The five-number summary of a data set is: 0, 4, 6, 14, 17

An observation is considered an outlier if it is below:

An observation is considered an outlier if it is above:

Answers

Answer 1

Answer:

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

Step-by-step explanation:

0, 4, 6, 14, 17

inner quartile range of 0 - 17 is 1/2 of 17 subtracted from the higher number = 17 - 1/2 of 8.5 =  8.5 - 4.25 = 4.25 - 4.25 x 3

= 4.25 to 12.75 for inner quartile

inner quartile range is 12.75-4.25 = 8.5

We then 1.5 x 8.5 to show the outlier

= 12.75 meaning there is no outlier if is below.

Lower quartile fences  = 4.25 - 1.5 = 2.75

or -1.5 x 8.5 (the range) =   -12.75

Upper quartile fence = 12.75 + 1.5 = 14.25 x 8.5 =   121.125  this would be an outlier if it is 12.75 higher than 121.125 or 12.75 lower than 5.50.

Outlier therefore could only be values below  - 12.75

or could only be values above + 121.125

An observation is considered an outlier if it exceeds a distance of 1.5 times the interquartile range (IQR) below the lower quartile or above the upper quartile. The values of the lower quartile - 1.5 x IQR and upper quartile + 1.5 x IQR are known as the inner fences.

An observation is an outlier if it falls more than above the upper quartile or more than below the lower quartile. The minimum value is so there are no outliers in the low end of the distribution. The maximum value is so there are no outliers in the high end of the distribution.


Related Questions

In the word PARADISE,how many pairs are there which have as many letters between them in the word as in the alphabet?​

Answers

Answer:

three

P A R

A R A D

A D I S E 

P Q R

A B C D

A B C D E

There are three such pairs of letters. 

Find the derivative of 4x^3-7x+8 ÷ x​

Answers

Step-by-step explanation:

If a fraction [tex]f(x)[/tex] is defined as

[tex]f(x) = \dfrac{g(x)}{h(x)}[/tex]

then the derivative [tex]f'(x)[/tex] is given by

[tex]f'(x) = \dfrac{g'(x)h(x) - g(x)h'(x)}{h^2(x)}[/tex]

So the derivative can be calculated as follows:

[tex]f'(x) = \dfrac{d}{dx}\left(\dfrac{4x^3 - 7x + 8}{x} \right)[/tex]

[tex]=\dfrac{(12x^2 - 7)x - (4x^3 - 7x + 8)}{x^2}[/tex]

[tex]= \dfrac{12x^3 - 7x - 4x^3 + 7x - 8}{x^2}[/tex]

[tex]= \dfrac{8x^3 - 8}{x^2}[/tex]

The proportion of brown M&M's in a milk chocolate packet is approximately 14% (Madison, 2013). Suppose a package of M&M's typically contains 52 M&M's

Answers

Answer:

7 brown M&Ms.

Step-by-step explanation:

This question is not complete, but I will assume that the final question is how many brown M&Ms will be in this package.

0.14 × 52 is our equation.

The answer is 7.28. We cannot have .28 of a brown M&M in a package (unless you count the broken ones) so there will be, on average, 7 brown M&Ms in a package.

(again, the question is incomplete, so this may not be the answer)

If X is a normal random variable with mean 6 and standard deviation 2.0, then find the value x such that P(X > x) is equal to .7054. Group of answer choices5.28

5.46

4.92

7.28

Answers

Answer:

Step-by-step explanation:

If X is a normal random variable with a mean of 6 and a standard deviation of 3.0, then find the value x such that P(Z>x)is equal to .7054.

-----

Find the z-value with a right tail of 0.7054

z = invNorm(1-0.7054) = -0.5400

x = zs+u

x = -5400*3+6 = 4.38

(ar^b) ^4 = 16r^20 where a and b are positive integers work our a and b​

Answers

Answer:

a = 2

b = 5

Step-by-step explanation:

Given :

(ar^b)^4 = 16r^20 ; a and b are positive integers :

Opening the bracket :

a^4r^4b = 16r^20

a^4 = 16 - - - - - (1)

r^4b = r^20 - - - (2)

a^4 = 16

Take the 4th root of both sides :

(a^4)^(1/4) = 16^1/4

a = 2

From (2)

r^4b = r^20

4b = 20

Divide both sides by 4

4b/4 = 20/4

b = 5

Hence ;

a = 2

b = 5

According to a Gallup poll, 60% of American adults prefer saving over spending. In a random sample of 10 American adults, what is the probability that more than 3 adults in the sample prefer saving over spending

Answers

Answer:

0.9452 = 94.52% probability that more than 3 adults in the sample prefer saving over spending

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they prefer saving over spending, or they do not. The answers for each adult are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

According to a Gallup poll, 60% of American adults prefer saving over spending.

This means that [tex]p = 0.6[/tex]

Sample of 10 American adults

This means that [tex]n = 10[/tex]

What is the probability that more than 3 adults in the sample prefer saving over spending?

This is:

[tex]P(X > 3) = 1 - P(X \leq 3)[/tex]

In which

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{10,0}.(0.6)^{0}.(0.4)^{10} = 0.0001[/tex]

[tex]P(X = 1) = C_{10,1}.(0.6)^{1}.(0.4)^{9} = 0.0016[/tex]

[tex]P(X = 2) = C_{10,2}.(0.6)^{2}.(0.4)^{8} = 0.0106[/tex]

[tex]P(X = 3) = C_{10,3}.(0.6)^{3}.(0.4)^{7} = 0.0425[/tex]

Then

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0001 + 0.0016 + 0.0106 + 0.0425 = 0.0548[/tex]

[tex]P(X > 3) = 1 - P(X \leq 3) = 1 - 0.0548 = 0.9452[/tex]

0.9452 = 94.52% probability that more than 3 adults in the sample prefer saving over spending

જ્યારે જહાંગીરની ઉંમર 18 વર્ષ થશે ત્યારે અકબરની ઉંમર 50 વર્ષ થર્શ.
જ્યારે અકબરની ઉંમર જહાંગીરની ઉંમર કરતા 5 ઘણી હશે ત્યારે
અકબરની ઉમર કેટલી હશે?
A) 36
B) 40
C) 44
D) 48

Answers

Answer:

C: 44

Step-by-step explanation:

• A certain test consists of multiple-choice questions
and essay questions in the ratio of 5:2. If the test
contains 6 essay questions, what is the total number
of questions on the test?

Answers

Answer: 21

Step-by-step explanation:

My teacher just did it

g Use properties of logarithms to condense the logarithmic expression. Write the expression as a single logarithm whose coefficient is 1. Evaluate logarithmic expressions if possible.

Answers

Answer:

[tex]4\log_bx - \log_by = \log(\frac{x^4}{y})[/tex]

Step-by-step explanation:

Given

[tex]4\log_bx - \log_by[/tex]

Required

Express as a single expression

Using power rule of logarithm, we have:

[tex]n\log m = \log m^n[/tex]

So, we have:

[tex]4\log_bx - \log_by = \log_bx^4 - \log_by[/tex]

Apply quotient rule of logarithm

[tex]4\log_bx - \log_by = \log(\frac{x^4}{y})[/tex]

I only need the odd numbers answered

Answers

Answer:

1.a+4=11

a=7

2.6=g+8

g=2

3.

?

4.k+8=3

k=-5

5.j+0=9

j=9

6.12+y=15

y=3

7.h-4=0

h=4

8.m-7=1

m=8

9.w+5=4

w=-2

10.b-28=33

b=61

11.45+f=48

f=3

12.n+7.1=8.6

n=1.5

Hope This Helps!!!

We are throwing darts on a disk-shaped board of radius 5. We assume that the proposition of the dart is a uniformly chosen point in the disk. The board has a disk-shaped bullseye with radius 1. Suppose that we throw a dart 2000 times at the board. Estimate the probability that we hit the bullseye at least 100 times.

Answers

Answer:

the probability that we hit the bullseye at least 100 times is 0.0113

Step-by-step explanation:

Given the data in the question;

Binomial distribution

We find the probability of hitting the dart on the disk

⇒ Area of small disk / Area of bigger disk

⇒ πR₁² / πR₂²

given that; disk-shaped board of radius R² = 5, disk-shaped bullseye with radius R₁ = 1

so we substitute

⇒ π(1)² / π(5)² = π/π25 = 1/25 = 0.04

Since we have to hit the disk 2000 times, we represent the number of times the smaller disk ( BULLSEYE ) will be hit by X.

so

X ~ Bin( 2000, 0.04 )

n = 2000

p = 0.04

np = 2000 × 0.04 = 80

Using central limit theorem;

X ~ N( np, np( 1 - p ) )

we substitute

X ~ N( 80, 80( 1 - 0.04 ) )

X ~ N( 80, 80( 0.96 ) )

X ~ N( 80, 76.8 )

So, the probability that we hit the bullseye at least 100 times, P( X ≥ 100 ) will be;

we covert to standard normal variable

⇒ P( X ≥  [tex]\frac{100-80}{\sqrt{76.8} }[/tex] )

⇒ P( X ≥ 2.28217 )

From standard normal distribution table

P( X ≥ 2.28217 ) = 0.0113

Therefore, the probability that we hit the bullseye at least 100 times is 0.0113

Okay, let's calculate the year end adjustment for overhead. Based on the data below, determine the amount of the year end adjustment to cost of goods sold due to over or under allocated manufacturing overhead during the year

Answers

Answer:

the adjustment made to the cost of goods sold is -$2,014

Step-by-step explanation:

The computation of the adjustment made to the cost of goods sold is given below:

Total actual overhead expenses $110,822

Less: Total overheads allocated -$112,836

Adjustment made to the cost of goods sold -$2,014

Hence, the adjustment made to the cost of goods sold is -$2,014

The same should be considered

number of bald eagles in a country a discrete random​ variable, a continuous random​ variable, or not a random​ variable?

Answers

Answer:

Discrete random variable.

Step-by-step explanation:

Discrete variable:

Countable numbers(0,1,2,3,...)

Continuous variable:

Can assume decimal values, such as 0.5, 2.5,...

Number of bald eagles:

Number of bald eagles is a countable value, either there a 0, 100, 1000,... so it is a discrete random variable.

Answer:

Discrete random variable.

Step-by-step explanation:

For what values of the variable, do the following fractions exist: y^2-1/y+y/y-3

For what values of the variable, do the following fractions exist: b+4/b^2+7

For what values of the variable, do the following fractions exist: a/a(a-1)-1

PLEASE HELP NEED ANSWER ASAPPPP!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWERRRR!!!

Answers

Answer:

Remember that the division by zero is not defined, this is the criteria that we will use in this case.

1) [tex]\frac{y^2 - 1}{y} + \frac{y}{y - 3}[/tex]

So the fractions are defined such that the denominator is never zero.

For the first fraction, the denominator is zero when y = 0

and for the second fraction, the denominator is zero when y = 3

Then the fractions exist for all real values except for y = 0 or y = 3

we can write this as:

R / {0} U { 3}

(the set of all real numbers except the elements 0 and 3)

2) [tex]\frac{b + 4}{b^2 + 7}[/tex]

Let's see the values of b such that the denominator is zero:

b^2 + 7 = 0

b^2 = -7

b = √-7

This is a complex value, assuming that b can only be a real number, there is no value of b such that the denominator is zero, then the fraction is defined for every real number.

The allowed values are R, the set of all real numbers.

3) [tex]\frac{a}{a*(a - 1) - 1}[/tex]

Again, we need to find the value of a such that the denominator is zero.

a*(a - 1) - 1 = a^2 - a - 1

So we need to solve:

a^2 - a - 1 = 0

We can use the Bhaskara's formula, the two values of a are given by:

[tex]a = \frac{-(-1) \pm \sqrt{(-1)^2 + 4*1*(-1)} }{2*1} = \frac{1 \pm \sqrt{5} }{2}[/tex]

Then the two values of a that are not allowed are:

a = (1 + √5)/2

a = (1 - √5)/2

Then the allowed values of a are:

R / {(1 + √5)/2} U {(1 - √5)/2}

We know that the remainder Rn will satisfy |Rn| ⤠bn + 1 = 1 (n + 1)9n + 1. We must make n large enough so that this is less than 0.0001. Rounding to five decimal places, we have b2 = _________ , b3 =_________and b4 =__________

Answers

This question is incomplete, the complete question is;

We know that the remainder R[tex]_n[/tex] will satisfy | R[tex]_n[/tex] | ≤ b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex].

We must make n large enough so that this is less than 0.0001.

Rounding to five decimal places,

we have b₂ = _________ , b₃ =_________and b₄ =__________

Answer:

b₂ = 0.00617, b = 0.00046 and  b₄ = 0.00004

Step-by-step explanation:

Given the data in the question;

| R[tex]_n[/tex] | ≤ b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex]

Now,

b[tex]_{ n + 1[/tex] = 1 / ( n + 1 )9[tex]^{ n + 1[/tex]

b₂ = b[tex]_{ 1 + 1[/tex] = 1 / ( 1 + 1 )9[tex]^{ 1 + 1[/tex] = 1 / (2)9² = 1 / 162 = 0.00617   { 5 decimal places }

b₃ = b[tex]_{ 2 + 1[/tex] = 1 / ( 2 + 1 )9[tex]^{ 2 + 1[/tex] = 1 / (3)9³ = 1 / 2187 = 0.00046 { 5 decimal places }

b₄ = b[tex]_{ 3 + 1[/tex] = 1 / ( 3 + 1 )9[tex]^{ 3 + 1[/tex] = 1 / (4)9⁴ = 1 / 19683 = 0.00004 { 5 decimal places }

Therefore, b₂ = 0.00062, b = 0.00046 and  b₄ = 0.00004

1) What is the opposite of adding 5?
2) What is the opposite of subtracting 20?
3) What is the opposite of multiplying by 1/2?
4) What is the opposite of dividing by 10?

Answers

Answer:

1) subtracting 5

2) adding 20

3) dividing by 2 (multiplying by 1/2)

4) multiplying by 1/10 (dividing by 10)

Step-by-step explanation:

There are four main operations in math: adding, subtracting, multiplying, and dividing. Each of the operations has an opposite. Adding and subtracting are opposites and multiplying and dividing are opposites. This means that subtracting can undo adding and vice versa; additionally, dividing can undo multiplying or vice versa. So, to find the opposite of something switch the operation to the opposite and keep the number. However, it is important to note that with multiplying and dividing you can also find the opposite by keeping the operation while changing the number to the reciprocal.


Andrew worked over 40 hours this week. He earns $12 an hour and gets paid time and a half for overtime. If x represents total hours worked, which equation will result in the
amount of money earned for the week?

Answers

Answer:

y = 480 + 1.5 (x-40)

Step-by-step explanation:

sometimes its better to answer the question and make the formula from that

40 x 12 = 480

1.5 for overtime

x

y = 480 + 1.5 (x-40)

Addison drove 960 miles in 16 hours what was her speed in miles per hour

Answers

The correct answer is 60 miles per hour

You would divide 960 by 16 and will get 60 as your answer

Answer:

60 miles/hour

Step-by-step explanation:

960÷16

=60 hours

HELPPP PLEASEEE! I tried everything from adding to dividing, subtracting, multiplying but still no correct answer. Can someone help me out here please? I am not sure where to start either now. Thank you for your time.

Answers

That is the solution to your question

William has been contracted to paint a school classroom. The classroom is 20 m long, 15 m wide and 5 m high. There are four windows (2m by 3m) and a door (2m by 1m). Determine the cost of painting the ceiling at N$ 6.50/m²​

Answers

Answer:

Step-by-step explanation:

l -> length

b -> width

h -> height

Find the area of four walls and ceiling. then subtract the area of four windows and a door form that area.

Area of four walls + ceiling = 2( lh + bh) +lb

 = 2*(20*5 + 15*5) + 20*15

= 2( 100 + 75) + 300

= 2* 175 + 300

= 350 +300

= 650 sq m

Area of window = 2 *3 = 6 sq.m

Area of four windows = 4*6 = 24 sq.m

Area of door = 2 * 1 =  2 sq.m

Area of four walls excluding 4 windows and door = 650 - 24 - 2 = 624 sq.m

Cost of painting = 624 * 6.50

                          = $ 4056

Answer:  1950 dollars to paint the ceiling only (ignoring the walls)

The cost to paint the walls only is 2106 dollars.

The cost to paint the walls and ceiling is 4056 dollars.

==================================================

Explanation:

It seems a bit strange how your teacher mentions the windows and doors, but then asks about the ceiling only. Perhaps this is a red herring, but I'm not sure.

Anyway, to directly answer the question, we'll need to find the area of the ceiling first. The ceiling is a rectangle of dimensions 20 m by 15 m, so its area is 20*15 = 300 square meters.

Since paint costs 6.50 dollars per square meter, the total cost for the ceiling alone is 6.50*300 = 1950 dollars

If your teacher only cares about the ceiling, then you can stop here (and ignore the next section below).

---------------------------

If you wanted to find the cost to paint the walls, then we need to find the area of the walls.

For now, ignore the windows and door. Two opposite walls have area of 20*5 = 100 m^2 each. That accounts for 2*100 = 200 m^2 of wall area so far.

The other pair of opposite walls have area 15*5 = 75 m^2 each. That's another 2*75 = 150 m^2 of wall area.

In all, the total wall area without considering the windows or door is 200+150 = 350 m^2.

Now we consider the windows. Each window is 2 m by 3 m, yielding an area of 2*3 = 6 m^2. Four such windows have a total area of 4*6 = 24 m^2.

The door is 2 m by 1 m, so its area is 2*1 = 2 m^2

We'll subtract the wall area and the combined window+door areas to get

wallArea - windowArea - doorArea = 350-24-2 = 324

So after accounting for the windows and door, the amount of wall to paint is 324 m^2, which leads to a cost of 6.50*324 = 2106 dollars.

Therefore, painting the walls and ceiling gets us a total cost of 1950+2106 = 4056 dollars

This section is entirely optional if your teacher only cares about the ceiling.

Find m angle QSRIf m angle TSQ=15x , m angle TSR=173^ , and m angle QSR=10x-2

Answers

[tex]{\color{red}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:꧁"Answer"꧂\:\:\: }}}}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find \:a X } } } }[/tex]

[tex]\small\color{black}{{\underline{\bold{173°=15z+10x-2 } } } } \\ = 173 = 25x - 2 \\ = - 25x = - 2 - 173 \\ = - 25x - 175 \\ = \small\color{blue}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: x=7\:\:\:\: }}}}[/tex]

[tex]\small\color{blak}{{\underline{\bold{ Find\:a\:m<QSR } } } }[/tex]

[tex]\small\color{blak}{{\underline{\bold{ 10(7)-2 } } } }\\=70-2\\=\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: m<QSR=68°\:\:\:\: }}}}[/tex]

[tex]\Large\color{red}{{\underline{\mathfrak {{꧁"Carry\:on\: learning"꧂ }}}}}[/tex]

The measure of angle QSR is 68 degrees.

What is substitution?

Substitution means putting numbers in place of letters to calculate the value of an expression.

According to the given question.

m ∠TSQ = 15x

m ∠TSR = 173 degrees

m ∠QSR = 10x -2

Since,

m ∠TSR = m ∠TSQ + ∠QSR

Substitute the value of m ∠TSR, m ∠TSQ and m ∠QSR in the above expression.

⇒ [tex]173 = 15x + 10x - 2[/tex]

⇒ [tex]173 = 25x - 2[/tex]

⇒ [tex]175 = 25x[/tex]

⇒ [tex]x = \frac{175}{25}[/tex]

⇒ [tex]x = 7[/tex]

Again, for finding the value of angle QSR substitute the value of x in 10x - 2.

Therefore,

m ∠QSR = 10(7) - 2

⇒ m ∠QSR = 70 - 2

⇒ m ∠QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees.

Fid out more information about substitution here:

brainly.com/question/27810586

#SPJ3

Find the perimeter of the
polygon if ZB = D.
3 om
B
4 cm
D
5 cm
C
P = [?] cm

Answers

Answer:

16 cm

Step-by-step explanation:

4 + 4 + 3 + 5 = 16

The = sign means that B (which is 4 cm) is equal to D (which had no number)

And because it says that B = D (with the squiggly line (or a tilde)) And the L's (which means that the letters represent an angle) All you have to do is add the numbers together, and you get 16.

Sorry if I explained it badly, you at least got the answer.

(And also, if I'm wrong, please tell me.)

Answer:

P = 32 cm

Step-by-step explanation:

Im just putting the right answer up so you don't accidentally put in the wrong one.

5. A cylindrical pipe is placed in a rectangular trench that is 5m x 4m
and 2.5m deep, is placed across the shorter side of the trench.
5.1 How much volume of cement will be needed to cover this hollow
pipe?

Answers

Answer:

The volume (density) of cement that will be needed to cover this hollow pipe is:

= 50,000 kg/m³

Step-by-step explanation:

Length of a cylindrical pipe = 5m

Width of the cylindrical pipe = 4m

Depth of the cylindrical pipe = 2.5m

The cubic meters of the cylindrical pipe = 5 * 4 * 2.5 = 50m³

1 cubic meter is equal to 1,000 kilogram

Therefore, the volume (density) of cement that will be needed to cover this hollow pipe is:

= 50 * 1,000

= 50,000 kg/m³

If angles A and B are consecutive interior angles, what is the measure of
angle B if angle A measures 75°?
A. 105
B. 75
C. 180°
O
D. 90°
SUBMIT

Answers

Answer:

A

Step-by-step explanation:

180 - 75 = 105

The answer is A
Consecutive interior angles means that they supplementary to each other. Which means they are parallel to each other and also add up to 180

Of five letters (A, B, C, D, and E), two letters are to be selected at random. How many possible are possible

Answers

Answer:

10

Step-by-step explanation:

5C2 =5!

       2! (3)!

=1 x 2 x 3 x 4 x 5

(1 x 2) (1 x 2 x 3)

=4 x 5

   2

=20

  2

5C2 = 10

a mountain railway AB is of length 864m and rises at an angle of 120° to the horizontal.A train is 856m above sea level when it is at A calculate the height above sea level of the train when it reaches B​

Answers

9514 1404 393

Answer:

  1604 m

Step-by-step explanation:

The relevant trig relation is ...

  Sin = Opposite/Hypotenuse

Here, the "opposite" is the elevation of point B above point A, and the "hypotenuse" is the length of the railway. Then the total height of point B is ...

  B = 856 + 864·sin(120°)

  B = 856 +864(√3)/2 = 856 +432√3 ≈ 1604.246

The height of the train at point B is about 1604 m above sea level.

Ed decided to build a storage box. At first, he was planning to build a cubical box with edges of length n
inches. To increase the amount of storage, he decided to make the box 1 inch taller and 2 inches longer,
while keeping its depth at n inches. The volume of the box Ed built has a volume how many cubic inches
greater than the box he originally planned to build?
O 3n2 + 2n
312 + 3n+3
O 6n2 + 3n
O 6n2 + 3n+3

Answers

Given:

Edge of a cubic box = n inches.

He decided to make the box 1 inch taller and 2 inches longer, while keeping its depth at n inches.

To find:

How many cubic inches greater than the box he originally planned to build?

Solution:

Edge of a cubic box is n inches, so the volume of the original cube is:

[tex]V_1=(edge)^3[/tex]

[tex]V_1=n^3[/tex]

According to the given information,

New width of the box = n+1

New length of the box = n+2

New height of the box = n

So, the volume of the new box is:

[tex]V_2=Length\times width\times h[/tex]

[tex]V_2=(n+2)(n+1)n[/tex]

[tex]V_2=(n^2+2n+n+2)n[/tex]

[tex]V_2=(n^2+3n+2)n[/tex]

[tex]V_2=n^3+3n^2+2n[/tex]

Now, the difference between new volume and original volume is:

[tex]V_2-V_1=n^3+3n^2+2n-n^3[/tex]

[tex]V_2-V_1=3n^2+2n[/tex]

So, the volume of new box is 3n^2+2n cubic inches more than the original box.

Therefore, the correct option is A.

A roll of carpet that contains 250 yd of carpet will cover how many rooms if each room requires 7 3/4 yards of carpet?

Answers

Answer: 32 room

Step-by-step explanation:

[tex]7\frac{3}{4} =\frac{4(7)+3}{4} =\frac{28+3}{4} =\frac{31}{4}=7.75[/tex]

If 1 room = 7.75 yd of carpet ⇒ x rooms = 250 yd of carpet

Use proportions & cross-multiply to solve:

[tex]\frac{1}{7.75} =\frac{x}{250}\\7.75x=250\\x=\frac{250}{7.75} =32.258[/tex]

So 250 yd of carpet can cover about 32 rooms.

Circle O has radius 5 m with an arc AB intercepted by a central angle of π5π5 radians. What is the length of arc AB expressed in terms of ππ?

Answers

Answer:

I am assuming that you meant to write π/5.

Step-by-step explanation:

Radius r = 5 meters

Circumference = 2πr = 10π

Central angle θ = π/5 radian

Arc length = 10π × θ/(2π radians)

= 5θ

= π meters

Roger has found a home to be purchase for $120,372 and has agreed to pay 28% down. Find the amount of Roger's down payment. Find the amount of money that Roger would need to borrow through a mortgage in order to purchase the home.

If Roger found a 30 year mortgage with a 5.9% APR. Find Roger's monthly payment. Using the monthly payment how much did Roger pay over the life of the mortgage?

Round your answer to the nearest cent.

Answers

Answer:

He needs to borrow: 86667.84

His monthly payment would be: 514.06

He would pay a total of: 185061.6 over the life of the loan

Step-by-step explanation:

roger would need to borrow .72*120372= 86667.84

2.)

calculate the effective rate .059/12= .004916667

[tex]86667.84=x\frac{1-(1+.004916667)^{-30*12}}{.004916667}\\x=514.0585984[/tex]

which we round to 514.06

3.) he is going to pay a total of 514.06*30*12= 185061.6 over the life of the loan

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