the line current in a balanced three-phase, wye-connected, resistive load is 25 a. what will happen if the neutral wire is disconnected?

Answers

Answer 1

Because of the imbalance, the power protection circuits will activate

if the neutral wire is unplugged.

If the neutral wire is damaged or disconnected, the out-of-balance current cannot, but must, return to the supply via the star point. As a result, this current follows the wires back to the source. The neutral current and neutral power in a balanced system are both zero. A balanced three-phase system may be thought of as three single-phase systems linked to a neutral line. As a result, if the supply voltage and motor impedance are both balanced, the induction motor draws a balanced current. The balancing current in the motor's three phases results in no current in the neutral. As a result, there is no need for a neutral in a three-phase induction motor.

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Related Questions

Which of the forces A, B, C, or D represent the tension force on the box?

Answers

The force that represents the tension force on the box is A because it is in the direction of the attached rope.

What is tension force?

Tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.

Tension force is described as the pulling force transmitted axially by the means of a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar three-dimensional object.

For the given diagram, the tension force is the force pulling the box upwards preventing downward motion of the box.

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two charged dust particles exert a force of on each other. what will be the force if they are moved so they are only one-eighth as far apart?

Answers

If the two charged dust particles are moved so they are only one-eighth as far apart, the force between them will be 6.912 N.

The electric force between two charged particles is given by Coulomb's law, which states that:

F = kq₁q₂/r²

here,

F is force between the particles,

The charges of the particles are q1 and q2.

r is distance between them, and

k is Coulomb's constant,

which is equal to 9 * 10⁹ Nm²/C².

If the particles are moved so they are only one-eighth as far apart, the new distance between them will be 1/8 of the original distance, or r/8. The new force between them can be calculated using the same formula as before:

F' = kq₁q₂/(r/8)²

To simplify this expression, we can use the fact that (1/8)² = 1/64, which gives:

F' = kq₁q₂*64/r²

Reserving the values for k, q1, q2, and F from the original problem, we get:

F' = (9 x 10⁹ Nm²/C²) * (2 x 10⁻⁶ C)² * (3 x 10⁻⁶ C)² * 64 / (0.1 m)²

Calculating this expression, we get:

F' = 6.912 N

Therefore, if the two charged dust particles are moved so they are only one-eighth as far apart, the force between them will be 6.912 N.

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how is the fact that an electromagnetic wave in space never slows down consistent with the law of conservation of energy? group of answer choices light contains no energy at all speeds, so its speed is always consistent with the law of conservation of energy. if light slowed down, its energy would increase, thereby violating the law of conservation of energy. if light slowed down, it would gain mass, thereby violating the law of conservation of energy. if light slowed down, its energy would decrease, thereby violating the law of conservation of energy.

Answers

The way that an electromagnetic-wave in space never dials back is predictable with the law of preservation of energy, as it keeps a steady energy as it goes through space.

The explanation that makes sense of how the way that an electromagnetic wave in space never dials back is steady with the law of protection of energy is: "Assuming light dialed back, its energy would diminish, subsequently abusing the law of preservation of energy."

The speed of light, or any electromagnetic, still up in the air by the properties of the medium through which it is voyaging. In a vacuum, the speed of light is consistent and doesn't dial back.

This is reliable with the law of preservation of energy, which expresses that energy can't be made or annihilated, just changed starting with one structure then onto the next.

If an electromagnetic wave were to slow down, its energy would have to go somewhere. It would either be converted to another form of energy or lost entirely. This would violate the law of conservation of energy.

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will the efficiency increase decrease or remain the same if you make the inclined plane steeper

Answers

The efficiency of an inclined plane will decrease if you make it steeper. This is because the steeper the incline, the more energy is required to move an object up the incline.

Answer:

The efficiency of a simple machine such as an inclined plane will decrease if the plane is made steeper. This is because a steeper plane requires more force to lift the same load, leading to a greater loss of energy due to friction and other sources of inefficiency. A gentler slope allows the force applied to the load to be spread out over a greater distance, reducing the force required to lift the load and therefore increasing the overall efficiency of the machine.

Explanation:

ALLEN

the amount of incoming solar radiation available at various places on the earth depends mainly on

Answers

This is based on a location's latitude. As latitude rises, the sun's rays' angle with the earth's surface decreases, resulting in slanted sunrays. Vertical rays always cover less area than rays that are angled.

What amount of incoming solar radiation on the earth?

The amount of incoming solar energy that is accessible varies on the longitude, day of the year, time of day, and degree of cloud cover. The amount of solar energy received at a given latitude would not change throughout the year if the earth were not tilted from the vertical.

The solar radiation that reaches the surface of the earth is known as insolation. The quantity of solar energy absorbed per square centimeter every minute is used to calculate it.

Therefore, the amount of insolation (incoming solar energy) that is received each day mostly relies on. the Sun's angle above the horizon, also known as the solar incidence angle. the amount of time the surface is exposed to the Sun, as well as the atmosphere.

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if you walk 3 kilometers in 30 minutes what is your average speed

Answers

For these paces, one hour is equivalent to 3.27 miles or 5.26 kilometers for women and 3.8 miles or 6.1 kilometers for males in terms of distance.

What is the parameter for determining average speed?

The ratio of the total distance travelled by the body to the amount of time it took to complete that distance can be used to calculate average speed.

Formula for the average speed of a moving object with a range of speeds. The minute the minutes cancel, giving us kilometres per hour, and the speed would be 6 kilometres per hour; it then asks us to compare.

A student's average speed while walking would be 9 km/h if they covered a distance of 3 km in 20 minutes.

Therefore, to convert it to kilometres per hour, we can do so by simply converting our minutes into hours and remembering that there are 60 minutes in an hour.

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assume steady-state, one-dimensional heat conduction through the axisymmetric shape. assuming constant properties and no internal heat generation, sketch the temperature distribution?

Answers

The actual temperature distribution will depend on the specific geometry and material properties of the axisymmetric shape

Based on the given assumptions of steady-state, one-dimensional heat conduction, constant properties, and no internal heat generation, we can expect the temperature distribution to have the following characteristics:

The temperature will vary only in the radial direction, perpendicular to the axisymmetric shape.

The temperature gradient in the radial direction will be constant, assuming that the thermal conductivity of the material is also constant

The temperature distribution will be symmetric about the axis of the shape.

The temperature at the center of the shape will be higher than the temperature at the outer surface.

Based on these characteristics, we can sketch the temperature distribution as follows:

             -------------

            /             \

          /                 \

        /                     \

       |                       |

       |           T1          |

       |                       |

        \                     /

          \                 /

            \             /

              -------------

                 R1

In this sketch, T1 is the temperature at the center of the shape, which is the highest temperature. R1 is the outer radius of the shape, and the temperature at the outer surface is assumed to be the lowest temperature. The temperature decreases linearly with increasing radial distance, and the temperature gradient is constant throughout the shape.

This sketch provides a general idea of what the temperature distribution might look like under the given assumptions.

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a sphere made of rubber has a density of 1.08 g/cm3 and a radius of 8.00 cm. it falls through air of density 1.20 kg/m3 and has a drag coefficient of 0.500. what is its terminal speed (in m/s)?

Answers

The terminal speed of the falling rubber sphere is approximately 2.43 m/s.

Terminal speed is the constant velocity that a falling object eventually reaches when the resistance of the medium through which it is falling (such as air or water) prevents further acceleration.

[tex]v = \sqrt{\dfrac{2 \times m \times g}{\rho \times A \times C_d}}[/tex]

where ρ is the density of air, v is the velocity of the sphere, A is the cross-sectional area of the sphere, and [tex]C_d[/tex] is the drag coefficient.

The mass of the sphere can be calculated from its density and volume:

[tex]m = \dfrac{4}{3} \times \pi \times r^3 \times\rho[/tex]

where r is the radius of the sphere.

Mass = [tex]m = \dfrac{4}{3} \times \pi \times (0.08 m)^3 \times 1.08 \times \dfrac{1 kg}{1000 g}[/tex]

Mass =  = 0.144 kg

Area is,

[tex]A = \pi \times r^2\\ = \pi \times (0.08)^2 \\= 0.0201 m^2[/tex]

The terminal velocity is,

[tex]v = \sqrt{\dfrac{2 \times 0.144 \times 9.81}{1.20\times 0.0201 \times 0.500}}[/tex]

= 2.43 m/s

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29) electrons in an x-ray machine are accelerated from rest trhough a potential difference of 50 kv. what is the kinetic energy of the electrons en ev?

Answers

Potential difference difference V = 50,000V

Kinetic Energy K.E. = q v    , for electron q=E

KE= 50,000 ev.

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy in physics.  It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body holds onto the kinetic energy it acquired during its acceleration until its speed changes. The body exerts the same amount of effort when slowing down from its current pace to a condition of rest. Formally, a kinetic energy is any term that includes a derivative with respect to time in the Lagrangian of a system.Gottfried Leibniz and Johann Bernoulli were the first to formulate the classical mechanics principle that E mv2, referring to kinetic energy as the "vital power," or vis viva. Experimental proof of this connection was supplied by Willem's Gravesande in the Netherlands. Willem's Gravesande discovered that the penetration depth of weights was proportional to the square of their impact speed by dropping weights from various heights upon a piece of clay.

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you make an interferometer using a 50-50 beam splitter and two mirrors, one being a perfect mirror and one which does not reflect all light. the wavelength of the 9-mw incident laser is 400 nm. because the top mirror is not perfectly reflective (it reflects 90% of the photons, allowing 10% of them to go through), the power measured at the detector when only the vertical arm is blocked is 2.25 mw, while the power measured at the detector when only the horizontal arm is blocked is only 2.025 mw. assume initially the detected power is at its maximum. how much would we need to translate the perfect mirror to the right to get a minimum power at the detector, and what is that minimum power?

Answers

Move perfect mirror to the right by 86.2 nm to produce minimum power at detector and minimum power is 0.225 mW.

To create an interferometer using a 50-50 beam splitter and two mirrors, we can split a laser beam into two paths using the beam splitter, bounce one path off a perfect mirror, and the other off a mirror that does not reflect all light.

In this setup, interference between the two paths of the laser light can produce a pattern of constructive and destructive interference, which can be detected at a detector.

If the detected power is initially at its maximum, we can move the perfect mirror to the right to produce a minimum power at the detector. This is because moving the mirror changes the path length difference between the two paths of the laser light, and this can change the interference pattern.

To determine how much we need to move the perfect mirror, we can use the fact that the detected power is maximum when the two paths of the laser light are in phase, and minimum when they are out of phase. When only the vertical arm is blocked, the power measured at the detector is 2.25 mw, and when only the horizontal arm is blocked, the power measured at the detector is 2.025 mw.

The power detected at the detector is given by:

P = [tex](1/2) * P_in * (1 +- cos(Δφ))[/tex]

where[tex]P_in[/tex] is the incident power, Δφ is the phase difference between the two paths of the laser light, and the ± sign depends on which path is blocked.

When the power is maximum, the phase difference is an integer multiple of 2π, i.e., Δφ = [tex]2\pi n[/tex]. When the power is minimum, the phase difference is an odd multiple of π, i.e., Δφ = [tex](2n+1)\pi /2.[/tex]

We can solve for the phase difference in terms of the incident power and the measured powers:

Δφ = [tex]arccos[(4P_min/P_in) - 1][/tex]

where [tex]P_min[/tex] is the minimum power detected at the detector, which is 2.025 mw.

Plugging in the values, we get:

Δφ = [tex]arccos[(4*2.025/9) - 1] = 2.18 radians[/tex]

To produce a minimum power at the detector, we need to change the phase difference to [tex](2n+1)\pi /2[/tex]. This means we need to move the perfect mirror by a distance Δx such that:

Δφ = [tex](2n+1)\pi /2 = 1.57, 4.71, 7.85, ...[/tex]

We can use the wavelength of the laser to determine the distance Δx:

Δx = Δφ * λ / [tex]2\pi[/tex]

lambda: wavelength of laser = 300 nm

Put values:

Δx = 86.2 nm

So we need to move the perfect mirror to the right by 86.2 nm to produce a minimum power at the detector, and the minimum power at the detector is 0.225 mW.

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what is the area of a figure using a square with sides of 15 centimenters and four attatched semicircles

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The area of the figure is approximately 577.86 square centimeters.

To find the area of the figure made up of a square with sides of 15 centimeters and four attached semicircles, we can break it down into two parts: the area of the square and the area of the four semicircles.

The area of the square is found by multiplying the length of one side by itself. So in this case, the area of the square is:

Area of square = side length x side length = 15 cm x 15 cm = 225[tex]cm^2[/tex]

The four semicircles make up a circle with a diameter equal to the length of one side of the square. So the radius of the circle is half of the length of one side of the square, which is:

Radius of circle = 1/2 x side length = 1/2 x 15 cm = 7.5 cm

The area of one semicircle is half the area of the full circle, which is π times the radius squared divided by 2. So the area of four semicircles is:

Area of four semicircles = [tex]4 x (1/2 x π x radius^2) = 2πr^2[/tex]

Plugging in the value of the radius, we get:

Area of four semicircles = [tex]2π x (7.5 cm)^2 = 352.86 cm^2[/tex](rounded to two decimal places)

Therefore, the total area of the figure made up of a square with sides of 15 centimeters and four attached semicircles is:

Total area = area of square + area of four semicircles

Total area = [tex]225 cm^2 + 352.86 cm^2[/tex]

Total area = [tex]577.86 cm^2[/tex] (rounded to two decimal places)

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[TRUE or FALSE] a frequency distribution usually has equal bin widths.

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In a frequency distribution, the bin widths are typically equal. Cross-sectional data does not employ line charts. Using a scatter plot, you can see trends over time. There must be two quantitative variables for a scatter plot (i.e., not categorical data). Thus, it is true.

What frequency distribution usually has equal bin widths?

The Pareto chart shows the few, most important flaws that account for the majority of the entire issue.

A Pareto chart makes it easier to see what elements make up the 20% that are the crucial few and what factors make up the inconsequential many by arranging the bars from the largest to the smallest.

The number of groups of classes that should be used to classify a distribution of observations according to the Sturges rule is 1 + 3.3 log n, where n is the total number of observations.

Therefore, it is true that a frequency distribution usually has equal bin widths.

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A negatively charged rod is brought near a metal can that rests on a wood table. You touch the opposite side of the can momentarily with your finger. The can is then
Group of answer choices

negatively charged

positively charged

uncharged

charged the same as it was before

Answers

The can is then positively charged after you touch it with your finger, option B.

What is induction?

Induction is a process by which a change in a magnetic field induces a current flow in a conductor, such as a wire. In physics, electromagnetic induction refers to the production of an electromotive force (EMF) across a conductor that is exposed to a changing magnetic field.

When the negatively charged rod is brought near the can, electrons are attracted to the positively charged can. When you touch the can, electrons flow from your body to the can, leaving it positively charged.

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a box sliding to the right across a frictinonless surface begins with a kinetic energy of 12 j. if the box then encounters a rough spot on the floor which applies a frictional force of 2 n to the left over a 0.25 m distance, what is the kinetic energy of the box after it has slid through the rough spot?

Answers

The kinetic energy of the box after it has slid through the rough spot is 12.5 J.

The initial kinetic energy of the box is 12 J.

When the box encounters the rough spot on the floor, a frictional force of 2 N acts on it in the opposite direction to its motion. The work done by this frictional force is:

work done by friction = force x distance x cos(theta)

where "theta" is the angle between the force and the displacement, which is 180 degrees in this case (since the force is opposite to the direction of motion). Therefore, cos(theta) = -1.

Plugging in the values, we get:

work done by friction = 2 N x 0.25 m x (-1) = -0.5 J

Since the work done by the frictional force is negative, it reduces the kinetic energy of the box. Therefore, the final kinetic energy of the box is:

final kinetic energy = initial kinetic energy - work done by friction

final kinetic energy = 12 J - (-0.5 J) = 12.5 J

Therefore, the kinetic energy of the box after it has slid through the rough spot is 12.5 J.

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the ________ is perhaps the most dramatic force now shaping our world.

Answers

The technology is perhaps the most dramatic force now shaping our world.

The rapid pace of technological advancement, driven by the emergence of new technologies such as artificial intelligence, machine learning, big data, and the internet, is arguably the most dramatic force shaping our world. This digital revolution has transformed the way we live, work, and communicate with one another, ushering in a new era of unprecedented connectivity and information exchange. With the rise of e-commerce and online marketplaces, the digital revolution has also brought about a significant shift in global economic power, as more and more businesses move to the online sphere. The digital revolution has also transformed our societies and political systems, as social media has become a powerful tool for activism and political mobilization.

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a plane flies 72 x 105 m north and then another 15 x 105 m west in a total time of 6 h. the magnitude of your average velocity for the entire trip is

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A plane flies 72 x 105 m north and then another 15 x 105 m west in a total time of 6 h. the magnitude of your average velocity for the entire trip is 340 m/s.

Displacement = [(72 x 10⁵]² + [15 x 10⁵]²

= 10⁵ x √72² + 15²

= 10⁵ x √5.409

= 73.545 x 10⁵

Time = 6 hours = 6 x 3600 sec

Velocity = 73.545x10⁵/36x6x100

V= 0.34044 x 10³

V = 340.49

V = 340 m/s

Magnitude of average velocity is 340 m/s.

The terms haste and speed give us an idea of how fast or decelerate an object is moving. relatively frequently, we come across situations where we need to identify which of the two or further objects is moving briskly. One can fluently tell the faster of the two if they're moving in the same direction on the same road. still, if their direction of stir is in the contrary direction, also it's delicate to determine the fastest.

In similar cases, the conception of haste is helpful. In this composition, let us learn the haste meaning, the unit of haste, the illustration of haste, and the difference between speed and haste.

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imad sets the charge of both particles to zero, then varies the charge on the left particle. what does jacob report on what he observes?

Answers

Jacob reports that as he varies the charge on the left particle, he observes that the force between the two particles changes.

Specifically, when the charge on the left particle is positive, the force between the two particles is attractive, and when the charge on the left particle is negative, the force between the two particles is repulsive. This is because opposite charges attract and like charges repel. As the magnitude of the charge on the left particle increases, the force between the two particles increases as well. The force of attraction is strongest when the charges on both particles are the same, and the force of repulsion is strongest when the charges on the particles are opposite.

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what is the length l of the pipe? an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?

Answers

Using the formula for the frequency of harmonics in an air-filled pipe, we can write:f_n = nv/(2L), where the pipe's length L, the air's sound speed (v), and harmonic number (n) are all variables.

What can be determined about the length of the pipe?

Solving for L, we get:L = nv/(2f_n)For the third harmonic (n=3), we have:L = (3v)/(2f_3) = (3343 m/s)/(21120 Hz) = 0.137 m or 13.7 cm.

Using the given harmonic frequencies, we can determine the length of the pipe by applying the formula: wavelength = speed of sound / frequency.

From this, we can calculate the wavelengths of each harmonic and determine the ratio of their wavelengths. The ratio of the wavelengths will be in the form of 1:3:5 for the 1st, 2nd and 3rd harmonics respectively.

We can then use this ratio to determine the length of the pipe using the formula: length = wavelength x (n/2), where n is the harmonic number.

Therefore, the length of the pipe is approximately 13.7 cm. Using the given harmonic frequencies,

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a bat flying toward a wall emits a 45000-hz sonar pulse. the pulse is reflected back from the wall and the bat hears the reflected pulse at a frequency of (45000 650) hz. take the speed of sound to be 343 m/s.

Answers

The speed of the bat, in meters per second of vbat Is 2.68m/s.

The apparent frequency, I of the Reflected Pulse is.

f = v_s  + v_b / v_s  - v_b.f_0

∴ 45710 = 343 + v_b /  343 - v_b.(45000)

   45710 / 45000 = 343 + v_b /  343 - v_b

                             = 1.01578

343 + v_b = (1.01578) (343 - v_b)

v_b + (1.01578)v_b = 348.41 - 343

v_b(1 + 1.01578) = 5.41

v_b = 5.41 /(1 + 1.10578) = 5.41 / 2.01578

v_b = 2.68 m/s

Apparent frequency refers to the frequency of a wave as it appears to an observer who is in motion relative to the source of the wave. When an observer is moving towards a sound source, for instance, the frequency of the sound waves appears to be higher, resulting in a higher pitch. Conversely, when the observer is moving away from the source, the frequency appears to be lower, resulting in a lower pitch.

The Doppler effect is applicable to various types of waves, including sound waves, light waves, and electromagnetic waves. It has significant applications in fields such as astronomy, where it is used to measure the movement of celestial bodies, and in medical imaging, where it is used in ultrasound technology.

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Complete Question: -

A bat flying toward a wall emits a 45000-Hz sonar pulse. The pulse is reflected back from the wall and the bat hears the reflected pulse at a frequency of (45000 + 710) Hz. Take the speed of sound to be 343 m/s.

Find the speed of the bat, in meters per second.

vbat =

The greater the blank of a moving object, the blank it has

Answers

Answer:

The greater the MASS of a moving object, the GREATER KINETIC ENERGY it has.

Explanation:

Anytime matter is in motion it has kinetic energy. The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Only second question. Thanks

Answers

a) When an identical resistor is added in series with the first resistor and the cell, the current through the resistors will remain the same as A amps.

What happens when iddentical resistor are added in series

When an identical resistor is added in series with the first resistor and the cell, the current through the resistors will remain the same as A amps.

This is because in a series circuit, the same current flows through each component. The total resistance of the circuit increases when a resistor is added in series, but the voltage across the resistors remains the same as the voltage across the cell.

According to Ohm's law, V = IR, where V is voltage, I is current, and R is resistance.

Since the voltage is constant and the resistance has increased, the current through the resistors must remain the same to satisfy Ohm's law. Therefore, the current through the second resistor will also be A amps.

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Is the rate-limiting step the slowest?

Answers

It is not important to the rate-limiting step in a chemical reaction how much energy is released or used. Instead, the slowest step among all the steps that take place in a specific chemical reaction is referred to as the rate-limiting step.

What is the rate-limiting step?

One of the fundamental steps in a multistep reaction mechanism moves along much more slowly than the others. The slowest step is the one that limits or determines rate.

This is because the phase that moves slowly needs more time to complete because it may entail numerous other processes.

As an illustration, a reactant would need to diffuse or migrate to a certain reaction site before another reaction can occur, which then immediately creates a product.

Therefore, A reaction can only move through its slowest phase; as a result, the rate-determining step restricts the rate of the entire reaction.

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the a string of a violin is a little too tightly stretched. beats at 6 per second are heard when the string is sounded together with a tuning fork that is oscillating accurately at concert a. what is the period of the violin string oscillations?

Answers

The period of the violin string oscillations is 0.0022 seconds.

The beat frequency of 6 per second means that the frequency of the violin string oscillations is slightly higher than the frequency of the tuning fork.

We can use the formula for beat frequency to find the difference in frequency between the two:

Beat frequency = |f1 - f2|

where f1 and f2 are the frequencies of the two sources.

In this case, the beat frequency is 6 beats per second and the frequency of the tuning fork is the standard Concert A pitch of 440 Hz. So we have:

6 = |f1 - 440|

Solving for f1, we get:

f1 = 446 Hz or 434 Hz

The two possible frequencies of the violin string are 446 Hz and 434 Hz, with 440 Hz being the frequency of the tuning fork.

The period of a wave is the time it takes for one complete oscillation or cycle. It can be calculated as:

period = 1 / frequency

So the period of the violin string oscillations for a frequency of 446 Hz would be:

period = 1 / 446 Hz ≈ 0.0022 seconds

And for a frequency of 434 Hz:

period = 1 / 434 Hz ≈ 0.0023 seconds

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If the index of refraction of a material is 2, this means that light travels2 times as fast in the material as it does in air.2 times as fast in vacuum as it does in the material.2 times as fast in the material than it does in vacuum.2 times as fast in air as it does in vacuum.1/2 as fast in air as it does in the material.

Answers

If the index of refraction of a material is 2, it means that, 1/2 as fast in air as it does in the material. The correct answer is d.

The index of refraction of a material is defined as the ratio of the speed of light in a vacuum to the speed of light in the material. So, an index of refraction of 2 means that light travels half as fast in the material as it does in a vacuum.

It does not have any direct relation to the speed of light in air, which has an index of refraction very close to 1, and which is commonly used as a reference medium.

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--The complete question is, If the index of refraction of a material is 2, this means that light travels,

a. 2 times as fast in the material as it does in air.

b. 2 times as fast in vacuum as it does in the material.2 times as fast in the material than it does in vacuum.

c. 2 times as fast in air as it does in vacuum.

d. 1/2 as fast in air as it does in the material.--

Why are positive charges free to move around in gases and liquids but not in solids?

Answers

solids are tightly packed together leaving no room for moving around at all!!

the energy loss over a ball valve (1/3 closed) has been calculated as 240 j/kg. what is the volumetric average fluid velocity (m/s) through the valve?

Answers

The volumetric average fluid velocity (m/s) through the valve of ball valve having energy loss as 240 j/kg is 15.5 m/s.

When energy is converted from one form to another, or moved from one place to another, or from one system to another there's energy loss. This means that when energy is converted to a different form, some of the input energy is turned into a largely disordered form of energy, like heat.

Flow rate is the volume of fluid per unit time flowing past a point through the area A. Then the shadowed cylinder of fluid flows once point P in a invariant pipe in time t. The volume of the cylinder is announcement and the average haste is v =d / t so that the inflow rate is Q = announcement/ t = Av.

Energy loss is given as 240 J/kg

So to find the volumetric average velocity we have,

Energy loss = 1/2 V² J/kg

240 = 1/2 V² J/kg

V = [tex]\sqrt{240}[/tex]

V = 15.49 ≈ 15.5 m/s

Therefore,  the volumetric average fluid velocity  is V = 15.49 ≈ 15.5 m/s.

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we have created a predictive model for the velocity of a galaxy based on the observed distance. suppose, that instead, we are interested in a predictive model of the distance based on the observed velocity: where is the slope, now of over , and is the intercept. fitting this linear model through least squares is essentially the same as flipping the axes of the original data and performing the same procedure again. what will the result be? (only one of these is true.) x(y)

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The result of flipping the axes of the original data and performing the same procedure again will be a linear model of the form y = mx + b, where y is the predicted distance, x is the observed velocity, m is the slope, and b is the intercept. So, the answer is y(x).

When we create a predictive model for the velocity of a galaxy based on the observed distance, we have a linear model of the form v = a*d + b, where v is the predicted velocity, d is the observed distance, and a and b are the slope and intercept, respectively. To fit this linear model through least squares, we minimize the sum of squared residuals between the observed and predicted velocities. Now, if we want to create a predictive model of the distance based on the observed velocity, we need to flip the axes of the original data and perform the same procedure again. That is, we now have a linear model of the form  [tex]d = m*v + b[/tex], where d is the predicted distance, v is the observed velocity, and m and b are the slope and intercept, respectively. To fit this linear model through least squares, we minimize the sum of squared residuals between the observed and predicted distances. Thus, the result of flipping the axes of the original data and performing the same procedure again is a linear model that predicts the distance based on the observed velocity, rather than the velocity based on the observed distance.

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How long will it take to get to the island 90km from the coast in a boat that travels 30km/m?

Answers

To find the time it will take to travel a certain distance at a certain speed, you can use the formula:

time = distance/speed

In this case, the distance is 90km and the speed is 30km/m.

So, time = 90km / 30km/m = 3m

Answer:

It will take 3 hours to get to the island 90km from the coast in a boat that travels 30km/m.

Answer:

The value of Time Will be

[tex]9minutes[/tex]

Explanation:

Greetings!!!

Given values:-

Distance (s)= 90km

Speed(V)= 30km/m

Required value:-

Time(t)= ?

Solution:-

But before that how did I know Time is required

So, from the given word problem it says "How long will it take" which means it's indicating the time period.

Firstly, recall speed-distance equation

[tex]speed = \frac{distance}{time} [/tex]

Substitute known variables into the equation

[tex]30km/m = \frac{90km}{t} [/tex]

Solve for time

[tex]30km/m(t) = 90km[/tex]

divide both sides of the equation by 30km/m

[tex] \frac{30km/m(t)}{30km/m} = \frac{90km}{30km/m} [/tex]

divide

[tex]t = 3m[/tex]

If you have any questions tag me on comments.

Hope it helps!!!

a 206000 kg jet has a take-off speed of 95 m/s. neglecting drag, what constant thrust force would the engines have to provide to take off at the end of a 1450 m runway?

Answers

The engines would need to provide a constant thrust force of approximately 6,040,375 N to allow the 206000 kg jet to take off at the end of a 1450 m runway, assuming negligible drag.

To determine the thrust force required for the jet to take off, we can use the equation:

Thrust force = (1/2) * (mass of jet) * [tex](take-off speed)^2[/tex] / (distance of runway)

Plugging in the given values, we get:

Thrust force = (1/2) * (206000 kg) * [tex](95 m/s)^2[/tex] / (1450 m)

Thrust force = 6,040,375 N

The thrust force required for a jet to take off at the end of a runway can be determined using the equation that takes into account the mass of the jet, take-off speed, and the distance of the runway. Neglecting drag, the engines would need to provide a constant thrust force of approximately 6,040,375 N for a 206000 kg jet to take off at the end of a 1450 m runway.

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Calculate the weight of an object of mass 15Kg kept on the earth. If the same object is taken to mars, what change will happen to its mass and weight?(freefall acceleration on mars=3.7 m/s2)

Answers

Answer:

Weight on Mars =  55.5 Newtons

Approximately 37.72% of weight on earth

Explanation:

Mass of an object is unchanged throughout the universe

Therefore mass on Mars = mass on Earth = 15kg

Weight = mass x freefall acceleration

Weight on Earth = 15 kg x 9.81 m/s² = 147.15 Newtons (N)
Weight on Mars = 15 x 3.7 m/s² = 55.5 N

Therefore weight on Mars/ weight on earth = 55.5 N/147.15N

≈ 0.3772

= 37.72 % of weight on earth

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