the pair of the lines x^2-3y^2=0 and the straight line x=a enclose a triangle which is

Answers

Answer 1

Step-by-step explanation:

x²-3y²=0x=√3y and x-√3yΔOAB is equilateral triangle∴ orthocentre and centroid of ΔOAB concides ∴ orthocentre =( 29/3 ,0)=( x1 + x2 + x3 / 3 , y1 + y2 + y3 / 3 )I NEED BRAINLIEST ✌️ PLZ

The Pair Of The Lines X^2-3y^2=0 And The Straight Line X=a Enclose A Triangle Which Is

Related Questions

what is the length of segment SR?

Answers

ST = ST (Common)

RT = TQ (Given)

∠ RTS = ∠ SQT (Both 90°)

So, ∆ RTS ≅ ∆ QTS (By SAS congruency rule)

So, RS = QS (By C.P.C.T.)

=> 2x + 8 = 8x - 4

=> 8 + 4 = 8x - 2x

=> 12 = 6x

=> 12/6 = x

=> 2 = x

SR = 2x + 8 (Given)

=> SR = 2(2) + 8 (Putting the value of x)

=> SR = 4 + 8

=> SR = 12

Answer:

Step-by-step explanation:

What is the equation of the following line?
(-4, 8)
(0,0)

Answers

Answer

Step-by-step explanation:

y = -2x + 0

Therefore; y = -2x

Log problem below in the picture

Answers

Your answer is 2.98004491789381.

help.........................​

Answers

Answer:

solution

here,

Step-by-step explanation:

f={(2,1/2), ( 3, 1/3) , (4, 1/4)}

Range = { / (\ frac 12\) , \ (\ frac 13\) ,

\( \ frac 14\ )}

Inverse function ( f-^1 ) = {( 1/2, 2) ,( 1/3 ,3) , 1/4, 4 )} is the required answer

Drag the tiles to the correct boxes to complete the pairs.Match each function to its domain

Answers

Answer:

f(x) = [tex]\sqrt{x+5}[/tex] : All real numbers greater than/equal to 5

Explanation: you can't square root negative numbers, and any number less than 5 would give us negative.

f(x) = [tex]\frac{7}{x-8}[/tex] : All real numbers except 8

Explanation: You can't divide by 0, and if we included 8 in the number set, we would get this: [tex]\frac{7}{8-8} =\frac{7}{0}[/tex] (this is impossible).

f(x) = [tex]\sqrt{2}[/tex] : All positive real numbers and 0

Explanation: Again, you can't square root negative numbers.

f(x) = 8x : All real numbers

Not much to explain for this one, any real number makes this equation true.

Find x and y

Help me please

Answers

Answer:

x = 70     y = 140

Step-by-step explanation:

Apologies if I get any names of vocabulary terms wrong, I never pay much attention to the names.

The central angle measure of an arc is the same as the arc's measure. In this case, y is the central angle and 140 is the arc's measure, so y = 140.

The inscribed angle measure of an arc is 1/2 the arc's measure. An inscribed angle lies on the circle. So 140/2 = 70 = x.

Are the two triangles similar. If so, State how

Answers

Answer:

Yes by AAA

Step-by-step explanation:

Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar

Please helpppp
Find l.

Answers

Answer:

Step-by-step explanation:

radius of base=8/2=4 ft

l²=4²+9²=16+81=97

l=√97 ft

Can someone please help me really struggling

Answers

I believe that the slope intercept is y=x+5.
And I don’t know about point slope form, it wasn’t in my standards, I’m sorry.

Answer:

your y-intercept is 5 and your slope is 1 hope this helps with translating into the form you want

Step-by-step explanation:

Find the value please!!!

Answers

the answer is in the picture

If f(x) = 6x - 4. what is f(x) when x = 8?​

Answers

Answer:

44

Step-by-step explanation:

* means multiply

put 8 where the x is

6 * 8 - 4

48 - 4

44

the first day she walked 27 kilometers. each day since she walked 2/3 of what she walked the day before. what is the total distance cecelia has traveled be the end of the 5th day?

Answers

Answer: 70

Step-by-step explanation:

We are required to calculate the total distance Cecilia travelled in 5 days

The total distance Cecilia travelled for 5 days is 99 kilometers

Day 1 = 27 kilometers

Day 2 to day 5 = 2/3 of 27

= 2/3 × 27

= 2 × 9

= 18 kilometers each day

Total distance = day 1 + day 2 + day 3 + day 4 + day 5

= (27 + 18 + 18 + 18 + 18) kilometers

= 99 kilometers

Therefore, the total distance Cecilia travelled for 5 days = 99 kilometers

Read more:

https://brainly.com/question/17207658

In one week, Alex worked 35 hours at $ 12.50 per hour plus 5 hours overtime at 'time and half'. How much would Alex have earned for the week? *

Answers

Find out how much Alex earned in 35 hours first.

1 hour = $12.50

35 hours = $12.50 x 35 = $437.50

Since ‘time and a half’ pays 1.5 times more than their usual pay, find out how much Alex earned per hour at ‘time and a half’

1 hour = 12.50 x 1.5 = $18.75

5 hours = 18.75 x 5 = $93.75

$437.50 + $93.75 = $531.25

Alex would have earned $531.25 for the week.

Find angle D if angle B = 50

Answers

Answer:  80 degrees

============================================================

Explanation:

I'm assuming that segments AD and CD are tangents to the circle.

We'll need to add a point E at the center of the circle. Inscribed angle ABC subtends the minor arc AC, and this minor arc has the central angle AEC.

By the inscribed angle theorem, inscribed angle ABC = 50 doubles to 2*50 = 100 which is the measure of arc AC and also central angle AEC.

----------------------------

Focus on quadrilateral DAEC. In other words, ignore point B and any segments connected to this point.

Since AD and CD are tangents, this makes the radii EA and EC to be perpendicular to the tangent segments. So angles A and C are 90 degrees each for quadrilateral DAEC.

We just found angle AEC = 100 at the conclusion of the last section. So this is angle E of quadrilateral DAEC.

---------------------------

Here's what we have so far for quadrilateral DAEC

angle A = 90angle E = 100angle C = 90angle D = unknown

Now we'll use the idea that all four angles of any quadrilateral always add to 360 degrees

A+E+C+D = 360

90+100+90+D = 360

D+280 = 360

D = 360-280

D = 80

Or a shortcut you can take is to realize that angles E and D are supplementary

E+D = 180

100+D = 180

D = 180-100

D = 80

This only works if AD and CD are tangents.

Side note: you can use the hypotenuse leg (HL) theorem to prove that triangle EAD is congruent to triangle ECD; consequently it means that AD = CD.

if p-1/p = 4 Find (p+1/p)²​

Answers

Answer:

4

Step-by-step explanation:

[tex] \frac{p - 1}{p} = 4[/tex]

Solve for p.

The numerator. difference has to be 4 times the answer of the denomiator.

So we can say

[tex]p - 1 = 4p[/tex]

Solve for p

[tex] - 1 = 3p[/tex]

[tex]p = - \frac{1}{3} [/tex]

Now plug this in for the other formula.

[tex]( \frac{ - \frac{1}{3} +1}{ \frac{1}{3} } ) {}^{2} = 2 {}^{2} = 4[/tex]

So

If A = [tex]\left[\begin{array}{ccc}cosx&-sinx\\sinx&cosx\end{array}\right][/tex], then show that [tex](A^{-1} )^{-1}[/tex]

Answers

Given:

The matrix is:

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

To show:

[tex](A^{-1})^{-1}=A[/tex]

Solution:

If a matrix is:

[tex]M=\begin{bmatrix}a&b\\c&d\end{bmatrix}[/tex]

Then,

[tex]M^{-1}=\dfrac{1}{ad-bc}\begin{bmatrix}d&-b\\-c&a\end{bmatrix}[/tex]

We have,

[tex]A=\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

Using the above formula, we get

[tex]A^{-1}=\dfrac{1}{(\cos x)(\cos x)-(-\sin x)(\sin x)}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\dfrac{1}{1}\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

[tex]A^{-1}=\begin{bmatrix}\cos x&\sin x\\-\sin x&\cos x\end{bmatrix}[/tex]

Now, the inverse of [tex]A^{-1}[/tex] is:

[tex](A^{-1})^{-1}=\dfrac{1}{(\cos x)(\cos x)-(\sin x)(-\sin x)}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{\cos^2x+\sin^2x}\begin{bmatrix}\cos x&-\sin x\\\sin x&\cos x\end{bmatrix}[/tex]

[tex](A^{-1})^{-1}=\dfrac{1}{1}A[/tex]

[tex](A^{-1})^{-1}=A[/tex]

Hence proved.

Write the expression as an exponent:

5^8 x 25
6^15 x 36

Answers

Answer:

a.) 5¹⁰

b.) 6¹⁷

Step-by-step explanation:

a.) 5⁸ × 25

Write 25 in the exponential form with the base of 5.

5⁸ × 5²

To calculate product use exponent rule

5⁸+²5¹⁰

b.) 6¹⁵ × 36

Similarly, 6¹⁵ × 36

Write 25 in the exponential form with the base of 6.

6¹⁵ × 6²

To calculate product use exponent rule.

6¹⁵ + ²6¹⁷

Answer:

[tex] \displaystyle {5}^{10} [/tex]

[tex] \displaystyle {6}^{17} [/tex]

Step-by-step explanation:

Question-1:

we want to rewrite the following expression as an exponent

[tex] \displaystyle {5}^{8} \times {25}[/tex]

remember that 25 is the square of 5 therefore

[tex] \displaystyle {5}^{8} \times {5}^{2} [/tex]

recall that,

[tex] \displaystyle {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]

with that law we obtain:

[tex] \displaystyle {5}^{8 + 2} [/tex]

simplify addition:

[tex] \displaystyle {5}^{10} [/tex]

Question-2:

likewise Question-1 36 is the square of 6 Thus,

[tex] \displaystyle {6}^{15} \times {6}^{2} [/tex]

similarly apply law of exponent:

[tex] \displaystyle {6}^{15 + 2} [/tex]

simplify addition:

[tex] \displaystyle {6}^{17} [/tex]

hence,

we have written the expression as an exponent

Find the missing side or angle. Round to the nearest tenth. C=95° a=5 c=6 A=[?]° ​

Answers

Answer:

Missing angle A = 56.1° (approximately)

Step-by-step explanation:

<A = arcsin(a×sin(C)/c)

= arcsin(5×sin 95/6)

= 56.1154084° ≈ 56.1°

Answered by GAUTHMATH

PLEASE ANSWER ASAAPPPPPPPP

Answers

Answer:

3

Step-by-step explanation:

Find all solutions to the equation.
cos x = sin x (6 points)

Answers

Answer:

Step-by-step explanation:

cos x=sinx

divide by cos x

1=tan x

tan x=1

[tex]tan x=1=tan \frac{\pi }{4}=tan (n\pi +\frac{\pi }{4})\\x=n\pi +\frac{\pi }{4} ,\\where~n~is~an~integer.[/tex]

One leg of a right triangle is 7 inches longer than the other leg, and the hypotenuse is 35 inches. Find the lengths of the legs of the triangle.

Answers

Answer: 21, 28

Step-by-step explanation:

Side #1 = xSide #2 = x + 7Hypotenuse = 35

Use the Pythagorean Theorem [tex]a^{2}+b^{2}=c^{2}[/tex]:

a = xb = x + 7c = 35

Substitute in the values & solve:

[tex]x^{2}+(x+7)^{2}=35^{2}\\x^{2}+x^{2}+14x+49=1225\\2x^{2}+14x+49-1225=0\\2x^{2}+14x-1176=0\\2(x^{2}+7x-588)=0\\2(x + 28)(x - 21)=0\\x_{1}=-28, x_{2}=21[/tex]

-28 is not a possible solution since you can't have negative inches...

a = x = 21b = x + 7 = 21 + 7 = 28c = 35

In a geometric progression, the first tern is 81 and the fourth term is 24. find the common ratio​

Answers

Step-by-step explanation:

81/24= 27/8

Hello,

Let's say a the  first term and r the ratio  of the G.P.

[tex]u_1=a=81\\u_2=a*r\\u_3=a*r^2\\u_4=a*r^3\\\\\dfrac{u_4}{u_1} =\dfrac{a*r^3}{a} =r^3=\dfrac{24}{81} =\dfrac{8}{27} \\\\r=\sqrt[3]{\dfrac{8}{27} } \\\\\boxed{r=\dfrac{2}{3}}\\[/tex]

The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Find the two weights that separate the top 3% and the bottom 3%. (These weights could serve as limits used to identify which components should be rejected)

Answers

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, [tex]\mu=8.04 g[/tex]

Standard deviation, [tex]\sigma=0.08g[/tex]

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of  machine components

[tex]P(X<x_1)=0.03, P(X>x_2)=0.03[/tex]

[tex]P(X<x_1)=P(Z<\frac{x_1-8.04}{0.08})[/tex]

=0.03

From z- table we get

[tex]P(Z<-1.88)=0.03, P(Z>1.88)=0.03[/tex]

Therefore, we get

[tex]\frac{x_1-8.04}{0.08}=-1.88[/tex]

[tex]x_1-8.04=-1.88\times 0.08[/tex]

[tex]x_1=-1.88\times 0.08+8.04[/tex]

[tex]x_1=7.8896[/tex]

[tex]\frac{x_2-8.04}{0.08}=1.88[/tex]

[tex]x_2=1.88\times 0.08+8.04[/tex]

[tex]x_2=8.1904[/tex]

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Need help on this!!!!

Answers

Answer:

D

Step-by-step explanation:

First find h(3)

2(3)-2= 4

then find g(4)

4³-5= 59

yeah it’s D lol djdjhdjxkandbshx

How long is JK?

Choose 1 answer:
A: 3
B: 2 square root 3
C: 3 square root 3
D: 6
E: 9

Answers

Answer:

C) 3 times the sq root of 3

Step-by-step explanation:

In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So

COS 60 = JK/JL

COS 60 = JK/(6*sq root 3)

.5 = JK/(6*3**1/2)

JK = .5 *(6*3**1/2)

JK = 3*3**1/2

A car and a bus were travelling towards each other at uniform speeds. They were 250 km apart at noon and passed each other at 2 p.m. If the speed of the car was 75 km/h, find the speed of the bus.

Answers

Answer:

50 km/hr

Step-by-step explanation:

speed = x + 75

distance = 250km

time = 2

250 = (x + 75) * 2

125 = x + 75

x = 50

Question 4 of 10
Which describes the graph of y=-(x - 3)^2 + 2?
O A. Vertex at (-3,2)
O B. Vertex at (3,-2)
C. Vertex at (3,2)
O D. Vertex at (-3,-2)

Answers

The correct answer is b

Answer:Vertex at (3, -2)

Step-by-step explanation:

Uma empresa do ramo de confecções produz e comercializa calças jeans. Se x representa a quantidade produzida e comercializada (em milhares de reais) e L(x) = -x² + 8x – 16 representa o lucro (em milhares de reais) da empresa para x unidades, então quando L(x) = 0 a empresa terá produzido e comercializadas quantas unidades dessas calças jeans? *

Answers

Answer:

I am in 5 classso i did not known answer

A jet travels 832 km in 5 hours.at this rate,how far could the jet fly in 12 hours? What is the rate of speed of the jet

Answers

Answer:

1344.

Step-by-step explanation :

.

The speed of the jet will be 166.4. If the jet fly for 12 hours, then the distance cover will be 1996.8.

What is speed?

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

Speed = Distance/Time

A jet travels 832 km in 5 hours.

Then the speed of the jet will be

Speed = 832 / 5

Speed = 166.4 km per hours

If the jet fly for 12 hours, then the distance cover will be

Distance = Speed x Time

Distance = 166.4 x 12

Distance = 1996.8 km

More about the speed link is given below.

https://brainly.com/question/7359669

#SPJ2

out of 1300 students in a school , only 60% passed . find the number of students failed .​

Answers

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

520 students.

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

60% of the 1300 students passed. This means that 40% of the students failed.

⸻⸻⸻⸻

[tex]1300 * 0.4= 520[/tex]

⸻⸻⸻⸻

520 students failed school.

⸻⸻⸻⸻

[tex]\boxed{\text{Another way to find this...}}\\\\\text{Take 60}\% \text{ of 1300:}\\\\1300 * 0.6 = 780\\\\\text{780 students passed school.}\\\\\text{Subtract 780 from 1300:}\\\\1300 - 780 = \boxed{520}[/tex]

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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