The first 5 terms of a sequence are 2 8 14 20 26 Find the nth term ​

The x-intercept and the asymptote of g(x) are x = 5 and x = 4, respectively

The equation of the function is given as:

g(x)  = log3 (x - 4)

Set the function to 0, to determine the x-intercept

log3 (x - 4) = 0

Express the function as an exponential function

x - 4 = 3^0

Evaluate the exponent

x - 4 = 1

Add 4 to both sides

x = 5

Set the radical to 0, to determine the asymptote

x - 4 = 0

Add 4 to both sides

x = 4

Hence, the x-intercept and the asymptote of g(x) are x = 5 and x = 4, respectively

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Answer: [tex]\Large\boxed{B.~\displaystyle 75~m^3}[/tex]

Step-by-step explanation:

Given information

Height = 2 m

Base = 5 m

Length = 15 m

Given the formula for Triangular Prism Volume

[tex]V~=~\displaystyle \frac{1}{2}\times ~b~\times~h~\times~l[/tex]

[tex]\to V=Volume\\\to b=base\\\to h = height\\\to l = length[/tex]

Substitute values into the formula

[tex]V~=~\displaystyle \frac{1}{2}\times ~(5)~\times~(2)~\times~(15)[/tex]

Simplify by multiplication

[tex]V~=~\displaystyle \frac{5}{2}~\times ~30[/tex]

[tex]\Large\boxed{V~=~\displaystyle 75~m^3}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex]y=\frac{-x}{78} -\frac{220}{78}[/tex]

Step-by-step explanation:

Remember to create a line perpendicular to one another the slope has to be the reverse reciprocal of the first line.

Given the current slope is [tex]\frac{-78}{1}[/tex] the new slope would be [tex]\frac{1}{78}[/tex].

To find the line that passes through a point with a given slope we must use point slope form, remember the default equation of point slope form:

[tex]y-y1=m(x-x1)[/tex]

Where y1 is the y value of the point, m is the slope, and x1 is the x value of the point.

Lets substitute in our values

[tex]y-(-3)=\frac{-1}{78} (x-14)[/tex]

Simplify the equation

[tex]y+3=-\frac{1}{78}\left(x-14\right)\\y+3=\frac{-x}{78}+\frac{14}{78}\\y=\frac{-x}{78}-\frac{220}{78}\\[/tex]

[tex]\qquad \qquad \textit{sum of an infinite geometric sequence} \\\\ \displaystyle S=\sum\limits_{i=0}^{\infty}\ a_1\cdot r^i\implies S=\cfrac{a_1}{1-r}\quad \begin{cases} a_1=\stackrel{\textit{first term}}{\frac{1}{8}}\\ r=\stackrel{\textit{common ratio}}{\frac{2}{3}}\\ \qquad -1 < r < 1 \end{cases}[/tex]

[tex]\displaystyle\sum_{k=0}^{\infty} ~~ \underset{a_1}{\frac{1}{8}}\underset{r}{\left( \frac{2}{3} \right)}^k\implies S=\cfrac{ ~~ \frac{1}{8} ~~ }{1-\frac{2}{3}}\implies S=\cfrac{ ~~ \frac{1}{8} ~~ }{\frac{1}{3}}\implies S=\cfrac{3}{8}[/tex]

Answer:

Step-by-step explanation:

2x + 1 = 4x - 19

Solve for x

2x + 1 = 4x - 19

2x - 4x = -19 - 1

-2x = -20

x = 20 : 2

x = 10

----------------

check

2 * 10 + 1 = 4 * 10 - 19

21 = 21

the answer is good

Answer: [tex]\Large\boxed{x=10}[/tex]

Step-by-step explanation:

2x + 1 = 4x - 19

Add 19 on both sides

2x + 1 +19 = 4x - 19 + 19

2x + 20 = 4x

Subtract 2x on both sides

2x + 20 - 2x = 4x - 2x

20 = 2x

Divide 2 on both sides

20 / 2 = 2x / 2

[tex]\Large\boxed{x=10}[/tex]

Hope this helps!! :)

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Answer:

They are only equal on day 0, both having 10 population.

Step-by-step explanation:

Given the bacteria on the counter is initially measured at 5 and doubles every 3 days we can generate the following geometric equation:

[tex]f(x)=10*2^{\frac{x}{3} }[/tex]

Given the bacteria on the stove is measured at 10 and doubles every 4 days we can create another equation:

[tex]f(x)=10*2^{\frac{x}{4} }[/tex]

To find how many days it will take for the bacteria population to equal the same lets set both equations equal to eachother:

[tex]10*2^{x/3}=10*2^{x/4}[/tex]

Divide both sides by 10

[tex]2^{x/3}=2^{x/4}[/tex]

Since both exponents have the same base we can set the exponents equal to eachother and solve for x:

[tex]\frac{x}{3}=\frac{x}{4}[/tex]

Multiply both sides by 3 to isolate x on the left side

[tex]x=\frac{3x}{4}[/tex]

Multiply both sides by 4 to remove fraction

[tex]4x=3x[/tex]

Subtract 3x to isolate x on the left side

[tex]x=0[/tex]

Plug x into one of our original equations

[tex]f(0)=10*2^{0/3}[/tex]

Solve

[tex]f(0)=10[/tex]

If adding only twelve, you must leave out three of the fifteen, and the number of ways is = 15! / (3! * 12!).

1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12∗13∗14∗15 over

(1∗2∗3)∗(1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12) =

13∗14∗15 over

(1∗2∗3)

27306 = 455

Answer: If all toppings are distinct, then you have C 4 15 combinations. If there are three distinct toppings, you have 3 ⋅ C 3 15 combinations (because we have C 3 15 choices for toppings and then 3 choices for which of those three toppings is doubled).

Step-by-step explanation:

According to general rules, what you can do now is; Ascend right away to 15 feet and stay there for 8 minutes before going to the surface and not dive for 6 hours

We are given;

Initial distance dived = 56 feet

Time for initial dive = 47 minutes

Time from finishing of initial dive to start of second dive = 30 minutes

Second dive distance = 56 ft

Her current bottom time is now 25 minutes

Now, bottom time is defined as the total time, in minutes, from the beginning of a descent to the beginning of an ascent.

Thus, according to general rules, what you can do now is to Ascend right away to 15 feet and stay there for 8 minutes before going to the surface and not dive for 6 hours

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The value of x from the given diagram is -10

Two triangles are known to be similar if the ratio of their similar sides is equal. The diagram shown is similar to the required diagram.

Given the following parameters

<ABC = 2x

<BAC = 3x + 10

Equate the expression since both angles are equal. Substitute;

2x = 3x + 10

Subtract 3x from both sides

2x-3x = 3x-3x+10

-x = 10

x = -10

Hence the value of x from the given diagram is -10

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Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

Given the following data:

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

Where:

Also, the period of a sine wave is given by:

t = 2π/ω

2 = 2π/ω

ω = 2

Substituting the given parameters into the equation, we have;

y = 3sin(2t + π/2)

At t = 0, we have:

y = 3sin(2(0) + π/2)

y = 3sin(π/2)

y = 3sin(90)

y = 3 × 1

y = 3.

In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.

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Answer:

I think its -10 or -8

Step-by-step explanation:

Answer:

The answer is 1. This table is an example of the principle of independence.

Step-by-step explanation:

This means any Trade activity is performed without reliance on another party.

He got the perfect answer to his question and he can get his answer without any other information.

the area and volume of the Pyramid of Gaza are  139, 840 m²

and 52950 m³ respectively.

The formula for volume and area of a square pyramid are given thus;

Volume, V= [tex]a^2\frac{h}{3}[/tex]

Area , [tex]A=a^2+2a \sqrt{\frac{a^2}{4}+ h^2 }[/tex]

Where

Substitute the values;

Area = [tex]230^2 + 2(230) \sqrt{\frac{230^2}{4}+ 150^2 }[/tex]

Area = [tex]52900 + 460 + \sqrt{13225 + 22500}[/tex]

Area = [tex]52900 + 460(189)[/tex]

Area = 52900 + 86, 940

Area = 139, 840 m²

Volume , v = [tex]230^2 + \frac{150}{3}[/tex]

Volume = 52900 + 50

Volume = 52950 m³

Thus, the area and volume of the Pyramid of Gaza are  139, 840 m²

and 52950 m³ respectively.

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answer is in the attachment below

goodluck!!

The statement; In western culture, 4 to 12 feet is considered public space whereas personal space is 1½ to 4 feet is false.

These refers to culture which is related to the people of the west.

Culture

This can be defined as the beliefs, values, behaviour and material objects that constitute a people's way of life.

Therefore, it is b false that in western culture, 4 to 12 feet is considered public space whereas personal space is 1½ to 4 feet.

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Answer:

0.012

Step-by-step explanation:

We know the standard notation of table salt is 0.003, so we simply multiply 40 by this.

answer - 0.0003 X 40 = 0.012

This number in expanded form 200 + 5 + 5/10 + 9/100  .

What is expanded form in math example?

Given  : 205.95 centimeters.

the number in a expanded form.

200 + 5 + 9/10 + 5/100

we have given 205.95 centimeters.

We can see 2 is at hundred place = 200.

0 is at tens place = 00.

5 is at ones place  = 5.

9 after decimal is at tenth place =  [tex]\frac{9}{10}[/tex].

5 is at hundredth place  = [tex]\frac{5}{100}[/tex] .

Therefore , Expanded form : 200 + 5 + 5/10 + 9/100 .

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The 95% confidence interval for the population standard deviation will be,

[tex]$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\[/tex]

simplifying the equation, we get

[tex]$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288[/tex]

The 95% confidence interval exists (9.887, 21.288).

A random sample of 15 men exists selected. The mean weight exists at $165.2 pounds and the standard deviation exists at $13.5 pounds. The population exists normally distributed.

So, [tex]$n=15, \bar{X}=165.2, s=13.5$[/tex]

where n exists the sample size, [tex]$\bar{X}$[/tex] exists the sample size

s exists the sample standard deviation.

The degrees of freedom will be n - 1 i.e.15 - 1 = 14.

For a 95% confidence interval, the level of significance will be [tex]$\alpha=0.05$[/tex].

The 95% confidence interval for the population standard deviation will be,

[tex]$\sqrt{\frac{(n-1) s^{2}}{\chi^{2}} \frac{\alpha}{2}} & < \sigma < \sqrt{\frac{(n-1) s^{2}}{\chi^{2}}} \\[/tex]

substitute the values in the above equation, we get

[tex]$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi^{2}} 0.05} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0}^{2}}} \\[/tex]

[tex]$\sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.975}^{2}}} & < \sigma < \sqrt{\frac{(15-1)(13.5)^{2}}{\chi_{0.025}^{2}}} \\[/tex]

simplifying the above equation, we get

[tex]$\sqrt{\frac{2551.5}{26.1}} & < \sigma < \sqrt{\frac{2551.5}{5.63}} \\9.887 & < \sigma < 21.288[/tex]

The 95% confidence interval exists (9.887, 21.288).

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Answer:

c.

Step-by-step explanation:

The two triangles are similar as they have the same angles, though not necessarily the same sides. ASA only applies to congruency.

the area of the shaded part is 30. 89 cm²

We have the shape to be a rectangle

The area of the shaded part should be;

Area of rectangle - 2 ( area of a semi circle)

The formula for area of a rectangle

Area = length × width

Area = 12 × 12

Area = 144 cm²

Area of a semicircle = 1/2 πr²

Area = 1/ 2 × 3. 142 × 6²

Area = 56. 56 cm²

Area of shaded part = area of rectangle - 2( area of semicircle)

Area of shaded part = 144 - 2(56. 56)

Area of shaded part = 144 - 113. 11

Area of shaded part = 30. 89 cm²

Thus, the area of the shaded part is 30. 89 cm²

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The length of the longest piece of the cut rope is; 105 cm

We are given that;

Length of rope = 245 cm

We need to make the ratio of second piece equal in both the ratio to find the ratio of all three pieces.

2:3

4:5

Multiply 1st ratio by 4 and 2nd ratio by 3:

Now, the ratio becomes: 8:12 and 12:15

And the ratio of three pieces can be represented as:

8: 12: 15, this ratio is the first piece: second piece: third piece

Thus;

8x + 12x + 15x = 245

35x = 245

x = 245/35

So, the pieces lengths will be;

First piece = 8 * 7 = 56 cm

Second piece = 12 * 7 = 84 cm

Third piece = 15 * 7 = 105 cm

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The general solution of the given higher-order differential equation y''' − 8y'' − 9y' = 0 is ,    [tex]y = C_{1} + C_{2} e^{8x} + C_{3}e^{-x}[/tex]

Given higher-order differential equation = y''' − 8y'' − 9y' = 0

We have to find the general solution of the above differential equation

The auxiliary equation for the above differential equation will be :                             [tex]m^{3} - 8m^{2} - 9m = 0[/tex]

Solve the equation :- [tex]m^{3} - 8m^{2} -9m = 0[/tex]

                                  [tex]m ( m^{2} - 8m - 9 ) = 0[/tex]

                                  m ( m - 8 ) ( m + 1 ) = 0

                                  m = 0 , m = 8 , m = -1

Then the general solution will be like :

[tex]y = C_{1} e^{0x} + C_{2} e^{x} +C_{3}e^{-1x}[/tex]

The above solution can be written as:

[tex]y = C_{1} +C_{2} e^{8x} +C_{3} e^{-x}[/tex]

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The missing reason in step 8 is the substitution property.

It should be noted that according to substitution property, if x = y, then x can be substituted for y in any equation.

When a variable is equal to another variable, then the variables can be interchangeable.

In this case, the missing reason in step 8 is the substitution property.

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Answer:

The value of

[tex]a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b \: [/tex]

is

[tex] \frac { 19}{8} [/tex]

Step-by-step explanation:

[tex]a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b[/tex]

where,

Thus, substitute these values to the given equation to find the values.

[tex]a {}^{b} - c \: b {}^{c} - a \: c {}^{a} - b ... \: substitute \: \\ given \: values \\ (1) {}^{2} - ( - 3)(2) {}^{ - 3} - 1( - 3) {}^{1} - 2 \\ 1 + 3 \: ( \frac{1}{8} ) - 1( - 3) - 2 \\ 1 + \frac{3}{8} + 3 - 2 \\ \frac{11}{8} + 3 - 2 \\ \frac{35}{8} - 2 \\ \frac{19}{8} = 2 \frac{3}{8} [/tex]

Hope it helps

The midpoint of PQ is (1, -0.5)

The coordinates of the point 2/3 of the way from p to q are (-0.2, 0.4)

What is the midpoint of a line segment?

the midpoint is the middle point of a line segment. It is equidistant from both endpoints.

The midpoint of PQ

To calculate this, we use the midpoint formula;

(x,y) = {(x1 + x2)/2 , (y1 + y2)/2}

From the question; (x1,y1) = (-5,4) and (x2,y2) = (7,-5)

So (x,y) = (-5+7)/2 , (4-5)/2 = 2/2, -1/2 = (1,-0.5)

The coordinates of the midpoint of PQ are (1,-0.5)

What is the internal division of the line segment?

we will use here the internal division formula of the section formula;

Mathematically the coordinates can be calculated using the formula;

(x,y) = (mx2 + nx1)/m+ n , (my2 + ny1)/m + n

in this case, m = 2 and n = 3

(x1,y1) = (-5,4)

(x2,y2) = (7,-5)

So substituting these values, we have;

(x,y) = (2(7)+ 3(-5))/(2+3) , 2(-5) + 3(4)/(2+3)

(x,y) = (14 -15)/5 , (-10 + 12)/5

= (-1/5, 2/5) = (-0.2, 0.4)

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[tex]\huge \mathbb{ \underline{EXPLANATION:}}[/tex]

▪ [tex] \bold{\: x + y + z = 20}[/tex]

[tex]\\[/tex]

◆ As we have a [tex]\small\bold{sum \: of \: three \: integers}[/tex] equal to 20 and less than 10, we know the integers have to be between 2 and 9 (1 and 0 don't apply because the sum wouldn't be equal to 20 between three integers.

[tex]\large\tt{Note:}[/tex]

The first value would be X value, second Y value and third Z value.

[tex]\huge \mathbb{ \underline{ANSWER:}}[/tex]

[tex] \large\boxed{ \sf 36 \: solution}[/tex]

Answer:

100

Step-by-step explanation:

to turn whole numbers to a fraction it is whatever numbers out of 100

Answer:

99

Step-by-step explanation:

The value of the function g(-3) from the given piecewise function is 1

A piecewise-defined function is a function defined by multiple sub-functions, where each sub-function applies to a different interval in the domain.

From the given piecewise function, we are to find the value of the function when x is -3 that is g(-3)

In order to determine the equivalent function, we need to determine the function where x = -3

The equivalent function is g(x) = x+ 4

Substitute x = -3 into the resulting function

g(x) = x + 4

g(-3) = -3 + 4

g(-3) = 1

Hence the value of the function g(-3) from the given piecewise function is 1

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The sample at option B, {0, 2} is not a part of the sample space of a spinner when spun two times.

The set consists of all the possible outcomes of an event called sample points, which is said to be a sample space.

It is given that,

a spinner has 5 sections of equal area and each section is numbered from 1 to 5.

If the spinner is spun two times, then the possible outcomes are 25. They are:

{(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5)}

So, from the given options, the sample {0, 2} is not possible since there is no such a section on the spinner named 0.

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The graph of the linear equation can be seen in the image below.

Here we have a linear equation:

y = -x

To graph it, we just need to find two points and the line, and then connect the points with a line.

Evaluating in x = 0, we get:

y = -0 = 0

Then we have the point (0, 0).

Evaluating in x = 1 we get:

y = -1

So we have the point (1, -1)

Now we just need to graph these two points and connect them with a line, the graph can be seen below.

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Step-by-step explanation:

sin∅=-3/4 in 4 quadrant which sine is negative there

using soh cah toa

sin=opp/hyp

where our opp=-3 and our hyp=4

using pythagoras theorem

hyp²=opp²+adj²

(4)²=(-3)²+adj²

16=9+adj²

16-9=adj²

adj²=7

adj=√7

from soh cah toa

cos∅=adj/hyp

cos∅=√7/4