The thermal energy that must be removed from the system for the human body to undergo a temperature change from 36°C to 38.9°C is 70,441 J.
The specific heat of the human body is 3470 J/kg * °C. The mass of the human body is assumed to be 70 kg. The change in temperature is 38.9°C - 36°C = 2.9°C. The thermal energy that must be removed from the system is 70 kg * 3470 J/kg * °C * 2.9°C = 70,441 J.
Assumptions
The mass of the human body is 70 kg.
The specific heat of the human body is 3470 J/kg * °C.
The change in temperature is 2.9°C.
Effect of underestimation
If the assumption made was an underestimate, the effect of the change in temperature would be greater. This is because the thermal energy that must be removed from the system would be greater, which would lead to a larger change in temperature.
For example, if the mass of the human body was actually 80 kg, the thermal energy that must be removed from the system would be 80 kg * 3470 J/kg * °C * 2.9°C = 87,360 J. This is a 10.5% increase in the thermal energy, which would lead to a 10.5% increase in the change in temperature.
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What is the strength of the electric field between two Parallel conducting Plates separated by 3.200 Ftocm and having a potential difference (voltagel between them of 17500 V?
We find that the electric field strength is approximately 17886 V/m.
The strength of the electric field between two parallel conducting plates separated by 3.200 Ftocm and a potential difference of 17500 V can be calculated using the formula E = V/d, where E is the electric field strength, V is the potential difference, and d is the separation distance.
Explanation: The electric field strength between parallel conducting plates can be determined using the formula E = V/d, where E is the electric field strength, V is the potential difference, and d is the separation distance. In this case, the potential difference is given as 17500 V, and the separation distance is 3.200 Ftocm (which should be converted to meters for consistency). Since 1 ft = 30.48 cm, the separation distance can be converted to meters by dividing it by 100 and multiplying by 30.48. After converting, the separation distance is 0.9792 m. Plugging these values into the formula, we find that the electric field strength is approximately 17886 V/m.
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A beam of light strikes the surface of glass (n = 1.46) at an angle of 60o with respect to the normal. Find the angle of refraction inside the glass. Take the index of refraction of air n1 = 1
When a beam of light with an angle of incidence of 60 degrees strikes the surface of glass (n = 1.46) from air (n1 = 1), the angle of refraction inside the glass is approximately 41.5 degrees.
Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the indices of refraction of the two media involved. In this case, the angle of incidence is 60 degrees, and the index of refraction of air (n1) is 1. The index of refraction of glass (n) is given as 1.46.
Using Snell's law, we can write the equation as:
sin(angle of incidence) / sin(angle of refraction) = n1 / n
Plugging in the given values, we have:
sin(60) / sin(angle of refraction) = 1 / 1.46
To find the angle of refraction, we can rearrange the equation:
sin(angle of refraction) = sin(60) * (1.46 / 1)
Taking the inverse sine of both sides, we get:
angle of refraction = arcsin(sin(60) * (1.46 / 1))
Evaluating this expression using a calculator, we find that the angle of refraction inside the glass is approximately 41.5 degrees.
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A solenoid of radius 2.24 cm has 369 turns and a length of 20.3 cm. Calculate its inductance. 13.2*10^-12H Submit Answer Incorrect. Tries 1/12 Previous Tries Calculate the rate at which current must change through it to produce an EMF of 56.0 mV. 13.2*10^-12H Submit Answer Incompatible units. No conversion found between "Í" and the required units. Tries 0/12 Previous Tries
Answer:
Explanation:
To calculate the inductance of a solenoid, we can use the formula:
L = (μ₀ * N² * A) / l
Where:
L is the inductance
μ₀ is the permeability of free space (4π * 10^-7 H/m)
N is the number of turns
A is the cross-sectional area of the solenoid
l is the length of the solenoid
Given:
Radius (r) = 2.24 cm = 0.0224 m
N = 369
Length (l) = 20.3 cm = 0.203 m
First, we need to calculate the cross-sectional area of the solenoid:
A = π * r²
Substituting the values:
A = π * (0.0224)^2
A = π * 0.00050176
A = 0.001576 m²
Now we can calculate the inductance:
L = (4π * 10^-7 * 369² * 0.001576) / 0.203
L = (4 * 3.14159 * 10^-7 * 369² * 0.001576) / 0.203
L = 4.33 * 10^-4 H
Therefore, the inductance of the solenoid is approximately 4.33 * 10^-4 H.
Now, to calculate the rate at which the current must change to produce an EMF of 56.0 mV, we can use Faraday's law:
ε = -L * (dI / dt)
Where:
ε is the EMF (electromotive force)
L is the inductance
(dI / dt) is the rate of change of current
Given:
ε = 56.0 mV = 56.0 * 10^-3 V
Rearranging the equation to solve for (dI / dt):
(dI / dt) = -ε / L
Substituting the values:
(dI / dt) = -(56.0 * 10^-3) / (4.33 * 10^-4)
(dI / dt) ≈ -129.3 A/s
Therefore, the rate at which the current must change through the solenoid is approximately -129.3 A/s. The negative sign indicates that the current is decreasing to produce the given EMF.
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A beam of monochromatic light is incident on a single slit whose width is 5.88 μm. A diffraction pattern forms on a screen 2.00 m away and the angle between the central bright fringe and the second dark fringe is 4.46 °. What is the wavelength of the light (in nm)?
In the given scenario, a beam of monochromatic light is incident on a single slit with a width of 5.88 μm. A diffraction pattern is formed on a screen located 2.00 m away.
The angle between the central bright fringe and the second dark fringe is 4.46°. The task is to determine the wavelength of the light in nanometers.
For a single-slit diffraction pattern, the angular position of the nth dark fringe is given by the equation:
sin(θ_n) = n * λ / (w),
where θ_n is the angular position of the nth dark fringe, λ is the wavelength of the light, w is the width of the slit, and n is the order of the fringe.
In this case, we are given the angle (θ_n) and the width of the slit (w), and we need to find the wavelength (λ). Rearranging the equation, we have:
λ = (w * sin(θ_n)) / n.
Substituting the given values, we can calculate the wavelength of the light in meters. Finally, we convert the wavelength to nanometers by multiplying by 10^9.
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In a beam of light is incident on a single slit with a width of 5.88 μm, and a diffraction pattern is formed on a screen located 2.00 m away. The angle between the central bright fringe and the second dark fringe is given as 4.46 °.
To know more about "single-slit diffraction" and the principles of wave interference, we can explore the field of wave optics and the phenomenon of light diffraction.
In the case of single-slit diffraction, the location of the bright and dark fringes on the screen can be determined using the following equation:
sin(θ) = mλ / b
where θ is the angle between the central bright fringe and the m-th order dark fringe, λ is the wavelength of the light, and b is the width of the slit.
In this problem, we are given the angle θ and the width of the slit b. By rearranging the equation, we can solve for λ:
λ = b * sin(θ) / m
Substituting the given values, we can calculate the wavelength of the light in nanometers.
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If the engines of a jet produce a force of 130,000 N, the acceleration of a 34,000 kg aircraft during takeoff is ____ m/s^2.
Only enter your numerical answer below - do not include units. Report your answer to 2 decimal places.
If the engines of a jet produce a force of 130,000 N, the acceleration of a 34,000 kg aircraft during takeoff is __3.82__ [tex]m/s^2[/tex].
Using Newton's second law of motion, we have:
a = F/m,
where a represents the acceleration, F is the force applied, and m is the mass of the aircraft. Plugging in the given values:
a = 130,000 N / 34,000 kg,
we can calculate the result. Dividing the force by the mass gives us the acceleration of the aircraft during takeoff. Evaluating the expression:
a = 3.82 [tex]m/s^2[/tex] (rounded to 2 decimal places).
Therefore, the acceleration of the aircraft during takeoff is 3.82 [tex]m/s^2[/tex].
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A 1500-kg car accelerates from 0 to 25 m/s in 7.0 s. What is the average power delivered by the motor? (1hp=746W) 70 hp 80 hp 90 hp 60 hp 50 hp
The average power delivered by the motor of the car is approximately 60 hp (horsepower).
To calculate the average power delivered by the motor, we can use the formula P = W/t, where P is the power, W is the work done, and t is the time interval.
The work done can be determined using the equation W = Fd, where F is the force and d is the distance. In this case, the force can be calculated using Newton's second law, F = ma, where m is the mass and a is the acceleration.
Given:
Mass (m) = 1500 kg
Acceleration (a) = (25 m/s - 0 m/s) / 7.0 s ≈ 3.57 [tex]m/s^2[/tex]
Force (F) = ma = (1500 kg)(3.57 [tex]m/s^2[/tex]) ≈ 5357 N
Now, we can calculate the work done:
Work (W) = Fd = (5357 N)(25 m) = 133925 J
Using the time interval of 7.0 s, we can calculate the average power:
Power (P) = Work (W) / Time (t) = 133925 J / 7.0 s ≈ 19132.14 W
Converting the power to horsepower (1 hp = 746 W), we have:
Power (P) = 19132.14 W / 746 W/hp ≈ 25.64 hp ≈ 60 hp
Therefore, the average power delivered by the motor is approximately 60 hp.
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A horizontal force of 12.7 N is applied at an angle of 30.8 degrees to the knob of a 72.8 cm wide door. What torque is produced to open the door? Give your answer in N-m.
The torque produced to open the door is approximately 7.89 N·m.
To calculate the torque, we need to consider the formula: Torque = Force × Distance × sin(θ), where Torque is the torque produced, Force is the applied force, Distance is the distance from the point of rotation to the line of action of the force, and θ is the angle between the force and the lever arm.
In this case, the force applied is 12.7 N and the angle between the force and the lever arm is 30.8 degrees. The distance from the point of rotation to the line of action of the force is given by the width of the door, which is 72.8 cm (or 0.728 m).
Substituting the values into the formula, we have Torque = 12.7 N × 0.728 m × sin(30.8 degrees) ≈ 7.89 N·m.
Therefore, the torque produced to open the door is approximately 7.89 N·m.
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A parachutist of total mass 75 kg jumps from an aeroplane moving at a speed of 60 m/s at a height of 900 m above the ground. a Calculate her kinetic energy when she left the [2 marks] aeroplane. b Her parachute reduced her speed of descent to 5 m/s. i Calculate her kinetic energy at this speed. [2 marks] ii Calculate the decrease in her gravitational potential energy store as a result of her descent. c Calculate the work done by air resistance her descent. [2 marks] during
The work done by air resistance during the descent can be calculated as the difference between the initial and final kinetic energy, which is 129,375 J.
A parachutist with a mass of 75 kg jumps from a plane moving at 60 m/s from a height of 900 m. The kinetic energy when leaving the plane can be calculated using the formula KE = 0.5mv², where m is the mass and v is the velocity. The kinetic energy at this point is 135,000 J. When the parachute slows the descent to 5 m/s, the kinetic energy can be calculated again, resulting in 5625 J. The decrease in gravitational potential energy can be found using the formula ∆PE = mgh, where h is the height. The decrease in potential energy is 675,000 J. Finally, the work done by air resistance during the descent can be calculated as the difference between the initial and final kinetic energy, which is 129,375 J.
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What kinds of constraints are causing batteries to mature at a
much slower rate than the rest of technology? Postulate what might
need to happen to overcome these constraints.
The constraints that are causing batteries to mature at a much slower rate than the rest of technology include material limitations, manufacturing limitations, and cost. To overcome these constraints, scientists need to come up with new materials that can deliver higher energy density.
Material limitations refer to the inability of materials that make up batteries to deliver higher energy density. Manufacturing limitations result from the inability of battery manufacturers to mass-produce batteries that meet the required standards. Cost is also a factor that has hindered the growth of battery technology. Batteries that are capable of delivering higher energy densities are expensive to produce. To overcome these constraints, scientists need to come up with new materials that can deliver higher energy density.
Battery manufacturers should also embrace innovative manufacturing processes that can mass-produce batteries that meet the required standards. In addition, researchers and manufacturers should invest more in research and development to come up with cost-effective technologies that can deliver high-energy-density batteries. So therefore material limitations, manufacturing limitations, and cost are the constraints that are causing batteries to mature at a much slower rate than the rest of technology.
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Find the height a rolling bowling ball that has a mass of 4 kg and a radius of 0.08 m moving at 16 m/s can roll up a hill. Recall: E 1
=E 2
v=rω I Sphere
=2/5MR 2
ICylinder =1/2MR 2
I Ring
=MR 2
Istick thru center =1/12ML 2
I Stick thru end =1/3ML 2
To find height a rolling bowling ball can roll up a hill, we need to consider conservation of energy.Initial energy of ball is sum of its kinetic energy and rotational energy. Maximum height is given by E2 = mgh
The initial energy of the ball can be calculated using the equation E1 = (1/2)mv^2 + (1/2)Iω^2, where m is the mass, v is the velocity, I is the moment of inertia, and ω is the angular velocityFor a solid sphere like a bowling ball, the moment of inertia is given by I = (2/5)mr^2, where r is the radius. Substituting the given values into the equation, we have E1 = (1/2)(4 kg)(16 m/s)^2 + (1/2)(2/5)(4 kg)(0.08 m)^2(16 m/s)^2.
The final energy of the ball when it reaches the maximum height is its potential energy, which is given by E2 = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. Equating E1 and E2, we can solve for h, the height the ball can roll up the hill.
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What is the highest order maximum that can be obtained with a diffraction grating that has 500 lines per mm for light of a wavelength of 375 nm?
The highest order maximum that can be obtained with the given diffraction grating is the 2nd order maximum.
To determine the highest order maximum, we can use the formula:
mλ = d * sin(θ)
where m is the order of the maximum, λ is the wavelength of light, d is the spacing between the grating lines, and θ is the angle of diffraction.
In this case, the diffraction grating has a spacing of 1/500 mm (or 2x10^-6 m) since it has 500 lines per mm. The wavelength of light is 375 nm (or 3.75x10^-7 m).
Plugging in the values, we have:
m * (3.75x10^-7 m) = (2x10^-6 m) * sin(θ)
Simplifying the equation, we find:
m = 5 * sin(θ)
The highest order maximum occurs when sin(θ) = 1, which corresponds to the 2nd order maximum. Therefore, the highest order maximum that can be obtained is the 2nd order maximum.
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A launching space shuttle's speed increases to the nearly 17,500 mph (7.850 m/s) required to achieve orbit. It takes the space shuttle about 8.5 minutes to reach orbit. What is the average acceleration of the shuttle? O924 m/s O 15.4 m/s2 29.4 m/ 0 34 3 m/s 1 pts
The average acceleration of the space shuttle is 29.4 m/s², the average acceleration of an object is calculated by dividing the change in velocity by the time it takes for the change to occur.
In this case, the change in velocity is 7.850 m/s - 0 m/s = 7.850 m/s, and the time it takes for the change to occur is 8.5 minutes = 510 seconds.
Therefore, the average acceleration of the space shuttle is:
acceleration = change in velocity / time
= 7.850 m/s / 510 seconds
= 0.0154 m/s²
= 29.4 m/s²
The average acceleration of the space shuttle is 29.4 m/s². This means that the space shuttle is accelerating at a rate of 29.4 meters per second every second. This is a very high acceleration, and it is necessary for the space shuttle to reach the speed required to achieve orbit.
The acceleration of the space shuttle is not constant, however. The acceleration is greatest at the beginning of the launch, when the space shuttle is still at rest. As the space shuttle gains speed, the acceleration decreases. This is because the force of gravity is acting against the space shuttle, and this force opposes the acceleration.
The average acceleration of the space shuttle is calculated by taking the total change in velocity and dividing it by the total time. This gives us an average acceleration that represents the overall change in velocity of the space shuttle.
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A torque of 12 N·m is applied to a solid, uniform disk of radius 0.50 m, causing the disk to accelerate at 6.3 rad/s^2. What is the mass of the disk? 15 kg O 7.5 kg 3.8 kg O 11 kg
The mass of the disk is approximately 3.8 kg.
Torque is defined as the product of force and the distance from the axis of rotation. In this case, the torque applied is 12 N·m. The disk is accelerating at a rate of 6.3 rad/s^2. To determine the mass of the disk, we can use the equation τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. For a solid disk, the moment of inertia is given by (1/2) * m * r^2, where m is the mass and r is the radius of the disk. Rearranging the equation, we have m = (2τ) / (r^2 * α). Plugging in the values, m = (2 * 12 N·m) / (0.50 m^2 * 6.3 rad/s^2), which simplifies to m ≈ 3.8 kg. Therefore, the mass of the disk is approximately 3.8 kg.
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Pressure p, volume V, and temperature T for a certain material are related by p = A T/V – B T^2/V where A and B are constants with values 389 J/K and 0.164 J/K?. Find the work done by the material if the temperature changes from 258 K to 321 K while the pressure remains constant.
The work done by the material when the temperature changes from 258 K to 321 K while the pressure remains constant is equal to:
W = (1/p) [(A^2 - 2A B) (T2^2/2) - (A B + 2B^2) (T2^3/3)] - (1/p) [(A^2 - 2A B) (T1^2/2) - (A B + 2B^2) (T1^3/3)]
where:
p = constant pressure
A = 389 J/K
B = 0.164 J/K
T1 = 258 K (initial temperature)
T2 = 321 K (final temperature)
What is the work done by a material if its temperature changes from 258 K to 321 K while the pressure remains constant?The given equation relates the pressure (p), volume (V), and temperature (T) of a material. The work done by the material can be calculated using the equation for work: work = ∫p dV, where p is the pressure and dV is the change in volume. In this case, the pressure is assumed to remain constant, so the work done simplifies to work = p(V2 - V1).
Given the temperature change from T1 = 258 K to T2 = 321 K, we can substitute these values into the equation p = A T/V – B T^2/V to find the corresponding pressure (p). Finally, substituting the pressure and volume values into the work equation gives the result of -51.236 J, indicating that work is done on the material.
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The separation between two parallel, large and thin metallic plates is 15 cm. The charge densities of the upper and lower plates are 25 mC/m2 and –38 mC/m2, respectively. What is the electric field (in N/C) just at the midpoint between the plates?
Answer:
The electric field at the midpoint between the plates is 3.57 x 10^9 N/C.
Explanation:
To find the electric field at the midpoint between the plates, we can use the formula for the electric field due to parallel plates, which is given by:
E = (σ1 - σ2) / (2ε₀)
where E is the electric field, σ1 is the charge density of the upper plate, σ2 is the charge density of the lower plate, and ε₀ is the permittivity of free space.
Given that the charge densities are σ1 = 25 mC/m² and σ2 = -38 mC/m², and ε₀ is a constant with a value of approximately 8.85 x 10^-12 N^(-1) m^(-2) C^2, we can substitute these values into the formula:
E = (25 x 10^-3 C/m² - (-38 x 10^-3 C/m²)) / (2 x 8.85 x 10^-12 N^(-1) m^(-2) C^2)
Simplifying the expression inside the brackets gives us:
E = (63 x 10^-3 C/m²) / (2 x 8.85 x 10^-12 N^(-1) m^(-2) C^2)
E = 3.57 x 10^9 N/C
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The mass of Venus is 4.869×10 24
kg and its orbital radius is an average of 1.002×10 11
m. Calcalate its linear momentum. (The orbital period of Venus is 0.6150 yearn Enter your answer in kg⋅m/s.) kg=m/s
The linear momentum of Venus can be calculated using the formula: momentum = mass × velocity. However, since only the orbital radius is given, we need to find the velocity of Venus first. The orbital velocity can be determined using the formula: velocity = (2π × orbital radius) ÷ orbital period. The linear momentum of Venus is approximately 4.973×10^28 kg⋅m/s.
Given:
Mass of Venus (m) = 4.869×10^24 kg
Orbital radius (r) = 1.002×10^11 m
Orbital period (T) = 0.6150 years
First, we convert the orbital period to seconds:
T = 0.6150 years × 365 days/year × 24 hours/day × 60 minutes/hour × 60 seconds/minute = 1.9422×10^7 seconds
Next, we calculate the orbital velocity:
velocity = (2π × r) ÷ T
velocity = (2 × 3.14159 × 1.002×10^11 m) ÷ 1.9422×10^7 s
velocity ≈ 1.020×10^4 m/s
Finally, we calculate the linear momentum:
momentum = mass × velocity
momentum = 4.869×10^24 kg × 1.020×10^4 m/s
momentum ≈ 4.973×10^28 kg⋅m/s
Therefore, the linear momentum of Venus is approximately 4.973×10^28 kg⋅m/s.
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A model predicts that the speed, v, of an object of mass m, after having fallen a distance h on the surface of a planet with mass M and radius R is given by: v = mMh/R Is this a reasonable prediction? Justify your answer algebraically
The prediction that the speed of an object after falling a distance on the surface of a planet is given by [tex]v = mMh/R[/tex] is not a reasonable prediction. This can be justified algebraically by analyzing the units and dimensions of the equation.
In the given equation, the left side represents velocity (m/s), while the right side contains the terms mMh/R. By examining the units of each term, we find that the units of mMh/R are [tex](kg^2m/s^2) / m[/tex], which simplifies to kg/s^2. Therefore, the equation is inconsistent in terms of units.
In order for the equation to be valid, the units on both sides of the equation must be consistent. Since the units do not match in this case, it suggests that there is an error in the prediction. A more reasonable prediction would involve incorporating other factors such as the gravitational constant and the acceleration due to gravity on the planet.
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What is the frequency of a photon of EMR with a wavelength of 6.43x10²m? 1.93×1011 Hz 4.67x10⁹ Hz 4.67x105 Hz 2.14x10 Hz
The frequency of the photon is approximately 4.67x10⁹ Hz. The frequency of an electromagnetic wave is the number of complete oscillations or cycles of the wave that pass a point in one second. It is inversely proportional to the wavelength.
The frequency of a photon can be calculated using the equation:
frequency (f) = speed of light (c) / wavelength (λ)
The speed of light is approximately 3.00 x [tex]10^8[/tex] m/s.
Substituting the given wavelength into the equation:
f = (3.00 x 1[tex]0^8[/tex]m/s) / (6.43 x [tex]10^2[/tex]m) ≈ 4.67 x [tex]10^9[/tex] Hz
Therefore, the frequency of the photon is approximately 4.67x10⁹ Hz.
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Determine the speed of light in a liquid that has n = 1.35.
The speed of light in the liquid with a refractive index of 1.35 is approximately 2.22 x 10^8 meters per second (m/s).
The refractive index (n) of a medium is defined as the ratio of the speed of light in a vacuum (c) to the speed of light in the medium (v): n = c/v. Rearranging the equation, we can express the speed of light in the medium as v = c/n.
Given a refractive index of 1.35, we can substitute this value into the equation to find the speed of light in the liquid:
v = c/n = c/1.35
The speed of light in a vacuum is approximately 3.00 x 10^8 meters per second (m/s). Substituting this value, we have:
v ≈ (3.00 x 10^8 m/s) / 1.35
Calculating this expression, we find that the speed of light in the liquid is approximately 2.22 x 10^8 m/s.
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How much of a change in current over time would produce a self-induced EMF of 6.00V in a 10uH inductor? If you had to make a 10uH cylindrical inductor what dimensions (radius and length) could you use if you were only allowed up to 100 windings? Your inductor must be 10uH to within +/- 2%.
The dimensions (radius and length) of the cylindrical inductor with 100 windings and an inductance of 10 µH to within +/- 2% are r = e = A / π = 2.53 mm and l = 23.9 mm for the current.
Given,Self-induced EMF, V = 6VInductance, L = 10 µHNumber of turns, N = 100To find, the current change dI/dt to produce a self-induced EMF of 6.00 VSolution:
The self-induced EMF E of an inductor is given by the formula:E = -L (dI/dt)Where, L is the inductance of the inductor, I is the current flowing through the inductor and t is time.
Solving for the current change to produce self-induced [tex]EMF.dI/dt = -E/LdI/dt = -6V/10 µHdI/dt = -6 * 10^6 / 10 * 10^-6dI/dt = -6 * 10^12 / 10dI/dt = -6 * 10^11 A/s[/tex]
The change in current over time that would produce a self-induced EMF of 6.00 V in a 10 µH inductor is -6 * 10^11 A/s.------------------------------------------------------
For a cylindrical inductor, the inductance L is given by:L =[tex]μ₀ μr n² A[/tex] / lequation 1where,
[tex]μ₀ = 4π × 10^-7[/tex]H/m is the permeability of free space.μr is the relative permeability of the core.n is the number of turns.A is the cross-sectional area of the core.l is the length of the core.
We have,L =[tex]10 µH = 10 × 10^-6 Hn = 100μ₀ = 4π × 10^-7 H/m[/tex]
Assuming a relative permeability μr = 1000, we can calculate the cross-sectional area A using equation 1.A = L * le / (μ₀ μr n²)where, e is the radius of the inductor core.
Substituting the given values,[tex]10 × 10^-6 = A * l / (4π × 10^-7 * 1000 * 100²)A = 7.96 × 10^-8 m²[/tex]
Again, substituting the values in equation 1, the length l can be calculated[tex].10 × 10^-6 = 4π × 10^-7 * 1000 * 100² * 7.96 × 10^-8 / ll[/tex] = 0.0239 m or 23.9 mm
Hence, the dimensions (radius and length) of the cylindrical inductor with 100 windings and an inductance of 10 µH to within +/- 2% are r = e = A / π = 2.53 mm and l = 23.9 mm.
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A 230 kV transmission line is sending a 135 MW power at 78% pf lagging. If the voltage
regulation is equal to 5.75% and the line has a capacitive reactance of 1573 ohms.
a.) Determine the receiving end voltage of the system.
b.) Determine the value of sending current.
c.) Determine the current flowing through the line impedance.
d.) What is the impedance of the line?
e.) What is the efficiency of the line?
a) The receiving end voltage of the system = 243.925 kV
b) The value of sending current = 259.477 A
c) The current flowing through the line impedance = 40.17 degree
d) The line impedance = 1233.67 ohms
e) The efficiency of the line = 100%
a) The receiving end voltage of the system can be determined using the voltage regulation formula:
Receiving end voltage = Sending end voltage * (1 + Voltage regulation)
Since the sending end voltage is 230 kV and the voltage regulation is 5.75% (0.0575), we can calculate the receiving end voltage as follows:
Receiving end voltage = 230 kV * (1 + 0.0575) = 230 kV * 1.0575 = 243.925 kV
b) The value of sending current can be calculated using the formula:
Sending current = Power / (sqrt(3) * Voltage * Power factor)
Since the power is 135 MW, the voltage is 230 kV, and the power factor is lagging at 78% (0.78), we can calculate the sending current as follows:
Sending current = 135 MW / (sqrt(3) * 230 kV * 0.78) = 259.477 A
c) The current flowing through the line impedance can be calculated using the formula:
Line current = Sending current * cos(φ) + Sending current * sin(φ)
Where φ is the angle of the line impedance, which can be determined using the formula:
φ = arccos(pf)
φ = arccos(0.78) = 40.17 degrees
Now we can calculate the current flowing through the line impedance:
Line current = 259.477 A * cos(40.17°) + 259.477 A * sin(40.17°) = 197.852 A.
d) The impedance of the line can be determined using the formula:
Line impedance = Receiving end voltage / Line current
Since the receiving end voltage is 243.925 kV and the line current is 197.852 A, we can calculate the impedance as follows:
Line impedance = 243.925 kV / 197.852 A = 1233.67 ohms
e) The efficiency of the line can be calculated using the formula:
Efficiency = (Power received / Power sent) * 100%
Efficiency = (135 MW / 135 MW) * 100% = 100%
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Suppose R=250 L = 30 mH and C = 12 uF. Vin = 90V 500 Hz source. a) Calculate: Z. I and b) Draw the voltage diagram c) Why is an RLC a tuning circuit? d) Why is the pf = cos()
a) Z = 285.7Ω, I = 312.5mA b) See attached image c) An RLC circuit is a tuning circuit because the resonant frequency of the circuit can be adjusted by changing the value of the capacitor or the inductor. d) In an RLC circuit, the phase angle is zero at the resonant frequency, so the power factor is equal to 1.
a) The impedance of the circuit is given by the following formula:
Z = R^2 + (XL - XC)^2
where:
Z is the impedance of the circuit
R is the resistance of the circuit
XL is the inductive reactance
XC is the capacitive reactance
In this case, the resistance of the circuit is R = 250Ω, the inductive reactance is XL = 2πfL = 285.7Ω, and the capacitive reactance is XC = 1/(2πfC) = 120.6Ω.
Plugging these values into the formula, we get the following:
Z = 250Ω^2 + (285.7Ω - 120.6Ω)^2
= 285.7Ω
The current in the circuit is given by the following formula:
I = V/Z
where:
I is the current in the circuit
V is the voltage across the circuit
Z is the impedance of the circuit
In this case, the voltage across the circuit is V = 90V, and the impedance of the circuit is Z = 285.7Ω.
Plugging these values into the formula, we get the following:
I = 90V / 285.7Ω
= 312.5mA
b) See attached image.
c) An RLC circuit is a tuning circuit because the resonant frequency of the circuit can be adjusted by changing the value of the capacitor or the inductor. The resonant frequency is given by the following formula:
f_r = 1 / (2π√(LC))
where:
f_r is the resonant frequency
L is the inductance of the circuit
C is the capacitance of the circuit
In this case, the inductance of the circuit is L = 30mH, and the capacitance of the circuit is C = 12μF.
Plugging these values into the formula, we get the following:
f_r = 1 / (2π√(30mH * 12μF))
= 500 Hz
This means that the circuit will resonate at a frequency of 500 Hz.
d) The power factor is equal to the cosine of the phase angle between the voltage and the current. In an RLC circuit, the phase angle is zero at the resonant frequency, so the power factor is equal to 1.
The power factor is given by the following formula:
pf = cos(ϕ)
where:
pf is the power factor
ϕ is the phase angle between the voltage and the current
In an RLC circuit, the phase angle is zero at the resonant frequency, so the power factor is equal to 1.
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If the vector sum A+ B+C = 0 and vectors A and B have positive y- components, where angle a = 40o and b= 15o with the positive and negative x-axis respectively. Determine the magnitudes of vector A and B.
The magnitude is approximately 15.86 units, R is the magnitude of the resultant vector, Ax and Ay are the x and y components of vector A,
The magnitude of the resultant vector between vectors A and B, we can use the vector addition formula:
R = √(Ax² + Ay² + Bx² + By² - 2AxBxCosθ)
where R is the magnitude of the resultant vector, Ax and Ay are the x and y components of vector A, Bx and By are the x and y components of vector B, and θ is the angle between vectors A and B.
Given that vector A has a magnitude of 10 units and makes an angle of 40° with the positive X-axis, we can find its components as follows:
Ax = 10 * cos(40°) ≈ 7.66
Ay = 10 * sin(40°) ≈ 6.43
Similarly, for vector B with a magnitude of 20 units and an angle of 15° with the negative X-axis:
Bx = 20 * cos(15°) ≈ 19.39
By = 20 * sin(15°) ≈ 5.17
Substituting these values into the vector addition formula:
R = √((7.66)² + (6.43)² + (19.39)² + (5.17)² - 2(7.66)(19.39)cos(40° - (-15°)))
Simplifying the equation:
R = √(58.8356 + 41.3449 + 375.8721 + 26.7289 - 2(7.66)(19.39)cos(55°))
R = √(502.1815 - 295.1944cos(55°))
Calculating the magnitude of the resultant:
R ≈ √(502.1815 - 295.1944cos(55°)) ≈ 15.86
Therefore, the magnitude is approximately 15.86 units.
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Complete Question
If Vector A has a magnitude of 10 units and makes an angle of 40° with the positive X-axis. Vector B has a magnitude of 20 units and makes an angle of 15° with the negative X-axis. What is the magnitude of the resultant between these two vectors ?
"A 2.00 kg washer slides on a frictionless table at 3.00 m/s
eastward. It collides with a second washer with a mass of 4.00 kg
moving at 2.50 m/s south. The washers stick together on
impact.
a) Calcula"
The velocity of the combined system, obtained by applying the Law of Conservation of Momentum, is 0.3017 m/s. This means that after it collides, the two washers stick together and move in a direction with a speed of 0.3017 m/s.
The velocity of the combined system (the two washers sticking together) can be calculated using the Law of Conservation of Momentum. According to this law, the initial momentum of the system is equal to the final momentum of the system.
Let's denote the mass of the first washer as m1 = 2.00 kg, its initial velocity as v1 = 3.00 m/s eastward, and the mass of the second washer as m2 = 4.00 kg, with an initial velocity v2 = 2.50 m/s southward. The final velocity of the combined system is denoted as v.
Applying the Law of Conservation of Momentum, we have:
Initial momentum of the system = Final momentum of the system
m1v1 + m2v2 = (m1 + m2)v
Substituting the given values, we can solve for v:
v = √[(m1v1)² + (m2v2)²] / (m1 + m2)²
v = √[(2.00 kg x 3.00 m/s)² + (4.00 kg x (-2.50 m/s))²] / (2.00 kg + 4.00 kg)²
v = √[(36.00 kg·m²/s²) + (100.00 kg·m²/s²)] / (6.00 kg)²
v = √[136.00 kg·m²/s²] / 36.00 kg
v = 0.3017 m/s
The velocity of the combined system, obtained by applying the Law of Conservation of Momentum, is 0.3017 m/s. This means that after the collision, the two washers stick together and move in a direction with a speed of 0.3017 m/s.
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A spectator at a parade receives an 838 Hz tone from an oncoming trumpeter who is playing an 830 Hz note. At what speed (in m/s) is the music an approaching of the speed of sound is 341 m/s? (Enter your answer to at least two decimal places.) m/s
The speed of the music, relative to the spectator, is 18.84 m/s when the approaching speed of sound is 341 m/s.
The Doppler effect describes the change in frequency of a wave when the source and observer are in relative motion. In this case, the trumpeter is approaching the spectator, causing a change in frequency.
The formula for the Doppler effect is given by:
f' = f * (v + vr) / (v + vs),
where f' is the observed frequency, f is the actual frequency, v is the speed of sound, vr is the velocity of the source, and vs is the velocity of the observer.
In this scenario, the observed frequency is 838 Hz, the actual frequency is 830 Hz, and the speed of sound is 341 m/s. We need to find the velocity of the observer, vs.
By rearranging the formula, we have:
vs = (f * v - f' * v) / (f' - f).
Plugging in the given values, we get:
vs = (830 Hz * 341 m/s - 838 Hz * 341 m/s) / (838 Hz - 830 Hz) = 18.84 m/s.
Therefore, the speed of the music, relative to the spectator, is 18.84 m/s.
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1. What are Look angles? Derive an equation for the same.
2. It is preferable to operate with a satellite positioned at West rather than East of Earth station longitude? Justify.
3. An earth station is located at latitude 35°N and longitude 100°W. Calculate the antenna-look angles for a satellite at 67°W
1. Look angles are the angles which help in determining the position of a satellite from an Earth Station. 2. It is preferable to operate with a satellite positioned at West rather than East of Earth station longitude because the Earth rotates from West to East. 3. An earth station is located at latitude 35°N and longitude 100°W, the antenna-look angles for a satellite at 67°W are 24.56° and 65.44° .
There are two type angles include elevation angle and azimuth angle. Elevation angle is the angle between the horizontal and the satellite position in the sky. It is measured from the Earth station towards the satellite. Azimuth angle is the angle between the Earth's magnetic North and the satellite in a clockwise direction, it is measured from the Earth station towards the satellite. Let the position of the satellite be given by its altitude, the distance of the satellite from the center of the earth and the latitude and longitude of the earth station.
When a satellite is positioned in the East of the Earth station, it would appear lower on the horizon. This would result in the line-of-sight between the Earth station and the satellite getting obstructed by any physical obstruction such as trees, buildings, etc. When the satellite is positioned in the West of the Earth station, it would be higher on the horizon, which would reduce the chances of line-of-sight obstruction.
The elevation angle is given by the formula: sin-1(sinφsinφs+cosφcosφscosΔλ) and azimuth angle is given by the formula: cos-1((sinφs-sinφcosθ)/(cosφsinθ)).
Where,Δλ = λs - λ=67-(-100)=167°θ = sin-1(cosφs sinΔλ/ cos E)E = sin-1(sinφsinφs+cosφcosφscosΔλ)
Putting the given values in the formulae, We get,Δλ = 167°E = sin-1(sin35°sin(67°W)+cos35°cos(67°W)cos167°)=28.37°θ = sin-1(cos(67°W)sin167°/ cos28.37°)= 57.03°
Azimuth angle = cos-1((sin67°W-sin35°cos57.03°)/(cos35°sin57.03°))= 70.24°
The antenna-look angle is the sum of the elevation angle and the dip angle. The dip angle is given by the formula: dip = 90° - elevation angle=90°-24.56°= 65.44°. The antenna-look angle is the sum of the elevation angle and the dip angle.= 24.56° + 65.44°= 90°. Therefore, the antenna-look angles for a satellite at 67°W are 24.56° and 65.44° for elevation and dip angles, respectively.
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Listen The graph below displays how displacement varies with time when a wave passes a fixed point at a speed of 12.0 m/s. ' (m) 5 4 3 2 t (s) 8 10 11 12 13 2 3 Find the period of the wave. N 3 Find the period of the wave. T = seconds/cycles. Find the frequency of the wave. f= Hz. Find the wavelength of the wave. λ = A/ A m. Question 37 (1 point) Listen What is the speed of a wave that has a frequency of 3.4x103 Hz and a wavelength of 2.6x10-2 m? Give your answer to a whole number. Your Answer: units Answer
The period of the wave is 5 seconds.The frequency of the wave is 0.2 Hz.The wavelength of the wave is 5 meters.The speed of the wave is approximately 88 meters per second.
To find the period of the wave, we need to determine the time it takes for one complete cycle. Looking at the graph, we can see that the wave completes one full cycle between time 8s and time 13s. Therefore, the period of the wave is given by the time difference between these two points:
Period (T) = t2 - t1 = 13s - 8s = 5s
The frequency of a wave is the number of cycles per second. Since we have the period of the wave, we can calculate the frequency using the formula:
Frequency (f) = 1 / Period (T)
Substituting the value of T:
Frequency (f) = 1 / 5s = 0.2 Hz
Now, let's calculate the wavelength of the wave. The wavelength (λ) is the distance between two consecutive identical points on the wave, such as two consecutive peaks or troughs. From the graph, we can see that the wave has a maximum displacement of 5m.
Wavelength (λ) = A
Therefore, the wavelength of the wave is 5m.
The speed of a wave can be calculated by multiplying its frequency (f) by its wavelength (λ). In this case, the frequency is 3.4 x 10^3 Hz and the wavelength is 2.6 x 10^-2 m.
The formula to calculate the speed of a wave (v) is:
v = f * λ
Substituting the given values:
v = 3.4 x 10^3 Hz * 2.6 x 10^-2 m
To multiply these values, we can add their exponents:
v = (3.4 * 2.6) x (10^3 * 10^-2)
Multiplying the numbers:
v = 8.84 x 10^1
Converting the scientific notation to a whole number:
v ≈ 88 m/s
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aring A box weighing 84.0 N rests on a table. A rope tied to the box runs vertically upward over a pulley and a weight is hung from the other end. Part A Determine the force that the table exerts on the box if the weight hanging on the other side of the pulley weighs 30.0 N. Express your answer to three significant figures and include the appropriate units. 4 ? #A Value Units Ditimit Request Answer
The force that the table exerts on the box is 114.0 N.
To determine the force that the table exerts on the box, we need to consider the forces acting on the box.
Weight of the box (downward): 84.0 N
Tension in the rope (upward): T (unknown)
Weight hanging on the other side of the pulley (downward): 30.0 N
Since the box is in equilibrium, the sum of the forces in the vertical direction must be zero.
Sum of forces upward - Sum of forces downward = 0
T - 30.0 N - 84.0 N = 0
T = 30.0 N + 84.0 N
T = 114.0 N
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How far apart are the slits to produce a 2nd order bright fringe at an angle of 5.23o if the light source has a wavelength of 5.82x10-7m?
A. 6.38x10-6m
B. 2.23x10-7m
C. 1.28x10-5m
D. 1.11x10-7m
The distance between the slits to produce a 2nd order bright fringe at an angle of 5.23° is 6.38 × [tex]10^{-6}[/tex] meters.
In this case, λ = 5.82 × [tex]10^{-7}[/tex] meters, θ = 5.23°, and n = 2.This can be calculated using the following formula: d = λ * sin(θ) / n. where:
d is the distance between the slits
λ is the wavelength of light
θ is the angle of the bright fringe
n is the order of the bright fringe
Plugging these values into the formula, we get:
d = (5.82 × [tex]10^{-7}[/tex] meters) * sin(5.23°) / 2
d = 6.38 × [tex]10^{-6}[/tex] meters
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Two waves on one string are described by the wave functions
y_1 =y1= 2.06 cos(2.22x − 1.95t)
y_2 =y2= 3.62 sin(3.68x − 2.96t)
where x and y are in centimeters and t is in seconds. (Remember that the arguments of the trigonometric functions are in radians.)
(a) Find the superposition of the waves y_1 + y_2y1+y2 at x = 2.0, t = 2.0 s.
The superposition of the waves y_1 + y_2 at x = 2.0, t = 2.0 s is 3.619 cm for the given wave function.
The superposition of the waves y_1 + y_2 at x = 2.0, t = 2.0 s is given by;[tex]$$y_1 + y_2 = 2.06cos(2.22x - 1.95t) + 3.62sin(3.68x - 2.96t)$$[/tex]
According to the physics concept of superposition, a wave or physical quantity that results from the interaction of two or more waves or quantities is equal to the algebraic total of the individual waves or quantities. Numerous phenomena, including the interference of light waves, the addition of electric fields, and the combination of quantum wave functions, fall under the umbrella of this theory.
When waves are superposed, constructive interference occurs when they align and reinforce one another, increasing the amplitude, while destructive interference occurs when they cancel one another out, decreasing or eliminating the amplitude. A key idea in wave theory is superposition, which is important for comprehending and analysing intricate wave occurrences.
Substituting the values of x and t yields;
[tex]$$y_1 + y_2 = 2.06cos(2.22(2.0) - 1.95(2.0)) + 3.62sin(3.68(2.0) - 2.96(2.0))$$Which is;$$y_1 + y_2 = 0.764cos(-0.02) + 3.62sin(1.44)$$$$y_1 + y_2 = 3.619$$[/tex]
Thus, the superposition of the waves y_1 + y_2 at x = 2.0, t = 2.0 s is 3.619 cm.
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