Answer:
Thomson’s model
Explanation:
Thompson regarded the atom largely as a sphere of positively charged matter in which negative charges were embedded.
This came to be known as the plum pudding model of the atom because it resembles a pudding studded with currants.
This was an early model of the atom and did not survive further experimental scrutiny of the structure of the atom.
Answer:
Thompsons model
Explanation:
i got it right on the quiz
famous comparative and superlative form
Answer:
comparative----more famous, superlative----- most famous
[tex]\huge{\fbox{\red{Answer:}}}[/tex]
Word Given :Famous
___________________✍
Comparative Form : more famous
Superlative Form : most famous
Hope you understand❣
Which is NOT true of balanced forces?
A. Balanced forces will cause the motion of an object to
increase
B. Balanced forces are two equal forces pushing against
each other on an object,
C. Balanced forces do not cause a change in the motion of
an object
An object accelerates to a velocity of 230 m/s over a time of 2.5 s. The acceleration it experienced was 42 m/s2. What was its initial velocity?
Answer:
230 = x + 105
x= 125
Explanation:
v = v0 + at
A driver of a car stopped at a gas station to fill up his gas tank. He looked at his watch, and the time read exactly 4 : 45 4:45 p.m. At this time, he started pumping gas into the tank. At exactly 4 : 50 4:50, the tank was full and he noticed that he had pumped 12.5 12.5 gallons. What is the average rate of flow of the gasoline into the gas tank
Answer:
Explanation:
Average rate = gallons / minutes
If 12.5gallons in 5mins
Xgallons in 1mins
12.5/5 = 2.5gallons per minute
Which statement accurately describes electronic tools? Check all that apply
Answer:
Electronic tools provide more accurate data and this data is more efficient fast and easy to understand
Hope this helps you!!
If the reading of a linear scale is 4 mm and no of division of the circular scale is 50, then what will be the diameter of the wire in mm? (Least count = 0.01) * 2 points 2.25 3.5 4.5 9.0
Answer:
Diameter of Wire = 4.5 mm
Explanation:
First, we need to find the fractional part of the reading. The fractional part o the reading can be given by the following formula:
Fractional Part = Circular Scale Reading x Least Count
where,
Circular Scale Reading = 50
Least Count = 0.01 mm
Therefore,
Fractional Part = (50)(0.01 mm)
Fractional Part = 0.5 mm
Now, the diameter of the wire can be given by using the following formula:
Diameter of Wire = Linear Scale Reading + Fractional Part
Diameter of Wire = 4 mm + 0.5 mm
Diameter of Wire = 4.5 mm
plz help
I need it fast
Answer:
perpendicular to
Explanation:
it means perpendicular to .....should u come across something like this / / , this one means parallel to .....
Answer:
perpendicular
Explanation:
Some of the most popular symbols are:
Heart symbol: this represents love, compassion and health.
Dove symbol: this represents peace, love, and calm.
Raven symbol: this represents death and doom.
Tree symbol: this represents growth, nature, stability, and eternal life.
Owl symbol: this represents wisdom and intelligence.
The cartesian coordinates of a point in the xy plane are x = −7.11 m, y = −4.41 m. Find the distance r from the point to the origin. Answer in units of m.
Explanation:
Use Pythagorean theorem:
r² = x² + y²
r² = (-7.11 m)² + (-4.41 m)²
r = 8.37 m
Use trig to find the angle.
tan θ = y / x
tan θ = (-4.41 m) / (-7.11 m)
θ = 31.8° or 211.8°
Since x is negative and y is negative, the point is in the third quadrant, so θ = 211.8°.
Or, if we subtract 360°, θ = -148.2°.
What is The distance traveled by a vehicle in 12 minutes,if it’s speed is 35km/h
Answer: 7 km
Explanation: 12 minutes is 1/5 of an hour. 35/5=7
what type of image is formed by a lens if m = -0.87
A. The image is larger than the object and the image is real
B. The image is smaller than the object and the object is real
C. The image is larger than the object and is virtual
D. The image is smaller than the object and is virtual
Answer:
B.
Explanation:
as there is a '-' sign before the magnification value, it forms a real image.
so the last two options get cancelled.
as the value of magnification is 0.87 ie. lesser than 1, we can say that the image is smaller.
The type of image is formed by a lens if m = -0.87 would be smaller than the object and the object is real
What is a lens?A lens is a transmissive optical tool that employs refraction to focus or disperse a light beam. The power of the lens is expressed in the dioptre which is the reciprocal of the focal length of the lens.
The image formation through the lens is calculated with the help of the lens formula given as follows
1/f = 1/v - 1/u
where f is the focal length of the lens
u is the distance of the object from the lens
v is the distance of the image formed from the
magnification (m) = size of image /size of the object
As given in the problem image is formed by a lens if m = -0.87
Thus, the negative sign represents that the image formed by the object is real, and the magnitude of the magnification is less than 1 this represents that size of the image is smaller than the size of the object.
Learn more about the lens from here
https://brainly.com/question/766997
#SPJ2
Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered by it in this time
Answer:
[tex] \boxed{\sf Acceleration \ (a) = 2 \ m/s^{2}} [/tex]
[tex] \boxed{\sf Distance \ covered \ (s) = 100 \ m} [/tex]
Given:
Initial velocity (u) = 0 m/s
Final velocity (v) = 20 m/s
Time taken (t) = 10 sec
To Find:
(i) Acceleration (a)
(ii) Distance covered (s)
Explanation:
[tex]\sf (i) \ From \ 1^{st} \ equation \ of \ motion:[/tex]
[tex] \sf \implies v = u + at[/tex]
[tex] \sf \implies 20 = 0 + a(10)[/tex]
[tex] \sf \implies 10a = 20[/tex]
[tex] \sf \implies \frac{10a}{10} = \frac{20}{10} [/tex]
[tex] \sf \implies a = 2 \: m/ {s}^{2} [/tex]
[tex]\sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:[/tex]
[tex] \sf \implies s = ut + \frac{1}{2} a {t}^{2} [/tex]
[tex]\sf \implies s = (0)(10) + \frac{1}{2} \times 2 \times {(10)}^{2} [/tex]
[tex]\sf \implies s = \frac{1}{ \cancel{2}} \times \cancel{2} \times {(10)}^{2} [/tex]
[tex]\sf \implies s = {10}^{2} [/tex]
[tex]\sf \implies s = 100 \: m[/tex]
A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.9 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
Answer:
22.73 m/s or 81.72 kph
Explanation
We can find the combined mass of both cars as
970 kg + 2300 kg = 3270 kg.
Then the normal force of the cars can be calculated as
F(n)= mg
Where g is acceleration due to gravity 9.8m/s^2
3270 kg ×9.8 = 32046 kg*m/s^2.
coefficient of kinetic friction between tires and road to be 0.80 × F(n)
Then the frictional force can be calculated as
= (32046kg*m/s^2 × 0.80 )
= 25636.8 kg*m/s^2
We can now calculate the work done that was used stopping the cars as
Frictional force × distance
(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2
From kinetic energy formula, the combined velocity of the car can be determined
E=0.5 M V²
√(2E/M) = V
√(2*74346.72kg*m^2/s^2 / 3270 kg) = V
V= √ (45.472)
V=6.743293m/s
the momentum of both cars can be determined as
6.743293m/s * 3270 kg
= 22050.57kg*m/s
Now the final momentum of both cars must be equal to the the momentum of
the sports car just prior to the collision. Therefore, the speed of the sports car at impact.
=(22050.57 kg*m/s) / 970 kg = 22.73 m/s
We can convert that to km/h.
22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph
A machine can never be 100% efficient because some work is always lost due to which factor? friction gravity static input force
Explanation:
Hi,
The answer is friction.
There is almost no machine which are not affected by friction. It losts some work due to friction while working.
Hope it helps..
Answer:
friction
Explanation:
the other options dont effect efficiency
An object of mass 25kg is at rest. What is its momentum ?
Answer:
[tex]\boxed{0}[/tex]
Explanation:
Momentum is the measure of mass in motion.
[tex]\sf momentum = mass \times velocity[/tex]
An object at rest has a velocity of 0.
[tex]p=mv[/tex]
[tex]p = 25 \times 0[/tex]
[tex]p=0[/tex]
The momentum of an object at rest is always 0.
Air contains 78.08% nitrogen, 20.095% oxygen, and 0.93% argon. a sample of air occupies 8 l at 273 k and applies a pressure of 2.45 atm to its container. the sample of air is heated to 550 k, at which time it takes up 11.8 l. what is the partial pressure of nitrogen after the air has been heated
Answer:
the partial pressure of nitrogen after the air has been heated is 2.61atm
Explanation:
Using combined gas law which is the combination of Boyle's Law and Charles' Law, and it gives The relationship between pressure, volume, and absolute temperature
PV/T= K
P1₁V₁/T₁=P₂V2₂/T₂
P₂=final pressure= ?
P₁= initial pressure=2.45 atm
.T₁= initial temperature= 273k
T₂= final temperature= 550 K,
We can make P₂ subject of the formula then we have
P₂=P₁V₁T₂/T₁T₂
=( 2.45×8×550)/(273×11.8)
P2=3.35atm
Now we can calculate the partial pressure of N₂
N₂= 3.35×(78.08/10)
=2.61atm
Therefore, the partial pressure of nitrogen after the air has been heated is 2.61atm
help me pleaseeeeeeddd
Answer:
Explanation:
a )
According to graph the object moves with constant velocity of 10 m /s during first 8 s and then its velocity changes to - 5 m /s from 8 th second upto 12 th second .
Initial displacement = 8 m
displacement during 8 s = velocity x time
= 8 x 10 = 80 m
total displacement = 88 m
b )
displacement during period from 8 th to 12 th s
= - 5 x 4 = - 20 m
total displacement after 12 s
= 88 - 20 = 68 m
c ) average speed = total distance covered during 12 s / total time
= (80 + 20) / 12
= 8.33 m /s
average velocity = total displacement during 12 s / total time
= 80 - 20 / 12
= 60 / 12
= 5 m /s .
What would happen to the
to the output force (F2)if the area
of the piston1 is made larger than that of piston2? plz help
Answer:
The output force would decrease since exerted force is inversely proportional to contact area.
Explanation:
F ∝ [tex]\frac{1}{A}[/tex] , Where 'F' is the exerted force and 'A' is the contact area.
the resistance per meter is 10 ohm. if the resistance of the material of the wire is 50 then 10^-8 ohm. find the area of cross section of the wire.
the question is at some point wrong or missing a word please help me with the question and answer!
Answer:
5×10⁻⁸ m²
Explanation:
I assume you mean the resistivity of the material is 50×10⁻⁸ Ωm.
R = ρL/A
10 Ω = (50×10⁻⁸ Ωm) (1 m) / A
A = 5×10⁻⁸ m²
Bus starts from rest if the acceleration of the bus is 0.5 MS squared what will be the velocity at the end of two minutes and what distance will it cover during that time
Explanation:
Given that,
Initial speed of the bus, u = 0
Acceleration of the bus, a = 0.5 m/s²
Let v is the velocity at the end of 2 minutes. The change in velocity divided by time equals acceleration.
So,
[tex]a=\dfrac{v-u}{t}\\\\v=u+at\\\\v=0+0.5\times 120\\\\v=60\ m/s[/tex]
Let d is the distance cover during that time. So,
[tex]v^2-u^2=2ad\\\\d=\dfrac{v^2-u^2}{2a}\\\\d=\dfrac{(60)^2}{2\times 0.5}\\\\d=3600\ m[/tex]
So, the final speed is 60 m/s and the distance covered during that time is 3600 m.
A student measures the depth of a water well with an adjustable frequency audio oscillator. 2 successive resonant frequencies are heard at 40Hz and 50Hz. What is the depth of the well?
Answer:
17.15 m
Explanation:
Assuming the well is empty (full of air instead of water), the speed of sound is v = 343 m/s.
The water well acts as a pipe closed at one end. Therefore, the depth of the water well must be an odd multiple of a quarter of the resonant wavelength.
L = (2n − 1) λ/4, n = 1, 2, 3, etc.
v = λf, so λ = v/f. Substituting:
L = (2n − 1) v/(4f)
Solving for frequency:
f = (2n − 1) v/(4L)
The difference between two successive resonant frequencies is therefore:
Δf = (2(n+1) − 1) v/(4L) − (2n − 1) v/(4L)
Δf = (2n + 1) v/(4L) − (2n − 1) v/(4L)
Δf = 2 v/(4L)
Δf = v/(2L)
Plugging in values:
50 Hz − 40 Hz = 343 m/s / (2L)
2L = 34.3 m
L = 17.15 m
An electric field from a charge has a magnitude of 4.5 x 10^4 N/C at a certain
location that points outward. If another charge with a magnitude of -2.0 x 10^-6 C
is brought near it, what is the strength of the electrostatic force that acts on this
charge and how do the two charges behave?
0.09 N; repel each other
-0.09 N; attract each other
-2.3 N; repel each other
2.3 N; attract each other
Answer:
4.5 x 10^4 x -2 x 10^-6 = -0.09N
Explanation:
-0.09N
2. Adelia holds a shiny steel spoon with its back (convex surface) facing her eyes at a distance
of approximately 30 cm. She sees an upright image of herself. However, when the spoon
is changed so that the front (concave surface) of the spoon is facing her eyes, an inverted
image is observed.
(a) Explain this situation.
(b) Why is an upright image not seen on the front surface of the spoon at that distance?
Answer:
(a) The convex mirror image, is always upright at all positions, while images formed by concave mirrors are always inverted when the object distance from the mirror is more than the mirrors focal length.
(b) An upright image is not seen for object at a distance from a concave mirror further than the focal length of the mirror, which is the spoon in the question
Therefore, the location of her eyes of approximately, 30 cm, from the mirror is more than the mirror's focal length
Explanation:
Which is the second step of the fusion process?
O
H+1H - ?H+e+ + v + energy
O 6(3H) +21_e) - He +24H) + energy + 2u
{H+1H He + energy
O
He He He + 1H+1H + energy
Answer:
The correct option is;
[tex]_{1}^{2}\textrm{He} + _{1}^{1}\textrm{H} \rightarrow _{3}^{2}\textrm{He} + energy[/tex]
Explanation:
The second step of the fusion process is the reaction (combination) where a Deuterium combines with a hydrogen to produce one helium 3, 3He, nucleus and a energy photon as follows;
[tex]_{1}^{2}\textrm{He} + _{1}^{1}\textrm{H} \rightarrow _{3}^{2}\textrm{He} +\gamma \ (energy)[/tex]
After which the produced Helium-3 combines to form the Helium nucleus an emit 2 protons
Steps 1 and 2 are take place two times (producing 26 MeV energy) before the step three (the combination of the formed helium-3) takes occurs.
Answer:
C on edge
Explanation:
Just did it and got it right :)
Pls help promise to mark as brainlist
Answer:
The answers to your questions are given below
Explanation:
A. Definition of momentum.
Momentum of an object can be defined as the product of the mass of the object and its velocity. Mathematically, it expreessed as:
Momentum = mass x Velocity
From the above equation, we can derive the SI unit of momentum as follow:
Mass is measured in Kilogram (Kg)
Velocity is measured in meter per second (ms¯¹).
Momentum = mass x Velocity
Momentum = Kg x ms¯¹
Momentum = Kg•ms¯¹
Therefore, the SI unit of momentum is Kg•ms¯¹.
Bi. Determination of the force of the body from O to A.
Mass (m) = 5 kg
Velocity (v) = 40 ms¯¹
Time (t) = 2 secs.
Force (F) =?
Next, we shall determine the acceleration of the body.
Acceleration (a) = Velocity (v) /Time (t)
a = v /t
Velocity (v) = 40 ms¯¹
Time (t) = 2 secs.
Acceleration (a) =.?
a = v/t
a = 40/2
a = 20 ms¯²
Now, we can obtain the force as follow:
Mass (m) = 5 kg
Acceleration (a) = 20 ms¯²
Force (F) =?
Force (F) = mass (m) x Acceleration (a)
F = ma
F = 5 x 20
F = 100 N
Therefore, the force of the body from O to A is 100 N.
Bii. Determination of the force of the body from B to C.
Mass (m) = 5 kg
Velocity (v) = 40 ms¯¹
Time (t) = 10 – 6 = 4 secs.
Force (F) =?
Next, we shall determine the acceleration of the body.
Acceleration (a) = Velocity (v) /Time (t)
a = v /t
Velocity (v) = 40 ms¯¹
Time (t) = 4 secs.
Acceleration (a) =.?
a = v/t
a = 40/4
a = 10 ms¯²
Now, we can obtain the force as follow:
Mass (m) = 5 kg
Acceleration (a) = 10 ms¯²
Force (F) =?
Force (F) = mass (m) x Acceleration (a)
F = ma
F = 5 x 10
F = 50 N
Therefore, the force of the body from B to C is 50 N.
what is a hypothesis reffered to as after being verified by a large number or independent experiments
Answer:
The hypothesis may or may not be true and needs to be tested. It might be the answer to the problem. Hence, it must be tested thoroughly. When these predictions are tested again and again in independent scientific experiments and gets verified, the hypothesis is converted into a scientific theory.
Match the words to the correct blanks in the sentences. Use each choice only once. a. The collapse of a protostar with less than 0.08 times the mass of the Sun is halted by________. b. As a protostar shrinks in size, its central temperature rises along with its________. c. A star that has not yet finished forming is called a_______. d. A forming star spins more rapidly as it collapses because of conservation of________. e. If a protostar has a mass too small for it to sustain nuclear fusion it becomes the type of object known as a________.A. thermal pressureB. angular momentumC. energy balanceD. degeneracy pressureE. brown dwarfF. gravitational equilibriumG. protostar
Answer:
The collapse of a protostar with less than 0.08 times the mass of the Sun is halted by DEGENERACY PRESSURE. b. As a protostar shrinks in size, its central temperature rises along with its THERMAL PRESSURE. c. A star that has not yet finished forming is called a__PROTOSTAR_____. d. A forming star spins more rapidly as it collapses because of conservation of ANGULAR MOMENTUM. e. If a protostar has a mass too small for it to sustain nuclear fusion it becomes the type of object known as a____BROWN DWARF____
i) A 100 W and 60 W bulb are joined in series and connected to the mains. Which bulb will glow brighter? Why? ii) A 100 W and a 60 W bulb are joined in parallel to the mains. Which bulb will glow brighter? Why?
Answer:
i) 60 W
ii) 100 W
Explanation:
In each case, the bulb that dissipates the most power is the bulb that glows brighter. Power is voltage times current (P = VI). Using Ohm's law, we can rewrite this as P = I²R or P = V²/R.
Bulbs are rated at a certain power for a certain voltage. P = V²/R, so the bulb with the lower resistance will have the higher power rating. Therefore, the 100 W bulb has a lower resistance than the 60 W bulb.
i) They are in series, so they have the same current. P = I²R, so the bulb with the higher resistance will glow brighter. That's the 60 W bulb.
ii) They are in parallel, so they have the same voltage. P = V²/R, so the bulb with the lower resistance will glow brighter. That's the 100 W bulb.
A mass, M, is at rest on a frictionless surface, connected to an ideal horizontal spring that is unstretched. A person extends the spring 30 cm from equilibrium and holds it at this location by applying a 10 N force. The spring is brought back to equilibrium and the mass connected to it is now doubled to 2M. If the spring is extended back 30 cm from equilibrium, what is the necessary force applied by the person to hold the mass stationary there
Answer:
The necessary force applied by the person to hold the mass stationary there is 10 N
Explanation:
We are told that this person extends the spring 30 cm from equilibrium and holds it at this location by applying a 10 N force.
Thus, based on Hooke's law formula which is F = k Δx, we can say that the mass attached to the spring does not change the spring constant. Thus, the
same resistive spring force will still be in place and in turn, the same stretching force of 10N would still be required.
Thus;
The necessary force applied by the person to hold the mass stationary there is 10 N
select the correct relationship of the densities of the given substances: !●water < iron < aluminium < mercury ● Iron < water < mercury < aluminium ● water < aluminium < iron < mercury ● none of the above. asap plz!!!
Answer:
option a is correct
Explanation:
water ∠iron∠aluminium∠mercury
water density =1.0000
iron =7.487
aluminium=2.07
mercury=13.59
The same motor is used in rockets with different masses. The rockets have different accelerations. According to Newton’s second law, how is acceleration expected to change as the rocket mass increases? As rocket mass increases, acceleration decreases. There are no changes in acceleration, as it would depend on the amount of force. As rocket mass increases, acceleration increases. Acceleration cannot be predicted based on changes in mass.
Answer:
As rocket mass increases, acceleration decreases.
Explanation:
From Newton's second law of motion;
F= ma
Where;
m= mass of the object
a= acceleration of the object
Hence we can write;
a= F/m
This implies that an increase in mass (m) will lead to a decrease in acceleration if the force on the object is held constant.
Hence, if the rockets have different masses, they will have different accelerations.
Hello!
---------
As rocket mass increases, acceleration decreases.
Hope this helps! The rest are available on Quizlet at "Unit 6: Lesson 4 Force, Mass and Acceleration". Thanks and good luck!
