H_{2} A[/tex] = (0.5 M x 100 mL)/(25 mL x 2) = 1.0 M

Notwithstanding, the naoh neutralizes 25 ml of a strong biprotic acid and the corrosive is biprotic, meaning it can give two protons. The response condition shows that two moles of NaOH respond with one mole of [tex]H_{2} A[/tex], demonstrating that only one proton is killed in this response. Accordingly, the molarity of the corrosive is divided to represent the subsequent proton.

Molarity of [tex]H_{2} A[/tex] = 1.0 M/2 = 0.5 M

In this manner, the response is b. 0.50 M.

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Answer:

Therefore, the final pressure inside the scuba tank after cooling from 500°C to 25.5°C is 47.4 atm.

Explanation:

To calculate the final pressure inside the scuba tank, we can use the ideal gas law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the initial temperature from Celsius to Kelvin:

T1 = 500°C + 273.15 = 773.15 K

Next, we need to calculate the number of moles of gas in the tank. We can use the equation:

n = PV/RT

where n is the number of moles, P is the pressure, V is the volume, R is the gas constant, and T is the temperature in Kelvin.

Assuming the volume of the tank remains constant, we can use the same volume for both the initial and final states, so we can cancel out V:

n = P1/RT1

where P1 is the initial pressure and T1 is the initial temperature.

n = (130.0 atm)/(0.08206 L·atm/mol·K × 773.15 K) = 2.009 mol

Now, we can use the same equation to calculate the final pressure, using the final temperature of 25.5°C or 298.65 K:

P2 = nRT2/V

where P2 is the final pressure, T2 is the final temperature, and V is the volume.

P2 = (2.009 mol) × (0.08206 L·atm/mol·K) × (298.65 K) / V

To solve for V, we need to assume a value for the volume of the tank. Let's assume a typical scuba tank volume of 11.1 L.

V = 11.1 L

P2 = (2.009 mol) × (0.08206 L·atm/mol·K) × (298.65 K) / 11.1 L

P2 = 47.4 atm

Therefore, the final pressure inside the scuba tank after cooling from 500°C to 25.5°C is 47.4 atm.

The calculation of relative quantities of reactants, products, and energy in a chemical reaction is called stoichiometry. Here is how you can perform this calculation:

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The pH of the given buffer solution is 6.87 (option B)

To calculate the pH of the given buffer solution, we need to use the Henderson-Hasselbalch equation which is given as:

[tex]pH = pKa + log([A^-]/[HA])[/tex]

Where pKa is the dissociation constant of the weak acid, [A^-] is the concentration of the conjugate base and [HA] is the concentration of the weak acid.

In this case, HClO is the weak acid and ClO^- is its conjugate base. Therefore, the pKa of HClO is 2.9 × 10^-8. The concentrations of HClO and NaClO are 1.58 M and 0.099 M respectively.

Now, we can substitute the values in the Henderson-Hasselbalch equation and solve for pH:

[tex]pH = 2.8 + log([0.099]/[1.58])pH = 6.87[/tex]

So, the correct answer is option B.

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When dissolved in water, the compound generally considered to be an Arrhenius acid is A) HNO2.

This is because Arrhenius acids are substances that increase the concentration of hydrogen ions (H+) when dissolved in water.

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Concentration is defined as the ratio of the amount of solute to the amount of solvent or solution. It is typically expressed in terms of mass or volume. For example, a 1:1 ratio of solute to solvent would indicate that the solution contains equal amounts of the two components.

A component is a reusable, independent piece of code that is designed to perform a specific task. Components are self-contained, often with their own user interface, and can be combined with other components to create larger, more complex applications. Components are a fundamental building block in software engineering, and they can be used in a variety of ways, such as to create a customer relationship management application, a web-based game, or a virtual assistant. Components can also be used to create software libraries, frameworks, and plugins. They are often written in different programming languages, such as HTML, CSS, JavaScript, or Java.

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The folds of the inner mitochondrial membrane are called cristae. The mitochondrial matrix is where many of the metabolic reactions of the mitochondria occur, such as the Krebs cycle and the oxidation of fatty acids. The inner mitochondrial membrane does not contain cholesterol.

The mitochondrial matrix is located within the inner mitochondrial membrane. The inner membrane has folds called cristae. In the matrix, crucial processes like the Krebs cycle (also known as the citric acid cycle or TCA cycle) and the conversion of pyruvate to acetyl-CoA occur. The inner mitochondrial membrane does not contain cholesterol, as it is primarily composed of phospholipids and proteins.

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The volume contained by 6.8 g of ammonia at STP is 8.96 L.

To find the volume of ammonia at STP (standard temperature and pressure) from the given mass, we can use the ideal gas law:

PV = nRT

where:

P = pressure (at STP, this is 1 atm)

V = volume

n = number of moles

R = gas constant (0.08206 L·atm/mol·K)

T = temperature (at STP, this is 273 K)

First, we need to calculate the number of moles of ammonia from the given mass. The molar mass of ammonia is:

(1 x 3) + (14 x 1) = 17 g/mol

So, the number of moles (n) of NH₃ is:

n = mass / molar mass

n = 6.8 g / 17 g/mol

n = 0.4 mol

Now, we can use the ideal gas law to find the volume (V):

PV = nRT

V = nRT / P

V = (0.4 mol)(0.08206 L·atm/mol·K)(273 K) / 1 atm

V = 8.69 L

Therefore, the volume contained by 6.8 g of ammonia at STP is 8.69 L.

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The direction in which molecules are transported via active transport across cell membranes is against their concentration gradient, meaning from an area of lower concentration to an area of higher concentration.

Active transport requires energy in the form of ATP (adenosine triphosphate) because it is working against the natural tendency of molecules to move toward equilibrium.

In contrast to passive transport (such as diffusion and osmosis), which relies on the inherent movement of molecules from higher to lower concentration without the need for energy input, active transport is vital for maintaining specific concentrations of certain substances within cells. This regulation is essential for proper cell function and homeostasis.

Examples of active transport include the sodium-potassium pump, which maintains the appropriate balance of sodium and potassium ions inside and outside of cells, and the uptake of glucose by cells in the small intestine. Both processes use specialized proteins called transporters to move the molecules across cell membranes, ensuring that the necessary concentrations are maintained for optimal cellular function.

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Strontium phosphate is expected to get readily dissolved in acidic solution.

Generally solubility is defined the term used for the ability of a substance, that is solute is the substance that is to be dissolve in a solution, and the substance in which solute gets dissolved is known as solvent. Some of the common examples are dissolving sugar in water to form sugar solution and sand not dissolving in water etc.

Generally when the solubility products of both ionic compounds are calculated, it has been found that the phosphate ion has more value. Hence, strontium phosphate dissolves readily in acidic solutions.

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