The heritability of a trait is constant over time in a species. True False QUESTION 12 10 points Explain why a trait entirely controlled by two alleles at one genetic locus does not fit all scenarios. Answer in one or two complete sentences.

Answers

Answer 1

The sentence, The heritability of a trait is constant over time in a species is False.

The heritability of a trait is not constant over time in a species. This is because the environment plays a role in the expression of genetic traits, which can change over time. Traits that are entirely controlled by two alleles at one genetic locus do not fit all scenarios because most traits are influenced by multiple genes and environmental factors. Therefore, the expression of a trait can vary widely depending on the context in which it is observed. It is also worth noting that traits with high heritability can still be influenced by environmental factors, and traits with low heritability can still have a genetic basis.

In conclusion, the heritability of a trait is not fixed and can vary over time and in different contexts, making it important to consider both genetic and environmental factors when studying traits.

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Related Questions




Briefly describe the key differences between type II and type III hypersensitivity disorders.

Answers

Type II Hypersensitivity Disorders:

- Antibodies produced by the immune system target antigens on cell surfaces.

- This leads to cell death, lysis, and tissue damage.

- Examples include drug reactions, hemolytic anemia, autoimmune diseases, and transfusion reactions.

Type III Hypersensitivity Disorders:

- Antibodies form complexes with circulating antigens.

- This causes inflammation, tissue damage, and disease.

- Examples include rheumatoid arthritis, systemic lupus erythematosus, serum sickness, and poststreptococcal glomerulonephritis.

Type II and Type III hypersensitivity disorders are autoimmune disorders characterized by an exaggerated immune response against foreign antigens. This immune overreaction leads to inflammation, organ damage, and disease. The key differences between Type II and Type III hypersensitivity disorders are as follows:

Type II Hypersensitivity Disorders:

In Type II hypersensitivity disorders, the immune system produces antibodies that target antigens present on the surfaces of cells or tissues. These antibodies can cause cell death, lysis, and tissue damage. Type II disorders can be triggered by various factors including drug reactions, autoimmune diseases, hemolytic anemia, and transfusion reactions.

Type III Hypersensitivity Disorders:

In Type III hypersensitivity disorders, antibodies bind to circulating antigens, forming antigen-antibody complexes that accumulate in tissues and organs. This accumulation leads to inflammation, tissue damage, and the development of disease. Type III disorders can be caused by factors such as rheumatoid arthritis, systemic lupus erythematosus, serum sickness, and poststreptococcal glomerulonephritis.

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1. Which of the following are plausible reasons why many adults lose less weight than predicted during exercise programs? Select all that apply a. Increased caloric intake during the exercise program b. Reduced appetite due to hormone changes c. The predicted amount of weight loss from exercise programs is often overestimated d. Increased physical activity outside of the exercise program 2. Which of the following are correct statements regarding how obesity varies in the United States by sex and race? Select all that apply. a. Obesity prevalence in women is highest among white non-Hispanics. b. Asians have the lowest prevalence of obesity among both children and adults. c. Obesity prevalence among adult black non-Hispanics is higher in women than in men. 3. Liam weighs 209 pounds (95 kg) and is 6 feet tall (1.83 m), and he would like to know whether he should be concerned about his weight Calculate Liam's body mass index and state whether he would be classified as underweight, normal weight, overweight, or obese. Does this mean he should be concerned about his weight? Why or why not? 4. List five chronic health conditions associated with obesity. 1. Select all that apply. Diabetes mellitus a. is characterized by hyperglycemia b. is a relatively rare condition c. is strongly associated with obesity d. is a disorder of fat metabolism 2. Select all that apply. Type 1 diabetes a. is the result of the ineffectiveness of insulin to facilitate the transport of glucose into the cells b. is caused by the inability of the pancreas to produce sufficient insulin c. is an autoimmune disease d. is usually diagnosed among those 40 to 60 years old

Answers

1. The plausible reasons why many adults lose less weight than predicted during exercise programs are: b. Reduced appetite due to hormone changes and c.) The predicted amount of weight loss from exercise programs is often overestimated, and d. Increased physical activity outside of the exercise program.

2. The correct statements regarding how obesity varies in the United States by sex and race are:

b. Asians have the lowest prevalence of obesity among both children and adults, and

c. Obesity prevalence among adult black non-Hispanics is higher in women than in men.

3. Liam's body mass index is calculated as follows: Body Mass Index = weight (kg) / height² (m²)BMI

= 95 / (1.83)²

= 28.3

Therefore, he is classified as overweight, which is concerning since being overweight is associated with various health risks.

4. Five chronic health conditions associated with obesity are: a. Diabetes mellitus, c. Hypertension, e. Dyslipidemia, f. Cardiovascular disease, and g. Respiratory problems.

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Describe what the dura mater in the sheep brain looks like.

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Dura mater is the outermost layer of the meninges that encases the entire central nervous system. It is one of the toughest layers, and it's dense, fibrous, and white, making it easy to identify.

The meninges is made up of three layers of connective tissue that encases the brain and spinal cord, offering support and protection against mechanical shocks and external influences. The outermost of the three meninges is known as the dura mater, which is Latin for "tough mother."It is a tough, dense, and fibrous membrane made up of collagen and elastin fibers that provide strength and resilience.

The dura mater is adhered to the inner surface of the cranium, surrounding the brain's outer surface and enveloping the spinal cord in a tube of the same name.In terms of the sheep brain, the dura mater appears as a dense, white fibrous layer that envelops the brain's outer surface, giving it the appearance of a white, glistening membrane.

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What exactly is phosphorylation and why is this important in terms
of available energy for the human body? What does the body use to
generated energy

Answers

Phosphorylation adds phosphate groups to molecules involved in cellular metabolism, enabling energy generation in the human body through ATP replenishment via substrate-level and oxidative phosphorylation.

Phosphorylation is a biochemical process in which a phosphate group (PO4) is added to a molecule, typically a protein or a molecule involved in cellular metabolism. It plays a crucial role in the energy metabolism of the human body.

Adenosine triphosphate (ATP) is the primary molecule used for energy storage in cells. When ATP is hydrolyzed, it releases a phosphate group, resulting in the formation of adenosine diphosphate (ADP) and inorganic phosphate (Pi).

This process releases energy that can be utilized by the body for various biological processes.

To replenish ATP levels, the body relies on phosphorylation. Phosphorylation occurs through two main mechanisms: substrate-level phosphorylation and oxidative phosphorylation.

In substrate-level phosphorylation, a phosphate group is transferred from a donor molecule to ADP, forming ATP. This process occurs during glycolysis and the citric acid cycle.

Oxidative phosphorylation takes place in the mitochondria and involves the transfer of electrons through the electron transport chain. This transfer generates a proton gradient, which drives the synthesis of ATP through the enzyme ATP synthase.

Phosphorylation is essential for the availability of energy in the human body because ATP is the currency used by cells to perform work.

From muscle contraction to cellular signaling, ATP provides the necessary energy for these vital processes.

Without phosphorylation and the replenishment of ATP, the body's energy supply would be severely compromised, leading to a loss of function and eventually cell death.

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What factor contributes to maximizing the muscle tension that is generated by the skeletal muscle fibers? Check all that apply.
The skeletal muscle is composed of a large percentage of fast glycolytic fibers.The skeletal muscle is composed of a large percentage of fast glycolytic fibers.
The skeletal muscle contains large motor units.The skeletal muscle contains large motor units.
A greater stimulus frequency to the skeletal muscle from the motor neurons. A greater stimulus frequency to the skeletal muscle from the motor neurons.
The skeletal muscle is stimulated when it is at stretched length.The skeletal muscle is stimulated when it is at stretched length.
The skeletal muscle is stimulated by actions potentials with a greater amplitude.

Answers

The factor that contributes to maximizing the muscle tension that is generated by the skeletal muscle fibers is as follows: 1. The skeletal muscle contains large motor units.2. A greater stimulus frequency to the skeletal muscle from the motor neurons.3. The skeletal muscle is stimulated by actions potentials with a greater amplitude.

Explanation:

Maximizing the muscle tension that is generated by the skeletal muscle fibers is one of the important characteristics of muscle fibers.

Muscle fibers contain actin and myosin, which are the two main contractile proteins that are responsible for generating the force that is required for movement.

The number of muscle fibers in the motor unit determines the force that can be generated by the muscle.

The factors that contribute to maximizing the muscle tension that is generated by the skeletal muscle fibers are the following:

1. Large motor units: The skeletal muscle contains large motor units.

The number of muscle fibers in the motor unit determines the force that can be generated by the muscle.

Large motor units can generate more force than small motor units.

2. Greater stimulus frequency to the skeletal muscle from the motor neurons:

A greater stimulus frequency to the skeletal muscle from the motor neurons can increase the force that is generated by the muscle.

A high stimulus frequency leads to a greater release of calcium ions, which leads to more cross-bridge cycling and more force production.

3. Greater action potential amplitude:

The skeletal muscle is stimulated by action potentials with a greater amplitude.

The amplitude of the action potential determines the number of calcium ions that are released from the sarcoplasmic reticulum.

A greater release of calcium ions leads to more force production.

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I.D: 1. DISCUSS THE KNEE EXTENSOR MECHANISM BIOMECHANICS? 15 2. DISCUSS THE LUNATE BONE AS SITE OF BONE NECROSIS? 3.DISCUSS CAUSES AND PRESENTAION OF COMPRESSION OF LATERAL CUTTANEOUS NERVE OF THIGH ? 4.DISCUSS THE DELTOID LIGAMENT IN ANKLE STABILITY ?

Answers

1. The knee extensor mechanism is a term used to describe a set of soft tissue structures that work in coordination to provide stability, mobility, and force transmission across the knee joint.

The components of the extensor mechanism are the quadriceps muscle, patella, patellar tendon, and the patellar retinaculum. The quadriceps muscle is responsible for generating the majority of the force required to extend the knee. The patella is a sesamoid bone located within the quadriceps tendon. It serves to increase the moment arm of the quadriceps, allowing for more efficient force transmission across the knee joint. The patellar tendon connects the patella to the tibia. The patellar retinaculum is a group of fibrous bands that help to keep the patella in place during knee movement.

2. Lunate bone is a small, moon-shaped bone found in the wrist.

The bone receives its blood supply from small branches of the radial artery. If the blood supply to the lunate bone is compromised, it can lead to a condition called Kienbock's disease.Kienbock's disease is a condition in which the lunate bone undergoes necrosis, or death of bone tissue. The exact cause of Kienbock's disease is unknown, but it is thought to be related to repetitive trauma to the wrist or abnormalities in the anatomy of the wrist. Symptoms of Kienbock's disease include wrist pain, swelling, and limited mobility.

3. The lateral cutaneous nerve of the thigh is a sensory nerve that supplies the skin over the lateral aspect of the thigh.

Compression of this nerve can lead to a condition called meralgia paresthetica. Meralgia paresthetica is a condition in which the lateral cutaneous nerve of the thigh is compressed, leading to symptoms such as burning, tingling, and numbness over the lateral aspect of the thigh. Causes of meralgia paresthetica include obesity, pregnancy, tight clothing, and injury.

4. The deltoid ligament is a strong, triangular ligament located on the medial side of the ankle.

It is responsible for providing stability to the ankle joint and preventing excessive eversion, or outward rolling, of the foot. The deltoid ligament is composed of four separate ligaments: the tibionavicular ligament, the tibiocalcaneal ligament, the posterior tibiotalar ligament, and the anterior tibiotalar ligament. Together, these ligaments provide a strong and stable connection between the tibia and the talus, helping to maintain ankle joint stability.

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During his hospital rotations, Lawrence notices that one of his patients has contracted a uninary tract infection from a contaminated catheter. A Gram stain from the urine shows Gram (+) cocci in chains. What is the Most Likely pathogen here?
Clostridium difficile
Enterococcus faecalis
Streptococcus pyogenes
Neisseria gonorthoeae
The Viridans Streptocacci

Answers

The most likely pathogen in this case is Streptococcus pyogenes (Option C).

Streptococcus pyogenes, also known as Group A Streptococcus (GAS), is a Gram-positive cocci bacterium that commonly causes urinary tract infections (UTIs). It is characterized by its arrangement in chains under Gram stain. UTIs can occur when a contaminated catheter is used, leading to infection in the urinary tract. Streptococcus pyogenes is one of the common pathogens associated with UTIs. Options A, B, D, and E (Clostridium difficile, Enterococcus faecalis, Neisseria gonorrhoeae, and The Viridans Streptococci) are not typically associated with urinary tract infections.

Option C is the correct answer.

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Short answer, labeling, drawing, and uploading: Explain how the respiratory centers regulate breathing. Include a diagram of where they are located (5pts). Draw and label three mechanisms how CO
2

is transported in a systemic capillary (10pts) Uplo During emphysema surface-area-to-volume ratio decreases increases The additional volume of air that can be inhaled with maximum effort after a normal inspiration is called ERV TV IRV TLV

Answers

Respiratory centers in the brainstem regulate breathing. [tex]CO_2[/tex] is transported in capillaries through carbonic acid formation, hemoglobin binding, and dissolved gas. Emphysema reduces gas exchange.

The respiratory centers in the medulla oblongata and pons of the brainstem regulate breathing. The medulla contains the primary respiratory center, while the pons has the pneumatic and apneustic centers. Carbon dioxide [tex](CO_2)[/tex] is transported in systemic capillaries through three mechanisms: carbonic acid formation, binding to hemoglobin, and dissolved gas in the plasma.

Emphysema reduces the surface-area-to-volume ratio, affecting gas exchange. This condition leads to decreased oxygen uptake and increased residual volume. The additional volume of air that can be inhaled after a normal breath is the inspiratory reserve volume (IRV), and the total lung volume (TLV) represents the sum of all lung capacities (tidal volume, inspiratory reserve volume, and expiratory reserve volume).

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Why
it is unavailable to microorganisms if avidin forms complex with
biotin in eggs. Explain in details

Answers

The avidin-biotin complex in eggs makes biotin unavailable to microorganisms.

Avidin, a protein found in egg whites, has a strong binding affinity for biotin, a vitamin essential for microorganisms' growth and metabolism.

When avidin encounters biotin in the environment, it forms a stable complex known as the avidin-biotin complex.

This complexation between avidin and biotin prevents microorganisms from accessing and utilizing biotin.

Microorganisms require biotin as a coenzyme for various enzymatic reactions involved in crucial metabolic processes.

Since microorganisms cannot synthesize biotin themselves, they rely on external sources for this essential nutrient.

When the avidin-biotin complex is formed, biotin becomes sequestered and unavailable to microorganisms for use.

As a result, microorganisms are unable to obtain the necessary biotin from eggs or egg-containing products, which limits their growth and survival.

Overall, the formation of the avidin-biotin complex in eggs creates a barrier that restricts microorganisms' access to biotin, impacting their ability to thrive and carry out vital metabolic functions.

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set the vertical velocity component equal to zero (vo sin α-gt 0) and solve for t. Choose the correct expression for t. v cos α cos α ○ B. sin α Vo sin α O C. D.

Answers

The given expression is vo sin α - gt 0. To solve for t, set the vertical velocity component to zero. The correct expression for t is `vo sin α/g`.So, the correct option is D.

We know that the velocity of an object can be defined as a vector quantity which means it has both magnitude and direction. Hence it can be represented as v = xvi + vyjHere, xi represents the horizontal component of velocity and vyj represents the vertical component of velocity. Therefore, the vertical component of the initial velocity can be written as vo sin α. The acceleration due to gravity is denoted by g. Hence, the vertical component of the velocity at time t can be expressed as:v = vo sin α - gtBy setting the above equation to zero, we can determine the time at which the object reaches its maximum height. Hence we get,0 = vo sin α - gtSolving the above equation for time t, we gett = vo sin α / gTherefore, the correct expression for t is vo sin α/g.

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please answer question 51 and question 52
Describe an intoxication caused by algae: name the organism, the toxin it produces, how the host acquires the toxin, and what the toxin does to the host.
Describe an infection caused by a protozoan.

Answers

One of the intoxications caused by algae is paralytic shellfish poisoning (PSP).PSP is caused by the ingestion of shellfish that have accumulated toxins produced by a group of marine dinoflagellates, including Alexandrium and Gymnodinium.

Protozoa are single-celled organisms that can cause a variety of infections in humans.One of the infections caused by protozoa is malaria, which is caused by the Plasmodium parasite.

Question 51: Algal Intoxication

One of the intoxications caused by algae is paralytic shellfish poisoning (PSP).PSP is caused by the ingestion of shellfish that have accumulated toxins produced by a group of marine dinoflagellates, including Alexandrium and Gymnodinium.

The toxin produced is called saxitoxin, which is a potent neurotoxin that blocks the sodium channels in nerve cells.The host acquires the toxin by ingesting shellfish, including clams, mussels, oysters, and scallops, which have accumulated the toxin.Toxins can also be obtained directly from eating small marine animals that feed on these algae, such as gastropods, crabs, and fish. Symptoms of PSP are nausea, vomiting, diarrhea, and stomach cramps, followed by headache, dizziness, and neurological symptoms. In severe cases, PSP can result in paralysis, respiratory failure, and even death.

Question 52: Protozoan Infection

Protozoa are single-celled organisms that can cause a variety of infections in humans.One of the infections caused by protozoa is malaria, which is caused by the Plasmodium parasite.

Malaria is transmitted by the bite of infected female Anopheles mosquitoes, which inject the parasite into the bloodstream of the host.The parasite then infects and destroys red blood cells, leading to anemia, fever, chills, headache, and other symptoms.In severe cases, malaria can lead to organ failure and death.Malaria is a major public health concern in many parts of the world, particularly in sub-Saharan Africa, where it is a leading cause of morbidity and mortality.

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Correctly list the maturation sequence of the Red Blood Cells, beginning from the most immature to mature.

Mature Eythrocyte

Basophilic Normoblast

Polychromatic Erythrocyte

Pronormoblast

Orthochromic Normoblast

Polychromatic Normoblast

Answers

The maturation sequence of Red Blood Cells, from immature to mature, is: Pronormoblast, Basophilic Normoblast, Polychromatic Normoblast, Orthochromic Normoblast, Polychromatic Erythrocyte, and Mature Erythrocyte.

The process of red blood cell maturation involves several stages. It begins with the formation of pronormoblasts, which are large cells with a high nucleus-to-cytoplasm ratio. Pronormoblasts then differentiate into basophilic normoblasts, which exhibit basophilic cytoplasm due to the presence of ribosomes.

Next, basophilic normoblasts mature into polychromatic normoblasts, characterized by a reduction in cell size and an increase in hemoglobin synthesis. These cells have a polychromatic appearance due to the combination of basophilic and acidophilic staining properties.

Orthochromic normoblasts follow the polychromatic normoblast stage, and they display an orthochromatic or acidophilic appearance. These cells have a pyknotic nucleus, indicating nuclear condensation.

Polychromatic erythrocytes are the subsequent stage, representing immature red blood cells with a residual amount of RNA. Finally, these cells lose their remaining RNA and become mature erythrocytes, also known as red blood cells.

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Homeostasis Response to stimuli Reproduction Evolution/Adaption Growth Organization Metabolism 1. Which of the abovementioned characteristics of living things does fire exhibit? Justify your answer.

Answers

Out of all the abovementioned characteristics of living things, fire exhibits only one characteristic, which is 'metabolism'.Living things can be defined as entities that have a set of characteristics that distinguish them from non-living things.

Homeostasis Response to stimuli Reproduction Evolution/Adaption Growth Organization MetabolismOut of all these characteristics, fire exhibits only one of them, which is 'metabolism'.Metabolism is a chemical process that occurs in the living organism to sustain life. It is the chemical reactions that happen in an organism's cells to keep it alive, like breathing, digestion, and blood circulation.

Fire is dependent on other factors to exist, and it can not sustain life on its own, unlike living organisms, which can produce their energy and perform their chemical reactions to survive. Therefore, it is safe to say that fire only exhibits the characteristic of metabolism among the above mentioned characteristics of living things.

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If
Jenny wants to lose weight and her resting metabolic rate is 1500
kcal what should her daily caloric intake be?

Answers

Based on Jenny's resting metabolic rate (RMR) of 1500 kcal, her daily caloric intake for weight loss should be approximately 1800 kcal (assuming a sedentary lifestyle and using a rough estimate).

To determine Jenny's daily caloric intake for weight loss, we need to consider her resting metabolic rate (RMR) and create a calorie deficit. The RMR is the number of calories her body needs to maintain basic bodily functions at rest. However, to calculate the specific caloric intake for weight loss, we require additional information such as her activity level, age, weight, and height. These factors play a crucial role in determining an individual's total daily energy expenditure (TDEE) and the appropriate caloric deficit for weight loss.

Assuming Jenny has a sedentary lifestyle, a rough estimate can be made by multiplying her RMR by an activity factor of 1.2. This factor accounts for minimal physical activity. Therefore, her estimated daily caloric intake for weight loss would be around 1500 kcal * 1.2 = 1800 kcal.

However, it's important to note that this is a rough estimate, and for more accurate results, consulting a healthcare professional or registered dietitian would be recommended. They can consider Jenny's specific needs, goals, and provide personalized guidance to ensure a safe and effective weight loss plan.

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If 50DD/dd pairs of parrots mate, and each pair has 2 offspring, how many of the 100 offspring would you expect to be Dd? A. 0 B. 100 C. 75 D. 50

Answers

If 50DD/dd pairs of parrots mate and each pair has two offspring, the 100 offspring would you expect to be Dd is B. 100.

As the given problem already specifies the genotype of parents, we can apply the rules of Mendelian Genetics to solve it. If both parents are heterozygous, they carry a dominant allele (D) and a recessive allele (d) each. So, we get: 50 DD/dd pairs of parrots. Each pair has 2 offspring. Total offspring produced= 50 DD x 2 + 50 dd x 2 = 200

Offspring that would be Dd: From the above, 50DD/dd pairs are there, so 50% of pairs are expected to have Dd offspring, so 100 Dd offspring are expected. In conclusion, the expected number of Dd offspring in 100 offspring produced by 50DD/dd pairs of parrots mating is 100. Therefore, the correct option is B. 100.

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The levels of which hormones dramatically decrease at the end of the previous ovarian cycle, promoting the secretion of hormones from the anterior lobe of the pituitary gland? [mark all correct answers] a. estrogen b. progesterone c. follicle stimulating hormpne (FSH) d. luteinizing hormone (LH) Which of these occur during the secretory phase of the uterine cycle? [mark all correct answers] a. the enodmetrium becomes more vascularized b. the endometrial glands stop secreting glycogen c. the cervical mucus becomes less thick d. The endomethim becomes thicker and filled with nutrients

Answers

The correct answers to the first question are c. follicle-stimulating hormone (FSH) and d. luteinizing hormone (LH).The levels of follicle-stimulating hormone (FSH) and luteinizing hormone (LH) dramatically decrease at the end of the previous ovarian cycle, promoting the secretion of hormones from the anterior lobe of the pituitary gland.

The secretion of these hormones stimulates follicular growth and development during the early stage of the ovarian cycle.The correct answers to the second question are a. the endometrium becomes more vascularized and d. The endometrium becomes thicker and filled with nutrients.Both the endometrium becomes thicker and filled with nutrients and the endometrium becomes more vascularized occur during the secretory phase of the uterine cycle. In the secretory phase, progesterone and estrogen promote the continued growth of blood vessels and glands in the endometrium, preparing it for implantation in the event of fertilization. During the secretory phase, the endometrial glands begin secreting glycogen. Additionally, the cervical mucus becomes thicker during the secretory phase, which makes it more difficult for sperm to enter the uterus.

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2. Artificial Selection - Explain how artificial selection is like natural selection. - Why are quail useful subjects for an experiment on selection? What other organisms share similar characteristics

Answers

Artificial selection is like natural selection in that both involve the selective breeding of organisms to produce desired traits. Quail are useful subjects for selection experiments due to their short generation time, ease of care, and diverse phenotypes. Other organisms with similar characteristics include fruit flies, mice, and plants like corn and wheat.

Artificial selection, similar to natural selection, involves the process of selectively breeding organisms to perpetuate specific traits over generations. In both cases, the traits that confer a reproductive advantage are favored and passed on, leading to the accumulation of desired characteristics. Quail are particularly useful subjects for selection experiments because they possess several advantageous attributes. They have a relatively short generation time, allowing for quicker observation of trait inheritance. Quail are also easy to care for in a laboratory setting, making them ideal for controlled experiments. Additionally, quail exhibit diverse phenotypes, providing researchers with a wide range of traits to study. Other organisms such as fruit flies, mice, and certain plants like corn and wheat share similar characteristics and are commonly used in artificial selection experiments.

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If there was a blockage within the nasopharynx, how would the process of ventilation be affected? Airflow into into the pharynx would be completely blocked Air could still flow through the oral cavity into the oropharynx Air could flow directly from the atmosphere into the laryngopharynx What is the main response elicited by the chemoreceptor reflex? Changes to the heart rate and stroke volume Changes to smooth muscle in the tunica media of blood vessels Changes to the rate and depth of ventilation In which of these scenarios would the organ receive the lowest rate of blood flow? The stomach while no food is being digested The brain while taking an exam A skeletal muscle while exercising The heart during an extremely stressful moment When being transported in the blood stream, 1.5% of the oxygen and 7% of the carbon dioxide are dissolved in the plasma. Why is more carbon dioxide dissolved in the plasma than oxygen? Carbon dioxide is unable to bind with hemoglobin Carbon dioxide is more soluble in water There is more total carbon dioxide than water in the body

Answers

1. We can see here that if there was a blockage within the nasopharynx, airflow into the pharynx would not be completely blocked.

2. The main response elicited by the chemoreceptor reflex is changes to the rate and depth of ventilation.

3. The organ that would receive the lowest rate of blood flow in the scenario you described is the stomach while no food is being digested.

What is nasopharynx?

The nasopharynx is a region located at the back of the nasal cavity, above the soft palate and behind the nose. It is the upper part of the pharynx (throat) and serves as a pathway for air to travel from the nasal passages to the rest of the respiratory system.

4. More carbon dioxide is dissolved in the plasma than oxygen because carbon dioxide is more soluble in water than oxygen.

The nasopharynx is the part of the pharynx that is located behind the nose. It is responsible for warming and moistening the air that we breathe. If there was a blockage in the nasopharynx, it would make it difficult for air to reach the lungs.

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Reverse transcription refers to_______________- the production of an exact DNA copy of a DNA molecule the production of an RNA copy of a DNA sequence the production of a protein from an RNA transcript the production of a DNA copy of an RNA sequence

Answers

Reverse transcription refers to the production of a DNA copy of an RNA sequence, option D is correct.

It is catalyzed by an enzyme called reverse transcriptase. This enzyme uses the RNA molecule as a template to synthesize a complementary DNA (cDNA) strand. Reverse transcription plays a crucial role in various biological processes. One important application is in the study of gene expression, where reverse transcription is used to convert RNA molecules into cDNA, which can then be amplified and analyzed.

This technique, known as reverse transcription polymerase chain reaction (RT-PCR), allows researchers to measure gene expression levels and detect specific RNA molecules. Additionally, reverse transcription is a key step in the life cycle of retroviruses, such as HIV, which use reverse transcriptase to convert their RNA genome into DNA for integration into the host cell's genome, option D is correct.

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The complete question is:

Reverse transcription refers to_______________

A) the production of an exact DNA copy of a DNA molecule

B) the production of an RNA copy of a DNA sequence

C) the production of a protein from an RNA transcript

D) the production of a DNA copy of an RNA sequence

Final answer:

Reverse transcription is the process where a DNA copy is made from an RNA sequence, enabled by an enzyme called reverse transcriptase. It is a usual procedure for retroviruses to reproduce inside host cells. The process is also important in biotechnological applications, including gene cloning, expression analysis, and viral infection diagnosis.

Explanation:

Reverse transcription refers to the production of a DNA copy of an RNA sequence. This bio-molecular process involves a unique enzyme called reverse transcriptase. The reverse transcriptase catalyzes the production of a DNA molecule from an RNA template, differing from the normal transcription process where an RNA molecule is synthesized from a DNA template.

In the framework of cellular biology, this process is utilized by retroviruses, which are a group of RNA viruses. After these viruses penetrate a host cell, they use reverse transcription to generate a DNA copy of their RNA genomes. This DNA is then incorporated into the host's genome, enabling the virus to hijack the host cell's machinery to produce more viruses.

In research and biotechnology, reverse transcription is a crucial component of the reverse transcriptase polymerase chain reaction (RT-PCR), a laboratory method widely used in gene cloning, gene expression analysis and the diagnosis of viral infections like HIV and COVID-19.


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a) In another cross involving parent plants of unknown genotypes, the offspring shown below were obtained. Determine the genotypes and phenotypes of parents.

Offspring: 3/8 full,round

3/8 full, wrinkled

1/8 constricted , round

1/8 constricted, wrinkled

Answers

The genotypes of the parents were AaBbCc, and their phenotypes cannot be determined from the given information.

A cross involving parent plants of unknown genotypes produced the following offspring: 3/8 full, round; 3/8 full, wrinkled; 1/8 constricted, round; and 1/8 constricted, wrinkled. The genotypes and phenotypes of the parents can be determined using the principle of segregation and independent assortment.

According to Mendelian genetics, traits are inherited as discrete units called genes, and each individual has two copies of each gene, one from each parent. The two copies can be identical or different, and they are called alleles. If the two alleles at a given locus are the same, the individual is homozygous for that gene; if they are different, the individual is heterozygous. When gametes are formed, the two alleles separate randomly, so each gamete carries one allele for each gene.

In the given case, the full/round and full/wrinkled offspring indicate that the parents were both heterozygous for two different genes, and the two genes are not linked on the same chromosome. The constricted/round and constricted/wrinkled offspring indicate that the parents were both heterozygous for a third gene that is not linked to the other two. Using the following symbols for the alleles, we can represent the genotypes of the parents:

P: AaBbCc x AaBbCc

F1: AB, Ab, aB, ab, AC, Ac, aC, ac

These eight possible gametes can combine randomly to produce the following offspring:

3/16 AB full/round

3/16 Ab full/wrinkled

3/16 aB full/round3

/16 ab full/wrinkled

1/16 AC constricted/round

1/16 Ac constricted/round

1/16 aC constricted/wrinkled

1/16 ac constricted/wrinkled

Therefore, the genotypes of the parents were AaBbCc, and their phenotypes cannot be determined from the given information.

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Case Study
Mrs. Moore is a 54-year-old high school teacher. She has been diagnosed with psoriasis. Presently, she has a few patches on her arms and legs, but not an extensive amount. She asks you to give her more information about her disorder.
Questions
Will the condition get worse, and will it eventually heal?
What can she do to relieve the symptoms?
Is her condition contagious, genetic, and what might cause it to get worse?
Where might you refer her for more information?
What is her long-term prognosis?

Answers

Psoriasis is a chronic condition that can persist throughout a person's lifetime.

While there is no cure, the condition's severity can vary over time, with periods of improvement and exacerbation. Mrs. Moore can manage her symptoms by following a few strategies. Regularly moisturizing the skin, avoiding triggers, using prescribed topical treatments, and considering phototherapy or systemic medications are all potential options. It's important to note that psoriasis is not contagious but may have a genetic component.

Triggers such as stress, infections, medications, and environmental factors can exacerbate symptoms. Mrs. Moore can seek more information from reliable sources like the National Psoriasis Foundation or consult a dermatologist for specialized guidance. With appropriate management, most individuals with psoriasis can lead fulfilling lives, although regular monitoring and treatment adjustments may be necessary.

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he "Great Migration" from Samoa to Hawaii during the 1950s was a result of
Select one:
a. The overcrowding of Samoan villages following the post-war "baby boom"
b. An offer by the United States Navy for Samoan employees to relocate to find new jobs
c. Widespread famine on Samoa caused by years of drought and poor harvests
d. Population displacement caused by the destruction of alrge areas of Samoa during WWII

Answers

The option (b) appears to be the most plausible explanation for the migration.The "Great Migration" from Samoa to Hawaii during the 1950s was a result of a specific cause among the options provided.

To determine the correct answer, we need to analyze the historical context and factors that influenced the migration.

Among the given options, the most likely answer for the "Great Migration" from Samoa to Hawaii during the 1950s is option (b): An offer by the United States Navy for Samoan employees to relocate to find new jobs.

During the post-war period, the United States Navy sought to recruit workers for various industries, including military bases and naval installations. This recruitment effort led to opportunities for Samoan employees to relocate to Hawaii and find new jobs. The promise of employment and a potentially better life in Hawaii likely motivated many Samoans to migrate during that time.

Factors such as overcrowding, famine, and population displacement due to WWII are not historically documented as primary reasons for the Great Migration from Samoa to Hawaii during the 1950s.

Therefore, option (b) appears to be the most plausible explanation for the migration.

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Which researcher proposed that change was caused by the environment acting directly on an organism, and that those changes acquired in an organism's lifetime were passed on to its offspring? Gould Darwin Wallace Lamarck Allison

Answers

The researcher who proposed that change was caused by the environment acting directly on an organism and that those changes acquired in an organism's lifetime were passed on to its offspring was Jean-Baptiste Lamarck.

The correct option is D.

Jean-Baptiste Lamarck, a French biologist, proposed the theory of inheritance of acquired characteristics, also known as Lamarckism. According to Lamarck, an organism could change its traits during its lifetime in response to the environment, and these acquired traits could be inherited by its offspring. Lamarck's theory was influenced by his observations of the natural world and the idea that organisms adapt to their environment.

It is important to note that Lamarck's theory was significant in the history of evolutionary thought as it contributed to the development of evolutionary concepts and stimulated further scientific inquiry into the mechanisms of evolution. However, subsequent research and discoveries in genetics and molecular biology have provided a more accurate understanding of how traits are inherited and how populations evolve over time.

Hence , D is the correct option

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NEW ANSWER PLEASE
Describe an injury of the knee or hip. What muscle group(s)
would be important to target in the rehabilitation process?
Why?

Answers

The knee joint is one of the largest and most complex joints in the human body. Knee injuries can be severe and may require surgery in some cases. Knee injuries can affect the meniscus, ligaments, bones, or tendons. Injuries to the knee can be caused by a sudden movement or a gradual buildup of pressure over time.

The hip joint is also a complex joint and is responsible for the majority of the body's weight-bearing activities. Hip injuries can be caused by trauma, repetitive stress, or degenerative conditions like arthritis.
Injuries of the knee or hip can result in decreased mobility, muscle weakness, and chronic pain. Rehabilitation plays a critical role in the recovery process for knee and hip injuries. Rehabilitation aims to help patients regain strength, mobility, and flexibility. Depending on the severity of the injury, rehabilitation may be a long-term process.
The muscle groups that are important to target in the rehabilitation process for knee and hip injuries include the quadriceps, hamstrings, glutes, and hip flexors. These muscle groups play a significant role in stabilizing the knee and hip joints and supporting movement. Strengthening these muscle groups can help prevent future injuries and improve overall physical performance.
Quadriceps and hamstrings are the main muscle groups that need to be targeted in knee injuries. Quadriceps can be worked out by doing leg extensions and squats. Hamstrings can be worked out by doing hamstring curls. These exercises will help in the process of rehabilitation by building up strength in the knee joint and restoring full range of motion.
For hip injuries, exercises that target the glutes and hip flexors are important. Hip flexor exercises can be done by using resistance bands or cables to work the muscles. For glutes, exercises such as squats and lunges can be performed to strengthen the muscles and improve mobility.
In conclusion, rehabilitation is an essential component of the recovery process for knee and hip injuries. Targeting the right muscle groups through exercises can help patients regain strength, mobility, and flexibility in the affected joint. The quadriceps, hamstrings, glutes, and hip flexors are important muscle groups to focus on in the rehabilitation process.

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You are walking along the beach and step on a broken seashell OUCHII Thankfully it doesn't break the skin, but it hurts What components of the nervous system must be in place for you to feel this type of stimulus? Name and explain the components and pathway.

Answers

To feel the stimulus of stepping on a broken seashell, several components of the nervous system must be in place. The process involves sensory receptors, sensory neurons, the spinal cord, and the brain.

The pathway can be summarized as follows: sensory receptors in the foot detect the stimulus, sensory neurons transmit the signals to the spinal cord, and the spinal cord relays the information to the brain for perception and interpretation of pain.

1. Sensory receptors: These specialized cells, located in the skin of your foot, detect the mechanical pressure and damage caused by stepping on the seashell. They convert this physical stimulus into electrical signals.

2. Sensory neurons: The electrical signals generated by the sensory receptors are transmitted through sensory neurons, which carry the information from the foot to the central nervous system.

3. Spinal cord: The sensory neurons relay the information to the spinal cord, which acts as a relay station. In the spinal cord, the signals are processed and integrated.

4. Brain: From the spinal cord, the signals are further transmitted to the brain, specifically the somatosensory cortex. This region of the brain receives and processes sensory information, allowing you to perceive and localize the pain.

Overall, the components involved in this pathway allow you to sense and respond to the stimulus of stepping on the broken seashell, helping you avoid potential harm and adjusting your behavior accordingly.

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41. What makes up the internal environment of the human body?
44. (a) What is deamination?
(b) Why is deamination?

Answers

The internal environment of the human body is composed of various components, including body fluids, blood, and cellular fluids.

The internal environment of the human body refers to the conditions and substances present within the body that are essential for maintaining homeostasis and supporting proper physiological functioning. It includes various components that work together to ensure the body's optimal performance.

Body fluids, such as blood, lymph, and interstitial fluid, are vital components of the internal environment. These fluids circulate throughout the body, transporting nutrients, oxygen, hormones, and waste products to and from cells. They help maintain the balance of solutes, pH, and temperature necessary for cellular function.

Blood, specifically, plays a crucial role in the internal environment. It carries oxygen from the lungs to tissues, removes carbon dioxide and other waste products, transports nutrients from the digestive system, and carries hormones to target organs or tissues. Additionally, blood helps regulate body temperature, maintain pH balance, and defend against infections through its immune components.

At a cellular level, the internal environment consists of cellular fluids, including cytoplasm and intracellular fluid. These fluids provide a medium for cellular metabolic reactions, regulate the concentration of ions and nutrients within cells, and facilitate communication and transport processes.

In summary, the internal environment of the human body comprises body fluids, blood, and cellular fluids, which collectively maintain the necessary conditions for proper physiological functioning.

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4. A 4-year-old Ahmed has been treated of recurrent bacterial infections wish smptiniz yach as cold and diarthoea since his first birthday party. His mother lost her firs son at zyeary with similar symptoms so she's afrad she might lose Ahmed too. His healthy 15-yeareli sister Dede is worried as well. Sample for culture and seneltivity has proven bacteral susceptibility to the avaliable antibiotics.

a. Describe why the boy ONLY started experiendng these symptoms atter his luew birthday party.
b. Justify a diagnostic marker that explains the genetic relatedness of this dversty in the family.
c. His recent FBC results is as follows: WBC-normal, Differential :Lymphocyte Extremely low, Neutrophil - low
I. If you are to investigate his white cells and function, mention
1. Type of antibodies needed.
2. Two Assays to be used.
3. Indicate two possible results from your assays.

Answers

The symptoms in the boy started after his first birthday party, possibly due to exposure to a new pathogen or environmental trigger during the event.

The timing of the symptoms appearing after the boy's first birthday party suggests a potential association between the party and the onset of symptoms. It is possible that the party introduced a new source of bacteria or other infectious agents that the boy came into contact with, leading to recurrent bacterial infections. Parties often involve increased social interactions, sharing of food and drinks, and exposure to different environments, which could contribute to the introduction of new pathogens. However, further investigation is needed to identify the specific cause or trigger for the boy's symptoms and recurrent infections.

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Arrange the following steps of the Kjeldahl nitrogen analysis procedure in order from first to last. I. Distill ammonia into a standard hydrochloric acid solution. II. Neutralize ammonium ion to release ammonia. III. Digest an organic sample with boiling sulfuric acid to convert nitrogen to ammonium ion. IV. Titrate unreacted hydrochloric acid with sodium hydroxide. a. III, II, I, IV b. II, 1, IV, III c. I, IV, III, II d. IV, III, II, I c. III, I, IV, II

Answers

The correct order of the steps in the Kjeldahl nitrogen analysis procedure is: c. I, IV, III, II

The correct order of the steps in the Kjeldahl nitrogen analysis procedure is as follows: first, the organic sample is digested with boiling sulfuric acid to convert nitrogen to ammonium ion (step III). Next, unreacted hydrochloric acid is titrated with sodium hydroxide (step IV) to determine the amount of nitrogen present.

Following that, ammonia is distilled into a standard hydrochloric acid solution (step I) to separate it from the sample. Finally, the released ammonium ion is neutralized to release ammonia (step II).

This order ensures that the nitrogen content of the organic sample is properly converted and separated, allowing for accurate quantification. It is important to follow this sequence to obtain reliable results in the Kjeldahl nitrogen analysis procedure.

Therefore, option c. I, IV, III, II is the correct order.

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Embryonic stem cells are routinely cultured in a medium containing 25 mM glucose. You have ordered medium, because you had run out, but you notice that you have accidentally ordered medium without any glucose in it. So, now you need to add it yourself and your supervisor tells you to make 5 ml of a 5 M stock solution of glucose. How much glucose powder do you weigh in? How much of the 5M stock solution are you adding to 500 mL of medium?

Answers

To make a 5 M stock solution of glucose, you would need to weigh 90.09 g of glucose powder. For the 500 mL of medium, you would add 0.138 mL of the 5 M stock solution.

To calculate the amount of glucose powder needed to make a 5 M stock solution, you can use the formula: mass = moles x molar mass. In this case, the molar mass of glucose is 180.16 g/mol, and the desired concentration is 5 M. Thus, the moles of glucose needed would be 5 moles (concentration) multiplied by 0.005 L (volume) = 0.025 mol. Finally, the mass of glucose can be calculated by multiplying the moles by the molar mass: 0.025 mol x 180.16 g/mol = 4.504 g. Rounding it up, you would weigh approximately 4.50 g of glucose powder.

For adding the 5 M stock solution to 500 mL of medium, you can use the formula: C₁V₁ = C₂V₂, where C₁ and V₁ are the initial concentration and volume, and C₂ and V₂ are the final concentration and volume. Rearranging the formula to solve for V₁, you have V₁ = (C₂V₂)/C₁. Substituting the values, you get V₁ = (5 M x 0.500 L) / 5 M = 0.500 L. Since 1 mL is equal to 0.001 L, the volume in milliliters would be 0.500 L / 0.001 L/mL = 500 mL.

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Discuss the significance of the interactions that prokaryotes
and protists have with other organism, including humans

Answers

The interactions between prokaryotes (such as bacteria) and protists (single-celled eukaryotic organisms) have significant implications for various ecosystems, including their interactions with other organisms, including humans.

Here are some key points highlighting their significance:

Symbiotic Relationships: Prokaryotes and protists can form symbiotic relationships with other organisms. For example, certain bacteria residing in the human gut (prokaryotes) have a mutualistic relationship with the host, aiding in digestion and producing essential vitamins. Similarly, some protists engage in symbiosis with other organisms, such as corals, where they provide nutrients and protection in exchange for a habitat.

Disease-causing Agents: Some prokaryotes and protists are pathogenic, causing diseases in humans and other organisms. Examples include bacterial infections like tuberculosis and foodborne illnesses caused by Salmonella. Protists such as Plasmodium cause malaria, a significant global health concern.

Environmental Impact: Prokaryotes and protists play crucial roles in nutrient cycling, decomposition, and maintaining ecological balance. Prokaryotes contribute to processes like nitrogen fixation, aiding in the conversion of atmospheric nitrogen into a usable form. Protists are involved in the breakdown of organic matter and serve as prey for other organisms, influencing food webs.

Biotechnological Applications: Prokaryotes and protists have extensive applications in various biotechnological processes. Prokaryotes like Escherichia coli are commonly used in genetic engineering and production of valuable compounds such as insulin. Protists like algae are studied for their potential in biofuel production and as a source of pharmaceutical compounds.

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Other Questions
An 8-bit computer has a 16-bit address bus. The first 15 lines of the address are used to select a bank of 32K bytes of memory. The high-order bit of the address is used to select a register which receives the contents of the data bus. Explain how this configuration can be used to extend the memory capacity of the system to eight banks of 32K bytes each, for a total of 256K bytes of memory. Show the design if any. (a) What is an optimal code for the following set of frequencies for a set of seven symbols? $1: 1,82: 2, S3 : 4, 84: 8,85: 16, S6 : 32, 87: 64 (b) What is the expected (average) number of bits for encoding a file of 1000 symbols? (c) What is an optimal code for a set of 256 symbols, where frequency of ith symbol s, is 2-1, for 1 Practice Problem F You took Loan of 5000 for 24 months on 1% per month, 1- Find A = 23.55 2- Find the interest and principal in the 7th payment? You have isolated different yeast strains that appear to have mutations in DNA replication proteins. At a normal temperature (30 C) the different strains grow normally, but if you grow them at a higher than normal temperature (42 C), the cells stop growing and have incompletely replicated DNA. If you visualize the DNA from the strains, you get the following results. Use your deductive reasoning and state which replication protein is likely inactive at the higher temperature. Mutant 1: The DNA from one strand is in small pieces (all approximately the same size). When you treat the DNA with an enzyme that chews up RNA, it becomes smaller still. Mutant 2: The DNA from one strand is in small pieces (all approximately the same size). When you treat the DNA with an enzyme that chews up RNA, its size is unaffected. (It) remains the same size). Mutant 3: You sce only small pieces of RNA. *15-60. Disk A has a mass of 2 kg and is sliding forward on the smooth surface with a velocity (VA)1 = 5 m/s when it strikes the 4-kg disk B, which is sliding towards A at (UB)= 2 m/s, with direct central impact. If the coefficient of restitution between the disks is e=0.4, compute the velocities of A and B just after collision. Prob. 15-60 (VA)1 = 5 m/s A (VB)1 = 2 m/s B Can you show details information on how to solve this problem.Assume that the sizes of processes P2, P3, P4, P5, and P6 are 200K, 125K, 185K, 185K, and 175K, respectively. Calculate the total internal fragmentation and the percentage of memory actually used. Aquatic fungi called hyphomycetes play important roles in decomposing plant material such as leaves in streams and lakes. In many environments, these fungi are the most important decomposers. Some researchers were interested to see how urban pollution influenced the decomposition rate of these fungi so they selected two relatively polluted sites L1 and L6 on a river in Portugal and an unpolluted site (L7) on the same river. At each site they submerged 6 well-separated bags of leaf litter and allowed them to decompose. After a while they measured the amount of fungi present by measuring the amount of ergosterol (the sterol in the cell membranes of fungi instead of cholesterol) and using a conversion factor to convert that into mg of fungal biomass per g of the leaf sample. They wanted to know if decomposition rates were different at these sites (by measuring fungal production). For these data "L1" = 1, "L6" = 2 and "L7" = 3.record.numbersite fungal.production1 L1 68.632 L1 90.873 L1 100.684 L1 82.575 L1 104.546 L1 75.487 L6 70.98 L6 93.439 L6 68.3310 L6 80.5611 L6 71.1212 L6 96.7913 L7 123.6614 L7 155.8315 L7 110.8516 L7 119.6317 L7 153.3518 L7 135.87For the fungal biomass example above:Which pairs of sites are significantly different from each other, based on the Tukey test?Group of answer choicesThe Tukey test was not appropriate for the analysis of these data.L7 and L1L7 and L6L6 and L1 An instructor knows from past experience that student exam scores have mean 77and standard deviation 15. At present the instructor is teaching two separate classes- one of size 25 and the other of size 64.a) Approximate the probability that the average test score in the class of size 25 lies between72 and 82.b) Repeat part a) for class of size 64.c) What is the approximate probability that the average test score in the class of size 25 ishigher than that of the class of size 64.d) suppose the average scores in the two classes are 76 and 83. Which class , the one of size 25or the one of size 64 , do you think was more likely to have averaged 83. Solve for x, whereu = (3, 3, 2),v = (0, 4, 3),andw = (0, 3, 1).5u 2x = 3v + w 9. 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If a processor has a CPI of 2 and runs at 2GHz, How much time does it need to execute 10 instructions? Select one: NO a. 1 sec O b. 0.001 sec O c. 0.004 sec O d. 4 sec e. None of the above Clear my choice Consider the limit lim (x,y)(0,0)2x 2 +y3x 2 +y 2 and consider the approaches along y=0 and x=0. Which of the following is a correct conclusion of the two-line test? A. The approach y=0 yields the limit 23 while the approach x=0 yields 0 . Therefore the limit does not exist. B. The approach y=0 yields the limit 23 while the approach x=0 yields 00 . Therefore we cannot conclude whether the limit exists yet. C. The approach y=0 yields the limit 0 while the approach x=0 yields the limit 0 . Therefore the limit exists. D. The approach y=0 yields the limit 0 while the approach x=0 yields the limit 0 . Therefore we cannot conclude whether the limit exists yet. E. The approach y=0 yields the limit 0 while the approach x=0 yields the limit 0 . Therefore the limit does not exi Sanborn Inc. is a new manufacturing company founded on February 2, 2012. The company had to choose between the LIFO and FIFO methods for its inventory. Inventory costs were rising during 2012, so the company decided to use the LIFO method. Which of the following items would be decreased by the choice of LIFO (compared to what would have happened if they chose to use FIFO)? (check all that apply) a.Retained Earnings b.SG&A Expense c.Accounts d.Payable Inventory e.Total Assets Child [] objc = new Child [2]; objc [0].dummyA (); 7. Child is a Java class with one (1) public method named dummy A(). objC is an array of objects of class Child. When compiled, the above code will trigger an error. What causes the error? CS - Design and Analysis of Computer AlgorithmsPlease help me understand/explain - (show work):Purpose of this problem is not to write computer code, but rather:i. prove correctness ( ie. 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