The HCF and LCM of two numbers x and 126 are 24 and 840 respectively. Find the value of x.

Answer:

5 units!

Step-by-step explanation:

Because Rectangle Perimeter = 2(a+b)

a=2w-1, b=w

2(2w-1+w)=28

3w-1=14

3w=15

w=5

So the answer is 5! 5! 5! A!A!A!

Fighting!! o(≧o≦)o

Answer:

C is the answer

Step-by-step explanation:

I'm sure it is

Answer:

4 , 4 , 5 , 6 , 11

Step-by-step explanation:

Mode = 4

So at least two times 4 should be there in the data.

And median is 5. So the middle term ( 3rd term} should 5.

Let x and y be the 4th term and 5th term

Data set:

4 , 4 , 5 , x , y

Mean =6

[tex]\frac{4+4+5+x+y}{5}=6\\[/tex]

4+4+5 +x + y = 6*5

13 + x + y = 30

     x + y = 30 - 13

     x + y = 17

x ,y can be any numbers that sum up to 17.

x , y  can be  10 , 7   or  6, 11

Data set: 4 , 4 , 5 , 6, 11

Answer:

y = (1/2)x + 3

Step-by-step explanation:

Slope intercept form is

y = mx + b

m is the slope

b is the y-intercept

The line rises 1 in y for every run of 2 in x

m = slope = rise/run = 1/2

b, The y-intercept is 3

The equation is

y = (1/2)x + 3

Answer:

[tex]\frac{2(x-6)(x-10)}{(x-4)(x-5)}[/tex]

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

[tex]\frac{()}{(x-4)(x-5)}[/tex]

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ([tex](x - 6)(x-10)[/tex]). Now one has this much of the function assembled

[tex]\frac{(x-6)(x-10)}{(x-4)(x-5)}[/tex]

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

[tex]\frac{2(x-6)(x-10)}{(x-4)(x-5)}[/tex]

Answer:

x=60

Step-by-step explanation:

solve, 180-(90+x) = 180-(30+2x)

Answer:

Area of a circle is denoted by: πr^2 where r is the radius of the circle. = 16/2 = 8 feet.

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\frac{2}{3} * 5 = \frac{2}{3}\frac{3}{2} x \\[/tex]

x = 10/3

Answer:

C

Step-by-step explanation:

The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

A graph is a intersection of {x} and {y} axis. On the graph, the coordinate points can be plotted in the form (x, y). In this, {x} represents the horizontal distance along the {x} axis and {y} is the vertical distance along the {y} axis.

Given is to identify the methods that are not used on graphs to lead the reader to misinterpret the graph.

The method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

Therefore, the method that is not used on graphs to lead the reader to misinterpret the graph is - Comparing two sets of related data on the same graph for the sake of comparison.

To solve more questions on graphs, visit the link below-

https://brainly.com/question/17267403

#SPJ7

Answer:

2. increasing when x > 0

the result of root is a positive number

and since there is no value of neg number in roots so it's increasing when x>0

plus in zero it self has a positive number (0,8)

but u cannot find either it's increasing or decreasing in zero bcoz in first derivative test

when x =0

y= not defined

Answer: y = 2x + 20; x is any real number greater than or equal to 0, and y is any real number greater than or equal to 20.

Step-by-step explanation:

Answer:

The second one is the answer.

Step-by-step explanation:

Objective: Linear Equation Problems.

Let model the equation given to us.

Vlad spent 20 minutes on his homework already and he complete x math problems every 2 minutes so we represent this as

[tex]y = 2x + 20[/tex]

X can be any real number greater than or equal zero because time isnt negative so anything below zero is wrong.

Y can be any real number but however since Vlad spent 20 mins on his homework already, he must spend over or equal to 20 minutes completing the total homework.

The second one is the answer

Answer:

D

Step-by-step explanation:

let y = f(x) and rearrange making x the subject

y = 2x - 10 ( add 10 to both sides )

y + 10 = 2x ( divide both sides by 2 )

[tex]\frac{y+10}{2}[/tex] = x

Change y back into terms of x with x = [tex]f^{-1}[/tex] (x) , then

[tex]f^{-1}[/tex] (x) = [tex]\frac{x+10}{2}[/tex] = [tex]\frac{1}{2}[/tex] x + 5 → D

Answer:

Step-by-step explanation:

=  [tex]\int\limits^1_0 {5x\sqrt{x} } \, dx[/tex]

=  [tex]\int\limits^1_0 {5xx^{1/2} } \, dx[/tex]

= [tex]\int\limits^1_0 {5x^{3/2} } \, dx[/tex]

= 5 [tex]\int\limits^1_0 {x^{3/2} } \, dx[/tex]

= 5*[tex]\frac{2}{5}[/tex]*[tex]x^{5/2}[/tex]  |[tex]\left[\begin{array}{ccc}1\\0\\\end{array}\right] \left[/tex]

= 5*[tex]\frac{2}{5}[/tex]*[tex]1^{5/2}[/tex]

= 2

Answer:

2 ( Option A )

Step-by-step explanation:

The given integral to us is ,

[tex]\longrightarrow \displaystyle \int_0^1 5x \sqrt{x}\ dx [/tex]

Here 5 is a constant so it can come out . So that,

[tex]\longrightarrow \displaystyle I = 5 \int_0^1 x \sqrt{x}\ dx [/tex]

Now we can write √x as ,

[tex]\longrightarrow I = \displaystyle 5 \int_0^1 x . x^{\frac{1}{2}} \ dx [/tex]

Simplify ,

[tex]\longrightarrow I = 5 \displaystyle \int_0^1 x^{\frac{3}{2}}\ dx [/tex]

By Power rule , the integral of x^3/2 wrt x is , 2/5x^5/2 . Therefore ,

[tex]\longrightarrow I = 5 \bigg( \dfrac{2}{5} x^{\frac{5}{2}} \bigg] ^1_0 \bigg) [/tex]

On simplifying we will get ,

[tex]\longrightarrow \underline{\underline{ I = 2 }}[/tex]

The number of servings you can make is 6

The given parameters are:

Next, we convert oz to pounds

Content per serving = 8 * 0.0625 pound

This gives

Content per serving = 0.5 pound

The number of serving is then calculated as:

Number = Available/Content per serving

This gives

Number = 3/0.5

Evaluate

Number = 6

Hence, the number of servings is 6

Read more about proportions at:

https://brainly.com/question/1781657

#SPJ9

Answer:

We know that the expression that models the situation is:

45 - n

Where n is the amount that she lost.

We know that she lost $3 for each hour closed.

And the shop was 8 hours closed, so the total loss is:

8*$3 = $24

The profit is the difference between the revenue (we know that it is $45) and the loss (we know that it is $24)

Then the profit is:

$45 - $24 = $21

Answer:

A

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Total waste = 22 000 in^3

If we use a proportion we have:

x : 100 = 2000 : 22 000

x = 200 000 / 22 000 = 9,09 % (option a is wrong

x : 100 = 7000 : 22 000

x = 700 000 / 22 000 = 31 % (ok)

Answer:

Q.5

Step-by-step explanation:

(2x)^3+3×(2x)^2×3y+3×2x×(3y)^2+(3y)^3

8x^3+3×4x^2 × 3y + 3×2x×9y^2 + 27y^3

8x^3 + 36x^2 × y + 54xy^2 + 27y^3

Answer:

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Step-by-step explanation:

Given

[tex]r = \frac{3}{2}[/tex]

[tex]f(5) = 81[/tex]

Required

The geometric sequence

A geometric sequence is represented as:

[tex]f(n) = ar^{n-1}[/tex]

Replace n with 5

[tex]f(5) = ar^{5-1}[/tex]

[tex]f(5) = ar^4[/tex]

Substitute values for f(5) and r

[tex]81 = a* (\frac{3}{2})^4[/tex]

Open bracket

[tex]81 = a* \frac{81}{16}[/tex]

Make a the subject

[tex]a = \frac{81 * 16}{81}[/tex]

[tex]a = 16[/tex]

So, the explicit function is:

[tex]f(n) = ar^{n-1}[/tex]

[tex]f(n) = 16 * (\frac{3}{2})^{n-1}[/tex]

Split

[tex]f(n) = 16 * (\frac{3}{2})^n \div (\frac{3}{2})[/tex]

Convert to multiplication

[tex]f(n) = 16 * (\frac{3}{2})^n * \frac{2}{3}[/tex]

[tex]f(n) = \frac{32}{3}(\frac{3}{2})^n[/tex]

Answer:

f(x) = 16*(3/2)^(x-1)

Step-by-step explanation:

right on edge

Hi there!

[tex]\large\boxed{\text{ B. 2}}[/tex]

f(x) = 2x + 6

Differentiating 2x = 2 (Power rule, dy/dx xⁿ =  nxⁿ⁻¹)

Differentiating a constant always equals 0.

Thus:

f'(x) = 2

Answer:

augmented

Step-by-step explanation:

In the field of linear algebra, the augmented matrix is defined as the matrix that is [tex]\text{obtained by appending}[/tex] the given columns of any two given matrices, that is usually for the [tex]\text{purpose of performing the same elementary row operations on each of the given matrices. }[/tex]

Here, each row forms an equation having a constant and the column have the  coefficients for the single variable.

Thus an augmented matrix is obtained from a system of linear equation in matrix.

Answer:

143

Step-by-step explanation:

to find the area we multiply half of the sum of the bases with height

(18+8)/2*11 = 143

Answer:

5%

Step-by-step explanation:

Both should be in same measurement. so convert 4 kg to gram

1 Kg = 1000 g

4 kg = 4 * 1000 = 4000 g

[tex]\frac{200}{4000}*100=\frac{2}{40}*100\\\\=\frac{1}{20}*100 = 1 * 5\\[/tex]

= 5%

Answer:

14 $1 coin

12 quarter coin

Step-by-step explanation:

Let :

x = $1 dollar coin

y = $0.25 (1 quarter) coin

x + y = 26 - - - (1)

1x + 0.25y = 17 - - - - (2)

From (1) :

x = 26 - y

Put x = 26 - y in (2)

1(26 - y) + 0.25y = 17

26 - y + 0.25y = 17

-y + 0.25y = 17 - 26

-0.75y = - 9

Divide both sides by - 0.75

-0.75y /- 0.75 = - 9 / - 0.75

y = 12

Put y = 12 in (1)

x = 26 - 12

x = 14