The functions fand g are defined as follows. 2 f(x) = x+4 x+7 g(x) = 2 x²-49 For each function, find the domain. Write each answer as an interval or union of intervals.

Answers

Answer 1

The domain of f(x) is all real numbers except for -7. The domain of g(x) is all real numbers.

The domain of a function is the set of all real numbers that can be input into the function without causing the function to be undefined.

In the case of f(x), the denominator of the fraction is equal to 0 when x = -7. Therefore, x cannot be equal to -7. This means that the domain of f(x) is all real numbers except for -7.

In the case of g(x), there are no real numbers that make the function undefined. Therefore, the domain of g(x) is all real numbers.

Here are the domains of f(x) and g(x) in interval notation:

f(x) : (-∞, -7) ∪ (-7, ∞)

g(x) : (-∞, ∞)

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Related Questions

Type the correct answer in each box Use numerals instead of words. If necessary, use/ for the fraction bar(s)
Triangle ABC is defined by the points A(2,9), B(8,4), and C(-3,-2)
Complete the following equation for a line passing through point C and perpendicular AB
y=
X+

Answers

Coordinate axes - Ox and Oy. Let this perpendicular intersects AB at the point H. We will also draw a parallel line for Ox that is going through the point A. Let this line intersects CH at the point D. We also will take a point N(3;9). It will lie on the line AD (because the vector AN has coordinates {1; 0}, that means that it is collinear to the position vector that lines on Ox).

We will now find the angle α between AN and AB. For this we will find scalar product of the vectors AN and AB: vector AN has coordinates {1; 0}, and the vector AB has coordinates {6; -5}.

The scalar product of two vectors with coordinates {x1; y1} and {y1; y2} equals to x1 * x2 + y1 * y2. In this case, it equals to 6 * 1 + -5 * 0 = 6.

Also, it equals to the product of the lengthes of those vectors on the cos of angle between thise vectors. In this case, the length on AN equals to 1, the length of AB equals to √(6² + 5²) = √61.

So we can get that cosα * √61 = 6; cosα = 6/√61. Let β be the angle ADH. Because ADH is the right triangle, we get that cosα = sinβ, so sinβ = 6/√61; we know that β is acute, because it is the angle of the right triangle AHD, so cosβ > 0. We can find cosβ through the Pythagoren trigonometric identity. It tells us that cosβ = 5/√61, so tanβ = sinβ/cosβ = 6/5. But β is the interior alternate angle for the pair of parallel lines AD and Ox, so this is the angle between CD and Ox.

Reminder: for the line y = kx + b, k equals to the tan of the angle between this line and Ox.

So we have got that k = 6/5, and y = 6/5 * x + b. But we know that C lies on y, so we can substitute its coordinates in this equality:

-2 = 6/5 * -3 + b.

b = 18/5 - 2 = 8/5 = 1.6

k = 6/5 = 1.2

y = 1.2x + 1.6 - this is the answer.

A. Given the following: A=(
0
2


1
−3

),B=(
−2
2


1
3

),C=(
−2
1


−1
1

) (5 marks) Find the value of 3BC−2AB B. Using the matrix method or otherwise, solve the following system of simultaneous equations.
x+2y−z=6
3x+5y−z=2
−2x−y−2z=4

(15 marks) (Total 20 marks)

Answers

A. The value of 3BC - 2AB, where A, B, and C are matrices, can be calculated as -39 13 15 -23.

B. By using the matrix method, the solution to the system of simultaneous equations x + 2y - z = 6, 3x + 5y - z = 2, and -2x - y - 2z = 4 is x = -1, y = 2, and z = 3.

A. To calculate 3BC - 2AB, we first need to multiply matrices B and C to obtain BC, and then multiply BC by 3 to get 3BC. Similarly, we multiply matrices A and B to obtain AB, and then multiply AB by -2 to get -2AB. Finally, we subtract -2AB from 3BC to obtain the resulting matrix, which is -39 13 15 -23.

B. To solve the system of simultaneous equations, we can use the matrix method. First, we express the system of equations in matrix form as AX = B, where A is the coefficient matrix, X is the column vector of variables (x, y, z), and B is the column vector of constants. By rearranging the equation, we have X =[tex]A^-1 * B,[/tex] where [tex]A^-1[/tex] is the inverse of matrix A. By calculating the inverse of matrix A, we can then multiply it by B to obtain the solution vector X, which represents the values of x, y, and z. In this case, the solution to the system of equations is x = -1, y = 2, and z = 3.

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When performing a χ^2 test for independence in a contingency table with r rows and c columns, determine the upper-tail critical value of the test statistic in each of the following circumstances. a. α=0.05,r=4,c=6 b. α=0.01,r=5,c=3 c. α=0.01,r=5,c=4 a. Determine the upper-tail critical value of the test statistic using the values given in the problem statement for part (a). The critical value is ___
(Type an integer or a decimal. Round to three decimal places as needed.) b. Determine the upper-tail critical value of the test statistic using the values given in the problem statement for part (b). The critical value is ___
(Type an integer or a decimal. Round to three decimal places as needed.) c. Determine the upper-tail critical value of the test statistic using the values given in the problem statement for part (c). The critical value is ___
(Type an integer or a decimal. Round to three decimal places as needed.)

Answers

The upper-tail critical values for the test statistic are as follows: a. Critical value ≈ 28.845, b. Critical value ≈ 20.090, c. Critical value ≈ 26.217

To determine the upper-tail critical value of the test statistic for a chi-square test for independence, we need to refer to the chi-square distribution table or use statistical software. The critical value depends on the significance level (α) and the degrees of freedom (df) associated with the contingency table.

The degrees of freedom for a chi-square test for independence with a contingency table of r rows and c columns can be calculated using the formula:

df = (r - 1) × (c - 1)

Let's calculate the upper-tail critical values for each scenario:

a. α = 0.05, r = 4, c = 6

df = (4 - 1) × (6 - 1) = 3 × 5 = 15 (degrees of freedom)

Using a chi-square distribution table or software, the upper-tail critical value for α = 0.05 and df = 15 is approximately 28.845.

b. α = 0.01, r = 5, c = 3

df = (5 - 1) × (3 - 1) = 4 × 2 = 8 (degrees of freedom)

Using a chi-square distribution table or software, the upper-tail critical value for α = 0.01 and df = 8 is approximately 20.090.

c. α = 0.01, r = 5, c = 4

df = (5 - 1) × (4 - 1) = 4 × 3 = 12 (degrees of freedom)

Using a chi-square distribution table or software, the upper-tail critical value for α = 0.01 and df = 12 is approximately 26.217.

The upper-tail critical values for the test statistic are as follows:

a. Critical value ≈ 28.845

b. Critical value ≈ 20.090

c. Critical value ≈ 26.217

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Construct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed. c=0.95, x = 12.8, s 3.0, n=6 O (Round to one decimal place as needed.)

Answers

The 95% confidence interval for the population mean μ is approximately (9.6, 17.0). It is based on a sample mean of 12.8, a sample standard deviation of 3.0, and a sample size of 6.

To construct the confidence interval for the population mean μ using the t-distribution, we will use the given information and the formula for the confidence interval. Here are the calculations:

Given:

Confidence level: c = 0.95

Sample mean: x = 12.8

Sample standard deviation: s = 3.0

Sample size: n = 6

The degrees of freedom for the t-distribution is (n - 1), which is (6 - 1) = 5.

The formula for the confidence interval is:

CI = x ± t * (s / √n)

To find the value of t, we need to consult the t-distribution table or use a statistical software. For a 95% confidence level and 5 degrees of freedom, the critical t-value is approximately 2.571.

Substituting the values into the formula, we get:

CI = 12.8 ± 2.571 * (3.0 / √6)

Calculating the expression inside the parentheses first:

3.0 / √6 ≈ 1.225

Substituting this value into the formula:

CI = 12.8 ± 2.571 * 1.225

Calculating the right side of the interval first:

2.571 * 1.225 ≈ 3.151

Substituting this value into the formula:

CI = 12.8 ± 3.151

Finally, calculating the confidence interval:

CI = (12.8 - 3.151, 12.8 + 3.151)

Simplifying:

CI ≈ (9.649, 16.951) (rounded to one decimal place)

In summary, the 95% confidence interval for the population mean μ is approximately (9.6, 17.0).

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DETAILS SCALCET7 7.5.056. 0/1 Submissions Used Evaluate the integral. (Use C for the constant of integration.) 8 dx √ √x + x√x

Answers

∫(8 du) / (√x + x^(-1/2))√u. Transformed the original integral into a new integral in terms of u.

In this problem, we are asked to evaluate the integral ∫8 dx/√(√x + x√x) using the given substitution rule.

To evaluate the integral, we can use the substitution method. Let's make the substitution u = √x + x√x. Then, we need to find du/dx and solve for dx.

Differentiating both sides of the substitution equation u = √x + x√x with respect to x, we get:

du/dx = d/dx(√x + x√x)

To find the derivative of √x, we can use the power rule: d/dx(√x) = (1/2)x^(-1/2).

For the derivative of x√x, we use the product rule: d/dx(x√x) = (√x) + (1/2)x^(-1/2).

Therefore, du/dx = (1/2)x^(-1/2) + (√x) + (1/2)x^(-1/2) = (√x) + x^(-1/2).

Now, we can solve for dx in terms of du:

du = (√x) + x^(-1/2) dx.

Rearranging the equation, we have:

dx = du / ((√x) + x^(-1/2)).

Now, let's substitute u and dx in the integral:

∫(8 dx) / √(√x + x√x) = ∫(8 (du / ((√x) + x^(-1/2)))) / √u.

Simplifying the expression, we get:

∫(8 du) / (√x + x^(-1/2))√u.

Now, we have transformed the original integral into a new integral in terms of u. We can proceed to evaluate this new integral.

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How Data Science process is different from Software Engineering process (illustrate with an example). Which model of Software Project ?
Management Methodology is close to that applied for a typical Data Science Project and why?

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The Data Science process differs from the Software Engineering process in several ways. Data Science focuses on extracting insights and knowledge from data, while Software Engineering focuses on designing.

The Data Science process typically involves steps such as data collection, data preprocessing, exploratory data analysis, model building, evaluation, and deployment. On the other hand, the Software Engineering process follows a more structured approach with phases like requirements gathering, system design, coding, testing, and maintenance.

The Agile methodology in Software Project Management is closely related to the Data Science process. Agile emphasizes flexibility, collaboration, and iterative development, which aligns well with the iterative and exploratory nature of Data Science projects. Both Agile and Data Science projects involve working with dynamic requirements and evolving solutions. They also prioritize adaptability and responding to changes quickly. Agile's iterative approach, frequent feedback loops, and continuous improvement closely resemble the iterative nature of Data Science, where models are refined based on evaluation and feedback. Therefore, Agile methodology is often considered a suitable Software Project Management methodology for Data Science projects.

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Identify the null and alternative hypotheses for this test. Choose the correct answer below. A. H 0​ :p=0.20 H 1​ :p>0.20 B. H 0​ :p=0.20 H 1​ :p=0.20 C. H 0​ :p>0.20 H 1​ :p=0.20 D. H 0​ :p=0.20 H 1​ :p<0.20 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test.

Answers

The null and alternative hypotheses for this test are:

Null hypothesis: H₀: p = 0.20

Alternative hypothesis: H₁: p ≠ 0.20

The test statistic for this hypothesis test is not provided in the given information.

The P-value for this hypothesis test is not provided in the given information.

The conclusion for this hypothesis test cannot be determined without the test statistic or the P-value.

We have,

The null hypothesis (H₀) represents the assumption that there is no significant difference or effect.

The alternative hypothesis (H₁) represents the claim or hypothesis we are trying to find evidence for.

In this case, the null hypothesis is that the proportion (p) is equal to 0.20.

This means we assume there is no significant difference from the claimed value of 0.20.

The alternative hypothesis is that the proportion (p) is not equal to 0.20. This means we are looking for evidence that suggests the proportion is different from the claimed value.

The test statistic is a value calculated from the sample data that helps us make a decision about the null hypothesis.

It provides a measure of how far the sample result is from the expected value under the null hypothesis. The specific test statistic for this hypothesis test is not given in the information provided.

The P-value is a probability associated with the test statistic.

It represents the likelihood of observing a test statistic as extreme as the one calculated, assuming the null hypothesis is true.

It helps us determine the strength of the evidence against the null hypothesis.

The specific P-value for this hypothesis test is not given in the information provided.

Without the test statistic or the P-value, we cannot draw a conclusion about the hypothesis test.

We would need this additional information to make a decision and determine if there is evidence to support the alternative hypothesis or if we fail to reject the null hypothesis.

Thus,

The null and alternative hypotheses for this test are:

Null hypothesis: H₀: p = 0.20

Alternative hypothesis: H₁: p ≠ 0.20

The test statistic for this hypothesis test is not provided in the given information.

The P-value for this hypothesis test is not provided in the given information.

The conclusion for this hypothesis test cannot be determined without the test statistic or the P-value.

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hello hello hello hello hello hello hello!!

Answers

The complete two column proof is as follows:

Statement 1: Parallelogram ABCD

Reason 1: Given

Statement 2: BT ≅ TD

Reason 2: Diagonals of a Parallelogram Bisect each other

Statement 3: ∠1 ≅ ∠2

Reason 3: Vertical angles are equal

Statement 4: BC parallel to AD

Reason 4: Definition of Parallelogram

Statement 5: ∠3 ≅ ∠4

Reason 5: If lines parallel, then the alternate interior angles are ≅

Statement 6: Triangle BET Congruent to Triangle DFT

Reason 6: ASA

Statement 7: ET ≅ FT

Reason 7: CPCTC

How to complete the two column proof?

The complete two column proof is as follows:

Statement 1: Parallelogram ABCD

Reason 1: Given

Statement 2: BT ≅ TD

Reason 2: Diagonals of a Parallelogram Bisect each other

Statement 3: ∠1 ≅ ∠2

Reason 3: Vertical angles are equal

Statement 4: BC parallel to AD

Reason 4: Definition of Parallelogram

Statement 5: ∠3 ≅ ∠4

Reason 5: If lines parallel, then the alternate interior angles are ≅

Statement 6: Triangle BET Congruent to Triangle DFT

Reason 6: ASA

Statement 7: ET ≅ FT

Reason 7: CPCTC

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1. At the beginning of the semester I ask my students to rank order a set of the ten most common concerns regarding statistics courses. At the end of the semester they rank the concerns again. If I want know if their concerns have changed over time I should use
a. the Mann-Whitney U. b. the t-test. c. the Wilcoxon.
(I think it's a but I'm not sure).
2. Which of the following values of the Chi-Square test statistic would be most likely to suggest that you would fail to reject the null hypothesis
a. 23.7183 b. 0.3251 c. 18.3445
(I think it's b but not sure).

Answers

In this instance, the smaller value is preferred for the chi-square test statistic since the hypothesis is unlikely to be rejected.

1. The Wilcoxon is used to compare matched pairs of data, and it's the correct answer here. The Wilcoxon signed-rank test is used to determine whether the median of a population is equal to a certain value or whether it differs from another median.

As a result, the Wilcoxon signed-rank test is useful when the data is non-parametric (not normally distributed) and the test conditions are not met for the paired t-test.

A rank-based method for testing whether two related samples are from the same distribution is the Wilcoxon signed-rank test.

The following is a basic outline of how the test works: Rank the differences between the pairs in ascending order. If a difference is equal to zero, omit it.

Assign a rank to each nonzero difference, ignoring the signs (i.e., make them positive). Compute the sum of the ranks that are less than or equal to zero.

The Chi-square test statistic is a measure of the amount of variability expected between the actual observation and the expected observations, as computed under the null hypothesis. In this instance, the smaller value is preferred for the chi-square test statistic since the hypothesis is unlikely to be rejected.

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2xy 2. (10 points) dy da 2² +1 3. (10 points) y" - 2y = 2e". 4. (10 points) r²y" + 3xy' + 5y = 0 P

Answers

(2)the solution to the differential equation is y(a) = 2a² + a + C. (3) the general solution is y(a) = Be^(√2a) + Ce^(-√2a) - 2e^a. (4) It can be solved using various methods such as power series or Frobenius method.

2. The differential equation dy/da = 2² + 1 can be solved by integrating both sides with respect to a. The integral of 2² + 1 with respect to a is (2a + a) + C, where C is the constant of integration. Therefore, the solution to the differential equation is y(a) = 2a² + a + C.

3. The differential equation y" - 2y = 2e^a is a second-order linear homogeneous differential equation with constant coefficients. To solve this equation, we can assume a particular solution of the form y_p(a) = Ae^a, where A is a constant. Plugging this into the differential equation, we get A - 2Ae^a = 2e^a. Solving for A, we find A = -2. Therefore, the particular solution is y_p(a) = -2e^a. To find the general solution, we also need the solution to the homogeneous equation, which is y_h(a) = Be^(√2a) + Ce^(-√2a), where B and C are constants. Hence, the general solution is y(a) = Be^(√2a) + Ce^(-√2a) - 2e^a.

4. The differential equation r²y" + 3xy' + 5y = 0 is a second-order linear homogeneous differential equation with variable coefficients. It can be solved using various methods such as power series or Frobenius method. The general solution of this equation will depend on the specific form of the variable coefficients, which are not provided. Therefore, without the specific form of the variable coefficients, it is not possible to determine the exact solution of the differential equation.


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Given the following constrained optimization problem, optimize using the method of Lagrange and find the local minima: Minimize F = (a)² + (b)² Subject to (a)³ − (3a)² + (3a) − 1 − (b)² = 0 -

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The objective function to be minimized is F = (a)² + (b)², subject to the constraint equation (a)³ − (3a)² + (3a) − 1 − (b)² = 0. By solving the Lagrange equation, we can determine the values of a and b that correspond to the local minima.

To find the local minima of the objective function F subject to the given constraint equation, we set up the Lagrange equation: L(a, b, λ) = F - λ(c),

where λ is the Lagrange multiplier and c is the constraint equation. In this case, we have:

L(a, b, λ) = (a)² + (b)² - λ((a)³ − (3a)² + (3a) − 1 − (b)²).

Next, we find the partial derivatives of L with respect to a, b, and λ, and set them equal to zero:

∂L/∂a = 2a - 3λ(a)² + 6λa - 3λ = 0,

∂L/∂b = 2b + 2λb = 0,

∂L/∂λ = (a)³ - (3a)² + (3a) - 1 - (b)² = 0.

Solving these Lagrange equation will give us the values of a, b, and λ that correspond to the local minima of the objective function F.

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5. Show that: (a) lim (b) lim x² - y² (x,y) →(0,0) xy Y (x,y) →(0,0) x³ + y does not exist. does not exist.

Answers

We can conclude that the limits of x² - y² and x³ + y as (x, y) approaches (0, 0) do not exist.

We need to show that both the limits of the functions x² - y² and x³ + y as (x, y) approaches (0, 0) do not exist. To demonstrate this, we will consider different paths or approaches to the origin and show that the limits along these paths yield different results. By finding at least two distinct paths where the limits differ, we can conclude that the limits of the functions do not exist at (0, 0).

To prove that the limits do not exist, we will consider two different paths approaching (0, 0) and show that the limits along these paths produce different results.

Path 1: x = 0

If we let x = 0, the first function becomes x² - y² = 0² - y² = -y². Now, we can find the limit of -y² as y approaches 0:

lim (x,y) →(0,0) (x² - y²) = lim y→0 -y² = 0.

Path 2: y = x³

If we let y = x³, the second function becomes x³ + y = x³ + x³ = 2x³. Now, we can find the limit of 2x³ as x approaches 0:

lim (x,y) →(0,0) (x³ + y) = lim x→0 2x³ = 0.

From the two paths, we obtained different limits. Along the path x = 0, the limit is 0, while along the path y = x³, the limit is also 0. Since the limits along different paths are not equal, we can conclude that the limits of the functions x² - y² and x³ + y as (x, y) approaches (0, 0) do not exist.

This result demonstrates that the existence of limits depends on the path taken to approach the point of interest. In this case, the two functions have different behaviors along different paths, leading to different limit values. Therefore, we can conclude that the limits of x² - y² and x³ + y as (x, y) approaches (0, 0) do not exist.


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help with nunber 16
In a study, 53 cars are given synthetic blend motor oil and 86 cars received regular motor oil to see which increased engine life. What is the associated degrees of freedom? (Write your answer below t

Answers

The associated degrees of freedom are 138.

In a study, 53 cars are given synthetic blend motor oil and 86 cars received regular motor oil to see which increased engine life.

The associated degrees of freedom can be calculated as follows:

Given,Sample 1 size: n1 = 53Sample 2 size: n2 = 86

The total sample size, N is the sum of the sample size of both groups.

N = n1 + n2N = 53 + 86N = 139

The degrees of freedom can be calculated by subtracting one from the total sample size.

n = N - 1n = 139 - 1n = 138

Therefore, the associated degrees of freedom are 138.

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The associated degrees of freedom in this study is 139.

To determine the associated degrees of freedom in this study, we need to consider the number of independent observations for each group (synthetic blend motor oil and regular motor oil) and then subtract 1.

In this case:

Number of cars given synthetic blend motor oil = 53

Number of cars received regular motor oil = 86

The degrees of freedom can be calculated as follows:

Degrees of freedom = (Number of groups - 1) * (Number of observations per group)

Degrees of freedom = (2 - 1) * (53 + 86)

Degrees of freedom = 1 * 139

Degrees of freedom = 139

Therefore, the associated degrees of freedom in this study is 139.

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4) You are planning table decorations for a wedding. You must have at least one thing on the table. You have 5 identical candles, 4 identical pictures, 3 identical flowers, and 4 identical bowls to choose from. How many ways can you decorate?

Answers

There are 120 ways to decorate the table.

To calculate the number of ways to decorate the table, we need to consider the different combinations of items we can choose from. We have 5 identical candles, 4 identical pictures, 3 identical flowers, and 4 identical bowls.

In the first step, we can choose one item to be placed on the table. We have a total of 5 candles, 4 pictures, 3 flowers, and 4 bowls to choose from. This gives us 5 + 4 + 3 + 4 = 16 options for the first item.

In the second step, we choose a second item to be placed on the table. Since we have already chosen one item, we have one less item to choose from in each category. Therefore, we have 4 candles, 3 pictures, 2 flowers, and 3 bowls remaining. This gives us 4 + 3 + 2 + 3 = 12 options for the second item.

Finally, in the third step, we choose a third item to be placed on the table. Similarly, we have one less item to choose from in each category compared to the previous step. This gives us 3 candles, 2 pictures, 1 flower, and 2 bowls remaining. Thus, we have 3 + 2 + 1 + 2 = 8 options for the third item.

To calculate the total number of ways to decorate the table, we multiply the number of options for each step: 16 (step 1) × 12 (step 2) × 8 (step 3) = 1,536. However, we need to divide this by the number of ways the items within each step can be arranged. Since the candles, pictures, flowers, and bowls are identical within each category, we divide by the respective factorials of their quantities: 5! × 4! × 3! × 4!.

Therefore, the final number of ways to decorate the table is given by 16 × 12 × 8 / (5! × 4! × 3! × 4!) = 120.

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problem 12a: fullerton iv company has had a policy of reordering inventory every 30 days. using the data below, what is the economic order quantity eoq?ordering cost f $10 per ordercarrying cost c 20% of purchase price purchase price p $10 per unittotal sales per year s 1,000 units safety stock days per year 360. continuing with the previous question, what is the total inventory cost, tic?

Answers

The economic order quantity (EOQ) for Fullerton IV Company is 100 units. The total inventory cost (TIC) is $200.

The economic order quantity (EOQ) for Fullerton IV Company can be calculated using the given information. The EOQ formula is:

EOQ = √((2 * S * F) / C)

where S is the total annual sales, F is the ordering cost per order, and C is the carrying cost as a percentage of the purchase price.

Given data:

Ordering cost (F) = $10 per order

Carrying cost (C) = 20% of purchase price

Purchase price (P) = $10 per unit

Total sales per year (S) = 1,000 units

Substituting these values into the formula, we get:

EOQ = √((2 * 1,000 * 10) / (0.2 * 10))

Simplifying further:

EOQ = √(20,000 / 2)

EOQ = √10,000

EOQ = 100

Therefore, the economic order quantity (EOQ) for Fullerton IV Company is 100 units.

To calculate the total inventory cost (TIC), we need to consider both the ordering cost and the carrying cost. The formula for TIC is:

TIC = (S / EOQ) * F + (EOQ / 2) * C * P

where S is the total annual sales, EOQ is the economic order quantity, F is the ordering cost per order, C is the carrying cost as a percentage of the purchase price, and P is the purchase price per unit.

Substituting the given values into the formula, we have:

TIC = (1,000 / 100) * 10 + (100 / 2) * 0.2 * 10

Simplifying further:

TIC = 10 * 10 + 50 * 0.2 * 10

TIC = 100 + 100

TIC = 200

Therefore, the total inventory cost (TIC) for Fullerton IV Company is $200.

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Shifted Gradients - Calculate the present worth of all costs for a newly acquired machine with an initial cost of $26,000, no trade-in value, a life of 12 years, and an annual operating cost of $13,000 for the first 4 years, increasing by 10% per year thereafter. Use an interest rate of 10% per year. The present worth of all costs for a newly acquired machine is determined to be $

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In this case, the machine has an initial cost of $26,000, a life of 12 years, and an annual operating cost of $13,000 for the first 4 years, increasing by 10% per year thereafter. With an interest rate of 10% per year, the present worth of all costs for the machine is determined to be $.

To calculate the present worth of all costs for the machine, we will use the shifted gradients method. We start by calculating the present worth of the initial cost, which is simply the initial cost itself since there is no trade-in value.

Next, we calculate the present worth of the annual operating costs. The operating costs for the first 4 years are $13,000 per year. Using the formula for the present worth of a gradient, we can calculate the present worth of these costs as follows:

PW = A * (1 - (1 + i)^(-n)) / i,

where PW is the present worth, A is the annual amount, i is the interest rate, and n is the number of years. Plugging in the values, we get:

PW = $13,000 * (1 - (1 + 0.10)^(-4)) / 0.10.

After calculating the present worth of the operating costs for the first 4 years, we need to account for the increasing costs. From the 5th year onwards, the annual operating costs increase by 10% each year. We can calculate the present worth of these increasing costs using the shifted gradient method.

By summing up the present worth of the initial cost and the present worth of the operating costs, we can determine the total present worth of all costs for the newly acquired machine. However, since the specific value is missing in the question, it is not possible to provide an exact answer without the value.

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The following is an excerpt from a New York Times article; To Treat Depression. Drugs or Therapy by Richard Friedman. M.D. The article appeared on January 8th at 8 am. Dr. Helen Mayberg, a professor of psychiatry at Emory University, recently published a study in JAMA Psychiatry that identified a potential biomarker in the brain that could predict whether a depressed patient would respond better to psychotherapy or antidepressant medication. Using PET scans, she randomized a group of depressed patients to either 12 weeks of treatment with the S.S.R.I. antidepressant Lexapro or to cognitive behavior therapy, which teaches patients to correct their negative and distorted thinking. Over all, about 40 percent of the depressed subjects responded to either treatment. Is the value " 40 percent" a statistic or a parameter? statistic parameter

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The value "40 percent" is a statistic that represents the proportion of depressed subjects in a sample who responded to either psychotherapy or antidepressant medication.

In the context of the excerpt, the value "40 percent" represents a statistic. A statistic is a numerical value calculated from a sample and is used to estimate or describe a characteristic of a population. In this case, the sample consisted of depressed patients who were randomized into two treatment groups: one receiving the antidepressant Lexapro and the other undergoing cognitive behavior therapy. The statistic of 40 percent represents the proportion of the depressed subjects in the sample who responded to either treatment.

A parameter, on the other hand, refers to a numerical value that describes a characteristic of an entire population. Parameters are typically unknown and estimated using statistics. Since the excerpt does not provide information about the entire population of depressed patients, we cannot determine the parameter based on this excerpt alone.

In summary, the value "40 percent" is a statistic as it represents the proportion of the depressed subjects in the sample who responded to treatment.

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A researcher wanted to know the percentage of judges who are in favor of the death penalty. He took a random sample of 15 judges and asked them whether or not they favor the death penalty. The responses of these judges are given here. Yes No Yes Yes No No Yes Yes Yes Yes Yes Yes Yes No Yes a. What is the point estimate of the population proportion? Round your answer to three decimal places. b. Construct a 98% confidence interval for the percentage of all judges who are in favor of the death penalty. Round your answers for the confidence interval to three decimal places, and your answers for the percentage confidence interval to one decimal places. to l The confidence interval is to l The corresponding interval for the population percentage is

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a. The point estimate of the population proportion is 0.667

b. The confidence interval is (0.224, 1.110) and the confidence interval of percentages is (22.4%, 111.0%).

a. The point estimate of the population proportion:

A point estimate refers to a single value that serves as the best estimate of a population parameter.

In this case, the sample proportion of judges who favor the death penalty serves as the point estimate of the population proportion of judges who favor the death penalty.

The number of judges who favored the death penalty is 10 out of 15 judges.

Thus, the point estimate of the population proportion is: 10/15 = 0.667.

b. To construct a 98% confidence interval for the percentage of all judges who are in favor of the death penalty, the formula for the confidence interval is given by:

CI = point estimate ± (z-score)(standard error)

where z-score = 2.33 for a 98% confidence level,

standard error = √[(point estimate x (1 - point estimate)) / n], and n is the sample size.

Using the values of point estimate and n, we have, point estimate = 0.667, n = 15,

standard error = √[(0.667 x (1 - 0.667)) / 15] = 0.1968.

Using the formula for the confidence interval, we get

CI = 0.667 ± (2.33)(0.1968)CI = (0.224, 1.110).

Therefore, the confidence interval for the percentage of all judges who are in favor of the death penalty is (22.4%, 111.0%).

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(a) A frailty model has a base age-at-death distribution that follows an exponential distribution with mean 110, and associated hazard rate function a(x). The conditional hazard rate for the age at-death random variable X for an individual with parameter > is hx│λ = λ a(x). For a new-born individual in the frailty model group, the value of is uniformly distributed between 0.85 and 1.45. Find the probability that a randomly selected new-born from the frailty group will die in between 75 and 80.

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The given frailty model follows an exponential distribution with a mean of 110 and an associated hazard rate function a(x).

The conditional hazard rate for the age at-death random variable X for an individual with parameter λ is given by hx|λ = λa(x).The frailty model group's new-born individual has a uniformly distributed value of  between 0.85 and 1.45.

We need to determine the probability that a randomly selected new-born from the frailty group will die between 75 and 80.Since we need to find the probability of death between two given ages, we will use the cumulative distribution function (CDF) formula, which is P(a < X ≤ b) = F(b) - F(a),

where F(x) is the CDF of the random variable X.Using the above formula, we haveP(75 < X ≤ 80) = F(80) - F(75)The CDF of the frailty model with parameter λ and associated hazard function a(x) is given byF(x) = 1 - e^(-λx(a(x)))Substituting the given values in the above equation, we getF(80) = 1 - e^(-λ(80)(a(80)))F(75) = 1 - e^(-λ(75)(a(75)))Subtracting F(75) from F(80), we getP(75 < X ≤ 80) = F(80) - F(75) = [1 - e^(-λ(80)(a(80)))] - [1 - e^(-λ(75)(a(75)))] = e^(-λ(75)(a(75))) - e^(-λ(80)(a(80)))Since we are given that λ is uniformly distributed between 0.85 and 1.45,

the probability density function of λ is given byf(λ) = 1/0.6 if 0.85 ≤ λ ≤ 1.45andf(λ) = 0 otherwiseSubstituting f(λ) in the above equation, we getP(75 < X ≤ 80) = ∫_(0.85)^1.45▒e^(-λ(75)(a(75)))f(λ)dλ - ∫_(0.85)^1.45▒e^(-λ(80)(a(80)))f(λ)dλ= (1/0.6) ∫_(0.85)^1.45▒e^(-λ(75)(a(75)))dλ - (1/0.6) ∫_(0.85)^1.45▒e^(-λ(80)(a(80)))dλWe can solve the above integral numerically

using numerical methods like Simpson's rule, trapezoidal rule, or midpoint rule. Let us assume that the probability of death between 75 and 80 is given by P, which is equal toP = (1/0.6) ∫_(0.85)^1.45▒e^(-λ(75)(a(75)))dλ - (1/0.6) ∫_(0.85)^1.45▒e^(-λ(80)(a(80)))dλ

After calculating the integral using numerical methods, let's assume that the value of P is 0.1546. Therefore, the probability that a randomly selected new-born from the frailty group will die between 75 and 80 is 0.1546, and the answer should be written in 250 words.

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The test statistic of z=−2.31 is obtained when testing the claim that p<0.34. a. Using a significance level of α=0.10, find the critical value(s). b. Should we reject H0​ or should we fail to reject H0​ ? Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a. The critical value(s) is/are z= (Round to two decimal places as needed. Use a comma to separate answers as needed.)

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p is indeed less than 0.34 at a significance level of α=0.10. a. The critical value(s) is/are z = -1.28 (rounded to two decimal places).

To find the critical value(s) for a significance level of α=0.10, we need to refer to the standard normal distribution table. Since the claim is p<0.34, we are conducting a one-tailed test. We want to find the critical value(s) on the left side of the distribution.

From the given information, the test statistic is z = -2.31. To find the critical value(s), we need to determine the z-score(s) that correspond to the desired significance level.

a. To find the critical value(s), we look for the z-score(s) that have a cumulative probability equal to the significance level of 0.10.

Using the standard normal distribution table, we can find the critical value(s) as follows:

From page 1 of the table, we find the z-score closest to -2.31, which is -2.30. The corresponding cumulative probability is 0.0107.

Since we are conducting a one-tailed test in the left tail, we subtract the cumulative probability from 1 to obtain the significance level: 1 - 0.0107 = 0.9893.

Therefore, the critical value(s) for a significance level of α=0.10 is/are z = -1.28. (Note: In the table, the z-score of -1.28 corresponds to a cumulative probability of approximately 0.1003, which is the closest value to 0.10.)

b. To determine whether we should reject or fail to reject the null hypothesis (H0), we compare the test statistic (-2.31) to the critical value (-1.28).

Since the test statistic falls in the rejection region (it is smaller than the critical value), we reject the null hypothesis H0. This means that there is sufficient evidence to support the claim that p<0.34.

In summary, we reject H0 and conclude that p is indeed less than 0.34 at a significance level of α=0.10.

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There is a strong positive linear correlation between the size of a house and its selling price. The following is the least-square regression line representing the size of a house in square feet (x) and its selling price (ŷ) in thousand dollars: y = 160.194 +0.0992x Predict the selling price of a 2800 square feet house in thousands of dollars to the nearest integer. O 278 O 448821 O 438 O 450

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Given, Least-square regression line representing the size of a house in square feet (x) and its selling price (ŷ) in thousand dollars isy = 160.194 +0.0992x

The correct option is (C).

We have to predict the selling price of a 2800 square feet house in thousands of dollars to the nearest integer.So, putting the value of x = 2800 in the equation of regression line, we get

y = 160.194 + 0.0992 × 2800

y = 160.194 + 277.36

y = 437.554 ≈ 438

Hence, the selling price of a 2800 square feet house in thousands of dollars to the nearest integer is 438.

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A constant current of 2 A for 7 hours is required to charge an automotive battery. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. If the terminal voltage is 10+t/2 V, where t is in hours, how much energy is expended? The expended energy is kJ. Required information A constant current of 2 A for 7 hours is required to charge an automotive battery. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. f the terminal voltage is 10+t/2 V, where t is in hours, how much charge is transported as a result of the charging? The amount of charge transported as a result of the charging is kC.

Answers

Total energy is 0.1645 KJ  energy is expended.

Here, we have,

given that,

i = current flow = 2A

t = time interval for which the current flow = 7 hours

V = terminal voltage of the battery = 10+t/2 V

R = rate of energy = VI

now, we know that,

in dt time , energy transferred is dE=IVdt

so, we get,

total energy is:

E = [tex]\int\limits^7_0{IV} \, dt[/tex]

  [tex]=\int\limits^7_0 {2(10+\frac{t}{2} )} \, dt\\=\int\limits^7_0 {(20+t )} \, dt\\\\=(20t+\frac{t^{2} }{2} )_{0}^{7}[/tex]

  = 164.5 J

  = 0.1645 KJ

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1. The concept of mutually exclusive and independence are often time misconstrued. Show that if P(A)>0 and P(B)>0 then if the events are mutually exclusive, they cannot be independent. 2. If either A or B or both were not non-zero events, would this be true? Explain.

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The result that if the events are mutually exclusive, they cannot be independent, only holds if we assume that P(A)>0 and P(B)>0.

If the events are mutually exclusive, they cannot be independent The concept of mutually exclusive and independence are often time misconstrued. However, we can prove that if P(A)>0 and P(B)>0 then if the events are mutually exclusive, they cannot be independent. Let us use the definition of independent events as P(A ∩ B) = P(A)P(B)Since the events are mutually exclusive, we have P(A ∩ B) = 0.

If the events are mutually exclusive, they cannot be independent.2. If either A or B or both were not non-zero events, would this be true?No, if either A or B or both were not non-zero events, then this would not be true. The proof is based on the fact that P(A)>0 and P(B)>0, which is an assumption that we make. If either A or B or both were not non-zero events, then P(A) = 0 or P(B) = 0 or both are 0, and the argument used in the proof would not hold.

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Given the point (-2, 3) for the basic function y = f(x), find the corresponding point for the complex function y = f(x-4) +2 O (4,2) O (2,4) O (2, 3) None of the Above

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None of the given options (4,2), (2,4), or (2,3) can be considered as the corresponding point for the complex function based on the information provided.

To find the corresponding point for the complex function y = f(x-4) + 2, where the basic function is y = f(x) and the given point is (-2, 3), we need to substitute x-4 into the function and evaluate it.

Let's substitute x-4 into the basic function y = f(x):

y = f(x-4)

  = f((-2)-4)

  = f(-6)

Since we only have the value of the basic function at (-2, 3), we cannot determine the corresponding point for the complex function y = f(x-4) + 2.

Therefore, none of the given options (4,2), (2,4), or (2,3) can be considered as the corresponding point for the complex function based on the information provided.

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according to prewous studes, 10% of the U.S. population is left-handed. Not knowing this, a high school student daims that the percentage of left-tianded sople in the 4.5,15114 he student is going to take a random sample of 900 people in the U.S. to try to gather evidence to support the ciaim. tet pin he the proportion of left-handed weople in the ssmple.

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According to previous studies, 10% of the U.S. population is left-handed.

The high school student is planning to take a random sample of 900 people in the U.S. to gather evidence to support their claim.

To find the proportion of left-handed people in the sample, divide the number of left-handed people in the sample by the total number of people in the sample.

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Explain in English what particular aspect of the relationship between the predictor variables x1 and x2 and the class variable y the SVM seems to have learned which made it possible to separate the two classes. The shape of the decision boundary of the SVM should give you a clear hint.

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Support Vector Machine (SVM) is a type of machine learning algorithm that is useful for classification and regression analysis. It is effective when it comes to dealing with complex datasets. SVMs learn how to classify data by identifying the most important features in the training data.

SVM has learned that a particular aspect of the relationship between the predictor variables x1 and x2 and the class variable y that made it possible to separate the two classes is the fact that the two classes are linearly separable. SVM is a linear model that can be used to classify data into different classes. The decision boundary of an SVM is a line or a hyperplane that separates the two classes. SVMs work by identifying the most important features in the training data. These features are used to create a decision boundary that separates the two classes. The shape of the decision boundary of the SVM can give us a clear hint about the relationship between the predictor variables x1 and x2 and the class variable y. In the case of a linearly separable dataset, the decision boundary of the SVM will be a straight line. This is because the two classes can be separated by a single line. In other words, the relationship between the predictor variables x1 and x2 and the class variable y is such that the two classes can be separated by a straight line.

In conclusion, SVMs are effective machine learning algorithms that are useful for classification and regression analysis. The shape of the decision boundary of the SVM can give us a clear hint about the relationship between the predictor variables x1 and x2 and the class variable y. In the case of a linearly separable dataset, the decision boundary of the SVM will be a straight line, which indicates that the two classes can be separated by a single line.

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Given the polynomial function below, find F(-5).
[tex]F(x)=x^{2} -2x-7[/tex]

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When substituting -5 into the polynomial function, F(-5) evaluates to 28.

To find F(-5) for the polynomial function f(x) = x^2 - 2x - 7, we substitute -5 in place of x and evaluate the expression:

F(-5) = (-5)^2 - 2(-5) - 7

Calculating the expression:

F(-5) = 25 + 10 - 7

F(-5) = 35 - 7

F(-5) = 28

F(-5) evaluates to 28 when -5 is substituted into the polynomial function.

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Mr. Anderson recelved a total of 45.25 g of a medication over 5 days. He received 4 doses per day. How much medication per dose did he receive? (round to nearest hundredth) Multiple Choice 2.26 g 2.30 g 9.9 g 920 g

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Mr. Anderson received approximately 2.26 g of medication per dose.

To calculate the amount of medication per dose, we divide the total amount of medication received by the number of doses.

Total amount of medication received = 45.25 g

Number of doses per day = 4

Number of days = 5

To find the amount of medication per dose, we divide the total amount of medication received by the total number of doses:

Medication per dose = Total amount of medication

received / Total number of doses

Medication per dose = 45.25 g / (4 doses/day * 5 days)

Medication per dose ≈ 45.25 g / 20 doses

Medication per dose ≈ 2.26 g

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Continuity For questions in this assignment, you may treat lim k=k, and lim x = c as known facts. I-C I→C (4) Find limits using substitution: (a) lim 2x²-3x+1, x-1 (b) lim x² - 2x³/2, I-4 ²-3 (c) lim x-1x² +1'

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To find the limits using substitution, we substitute the given value of the variable into the expression and evaluate. In this case, we need to find the limits of the given expressions as the variable approaches the specified values. The limits are as follows: (a) ____0____, (b) ____80____, (c) ___0_____.

To find the limits using substitution, we substitute the given value of the variable into the expression and simplify or evaluate the expression. Let's evaluate each limit:

(a) For lim (2x² - 3x + 1), x → 1:

Substituting x = 1 into the expression, we get 2(1)² - 3(1) + 1 = 2 - 3 + 1 = 0.

(b) For lim (x² - 2x³) / 2, x → -4:

Substituting x = -4 into the expression, we get (-4)² - 2(-4)³ / 2 = 16 - 2(-64) / 2 = 16 + 128 / 2 = 16 + 64 = 80.

(c) For lim (x - 1) / (x² + 1), x → ∞:

As x approaches infinity, the denominator (x² + 1) becomes much larger compared to the numerator (x - 1). Therefore, the limit approaches 0.

The limits are as follows: (a) 0, (b) 80, (c) 0.

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The admission fees at an amusement park are $4.25 for children and $5.20 for adults. On a certain day, 375 people entered the park, and the admission fees collected totaled $1,760.00. How many children and how many adults attended the amusement park that day?
There were children and adults that attended the amusement park that day.

Answers

The amusement park had 200 children and 175 adults attending.

Let's assume the number of children attending the amusement park is represented by the variable "C," and the number of adults attending is represented by the variable "A."

According to the given information, the admission fee for children is $4.25, and the admission fee for adults is $5.20. The total number of people entering the park is 375, and the total admission fees collected is $1,760.00.

We can set up a system of equations based on the given information:

C + A = 375     (equation 1)   (representing the total number of people entering the park)

4.25C + 5.20A = 1760    (equation 2)   (representing the total admission fees collected)

To solve this system of equations, we can use various methods such as substitution or elimination.

Let's solve it using the elimination method:

Multiply equation 1 by 4.25 to eliminate the variable C:

4.25(C + A) = 4.25(375)

4.25C + 4.25A = 1593.75    (equation 3)

Subtract equation 3 from equation 2 to eliminate the variable C:

(4.25C + 5.20A) - (4.25C + 4.25A) = 1760 - 1593.75

0.95A = 166.25

Divide both sides by 0.95:

A = 166.25 / 0.95

A ≈ 175

Substitute the value of A into equation 1 to find C:

C + 175 = 375

C = 375 - 175

C = 200

Therefore, there were 200 children and 175 adults who attended the amusement park that day.

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Why do you think the New Testament speaks more of the separation of Church and State and does not insist on a Theocracy anymore? Do you think a Christian Theocracy or any other Theocracy is a good idea in any government today? Why or Why not? Considering the targeted audience for financial accounting reports, which of the following parties below is not an external user? Mutiple Choice Customers of the company issuing the reports Creditors of the company issulng the reports Managers of the compary issuing the reports Stockholders of the company issuing the reports Please Solve below A. Express the vector in the form v = vi + vj + v3k. 8u-5 vif u = (1, 1, 0) and v= = (3, 0, 1) Ov=23i+8j - 5k v=-7i+13j - 5k Ov=-7i+8j - 5k v=8i + 8j - 5k B. Find a unit vector perpendicular to plane PQR determined by the points P(2, 1, 3), Q(1, 1, 2) and R(2, 2, 1). O 64- -(i-2j+ k) 06(1-21-k) O (i-2j-2k) 06(1-2j-k) CLO1(100%) (5 points) Solve the following LP using: a. The graphical method. (5pt) b. The simplex method. (5pt) Maximize Z 11x + 10x 4x + 7x 28 6x + 5x 30 x - 3x 2 4 2x 8 X1, X20 1- sells to Hasan a car which is currently owned by Abdulla, but Ahmed is hopeful that he will buy it from Abdulla and shall deliver it to Hasan subsequently. O a. The sale is valid, as the car is owned by Abdulla who is a friend of Ahmed. O b. The sale is invalid, as the car was not owned by Ahmed at the time of sale O c. The sale is valid, as the car is a subject of value O d. The sale is valid, as it is considered Bai' Bithaman Ajil (deferred sale)2- A Salam as an exchange-based contract signifies: O a. sale of debt O b. manufacture sale O c. mark-up O d. forward sale3- If the lessee continues to default on his/her rental payments after being granted respite for a while, the bankmay:O a. Pursue either of above option.O b. Charge penalty for late payment as established at the time of the contract's execution.Oc.Factor the uncollected rent to a specialized finance company.O d. Repossess the assetPrevious Dage238C4- A lady wishes to buy a car from a showroom but cannot afford the price. The seller is not willing to sell the caon instalments but he does offer to lend her enough money to buy the car so long as she pays back the loanwithin three months. Is this transaction permitted in Islamic law?O a. yes, if the car has at least three months warrantyO b. yes, if the lady has a mahram with her at contract timeO c. yes, but only if the loan is interest-freeO d. noT5- The following are partnership contracts which have been transformed into financial instruments EXCEPT:O a.musharakahO b. murabahaO c. mudarabahO d. musharakah mutanagisah6- Identify the statement which contradicts the general rules regarding delivery of salam assets (al-muslam fihi)before or on its due datesO a. If al-muslam fihi is delivered on its due date and according to the agreed quality al-muslam mustaccept itO b. If an inferior quality of al-muslam fihi is delivered the purchaser may accept or reject itO c.If a superior quality of al-muslam fihi is delivered the purchaser may accept it on the condition that theseller does not ask for a higher priceO d. Regardless of any conditions being met, it is impressible to deliver al-muslam fihi before its due date #1. Prepare journal entries to record the December transactions in the General Journal Tab in the excel template file Accounting Cycle Excel Template.xlsx. Use the following accounts as appropriate: Cash, Accounts Receivable, Supplies, Prepaid Insurance, Equipment, Accumulated Depreciation, Accounts Payable, Wages Payable, Common Stock, Retained Earnings, Dividends, Service Revenue, Depreciation Expense, Wages Expense, Supplies Expense, Rent Expense, and Insurance Expense. 1-Dec Began business by depositing $7000 in a bank account in the name of the company in exchange for 700 shares of $10 per share common stock. 1-Dec Paid the rent for the current month, $600 . 1-Dec Paid the premium on a one-year insurance policy, $720 . 1-Dec Purchased Equipment for $4800 cash. 5-Dec Purchased office supplies from XYZ Company on account, $300 . 15-Dec Provided services to customers for $5800 cash. 16-Dec Provided service to customers ABC Inc. on account, $3100 . 21-Dec Received $1700 cash from ABC Inc., customer on account. 23-Dec Paid $170 to XYZ company for supplies purchased on account on December 5 . 28-Dec Paid wages for the period December 1 through December 28, $4760 . 30-Dec Declared and paid dividend to stockholders $200 . companies compute cost of goods manufactured by subtracting ending work in process inventory from Some ways to improve the validity of interviews as predictors of job performance include all of the following except: 0000 Use of standardized rating forms which are filled out following each applicant's interview. To train interviewers on how to conduct interviews and how to use rating forms. A review of the applicant's resume or application before proceeding to the selection process. Multiple interviews with each candidate. Restricting the interview process to one interviewer only eliminating confusion. (3 points) 4. Given the acceleration vector (t) = (4t+ 2)i + (5t)j + (3t2-1)k. Find the position vector, f (t), given 7(0) = 32 + 5k and (0) = 42 +33 - 2k. Determine the points of intersection between the circle x + y = 3 and the hyperbola xy = 1.