The experiment looks into how temperature impacts how quickly magnesium metal reacts with hydrochloric acid. The creation of hydrogen gas over time is used to determine the dependent variable, which is the reaction rate.
The experiment can be run at various temperatures to change the experiment's independent variable, which is the reaction mixture's temperature. Higher temperatures cause molecules to move more quickly, increasing the likelihood of reactant collisions and kinetic energy. By enabling more successful collisions between magnesium atoms and hydrochloric acid, can quicken the reaction and increase the amount of hydrogen gas produced. In contrast, it is anticipated that the reaction rate will be slower at lower temperatures since there will be less molecular mobility and fewer successful collisions.
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--The complete Question is, What is the effect of temperature on the rate of reaction between hydrochloric acid and magnesium metal?
The dependent variable in this experiment is the rate of reaction, which can be measured by monitoring the production of hydrogen gas over time. The independent variable is the temperature of the reaction mixture, which can be controlled and varied by conducting the experiment at different temperatures.--
Mathematically combine the three given reactions so that they sum to give a balanced chemical equation describing the production of propane, C3H8(g), from its elements, C(s,graphite) and H2(g).
Show your intermediate steps. For example, if you must reverse reaction (c), enter the reverse in the appropriate answer box; if you multiply reaction (a) by 2, enter the updated equation in the corresponding answer box. Make sure to enter the overall balanced equation at the bottom.
(a) C2H8(g)+5O2(g) --> 3CO2(g)+ 4H2O(l)
(b) C(s) + O2(g) --> CO2(g)
(c) H2(g) + 0.5O2(g) --> H2O(l)
1 Intermediate step showing reversal and/or multiplication for equation A?
2 Intermediate step showing reversal and/or multiplication for equation B?
3 Intermediate step showing reversal and/or multiplication of equation C?
4 Overall balanced equation?
The balanced chemical reaction for the production of the C₃H₈, the propane :
3C(s) + 4H₂(g) → C₃H₈(g)
The chemical equations are :
(a) C₂H₈(g)+5O₂(g) --> 3CO₂(g)+ 4H₂O(l)
(b) C(s) + O₂(g) --> CO₂(g)
(c) H₂(g) + 0.5O₂(g) --> H₂O(l)
On multiplying the reaction b by 3 we get :
3C(s) + 3O₂(g) → 3CO₂
On multiplying the reaction c by 4 we get :
4H₂(g) + 2O₂(g) → 4H₂O(l)
On adding the both the equation :
3C(s) + 4H₂(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(l)
After subtracting the equation we get the balanced chemical equation and will produce the propane, C₃H₈(g), from the elements :
3C(s) + 4H₂(g) → C₃H₈(g)
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To burn the mixture of methane CH4 and ethene C2H4, 10 mol of O2 are needed. How many moles of C2H4 are there in the mixture?
There are 3.33 moles of [tex]C_{2}H_{4}[/tex] in the mixture.
The balanced chemical equation for the combustion of methane and ethene is:
[tex]CH_{4} + 2O_{2} = CO_{2} + 2H_{2}O\\C_{2}H_{4} + 3O_{2} = 2CO_{2} + 2H_{2}O[/tex]
From the equation, we can see that for every mole of [tex]C_{2}H_{4}[/tex], 3 moles of O2 are needed. Therefore, to burn 10 moles of O2, we need:
10 moles [tex]O_{2}[/tex]x (1 mole [tex]C_{2}H_{4}[/tex]/3 moles [tex]O_{2}[/tex]) = 3.33 moles [tex]C_{2}H_{4}[/tex]
So, there are 3.33 moles of [tex]C_{2}H_{4}[/tex] in the mixture.
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1.40 g H2 is allowed to react with 9.66 g N2, producing 2.24 g NH3
What is the theoretical yield in grams for this reaction under the given conditions?
The amount of NH₃ that would be produced from H₂ is less than the amount that would be produced from N₂, H₂ is the limiting reagent. Then, the theoretical yield of NH₃ is 6.98 g.
The balanced chemical equation for the reaction between H₂ and N₂ to form NH₃ is;
N₂ + 3H₂ → 2NH₃
To calculate the theoretical yield of NH₃, we need to determine the limiting reagent in the reaction. We can do this by calculating the amount of NH₃ that would be produced from each reactant, assuming that the other reactant is in excess.
For H₂; 1 mole of H₂ (2.02 g) reacts with 0.5 moles of NH₃ (17.03 g)
Therefore, 1.40 g of H₂ would produce: (0.5 mol NH₃ / 1 mol H₂) x (17.03 g NH₃ / 1 mol NH₃) x (1.40 g H₂ / 2.02 g H₂)
= 6.98 g NH₃
For N₂ 1 mole of N₂ (28.02 g) reacts with 2 moles of NH₃ (34.06 g)
Therefore, 9.66 g of N₂ would produce; (2 mol NH₃ / 1 mol N₂) x (34.06 g NH₃ / 1 mol NH₃) x (9.66 g N₂ / 28.02 g N₂) = 23.5 g NH₃
Therefore, the theoretical yield of NH₃ is 6.98 g.
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i just told the guy i like that I like him and he said he wants to get to know me better before making a decision. but now everything feels different. he's been really distant. what does that mean and how do I stop getting so attached?
Answer: you have to talk to someone who wont mind wanting to wanting to like you a lot like that.
Explanation: I wish I could be able to talk to someone who would want to get to like me like that, so its a very relatable situation.
Enhance your oven and retest it, following the same steps as when you first tested the oven. After 30 minutes, did the oven get hotter than your original design? Give reasons.
As we know that, Because improving an oven entails increasing the heat released by the oven while it is operating, it is related to the idea of endothermic and exothermic reactions in chemistry.
Exothermic reactions emit heat into their surroundings, whereas endothermic reactions absorb heat from them. After 30 minutes of operation, the oven's modifications would probably cause it to release more heat, which would change the interior temperature. By observing the flow of heat from the heating components to the interior of the oven, the performance of the improved oven can be evaluated using the laws of thermodynamics and heat transfer.
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--The complete Question is, How does the process of enhancing an oven relate to the concept of endothermic and exothermic reactions in chemistry? Would the changes make to the oven lead to an increase or decrease in the heat released by the oven during operation, and how would this affect the temperature inside the oven after 30 minutes of use? How can the principles of thermodynamics and heat transfer be applied to analyze the performance of the enhanced oven, and what chemical reactions might be involved in the heating process? --
the solubilites of some copper compounds are shown
which method is used to make copper sulfate
The mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.
The balanced chemical equation for the reaction between copper oxide and sulfuric acid is:
[tex]CuO + H_2SO_4\ - > CuSO_4 + H_2O[/tex]
First, we need to calculate the number of moles of CuO:
n(CuO) = m/M = 25 g / 79.55 g/mol = 0.314 mol
Therefore, the number of moles [tex]CuSO_4[/tex] produced is also 0.314 mol.
Finally, we can calculate mass [tex]CuSO_4[/tex] produced:
m([tex]CuSO_4[/tex]) = n([tex]CuSO_4[/tex]) x M([tex]CuSO_4[/tex]) = 0.314 mol x 159.61 g/mol = 50.27 g
Therefore, assuming the reaction proceeds to completion, the mass of copper sulfate obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid is 50.27 grams.
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--The complete question is, What mass of copper sulfate can be obtained from the reaction of 25 grams of copper oxide with excess sulfuric acid, assuming the reaction proceeds to completion?--
Estimate the latent heat of fusion for a food product with 68% moisture content
The latent heat of fusion for a food product with 68% moisture content could be between 70-150 Joules per gram (J/g).
The latent heat of fusion is a crucial factor that determines the energy required to melt a food product. The percentage of moisture content present in a food product is a key variable that can significantly affect its latent heat of fusion. However, the latent heat of fusion for such food products is not set in stone and can vary depending on several other factors as well.
The type of food product, its composition, and melting point are some of the other key aspects that can influence a food product's latent heat of fusion. Different food products may have different latent heats depending on their composition and melting point. For instance, products with high-fat content may require more energy to melt than products with low-fat content. Similarly, if a food product has a low melting point, it may require less energy to melt.
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What is true of an aqueous solution that is 15.0 percent HNO3 by mass?
A. It contains 15.0 grams of HNO3 per 1.0 liter of water.
B. It contains 15.0 grams of HNO3 per 100 grams of solution.
C. It contains 15.0 moles of HNO3 per 100 moles of water.
D. It contains 15.0 moles of HNO3 per 100 liter of solution.
Answer:
B. It contains 15.0 grams of HNO3 per 100 grams of solution.
Explanation:
The question asks about the mass percent of HNO3 in a solution. Mass percent is the ratio of the mass of the solute (HNO3) to the mass of the solution (HNO3 + water) multiplied by 100. A solution that is 15.0 percent HNO3 by mass means that for every 100 grams of solution, there are 15.0 grams of HNO3 and 85.0 grams of water. This ratio does not change with the volume or the moles of the solution or the solute. The only answer that matches this definition is B. It contains 15.0 grams of HNO3 per 100 grams of solution.
I require assistance.
pH is defined as the negative logarithm (base 10) of the hydrogen ion concentration ([H+]) in a solution. Therefore, option (C) is correct.
In other words, the pH scale measures the acidity or basicity of a solution. The lower the pH value, the more acidic the solution is, and the higher the pH value, the more basic or alkaline the solution is.
For example, pure water has a pH of 7, which is considered neutral, meaning it is neither acidic nor basic. Acids have pH values lower than 7, while bases have pH values greater than 7. The pH scale is important in many areas of chemistry, including biochemistry, environmental science, and medicine.
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What mass (grams) of oxygen would you need to completely burn 80 grams of methane CH4?
Answer:
The mass of oxygen needed to completely burn 80 grams of methane is 320 grams.
Explanation:
The balanced chemical equation for the combustion of methane with oxygen is:
CH4 + 2O2 -> CO2 + 2H2O
From the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to form 1 mole of carbon dioxide and 2 moles of water. We can use this information, along with the molar masses of the compounds, to calculate the mass of oxygen needed to burn 80 grams of methane.
First, we need to convert the given mqss of methane to moles. The molar mass of methane is 16.04 g/mol, so:
Moles of CH4 = Mass of CH4 / Molar mass of CH4
Moles of CH4 = 80 g / 16.04 g/mol
Moles of CH4 = 4.98 mol
Next, we can use the mole ratio from the balanced equation to calculate the moles of oxygen needed:
Moles of O2 = Moles of CH4 x (2 Moles of O2 / 1 Mole of CH4)
Moles of O2 = 4.98 mol x 2
Moles of O2 = 9.96 mol
Finally, we can convert the moles of oxygen to grqms using its molar mass of 32.00 g/mol:
Mass of O2 = Moles of O2 x Molar mass of O2
Mass of O2 = 9.96 mol x 32.00 g/mol
Mass of O2 = 319.68 g
Therefore, the mass of oxygen needed to completely burn 80 grams of methane is 319.68 grams, which we can round up to 320 grams.
If 2.7 moles of lithium reacts with oxygen gas in a synthesis reaction how many moles of the product will be produced?
5.93 moles of lithium oxide i.e. the product will be produced in the reaction.
The balanced chemical equation for the synthesis of lithium oxide from lithium and oxygen gas is:
4 Li + O₂ → 2 Li₂O
We must first compute the required volume of oxygen gas in order to determine the moles of lithium oxide that are created. Going by the stoichiometry of the reaction, 2.7 moles of lithium will produce 2 moles of lithium oxide when reacted with 0.675 moles of oxygen gas.
Therefore, the amount of lithium oxide generated can be calculated as follows, The formula is 2 moles Li₂O/0.675 moles O₂*1 = 5.93 moles Li₂O.
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Calculate the pH of aqueous solutions having the following ion concentrations at 298 K [H+1 = 0.0055M
The pH of the given aqueous solution with [H+] = 0.0055 M at 298 K is approximately 2.26.
The formula used to find the pH of the solution is given as,
pH = -log[H+]
Substituting [H+] = 0.0055 M into the above formula, we get,
pH = -log(0.0055) ≈ 2.26
Therefore, the pH of the given aqueous solution with [H+] = 0.0055 M at 298 K is around 2.26.
A solution's acidity or basicity is determined by its pH. It is described as the hydrogen ion concentration's negative logarithm, pH = -log(H+). It is commonly expressed as [H+] and measured in units of moles per litre (M).
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Use the band of stability to determine if europium-154 is a stable or unstable nucleus. Hint: You
must first find the atomic number to determine the number of protons and then use the equation,
neutrons = mass number - protons, to find the neutrons.
On/Z=0.69, unstable
On/Z=0.69, stable
On/Z=1.44, unstable
On/Z=1.44, stable
Answer:
1.44 STABLE
Explanation:
Diethylamine draw structural formula
Answer:
The structural formula for diethylamine is C4H11N
Explanation:
Match each tern with its definition by writing the letter of the correct definition on
the line beside tite term.
Answer:
3. d
4. c
5. i
6. h
7. a
8. g
9. j
10. b
11. e
12. f
Explanation:
Write the empirical formula of at least four binary ionic compounds that could be formed form the following ions: Fe2+,Au3+, Cl-,O2-
To write the empirical formula of a binary ionic compound. Here are four possible binary ionic compounds that could be formed from the given ions:
Iron (II) chloride: [tex]FeCl_2 (Fe_2+ and\ 2 Cl-)[/tex]
Iron (II) oxide: FeO[tex](Fe_2+ and O_2-)[/tex]
Gold (III) chloride: [tex]AuCl_3[/tex] ([tex]Au_3[/tex]+ and 3 Cl-)
Gold (III) oxide: [tex]Au_2O_3[/tex] (2 [tex]Au_3[/tex]+ and 3 O2-)
We need to balance the charges of the cation and anion by using the lowest possible whole-number ratio of the ions. The charges of the cation and anion in each combination equal zero. The empirical formulas depict each compound's simplest whole number ion ratio. In each compound, the charges of the cation and anion balance out to zero. These formulas represent the simplest whole-number ratio of ions in each compound.
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Calculate the amount of heat, in calories, that must be added to warm 89.7 g
of brick (0.20) from 22.0 °C
to 44.1 °C.
Assume no changes in state occur during this change in temperature.
A car's engine block is made of steel and has a mass of 21080g. How much heat (J) is absorbed by the engine block when its temperature is raised from 20°C to 90°C?
The heat absorbed by the engine block when its temperature is raised from 20°C to 90°C is 665,640 J.
To calculate the heat absorbed by the engine block, we can use the equation:
Q = mcΔT
where Q is the heat absorbed, m is the mass of the engine block, c is the specific heat capacity of steel, and ΔT is the change in temperature.
First, we need to calculate the specific heat capacity of steel. The specific heat capacity of steel is typically around 0.45 J/g°C.
Using this value and the given values of mass and temperature change, we can calculate the heat absorbed by the engine block as follows:
Q = (21080 g) x (0.45 J/g°C) x (90°C - 20°C)
Q = 21080 g x 0.45 J/g°C x 70°C
Q = 665,640 J
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Given the equation, Na+ + CI→ NaCl, calculate the mass of NaCl produced by the reaction of 54.2 g of chloride ions with an excess of sodium. A. 165.0 g B. 17.8 g c. 72.0 g D. 219.2 g E. 89.3 g
The mass of NaCl produced by the reaction of 54.2 g of chloride ions with an excess of sodium is 89.51 grams.
How to calculate mass using stoichiometry?Stoichiometry is the concentration of a substance in solution, expressed as the number of moles of solute per litre of solution.
According to this question, 1 mole of sodium reacts with 1 mole chloride ion to produce 1 mole of sodium chloride.
54.2 grams of chlorine is equivalent to 1.53 moles. Hence, 1.53 moles of sodium chloride will be produced.
1.53 moles of sodium chloride is equivalent to 89.51 grams.
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(3 sig figs) Given the chemical equation below, with 202 grams of Barium Oxide being produced how many grams of Aluminum Oxide would you need? 3 BaSO4 + Al203 —>
3 Ba0 + Al2(SO4)3
44.4 g is the mass of Aluminum Oxide is required for the given chemical reaction 3 BaSO[tex]_4[/tex] + Al[tex]_2[/tex]O[tex]_3[/tex]—> 3 BaO + Al[tex]_2[/tex](SO[tex]_4[/tex])[tex]_3[/tex].
It is the most fundamental characteristic of matter as well as one of the essential quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilogramme (kg) is the international standard of mass. A body's bulk remains constant at all times. only in rare instances where an enormous quantity of energy is supplied to or taken away from a body.
3 BaSO[tex]_4[/tex] + Al[tex]_2[/tex]O[tex]_3[/tex]—> 3 BaO + Al[tex]_2[/tex](SO[tex]_4[/tex])[tex]_3[/tex]
moles of BaO =202/ 153.3
=1.32
moles of Al[tex]_2[/tex]O[tex]_3[/tex] = 1/3×1.32=0.44
mass of Al[tex]_2[/tex]O[tex]_3[/tex] = 0.44×101.9=44.4 g
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The materials and procedures are listed in your virtual lab. You do not need to repeat them here. Please clearly define the dependent and independent variables of the experiment.
Independent
Variable:
Dependent
Variable:
The independent variable in the experiment is the temperature of the hydrochloric acid, which is controlled and manipulated by the experimenter.
Different temperatures are tested to observe the effect on the rate of reaction. The dependent variable is the rate of reaction between magnesium and hydrochloric acid, which is the variable that is measured or observed as a result of changing the temperature. The reaction rate can be measured by monitoring the production of hydrogen gas, the disappearance of magnesium, or changes in the temperature of the reaction mixture. The independent variable is the temperature of the hydrochloric acid, and the dependent variable is the rate of reaction between magnesium and hydrochloric acid.
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--The complete Question is, In an experiment to investigate the effect of temperature on the rate of reaction between magnesium and hydrochloric acid, what is the independent variable and what is the dependent variable? --
If you evaporated 150. mL of a 3.5 M solution of iron (II) nitrite, how many moles of iron (II) nitrite would you recover?
Taking into account the definition of molarity, you would recover 0.525 moles of iron (II) nitrite.
Definition of molarityMolar concentration or molarity indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
molarity= number of moles÷ volume
Molarity is expressed in units moles/L.
Moles of iron (II) nitriteIn this case, you have:
Molarity= 3.5 MNumber of moles= ?Volume= 150 mL= 0.150 L (being 1000 mL= 1 L)Replacing in the definition of molarity:
3.5 M= number of moles÷ 0.150 L
Solving:
3.5 M× 0.150 L= number of moles
0.525 moles= number of moles
Finally, you would recover 0.525 moles.
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which has the lowest number of valence electrons? and how many does each have?
Mg2+
Ga+
Ar+
C+
S2-
F-
Fluorine (F-) is the element with the fewest valence electrons. Seven electrons make up the outermost shell of fluorine, and one of them is unpaired. As a result, fluorine possesses seven valence electrons altogether.
Eight valence electrons are present in magnesium (Mg2+), nine are present in gallium (Ga+), eight are present in argon (Ar+), four are present in carbon (C+), six are present in sulphur (S2-), and seven are present in fluorine (F-).
Fluorine has a lower number of valence electrons than the other elements because it has a greater effective nuclear charge. This indicates that the fluorine atom will take electrons away from its outermost shell since it is more attracted to electrons than the other elements.
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PLEASE HELP ME very urgent i’m sorry I can’t give a lot of points it’s not letting me
Answer:a=10.3 b=250.7c c= gass d= liquid
Explanation:
A sample of 2.0 grams of helium gas is contained in a tank with a volume of 5.0 L at a temperature of 25° C. what is the pressure of the gas in the tank in atm?
After some salt was added to it, a 45.4 g solution in a coffee-cup calorimeter increased in temperature from 23.0 oC to 31.5 oC.
The specific heat constant
(c) for the solution is 1 cal/g oC. The q of the reaction is ________ cal
The heat absorbed by the solution is 386.9 cal.
First, we need to calculate the heat absorbed by the solution using the formula:
q = m × c × ΔT
Where q is the heat absorbed, m is the mass of the solution, c is the specific heat constant, and ΔT is the change in temperature.
m = 45.4 g
c = 1 cal/g oC
ΔT = 31.5 oC - 23.0 oC = 8.5 oC
Substituting the values in the formula, we get:
q = 45.4 g × 1 cal/g oC × 8.5 oC
q = 386.9 cal
Therefore, the heat absorbed by the solution is 386.9 cal.
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How many liters of hydrogen, measured at STP, would be needed to produce 88.5 grams of ammonia NH3?
174.72 liters of hydrogen, measured at STP, would be needed to produce 88.5 grams of ammonia
The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.
A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.
Given,
Mass of ammonia = 88.5g
Moles of ammonia = mass / molar mass
= 88.5 / 17
= 5.20 moles
From the reaction,
3 moles of hydrogen are needed to produce 2 moles of ammonia
Thus, 1 mole of ammonia is produced by 3/2 moles of hydrogen
So, 5.20 moles of ammonia is produced by (3 × 5.2) ÷ 2
= 7.8 moles of hydrogen
1 mole of a gas occupies 22.4 L of volume
7.8 moles occupy = 7.8 × 22.4 = 174.72 L
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Ammonia (NH3) has a heat of vaporization of 23.4 kJ/mol. What quantity of energy (in kilojoules) is required to change 50.5 grams of ammonia from the liquid to the gaseous state?
50.5 grams of ammonia requires 69.498 kJ of energy to vaporize from the liquid to the gaseous state.
To calculate the energy required to vaporize 50.5 grams of ammonia (NH3), we need to first convert the mass of NH3 to moles:
moles of NH3 = mass / molar mass
moles of NH3 = 50.5 g / 17.03 g/mol
moles of NH3 = 2.97 mol
The energy required to vaporize 1 mole of NH3 is 23.4 kJ/mol. Therefore, the energy required to vaporize 2.97 moles of NH3 is:
energy = moles of NH3 x heat of vaporization
energy = 2.97 mol x 23.4 kJ/mol
energy = 69.498 kJ
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What quality does Tom Walker and his wife have in common?
The qualities Tom Walker and his wife have in common were they both were grasping and without conscience
The question has been asked from the story "The Devil and Tom Walker" by Washington Irving. As the story describes Tom's encounter with the devil, he is a complex character. However, he and his wife seem to complement each other well and have some personality traits in common. Tom and his wife are both miserly, avaricious, cruel, and morally void.
More so than her husband, Tom's stereotypically nagging, scolding wife verbally and perhaps even physically abuses him when she's not hoarding his valuables. Tom's wife courageously decides to accept Old Scratch's offer to sell her husband's soul for money when Tom first rejects it. She takes the family's silver into the swamp with her so she may haggle with the devil.
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What mass (grams) of antimony(III) chloride would be produced by reacting with 112 liters of chlorine measured at STP?
Answer:
radius = 16 in ; height = 27 in
