Static friction is the frictional force that opposes the motion of stationary objects when an external force is acting upon them. It is the force of friction that prevents an object from sliding or moving when a force is applied to it. Static friction is different from kinetic friction, which is the force of friction between two objects that are in motion relative to each other.
The force of static friction depends on two factors: the normal force acting on the object and the coefficient of static friction between the object and the surface it is in contact with. The normal force is the perpendicular force that acts on an object in contact with a surface, such as the force of a book resting on a table.
The coefficient of static friction is a dimensionless quantity that represents the frictional force between two objects in contact with each other. It is dependent on the materials of the objects in contact with each other and is always greater than or equal to the coefficient of kinetic friction.
Static friction is an important force in many areas of physics and engineering. It plays a role in the design of machines, the movement of vehicles, and the behavior of materials under different conditions. Understanding static friction is crucial for engineers and scientists to design efficient and effective systems and structures.
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Two students are canoeing on a river. While heading
upstream, they accidentally drop an empty bottle overboard. They
then continue paddling for 2 hours, reaching a point 2.5 km
farther upstream. At this point they realize that the bottle is
missing and, driven by ecological awareness, they turn around
and head downstream. They catch up with and retrieve the bottle
(which has been moving along with the current) 4.0 km downstream
from the turnaround point. (a) Assuming a constant paddling effort
throughout, how fast is the river flowing? (b) What would the canoe
speed in a still lake be for the same paddling effort?
The speed of the river flowing is 3.75 km/h, and the canoe speed in a still lake for the same paddling effort is 3.6 km/h (approximately).
The distance between the two points upstream and downstream is equal to the distance traveled by the empty bottle. Hence, the distance traveled by the bottle = distance traveled by canoeists = 4 km.Total distance traveled = distance upstream + distance downstreamTotal distance traveled = 2.5 + 4 = 6.5 kmTotal time taken = 2 hours upstream + (4/6) hours downstream (since they are covering 4 km in downstream with the current flowing downstream)Total time taken = 3.67 hours upstream + downstreamFrom the definition of speed, the speed upstream is given by:Speed upstream = distance/time upstreamSpeed upstream = 2.5/2Speed upstream = 1.25 km/hSimilarly, the speed downstream is given by:Speed downstream = distance/time downstream Speed downstream = 4/(4/6)Speed downstream = 6 km/hThe speed of the canoe in still water is given by the average of the upstream and downstream speeds:Speed in still water = (1.25 + 6)/2Speed in still water = 3.625 km/h or 3.6 km/h (approximately).
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A carousel is (more or less) a disk of mass, 15,000 kg, with a radius of 6.14. What torque must be applied to create an angular acceleration of 0.0500 rad/s^2?round to 3 significant figures
(Plssss help me im suffering from severe brainrot)
To calculate the torque required to create an angular acceleration, we can use the formula:
Torque = Moment of Inertia × Angular Acceleration
The moment of inertia of a disk can be calculated using the formula:
Moment of Inertia = (1/2) × Mass × Radius^2
Given:
Mass = 15,000 kg
Radius = 6.14 m
Angular Acceleration = 0.0500 rad/s^2
First, calculate the moment of inertia:
Moment of Inertia = (1/2) × Mass × Radius^2
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Next, calculate the torque:
Torque = Moment of Inertia × Angular Acceleration
Torque = Moment of Inertia × 0.0500 rad/s^2
Now, let's plug in the values and calculate:
Moment of Inertia = (1/2) × 15,000 kg × (6.14 m)^2
Moment of Inertia ≈ 283,594.13 kg·m^2
Torque = 283,594.13 kg·m^2 × 0.0500 rad/s^2
Torque ≈ 14,179.71 N·m
Rounding to three significant figures, the torque required to create an angular acceleration of 0.0500 rad/s^2 is approximately 14,180 N·m.
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jack runs a company in the US He exchanges goods and services with parties and is from other countries which t activity is jack
Reset
Next
Since he runs a company in the US He exchanges goods and services with parties, Jack is engaged in international trade.
What is international trade?International trade is the exchange of goods and services between countries. It is a major driver of economic growth and prosperity. Jack's company can benefit from international trade in a number of ways. First, it can access new markets and customers. Second, it can source lower-cost inputs from other countries. Third, it can diversify its risk by selling to customers in multiple countries.
However, Jack's company also faces some challenges when engaging in international trade. First, it must deal with different languages, cultures, and legal systems. Second, it must comply with import and export regulations. Third, it must manage the risk of currency fluctuations.
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A 1.2 kg ball drops vertically onto a floor hitting with a speed of 15 m/s
The magnitude of the change in momentum is 36 kg m/s.
The momentum of an object is defined as the product of its mass and velocity.
The symbol for momentum is p. Its unit is kilogram meters per second (kg m/s). When a ball falls vertically onto a surface, the momentum is said to change.
The magnitude of the change in momentum can be found by calculating the difference between the initial momentum and the final momentum.
We can use the equation below to find the change in momentum.Δp = pf - pi
Where Δp is the change in momentum, pf is the final momentum, and pi is the initial momentum.The initial momentum of the ball can be found using the equation:
p = mv
where p is momentum, m is mass and v is velocity.
Therefore, the initial momentum of the ball is:
p = mv= 1.2 kg × 15 m/s= 18 kg m/s
The final momentum can be found using the same equation, but with a negative velocity since the ball is bouncing back with the same speed but opposite direction.
Therefore, the final momentum is:-18 kg m/s/
The change in momentum can now be calculated using the equation:
Δp = pf - piΔp = (-18 kg m/s) - (18 kg m/s)Δp = -36 kg m/s
Therefore, the magnitude of the change in momentum is 36 kg m/s.
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Thomas the Train chugs along at 2 m/s. Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s. What is Thomas' acceleration?
The acceleration of Thomas is 0.233 m/s^2.
Acceleration is the rate of change of velocity. Thomas the Train chugs along at a velocity of 2 m/s.
Thomas needs to go faster so more coal is shoveled into his engine and he accelerates for 10 seconds until he is going 4.33 m/s.
We are to find the acceleration of Thomas.
The formula for acceleration is given as :
acceleration = (final velocity - initial velocity) / time
In the given problem, the initial velocity of Thomas, u = 2 m/s.
The final velocity of Thomas, v = 4.33 m/s The time for which Thomas accelerates, t = 10 s.
Therefore, the acceleration of Thomas will be given as:
a = (v - u) / ta = (4.33 - 2) / 10s => 2.33 / 10s => 0.233 m/s^2
Thus, the acceleration of Thomas is 0.233 m/s^2.
To summarize, the acceleration of Thomas is 0.233 m/s^2.
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report of "fan made of plastic bottle" with string
Fan made of plastic bottle is an innovative way to reuse plastic bottles and can be easily made at home. This can be done by following simple steps, and a few materials are required to make it. The fan can be created by using a plastic bottle, scissors, string, a ruler, and a marker.
First, the bottle needs to be cut into half, and the upper part needs to be cut into three equal sections, then fold each section to make a blade. With the help of a ruler and marker, make a mark on each section, then make a hole in the center of each blade. Insert a string through the holes and tie the ends of the strings. The fan is ready to use by holding the string and swinging it back and forth.
The use of plastic bottle fans can significantly reduce the number of plastic waste and provide a practical solution to avoid environmental pollution. Besides, it is easy to make, and the materials are readily available, which can be used for various occasions, such as picnics, camping, or any outdoor activities.
In conclusion, the creation of a fan made of plastic bottle with string is an excellent way to reuse plastic bottles and can be made with simple steps. This project encourages everyone to contribute to environmental protection by utilizing what is available at home and reducing the number of plastic wastes.
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A boy throws an arrow at an original speed of 2m / s to create an angle 0 referring to the balloon at a distance of 3m from the departure point. Calculate the angle 0 and the height of the arrow. Let g = 10m / s2.
Calculate the horizontal component of the velocity. The horizontal component of the velocity is given by:
v_x = v * cos(theta)
where v is the original speed of the arrow and theta is the angle of projection.In this case, v = 2 m/s and theta is unknown. Solving for theta, we get:
theta = arccos(v_x / v)
theta = arccos(2 / 2) = 45 degrees
Calculate the vertical component of the velocity. The vertical component of the velocity is given by:
v_y = v * sin(theta)
In this case, v = 2 m/s and theta = 45 degrees. Solving for v_y, we get:
v_y = 2 * sin(45 degrees) = 1.414 m/s
Calculate the time of flight. The time of flight is given by:
t = 2 * v_y / g
In this case, v_y = 1.414 m/s and g = 10 m/s^2. Solving for t, we get:
t = 2 * 1.414 / 10 = 0.283 seconds
Calculate the height of the arrow. The height of the arrow is given by:
y = v_y * t - 0.5 * g * t^2
In this case, v_y = 1.414 m/s, t = 0.283 seconds, and g = 10 m/s^2. Solving for y, we get:
y = 1.414 * 0.283 - 0.5 * 10 * 0.283^2 = 0.303 meters
Therefore, the angle of projection is 45 degrees and the height of the arrow is 0.303 meters.
Answer the following Critical Thinking Questions. Each answer is worth 5 points, for a total of 25 points.
A particular star is 20 pc away from the Earth, and its luminosity is 160 times the luminosity of the Sun and has a surface temperature of 4000 K. Its absolute magnitude is -0.66. The temperature of the Sun is 5800 K. Explain/show your work.
What is this star's parallax?
What is this star's spectral class?
What is the wavelength at which this star radiates the most energy?
What is this star's apparent magnitude?
What is this star's radius, in solar radii?
Using a suitable diagram illustrate the following as applicable to the wave . 1. crest 2. Trough 3. Amplitude 4.Wavelength 5.Period
The images that shows the terms have been attached to this answer.
What does the terms mean?A crest refers to the highest point or peak of a wave. It represents the maximum positive displacement or upward excursion of the wave from its rest position.
A trough is the maximum negative displacement or downward excursion of the wave from its rest position.
The amplitude of a wave refers to the maximum displacement or distance from the rest position to either the crest or the trough.
The wavelength is the distance between two adjacent crests or two adjacent troughs. In other words, it is the length of one complete wave cycle.
Period is the the duration between two corresponding points in a wave, such as two adjacent crests or troughs passing a fixed point.
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Suppose that you drop a marble from the top of a building, which is about 890 m tall. If you ignore air resistance, how long will it take for the marble to hit the ground?
The marble will take approximately 12 seconds to hit the ground, ignoring air resistance.
To solve this problem we can use the equations of motion that are given as below:
Vf = Vi + atX =[tex]Vi*t + 1/2*a*t^2Vf^2 = Vi^2 + 2*a*X[/tex]
Where:Vf = final velocity, Vi = initial velocity, a = acceleration, X = distance traveled, and t = time taken.For a freely falling object near the surface of the earth, we can assume that the acceleration due to gravity is constant at 9.8 [tex]m/s^2[/tex] (downward direction).
At the top of the building, the initial velocity is zero. Hence, using the equation, [tex]Vf^2 = Vi^2 + 2*a*X[/tex], we can find the final velocity, Vf, just before the marble hits the ground.
So, we have:[tex]Vf^2 = 2*a*X[/tex]
where, X = 890 m (height of the building) and
a = 9.8[tex]m/s^2Vf[/tex]
= sqrt(2*9.8*890) ≈ 118 m/s
Now, using the equation, Vf = Vi + at, we can find the time, t, taken by the marble to reach the ground. So, we have:118 = 0 + 9.8*t.
Therefore, t = 118/9.8 ≈ 12 seconds.
Therefore, the marble will take approximately 12 seconds to hit the ground, ignoring air resistance.
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An ancient building was known to have been built 3,000 years ago. Approximately what proportion of Carbon-14 atoms are yet in the building's wooden framing compared to the number which were present at the time of its construction? (half life of 14C = 5,730 years)
83.2% of the original 14Carbon atoms present in the wooden framing of the ancient building at the time of its construction are still present today.
The half-life of Carbon-14 (14C) is 5,730 years, which means that after this time, half of the 14C atoms in a sample will have decayed. Using this information, we can estimate the proportion of remaining 14C atoms in the wooden framing of an ancient building that was constructed 3,000 years ago.
Since 3,000 years have passed, we can calculate the number of half-lives that have occurred by dividing the time elapsed (3,000 years) by the half-life of 14C (5,730 years). In this case, approximately 0.524 half-lives have occurred (3,000 / 5,730 ≈ 0.524).
With each half-life, the number of 14C atoms is halved. Therefore, after 0.524 half-lives, the proportion of remaining 14C atoms in the wooden framing can be estimated to be approximately [tex]0.5^{0.524}[/tex], which is about 0.832 or 83.2%. The rest have decayed over time. It is worth noting that this estimation assumes a constant rate of decay and no additional 14C uptake or loss since the construction of the building.
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A precondition for perfect competition is that
the product should be homogeneous. True or false
The given statement, "A precondition for perfect competition is that the product should be homogeneous" is true.
Perfect competition is a market structure in which numerous small firms compete against each other with identical or homogeneous products, and no one firm can influence the market price independently.
In a perfectly competitive market, there is free entry and exit of firms, perfect knowledge of the market, and no barriers to entry.What does homogeneous mean?Homogeneous products refer to goods or services that are identical or very similar in nature and have the same level of quality and features. Examples of homogeneous products include agricultural goods, basic raw materials, commodities, and so on.
In perfect competition, all firms offer identical products to customers. Homogeneous products are essential to ensure that no single firm has an advantage over others in terms of quality or price. If there were differences in quality or price, customers would prefer to buy from the firm with the lowest price or highest quality. This would give that firm a competitive advantage over others in the market.
As a result, it would no longer be a perfectly competitive market, since one firm could influence the market price independently. Therefore, the precondition for perfect competition is that the product should be homogeneous, which means that all firms should offer identical or very similar products to their customers.
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A student plucks a guitar string and the vibrations produce a sound wave with a frequency of 650 hertz. The sound wave produced can best be described as a
Answer:
I think its could be C
Explanation:
I think c because it makes the most sense and seems logical
Initial velocity: U = ?
Final velocity: v = 0
Gravity: g = 9,8 ms²
Height: h = 20m
v² = u² + 2gh
0 = u² + 2 (-9,8ms²) x 20m
The initial velocity of the object in motion is determined as 19.8 m/s.
What is the initial velocity of the object?The initial velocity of the object in motion is calculated by applying the third equation of motion as follows;
v² = u² + 2gh
where;
v is the final velocity of the objectu is the initial velocity of the objectg is acceleration due to gravityh is the height through which the object riseswhen the object reaches maximum height, the final velocity, v = 0
The initial velocity of the object in motion is calculated as;
0 = u² + 2 (-9,8ms²) x 20m
0 = u² - 392
u² = 392
u = √392
u = 19.8 m/s
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how does mass relates to latent heat?
The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.
What is latent heat?Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.
Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.
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6. A force of F = (6x²i+4j) N acts on a particle that moves from point A with coordinates (2,2) m to point B with coordinates (3,4) m. How much work is done on the particle as it moves from point A to point B?
The work done by the force to move the particle from A to B is 18(3)² + 8= 170 J.
Given a force of F = (6x²i+4j) N acts on a particle that moves from point A with coordinates (2,2) m to point B with coordinates (3,4) m.
We need to calculate how much work is done on the particle as it moves from point A to point B.
The work done W is given by the dot product of the force and displacement vectors.
W = F .
s where s is the displacement vector from A to B.W
= (6x²i+4j) . (3i + 2j)W = (6x²)(3) + (4)(2)W = 18x² + 8 J
The work done by the force is 18x² + 8 J.
Therefore, the work done by the force to move the particle from A to B is 18(3)² + 8= 170 J.
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indirect comparison method of measurements
The indirect comparison method of measurements is a method for measuring quantities that are difficult to measure directly or that cannot be measured directly. The method is based on comparing the quantity to be measured to a known standard or reference quantity that is related to the quantity being measured. The indirect comparison method can be used for measuring a wide range of quantities, including length, mass, volume, and time.
To use the indirect comparison method, the first step is to select a known standard or reference quantity that is related to the quantity being measured. For example, to measure the length of an object, a ruler or tape measure could be used as a standard.
Next, the standard is used to measure the reference quantity, such as the length of the ruler. This measurement is then used to calculate the conversion factor between the reference quantity and the quantity being measured. For example, if the ruler is 30 cm long and the length of the object is 4 times the length of the ruler, then the length of the object is 120 cm.
The indirect comparison method is useful when direct measurement is not possible or when the accuracy of the measurement needs to be improved. It is often used in scientific research and engineering to measure quantities such as distance, speed, and flow rate.
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A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm,find the emf of the cell.
A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.
To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.
Given:
Resistance of the coil, R1 = 4 ohm
Resistance of the other resistor, R2 = 8 ohm
Current passing through the 8-ohm resistor, I = 2A
First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.
The total resistance of two resistors in parallel can be calculated using the formula:
1/Rp = 1/R1 + 1/R2
Substituting the given values, we have:
1/Rp = 1/4 + 1/8
1/Rp = 2/8 + 1/8
1/Rp = 3/8
Rp = 8/3 ohm
Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).
R_total = R_internal + Rp
R_total = 0.5 + 8/3
R_total = 1.833 ohm
Now, we can find the emf of the cell using Ohm's Law:
emf = I * R_total
emf = 2 * 1.833
emf ≈ 3.667 volts
Therefore, the emf of the cell is approximately 3.667 volts.
However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.
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Which of the following are examples of light behaving like an electromagnetic wave? Choose all that apply.
Group of answer choices
Compton scattering
interference through two slits
diffraction through one slit
photoelectric effect
refraction
The examples of light behaving like an electromagnetic wave are Compton scattering, interference through two slits, diffraction through one slit, and refraction.
Light is a type of electromagnetic radiation that is composed of electromagnetic waves. Light behaves like an electromagnetic wave in several ways. Electromagnetic waves are transverse waves that travel through a vacuum. They don't need a medium to propagate. Light can behave like an electromagnetic wave in several ways. Let's discuss each option in the question.
Compton scattering: Compton scattering is a phenomenon in which an incident X-ray or gamma-ray photon collides with an electron resulting in a scattered photon and a recoiling electron. It can only be explained by assuming that light behaves as both waves and particles. Therefore, Compton scattering is an example of light behaving like an electromagnetic wave.
Interference through two slits: When light passes through two narrow slits separated by a distance that is small compared to the wavelength of the light, it will diffract and interfere. The interference pattern will be characterized by bright and dark fringes. This phenomenon is an example of light behaving like an electromagnetic wave.
Diffraction through one slit: When light passes through a single narrow slit, it diffracts and creates an interference pattern similar to that produced by two slits. This phenomenon is an example of light behaving like an electromagnetic wave.
Photoelectric effect: The photoelectric effect is a phenomenon in which electrons are ejected from a metal surface when light shines on it. The photoelectric effect can be explained by assuming that light behaves as a stream of particles or photons. Therefore, the photoelectric effect is not an example of light behaving like an electromagnetic wave.
Refraction: Refraction is the bending of light as it passes from one medium to another, such as from air to water. It can be explained by assuming that light behaves like an electromagnetic wave. Therefore, refraction is an example of light behaving like an electromagnetic wave.
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A boy throws an arrow at an original velocity of 2m / s, aiming to create an angle 0, referring to the balloon at a distance of 3m from the point of departure. Calculate the angle 0 and the height of the arrow.
Answer:
s=0.204m
Explanation:
Assuming that the arrow is thrown horizontally and there is no air resistance, we can use the following formula to calculate the launch angle 0:
tan(0) = opposite/adjacent = height/distance
where opposite is the height that the arrow reaches and adjacent is the distance to the balloon.
Rearranging the formula, we get:
0 = arctan(height/distance)
0 = arctan(height/3)
Taking the tangent of both sides, we get:
tan(0) = tan(arctan(height/3))
tan(0) = height/3
Now, we need to find the height of the arrow. Using the kinematic equation:
v^2 = u^2 + 2as
where v is the final velocity (0m/s, at maximum height), u is the initial velocity (2m/s), a is acceleration (-9.8m/s^2, due to gravity) and s is the distance travelled vertically until the arrow reaches maximum height.
At maximum height, the final velocity is 0m/s. Therefore, we have:
0 = (2m/s)^2 + 2(-9.8m/s^2)s
Solving for s, we get:
s = 0.204m
Therefore, the height of the arrow is approximately 0.204m.
Question 2 A mass of 100N is suspended from two ropes, 3m and 4m long respectively, attached to two points 5m apart. Find the tension in the rope. (4 marks) 3 m 5 m W = 100 N
The tension in the rope is 100 N.
1. Draw a diagram representing the given scenario. The mass of 100N is suspended from two ropes, one measuring 3m and the other measuring 4m, attached to two points 5m apart. Label the mass as "W" and the distances as given.
2. Break down the forces acting on the mass. There are two vertical forces: the tension in the 3m rope and the tension in the 4m rope. Additionally, there is a horizontal force due to the weight of the mass.
3. Apply the principle of equilibrium in the vertical direction. Since the mass is not moving vertically, the sum of the vertical forces must be zero. The tension in the 3m rope can be represented as T1, and the tension in the 4m rope as T2. Therefore, T1 + T2 - W = 0.
4. Apply the principle of equilibrium in the horizontal direction. Since there are no horizontal accelerations, the sum of the horizontal forces must be zero. In this case, the horizontal force is simply T2. Therefore, T2 = 0.
5. Solve the system of equations formed in step 3. Substitute the value of T2 from step 4 into the equation T1 + T2 - W = 0. This gives T1 + 0 - W = 0. Rearrange the equation to isolate T1, resulting in T1 = W.
6. Substitute the given value for W (100N) into the equation to find T1. T1 = 100N.
7. Therefore, the tension in the rope is 100N.
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A car is moving north at 5.2 m/s². Which type of motion do the SI units in this value express?
A. Displacement
B. Velocity
C. Speed
D. Acceleration
A car is moving north at 5.2 m/s². SI unit in this value is m/s² (meter per second square), expressing Acceleration. Thus, Option D is the correct answer.
Here Acceleration of any object is given by the Rate of change in velocity in relation to time.
[tex]Acceleration = \frac{velocity}{time}[/tex] ............(i)
The standard Indian (SI) unit of Acceleration is meter per second square(m/s²).
The velocity of any object is displacement per unit time.
[tex]velocity = \frac{Displacement}{Time}[/tex]............(ii)
The standard Indian (SI) unit of Velocity is meter per second(m/s)
The Displacement of any object is the shortest distance covered by any object considering the direction of motion also.
The standard Indian (SI) unit of displacement is meter(m).
The standard Indian (SI) unit of Time is Second(s).
We can find standard Indian (SI) unit of Acceleration using formula as follows:
[tex]Acceleration= \frac{Velocity}{time*time}[/tex] (we got this formula from (i), (ii) )
The standard Indian (SI) units of acceleration are [tex]=\frac{m}{s*s}[/tex]
[tex]=m/s^{2}[/tex]
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imagine you have been closed in a car where their pieces of cardboard and 2 mirrors,a masking tape and a pair of scissors as you're inside you hear your friends talking about something funny using the materials inside the car design an instrument you can use to see what is happening outside support your design with the scientific report
To see what is happening outside the car using the available materials, you can design a periscope using mirrors, cardboard, masking tape, and scissors.
Explanation:To design an instrument to see what is happening outside the car, we can make a periscope using the materials available. A periscope uses mirrors to reflect the light and images, allowing us to see around corners or over obstacles. Using the mirrors, cardboard, masking tape, and scissors, we can create a periscope by positioning one mirror at a 45-degree angle, reflecting the image towards the second mirror which is positioned horizontally to observe the outside environment. By adjusting the angles and positions of the mirrors, we can see what is happening outside the car without directly looking out.
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Please help (science)
Plate Boundaries on Earth
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Open the worksheet to get started. Use the criteria below to see what you should include in this assignment.
Row 1: Plate Boundary (Movement)
Write the type of plate boundary: convergent, divergent, transform.
Write the correct description for each in parentheses below the name: sliding, separating, or colliding.
Row 2: Diagram
Draw a diagram or illustration of the plate movement at the plate boundary. Include arrows to show whether the plates are colliding, separating, or dividing.
Row 3: Lithosphere (Created or Destroyed)
Identify whether the Earth's crust is created or destroyed at this type of plate boundary.
Row 4: Geologic Process
Give at least one example of the type of process or geological event that occurs on the Earth when the plates move in this manner.
Row 5: Real World Example
Give at least one example of a place on the planet where this type of plate movement is demonstrated along the plate boundary. Include both the location and name of the example.
Row 6: References
This assignment requires you to conduct formal research. When researching, make sure to use only valid and reliable resources; Wikipedia, blogs, and answer sites are not valid or reliable. References must be cited in APA format. Please provide your references in APA format in this column.
Here is a draft of the worksheet for the three main plate boundary types:
Plate Boundary (Movement) Convergent (Colliding)
Diagram
||
||
||
Lithosphere (Created or Destroyed)
Created
Geologic Process Mountain building
Real World Example
Himalayas (Along India-Eurasia plate boundary in Asia)
References
APA reference for research
Plate Boundary (Movement) Divergent (Separating)
Diagram
|||||
Lithosphere (Created or Destroyed)
Destroyed
Geologic Process
Volcanic eruptions and rift valleys
Real World Example
Mid-Atlantic Ridge (Between North America and Europe plates)
References
APA reference
Plate Boundary (Movement) Transform (Sliding)
Diagram
|||||||||
Lithosphere (Created or Destroyed)
Neither
Geologic Process
Earthquakes
Real World Example
San Andreas Fault (California, USA along Pacific-North America plates)
References
APA reference
Define measurement.
Answer:
Measurement is the comparison of any physical quantity of an object to a standard unit which is pre-determined. The standard units such as length, time, mass etc are known as the Fundamental units of Measurement.
Explanation:
Any object that can be measured is known as a physical quantity. So, to measure the physical quantity, we require some standard units. A measurement consists of two parts - the numerical measurement and the standard unit which is pre-determined. For example, the length of a given table is 10cm, which implies that 10 is the numerical value and the standard unit of measurement is centimeter (cm).
Measurements can be both Fundamental and Derived. Examples of Fundamental quantities are Length, Time etc, while example of Derived quantity is speed which is derived from Length and Time.
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What is the distance CE Called?
The distance CE is called the altitude of the triangle ABD.
In mathematics, the distance CE is called the altitude of the triangle ABD.
An altitude is a line segment drawn from the vertex of a triangle to the opposite side, and it is perpendicular to that side.The altitude CE divides the triangle into two smaller right triangles, ACE and BCE.
The length of the altitude can be found using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
To find the length of the altitude CE, you would use the Pythagorean theorem on either of the right triangles.
For example, using the right triangle ACE, you would have:
AC² + CE² = AE²
Where AC is the length of one of the legs of the triangle, CE is the length of the altitude, and AE is the length of the hypotenuse.
By rearranging this equation, you can solve for CE:
CE² = AE² - AC²CE = √(AE² - AC²)
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A Quartz piezo-electric crystal having a thickness of 2 mm and voltage sensitivity of 0.055 V-m/N is subjected to a pressure of 1.5 MN/2. Calculate the voltage output. If the permittivity of quartz is 40.6 X 10−12 F/m, calculate its charge sensitivity.
(a) The voltage output of the quartz piezo-electric crystal is 8.25 x 10⁻⁵ V.
(b) The charge sensitivity is 2.44 x 10⁻⁶ F.
What is the voltage output?The voltage output of the quartz piezo-electric crystal is calculated as follows;
V = SdP
where:
S is the voltage sensitivity,d is the thickness of the crystalP is the applied pressure.The given parameters include;
S = 0.055 V-m/N
d = 2 mm = 0.002 m
P = 1.5 MN/2 = 0.75 N/m²
The voltage output is calculated as follows;
V = 0.055 V-m/N x 0.002 m x 0.75 N/m²
V = 8.25 x 10⁻⁵ V
(b) The charge sensitivity is calculated as follows;
C = εA / d
where:
C is the charge sensitivity,ε is the permittivity of quartz,A is the area of the crystal, andd is the thickness of the crystal.The given parameters include;
ε = 40.6 x 10⁻¹² F/m
d = 0.002 m
A = 1.2 x 10² m²
C = ( 40.6 x 10⁻¹² x 1.2 x 10² ) / ( 0.002)
C = 2.44 x 10⁻⁶ F
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The complete question is below:
A Quartz piezo-electric crystal having a thickness of 2 mm and voltage sensitivity of 0.055 V-m/N is subjected to a pressure of 1.5 MN/2. Calculate the voltage output. If the permittivity of quartz is 40.6 X 10−12 F/m, calculate its charge sensitivity if the area is 1.2 x 10² m².
The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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Which of the following will happen to the sorrounding air as warm air rises?
a. Moves in all directions
b. Moves to a higher altitude
c. Moves away from the rising air
d. Moves toward to the place where warm air rises
Which of the following statement it's NOT TRUE about amihan and habagat?
a. Amihan is known as the northeast monsoon
b. Habagat is known is as the southwest monsoon
c. From october to march the hagabat comes from the northeast and moves towards the south
d. From october to march the amihan comes from the northeast and moves towards the south.
PLEASE KINDLY ASNWER MY QUENSTION, THANKYOU PO!
As warm air rises, the surrounding air will move in from all directions to take its place.
Thus, the correct option is a.
- The statements" From October to March, the Habagat comes from the northeast and moves towards the south," and "'From October to March, the Amihan comes from the northeast and moves towards the south." are not true about amihan and habagat . The correct option are c and d.
When air is warmed by the ground, it rises, cools, and sinks again. This is referred to as a convection cycle. As the air heats up, it becomes lighter and rises, causing the surrounding air to rush in and replace it. As the air cools, it sinks back down to the surface, creating a circulation loop that continues as long as the ground is being heated.
- The statements that are not true about amihan and habagat are C. From October to March, the Habagat comes from the northeast and moves towards the south, and D. From October to March, the Amihan comes from the northeast and moves towards the south. The actual direction of airflow is reversed.
Amihan is known as the northeast monsoon, which comes from Siberia and passes over the Pacific Ocean before entering the Philippine region from the northeast and moving southward. Habagat is known as the southwest monsoon, which comes from the Indian Ocean and passes over the Philippines before exiting the country to the west and moving northward.
Amihan and Habagat are two prevailing winds that alternate with each other in the Philippines. Amihan prevails from October to March and Habagat from April to September. Amihan is colder and drier, while Habagat is warmer and wetter. Amihan is known for its northeast wind, which cools the air, and Habagat is known for its southwest wind, which causes heavy rainfall and flooding.
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1. Two vectors A and B are perpendicular to each other. The magnitude of the resultant is √80 unit and vector à is twice vector B. Calculate the value of the two vectors.
The magnitude of the resultant is √80 unit and vector à is twice vector B ,hence The two vectors are A = 8 and B = 4.
Given that Two vectors A and B are perpendicular to each other.
The magnitude of the resultant is √80 unit and vector à is twice vector B.
So, the resultant of vectors A and B can be represented as;
[tex]`A^2 + B^2 = (\sqrt(80)^2`[/tex]
Where [tex]A^2 and B^2[/tex] are the magnitudes of vectors A and B respectively.
So, `[tex]A^2 + B^2 = 80`[/tex]
We also know that `A = 2B`
Substitute A with 2B in equation `[tex]A^2 + B^2 = 80[/tex]` and simplify.
[tex]`(2B)^2 + B^2 = 80``5B^2 = 80``B^2 = 16``B = ±4`[/tex]
Since B is a vector, we take the positive value of B i.e.
`B = 4`
Then `A = 2B = 2 × 4 = 8`
Hence, the two vectors are A = 8 and B = 4.
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