the graph of y=f(x) is shown below. find all values of x for which f(x)>0

The statement "___ + ___ = 9" can be filled with the numbers 4 and 5 to make it true. When these two numbers are added together, they equal 9. The product of 4 and 5 is 20.

However, it is important to note that there are other ways to fill in the blanks to make the statement true. For example, 3 and 6 can be used as the two numbers, or 1 and 8. In both cases, the sum of the two numbers equals 9.
This type of problem is often used as a way to test basic arithmetic skills and logical reasoning. It requires the solver to think about the properties of numbers and how they can be combined to create a desired outcome. By practicing these types of problems, individuals can improve their mathematical abilities and become more confident in their problem-solving skills.

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To obtain an error of less than 0.001 when approximating the sum of the series, a minimum of 50 terms are required.

To approximate the sum of the series [infinity]∑_n=1 1/n2 with an error of less than 0.001, we can use the formula for the error of a partial sum: |S - S_n| < ε, where S is the sum of the series, S_n is the nth partial sum, and ε is the maximum allowable error.

The sum of the terms of a sequence is called a series.

The sum of the artithmetic sequence formula is used to calculate the total of all the digits present in an arithmetic progression or series.

To recall, arithmetic series of finite arithmetic progress is the addition of the members. The sequence that the arithmetic progression usually follows is (a, a + d, a + 2d, …) where “a” is the first term and “d” is the common difference.

There are two ways with which we can find the sum of the arithmetic sequence.

For this problem, we have:
S = π^2/6 (the famous Basel problem)
ε = 0.001
To find the number of terms necessary to satisfy this inequality, we can rearrange it to get:
S_n > S - ε
π^2/6 - 0.001
Using a calculator, we find that S_n > 1.64467.

Now we need to find the smallest value of n such that the nth partial sum is greater than this:
1 + 1/4 + 1/9 + ... + 1/n^2 > 1.64467
We can use a computer program or a table of values to find that n = 50 is the smallest value that satisfies this inequality.

Therefore, we need at least 50 terms to approximate the sum of the series with an error of less than 0.001.

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The difference quotient for f(x) = x(¹/²) at x=37 and h=33 as ((70(¹/²)) - (37(¹/²))/33.

Compute the difference quotient?

The function f(x) = x(¹/²) at x=37 and h=33.

The difference quotient formula is: (f(x + h) - f(x))/h.

First, find f(x + h) by substituting x + h into the function: f(37 + 33) = ((37 + 33)(¹/²)).

Simplify f(x + h): f(70) = (70(¹/²)).

Find f(x) by substituting x into the function: f(37) = (37(¹/²)).

Plug f(x + h) and f(x) into the difference quotient formula: ((70^(1/2)) - (37(¹/²)))/33.

Now, you have computed the difference quotient for f(x) = x(¹/²) at x=37 and h=33 as ((70(¹/²)) - (37(¹/²))/33. m

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The simplified form of the expression is  [tex](2m-3n)^2[/tex].

What is expression?

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation. Unknown variables, integers, and arithmetic operators are the components of an algebraic expression. There are no symbols for equality or inequality in it.

Here the given expression is [tex]4m^2-12mn+9n^2[/tex].

Then,

=> [tex]2^2m^2-2\times2\times3\times m\times n+3^2n^2[/tex]

=> [tex](2m)^2-2\times2m\times3n+(3n)^2[/tex]

We know that [tex](a-b)^2=a^2-2ab+b^2[/tex] Then,

=> [tex](2m-3n)^2[/tex]

Hence the simplified form of the expression is  [tex](2m-3n)^2[/tex].

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Answer:

13 and 26

Step-by-step explanation:

Let's say x and y are our two numbers. We know that:

1) x + y = 39

2) x = 2 * y We could also say y = 2 * x, but I chose x to be larger.

We can use the method of substitution, plugging the second equation into our first and then solving:

(2 * y) + y = 39

3 * y = 39

y = 13

Using our second equation:

x = 2 * (13)

x = 26

Using the laws of decimal,

a. The decimal equivalent of the given numbers are as follows:

π = 3.14

√6 = 2.44

2√6 = 4.89

√7 = 2.64

b. Ordering these from least to greatest:

2.44, 2.64, 3.14, 4.89

Decimals are a set of numbers on a number line that appear between integers. They only serve as another way to represent fractions mathematically. Decimals give us a more precise way to express measurable quantities like length, weight, distance, money, etc.

Decimal fractions are shown to the right of the decimal point, while integers, commonly known as whole numbers, are shown to the left of the decimal point. If we continue straight from the first place, the next place, which is (1/10)th or tenth place value, is (1/10) times smaller.

As per the question,

a. The decimal equivalent of the given numbers are as follows:

π = 3.14

√6 = 2.44

2√6 = 4.89

√7 = 2.64

b. Ordering these from least to greatest:

2.44, 2.64, 3.14, 4.89

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Answer:

London Underground

Step-by-step explanation:

a)  The velocity at time t is (π/2)cos(π*t/2)

b) The velocity after 2 seconds is 0

c) At the time of 1/2, 3/2, and 5/2 the particle moving in the positive direction

d) The particle moving in the positive direction are 4 < t < 6

e) The particle travels a total distance of 2 feet in the first 6 seconds.

f) The rate of change of velocity with respect to time.

g) The acceleration after 3 seconds is -π²/4

h) The particle accelerating in the positive direction in the first 6 seconds at 5 < t < 6

i) The particle is speeding up in the positive direction during this time interval.

a) To find the velocity at any given time, we need to take the derivative of the position equation with respect to time. In this case, we have s(t) = sin(π*t/2), so the velocity is given by:

v(t) = ds/dt = (π/2)cos(π*t/2)

b) To find the velocity after 2 seconds, we simply plug in t = 2 into the velocity equation:

v(2) = (π/2)cos(π*2/2) = 0

This means that the particle is not moving at 2 seconds.

c) To find when the particle is at rest in the first six seconds, we need to find the values of t where the velocity is equal to zero. We can set the velocity equation equal to zero and solve for t:

(π/2)cos(π*t/2) = 0

cos(π*t/2) = 0

This occurs when π*t/2 = (n + 1/2)π, where n is any integer. Solving for t, we get:

t = (2n + 1)/2

We want to find the values of t that satisfy this equation and are between 0 and 6. These values are:

t = 1/2, 3/2, 5/2

So the particle is at rest at these times.

d) To find when the particle is moving in the positive direction, we need to look at the velocity equation. If the velocity is positive, the particle is moving in the positive direction. We can see from the velocity equation that cos(π*t/2) is positive when 0 < t < 2 and when 4 < t < 6. This means that the particle is moving in the positive direction during these time intervals.

e) To find the total distance traveled in the first 6 seconds, we need to integrate the absolute value of the velocity over the time interval [0,6]. This gives us the total distance traveled, since the absolute value of velocity tells us how fast the particle is moving regardless of direction. The integral is:

distance = ∫|v(t)|dt, from 0 to 6

= ∫(π/2)|cos(π*t/2)|dt, from 0 to 6

= 2

f) Acceleration is a measure of how fast the velocity of an object is changing over time.  To find the acceleration at any given time, we need to take the derivative of the velocity equation with respect to time:

a(t) = dv/dt = (-π²/4)sin(π*t/2)

g) To find the acceleration after 3 seconds, we simply plug in t = 3 into the acceleration equation:

a(3) = (-π²/4)sin(π*3/2) = -π²/4

h) To find when the particle is accelerating in the positive direction in the first 6 seconds, we need to look at the acceleration equation. If the acceleration is positive, the particle is accelerating in the positive direction. We can see from the acceleration equation that sin(pi*t/2) is negative when 1 < t < 3 and when 5 < t < 6. This means that the particle is accelerating in the positive direction during these time intervals.

i) To find when the particle is speeding up in the positive direction in the first 6 seconds, we need to look at the acceleration equation again. If the acceleration is positive and the velocity is also positive, then the particle is speeding up in the positive direction.

We can see from the velocity equation that cos(pit/2) is positive when 0 < t < 2 and when 4 < t < 6. We can also see from the acceleration equation that sin(pit/2) is negative when 1 < t < 3 and when 5 < t < 6. This means that the particle is both moving and accelerating in the positive direction during the time interval 0 < t < 2.

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The time axis is divided into slots equal to the packet transmission duration. In the collision control protocol, a station with a ready packet will transmit in the next time slot with a probability p (0 < p < 1). This protocol helps manage collisions and ensures efficient communication among the stations.

In a shared bus network with 6 stations, the collision control protocol requires that each station transmits its packet in the next time slot with a probability of p, where 0 < p < 1. If multiple stations transmit simultaneously, a collision occurs and the packets are lost. The probability of a successful transmission depends on the number of stations attempting to transmit at the same time. As the number of stations increases, the probability of collisions also increases, leading to lower overall network efficiency. Therefore, it is important to carefully manage the number of stations on the network and the probability of transmission to ensure optimal performance.

Additionally, it may be necessary to implement mechanisms such as back-off and retransmission to improve the reliability of the network and reduce the impact of collisions.
The time axis is divided into slots equal to the packet transmission duration. In the collision control protocol, a station with a ready packet will transmit in the next time slot with a probability p (0 < p < 1). This protocol helps manage collisions and ensures efficient communication among the stations.

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Answer:

c-(-5)=-19

Step-by-step explanation:

"ln" represents the natural logarithm (base e) and "log" with a number represents a logarithm with the specified base.

Here are the solutions for each equation:

a. y * 9^x = ln(9y)
Step 1: Rewrite the equation as a logarithm: x = log9(ln(9y)/y)
Step 2: Solve for the other variable (y): y = ln(9y)/log9(x)

b. v = 6(2.5)^t and t = ln(2.5v)
Step 1: Rewrite the equation as a logarithm: t = log2.5(v/6)
Step 2: Solve for the other variable (v): v = 6 * 2.5^(t)

c. b = 29a and a = ln(2b^(1/9))
Step 1: Rewrite the equation as a logarithm: (1/9) * log2(b) = a
Step 2: Solve for the other variable (b): b = 2^(9a)

Remember that "ln" represents the natural logarithm (base e) and "log" with a number represents a logarithm with the specified base.

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(a) The series converges conditionally by the alternating series test.

(b) The series converges conditionally by the alternating series test and the fact that the series ∑1/ n diverges.

(c) The series converges absolutely by the ratio test.

(d) The series converges conditionally by the alternating series test.

(e) The series converges absolutely by the comparison test with the convergent series ∑1/ n^2.

(f) The series converges absolutely by the comparison test with the convergent series ∑1/ n^2.

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Therefore, there are 10,241 females at the university when the ratio of males to females is 4:7.

A ratio is a mathematical comparison between two quantities, which can be expressed as a fraction or with the word "to". It represents the relationship in size or quantity between two or more things.

Here,

Let's use algebra to solve the problem. Let's represent the number of females with "x". According to the problem, the ratio of males to females is 4:7. This means that for every 4 males, there are 7 females.

We know that there are 5852 males.

So, we can set up the following proportion:

4/7 = 5852/x

To solve for x, we can cross-multiply:

4x = 7 * 5852

4x = 40,964

x = 10,241

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To determine the probability of each system operating under different conditions, we need to use probability calculations and convert the decimals to percentages.
a. The probability of the system operating as shown is simply the given decimal, which is 0.817. We don't need to do any further calculations.

Probability = 0.817
b. For each component to have a backup with a probability of .81 and a switch that is 100% reliable, we can use the formula for independent events:
Probability = P(backup) x P(switch) = 0.81 x 1 = 0.81
Since there are multiple components in the system, we need to raise the probability to the power of the number of components:
Probability = 0.81^2 = 0.6561
c. For backups with .81 probability and a switch that is 98 percent reliable, we need to adjust the probability of the switch failing:

Probability = P(backup) x P(switch) x P(switch failure) = 0.81 x 0.98 x 0.02 = 0.015876
Again, since there are multiple components in the system, we need to raise the probability to the power of the number of components:
Probability = 0.015876^2 = 0.00025203
Therefore, the probabilities for the three different conditions are:
a. Probability = 0.817
b. Probability = 0.6561
c. Probability = 0.00025203
Remember to round the final answers to four decimal places.
a. To determine the probability that the system will operate as shown, you can simply multiply the probabilities of each component:

Probability = 0.81 * 7 * 0.81 * 7
This calculation does not make sense since the probability should be between 0 and 1. Please check the values and conditions for the correct calculation.
b. If each system component has a backup with a probability of 0.81 and a switch that is 100% reliable, the probability that either the main component or the backup will operate is:
Probability = 1 - ((1 - 0.81) * (1 - 0.81))
Calculate the resut and round to 4 decimal places.
c. For backups with a 0.81 probability and a switch that is 98% reliable, first determine the probability that either the main component or the backup will operate:

Unreliable_switch_probability = 1 - 0.98 = 0.02
Component_probability = 1 - ((1 - 0.81) * (1 - 0.81))
Probability = 0.98 * Component_probability + 0.02 * 0.81

Calculate the result and round to 4 decimal places.

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To find the length of the curve x=cost, y=t+sint, 0≤t≤π, we first need to find the derivative of y with respect to t.

dy/dt = 1+cos(t)

We can now use the formula for arc length:

L = ∫√(1+dy/dt)^2 dt from 0 to π

L = ∫√(1+cos(t))^2 dt from 0 to π

L = ∫(1+cos(t)) dt from 0 to π

L = [t + sin(t)] from 0 to π

L = π

Therefore, the length of the curve x=cost, y=t+sint, 0≤t≤π is π units.
To find the length of the curve x = cos(t) and y = t + sin(t) with 0 ≤ t ≤ π, we can use the arc length formula for parametric equations:

Arc length = ∫(from a to b) √((dx/dt)² + (dy/dt)²) dt

First, find the derivatives dx/dt and dy/dt:
dx/dt = -sin(t)
dy/dt = 1 + cos(t)

Now, square each derivative and add them together:
(-sin(t))² + (1 + cos(t))² = sin²(t) + 1 + 2cos(t) + cos²(t)

Since sin²(t) + cos²(t) = 1, the expression becomes:
1 + 1 + 2cos(t) = 2 + 2cos(t)

Now, take the square root of the expression:
√(2 + 2cos(t))

Finally, integrate this expression with respect to t from 0 to π:
Arc length = ∫(from 0 to π) √(2 + 2cos(t)) dt

This integral does not have a simple closed-form expression, so you would need to use numerical methods or a calculator to find the approximate length of the curve.

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According to proportion, when y = 42, x = -7.

Proportions are a fundamental concept in mathematics that are used to relate two or more quantities. In this case, if y varies directly with x, it means that y and x are proportional to each other. This means that if one quantity changes, the other changes in the same proportion.

To solve the problem of finding x when y = 42, we can use the proportionality between y and x. This proportionality can be expressed as:

y/x = k

where k is the constant of proportionality. Since we know that y = -36 when x = 6, we can substitute these values into the equation above to solve for k:

-36/6 = k

k = -6

Now that we have the value of k, we can use the equation above to find x when y = 42:

42/x = -6

To solve for x, we can cross-multiply and simplify:

42 = -6x

x = -7

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The equation which is used to calculate the amount of money that the

store paid for the television set is $312.50 = a + 0.25a. The expression for the amount of money and money represented by each section are 0.25 a = $250. and $62.50 respectively in tape diagram.

Tape diagram is a pictorial representation that students use to draw equation fir representing a mathematical relationship.

We have, total cost of television set paid by Romano = $312.50

The makeup on cost/ price of tv set = 25%

To solve this problem we have a tape diagram for it as present in above figure.

first we have to write the equation which justify this problem. So, let the amount paid by store for tv set be ' a dollars'. Then, the makeup amount = 25% of amount paid by store = 0.25a

Total amount paid by Romano = amount paid by store + makeup amount

=> $312.50 = a + 0.25a

which is required equation. Now, first we have to write an expression for the amount of money represented by each section. As we see, 4 sections of 25% each includes in amount paid by store that 'a'. So, expression for this section is

$a = $312.50 - $0.25a

Expression for makeup section, 0.25a

= $312.50 - $a

As solving the equation, 0.35 a = 312.50

=> a = 250

so, amount paid by store section = $250, then divide it into 4 = $62.50.

then makeup section amount = 0.25 × 250

= $62.50

Hence, required amount is $62.50.

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Complete question :

The above figure complete the question.

Romano pays $312.50 for a television set. The markup on the price of the television set is 25%. What equation could you use to find the amount of money that the

store paid for the television set?

You can draw a tape diagram to help you

understand the problem. Write an expression for the amount of money represented by each section of the tape diagram. How much money is represented by each section

As per the concept of percentage, Mark can calculate the optimal allocation of funds among different stocks to achieve his goal of a total annual return of 12% while minimizing overall risk.

The average annual return for each stock is given as follows:

Internet - 0.18

Software - 0.12

Computer - 0.10

Entertainment - 0.15

The variance for each stock is not explicitly given but is implied to be the same as the squared value of the standard deviation. Therefore, the higher the variance, the riskier the investment.

To minimize overall risk, Mark needs to consider the correlation coefficients between each stock. Correlation coefficients measure the relationship between two variables, in this case, the stocks in Mark's portfolio.

The correlation coefficients between the stocks are given as follows:

1, 2 - 0.9

1, 3 - 0.7

1, 4 - 0.3

2, 3 - 0.8

2, 4 - 0.4

3, 4 - 0.2

The closer the correlation coefficient is to 1, the stronger the positive relationship between the stocks. A coefficient of 0 indicates no relationship, while a coefficient of -1 indicates a strong negative relationship.

To determine the percentage of funds Mark should invest in each stock, he needs to use the Markowitz Portfolio Theory. This theory uses the expected returns and variances of stocks and their correlations to determine the optimal allocation of funds among different stocks.

Mark's goal is to minimize overall risk while still achieving a total annual return of 0.12. Using the theory, Mark can calculate the percentage of funds to invest in each stock to achieve his goal.

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The CDF of X is F(x) = 0 for x < 1, F(x) = 2arctan(x) - π/2 for 1 ≤ x ≤ 2, and F(x) = 1 for x > 2. The expression for the 100p-th percentile is η(p) =  tan(πp/200). The expected demand is E(X) = 5/3 thousand gallons and the variance is V(X) = 1/9 thousand gallons^2. The amount of propane gas expected to be left at the end of the week is 0.347 thousand gallons.

The cdf of X is given by

F(x) = ∫1x 2(1-(1/t^2)) dt = 2[arctan(x) - arctan(1)]

F(x) = {0 if x < 1, 2arctan(x) - π/2 if 1 ≤ x ≤ 2, 1 if x > 2}

The (100p)th percentile is the value x such that F(x) = p. Solving 2arctan(x) - π/2 = πp/100, we get

x = tan(πp/200)

Using the formula for the mean and variance of a continuous random variable

E(X) = ∫1^2 t f(t) dt = 5/3 thousand gallons

E(X^2) = ∫1^2 t^2 f(t) dt = 7/2 thousand gallons^2

V(X) = E(X^2) - [E(X)]^2 = 1/9 thousand gallons^2

Let h(x) be the amount left when demand is x. Then, we have:

h(x) = 1.6 - x if x ≤ 1.6

h(x) = 0 if x > 1.6

The expected amount left at the end of the week is:

E[h(X)] = ∫1^2 h(x) f(x) dx = ∫1^1.6 (1.6 - x) 2(1-(1/x^2)) dx

E[h(X)] = 0.347 thousand gallons (rounded to three decimal places)

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The best name for the quadrilateral K.J. graphed is a parallelogram.

A parallelogram is a quadrilateral with opposite sides parallel to each other. Looking at the slopes of opposite sides, we see that AB and CD both have a slope of -4/3, while BC and DA both have a slope of 0. This means that opposite sides are parallel.

Additionally, we can see that opposite sides have equal length. AB and CD both have a length of 5, while BC and DA both have a length of 4. This is another characteristic of a parallelogram.

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To construct an interval estimate for mu with 95 percent confidence, we can use the formula: Confidence interval = sample mean +/- (critical value) x (standard error).

where the critical value is determined based on the desired level of confidence and the sample size, and the standard error is calculated as sigma/sqrt(n), where n is the sample size. Using the given information, we have: - When sigma = 50: - Sample mean (x) = 850, - Sample size (n) = 100, - Standard error (sigma/sqrt(n)) = 50/sqrt(100) = 5, - Critical value for 95% confidence interval (from t-distribution table with 99 degrees of freedom) = 1.984, - Interval estimate: - Lower limit = 850 - 1.984 x 5 = 840.08,  - Upper limit = 850 + 1.984 x 5 = 859.92, - 95% confidence interval is from 840.08 to 859.92.

   - When sigma = 100: - Sample mean (x) = 850, - Sample size (n) = 100, - Standard error (sigma/sqrt(n)) = 100/sqrt(100) = 10, - Critical value for 95% confidence interval (from t-distribution table with 99 degrees of freedom) = 1.984, - Interval estimate: - Lower limit = 850 - 1.984 x 10 = 829.16, - Upper limit = 850 + 1.984 x 10 = 870.84. - 95% confidence interval is from 829.16 to 870.84.

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When k = 1/2, the level curve is given by y - x² = 4. This is the equation of a shifted parabola, where the vertex is at (0,4) and the axis of symmetry is the y-axis.

(a) To sketch the domain of f(x, y) = 1/√(y - x²), first consider the restrictions:
1. The denominator cannot be zero: y - x² ≠ 0, or y ≠ x².
2. The square root cannot be negative: y - x^2 > 0, or y > x².
Thus, the domain of f(x, y) consists of all points (x, y) where y > x². This region can be sketched as a parabola opening upward (y = x²) with the region above the parabola being the domain.

(b) To sketch the level curves f(x, y) = k for k = 1 and k = 1/2, first set f(x, y) equal to k:
1. For k = 1: 1/√(y - x²) = 1, which implies y - x² = 1. The level curve for k = 1 is the graph of y = x² + 1, which is a parabola opening upward and translating one unit upward from the origin.
2. For k = 1/2: 1/√(y - x²) = 1/2, which implies y - x² = 4. The level curve for k = 1/2 is the graph of y = x² + 4, which is a parabola opening upward and translating four units upward from the origin.
These level curves can be sketched on the same graph with the domain, illustrating how the function f(x, y) behaves for the given values of k.

(a) To sketch the region that is the domain of f(x), we need to find the values of x and y that make the expression under the square root non-negative.
y - x² ≥ 0
y ≥ x²
This means that the domain of f(x) is all points (x,y) where y ≥ x². This is the region above the parabola y = x² in the xy-plane.

(b) To sketch the level curves f(x) = k, we need to find the equations of the curves where f(x,y) takes on a constant value of k.
1/ √ y - x² = k
√ y - x² = 1/k
y - x² = 1/k²
When k = 1, the level curve is given by y - x² = 1. This is the equation of a shifted parabola, where the vertex is at (0,1) and the axis of symmetry is the y-axis. When k = 1/2, the level curve is given by y - x² = 4. This is the equation of a shifted parabola, where the vertex is at (0,4) and the axis of symmetry is the y-axis.

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When k = 1/2, the level curve is given by y - x² = 4. This is the equation of a shifted parabola, where the vertex is at (0,4) and the axis of symmetry is the y-axis.

(a) To sketch the domain of f(x, y) = 1/√(y - x²), first consider the restrictions:
1. The denominator cannot be zero: y - x² ≠ 0, or y ≠ x².
2. The square root cannot be negative: y - x² > 0, or y > x².
Thus, the domain of f(x, y) consists of all points (x, y) where y > x². This region can be sketched as a parabola opening upward (y = x²) with the region above the parabola being the domain.

(b) To sketch the level curves f(x, y) = k for k = 1 and k = 1/2, first set f(x, y) equal to k:
1. For k = 1: 1/√(y - x²) = 1, which implies y - x² = 1. The level curve for k = 1 is the graph of y = x² + 1, which is a parabola opening upward and translating one unit upward from the origin.
2. For k = 1/2: 1/√(y - x²) = 1/2, which implies y - x² = 4. The level curve for k = 1/2 is the graph of y = x² + 4, which is a parabola opening upward and translating four units upward from the origin.
These level curves can be sketched on the same graph with the domain, illustrating how the function f(x, y) behaves for the given values of k.

(a) To sketch the region that is the domain of f(x), we need to find the values of x and y that make the expression under the square root non-negative.
y - x² ≥ 0
y ≥ x²
This means that the domain of f(x) is all points (x,y) where y ≥ x². This is the region above the parabola y = x² in the xy-plane.

(b) To sketch the level curves f(x) = k, we need to find the equations of the curves where f(x,y) takes on a constant value of k.
1/ √ y - x² = k
√ y - x² = 1/k
y - x² = 1/k²
When k = 1, the level curve is given by y - x² = 1. This is the equation of a shifted parabola, where the vertex is at (0,1) and the axis of symmetry is the y-axis. When k = 1/2, the level curve is given by y - x² = 4. This is the equation of a shifted parabola, where the vertex is at (0,4) and the axis of symmetry is the y-axis.

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The "(13-7) factorial" (13−7)! is equal to 720 (option a)

A factorial is denoted by the exclamation mark (!) and is a way of multiplying a sequence of consecutive numbers.

In this case, we are asked to evaluate the expression (13-7)!. To do this, we first need to simplify the expression inside the parentheses. 13-7 is equal to 6, so we can rewrite the expression as 6!.

Now, what does 6! mean? It means 6 multiplied by all the positive integers less than 6. In other words:

6! = 6 x 5 x 4 x 3 x 2 x 1

When we multiply these numbers together, we get:

6! = 720

So the answer to the question is 720.

So the correct option is (a).

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Answer: 36 ft tall

Step-by-step explanation:

V= l*W*H

V=6*2*3

voluume= 36

Answer:

B

Step-by-step explanation:

We can find the zeros of the quadratic function f(x) = x² - 10x + 25 by setting f(x) equal to zero and solving for x:

x² - 10x + 25 = 0

This quadratic equation can be factored as:

(x - 5)² = 0

Using the zero product property, we can see that this equation is true when:

x - 5 = 0

So the only zero of f(x) is x = 5.

Therefore, the correct answer is option B: x = 5 only.

Step-by-step explanation:

x² - 10x+25 = (x - 5)(x + 5)

If U want to do this U have to know (ax+b)(cx+d) = acx² + (bc+ad)x + bd

and how to use this and the quadratic formula to get your values. Although some people just know the values because of familiarity.

If set equal to zero we get

(x - 5)(x + 5) = 0

Therefore if x = 5 we get (5-5)(5+5) = (0)(5) = 0

And we have if x = -5, then (-5-5)(5-5) = (-10)(0) = 0

So our x-values should be 5 & -5

Which would be OA.

An amount 'a' divided by 3 can be expressed as a/3. For instance, if the number 30 is divided by 3, the result will be 10.

The mathematical statement a divided by 3 can be expressed as an algebra as follows: a/3. Often in algebra, words, and letters are used for mathematical expressions.

To resolve an equation of this nature, you simply have to insert the figure represented by 'a' and then divide it by 3 to arrive at your answer. For instance, if the number is 30, we could divide it by 3 to arrive at the answer 10.

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The indefinite integral of (9 - x^2) / (5x^3 + x) is (1/5) ln|x| - (1/10) ln|5x^2 + 1| + (9/5) tan^-1(√5x) + C, where C is the constant of integration.

To perform partial fraction decomposition, we first factor the denominator:

5x^3 + x = x(5x^2 + 1)

We can then write the integrand as a sum of two fractions:

(9 - x^2) / (5x^3 + x) = A/x + (Bx + C) / (5x^2 + 1)

Multiplying both sides by the denominator, we have:

9 - x^2 = A(5x^2 + 1) + (Bx + C)x

Simplifying and equating coefficients, we obtain the following system of equations:

A + B = 0

C = 9

5A = 1

Solving for A, B, and C, we get:

A = 1/5

B = -1/5

C = 9

Therefore, we can write the integrand as:

(9 - x^2) / (5x^3 + x) = (1/5) * (1/x) - (1/5) * (x/(5x^2 + 1)) + 9/(5x^2 + 1)

Integrating each term separately, we get:

∫ (9 - x^2) / (5x^3 + x) dx = (1/5) ln|x| - (1/10) ln|5x^2 + 1| + (9/5) tan^-1(√5x)

Therefore, the indefinite integral of (9 - x^2) / (5x^3 + x) is (1/5) ln|x| - (1/10) ln|5x^2 + 1| + (9/5) tan^-1(√5x) + C, where C is the constant of integration.

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There is a very small chance (less than 1%) that a randomly selected baby from this sample was born on Tuesday OR on Friday.

To find the probability that a randomly selected baby from this sample was born on Tuesday OR on Friday, we need to add the number of babies born on Tuesday to the number of babies born on Friday, and then divide by the total number of babies in the sample.

The number of babies born on Tuesday is 202020, and the number of babies born on Friday is 151515. Therefore, the total number of babies born on Tuesday or on Friday is 202020 + 151515 = 353535.

The total number of babies in the sample is 500500500. Therefore, the probability that a randomly selected baby from this sample was born on Tuesday OR on Friday is:

353535 / 500500500 = 0.0007061

It is interesting to note that the number of babies born on different days of the week varies in this sample. For example, there are more babies born on weekdays (Monday-Friday) than on weekends (Saturday and Sunday), and there are more babies born on Tuesday than on Wednesday or Thursday.

The number of scheduled deliveries is higher than the number of unscheduled deliveries overall, but there are some days (e.g., Friday and Saturday) where there are more unscheduled deliveries than scheduled deliveries. These patterns could be explored further to understand the factors that influence the timing and scheduling of deliveries.

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Answer:  x = (Y - b) / 3.

Answer:

x = (Y - b) / 3

Step-by-step explanation:

First, we can subtract b from both sides of the equation to get:

Y - b = 3x

Next, we can divide both sides of the equation by 3 to get:

x = (Y - b) / 3

*IG:whis.sama_ent

The side length of the smallest square plate on which a 38-cm chopstick can fit along a diagonal without any overhang is approximately 26.87 cm.

The Pythagorean theorem is a fundamental mathematical conclusion that connects the lengths of a right triangle's sides. It asserts that the square of the length of the hypotenuse in a right triangle with legs of lengths a and b and c is equal to the sum of the squares of the lengths of the legs.

Let the side of the square = x.

Given that, 38​-cm chopstick can fit along a diagonal without any​ overhang.

That is the hypotenuse or diagonal of the square plate needs to be 38.

The side of the square can be calculated using the Pythagoras Theorem as follows:

x² + x² = 38²

2x² = 38²

Taking square root on both sides we have:

√2x = 38

x = 38 /√2

Hence, the side length of the smallest square plate on which a 38-cm chopstick can fit along a diagonal without any overhang is approximately 26.87 cm.

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