Answer:(c) the solar system.
Explanation: A quasar is an extragalactic object which is believed to be the most luminous object in the universe. They radiate a very large amount of radiation and are known to be like the stars.
The solar system is a term used to describe the Sun and the objects such as the planets,Stars moving round the Sun and are attracted towards the sun by the force of gravity.
A 60-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 818 N. What is the acceleration of the elevator
Answer:
[tex]a=8.34\ m/s^2[/tex]
Explanation:
Given that,
The mass of a man, m = 60 kg
When the elevator rises, the scale rads 818 N
We need to find the acceleration of the elevator. Let it is a. The equation of motion can be written as :
F - mg = ma
Put g = 9.8 m/s²
[tex]a=\dfrac{F-mg}{m}\\\\a=\dfrac{818-60(9.8)}{60}\\\\=8.34\ m/s^2[/tex]
So, the acceleration of the elevator is [tex]8.34\ m/s^2[/tex]
what is the source of waves
Answer:
the ocean
Explanation:
the ocean I think
Answer:
The movement of the water, the way the water is movement...
Which substance is water least likely to be able to dissolve?
A. a nonpolar substance that is composed of hydrogen atoms bonded to carbon atoms
B. a polar substance that is composed of nitrogen atoms bonded to hydrogen atoms
C. a substance that is composed of positive and negative ions
D. a substance that is composed of hydrogen atoms bonded to oxygen atoms
Answer:
D
Explanation:
Took Test
At what distance above the surface of the earth is the acceleration due to the earth's gravity 0.765 m/s^2if the acceleration due to gravity at the surface has magnitude 9.80 m/s^2?answer in meters
Answer:
1.6441×10^7m
Explanation:
The distance above the surface of the earth can be calculated by finding the difference between the distance between the masses of the object and the radius of the earth which is expressed below
r= RE + h
Where
h=distance above the surface of the earth
r= distance between the masses
RE= radius of the earth= 6.3781×106 m
acceleration due to gravity can be expressed as
(g)= GmE/r^2.
Where r= distance between the masses of object
mE= mass of the earth= 5.972 × 10^24 kg
G =gravitational constant= 6.67×10^-11 m3 s-2 kg-1),
g= acceleration due to the earth's gravity= 0.765
Making r subject of the formula
r=√GmE/g
r=√[(6.67×10^-11) ×5.972 × 10^24 )]/0.765
=√5.207×10^15
=2.282×10^7m
Substitute the values in below expresion
h= r - RE
=(2.282×10^7)-(6.3781×106 m)
=1.6441×10^7m
Hence, distance above the surface of the earth is 1.6441×10^7m
What change occurs in a muscle during an eccentric contraction
Answer:
During an eccentric contraction, when an active muscle, fiber or myofibril is actively stretched, its force increases substantially during the stretch.
The action force is the balloon pushing the air out. What is the magnitude of the reaction force of the air pushing on the balloon? N.
Answer:
reaction force is 3N
Explanation:
The question is not complete.
From estudyassistant, I've gathered that the action force pushing the air out of the balloon is -3N.
Now,from Newton's third law of motion, it says, for every action, there is an equal and opposite reaction.
Thus, the reaction force will be equal and opposite in direction to the action force.
Thus, reaction force is 3N
Answer:
3n
Explanation:
edge 2021
Two asteroids with masses 5.34*10^3 kg and 2.06*10^4 are separated by distance of 5,000 m. What is the gravitational force between the astroids? Newtons law of gravitation is F gravity =Gm1 m2/ r^2. The gravitational constant G is 6.67*10^-11 N*M^2/kg^2
A. 1.4*10^-6N
B.4.00 N
C. 1.24*10^32N
D. 2.93*10^-10N
I NEED HELP ASAP
Answer:
D. 2.93*10^-10N
Explanation:
A.pex
If a 3-kg rock is thrown at a speed of 2 m/s in a gravity-free environment (presuming one could be found), then an unbalanced force of 6 N would be required to keep the rock moving at a constant speed.
Select one:
a. False
b. True
Answer:
a. False
Explanation:
For an object to be moving at a constant velocity, a net force of 0 N would be required.
Newton's 1st Law of Motion states that an object will remain at rest unless acted upon by an unbalanced force, and an object will remain in motion unless acted upon by an unbalanced force.
Therefore, the unbalanced force of 6 N would not allow the rock to maintain its constant speed.
The answer to this question is A) False.
That's false.
NO FORCE is required to keep an object moving at a constant speed.
A stoplight with weight 100 N is suspended at the midpoint of a cable strung between two posts 200 m apart. The attach points for the cable on the posts are each 15 m above the ground level. The cable is tightened until its tension is 1,000 N. How far is the stoplight attach point above ground
There are 3 forces acting on the stoplight:
• its weight W, with magnitude W = 100 N, pointing directly downward
• two tension forces T₁ and T₂ with equal magnitude T₁ = T₂ = T = 1000 N, both making an angle of θ with the horizontal, but one points left and the other points right
The stoplight is in equilibrium, so by Newton's second law, the net vertical force acting on it is 0, such that
∑ F = T₁ sin(θ) + T₂ sin(180° - θ) - W = 0
We have sin(180° - θ) = sin(θ) for all θ, so the above reduces to
2T sin(θ) = W
2 (1000 N) sin(θ) = 100 N
sin(θ) = 0.05
θ ≈ 2.87°
If y is the vertical distance between the stoplight and the ground, then
tan(θ) = (15 m - y) / (100 m)
Solve for y :
tan(2.87°) = (15 m - y) / (100 m)
y = 15 m - (100 m) tan(2.87°)
y ≈ 9.99 m
A lever is 3.2 m long. The distance from the fulcrum to the underside of a boulder to be lifted is 1.4 m. If a farmer pushes on the opposite end with 350 N, what is the maximum force that is applied to the boulder
Answer:
The value is [tex]W = 450 \ N[/tex]
Explanation:
From the question we are told that
The force applied at the other end is [tex]F = 350 \ N[/tex]
The length of the lever is [tex]l = 3.2 \ m[/tex]
The distance from the fulcrum to the underside of a boulder is [tex]x_1 = 1.4 \ m[/tex]
The distance from the fulcrum to the point where the farmer applied the force is
[tex]x_2 = 3.2 - 1.4[/tex]
=> [tex]x_2 = 1.8 \ m[/tex]
Generally at equilibrium the net torque experienced by the lever is 0 and this is mathematically represented as
[tex]F * x_2 - W * x_1 = 0[/tex]
Here W is the maximum force applied to the boulder by the lever
So
[tex]F * x_2 - W * x_1 = 0[/tex]
=> [tex]350 * 1.8- W * 1.4 = 0[/tex]
=> [tex]W = 450 \ N[/tex]
A sample of Iron has a mass of 46.8 grams and a volume of 6 cm 3. what is the density of iron?
Moving hot air balloon experiences a 30,000 N lift force up and a 30,000 N gravitational force down, what is the resulting motion of the balloon?
The net force on the balloon is zero, so it has no acceleration. So by Newton's first law, if the balloon has some velocity in a given direction, it will continue moving in that direction at a constant speed. If it's motionless, it stays motionless.
What is the gravitational acceleration close to the surface of a planet with a mass of 9ME and radius of 3RE, where ME and RE are the mass and radius of Earth, respectively?
Answer:
9.78 m/s²
Explanation:
To solve this, we use the gravitational formula
g = GM/r², where
g = acceleration due to gravity
G = gravitational constant
M = mass of the planet
r = radius of the planet
From the question, we got that the mass of the planet is
M = 9ME, where ME = 5.95*10^24
M = 9 * 5.95*10^24
M = 5.355*10^25 kg
Also, the Radius of the planet, R = 3RE, where RE = 6.37*10^6
R = 3 * 6.37*10^6
R = 1.911*10^7 m
On applying the values of both R and M to the equation, we get
g = GM/r²
g = (6.67*10^-11 * 5.355*10^25) / (1.911*10^7)²
g = 3.57*10^15/3.65*10^14
g = 9.78 m/s²
Therefore, the acceleration due to gravity on the planet is 9.78 m/s²
Please vote brainliest if it helped you <3
When the temperature of 0.0788 moles of a diatomic gas drops, its internal energy drops by -50.7 J. What was the temperature change?
Answer:
30.93
Explanation:
It is correct on Acellus
What's the average speed of an object moving 3790 meters in 249 s.
Heya!!
For calculate velocity, lets applicate formula
[tex]\boxed{d = v * t}[/tex]
Δ Being Δ
d = Distance = 3790 m
t = Time = 249 s
v = Velocity = ?
⇒ Let's replace according the formula and clear "v":
[tex]\boxed{v= 3790\ m / 249\ s}[/tex]
⇒ Resolving
[tex]\boxed{ v = 15,22 \ m/s }[/tex]
Result:
The velocity is 15,22 meters per second.
Good Luck!!
Pls help physics homework
True or False:
- Gravity depends on the material of the objects.
- Gravity is not a force because it cant move objects
- Gravity is a force because a force is a push or a pull
- The moon has less gravity than the earth because it has less mass than the earth
- The moon has less gravity than the earth because it has no atmosphere
A heat engine performs (245 + A) J of work in each cycle while also delivering (142 + B) J of heat to the cold reservoir. Find the efficiency of the heat engine. Give your answer in percent (%) and with 3 significant figures.
A=14, B=72
Answer:
The value is [tex]\eta = 54.4 \%[/tex]
Explanation:
From the question we are told that
The work input is [tex]W = ( 245 + A ) \ J[/tex]
The heat delivered is [tex]Q = (142 + B) \ J[/tex]
The value of A is A = 14
The value of B is B = 72
Generally the efficiency of the heat engine is mathematically represented as
[tex]\eta = \frac{W}{Q_t}[/tex]
Here [tex]Q_t[/tex] is the total out energy produce by the heat engine and this is mathematically represented as
[tex]Q_t= Q + W[/tex]
=> [tex]Q_t= 245 + A + 142 + B[/tex]
=> [tex]Q_t= 390 + A+B[/tex]
So
[tex]\eta = \frac{245 + A }{390 + A+ B}[/tex]
=> [tex]\eta = 0.544[/tex]
=> [tex]\eta = 0.544 *100[/tex]
=> [tex]\eta = 54.4 \%[/tex]
An elite Tour de France cyclist can maintain an output power of 450 W during a sustained climb. At this output power, how long would it take an 88 kg cyclist (including the mass of his bike) to climb the famed 1100-m-high Alpe d'Huez mountain stage?
Answer:
T = 35' 08"
Explanation:
By definition, the power is the rate of change of energy, with respect to time:[tex]P = \frac{\Delta E}{\Delta t} (1)[/tex]
ΔE, in this case, must be equal to the change in the gravitational potential energy during the climb (neglecting friction), as follows:[tex]\Delta E = m*g*h = 88 kg*9.8m/s2*1100 m = 948640 J (2)[/tex]
From (1) and (2), being P= 450 W, we can solve for Δt, as follows:[tex]\Delta t = \frac{\Delta E}{P} = \frac{948640J}{450W} = 2108 sec. (3)[/tex]
Converting seconds to minutes, we get: Δt = 35' 08"Give me a copy and pasted bible lol
Answer:
what
Explanation:
A 10,000 W motor operates an elevator weighing 5000 N. Assuming no frictional losses, how high is the elevator raised in 10 seconds.
Answer:
20 meters
Explanation:
Given that
Power of the motor, P = 10,000 Watts
Weight of the motor, w = 5,000 Newton
Time used in raising the elevator, t = 10 seconds.
Height the elevator was raised through, h = ?
To find this, we're going to use simple relationship between them all.
Say, we find the power to weight ratio which is, Power / Weight
10,000 / 5,000 = 2
This power to weight ratio is then multiplied by the time used in moving the elevator to get the distance through which it moved.
2 * 10 = 20 meters.
A shear force of 400 N is applied to one face of an aluminum cube with sides of 30 cm. What is the resulting relative displacement? (the shear modulus for aluminum is 2.5x1010N/m2)
Answer:
5.3 × 10^(-8) m
Explanation:
We are given;
Shear force; F = 400 N
Length of cube; L_o = 30 cm = 0.3 m
Shear modulus; S = 2.5 × 10^(10) N/m²
Now,the resulting relative displacement can be gotten from the formula;
F = A × S × Δx/L_o
Where Δx is resulting relative displacement
A is area.
Area of cube = (L_o)² = 0.3² = 0.09
Thus, making Δx the subject, we have;
Δx = (F × L_o)/(A × S)
Plugging in the relevant values;
Δx = (400 × 0.3)/(0.09 × 2.5 × 10^(10))
Δx = 5.3 × 10^(-8) m
By what factor is the self-inductance of an air solenoid changed if its length and number of coil turns are both tripled
Answer:
The new self inductance is 3 times of the initial self inductance.
Explanation:
The self inductance of a solenoid is given by :
[tex]L=\dfrac{\mu_oN^2 A}{L}[/tex]
Where
N is number of turns per unit length
A is area of cross section
l is length of solenoid
If length and number of coil turns are both tripled,
l' = 3l and N' = 3N
New self inductance is given by :
[tex]L'=\dfrac{\mu_oN'^2 A}{L'}\\\\=\dfrac{\mu_o(3N)^2 A}{3L}\\\\=3\dfrac{\mu_oN^2 A}{L}\\\\=3L[/tex]
So, the new self inductance is 3 times of the initial self inductance.
Please help and if you get this and answer the other one on my thing i’ll give u brainliest
How does increasing the energy of a wave affect its wavelength?
The increase in energy causes an increase in wavelength.
The shorter the wavelength, the lower the energy.
The higher the energy, the shorter the wavelength.
There is no relationship between energy and wavelength.
Answer:
The higher the energy, the shorter the wavelength.
Explanation:
Two long current-carrying wires run parallel to each other and are separated by a distance of 5.00 cm. If the current in one wire is 1.80 A and the current in the other wire is 3.45 A running in the opposite direction, determine the magnitude and direction of the force per unit length the wires exert on each other.
Answer:
2.48*10^-5 N/m
Explanation:
The magnitude force per unit length on parallel wires separated by a distance D and currents I1 & I2.
F/l = µ.I1.I2/2πd
Where
µ = 4π *10^-7
I1 = 1.80 A
I2 = 3.45 A
d = 5 cm = 0.05 m
F/l = (4π*10^-7 * 1.8 * 3.45) / (2 * π * 0.05)
F/l = (1.2568*10^-6 * 6.21) / 0.3142
F/I = 7.8*10^-6 / 0.3142
F/l = 2.48*10^-5 N/m
Therefore, the magnitude of the force per unit length is 2.48*10^-5 N/m
Question 1 options:
steam engines to be used on a small enough scale for personal transportation
steam engines to operate using only hot steam
turbines to convert steam energy into kinetic energy
steam to be used to do work
Answer:
Steam engines to operate using only hot steam
Explanation: i took the quiz
What is the total distance that the object traveled?
Answer:
for what?
Explanation:
d=S x T
or
d=vt+1/2at2
srry if wrong but
hope this helps
take care
Two or more waves combining to produce a wave with a smaller displacement is called
What is true of any ferromagnetic material?
Answer:
Standing Wave
Explanation:
Destructive interference. Occurs when two or more waves combine to produce a wave with a smaller displacements
A car travelled a distance of 200 m with initial velocity of 216 km/hr. Calculate the acceleration
in meters per second of the car if it has a final velocity of 360 km/hr.
Answer:
[tex]a = 16\ m/s^2[/tex]
Explanation:
When the velocity changes uniformly, the object has a constant acceleration. The acceleration, the velocities, and the distance are related by the equation:
[tex]v_f^2=v_o^2+2ax[/tex]
Where:
vf = final velocity
vo = initial velocity
a = acceleration
x = distance
Solving for a:
[tex]\displaystyle a=\frac{v_f^2-v_o^2}{2x}[/tex]
The car travels a distance of x=200 m and the velocities are:
vo = 216 Km/h
vf = 360 Km/h
Both velocities must be converted to meters by seconds.
vo = 216 Km/h *1000/3600 = 60 m/s
vf = 360 Km/h *1000/3600 = 100 m/s
The acceleration is:
[tex]\displaystyle a=\frac{100^2-60^2}{2*200}[/tex]
[tex]\displaystyle a=\frac{10000-3600}{400}[/tex]
[tex]\displaystyle a=\frac{6400}{400}[/tex]
[tex]\mathbf{a = 16\ m/s^2}[/tex]
If it takes 7.4 s to run up the stairs at your house, and you run an average speed of 1.2 m/s, how tall is your staircase?
A driveway is illuminated at night by identical lamps at the top of two poles 30 ft high and 40 ft apart. Assuming the lamps radiate equally in all directions, compare the illumi- nance at ground level for points directly under one lamp and midway between them.
Answer:
Step 1 of 3
Step 1 of 3Solution:
Step 1 of 3Solution:Height of two poles is 
Step 1 of 3Solution:Height of two poles is Distance between two poles is 
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp isNow illuminance of two lamps at a point at ground level which is midways between two poles is
Step 1 of 3Solution:Height of two poles is Distance between two poles is It is given that there are two identical lamps at the top of two poles which radiate equally in all directions. Thus powers of the two lamps are equal then.Now illuminance of two lamps at a point at ground level directly below one lamp isNow illuminance of two lamps at a point at ground level which is midways between two poles is
Illuminance is greater at midpoint of the ground compare to points directly under one lamp.
Given that, height of the two pole is = 30 ft.
Distance between the two pole is = 40 ft.
And, the lamps radiate equally in all directions, so illuminance of two light is same. say, it is I.
The light intensity is inversely proportional to the square of the distance.
So, at a point directly under one lamp, total intensity is = I/30² + I/(30²+40²) = 0.001511 I.
And, at a point midway between them, total intensity is = 2×I/(30²+20²) = 0.001538I.
Hence, at midpoint of the ground, illuminance is greater.
Learn more about illumination here:
https://brainly.com/question/15300512
#SPJ5
