The inner core is solid because the inner core consists of a lot of pressure and high temperatures. And the more pressure and high temperatures the more dense the substance gets.

Answers

Answer 1

The inner core is solid because the inner core consists of a lot of pressure and high temperatures. This is true.

How to illustrate the information?

The pressure surrounding the inner core, as well as the planet's atmosphere, keeps the iron from melting. The iron atoms cannot migrate into a liquid form due to the pressure and density, which are simply too high.

Temperature is a measure of how hot or cold something is, more particularly the average kinetic energy of the particles in an object, which is a sort of energy related with motion. Temperature is a measure of how hot or cold something is represented in terms of one of several scales, including Fahrenheit and Celsius.

Because the inner core is under intense pressure and is extremely hot, it is solid. And the stuff becomes denser as pressure and temperature increase. Therefore, the inner core's high heat and pressure are what are solidifying it since the denser the stuff is, the more solidified it becomes.

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The inner core is solid because the inner core consists of a lot of pressure and high temperatures. And the more pressure and high temperatures the more dense the substance gets. True or false?


Related Questions

Determine the value of x using a trigonometric ratio.Question options:A) 4.98B) 8.49C) 4.18D) 10.11

Answers

We know that the hypotenuse is 6.5 units long, and x is the opposite leg to angle 50.

To find the value of x, use the sine trigonometric reason.

[tex]\begin{gathered} \sin 50=\frac{x}{6.5} \\ x=6.5\cdot\sin 50 \\ x\approx4.98 \end{gathered}[/tex]Therefore, the answer is A) 4.98.

help me please


thank you

Answers

Answer:

Domain: [tex](-\infty, \infty)[/tex]

Range: [tex][0, \infty)[/tex]

Step-by-step explanation:

The domain is the set of x-values and the range is the set of y-values.

8) Find the volume of a cylinder that has a radius of 9 cm and a height of 15 cm. 15 cm 9 cm

Answers

In order to find the volume of the given cylinder, use the following formula:

V = π·r²·h

where:

r: radius of the cylinder = 9 cm

h: height of the cylinder = 15 cm

π = 3.1415

replace the previous values of the parameters into the formula for V:

V = (3.1415)(9 cm)²(15 cm)

V = 3,816.92 cm³

Hence, the volume of the given cylinder is 3,816.92 cm³

Innings in his latest game,

Answers

The equation for the expression is given by

[tex]x+6\frac{2}{3}>82\frac{1}{3}[/tex]

To get the value for x

Step 1: Subtract

[tex]\begin{gathered} 6\frac{2}{3} \\ \text{from both sides} \end{gathered}[/tex][tex]x+6\frac{2}{3}-6\frac{2}{3}>82\frac{1}{3}-6\frac{2}{3}[/tex][tex]x>82\frac{1}{3}-6\frac{2}{3}[/tex][tex]\begin{gathered} 82\frac{1}{3}=\frac{247}{3} \\ \\ 6\frac{2}{3}=\frac{20}{3} \\ \\ x>\frac{247}{3}-\frac{20}{3} \end{gathered}[/tex]

Simplifying further

[tex]\begin{gathered} x>\frac{247-20}{3} \\ \\ x>\frac{227}{3} \end{gathered}[/tex][tex]\begin{gathered} x>\frac{227}{3}\text{ } \\ or \\ x>75\frac{2}{3} \end{gathered}[/tex]

There are 360° in a circle graph. If 50° of the graph represents rent and 7° of the graph represents savings, what fractional portion of the whole graph is not represented by rent and savings?​

Answers

Based on the circle graph and portions that are represented by rent and savings, the fractional portion of the graph that is not represented by rent and savings is 84.2%

How to find the fractional portion?

First, find the degrees in the circle graph that is not represented by rent and savings. This is:

= Total number of degrees in circle graph - degrees represented by rent and savings

= 360 - 50 - 7

= 303 °

The fractional portion which isn't represented by either rent or savings is:

= Degrees not represented by rent or savings / Total number of degrees  x 100%

= 303 / 360 x 100%

= 84.2%

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Nate is 22 years old. Karina is 13 years old. How many years ago was Nate's age 4 times Karina'sage?

Answers

Nate current age = 22 years

Karina current age = 13 years

let

x = the years ago

[tex]\begin{gathered} 4(13-x)=22-x \\ 52-4x=22-x \\ 52-22=-x+4x \\ 30=3x \\ x=\frac{30}{3} \\ x=10 \end{gathered}[/tex]

The answer is 10 years ago.

What is the equation for this graph?

Answers

Answer:

[tex]y=\frac{2}{3}x+4[/tex]

Step-by-step explanation:

What two numbers multiply to -25 adds up to 2

Answers

-6 and 4 multiply to -24 and add up to -2: -6 × 4 = -24 -6 + 4 = -2.

Based on the table below, find the range of f(x) x 137911f(x) 8175209Range = {

Answers

The range of the functions is the set made of the f(x) values. Therefore the range is:

[tex]\lbrace8,17,5,20,9\rbrace[/tex]

-2/5y=4 what is y???????

Answers

Answer:

-10

Step-by-step explanation:

solve for y by simplifying both sides of the equation, then isolating the variable.

“Rewrite the following expression so there are no negative exponents. Do not simplify”

Answers

The rule of the negative exponent is given below:

[tex]X^{-a}=\frac{1}{X^a}[/tex]

Hence, the expression:

[tex]\frac{yx^3.-2x^{-2}y^{-2}}{-3x^{-1}y^{-4}.-3y^3}[/tex]

can then be re-written, without the negative exponent, as:

[tex]\frac{yx^3\text{ . }\frac{-2}{x}\frac{1}{y^2}}{\frac{-3}{x}\frac{1}{y^4}.-3y^3}[/tex]

2) The expression:

[tex]\begin{gathered} \frac{x^3y^{-1}}{3x^4y^{-2}.2x^2y^2} \\ \end{gathered}[/tex]

can be re-written, without the negative exponent, as:

[tex]\frac{x^3\times\frac{1}{y}^{}}{3x^4\times\frac{1}{y^2}.2x^2y^2}[/tex]

The price of a gallion of unleaded gas has risen to $2.89 today. Yesterday's price was $2.84. Find the percentage increase, Round your answer to the nearesttenth of a percentX5 ?

Answers

Answer:

1.8%

Explanation:

Given the original price as $2.84 and the new price as $2.89, let's go ahead and determine the increase in price as seen below;

[tex]\begin{gathered} \text{Increase }=\text{ New price - Original price} \\ =2.89-2.84 \\ =0.05 \end{gathered}[/tex]

We'll use the below formula to determine the percentage increase;

[tex]\begin{gathered} \text{Percentage Increase }=\frac{Increase}{\text{Original price}}\times100 \\ =\frac{0.05}{2.84}\times100 \\ =0.0176\times100 \\ =1.8\text{\%} \\ \end{gathered}[/tex]

{-3,0,3} what is it closed under addition, multiplication,both or neither

Answers

{-3,0,3} is closed under multiplication.

What are functions of different types of brackets?

Curly brackets are often used to denote sets in writing. For instance, a set of the integers 3, 4, 5, and 6 is denoted by "3, 4, 5, 6." In a calculus or physics lecture, angular brackets like 1,3> may denote an inner product, and square brackets may denote a matrix. Mathematicians often use brackets to group similar phrases or numbers together, which is a very important use of these symbols. An expression or thing encompassed by brackets is implied to be given precedence over other things by the presence of brackets. The most popular method for enclosing extra information from a third party is to use square brackets (someone other than the original author). In writing, a list of equal options is frequently denoted by curly brackets.

The set consist of numbers -3, 0 and 3 so if we use any combination of those 3 numbers under some operation and get as result one of those 3 numbers that means set is closed under that operation.

for multiplication you get:

0 × 3 = 0

0 × -3 = 0

-3 × 3 = -9

So all combinations used and answers are 0 and -9 which means set is closed under multiplication.

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Bath and Body works is having a sale. Their Body Mists are 65% off. If the original price is $14.50, how much would you spend if you bought 5 body mists? Write an equation(s) to represent the problem and solve.

Answers

Body mists are 65% off

The original price is $14.50

So, the 60% of 14.50 is

[tex]\begin{gathered} 60\text{ percent of 14.50 dollars is =}\frac{60\times14.50}{100} \\ 60\text{ percent of 14.50 dollars is}=8.7\text{ dollars} \end{gathered}[/tex]

Since the 8.7 dollars is off so, the net price is 14.50-8.7

The prics of one body mists after 60% off is $5.8

Let the x is the amount spend in the 5 body mists

Since the prics of 1 body mists is $5.8

So, the price of 5 body mists is : 5 times of $5.8

[tex]\begin{gathered} \text{The price of 5 body mists =5}\times5.8 \\ \text{The price of 5 body mists=}29\text{ dollars} \\ \text{ Since we assume that the price of the 5 body mists is x } \\ So,\text{ x = 29 Dollars} \end{gathered}[/tex]

Answer : x = $29

In a bake sale, you recorded the number of muffins sold and the amount of sales in a table as shown. a. What is a function that relates the sales and the number of muffins?b. How many muffins would you have to sell to make at least $175.000 in sales?a. Write the function.s= ______. (Type and expression using m as the variable.)

Answers

The function is S = N*1.75. The number of muffins that must be sold to earn $175 is 100.

The number of muffins sold and the amount of sales in a bake sale are shown in the given table. The number of muffins sold is 12, 14, 17, and 18. The amount of the sale is $21, $24.5, $29.75, and $31.5. We can write these in the form of coordinates as (12, 21), (14, 24.5), (17, 29.75), and (18, 31.5).

We should first determine if the ratio is constant. The ratio is the division of the sales amount by the respective number of muffins sold. We find that the ratio of all the pairs is the same and is equal to 1.75. We can form an equation as given below :

S = N*1.75

The variables "S" and "N" represent the sales amount and the number of muffins, respectively. We need to find the number of muffins that need to be sold to earn $175.

S = N*1.75

175 = N*1.75

N = 100

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Quadrilateral DEFG has vertices D(-1,2), E(-2, 0), F(-1,-1) and G(1, 3). A
translation maps quadrilateral DEFG to quadrilateral D'E'F'G'. The image of D is D'(-2,-2).
What are the coordinates of E, F, and G′ ?

Answers

Answer:

E' = (-3, -4)

F' = (-2, -5)

G' = (0, -1)

Step-by-step explanation:

Given vertices of quadrilateral DEFG:

D = (-1, 2)E = (-2, 0)F = (-1, -1)G = (1, 3)

A translation is a type of transformation and moves a figure left, right, up or down.  

Every point on the original figure is translated (moved) the same distance in the same direction.

Therefore, to calculate the mapping rule that translates DEFG to D'E'F'G', compare the coordinates of D with the coordinates of D'.

D = (-1, 2)D' = (-2, -2)

The x-coordinate has be translated 1 unit to the left.

The y-coordinate has been translated 4 units down.

Therefore, the mapping rule is:

(x, y) → (x-1, y-4)

To find the coordinates of E', F' and G', apply the mapping rule to the given vertices of the pre-image:

E' = (-2-1, 0-4) = (-3, -4)

F' = (-1-1, -1-4) = (-2, -5)

G' = (1-1, 3-4) = (0, -1)

what are the domain and range of this exponential functions y=4×+8

Answers

The given function is

[tex]y=4^{x+8}[/tex]

The domain of the function would be all real numbers.

But the range would be all real numbers greater than zero because the function approximates to y = 0 but it doesn't go through.

Hence, the answer is the first option.

what principal will amount to $1750 if invested at 3% interest compounded quarterly for 5 years

Answers

The formula for calculating compound interest is expressed as

A = P(1 + r/n)^nt

Where

A is the total amount after t years

P is the principal or initial amount invested

r is the interest rate

n is the number of compouding periods in a year

t is the number of years

From the information given,

A = $1750

r = 3% = 3/100 = 0.03

t = 5

n = 4 because it was compounded quarterly

By substituting these values into the formula, we have

1750 = P(1 + 0.03/4)^4 * 5

1750 = P(1 + 0.03/4)^20

1750 = P(1.0075)^20

Dividing both sides by (1.0075)^20, it becomes

P = 1750/(1.0075)^20

P = 1507.0822

Approximating to the nearest whole number,

Principal = $1507

At a restaurant, you order a moal that costs $12. You leave a 15% tip. The sales tax is 9%. What is the total costof the meal In dollars

Answers

SOLUTION:

Case: Percentages

Given:

Meal cost= $12

tip= 15%

sales tax= 9%

Method:

To find the Total cost of the meal,

We calculate the actual cost of the tip

[tex]\begin{gathered} 15\%\times12 \\ \frac{15}{100}\times12 \\ \frac{180}{100} \\ 1.8 \end{gathered}[/tex]

The actual cost of the tip was $1.80

We then calculate the actual cost of the sales tax

[tex]\begin{gathered} 9\%\times12 \\ \frac{9}{100}\times12 \\ \frac{108}{100} \\ 1.08 \end{gathered}[/tex]

The cost of sales tax is $1.08

The total cost of the mean is:

[tex]\begin{gathered} 12+1.80+1.08 \\ =14.88 \end{gathered}[/tex]

Final answer:

The total cost of the meal is $14.88

homework help
give two examples of when you might estimate differences in everyday life.

Answers

Some examples of the use of estimates in our everyday lives are given below:

Making an estimate when shopping so as not to exceed budgetMaking an estimate of the number of shoppers in a shopping mall

What is an Estimate?

This refers to the rough calculation that is done to judge the value of a thing or the data outcome of a proposition.

Hence, when it comes to estimation or rough calculation of values or numbers, it is important that it is done as accurately as possible within the limits of current available data or data projections.

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(5 x 2c) + 50 ÷ 5 = 30
Solve for C

Answers

Answer:   The correct answer is c=4/x^2

Step-by-step explanation:

Solve for c:

5x^2c+50/5=30

Add -10 to each side:

5cx^2+10+(−10)=30+(−10)

5cx^2=20

Divide both sides by 5x^2:

(5cx^2)/(5x^2)=20/(5x^2)

c=4/x^2

can someone help me

Answers

The answer is f(-2) = 30

The question requires us to substitute the value of x into the function.

if the function is:

[tex]f(x)=-2x^3+2x^2-2x+2[/tex]

then f(-2) means we only need to substitute -2 for x into the equation given.

[tex]\begin{gathered} f(-2)=-2(-2)^3+2(-2)^2-2(-2)+2 \\ (-2)^3=-8_{} \\ (-2)^2=4 \\ -2(-2)=4 \\ \\ f\mleft(-2\mright)=-2\mleft(-8\mright)+2\mleft(4\mright)+4+2 \\ f(-2)=16+8+4+2 \\ f(-2)=30 \end{gathered}[/tex]

Therefore,

The final answer is f(-2) = 30

Ill send you the pictures of my question, it isnt allowing me to put them here

Answers

A is the correct option

find the area of the trapezoid __ m squared simplify the answer

Answers

A trapezoid is given with base lengths of 10m and 14m, and a height of 9m.

It is required to find the area of the trapezoid.

Recall that the area of a trapezoid with base lengths b₁, b₂, and height h is given by:

[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]

Substitute b₁=14, b₂=10, and h=9 into the formula:

[tex]\begin{gathered} A=\frac{1}{2}(14+10)\cdot9 \\ \Rightarrow A=\frac{1}{2}\cdot24\cdot9=108 \end{gathered}[/tex]

Hence, the required area is 108 m².

The answer is 108 m².

need answer asap ty

multiplying integers
(-5) (-12) =
-9 × (-6) =
(-7) (8) =
11 × -8 =
(-12) (4) =​

Answers

question 1 =60

2=54

3=-56

4=-88

5=-48

A line passes though two points A(-2, 2). B(-1, 2). What is the slope:

Answers

The slope of the line that passes through points (-2, 2) and (-1, 2) is 0.

What is the slope of the line with the given coordinates?

Slope is simply expressed as change in y over the change in x.

Slope m = ( y₂ - y₁ )/( x₂ - x₁ )

Given the data in the question;

Point A(-2, 2)

x₁ = -2y₁ = 2

Point B( -1, 2 )

x₂ = -1y₂ = 2

To determine the slope, plug the given x and y coordinates into the slope formula and simplify.

Slope m = ( y₂ - y₁ )/( x₂ - x₁ )

Slope m = ( 2 - 2 )/( -1 - (-2) )

Slope m = ( 0 )/( -1 + 2 )

Slope m = ( 0 )/( 1 )

Slope m = 0

Therefore, the slope of the line is 0.

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please help. i don’t under any of this and it’s due today

Answers

GIVEN:

We are given the exponential relationship as shown below;

[tex]g(x)=4(0.6)^x[/tex]

Required;

To determine the characteristics of the graph as indicated.

(1) The range of the function; The range of the function is determined as follows;

[tex]\begin{gathered} For\text{ }the\text{ }function;\text{ }c\times n^{ax+b}+k \\ \\ Range=g(x)>k \end{gathered}[/tex]

In this question, the value of k is nil or zero. Therefore, we have

[tex]\begin{gathered} Range: \\ \\ g(x)>0 \\ \\ That\text{ }is; \\ \\ y>0 \end{gathered}[/tex]

I need to know how to do the whole thing and understand it.

Answers

We are given the data on the number of candies handed by neighborhood A and neighborhood B.

Let us first find the mean and variance of each neighborhood.

Mean:

[tex]\bar{x}_A=\frac{\sum x}{N_1}=\frac{12}{6}=2[/tex][tex]\bar{x}_B=\frac{\sum x}{N_2}=\frac{20}{6}=3.33[/tex]

Variance:

[tex]s_A^2=\frac{\sum x^2}{N_1}-\bar{x}_A^2=\frac{28}{6}-2^2=0.667[/tex][tex]s_B^2=\frac{\sum x^2}{N_2}-\bar{x}_B^2=\frac{80}{6}-3.33^2=2.244[/tex]

A. Null hypothesis:

The null hypothesis is that there is no difference in the mean number of candies handed out by neighborhoods A and B.

[tex]H_0:\;\mu_A=\mu_B[/tex]

Research hypothesis:

The research hypothesis is that the mean number of candies handed out by neighborhood A is more than neighborhood B.

[tex]H_a:\;\mu_A>\mu_B[/tex]

Test statistic (t):

The test statistic of a two-sample t-test is given by

[tex]t=\frac{\bar{x}_A-\bar{x}_B}{s_p}[/tex]

Where sp is the pooled standard deviation given by

[tex]\begin{gathered} s_p=\sqrt{\frac{N_1s_1^2+N_2s_2^2}{N_1+N_2-2}(\frac{N_1+N_2}{N_1\cdot N_2}}) \\ s_p=\sqrt{\frac{6\cdot0.667+6\cdot2.244}{6+6-2}(\frac{6+6}{6\cdot6})} \\ s_p=0.763 \end{gathered}[/tex][tex]t=\frac{2-3.33}{0.763}=-1.74[/tex]

So, the test statistic is -1.74

Critical t:

Degree of freedom = N1 + N2 - 2 = 6+6-2 = 10

Level of significance = 0.05

The right-tailed critical value for α = 0.05 and df = 10 is found to be 1.81

Critical t = 1.81

We will reject the null hypothesis because the calculated t-value is less than the critical value.

Interpretation:

This means that we do not have enough evidence to conclude that neighborhood A gives out more candies than neighborhood B.

multiply the question

Answers

EXPLANATION:

In order to multiply correctly we must follow the following steps:

-Multiply the numbers that are not in power of 10 and finally add the powers of 10.

The exercise is as follows:

[tex]undefined[/tex]

The radius of a circle is 6 feet. What is the area of a sector bounded by a 66° arc?Give the exact answer in simplest form. ____ square feet. (pi, fraction,)

Answers

[tex]\text{Area of a sector =}\frac{\theta\cdot\pi}{360}\cdot r^2[/tex]

where:

r= radius = 6 ft

Θ = angle = 66°

Replacing:

[tex]A=\frac{66\cdot\pi}{360}\cdot6^2[/tex]

A= 33/5 π

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