​The pair of points (5, 6) and (10, y) lie on a line with slope 4/5 . What is the value of y?​

Answers

Answer 1

If the pair of points (5, 6) and (10, y) lie on a line with slope 4/5, then the value of y is 10

The slope m of the line passing through the points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is calculated as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

For the line passing through points (5, 6) and (10, y)

[tex]x_1=5, y_1=6, x_2=10, y_2=y[/tex]

The slope, m = 4/5

Substitute these value into the slope formula and solve for y

[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\\frac{4}{5}=\frac{y-6}{10-5} \\\\\frac{4}{5}=\frac{y-6}{5}[/tex]

Cross  multiply:

4(5)  =  5(y-6)

4   =  y  -  6

Collect like terms

y  =  4  +  6

y  =  10

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