The following orbital notation is for which element?

When force is applied to the objects, then the shape of some objects deforms. It modifies the relative locations of the crystal lattice's constituent particles.

Interatomic or intermolecular forces begin to operate as soon as that occurs, and they have a tendency to return the solid to its former configuration. Force is defined as a physical quantity that has the power to alter an object's condition and shape. A force imparted to an object causes it to alter shape. For instance, a piece of metal changes shape when hit with a hammer. A contact force that is applied to an object externally is referred to as an applied force. The object moves or deforms as a result of the applied force. In general, an object moves in the direction of a force. Assume a pulley is used to raise it off the ground. In that situation, the object is moving in the opposite direction from where the force is being applied.

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The pH values after the given volumes of acid have been added are: a) 12.18, b) 12.39, c) 11.78, d) 11.25, and e) 10.79.To solve the problem, we need to use the balanced chemical equation for the reaction between KOH and HClO4:

KOH + HClO4 -> KClO4 + H2O

At the start of the titration, before any HClO4 has been added, we have a solution of KOH with a concentration of 0.150 M. We can use this concentration to calculate the initial concentration of hydroxide ions in the solution:

[OH-] = 0.150 M

a) Before any HClO4 has been added, the volume of the solution is 20.0 mL. At this point, no HClO4 has reacted with the KOH, so the concentration of OH- ions is still 0.150 M.

To calculate the pH, we can use the formula for the dissociation constant of water:

Kw = [H+][OH-] = 1.0 x 10^-14

pH = -log[H+]

[H+] = Kw/[OH-] = 6.67 x 10^-13 M

pH = -log(6.67 x 10^-13) = 12.18

b) After 1.5 mL of HClO4 has been added, the volume of the solution is 21.5 mL. The moles of HClO4 added is:

0.125 mol/L x 0.0015 L = 1.875 x 10^-5 mol

The moles of KOH initially in the solution is:

0.150 mol/L x 0.020 L = 0.003 mol

Thus, the moles of KOH remaining after reaction with HClO4 is:

0.003 mol - 1.875 x 10^-5 mol = 0.00298125 mol

The total volume of the solution is 21.5 mL, so the new concentration of KOH is:

0.00298125 mol / 0.0215 L = 0.1387 M

Using this concentration, we can calculate the concentration of OH- ions:[OH-] = 0.1387 M

Using the same formula for Kw and pH as before, we find that:

[H+] = 4.06 x 10^-13 M

pH = -log(4.06 x 10^-13) = 12.39

c) Repeating the above process for a volume of 24.0 mL gives:

[H+] = 1.64 x 10^-12 M

pH = -log(1.64 x 10^-12) = 11.78

d) For a volume of 26.5 mL:

[H+] = 5.67 x 10^-12 M

pH = -log(5.67 x 10^-12) = 11.25

e) For a volume of 29.0 mL:

[H+] = 1.63 x 10^-11 M

pH = -log(1.63 x 10^-11) = 10.79

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According to Beer-Lambert law, the absorbance of dye such as crystal violet is proportional to its molar concentration.

Beer-Lambert law says that, "there is a linear relationship between the absorbance of the solution and the concentration, which enables the concentration of a solution to be calculated by measuring its absorbance.

Beer Lambert law is basically used in chemistry to measure the concentration of chemical solutions, analyze oxidation, and measure polymer degradation. This law also explains the attenuation of radiation through the Earth's atmosphere.

The Beer-Lambert law is mathematically expressed as:

A = εLc

where,

A is the denotation for absorbance, ε is the molar extinction coefficient, l is the length of the path light which must travel in the solution in centimeters, and c is the concentration of a given solution.

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At pH 9.0, the solution is basic and the ionizable groups in the peptide will be ionized. The correct answer is option b: n-terminus: amine; lysine r group: ammonium; c-terminus: carboxylate; aspartic acid r group: carboxylate.

At pH 9.0, the ionizable groups in a peptide are likely to be ionized. The pKa values of the different ionizable groups in the peptide determine which form they will be in at a given pH. The amino group at the N-terminus of the peptide has a pKa value of about 9.0, which means that it will mostly exist in the ionized form as an amine (NH2) at pH 9.0. The lysine R group has a pKa value of approximately 10.8, which means that it will exist in the ionized form as ammonium (NH3+) at pH 9.0. The carboxyl group at the C-terminus of the peptide has a pKa value of around 2.2, which means that it will exist in the ionized form as a carboxylate (COO-) at pH 9.0. The aspartic acid R group has a pKa value of about 3.9, which means that it will also exist in the ionized form as a carboxylate (COO-) at pH 9.0. Therefore, at pH 9.0, the major forms of each ionizable group in a peptide are N-terminus - amine (NH2), Lysine R group - ammonium (NH3+), C-terminus - carboxylate (COO-), and Aspartic acid R group - carboxylate (COO-). Understanding the ionization of peptides at different pH values is important in many biochemical and biophysical studies that involve peptides and proteins.

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A brief conclusion to the experiment summarizing the experimental conditions that gave rise to the greatest observed electrical conductivity:

Electrical conductivity is grounded on the inflow of electrons. Essence are good operators of electricity because they allow electrons to flow through the entire piece of material. therefore, electrons flow like a “ ocean of electrons ” through essence. In comparison, distilled water is a veritably poor captain of electricity since veritably little electricity flows through water. largely ionized substances are strong electrolytes. Strong acids and mariners are strong electrolytes because they fully ionize( disconnect or separate) in result. The ions carry the electric charge through the result therefore creating an electric current.

Slightly ionized substances are weak electrolytes. Weak acids and bases would be distributed as weak electrolytes because they don't fully disconnect in result.

Substances that don't conduct an electric current are called non-electrolytes. Non-electrolytes don't ionize; they don't contain portable ions. The LEDs of a conductivity cadence won't light because there are no ions to carry the electric current. The table below lists exemplifications of strong, weak and non-electrolytes.

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124 L is the correct answer

Thus, the volume of the helium is 124 L when the balloon rises to an altitude where the pressure is only 25 kPa.

What is temperature ?

Temperature is a measure of the thermal energy of a substance or system. It reflects the degree of hotness or coldness of a material, and is a crucial parameter in many physical and biological systems. It is usually measured in units of kelvins, Celsius, or Fahrenheit. The Kelvin scale is an absolute temperature scale, where 0 K represents absolute zero, the temperature at which all matter has no thermal energy. The Celsius and Fahrenheit scales are relative temperature scales, with 0°C and 32°F defined as the freezing point of water and 100°C and 212°F defined as the boiling point of water.

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There are 1.5 moles of calcium in 0.5 mole Ca3(PO4)2.

First we need to first find the molar mass of Ca3(PO4)2:

Molar mass of Ca3(PO4)2 = (3 x molar mass of Ca) + (2 x molar mass of PO4)

= (3 x 40.08 g/mol) + (2 x (1 x 30.97 g/mol + 4 x 16.00 g/mol))

= 310.18 g/mol

Next, we can use the following mole ratio:

3 moles of Ca / 1 mole of Ca3(PO4)2

This means that for every 1 mole of Ca3(PO4)2, there are 3 moles of Ca.

Therefore, the number of moles of calcium in 0.5 mole Ca3(PO4)2 is:

0.5 mole Ca3(PO4)2 x (3 moles of Ca / 1 mole of Ca3(PO4)2) = 1.5 moles of Ca

Therefore, there are 1.5 moles of calcium in 0.5 mole Ca3(PO4)2.

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From the given information using the colligative property, the vapor pressure of seawater at 20°C is approximately 17.07 Torr.

To calculate the vapor pressure of seawater at 20°C, we can use the following equation:

ΔP = P°(solvent) - P(solvent)

where ΔP is the change in vapor pressure, P°(solvent) is the vapor pressure of the pure solvent (water), and P(solvent) is the vapor pressure of the solvent in the solution (seawater). We can solve for P(solvent) to get the vapor pressure of seawater.

The vapor pressure of pure water at 20°C is given as 17.54 Torr. We can assume that the seawater solution is dilute and therefore can use the following approximation:

ΔP ≈ -Km

where K is the cryoscopic constant (for water, K = 1.86 °C/m) and m is the molality of the solution.

Substituting the given values, we get:

ΔP = -Km = -1.86 °C/m × 1.10 m = -2.046 °C

To convert this temperature change to a vapor pressure change, we can use the Clausius-Clapeyron equation:

ln(P°(solvent)/P(solvent)) = ΔHvap/R × (1/T(solvent) - 1/T°)

where ΔHvap is the enthalpy of vaporization of the solvent, R is the gas constant, T(solvent) is the temperature of the solvent in kelvin (20 + 273 = 293 K), and T° is the normal boiling point of the solvent (100°C or 373 K for water).

We can solve for P(solvent) to get:

P(solvent) = P°(solvent) × exp(-ΔHvap/R × (1/T(solvent) - 1/T°))

The enthalpy of vaporization of water is approximately 40.7 kJ/mol, and R is 0.08206 L·atm/mol·K.

Substituting the values, we get:

P(solvent) = 17.54 Torr × exp(-40700 J/mol / (0.08206 L·atm/mol·K × 293 K) × (1/293 K - 1/373 K)) = 17.07 Torr

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An element in activity series can replace the more reactive elements  Because of this, the single replacement reaction occurs.

The activity series is defined as a list of elements in decreasing order of their reactivity. In a single replacement reaction, a given element is capable of replacing an element that is below it in the activity series. It can be used to predict if a reaction will occur. This reactions only occur when the element that is doing the replacing is more reactive than the element that is being replaced. It is useful to have a list of elements in order of their relative reactivities. The activity series defined as a list of elements in decreasing order of their reactivity. Since metals replace other metals while nonmetals replace other nonmetals and elements replace elements they each have a separate activity series.

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6.0 moles of magnesium (Mg) metal would be produced if 12 moles of potassium (K) reacted.

What is magnesium?

Magnesium is a chemical element with the symbol Mg and atomic number 12. It is a silvery-white, shiny, and highly reactive metal. Magnesium is the ninth most abundant element in the universe and the eighth most abundant element in the Earth's crust. Magnesium is an essential mineral and is particularly important for human metabolism, being involved in over 300 biochemical reactions. It is required for the proper functioning of muscles, nerves, and enzymes and helps to regulate blood sugar levels, blood pressure, and the body's calcium levels.

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Option A: It is the amount of energy stored in the intermolecular attractions that hold particles together in an ionic solid, and option C: it is the amount of enthalpy change that occurs when 1mol of ionic solid is converted into gaseous ions, describes lattice energy.

The enthalpy change required to convert one mole of an ionic solid into gaseous ionic components is known as lattice energy. The strength of the ionic bonds in an ionic compound is gauged by lattice energy. It holds the particles together in a molecule. Thus, option A and C describes lattice energy. It sheds light on a number of ionic solids' characteristics, such as their solubility, hardness, and volatility.

The lattice energy of an ionic solid cannot be measured directly, but only be detected with Born-Haber cycle. It is expressed in terms of kilo-joule per mole, KJ/mol.

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The pressure values for propane and butane after each addition of water were not always the same.

This is due to the fact that the vapor pressure of a liquid is directly related to its boiling point. Propane has a boiling point of -42.1°C, whereas butane has a boiling point of 0.5°C. This means that at a given temperature, propane will have a higher vapor pressure than butane, resulting in higher pressure values when the same amount of water is added to each gas. This can be expressed mathematically by the Clausius-Clapeyron equation, which states that the vapor pressure of a liquid is directly proportional to its temperature.

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After 3 half-lives, only 15.625 grams of the original 125-gram sample of U-235 would remain, and approximately 2.1114 billion years would have passed. It's worth noting that this calculation assumes that the decay of U-235 follows a constant exponential decay, which may not be entirely accurate due to variations in decay rates over time.

What is Half Life Reaction?

Half-life is a term commonly used in nuclear physics and chemistry to describe the time required for half of the atoms in a particular sample to decay. In a half-life reaction, the amount of a substance or reactant present in a reaction is reduced by half after a specific amount of time.

In a chemical reaction, the half-life refers to the amount of time it takes for half of the reactants to be converted into products. The half-life of a chemical reaction is dependent on a variety of factors, including temperature, pressure, concentration, and the specific chemical reaction taking place.

After one half-life, half of the original U-235 sample would remain, which would be 62.5 grams (125 g / 2). After two half-lives, only one-quarter (or 25%) of the original sample would remain, which would be 31.25 grams (62.5 g / 2). After three half-lives, only one-eighth (or 12.5%) of the original sample would remain, which would be 15.625 grams (31.25 g / 2).

To determine how much time has passed, we can use the formula:

t = n x t1/2

where t is the total time, n is the number of half-lives, and t1/2 is the half-life of the substance.

In this case, we have n = 3 and t1/2 = 703.8 million years. Therefore, the total time that has passed would be:

t = 3 x 703.8 million years

t = 2.1114 billion years

So, after 3 half-lives, only 15.625 grams of the original 125-gram sample of U-235 would remain, and approximately 2.1114 billion years would have passed. It's worth noting that this calculation assumes that the decay of U-235 follows a constant exponential decay, which may not be entirely accurate due to variations in decay rates over time.

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The chloride ion's ground state electron configuration is [Ne] 3s2 3p6.

An atom of chlorine that has lost one electron and now has a net charge of -1 is known as a chloride ion.

The chloride ion contains 16 electrons overall due to the loss of one electron from the chlorine atom, which has 17 protons in its nucleus.

The chloride ion's atomic structure resembles that of a chlorine atom, but one electron from the 3s orbital is missing.

The chloride ion now has an electron configuration of [Ne] 3s2 3p6, with the 3s orbital having two electrons and the 3p orbital having six.

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a sample of trifluoroacetic acid, c2hf3o2, contains 88.9 88.9 g of oxygen, the mass of the trifluoroacetic acid sample is: 316.484 grams

The mass in grams of one mole of a chemical is its molar mass. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a material. It provides you with the amount of grams per mole of a substance, to put it another way. The molar mass of a material is a bulk attribute rather than a molecular one. The fundamental units of matter are called atoms, and by joining atoms together, molecules are created. Chemists use the term "mole" because atoms, molecules, and other particles are all very tiny and require a large amount to even weigh them.

As we know,

1 mole of C₂HF₃O₂ contains 2 moles of oxygen

molar mass of C₂HF₃O₂ = 114.0 gm

atomic mass of 2 Oxygen = 32 gm

(114 / 32) = 3.56

grams of C₂HF₃O₂ = 88.9 x 3.56 = 316.484 grams

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As mechanism 2 matches the given rate law, the correct answer is: only mechanism 2 is consistent with the rate law.

To determine which mechanism is consistent with the experimentally determined rate law, we need to check if the predicted rate law for each mechanism matches the given rate law.

The given rate law is: rate = k [X][Y₂]

Mechanism 1:

The slow step is the formation of X radicals from X₂, which is a bimolecular reaction. The intermediate X formed in the first step then reacts with Y₂ to form XY₂, and this intermediate reacts with X to form the final product X₂Y₂. Since the rate-determining step involves only X₂, we can assume that the rate law is determined by the concentration of X₂ only, and the rate law for mechanism 1 is therefore: rate = k[X₂]. This does not match the given rate law, so mechanism 1 is not consistent with the rate law.

Mechanism 2:

The slow step is again the formation of X radicals from X₂. The intermediate XY formed in the second step then reacts with Y to form X₂Y, and this intermediate reacts with Y to form the final product X₂Y₂. The rate-determining step involves X₂, XY, and Y, so we can write the rate law for mechanism 2 as:

rate = k [X₂][XY][Y].

Simplifying this rate law using the equilibrium constant for the fast equilibrium XY₂ ⇌ XY + Y₂, we can rewrite it as:

rate = k [X₂][Y₂]/K

This matches the given rate law, so mechanism 2 is consistent with the rate law.

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The concentration of sulfuric acid remaining after neutralization is 0 M.

First, we need to determine the number of moles of [tex]H_{2} SO_{4}[/tex] and KOH that are present in the solution.

The number of moles of [tex]H_{2} SO_{4}[/tex] in 0.450 L of 0.450 M solution can be calculated as follows:

moles [tex]H_{2} SO_{4}[/tex] = volume of solution (L) x molarity

moles [tex]H_{2} SO_{4}[/tex] = 0.450 L x 0.450 mol/L

moles [tex]H_{2} SO_{4}[/tex] = 0.2025 mol

Similarly, the number of moles of KOH in 0.400 L of 0.270 M solution can be calculated as follows:

moles KOH = volume of solution (L) x molarity

moles KOH = 0.400 L x 0.270 mol/L

moles KOH = 0.108 mol

The balanced chemical equation for the reaction between [tex]H_{2} SO_{4}[/tex] and KOH is:

[tex]H_{2} SO_{4}[/tex] + 2KOH → [tex]K_{2} SO_{4}[/tex] + [tex]2H_{2} O[/tex]

From the equation, we can see that 1 mole of [tex]H_{2} SO_{4}[/tex] reacts with 2 moles of KOH. Since the number of moles of KOH (0.108 mol) is less than half the number of moles of [tex]H_{2} SO_{4}[/tex] (0.2025 mol), KOH is the limiting reactant.

The reaction between [tex]H_{2} SO_{4}[/tex] and KOH consumes all of the KOH and produces [tex]K_{2} SO_{4}[/tex] and [tex]H_{2} O[/tex].

The number of moles of [tex]H_{2} SO_{4}[/tex] that reacts with KOH is:

moles [tex]H_{2} SO_{4}[/tex] consumed = 2 x moles KOH

moles [tex]H_{2} SO_{4}[/tex] consumed = 2 x 0.108 mol

moles [tex]H_{2} SO_{4}[/tex] consumed = 0.216 mol

The number of moles of [tex]H_{2} SO_{4}[/tex]that remain after neutralization is:

moles [tex]H_{2} SO_{4}[/tex] remaining = initial moles [tex]H_{2} SO_{4}[/tex] - moles [tex]H_{2} SO_{4}[/tex] consumed

moles [tex]H_{2} SO_{4}[/tex] remaining = 0.2025 mol - 0.216 mol

moles [tex]H_{2} SO_{4}[/tex] remaining = -0.0135 mol

Since we cannot have a negative number of moles, this means that all of them [tex]H_{2} SO_{4}[/tex] has been consumed and there is an excess of KOH remaining.

Therefore, the concentration of sulfuric acid remaining after neutralization is 0 M.

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The favored conformations of cyclopropane and cyclobutene have approximately the same bond angle of about 60 degrees.

Cyclopropane and cyclobutane sacrifice bond angle to relieve torsional strain.

Both torsional strain and steric strain are examples of steric interactions.

The cycloalkane with the chemical formula (CH2)3 is known as cyclopropane. It is made up of three methylene groups (CH2) that are joined together to create a ring.

It is an extremely strained molecule due to the high angle strain resulting from the 60-degree bond angles in the ring. It is used as a starting material in organic synthesis and as an anesthetic in medicine.

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Chemical formula of one compound formed by the combination of K+ ions with one of these ions as water completely evaporates from the seawater sample is KCl( Poassium Chloride).

Potassium chloride is an ionic compound that contains the ions K+ and Cl-. The K+ ions and Cl- ions create an ionic connection when the water evaporates from the saltwater sample. Because the K+ and Cl- ions are attracted to each other, the bond forms when the two ions create a symmetrical configuration.

The process of ionic bonding is a key aspect of seawater chemistry. Several dissolved ions are found in seawater, including K+, Na+, Ca2+, and Mg2+. The dissolved ions get concentrated when the water evaporates and interact with other ions to create compounds. In the case of KCl, the K+ ions will create an ionic connection with the Cl- ions, which is a strong bond that binds the two ions together.

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Once a reactant's correct formula has been placed in an equation, the A. The equation is balanced by adjusting the subscripts.

The correct formula for a reactant in a chemical equation must be written first, and then the subscripts are adjusted to balance the equation. Balancing the equation means making sure that the same number of each type of atom appears on both the reactant and product sides of the equation. This can be done by adding coefficients in front of the formulas as necessary. Once the equation is balanced, the formula should not be changed. The same formula must appear on both the reactant and product sides of the equation, but the coefficients may be different. The symbols in the formula must not appear on the product side of the equation unless the formula has been balanced first.

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The option that exemplifies a molecular formula is [tex]P_4O_{10[/tex].

A molecular formula is a chemical formula that represents the number and type of atoms present in a molecule. A molecular formula specifies the exact number of atoms of each element in a molecule, which can help to identify the type of molecule and its composition.

Molecular formulas are unique from empirical formulas. Empirical formulas are the simplest formulas that show the atoms present in a compound in their simplest whole-number ratios.

Thus, C₂H₁₁, C₂H₁₂O, and [tex]P_2O_5[/tex] are all empirical formulas while [tex]P_4O_{10[/tex] is a molecular formula.

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Explanation: its moles

Answer:

A

Explanation:

A. Narrower radiation beams are most likely to decrease the side effects of radiation treatment. This is because the use of narrower beams helps to reduce the exposure of surrounding healthy tissue to the radiation, which in turn reduces the risk of negative side effects such as fatigue, skin irritation, and cognitive decline.

The dependence of the rate constant on temperature is expressed by equation i.e. The Arrhenius equation. Hence, the correct option is (a).

The dependence of the rate constant on temperature is expressed by the Arrhenius equation. The Arrhenius equation is a simple mathematical relationship that describes the temperature dependence of the rate constant, k, of a chemical reaction. The equation is given by:

[tex]k = Ae^(-Ea/RT)[/tex]

here,

A is pre-exponential factor,

Ea is activation energy,

R is gas constant,

T is temperature (Kelvin)

The Arrhenius equation states that the rate constant of a reaction increases exponentially with temperature. This means that as the temperature increases, the rate constant also increases, resulting in an increase in the reaction rate. The de Broglie equation describes the relationship between the wavelength and momentum of a particle and is not related to the rate constant of a chemical reaction. The van't Hoff equation is related to the Arrhenius equation and is used to describe the relationship between the reaction rate and temperature for a reaction in solution.

Hence, the Arrhenius equation is the equation that expresses the dependence of the rate constant on temperature.

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Question - The dependence of the rate constant on temperature is expressed by which equation? Choose the correct answer.

(a) The Arrhenius equation.

(b) The de Broglie equation.

(c) The van't Hoff equation.

(d) Temperature has no effect on the rate constant.

Atomic absorption lines are sharper than the absorption spectrum of a molecule dissolved in solution because Atomic spectra are pure electronic spectra.

Atomic spectra are pure electronic spectra  where as molecular spectra are a combination of electronic, vibrational and microwave spectra which makes the absorption spectrum of a molecule broad.

The presence of spectral lines is explained by amount mechanics in terms of the energy situations of tittles, ions and motes. These energy situations depend on the figures of protons, electrons and neutrons in an snippet, and the limited set of configurations in which these essential patches can live( the set of amount figures). tittles prefer to be in their ground state, where all of the electrons are located as close to the nexus as possible.

Absorption lines do when an snippet, element or patch absorbs a photon with an energy equal to the difference between two energy situations. This causes an electron to be promoted into a advanced energy position, and the snippet, element or patch is said to be in an agitated state.

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Pouring salt on an icy sidewalk to make it free of ice is an example of a colligative property. Colligative properties are properties of solutions that depend on the concentration of solute particles, but not on their identity.

Four common colligative properties are:

Pouring salt on an icy sidewalk to make it free of ice is an example of freezing point depression. The salt dissolves in the water on the surface of the ice and forms a solution. The presence of salt in the water lowers the freezing point of the water, causing it to melt even at temperatures below the normal freezing point of pure water. This effect is due to the increased number of solute particles in the solution, which interferes with the formation of the crystal lattice of ice.

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Answer:

3.55x10^24 atoms Ca

Explanation:

Use Avogadro's number: 6.022 x 10^23

5.90molsCa x (6.022x10^23/1mol) = 3.55x10^24

A saturated solution this is an indication that the solution.

A saturated solution is a solution which contains the maximum amount of solute that can be dissolved in a given amount of solvent. If there is still undissolved solid on the bottom of the flask after the student has mixed the NaCl and H2O, then this indicates that the solution is saturated, as all of the solute that can be dissolved has been dissolved.A very saturated solution is created by repeatedly adding solute to a solution up until a point when the solute manifests as a solid precipitate or crystals.

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complete question:While working in the lab, a student prepares a solution by mixing NaCl and H2O in a flask. After adding the salt and mixing, the student notices that there is some undissolved solid on the bottom of the flask. This is an indication that the solution is:

A.a saturated solution.

B.a concentrated solution.

C.an unsaturated solution.

D.a supersaturated solution.