the magnitude of the electrostatic force getween two identical ions that are seperated by a distance of

Answer:

The experiments are not shown, so I will answer in a general way.

By the first Newton's law, an object will only change it's velocity if there is a net force different than zero acting on the object.

Then in the experiments (depending on the experiment), you can see different things.

If an object is not moving and you apply a force in it, the object will move.

If an object is moving and you apply a force in the opposite direction of it's motion, the motion will: decrease the speed, stop at all, or move in the opposite direction. Depending on the force that you apply.

An excellent experiment (but hard to do) is dropping an object from a really high place.

The gravitational force will pull down the object and the object will start to increase it's velocity.

But there is the air resistance, that opposes to this motion and increases with the speed of the object.

Then there is a given speed such that the air resistance force will be equal to the gravitational force, then we have a balanced force (the net force is zero) which means that the object will keep falling at a constant velocity.

Answer:

Explanation:

Since the fans are blowing in opposite directions, the net force stays the same and so does the velocity. (I wrote this and got it right)

Answer: 96

Explanation:

Complete question is;

The abc battery company claims that their batteries last 100 hours, on average. You decide to conduct a test to see if the company's claim is true. You believe that the mean life may be different from the 100 hours the company claims. you decide to collect data on the average battery life (in hours) of a random sample of n = 20 batteries. some of the information related to the hypothesis test is presented below:

Test of H0: μ = 100 versus H1: μ ≠ 100

Sample mean: 98.5

Std error of mean: 0.777

Assuming the life length of batteries is normally distributed, what is the p-value associated with this test?

Answer:

p-value =  0.00001

Explanation:

We are given;

Null hypothesis; H0: μ = 100

Alternative Hypothesis; H1: μ ≠ 100

Sample mean: x = 98.5

Standard error of mean; s = 0.777

To find the test statistic, we will use the formula;

t = (x - μ)/(s/√n)

t = (98.5 - 100)/(0.777/√20)

t = -1.5/0.1737

t = -8.64

Now, from online p-value from t-score calculator attached, using t = -8.64; DF = n - 1 = 20 - 1 = 19; two tail distribution;significance level of 0.05; we have;

The p-value =  0.00001

In a perfectly inelastic collision between two identical gliders, all of the initial kinetic energy of the first glider is transformed into thermal energy. Therefore, the fraction of the first glider's initial kinetic energy transformed into thermal energy is 100%.

Let's assume the initial kinetic energy of the first glider is K₁ and the final kinetic energy after the collision is Kf. Since the second glider is initially at rest, its initial kinetic energy is zero.

During the collision, the initial kinetic energy of the first glider is completely transferred to the combined system. Therefore, the final kinetic energy can be expressed as Kf = K₁ + 0 = K₁.

The fraction of the first glider's initial kinetic energy transformed into thermal energy can be calculated as:

Fraction = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy

        = (K₁ - K₁) / K₁

        = 0 / K₁

        = 0

Thus, in a perfectly inelastic collision, all of the initial kinetic energy of the first glider is transformed into thermal energy.

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An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction of the first glider's initial kinetic energy is transformed into thermal energy in this collision?

Experimenting with different material properties and transparency settings can indeed help create reflective surfaces. Your approach of adjusting the transparency and reflectivity properties of the material can certainly contribute to achieving the desired result.

It's great to explore and share creative techniques like this to enhance visual representations. Keep up the experimentation and enjoy the process of creating visually appealing scenes!

Creating realistic reflections in a virtual environment can greatly enhance the visual quality of a scene. Here are some additional tips and techniques to consider when working with reflective materials:

Material settings: In addition to adjusting the transparency and reflectivity properties, you can experiment with other material settings such as glossiness, roughness, and index of refraction. These properties can influence the appearance and behavior of the reflections.

Environment setup: The surrounding environment plays a crucial role in creating reflections. You can place objects or a skybox around the reflective material to provide something for it to reflect. This will add depth and realism to the scene.

Light sources: Proper lighting is essential for realistic reflections. Make sure to position light sources strategically to create accurate reflections based on the scene's lighting conditions. Consider using techniques like global illumination or ray tracing for more accurate and physically-based reflections.

Texture mapping: Applying textures to reflective surfaces can add more visual interest and realism. Consider using environment maps or HDR (high dynamic range) images to provide accurate reflections based on the scene's surroundings.

Post-processing effects: After rendering your scene, you can further enhance reflections using post-processing techniques. These include adding bloom or glare effects to create more dynamic and eye-catching reflections.

Remember, the specific techniques and settings may vary depending on the software or rendering engine you are using. It's always recommended to consult the documentation or tutorials specific to your chosen tools to learn more about creating realistic reflections in virtual environments.

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Answer:

Examples are stated below.

Explanation:

Observation is simply when we make use of one or more of our sense to gather information while inference is simply the explanation/conclusion we make for what we observed.

Examples are as follows;

1) - Observation: There a lot of questions on google about the year 2021 being the end of the world.

Inference:

- Many people are just too lazy to do their own proper research.

2) - Observation: There is far more cold in the winter than in summer.

- Inference: Very little sunlight shines on the Earth's surface during the winter season.

3) - Observation: The fire alarm in the school is ringing.

-Inference: The school is burning

4) - Observation: The burglar alarm in the bank is ringing.

-Inference: Robbers have broken into the bank.

5) - Observation: The field in the school is very wet.

Inference: There was heavy Rainfall in the school.

A) The local change of temperature is given by ∇T = (3y^3z^4)i + (9xy^2z^4)j + (12xy^3z^3)k.
B) This describes cold air advection because the horizontal velocity vector has a positive x-component.
C) The units for the local change of temperature would be the same as the units of the temperature function T, which in this example would be m * s³ * kg⁴.

A) To solve for the local change of temperature, we need to find the gradient of the temperature function. The gradient (∇) is a vector operator that represents the rate and direction of the steepest increase of a function. In this case, the temperature function T = 3xy^3z^4.
∇T = (∂T/∂x)i + (∂T/∂y)j + (∂T/∂z)k
Using the given temperature function, we can calculate the partial derivatives with respect to each variable:
∂T/∂x = 3y^3z^4
∂T/∂y = 9xy^2z^4
∂T/∂z = 12xy^3z^3
So, the gradient of the temperature function is:
∇T = (3y^3z^4)i + (9xy^2z^4)j + (12xy^3z^3)k
B) To determine if this describes warm or cold air advection, we need to consider the sign of the horizontal velocity vector. The horizontal velocity vector V = 7xi + 2x^3y^2j has a positive x-component (7xi), indicating a rightward motion. If the air parcel is moving rightward, it means it is being transported from a warmer region to a colder region. Therefore, this describes cold air advection.
C) The units for the local change of temperature will depend on the units of the temperature function T. Since the temperature function T = 3xy^3z^4, the units of T would be the product of the units of x, y, and z. Let's say x is in meters (m), y is in seconds (s), and z is in kilograms (kg). Then, the units of T would be m * s^3 * kg^4.
Therefore, the units for the local change of temperature, which is the gradient of T, would be the same as the units of T, which in this example would be m * s^3 * kg^4.
In summary:
A) The local change of temperature is given by ∇T = (3y^3z^4)i + (9xy^2z^4)j + (12xy^3z^3)k.
B) This describes cold air advection because the horizontal velocity vector has a positive x-component.
C) The units for the local change of temperature would be the same as the units of the temperature function T, which in this example would be m * s³ * kg⁴.

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a) When voltage drops by 15%, the current remains the same. ; b) If the resistance of the device were reduced by 15% the current is 4.76 A.

(a) The voltage in the first instance is 240 V. Therefore, a voltage drop of 15% means that the new voltage will be

240 V - 15% × 240 V

= 240 V - (15/100) × 240 V

= 204 V.

Since P = VI and assuming that the power (P) remains the same, then the new current is given by:

5.6 A = P/240 V ,

therefore P = 5.6 A × 240 V

= 1344 W.5.6 A

= 1344 W / 240 V,

therefore 5.6 A = 5.6 A.

When voltage drops by 15%, the current remains the same.

(b) If the resistance is reduced by 15%, it implies that the new resistance (R₁) is 85% of the initial resistance (R₀) so that R₁ = 0.85R₀.

Since P = VI and P = V²/R, the new current, I₁ is given by: P = I₁V₁= I₀V₀,

which implies that I₁ = I₀ × V₀/V₁

= I₀ × R₁/R₀.

For the initial condition, the current is given by 5.6 A.

Therefore, the new current, I₁ is given by:

I₁ = I₀ × R₁/R₀

= 5.6 A × (0.85R0 / R₀)I₁

= 4.76 A.

Therefore, the current is 4.76 A.

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Answer:B

Explanation:

Answer:

Not 100% sure but..

Explanation:

I think it's b. If the forces are equal and opposite it either makes the object move at a constant speed or makes it stop. I don't think that it will change it's shape though.

According to Newton's Law of Cooling, the temperature of the white wine will have dropped by approximately 17.3 degrees Fahrenheit by 6 P.M. The temperature of the wine at 6 P.M. will be around 50.7 degrees Fahrenheit.

Newton's Law of Cooling describes how the temperature of an object changes over time when placed in a different environment. It states that the rate of change of temperature of an object is proportional to the difference between its current temperature and the surrounding temperature.

In this scenario, the temperature of the white wine is changing at a rate of -18e^(-0.6t) degrees Fahrenheit per hour. To determine how much the temperature will drop by 6 P.M., we need to integrate this rate of change from 4 P.M. to 6 P.M.:

∫[-18e^(-0.6t)]dt from t=0 to t=2

Integrating this expression gives us the change in temperature:

-18∫e^(-0.6t)dt from t=0 to t=2

= -18[-(5/3)e^(-0.6t)] from t=0 to t=2

≈ 17.3 degrees Fahrenheit

Therefore, the temperature of the wine will have dropped by approximately 17.3 degrees Fahrenheit by 6 P.M.

To find the temperature of the wine at 6 P.M., we need to subtract the temperature drop from the initial temperature of 68 degrees Fahrenheit:

68 - 17.3 ≈ 50.7 degrees Fahrenheit

Hence, the temperature of the wine at 6 P.M. will be around 50.7 degrees Fahrenheit.

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The type of figurative language present in the example "in leaves no step had trodden black" is personification.

Personification is a figure of speech in which human qualities or actions are attributed to non-human entities. In the given example, the phrase "leaves no step had trodden black" personifies the leaves by suggesting that they have the ability to tread or walk.

By attributing the human action of stepping to the leaves, the poet gives them a sense of agency and animates them. This personification enhances the imagery of the poem, creating a vivid picture of untouched and unexplored surroundings, where the leaves have remained undisturbed.

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The figurative language present in the phrase 'In leaves no step had trodden black' is imagery. This phrase creates a visual image for the reader, contrasting with symbol, metaphor, and personification.

The phrase 'In leaves no step had trodden black' from your question is an example of imagery. Imagery refers to language that appeals to one or more of the five senses. Here, this phrase creates a visual image of untouched leaves, helping the reader to more vividly imagine the scene being described. It does not suit the definitions of symbol, metaphor, or personification. A symbol represents itself and something else simultaneously, a metaphor makes a direct comparison between two unlike things, and personification assigns human traits to non-human entities or concepts. In this case, the leaves are not representing something else (symbol), not being compared directly with something else (metaphor), and not given human traits (personification).

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Answer:

The angle α which the resultant R makes with A is given by

tanα=

A+Bcosθ

Bsinθ

or

cos(θ/2)

sin(θ/2)

=

A+Bcosθ

2Bsin(θ/2)cos(θ/2)

which gives A+Bcosθ=2Bcos

2

(

2

θ

)

or A+B[2cos

2

(

2

θ

)−1]=2Bcos

2

(

2

θ

)

A=B

The given statement "True or false, the three stages of collision include the vehicle crash, the human crash, and the external crash" is False.

The stages of collision include three steps namely: the vehicle collision, the human collision, and the internal collision. The stages of collision are as follows:Vehicle collision: In this stage, the vehicles collide and crush each other which results in the sudden deformation of the vehicle.Human collision:

In this stage, the occupants of the vehicle crash and experience injury due to the collision.Internal collision: In this stage, internal organs are affected due to the sudden change in speed and the occupants may experience life-threatening injuries due to the collision.Therefore, it is concluded that the given statement is False and the main answer is: False.

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The speed of light in a vacuum is approximately 299,792,458 meters per second. To calculate the time it takes for light to travel from the Moon to Earth, we can use the formula:

Time = Distance / Speed

Given that the distance from the Moon to Earth is approximately 3.84 x 10^8 meters and the speed of light is 299,792,458 meters per second, we can plug these values into the formula:

Time = (3.84 x 10^8) / (299,792,458) = 1.281 seconds (approximately)

Therefore, light would take approximately 1.281 seconds to travel from the Moon to Earth after an asteroid hit the Moon.

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To generate a magnetic field of 15.0 T in a superconducting solenoid with a winding of 1900 turns/m, a current of approximately X.XX kA is required.

To determine the required current for the superconducting solenoid, we can use Ampere's law, which relates the magnetic field (B) generated by a solenoid to the current (I) flowing through it. The formula is given by:

B = μ₀ * n * I

Where:

B = Magnetic field (15.0 T)

μ₀ = Permeability of free space (4π × 10⁻⁷ T·m/A)

n = Number of turns per unit length (1900 turns/m)

I = Current (to be determined)

Rearranging the equation to solve for the current (I), we have:

I = B / (μ₀ * n)

Plugging in the given values:

I = 15.0 T / (4π × 10⁻⁷ T·m/A * 1900 turns/m)

Simplifying:

I = 15.0 / (4π × 10⁻⁷ * 1900) A

I ≈ 2.46 × 10⁶ A

Converting the current to kiloamperes:

I ≈ 2.46 × 10³ kA

Therefore, the required current for the superconducting solenoid to generate a magnetic field of 15.0 T with a winding of 1900 turns/m is approximately 2.46 kA.

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The average Earth-Moon distance is approximately 3.84x10^5 km. To convert this value to millimeters, we need to multiply it by the conversion factor that represents the number of millimeters in a kilometer. Since there are 1,000,000 millimeters in one kilometer, we can perform the following calculation:

3.84x10^5 km * 1,000,000 mm/km = 3.84x10^5 * 10^6 mm = 3.84x10^11 mm.

Therefore, the average Earth-Moon distance is approximately 3.84x[tex]10^11[/tex] mm when using the 5.7899x[tex]10^6[/tex]mm format.

To explain further, the conversion from kilometers to millimeters involves multiplying the given distance by a conversion factor. In this case, we use the conversion factor of 1,000,000 mm/km because there are 1,000,000 millimeters in one kilometer. When we multiply the given distance of 3.84x[tex]10^5[/tex] km by the conversion factor, the kilometers cancel out, leaving us with the distance in millimeters.

The scientific notation is used to represent large numbers or small numbers conveniently. In this case, the answer is presented in scientific notation as 3.84x[tex]10^11[/tex] mm, which means 3.84 multiplied by 10 raised to the power of 11. This notation allows us to express the large value in a concise and standardized format.

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The gravitational potential energy between the two spherical steel balls is calculated as -2.223 × 10⁻⁵ J. The formula for the gravitational potential energy between two spherical steel balls separated by a center-to-center distance is as follows: PEg = -(GMm / r).

PEg = -(GMm / r), Where PEg denotes gravitational potential energy, G is the gravitational constant (6.67 × 10⁻¹¹ Nm²/kg²), M and m are the masses of the steel balls, and r is the center-to-center distance.

Using the formula above to evaluate the gravitational potential energy between two 10.0 kg spherical steel balls separated by a center-to-center distance of 30.0 cm, we have:

PEg = -(6.67 × 10⁻¹¹ Nm²/kg² * 10.0 kg * 10.0 kg / (0.3 m))

= -2.223 × 10⁻⁵ J

Therefore, the gravitational potential energy between the two spherical steel balls is -2.223 × 10⁻⁵ J.

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(a) What is the total number of absorbing particles in the cloud?

The total number of absorbing particles in the cloud is: number of particles = volume * number density = (4/3)pi * (5e10 cm)^3 * 0.1 cm^-3 = 5.236e31

(b) What is the average distance between absorbing particles? The average distance between absorbing particles is: average distance = (volume / number of particles)^(1/3) = (4/3)pi * (5e10 cm)^3 / 5.236e31 cm^-3)^(1/3) = 10 cm

(c) What is the mean free path in the cloud? The mean free path in the cloud is: mean free path = (average distance)^2 / number density = 10^2 cm^2 / 0.1 cm^-3 = 100 cm

(d) What is the optical depth through the center of the cloud? The optical depth through the center of the cloud is: optical depth = (mean free path) * (number density) = 100 cm * 0.1 cm^-3 = 10 cm

(e) What fraction of the radiation that passes through the center of the cloud would be absorbed? The fraction of the radiation that passes through the center of the cloud would be absorbed is: fraction absorbed = 1 - e^-(optical depth) = 1 - e^-10 = 1 - 0.3678 = 0.6322

The total number of absorbing particles in the cloud is 5.236e31, the average distance between absorbing particles is 10 cm, the mean free path in the cloud is 100 cm, the optical depth through the center of the cloud is 10 cm, and the fraction of the radiation that passes through the center of the cloud would be absorbed is 0.6322.

The total number of absorbing particles in the cloud was calculated by multiplying the volume of the cloud by the number density of the absorbing particles.

The average distance between absorbing particles was calculated by taking the cube root of the volume of the cloud divided by the number of absorbing particles.

The mean free path in the cloud was calculated by squaring the average distance between absorbing particles and dividing by the number density of the absorbing particles.

The optical depth through the center of the cloud was calculated by multiplying the mean free path in the cloud by the number density of the absorbing particles.

The fraction of the radiation that passes through the center of the cloud would be absorbed was calculated by subtracting the exponential of the optical depth from 1.

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The resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

To calculate the effective stress in the aquifer, we need to subtract the fluid pressure from the total stress.

Given:

Pressure head in the aquifer = 100 ft (or 30.48 m)

The pressure head in the aquifer is directly proportional to the fluid pressure, which can be calculated using the formula:

Fluid pressure (P) = ρ * g * h

Where:

ρ = density of the fluid (water) = approximately 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

h = pressure head

Fluid pressure = 1000 kg/m³ * 9.8 m/s² * 30.48 m ≈ 298,440 N/m² (or Pa)

The total stress in the aquifer is the sum of the fluid pressure and the effective stress. Therefore, the effective stress can be calculated by subtracting the fluid pressure from the total stress.

Now, let's consider the changes in the hydraulic head due to pumping:

Change in hydraulic head = -12 ft (or -3.66 m)

The resulting changes in each parameter will be as follows:

1. Pressure head:

The pressure head will be reduced by 12 ft, so the new pressure head will be 100 ft - 12 ft = 88 ft (or 26.82 m).

2. Fluid pressure:

The fluid pressure does not change, as it depends on the density of the fluid and the acceleration due to gravity, which remain constant.

3. Effective stress:

The effective stress can be calculated as the total stress minus the fluid pressure. Since the fluid pressure remains constant, the effective stress will also remain constant unless there are other factors affecting it.

4. Total stress:

The total stress is the sum of the fluid pressure and the effective stress. As mentioned earlier, the fluid pressure remains constant, so the total stress will decrease by the same amount as the effective stress, assuming no other factors affect the total stress.

Therefore, the resulting changes will be:

1. Pressure head: 88 ft (or 26.82 m)

2. Effective stress: No change, assuming no other factors affect it

3. Fluid pressure: No change

4. Total stress: Decreased by the same amount as the effective stress

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The trainee in the device is revolving at a speed of approximately 9.81 m/s or 0.15 rev/s.

In this scenario, the force felt by the trainee is given as 7.45 times her own weight. The force experienced by an object moving in a circle is the centripetal force, which is provided by the tension in the device.

In this case, the centripetal force is equal to the gravitational force acting on the trainee.Let's denote the trainee's weight as W. The centripetal force is then 7.45W.

The centripetal force can also be expressed as the product of the trainee's mass (m) and the acceleration towards the center of the circle (a), which is given by the formula a = v^2 / r, where v is the speed and r is the radius of the circle.

Equating the centripetal force equations, we have 7.45W = m * (v^2 / r). Since W = mg, where g is the acceleration due to gravity, we can substitute and simplify the equation to 7.45mg = m * (v^2 / r). The mass cancels out, giving 7.45g = v^2 / r.

Solving for v, we find v = √(7.45g * r). Substituting the values of g = 9.81 m/s^2 and r = 11.0 m, we get v = √(7.45 * 9.81 * 11.0) ≈ 9.81 m/s. This is the speed at which the trainee is revolving.

To express the answer in rev/s, we divide the speed by the circumference of the circle. The circumference of a circle is 2πr, so the trainee's speed in rev/s is approximately 9.81 m/s / (2π * 11.0 m) ≈ 0.15 rev/s.

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The correct free body diagram for the chandelier includes the gravitational force (mg) acting downward, the force exerted by the chains (Fe) pulling upward at an angle, and the normal force (FN) exerted by the ceiling.

The angle between one of the chains and the vertical where it contacts the chandelier can be determined using trigonometry.The expression for the magnitude of the y-component of the tension in one chain (FIv) can be written using the given information and variables available.

The tension in one chain (Fy) can be calculated using the previously derived expression for FIv.The correct free body diagram for the chandelier will show the gravitational force (mg) acting downward from the chandelier's center of mass.

The force exerted by the chains (Fe) will be directed upward and at an angle with respect to the vertical. Finally, the normal force (FN) exerted by the ceiling will counterbalance the gravitational force.

This free body diagram represents the equilibrium of forces acting on the chandelier. To find the angle between one of the chains and the vertical where it contacts the chandelier, we can consider the right triangle formed by the chain, the vertical line, and the horizontal distance between the chains (L).

By applying trigonometry, we can use the known values of h and L to calculate the angle.The magnitude of the y-component of the tension in one chain (FIv) can be determined by decomposing the force exerted by the chains (Fe) into its vertical component.

Since the chains are separated by the length L at the ceiling, the vertical component of the tension in one chain can be expressed as FIv = Fe * L / h. Using the expression for FIv, we can find the tension in one chain (Fy) by substituting the known values of Fe, L, and h into the expression.

The tension in one chain can be calculated as Fy = Fe * L / h, where Fe is the force exerted by the chains. By following these steps, the angle between the chain and the vertical, as well as the tension in one chain, can be determined based on the given information and variables.

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Answer: The rate of heat transfer from the steam to the cooling water flowing through the pipe is 2,800,000 W.

To determine the rate of heat transfer from the steam to the cooling water flowing through the pipe, we need to apply the heat transfer equation. Q = U * A * ΔT

Where Q is the rate of heat transfer U is the overall heat transfer coefficient A is the surface area through which heat transfer occurs ΔT is the temperature difference between the hot and cold fluids.

Now we can find each of these values and plug them into the equation: U-value = 700 W/m²K

Surface area = 50 m²

Temperature difference = 80°C

Rate of heat transfer (Q) = U * A * ΔT= 700 * 50 * 80= 2,800,000 W.

Therefore, the rate of heat transfer from the steam to the cooling water flowing through the pipe is 2,800,000 W.

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Answer:

the projection of a vector quantity, as force or velocity, along an axis.

Explanation:

Answer:

C

Explanation:

120 - 10 = 100

100 - 10 = 90

90 and 100 (110)

Answer = c

Answer:

c. 90-1110 mw

Explanation:

I know 100 mw is the answer and the only one you could choose is C because it is smack in the middle of 90 and 110 mw.

so The modern ac generator with a typical output capacity of (100 MW) 90-110 MW is a highly evolved machine.

Answer:

and answer is density ......

Answer:

Density is the measurement which uses g/cm³

Answer:

50 swings = 2 mins 40 secs

=> 50 swings = 160 secs

=> 1 swing = 160 / 50 secs

=> 1 swing -= 3.2 secs

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

The time period to complete 1 swing is 3.2 seconds

The calculation can be done as follows;

50 complete swings are completed in 2 minutes 40 seconds

2 minutes 40 seconds to seconds is

= 2mins to seconds is 120 seconds

= 120 seconds + 40 seconds

= 160 seconds

50 complete swings= 160 seconds

1 complete swing= 160/50

1 complete swing= 3.2

Hence the time period for 1 complete swing is 3.2 seconds

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Approximately 168,604 joules of heat energy would be released when 506 grams of liquid water freezes.

To determine the quantity of heat energy released when a given amount of liquid water freezes, we need to use the specific heat of water and the heat of fusion.

The specific heat of water is the amount of heat energy required to raise the temperature of 1 gram of water by 1 degree Celsius. It is approximately 4.18 joules/gram°C.

The heat of fusion of water is the amount of heat energy required to change 1 gram of water from a liquid state to a solid state at its freezing point, which is 0 degrees Celsius. It is approximately 334 joules/gram.

Given that we have 506 grams of liquid water, we can calculate the quantity of heat energy released during freezing using the formula:

Heat energy released = mass of water × heat of fusion

Heat energy released = 506 g × 334 J/g

Heat energy released = 168,604 J

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Answer:

Explanation:

To find the acceleration of an object given it's initial and final velocity and time taken we use the formula

[tex]a = \frac{v - u}{t} \\ [/tex]

where

v is the final velocity

u is the initial velocity

t is the time taken

a is the acceleration

From the question

v = 39 m/s

u = 27 m/s

t = 13 s

We have

[tex]a = \frac{39 - 27}{13} = \frac{12}{13} \\ = 0.923076... \: \: \: [/tex]

We have the final answer as

Hope this helps you