The given program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented. The program fails and throws an exception if the second input on a line is a string rather than an integer. At FIXME in the code, add try and except blocks to catch the ValueError exception and output 0 for the age.




Ex: If the input is:


Lee 18

Lua 21

Mary Beth 19

Stu 33

-1

then the output is:


Lee 19

Lua 22

Mary 0

Stu 34



# Split input into 2 parts: name and age
parts = input().split()
name = parts[0]
while name != '-1':
# FIXME: The following line will throw ValueError exception.
# Insert try/except blocks to catch the exception.
try:
age = int (parts [ 1 ]) + 1
print('{ }{ }'.format(name, age))
# Get next line
parts = input().split()
name = parts[0]
except ValueError:
print ('Invalid value!')
# Get next line
parts = input().split()
name = parts[0]

Using the knowledge of computational language in python it is possible to write a code that program reads a list of single-word first names and ages (ending with -1), and outputs that list with the age incremented.

# Split input into 2 parts: name and age

parts = input().split()

name = parts[0]

while name != '-1':

   # Insert try/except blocks to catch the exception.

   try:

       age = int(parts[1]) + 1

       # printing name and age

       print('{} {}'.format(name, age))

   except ValueError:

       # printing name and age as 0

       print('{} {}'.format(name, 0))

   # Get next line

   parts = input().split()

   name = parts[0]

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