The graph shows a line of fit for data collected on the value of used cars in a relation to the number of years since they were purchased. The equation of line of fit is y = -750x + 11000. Using the equation of the line of fit, what is the value of a car 5 years after its purchase?

The transformation that will produce g(x) from f(x) is:

g(x) = 1/3f(x)

A transformation in geometry is a function that assigns new positions, orientations, or configurations to points, lines, or forms in a plane or in space. An object's attributes, such as distance, angle, or symmetry, can be preserved while its size, shape, or location are changed.

This is so because g(x) scales down f(x) by a factor of three-quarters. To acquire the appropriate y-value of g, each y-value of f(x) is multiplied by a third (x).

The other answer choices are not correct:

It is not the same as g(x) = -f(1/3 x) to reflect f(x) across the y-axis and compress it horizontally by a factor of 3. (x).

That is not the same as g(x) = f(3x), which would expand f(x) horizontally by a factor of three (x).

The equation g(x) = -3f(x) would extend f(x) vertically by a factor of 3 and reflect it across the x-axis (x).

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Answer:

$58(0.20) + $58

Step-by-step explanation:

this is true because you would need to find what 20% of 58 is before you add it to the bill

The circumference of a circle with diameter 379 can be found using the formula:

C = πd

where d is the diameter of the circle. Substituting the given value of d, we get:

C = 3.14 x 379

C ≈ 1191.06

Rounding to the hundredths place, the circumference is approximately 1191.06 units of length (e.g. inches, centimeters, etc.).

Therefore, the answer to fill in the blank is 1191.06.

From the given question we cannot conclude that Burger Quick has a smaller range based on the given information.

Range refers to the set of potential target value, and if we have a graph, then the range is the collection of all feasible y-values on the graph.

Burger Quick is able to estimate their wait time more consistently because it has a smaller interquartile range (IQR). The IQR is a measure of the spread of the middle 50% of the data, and a smaller IQR indicates that the data is more tightly clustered around the median. In this case, Burger Quick has an IQR of 14.5 (from 9.5 to 24), while Fast Chicken has an IQR of 4.5 (from 10 to 14.5). This means that the wait times reported by Burger Quick are more consistent and less variable than those reported by Fast Chicken.

The range is a measure of the total spread of the data, and while a smaller range can indicate less variability, it doesn't necessarily mean that the data is more consistent in the middle. Therefore, we cannot conclude that Burger Quick has a smaller range based on the given information.

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Answer:

C (2)

Step-by-step explanation:

The weighted average of -1 and 5 with two-thirds of the weight on the first number and one-third on the second number is 1.

As per the question, we have:

First number: -1

Weight on the first number: 2/3

Second number: 5

Weight on the second number: 1/3

To calculate the weighted average:

Weighted average = ((-1) × (2/3) + (5) × (1/3)) / ((2/3) + (1/3))

Simplifying the expression:

Weighted average = ((-2/3) + (5/3)) / (2/3 + 1/3)

Weighted average = (3/3) / (3/3)

Weighted average = 3/3

Thus, the weighted average of -1 and 5 with two-thirds of the weight on the first number and one-third on the second number is 1.

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Answer:

9

Step-by-step explanation:

The probability that neither interval contains the respective population mean is 0.01 and the probability that both intervals contain their respective population means is 0.81.

Assuming that the two populations are independent, we can use the fact that the confidence interval is constructed such that there is a 90% probability that the true population mean falls within the interval.

Let's denote the two populations as Population A and Population B, and the confidence intervals for their respective means as CI_A and CI_B.

The probability that neither interval contains the respective population mean can be calculated as the complement of the probability that at least one interval contains its respective population mean.

P(neither interval contains its respective population mean) = 1 - P(at least one interval contains its respective population mean)

To calculate the probability of at least one interval containing its respective population mean, we can use the fact that the probability of an event A or B occurring is equal to the sum of their individual probabilities minus the probability of both events occurring simultaneously:

P(A or B) = P(A) + P(B) - P(A and B)

In this case, the event A is the event that CI_A contains the true population mean for Population A, and event B is the event that CI_B contains the true population mean for Population B.

Using this formula, we can calculate:

P(at least one interval contains its respective population mean) = P(CI_A contains true mean for Population A) + P(CI_B contains true mean for Population B) - P(both intervals contain their respective population means)

Since the two populations are independent, the events of each interval containing its respective population mean are also independent. Therefore, the probability of both intervals containing their respective population means can be calculated as the product of their individual probabilities:

P(both intervals contain their respective population means) = P(CI_A contains true mean for Population A) * P(CI_B contains true mean for Population B)

Now we have all the information we need to calculate the probability of interest:

P(neither interval contains its respective population mean) = 1 - P(at least one interval contains its respective population mean)

= 1 - [P(CI_A contains true mean for Population A) + P(CI_B contains true mean for Population B) - P(CI_A contains true mean for Population A) * P(CI_B contains true mean for Population B)]

Note that we don't have any specific information about the probabilities of the intervals containing their respective population means, so we can't calculate this probability exactly. However, we do know that the confidence intervals are constructed such that there is a 90% probability that the true population mean falls within the interval. This means that the probability of each interval containing its respective population mean is 0.9.

Using this information, we can calculate:

P(neither interval contains its respective population mean) = 1 - [0.9 + 0.9 - 0.9 * 0.9]

= 1 - 0.99

= 0.01

Therefore, the probability that neither interval contains the respective population mean is approximately 0.01, assuming that the confidence intervals were constructed using a 90% confidence level.

Similarly, the probability that both intervals contain their respective population means can be calculated as:

P(both intervals contain their respective population means) = P(CI_A contains true mean for Population A) * P(CI_B contains true mean for Population B)

= 0.9 * 0.9

= 0.81

Therefore, the probability that both intervals contain their respective population means is approximately 0.81, assuming that the confidence intervals were constructed using a 90% confidence level.

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The value of the variables are y = 2 and x = 1

From the information given, we have that;

y= 6x-11

-2x-3y =-7

Using the substitution method, we have;

Substitute the value of y in equation (2)

-2x - 3(6x - 11) = -7

expand the bracket

-2x - 18x + 33 = -7

collect the like terms

-20x = -7 - 33

subtract the values

-20x = -40

Make 'x' the subject

x = 2

Substitute the values of x in equation 1

y = 6(2) - 11

expand the bracket

y = 12 - 11

y = 1

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The two solutions to the system as a whole of equations is (3, 7) as (7, 3), respectively. These locations show where a line [tex]y = x+10[/tex] with the parabola of [tex]y = (x^{5} )^{2+6}[/tex] cross.

We can change the initial equation in the second to solve a set of equations[tex]y=x+10[/tex],  [tex]y = (x^{5} )^{2+6}[/tex] , yielding: [tex]−x+10 = (x^{5} )^{2+6}[/tex]

When we simplify and enlarge the right side, we obtain: [tex]x^{2} - 11x + 21 = 0[/tex]The quadratic equation is factored to yield: (x - 3)(x - 7) = 0.

x has solutions of 3 and 7. In order to determine the associated y-values, we may then enter these values back into one of the original equations. There are two possible answers: (3, 7) and (7, 3).

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Answer:

the formula is y=0.06x + 45

A. The rate of change is 0.06 dollars per kilometer

B. The initial cost is $45 dollars

C. The charge after 837 km is 95.22 including the initial cost

D. For $200 dollars you could drive 2583.3 km repeating.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Your initial equations are:  r is rate  i is initial fee

59.4 = r(240) + i

74.4  =  r(490) + i

solve the systems of equations.  I eliminate i by multiplying both sides of top equation by -

74.4  =  r(490) + i
-59.4 = -r(240) - i

15=250r

r=.06

plug r back in to get i

59.4=(.06)(240)+i

i=45

so

y=.06x+45

Answer:

Step-by-step explanation:

Distance formula looks a little like pythagorean because that where it comes from

d = [tex]\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }[/tex]

=[tex]\sqrt{(-1-(-2))^{2}+(3-1)^{2} }[/tex]

=[tex]\sqrt{1^{2}+2^{2} }[/tex]

=√5 or 2.24

Answer:

well maybe if Jensine gets a better f ***** job she can buy it instead she wants to waste her time to watch a annoying a *baby for 6$ a hour

Step-by-step explanation:

This is all a joke dont get mad :)

Answer: 1/9

Step-by-step explanation: I do rsm it is correct from my hw

The complete table is as follows

x       y

0     -11/2

1     -3

2      -1/2

3      2

4      9/2

5      7

The table is completed by identifying the constant change

-11/2 + k = -3

k = -3 + 11/2

k = 5/2

This is used to complete the table as follows

For x = 1

-11/2 + 5/2 = -3

For x = 2

-3 + 5/2 = -1/2

For x = 3

-1/2 + 5/2 = 2

For x = 4

2 + 5/2 = 9/2

For x = 5

9/2 + 5/2 = 7

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Answer:

125

Step-by-step explanation:

By using normal division method,

3125÷25 goes as 125

The probability that the committee will consist of men is 17.95%. 

To fathom this issue, we ought to utilize the concept of combinations. The number of ways to select a committee of 3 individuals from a add up to of 24 individuals is:

C(24,3) = 24! / (3! * 21!) = 2024

Presently, we ought to discover the number of ways to select a committee comprising of as it were men. We will select 3 men from 14 in:

C(14,3) = 14! / (3! * 11!) = 364 ways.

In this manner, the likelihood of choosing a committee comprising of as it were men is:

P(3 men) = C(14,3) / C(24,3) = 364 / 2024 = 0.1795

So the likelihood that the committee will comprise men is 0.1795, or approximately 17.95%. 

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Mathematics and data can help make decisions clearer, but ultimately you only have to make one decision at a time. This statement is true.

Information and factual investigation give profitable bits of knowledge and back decision-making, but it isn't continuously conceivable or fundamental to have full factual information sometime recently making decisions.

Decisions often have to be made with fragmented or fragmented data, and managers use them to possess judgment and encounter to weigh accessible alternatives, and make the most excellent conceivable choices. 

A decision must be made. Additionally, decisions often involve more than purely numeric data, such as B.

Social and ethical considerations require thoughtful and nuanced decisions that are not always fully captured by statistical analysis. 

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Answer: Answers will vary

one answer is...

The dimensions are 5cm 10cm and 10cm

Step-by-step explanation:

You just have to find 3 numbers that equal 500.

When rolling a fair six-sided die, the probability of rolling a six is 1/6. Assuming that the dice are fair and independent, we can use the rules of probability to find the probability of rolling certain outcomes when 4 dice are thrown:

i. To find the probability of getting exactly 3 sixes when 4 dice are thrown, we can use the binomial probability formula:

P(exactly k successes in n trials) = (n choose k) * p^k * (1-p)^(n-k)

where n is the number of trials, k is the number of successful outcomes, p is the probability of success on each trial, and (n choose k) is the binomial coefficient.

For this problem, n = 4, k = 3, and p = 1/6.

P(exactly 3 sixes) = (4 choose 3) * (1/6)^3 * (5/6)^1

= 4 * (1/216) * (5/6)

= 5/54

Therefore, the probability of getting exactly 3 sixes when 4 dice are thrown is 5/54.

ii. To find the probability of getting exactly 2 sixes when 4 dice are thrown, we can use the same formula with k = 2:

P(exactly 2 sixes) = (4 choose 2) * (1/6)^2 * (5/6)^2

= 6 * (1/36) * (25/36)

= 25/72

Therefore, the probability of getting exactly 2 sixes when 4 dice are thrown is 25/72.

iii. To find the probability of getting no sixes when 4 dice are thrown, we can use the complement rule:

P(no sixes) = 1 - P(at least one six)

To find the probability of getting at least one six, we can use the complement of getting no sixes:

P(at least one six) = 1 - P(no sixes)

For each die, the probability of not rolling a six is 5/6. Therefore, the probability of getting no sixes on 4 dice is:

P(no sixes) = (5/6)^4

= 625/1296

Therefore, the probability of getting no sixes when 4 dice are thrown is 625/1296, and the probability of getting at least one six is 1 - 625/1296 = 671/1296.

The Probability that the tennis team won 9  games is 1.35% , under the given condition that the tennis team wins 73% of their game,  if they play 10 games.

Therefore, probability of winning nine games out of ten with a 73% win rate can be evaluated using the binomial distribution formula
[tex]P(X=k) = (n choose k) * p^k * (1-p)^{(n-k)}[/tex]

Here
P(X=k) = probability of winning k games out of n games
n = total number of games played (n=10)
k = number of games won (k=9)
p = probability of winning a single game (p=0.73)

Staging the values in the formula
[tex]P(X=9) = (10 choose 9) * 0.73^9 * (1-0.73)^{(10-9)}[/tex]
= ( 10 - 9) x (0.05) x ( 0.27)¹

= 1 x 0.05 x 0.27

= 0.0135

Converting into percentage

0.0135 x 100

= 1.35%

The probability that the tennis team won 9  games is 1.35% , under the given condition that the tennis team wins 73% of their game,  if they play 10 games.

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The function of time x(t) corresponding to the Laplace transform 1/(s^2 + 9), Re{s} > 0, is x(t) = (1/3π) sin(3t) e^(st).

To compute the inverse Laplace, transform of 1/(s^2 + 9), we can use the formula for the inverse Laplace transform of a rational function:

L^-1{F(s)} = (1/2πi) ∫γ+σ-iγ+σ+ iF(s)e^(st) ds

where γ is a real number greater than the real part of all singularities of F(s), σ is a positive real number such that the contour of integration lies to the right of all singularities of F(s), and the contour of integration γ+σ is a line parallel to the imaginary axis.

In this case, the Laplace transform of 1/(s^2 + 9) is:

F(s) = L{1/(s^2 + 9)} = 1/[(s + 3i)(s - 3i)]

which has singularities at s = ±3i. Since Re{s} > 0, we can choose γ = 0 and σ > 3. Then, the inverse Laplace transform of F(s) is:

L^-1{F(s)} = (1/2πi) ∫γ+σ-iγ+σ+ iF(s)e^(st) ds
= (1/2πi) ∫γ+σ-iγ+σ+ i [1/((s + 3i)(s - 3i))] e^(st) ds

We can use partial fraction decomposition to express F(s) as:

F(s) = A/(s + 3i) + B/(s - 3i)

where A = 1/(2(3i)), B = -1/(2(3i)), and we get:

L^-1{F(s)} = (1/2πi) [∫γ+σ-iγ+σ+ i A/(s + 3i) e^(st) ds + ∫γ+σ-iγ+σ+ i B/(s - 3i) e^(st) ds]
= (1/2πi) [A e^(-3it) ∫γ+σ-iγ+σ+ i e^(su) du + B e^(3it) ∫γ+σ-iγ+σ+ i e^(sv) dv]
= (1/2πi) [(A e^(-3it) + B e^(3it)) ∫γ+σ-iγ+σ+ i e^(su) du]

where u = s - 3i, v = s + 3i, and we can evaluate the integral using the residue theorem:

∫γ+σ-iγ+σ+ i e^(su) du = 2πi Res[e^(su)/(u + 3i), u = -3i]
= 2πi e^(-3it)/(2(3i))
= -i/3 e^(-3it)

Therefore, we have:

x(t) = L^-1{F(s)} = (1/2πi) [(A e^(-3it) + B e^(3it)) ∫γ+σ-iγ+σ+ i e^(su) du]
= (1/2πi) [(1/(2(3i)) e^(-3it) - 1/(2(3i)) e^(3it)) (-i/3) e^(st) ds]
= (1/6π) [e^(-3it) - e^(3it)] e^(st) ds
= (1/3π) sin(3t) e^(st)

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Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.

Given that Anna has a loyalty card good for a 7% discount at her local grocery store.

We have to find the number should she multiply the prices on the tags by to find the price she would have to pay, before tax

Anna should multiply the prices on the tags by 0.93 (which is 1 minus the 7% discount) to find the price she would have to pay before tax in one step.

For example, if an item costs $10 before the discount, Anna would pay $10 x 0.93 = $9.30 after the discount.

Hence, Anna should multiply the prices on the tags by 0.93 to find the price she would have to pay before tax in one step.

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The best measure of center to determine which bus typically has the faster travel time is: A. Bus 47, with a median of 16.

In Mathematics and Statistics, a line plot simply refers a type of graph that is used for the graphical representation of data set above a number line, while using crosses, dots, or any other mathematical symbol.

For Bus 47, the median is given by;

4,6,14,28,10,10,12,12,18,18,22,22,16,16,16

Median of Bus 47 = 16

Mean of Bus 47 = 15.

For Bus 14, the median is given by;

10,16,20,28,8,8,14,14,18,18,18

Median of Bus 14 = 16.

Mean of Bus 14 = 16

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   1. True

   2. True

   3. False. The point where the coordinate axes cross is called the origin.

Answer:

Step-by-step explanation:

he height of the storage unit is equal to twice its radius (since the diameter is twice the radius), so the height is 2 x 8 = 16 feet.

The storage unit is in the shape of a cylinder, so we can use the formula for the volume of a cylinder, V = πr^2h, where r is the radius and h is the height:

V = π(8^2)(16)

V = π(64)(16)

V = 3,218.69 cubic feet (rounded to two decimal places)

Therefore, the volume of the storage unit is approximately 3,218.69 cubic feet.

The probability that the player would miss 7 or more shots is given as follows: 17%.

As the probability is greater than 5%, it would not be a surprise.

The binomial distribution formula gives the probability of obtaining a specific number of successes in a fixed number of independent trials, where each trial has only two possible outcomes (success or failure) and the probability of success is constant throughout the trials.

The mass probability formula is given by the equation presented as follows:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters, along with their meaning, are listed as follows:

The parameter values for this problem are given as follows:

n = 10, p = 0.5.

Hence the probability of 7 or more misses is given as follows:

P(X >= 7) = P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10).

Using a calculator, with the given parameters, the probability is given as follows:

P(X >= 7) = 0.17 = 17%.

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Answer:

Step-by-step explanation:

The parent function is f(x) = 0.8^x, which represents exponential decay. This means that as x increases, f(x) gets smaller and smaller.

The given function g(x) is obtained by multiplying f(x) by 800, which stretches the graph vertically by a factor of 800.

Also, the function g(x) has an additional translation: the entire graph of f(x) is shifted vertically upwards by 800 units. This is because the computer originally sold for $800, and g(x) represents the current value of the computer, which is $800 times the value of the parent function.

Therefore, g(x) can be described as a vertical stretch and translation of the parent function f(x) = 0.8^x.

Answer:

The answer would be Option C. [tex]\frac{1}{8}[/tex]

Step-by-step explanation:

Answer:

[tex]2 {a}^{2} - 8a = 0[/tex]

[tex]2a(a - 4) = 0[/tex]

[tex]a = 0[/tex]

[tex]a = 4[/tex]

The excluded values are a = 0 and a = 4.