X corresponds to 20 mm on the thermometer.
To calculate the value of X, we can use the concept of linear interpolation.We can estimate a value between two known points on a straight line using linear interpolation.
In this case, we have three data points: X corresponding to an unknown temperature, 60 °C corresponding to 52 mm, and 100 °C corresponding to 50 mm.
We can set up a proportion based on the relationship between temperature and the corresponding position on the thermometer:
(60 - X) / (100 - X) = (52 - 50) / (50 - X)
Simplifying the proportion:
(60 - X) / (100 - X) = 2 / (50 - X)
Cross-multiplying:
(60 - X)(50 - X) = 2(100 - X)
Expanding and simplifying:
3000 - 110X + X^2 = 200 - 2X
Putting all terms on the same side of the equation:
X^2 - 108X + 2800 = 0
Solving this quadratic equation yields two solutions: X = 20 and X = 88.
However, since the ice and steam points on a thermometer typically correspond to 0 °C and 100 °C, respectively, we can eliminate the X = 88 solution. As a result, the value of X is 20.
Therefore, X corresponds to 20 mm on the thermometer.
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