The graph shows how the force component F cos θ along the displacement varies with the magnitude s of the displacement. Find the work done by the force. The graph plots F cosine of theta versus s. At s equals zero the graph is at zero and then rises linearly to the value 62 newtons. It then descends linearly to zero forming a shaded triangle of base 1.6 meters.

The period of the asteroid that  revolves around the Sun with a mean orbital radius 2.5 times is 3.95 year.

The cubes of the semi-major axes of the planets' orbits are directly proportional to the squares of the planets' orbital periods. According to Kepler's Third Law, a planet's period of orbiting the Sun should increase rapidly as its orbital radius does.

Given that:

An asteroid revolves around the Sun with a mean orbital radius 2.5 times that of Earth’s.

Hence, the period of the asteroid  is = (2.5)^(3/2) × 1 year

= 3.95 year.

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The required length of the pipe when tension in the pipe is given is calculated to be 0.1144 m.

The length of the taut is given as L = 62 cm = 0.62 m

Mass of the wire is given as 7.25 g = 7.25 x 10⁻³ kg

Tension in the wire = 4510 N

The speed of sound is 344 m/s.

We first determine the wave's speed on a string to get the length of the pipe by:

v = √F/μ  ----(1)

where,

v = speed

F = tension

μ = linear density

m is the mass, and L is the length, so = m/L.

Thus, v = √FL/m = √(4510)(0.62)/(7.25 x 10⁻³) = √(385.68 x 10³) = 10 ×√(3856.8) = 621.03 m/s

Now, we use to determine the wire's frequency

f = n v /L

where, f is frequency

Second overtone has large amplitude, n = 3  

f = 3(621.03)/2×0.62 = 1502.49

Using the second equation, we can now determine the pipe's length. the frequency of the pipe and the wire is the same, therefore,

f = n v /2L

n = 1, fundamental frequency

L = v/2f = 344/(2×1502.49) = 344/3004.98 = 0.1144 m

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Based on the equation D = ΔT 8.4 and the information provided, the distance to the epicenter of the earthquake would be is 16.8 kilometers.

The epicenter refers to the location on the earth's surface that is vertically aligned with the original location of this event. This means the epicenter does not determine the exact location of origin but the location on the earth's surface.

The equation to know this is D =ΔT 8.4. In this equation:

Now, let's calculate the distance:

D =ΔT 8.4

D = 2 x 8.4

D = 16.8 km

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The capacitor's energy reserve is   [tex]\frac{1}{2} QV[/tex]

Consider a parallel plate capacitor that has a +q charge at all times.

giving a nominal fee "dq"

W.D = dw

V = d w / q

V = q/c

dw = (q/c) dq

In an electrical circuit, a capacitor is a component that is used to hold charges. A capacitor operates under the premise that when an earthed conductor is moved close to a conductor, its capacitance increases noticeably. As a result, a capacitor has two plates with equal and opposite charges that are spaced apart.

total W.D. in levying a fine plus Q

[tex]\int\limits dw = \int\limits^Q_0 (q/c) dq[/tex]

w = [tex]\frac{1}{c} \frac{Q^2}{2}[/tex]

The energy created by the work is then stored in the form of energy,

[tex]E = \frac{Q^2}{2C}[/tex]

and

[tex]Q = \frac{1}{2} CV^2[/tex]

[tex]Q = \frac{1}{2} QV[/tex]

The capacitor's energy reserve is

[tex]E = \frac{Q^2}{2C}[/tex]

[tex]E = \frac{1}{2} QV[/tex]

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In this problem, y-polarized light passes through two polarizers. We need to look at the intensity of the light after passing through the first polarizer.

With respect to the initial intensity and the angle between the transmission axis of the first polarizer and the y-axis, the intensity i 1 after passing through the first polarizer is the initial intensity. Multiply cos squared theta 1 before passing through the first polarizer. where theta 1 is the angle between the initial polarization direction of the light and the axis of motion of the first polarizer. So this is the intensity after passing through the first polarizer, which comes from the men's law in part b.

We need to know the intensity of the light after passing through the second polarizer, i.e. before entering the second polarizer. Their intensity is i 1 , which is the intensity after passing through the first polarizer, so i is 2 i 1 x cos 2 cos 2 alpha. where alpha is the angle between the two polarizers and the angle between the two polarizers is theta 2 - theta. 1 and theta 2 minus theta 1 can be written as delta theta 12 points. So this is the intensity after passing through his second polarizer. Now we need to find the fraction of light transmitted through the two polarizers with respect to theta 1 and the angle difference between the two polarizers. Therefore, i 2 equals i 1 cos delta squared, and theta 12 equals i 1 . Since we don't square cos theta 1, the part that passes through the two polarizers is the final light that passes through the second polarizer with the intensity. I 2 at the initial intensity. This is the part that passes through the two polarizers and is equal to cos squared theta 1. From this equation, i 2 on i does not give cos squared theta 1 times cos squared delta theta 12 . Now we need to find f like this cos squared theta 1 times cos squared delta theta 12 delta. Theta 12 is the difference in polarization angles of Theta 2 minus Theta. 1 theta 1 equals 36 degrees. Theta 2 is 56 minus theta 136 degrees. From this we get the fraction 0.5 8 points. This is the break and the solution is now complete.

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Answer:

D

Explanation:

The minimum thickness of the magnesium fluoride coating to cause destructive interference of reflected light of wavelength 455 nm is 144 nm.

The minimum thickness of the magnesium fluoride coating that will cause destructive interference of reflected light of wavelength 455 nm can be calculated using the formula for the optical thickness of a coating:

t = m * λ / (4 * (n1 - n2))

where:

t = minimum thickness of coating

m = an integer, representing the order of the destructive interference

λ = wavelength of light (455 nm)

n1 = refractive index of air (approximately 1)

n2 = refractive index of flint glass (1.66)

For destructive interference to occur, the optical thickness of the coating must be equal to an odd multiple of one-quarter of the wavelength of light. In this case, we will use m = 1:

t = 1 * 455 nm / (4 * (1 - 1.66))

t = approximately 144 nm

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Answer:

I don't know why?? is this a homework question or a riddle?

There is a zero induced magnetic field in the image shown in A.

We know that the principle of electromagnetic induction states that there would be an induced emf only when there is a change in the induced magnetic flux. In this case, we would have to look at each of the images so as to know where there is no change in the magnetic flux.

The induced current is zero in a conductor when there is no change in magnetic field passing through it as shown in image A.

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Answer:

Rounded to the nearest whole number the electric field is 899000000

Explanation:

To calculate the magnitude of the electric field at point P, we can use Coulomb's law, which states that the force between two point charges is given by F = k * Q₁ * Q₂ / r², where k is Coulomb's constant, Q₁ and Q₂ are the charges, and r is the distance between the charges.

In this case, we are trying to find the electric field at point P, which is the force per unit charge. So we can find the force on a small test charge, q, placed at point P and divide by q to find the electric field.

F = k * Q₁ * q / x²

E = F/q

where E is electric field,

k = 8.99 x 10⁹ N.m²/C²

x = 51 cm = 0.51 m

Q₁ = -2 x 10⁻⁶ C

q = -1 x 10⁻⁶ C

Substituting these values into the equation, we get:

E = (k * Q₁ * q) / x²

E = (8.99 x 10⁹ N.m²/C² * -2 x 10⁻⁶ C * -1 x 10⁻⁶ C) / (0.51 m)²

E = -8.99 x 10⁹ N/C

The magnitude of the electric field at point P is 8.99 x 10⁹ N/C.

Rounded to the nearest whole number the electric field is 899000000 N/C.

The distance traveled (in mi) by the car over the interval [0, 100] is 1.37222

Distance is a measurement of how far apart two things or points are, either numerically or occasionally qualitatively. Distance can refer to a physical length in physics or to an estimate based on other factors in common usage. The phrase is widely used figuratively to denote a measurement of the amount of difference between two similar objects (or a degree of separation), as spatial cognition provides a rich source of conceptual metaphors in human understanding (as exemplified by distance between people in a social network). The concept of a metric space is used in mathematics to formalize the majority of these conceptions of distance, both literal and figurative.

The velocity of a car was read from its speedometer at 10-second intervals and recorded in the table.

Divide the interval [0,100] into 5 subintervals :

     [tex]\Delta[/tex] x =  [tex]\frac{100-0}{5}[/tex] = 20 sec

    [tex]\Delta[/tex] x   =  [tex]\frac{20}{3600}[/tex] hour

[tex]M_5=v(10)\Delta x+v(30)\Delta x+v(50)\Delta x +v(70)\Delta x+v(90)\Delta x[/tex]

[tex]M_5=(38+58++51+53+47)\frac{20}{3600}[/tex]

[tex]M_5=1.37222[/tex]

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The accurate statement would be that the magnitude of a vector can be zero even though one of its components is not zero.

The magnitude of a vector is a scalar value that represents the length of a vector. It is calculated using the Euclidean distance formula and is independent of the direction of the vector. A vector with a magnitude of zero is known as the null vector, and it can be represented by a vector with all zero components. Thus, even though one of the components of a vector may not be zero, the magnitude of the vector can still be zero if the other components are sufficiently small.

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Your question seems to be missing, but I suppose the full question was:

"Which of the following is an accurate statement?

The magnitude of a vector can be zero even though one of its components is not zero.

Rotating a vector about an axis passing through the tip of the vector does not change the vector.

The magnitude of a vector is independent of the coordinate system used.

Even though two vectors have unequal magnitudes, it is possible that their vector sum is zero

It is possible to add a scalar quantity to a vector."

The upward force the water will exert on the dust is 3770.3 Newton. The result is obtained by using the formula for buoyant force.

According to Archimedes principle, the buoyant force is the upward force exerted by a fluid on an object placed in them. The magnitude of the buoyant force is equal to the weight of a fluid displaced by an object.

The buoyant force can be expressed as

Fb = ρgV

Where

We have a ductwork with

Find the upward force by the water on the duct!

The upward force exerted is called the buoyant force. So, we can solve the problem by using the formula above.

We find the volume immersed under the water.

V = πr²L

V = π(½d)²L

V = ¼πd²L

V = ¼(3.14)(0.12)²(34)

V = ¼(3.14)(0.12)²(34)

V = 0.384336 m³

We use g = 9.81 m/s². The upward force will be

Fb = ρgV

Fb = 1000 × 9.81 × 0.384336

Fb ≈ 3770.3 Newton

Hence, the water will exert the upward force of 3770.3 Newton on the duct.

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Answer:

To find the height at which the two objects will first meet, we need to use the equations of motion for free fall and vertical upward motion.

The equation for free fall is:

h = h0 + v0t + (1/2)at^2

where h is the height of the object at time t, h0 is the initial height, v0 is the initial velocity (which is zero for free fall), and a is the acceleration due to gravity (which is 9.8 m/s^2 downward).

The equation for vertical upward motion is:

h = h0 + v0t - (1/2)gt^2

where h is the height of the object at time t, h0 is the initial height, v0 is the initial velocity, and g is the acceleration due to gravity (which is 9.8 m/s^2 downward).

We know that the first object is in free fall, and that it began at a height of 22.0 m. We also know that the second object was launched upward with an initial velocity of 32.0 m/s, 1.10 s after the first object was released.

We can use these values to find the height of the first object at the time the second object is launched:

h1 = 22.0 + 0 + (1/2)(-9.8)(1.10^2) = 20.27 m

We can use this value as the initial height for the second object:

h2 = 20.27 + 32.0(1.10) - (1/2)(-9.8)(1.10^2) = 37.47 m

Now we need to find the time at which the two objects will meet. We can use the height of the first object at the time the second object is launched, and the equation for free fall to find the time it takes for the first object to reach the height of the second object:

37.47 = 20.27 + 0 + (1/2)(-9.8)t^2

Solving for t, we find that the objects will meet at a time of approximately 1.47 seconds.

Finally, we can use this time to find the height at which they will meet:

h = 22.0 + 0 + (1/2)(-9.8)(1.47^2) = 37.47 m

So the objects will first meet at a height of 37.47 m above the ground.

if you point toward the zenith today and point there again 45 days later, you will have pointed twice in the same direction relative to the your horizon

We put more restrictions and limitations on ourselves than what a balanced horizon requires. Sometimes we rely too much on our optimism and joy, losing sight of the reality of the situation. A horizon is actually trying to teach us that opportunities and difficulties are closely related to one another on the spectrum between our actions and the outcomes that follow. If we decide to choose our route and then put in the necessary effort, a horizon establishes the stage of life when positive things can occur. A warning about troublesome and troubling events is being sent by the horizon.

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The wavelength of the sound is 2.6 x 10⁻³ m.

The wavelength of the sound or distance travelled by the sound wave is calculated by applying the following formula.

v = fλ

λ = v / f

where;

The wavelength of the sound is calculated as follows;

λ = v / f

λ = ( 343 m/s ) / ( 134,000 Hz )

λ = 2.6 x 10⁻³ m

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Based on the results we conclude that the toxin delays channel closing.

A toxin is a naturally occurring organic poison created by the metabolic processes of living cells or organisms. In particular, toxins exist as proteins or proteins that have been conjugated. Organic chemist Ludwig Brieger (1849–1919)[4] coined the term "toxin," which is derived from the word "toxic."

Toxins can be small molecules, peptides, or proteins that can cause disease when they come into contact with or are absorbed by body tissues and interact with biological macromolecules like enzymes or cellular receptors. Toxins range widely in their toxicity, from typically minor (like a bee sting) to potentially fatal even at very low doses (such as botulinum toxin)

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The magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal.

A magnetic field is a region of space in which a magnetic force is exerted by a magnet, electric current, or moving charged particles. This force is what causes a compass to point north and is responsible for many of the phenomena associated with electricity and magnetism.

For a symmetrical capacitor, the magnetic field between the capacitor plates is equal to the magnetic field outside the plates, as there is no real current between the plates. Therefore, the magnetic field in the loop l is equal to the magnetic field outside the loop, which is assumed to be purely azimuthal. Thus, the magnetic field in the loop l is equal to the azimuthal component of the magnetic field outside the loop, which can be calculated using the equation:
B = μ0*I/2πr,
where μ0 is the permeability of free space, I is the current in the loop, and r is the radius of the loop.

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Almost two-third of Stanley Milgram's research subjects went all the way to what could have been a deadly jolt of electricity if the shock generator had been real. The word in the fill in blank is two-third.

All of the participants gave the initial mild levels of shock. Some refused to continue after about 150 volts. Others, continued to administer the shocks, under the pressure of the experimenter.

In the end, 65% of the participants continued giving the shock up to the 450 volts maximum, that shock was marked as “danger: severe shock”.

In sum, almost two-thirds of the men who participated had, shocked another person to death, all as part of a supposed experiment on learning.

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-- The complete question is, Almost __________ of Stanley Milgram's research subjects went all the way to what could have been a deadly jolt of electricity if the shock generator had been real.--

The following affect how can see an object is removing, blocking, or changing the light source. so, option (a) is correct.

What is light?

The electromagnetic radiation known as light is what enables the human eye to see and makes things visible. It can also be described as radiation that can be seen by humans. Light is made up of small energy packets called photons. Light moves in a straight line at all times.

What is light source?

An artificial or natural light source is anything that produces light. The Sun and stars are examples of natural light sources. Televisions and lampposts are examples of artificial lighting sources. Without light sources, we wouldn't be able to view the world around us, yet not all things we can see are light sources.

Therefore, following affect how can see an object is removing, blocking, or changing the light source. so, option (a) is correct.

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Answer:

0 J

Explanation:

1. We know that U = mgh,
h = U/mg
or h = 73.5/3*9.8 = 2.5 m

2. When the book falls on the ground, there will be no kinetic energy by the book as the book will once again be stationary, and will convert this kinetic energy to other forms, so your answer must be 0 J.  

Compared to wave A, wave B has a longer wavelength and lower frequency.The correct answer is C.

The distance between two adjacent crusts or troughs is known as the wavelength.The frequency is the quantity of waves passing a specific spot in a unit of time.

The relationship between wavelength and frequency is inverse, meaning that waves with shorter wavelengths have higher frequencies while those with longer wavelengths have lower frequencies.

As seen in the illustration, wave B has a greater difference between its two consecutive crests or troughs than wave A. Since wavelength and frequency are inversely related, this indicates that wave B has a lower frequency and a longer wavelength.

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The wind speed at the rim of the hurricane is  17.14[tex]\frac{km}{hour}[/tex] and the pressure difference at the earth's surface between the eye and the rim is 1835 N/m² and the air would go high to 157.50m.

The wind speed at the rim of the hurricane will be calculated thus:

speed= [tex]\frac{200\times30}{350}[/tex]

speed= 17.14[tex]\frac{km}{hour}[/tex]

The pressure difference at the earth's surface between the eye and the rim will be:

=[tex](\frac{1}{2}\times 120\times55.56x^{2} -4.76^{2} )[/tex]

= 1835 N/m²

Kinetic Energy = Gravitational Potential Energy

[tex]\frac{1}{2}mv^{2}=mgh[/tex]

h = [tex]\frac{v^{2}}{2g}[/tex]

h=[tex]\frac{55.56^{2}}{2\times 9.8}[/tex]

h= 157.50 m

Although air can be compressed, it does not satisfy the Bernoulli equation. There are many factors that affect how the air behaves, including:

Higher altitudes have a lower temperature

Temperature and density are correlated.

High altitudes have lower pressure levels.

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The correct order of steps (4,1,3,2) that show how hydrogen is involved during photosynthesis is as follows:

Green plants use the process of photosynthesis to create their own nourishment with the help of solar energy.

Certain compounds are necessary for photosynthesis and are employed as reactants. Water, carbon dioxide, and solar light energy are some of these substances.

The correct steps are 4, 1, 2, 3

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Answer:

Gravity is at the center of many motion and force equations because it is a fundamental force that affects the motion of objects in the universe. The force of gravity can be described by Newton's law of gravitation, which states that two objects in the universe are attracted to each other with a force proportional to the product of their masses and inversely proportional to the square of the distance between them.

This force of gravity affects the motion of objects in the universe, including the motion of sound waves. Sound waves are disturbances that propagate through a medium, such as air or a solid, and transfer energy from one location to another. The presence of a gravitational field can alter the speed and path of sound waves.

For example, the speed of sound is influenced by the local pressure and temperature of the medium, and these can be affected by gravity. In a uniform gravitational field, the pressure decreases with height, which can result in a reduction in the speed of sound. In contrast, if the medium is accelerating, such as in a rocket, the effective gravity experienced by the medium can change, which can alter the speed of sound.

In summary, gravity plays a central role in many motion and force equations, and it can also impact the behavior of sound waves by altering the speed and path of the waves in a gravitational field.

Explanation:

Gravity is one of the four fundamental forces and it attracts all the matter with mass.

Contrary to popular belief, heavy metal music isn't actually heavy. The mass of sound waves is negative, and they can interact through gravity. So, sound rises, to put it another way.

By accounting for intricate particle interactions that had previously been disregarded, Angelo Esposito at Columbia University in New York and his colleagues estimated the link between sound and gravity. According to their findings, sound waves should have a detrimental effect even though it is minor.

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The velocity of the second marble after the collision is 0.47 m/s

According to conservation of linear momentum

The law of conservation of momentum states that in an isolated system the total momentum of two or more bodies acting upon each other remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed

M1u1 + M2u2 = M1v1 + M2v2

0.018 x 0.42 + 0.018 x 0.32 = 0.018 x 0.27 m/s + 0.018 x v2

0.00756 + 0.00576 = 0.00486 + 0.018 x v2

0.01332 = 0.00486 + 0.018 x v2

0.00846/0.018 = v2

v2 = 0.47 m/s

Hence, velocity of the second marble after the collision is 0.47 m/s

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Answer: The normal force N is given by N = μ * F, where μ is the coefficient of friction and F is the frictional force required to keep the block of metal moving with constant velocity across a surface. The frictional force F is equal to the normal force N multiplied by the coefficient of friction μ. The normal force is the force exerted by the surface on the block of metal perpendicular to the surface, and it is what opposes the weight of the block and prevents it from sinking into the surface.

Explanation:

An expression for how high in the air (vertical distance) the golf ball will travel is [tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex] and an expression for how far (horizontal distance) the golf ball will travel [tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex].

The scientific definition of velocity is probably similar to how you think of it. You are aware that a large displacement over a short period of time indicates a large velocity, and that velocity has units of distance / time, like miles/hour or kilometers/hour.

a) Golfer uses a six-iron with [tex]{eq}\alpha=31\enspace deg{/eq}[/tex]

The setting point at 2nd tree (14 m). Once we clear this height, we will check if the velocity we get will clear the 1st tree as well.

From Motion Equations:

[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]

since vertical distance is 14 m (minimum)

[tex]{eq}14=V_o \sin (31) t-\frac{9.81t^2}{2} {/eq}[/tex]

For Horizontal Component:

[tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex]

Since R=30+70=100

[tex]{eq}100=V_o \cos (31) ( t) {/eq}[/tex]

Getting t:

[tex]{eq}t=\frac{100}{V_o \cos (31) } {/eq}[/tex]

Substituting to 1st equation we get:

[tex]{eq}14=100 \tan (31)-4.9(\frac{100}{V_o \cos (31) })^2 {/eq}[/tex]

Solving for Initial Velocity:

[tex]{eq}V_o=38.0406\enspace m/s {/eq}[/tex]

Now, let's check if it clears the first tree.

[tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex]

Since R=30 m

[tex]${eq}t=\frac{30}{38.0406 \cos (31)} {/eq}[/tex]

[tex]{eq}t=0.92\enspace s {/eq}[/tex]

Substituting to Vertical Component:

[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]

[tex]{eq}S=13.47\enspace m {/eq}[/tex]

Since it is greater than 12 m, it clears the first tree.

Now the initial requirements are complied, let's solve for distance d (distance from the flag):

[tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex]

where S=0

Solving for time, we get:

[tex]{eq}t=3.9944\enspace s {/eq}[/tex]

Substituting to Horizontal Equation:

[tex]{eq}R=V_o \cos (31)(t) {/eq}[/tex]

[tex]{eq}R=130.25\enspace m {/eq}[/tex]

Solving for d:

[tex]{eq}d= (130.25)-(30+10+70) {/eq}[/tex]

[tex]{eq}d= (130.25)-(30+10+70) {/eq}[/tex]

[tex]{eq}d=20.25\enspace m {/eq}[/tex]

Thus, An expression for how high in the air (vertical distance) the golf ball will travel is [tex]{eq}s=V_o \sin (31) t-\frac{gt^2}{2} {/eq}[/tex] and an expression for how far (horizontal distance) the golf ball will travel [tex]{eq}R=V_o \cos (31) ( t) {/eq}[/tex].

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The work that is done in 10 minutes is  6000 J

Work that is done in one hour is 36000 J

Work is done when a force acts on an object and causes it to move in the direction of the force. The amount of work is calculated as the product of the force and the distance over which it acts.

Now we know that the work that have been done by the person that is carry the block is;

Work = Force * Distance

Force =  1.50 X 10^2 N

Distance = 8.00 m

Work = 1.50 X 10^2 N *  8.00 m

= 1200 J

Work done in 10 minutes = 5 *  1200 J = 6000 J

Work done in one hour = 30 * 1200 = 36000 J

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D. 3/4 of the total energy is stored in the spring, As per conservation of energy where the energy stored in the Spring will pass to the masses kept there.

As Conservation of energy states that energy remains conserved in case of elastic collisions. And here we can say that on a Frictionless surface, no energy would be dissipated.

So as 3/4 of the mass is at the mass with 3m so to equate the energy, which we can say 3/4 of the total energy Let's see how-

3Mv1 + Mv2 =0

3v1 = -v2

so we can see the speed of lighter mass will be thrice so so energy will be

1/2mv^2 so we can conclude the energy of mass with 3m will have the energy of 3/4

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