Answer:
the name of the SI unit for force is the newton
Answer:
newton
Explanation:
don't have explanation
but I know this is the answer
which correctly lists three main causes of deforestation?
O air pollution,mining, logging
O mining,cattle ranching, logging
O cattle ranching,water pollution, air pollution
O water pollution, logging, mining
Answer:
B. mining, cattle ranching, logging
Explanation:
Took the quiz on edge2020 :)
A system has 4 independent and identical motors, in order for the system to work, at least one of the motors must operate. Each motor's failure rate is 0.002 failures per hour. What is the system's Mean Time to Failure (MTTF)?
Answer:
The system's Mean Time to Failure is 1,041.[tex]\bar 6[/tex] hours
Explanation:
The number of independent identical motors = 4
The failure rate of each motor, λ = 0.002 failures per hour
Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel
The Mean Time to Failure for a parallel system of four identical components is given as follows;
[tex]MTTF = \dfrac{1 }{\lambda} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right)[/tex]
Which gives;
[tex]MTTF = \dfrac{1 }{0.002} \times \left (1 + \dfrac{1}{2} + \dfrac{1}{3} + \dfrac{1}{4} \right) = 1,041.\bar 6[/tex]
The system's Mean Time to Failure = 1,041.[tex]\bar 6[/tex] hours.
please answer fast!
You push a 10 kg box across the floor. The box is initially at rest. You apply a force on the box for
0.05 seconds. If the velocity of the box is 50 m/s after you push it, what is the net force you applied
to the box? (Hint: remember impulse! F*t = m*v2 - m*v1)
Answer:
F = ma The force of friction for a 7.5-kg object being pushed horizontally at a constant A 30-kg wooden box is resting on a carpeted surface. If the ... An applied force of 21 N accelerates a 9.0-kg wagon at 2.0 m/s² along the sidewalk. (u=0,034. 5. A sled of mass of 50.0 kg is pulled along a flat, snow-covered ground.
Explanation:
what is the correct answer?
Answer:
Option (3)
Explanation:
From the graph attached,
Zeros of the function are, x = -3,
Graph of the polynomial touches x axis at x = -3, 1 and 3
Therefore, equation of the given function will be in the form of,
P(x) = [tex]k(x+3)^a(x-1)^b(x-3)^c[/tex]
Since, graph of the function just touches the x-axis, multiplicity of zero at x = -3 will be even and crosses x-axis so the multiplicity at x = 1 and 3 will be odd.
Therefore, possible function will be,
P(x) = [tex]k(x+3)^2(x-1)(x-3)[/tex]
Since, y-intercept of the function is at (0, -3),
P(0) = k(0 + 3)²(0 - 1)(0 - 3)
-3 = 27k
k = [tex]-\frac{3}{27}=-\frac{1}{9}[/tex]
Therefore, given polynomial function is,
P(x) = [tex]-\frac{1}{9}(x+3)^{2}(x-1)(x-3)[/tex]
Option (3) will be the correct option.
How can you determine the class of lever of simple machine?
Answer:
A first-class lever has the fulcrum between the load and the effort. A second-class lever has the load between the effort and the fulcrum. A third-class lever has the effort between the load and the fulcrum. A see-saw is an example of a first-class lever.
Explanation:
the SI unit that equals 0.01 meters is
Answer:
0.3937008
Explanation:
Answer: 1 centimeter is your answer
I apoligize that this is a late answer , I stumbled upon this post. Good luck to any future veiwers. P.S the picture below is for a similiar question for other students who pressed this post
A hockey puck slides 55.0 m along the length of the rink in just 1.25 s. The slight friction between the puck and the ice provides a uniform acceleration. If the puck's final speed is 43.2 m/s, what is its initial speed? 31.4 m/s?
Answer:
44.8 m/s
Explanation:
Use the Initial Speed Formula:
InS = 2(d/t) - Final Speed
InS = 2(55/1,25) - 43.2
InS = 2.44 - 43,2
InS = 88 - 43,2
InS = 44.8 m/s
A helium balloon is tied to a top-pan balance. A metal block of mass 100 g is placed on the balance. The reading on the balance is 91 g. Which statement can be deduced from this experiment?
Answer:
The resultant downward force on the top-pan balance is 0.91N.
The best answer from the options is D : The resultant downward force on the top pan balance is 0.91 N
Although your question is incomplete attached below is the complete question.
Given data :
mass of metal block = 100 g
reading on the balance = 91 g
In order to deduce the best statement we will Neglect weight while considering the force acting on the balance ( reading on the balance ). therefore the resultant downward force on the top pan will be
91 g ≈ 0.91 N ( 91 * 0.0098 N )
hence the statement that can be deduced from this experiment is that The resultant downward force on the top pan balance is 0.91 N
Learn more at : https://brainly.com/question/18273752
A notebook is on a desk the force of the notebook weight pushing down on the table is 10 in the force of the table normal force pushing back up on the notebook with 10 in is this balanced
Answer:
Yes it is balanced
Explanation:
Because 10-10= a net force of 0N
Its equal (balanced)
Is density of an object proportional to its conductivity?
Answer:
Yes, the density of an object is proportional to its conductivity.
Explanation:
The "Thermal conductivity" of an object is dependent on three things: temperature, density and moisture content. This means that an object becomes more conductive if it has a higher temperature, higher density and more moisture in its content. This makes them directly proportional to each other.
The denser an object is, the more likely it will conduct heat because its atoms are tightly packed compared to less denser ones like air. Such position of atoms hastens the transfer of energy.
The electromagnetic waves have a frequency of 2 400 000 000 Hz The speed of electromagnetic waves is 300 000 000 m/s Calculate the wavelength of the electromagnetic waves.
Answer:wavelength of the electromagnetic waves=0.125 m
Explanation:
The wavelength of an electromagnetic wave is given as
λ = c/f
where λ=wavelength =??
c= Speed =300 000 000 m/s
f =frequency=2 400 000 000 Hz
Wavelength =Speed /frequency
=300 000 000 m/s / 2 400 000 000 Hz
=300 000 000 m/s / 2 400 000 000 s⁻¹
=0.125 m
Sedimentary rocks were initially deposited as? will give brainliest
a. flat vertical layers
b. horizontal layers
c. soft folded beds
d. hard, flat rock layers
Based on my notes the answer must be B. horizontal layers
Answer:
B. horizontal layers
Explanation:
HELP SCIENCE WORK ON MOTION DUE!
1. A student athlete is participating in the hammer throw. The student rotates in uniform circular
motion with the mass rotating 4.5m away from the center of the rotation
4.5m
Refer to the above information and diagram. The student athlete can rotate so that the
Object is moving with a speed of 15 m/s.
What is the acceleration for this uniform circular motion?
Answer:
[tex]a_{c} = 50\ m/s^2[/tex]
Explanation:
In uniform circular motion, the acceleration of the object is due to the changing direction of velocity of the object. this acceleration is referred to as centripetal acceleration. It can be calculated by following formula:
[tex]a_{c} = \frac{v^2}{r}[/tex]
where,
ac = centripetal acceleration = ?
v = speed of the object = 15 m/s
r= radius of circular motion = distance of object from center of rotation = 4.5 m
Therefore, using these values in equation, we get:
[tex]a_{c} = \frac{(15\ m/s)^2}{4.5\ m}\\\\a_{c} = 50\ m/s^2[/tex]
What is the opposite of dividind hy 3?
Answer:
multiplying by 3.
Explanation:
A tiger waits in hiding behind a bush. The tiger spots an impala running past at 10 m/s. At the instant the impala passes the tiger, the tiger accelerates from rest at 4 m/s² to catch the impala. The displacement of the tiger when it catches the impala is --------------.
Please answer.
Answer: the displacement is 50 meters.
Explanation:
We can assume that the initial position of both animals is the same, let's find the position equation for each one of them.
Impala:
We know that its velocity is 10m/s
then the velocity equation is
Vi(t) = 10m/s
For the position equation, we need to integrate over time to get:
Pi(t) = 10m/s*t + C
Where C is the constant of integration and represents the initial position of the impala.
For the Tiger, we know that the acceleration is 4m/s^2, then the acceleration equation is:
At(t) = 4m/s^2
The velocity equation can be found by integrating over time, we get:
Vt(t) = (4m/s^2)*t + V0
Where V0 is a constant of integration and represents the initial velocity of the tiger, we knew that the tiger was at rest, then the initial velocity is zero, and the velocity equation is:
V(t) = (4m/s^2)*t
For the position equation of the tiger we need to integrate over time again, and because both animals have the same initial position, the constant of integration will be equal to C.
Pt(t) = (1/2)*(4m/s^2)*t^2 + C
The tiger will catch the impala when the position of the tiger is the same as the position of the impala, then we need to solve:
Pi(t) = Pt(t)
10m/s*t + C = (1/2)*(4m/s^2)*t^2 + C
We can remove C in both sides to get:
10m/s*t = (1/2)*(4m/s^2)*t^2
Now we can divide both sides by t, to get
10m/s = (1/2)*(4m/s^2)*t
10m/s = (2m/s^2)*t
(10m/s)/(2m/s^2) = t = 5s
The tigger runs for 5 seconds before catching the Impala, knowing this we can find the displacement of the tiger, wich will be the difference between the final position of the tiger, Pt(5s) and the initial position of the tiger Pt(0s)
Displacement = (1/2)*(4m/s^2)*(5s)^2 + C - ((1/2)*(4m/s^2)*(0s)^2 + C)
= (1/2)*(4m/s^2)*(5s)^2 = 50m
The displacement of the tigger is 50 meters.
A helicopter flies for 80 miles. then turns and flies at a heading of 60°for 40 miles.What is the magnitude and direction of the net displacement of the helicopter.Include a drawing
Answer:
Please find attached the motion of the helicopter (drawn to scale) showing the magnitude and the direction of the net displacement of the helicopter obtained by measurement to be 105 miles and 19° respectively
By calculation, the magnitude of the net displacement is approximately 105.83 miles and the direction of the net displacement is approximately 19.1066°
Explanation:
The parameters of the motion of the helicopter are;
The distance the helicopter flies before turning = 80 miles
The distance the helicopter then turns and flies = 40 miles
The direction the helicopter turns = 60°
Therefore, we have;
The total length the helicopter flies in the original direction = The component of the length of the 40 mile flight that is in the original direction + The distance the helicopter flies before turning
∴ The total length the helicopter flies in the original direction = 40 × cos(60°) + 80 = 20 + 80 = 100
The total length the helicopter flies in the original direction = 100 miles
The component of the 40 mile flight that is perpendicular to the original direction = 40 × sin(60°) = 40 × √3/2
The magnitude of the net displacement = √(100² + (40×√3/2)²) ≈ 105.83
The magnitude of the net displacement ≈ 105.83 miles
The direction of the net displacement = tan⁻¹((40 ×√3/2)/(100)) ≈ 19.1066°
The direction of the net displacement ≈ 19.1066°.
True or false: a moving object can have a displacement of zero
Answer:
true
Explanation:
the object instead of moving through a distance can have zero displacement. Example: If an object travels from point A and reaches to the same point A, then its displacement is zero.
Answer:
It would be False :)
Explanation:
Hope this helps Have a blessed day! :)
help with this question.....
Answer:
[tex]g_{moon}=1.67 [m/s^{2} ][/tex]
Explanation:
The weight of some mass is defined as the product of mass by gravitational acceleration. In this way using the following formula we can find the weight.
[tex]w =m*g\\[/tex]
where:
w = weight [N]
m = mass = 0.06 [kg]
g = gravity acceleration = 10 [N/kg]
Therefore:
[tex]w=0.06*10\\w=0.6[N][/tex]
By Hooke's law we know that the force in a spring can be calculated by means of the following expression.
[tex]F=W\\F = k*x[/tex]
where:
k = spring constant [N/m]
x = deformed distance = 6 [cm] = 0.06 [m]
We can find the spring constant.
[tex]k= F/x\\k=0.6/0.06\\k=10 [N/m][/tex]
Since we use the same spring on the moon and the same mass, the constant of the spring does not change, the same goes for the mass.
[tex]F_{moon}=k*0.01\\F = 10*0.01\\F=0.1[N][/tex]
Since this force is equal to the weight, we can now determine the gravitational acceleration.
[tex]F=m*g_{moon}\\g=F/m\\g = 0.1/0.06\\g_{moon} = 1.67[m/s^{2} ][/tex]
Four items are affected by a change in temperature. Which one of the following results in a chemical change?
A. water drops forming on a cold soda can
B. a wet beach towel drying in the sun
C. melting chocolate on a stove
D. making cookies in an oven
is the chorion the yolk of the egg
Answer:
Yes
Explanation:
Inside the egg are a series of fluid-filled membranes that permit the embryo to survive: the amnion, allantois, yolk sac, and chorion. Around the chorion is the albumin or "white" of the egg, and an outer shell protects the whole egg, preventing drying while still permitting air to reach the embryo.
The diagram will help you below:
What is the path of a projectile?
a wavy line
a parabola
straight down
Projectiles do not follow a predictable path.
Answer:
I think it is a parabola.
1. What happens when like charges come together?*
Answer:
When like charges come together, they repel each other. For instance, when the north and south poles of a magnet come together, they push each other apart. The like poles in the magnet repel each other and unlike poles attract each other much. The same reaction occurs in like and unlike charges. Also, the repulsion acts along the line between the two charges.
A 6.0 kg bowling ball moving at 3.5m/s to the right makes a collision, head-on, with a stationary 0.70 kg bowling pin. If the ball is moving 2.77 m/s to the right after the collision, what will be the velocity ( magnitude and direction) of the pin?
Answer:
The velocity of the pin will be 6.26 m/s in the right direction.
Explanation:
Let's use the momentum conservation equation.
[tex]p_{i}=p_{f}[/tex]
Initially, we have:
[tex]p_{i}=m_{b}*v_{ib}[/tex]
Where:
m(b) is the ball massv(ib) is the initial velocity of the ballNow, the final momentum will be:
[tex]p_{f}=m_{b}*v_{fb}+m_{p}*v_{fp}[/tex]
Where:
m(p) is the pin massv(fb) is the final velocity of the ballv(fp) is the final velocity of the pinThen, using the equation of the conservation we have:
[tex]m_{b}*v_{ib}=m_{b}*v_{fb}+m_{p}*v_{fp}[/tex]
[tex]6*3.5=6*2.77+0.7*v_{fp}[/tex]
[tex]6*3.5=6*2.77+0.7*v_{fp}[/tex]
[tex]v_{fp}=6.26 m/s[/tex]
Therefore the velocity of the pin will be 6.26 m/s in the right direction.
I hope it helps you!
Which of the following does not show an example of energy being transferred according to the work-energy theorem?
a child pushing a toy car and making it move very fast
a baseball player hitting a baseball to the outfield
a soccer player kicking a soccer ball to a teammate
a driver pushing on a stalled car without moving it
The answer for you is D.
Have a nice day!
Hope This Helped! : )
The A-36 hollow steel shaft is 2 m long and has an outer diameter of 40 mm. When it is rotating at 77 rad/s , it transmits 32 kW of power from the engine E to the generator G. The shear modulus of elasticity for A-36 steel is 75 GPa.
Complete Question
The A-36 hollow steel shaft is 2 m long and has an outer diameter of 40 mm. When it is rotating at 77 rad/s , it transmits 32 kW of power from the engine E to the generator G. The shear modulus of elasticity for A-36 steel is 75 GPa.
Determine the smallest thickness of the shaft if the allowable shear stress is Tallow 140 MPa and the shaft is restricted not to twist more than 0.05 rad
Answer:
The value is [tex]t = 8.28 *10^{-3} \ m[/tex]
Explanation:
From the question we are told that
The length is [tex]l = 2 \ m[/tex]
The outer diameter is [tex]d_o = 40 \ mm = 0.04 \ m[/tex]
The angular speed is [tex]w = 77 \ rad/s[/tex]
The amount of power transmitted is [tex]P = 32 \ kW = 32*10^{3} \ W[/tex]
The shear modulus of elasticity is [tex]G = 75 GPa = 75 *10^{9} \ Pa[/tex]
The allowable shear stress is [tex]\tau_{allow} = 140 MPa = 140 *10^{6}\ Pa[/tex]
The allowable angular displacement is [tex]\theta = 0.05 \ rad[/tex]
Generally the power transmitted is mathematically represented as
[tex]P = \tau * w[/tex]
Here [tex]\tau[/tex] is the amount of torque generated by the hollow steel shaft
[tex]32*10^{3} = \tau * 77[/tex]
=> [tex]\tau = 415.6 \ N\cdot m[/tex]
Generally the polar moment of inertia of the hollow steel shaft is mathematically represented as
[tex]J = \frac{\pi}{32 } ( d_o^4 - d_i^4 )[/tex]
Generally the allowable displacement of the hollow steel shaft is mathematically represented as
[tex]\theta = \frac{\tau * l }{ G J }[/tex]
=> [tex]\theta = \frac{ 415.6 * 2 }{ 75*10^{9} * \frac{\pi }{ 32} * ( d_o^4 - d_i^4 ) }[/tex]
=> [tex]0.05 = \frac{ 415.6 * 2 }{ 75*10^{9} * \frac{\pi }{ 32} * ( 0.04^4 - d_i^4 ) }[/tex]
=> [tex]d_i = 0.0235 \ m[/tex]
Generally the thickness of the shaft is mathematically represented as
[tex]t = \frac{d_o - d_i }{2}[/tex]
=> [tex]t = \frac{0.04 - 0.02345 }{2}[/tex]
=> [tex]t = 8.28 *10^{-3} \ m[/tex]
A glacier can cause a change in landforms as it picks up rocks and moves the rock to new locations. How fast does the glacier have to be moving to impact local landforms?
Answer:
30 meters/day.
Explanation:
Glacial motion can be fast up to 30 meters/day or slow up to 0.5 m/year on small glaciers moving the impact on local landforms. If the glacial motion goes up to 30 meters/day, more fast change occurs in the local landforms while on the other hand, if the glacial motion goes up to 0.5 m/year, very slow change occurs in the local landforms. So glacial motion has a direct affect on the changes occurs in the local landforms.
Explain how radio waves and digital signals will store and transmit this assignment to your instructor.
The radio waves and digital signals will store and transmit through the electromagnetic wave.
What is an electromagnetic wave?EM waves are another name for electromagnetic waves. Electromagnetic radiations are made up of electromagnetic waves created when an electric field collides with a magnetic field.
Electromagnetic waves may alternatively be defined as the combination of oscillating electric and magnetic fields. Maxwell's equations are solutions to electromagnetic waves.
Electromagnetic waves are employed to transfer digital and analogue signals. The music you listen to or the graphics you see on a screen are created by changes in frequency and amplitude.
Hence, electromagnetic waves are used to transfer digital and analogue signals.
To learn more about the electromagnetic wave, refer to the link;
https://brainly.com/question/8553652
#SPJ2
When dave solved the following question , His workings were as follows
Question : Find the resultant of two vectors of 3 units and 4 units acting at a point O at an angle of 45° with each other.
Workings:(see image)
Main Question : Why did Dave change the Subtraction sign to addition sign ? (see 1st and 2nd line of workings) or see 2nd image.
Well, the lines of workings are cut off in the middle, and there's no 2nd image.
But I think it must have to do with the "cos" terms at the right end of the picture.
I'm guessing now, because the part I'm interested in would be just past the edge, where we can't see it.
I think that the first line says "cos(some angle)", and at the same place in the second line it says "cos(180 - the same angle)".
If that's what it says, then that's your answer, because cos(anything) is equal to the negative of cos(180 - the same thing).
That's the best I can do for you just now. Honestly, I don't see the connection yet between the question Dave is working on and the two lines I see in the picture.
When is mechanical energy NOT conserved? ANSWER ASAP WILL GIVE BRAINLIEST IF CORRECT
A-When you are in outer space
B-When it is cold outside
C-When the electricity is turned off
D-When there is significant friction or air resistance or other force affecting on the object.
Answer:
hope this helps D.
Explanation:
Mechanical energy may not be conserved when nonconservative forces act. For example, when a car is brought to a stop by friction on level ground, it loses kinetic energy, which is dissipated as thermal energy, reducing its mechanical energy.
A when you are in outer space since there is no gravity the mechanical energy just continues to push the direction it was pointed to
