When the resistance R is doubled, I = 1 A
One of the most fundamental and significant principles controlling electrical and electronic circuits is called Ohm's Law. For a linear device, it relates current, voltage, and resistance.
According to Ohm's Law, the current flowing through a circuit is inversely proportional to the resistance in the circuit and directly proportional to the applied potential difference.
Ohm's law can be written mathematically as follows:
V = IR
Where:
V = voltage expressed in Volts
I = current expressed in Amps
R = resistance expressed in Ohms
If any two quantities are known, the third can be computed by manipulating the formula.
I= V/R
R= V/I
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A concave lens has a focal length of 25cm. it's power in diaptor is
As we know that :
[tex]\begin{gathered}\large{\boxed{\sf{P \: = \: \dfrac{1}{f}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{1}{-25}}}\end{gathered}[/tex]
Power, is in Meter. So divide focal length by 100
[tex]\begin{gathered}\rightarrow {\sf{P \: = \: \dfrac{1}{\dfrac{-25}{100}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{-100}{25}}} \\ \\ \rightarrow {\sf{P \: = \:- 4}} \\ \\ \underline{\sf{\therefore \: Power \: of \: Concave \: lens \: is \: - \: 4D}}\end{gathered}[/tex]
Which is expected to happen during El Niño?
A) Drought conditions in Australia
B) Cool temperatures in the equatorial Pacific
C) An increase in the pressure gradient
D) Unusually high fish yields in Peru
A. Drought conditions in Australia are expected to happen during El Niño.
What is El Nino?El Niño is a normal cycle occurrence of a change in temperatures on the surfaces of the central equatorial, and east equatorial waters of the Pacific Ocean.
The result of this phenomenon which changes the weather condition taking place on the surfaces of the Pacific Ocean is a change in the climate temperatures around the globe, and also the development of weather changes that will affect different parts of the world in different ways.
Hence, drought conditions are a period of time when an area or region experiences below-normal precipitation and El Nino's normal cycle's occurrence changes temperature.
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The thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw is:_____.
The thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw is 66.67%.
It is given that,
Rejected heat at the rate of 20 mw and supplied heat a rate of 60 mw.
It is required to find the thermodynamic efficiency of a heat engine.
What is the thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw?As we know that
Work Done = Heat Supplied - Heat Rejected
Work Done = 60 mw - 20 mw
Work Done = 40 mw
So the efficiency of heat engine will be:
[tex]\eta=\frac{Work done}{Heat energy supply}[/tex]
[tex]\eta=\frac{40}{60}[/tex]×[tex]100\\[/tex]
η = [tex]\frac{2}{3}[/tex]×[tex]100\\[/tex]
η = 66.67%
Thus, thermodynamic efficiency of a heat engine that rejects heat at a rate of 20 mw when heat is supplied to it at a rate of 60 mw is 66.67%.
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At what distance from a 27 mw point source of electromagnetic waves is the electric field amplitude 0. 060 v/m ?
The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.
c = 3 * [tex]10^{8}[/tex] m/s
∈ = 8.85 * [tex]10^{- 12}[/tex] [tex]C^{2}[/tex] / N/ [tex]m^{2}[/tex]
E = 0. 060 v/m
I = P / 4π[tex]r^{2}[/tex]
Also , I = c ∈ [tex]E^{2}[/tex] /2
[tex]r^{2}[/tex] = P / 4π I equation 1
substituting the value of I in equation 1
[tex]r^{2}[/tex] = 2 P / 4π (c ∈ [tex]E^{2}[/tex] )
[tex]r^{2}[/tex] = 2 * 27 * [tex]10^{-3}[/tex] / 4 * 3.14 * 3 * [tex]10^{8}[/tex] * 8.85 * [tex]10^{- 12}[/tex] * [tex](0.06)^{2}[/tex]
r = 21.21 m
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The electric field at a distance of 10 cm from an isolated point particle with a charge of 2 x 10–9 c is:________
The electric field at a distance of 10 cm from an isolated point particle with a charge of 2 x 10–9 c is 1.8×10³N/C.
When the charge is present in any form, an electric field is linked with each point in space. The value of E, also known as electric field strength, electric field intensity, or simply the electric field, expresses the magnitude and direction of the electric field.
The electric field is formally defined as a vector field associated with each location in space, the force per unit charge exerted on a positive test charge at rest at that point. The electric charge or time-varying magnetic fields generate the electric field. The magnitude of the electric field produced by a point charge Q is given by this equation.
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Static electric fields are caused by charged particles. What characterizes a positively charged particle?
A
The atoms which compose the particle will have more electrons than protons.
B
The atoms which compose the particle will have the same number of electrons as protons.
C
The atoms which compose the particle will have more protons than electrons.
D
By convention, positively charged particles always have all their magnetic dipoles aligned with the north pole.
Static electric fields are caused by charged particles when the atoms which compose the particle will have the same number of electrons as protons.
Each point in space has an electric field associated with it when the charge of any kind is present. The value of E, often known as the electric field strength, electric field intensity, or just the electric field, expresses the strength and direction of the electric field.
Both the electromagnetic wave produced by a radio broadcast monopole antenna and the field created in the dielectric of a parallel-plate capacitor are examples of electric fields (which create a time-varying field). Every place in space where a charge, regardless of its shape, is present is said to have an electric field, which is an electric attribute. The electric field's equation is given as E = F / Q.
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How far apart are two conducting plates that have an electric field strength of 4. 4 kv/m between them, if their potential difference is 15 kv?
Conducting plates will be 3.75 m apart if an electric field strength of 4. 4 kV/m between them, if their potential difference is 15 kV
The potential difference, also referred to as voltage difference between two given points is the work in joules required to move one coulomb of charge from one point to the other. The SI unit of voltage is the volt. Volt Formula.
In a simple parallel-plate capacitor, a voltage applied between two conductive plates creates a uniform electric field between those plates. The electric field strength in a capacitor is directly proportional to the voltage applied and inversely proportional to the distance between the plates.
E = V/d
E = Electric field strength
d = distance between the plates
V = potential difference
Electric field strength = 4 kV/m
Potential difference = 15 kV
d = V / E = 15 kV / 4 kV/m
= 3.75 m
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A 0.20-μf capacitor is connected to a 300-v battery. What potential energy is stored in the capacitor?
A 0.20-μf capacitor is connected to a 300-v battery, the potential energy is stored in the capacitor will be 9 * [tex]10^{-3}[/tex] J
The energy stored in a capacitor is nothing but the electric potential energy and is related to the voltage and charge on the capacitor. If the capacitance of a conductor is C, then it is initially uncharged and it acquires a potential difference V when connected to a battery.
Its two plates hold opposite charges and the separation between them creates an electric field. That's why a capacitor stores energy.
Capacitance = 0.20 * [tex]10^{-6}[/tex]
voltage = 300 V
Potential energy stored in a capacitor = 1/2 *C * [tex]V^{2}[/tex]
= 1/2 * 0.20 * [tex]10^{-6}[/tex] * [tex](300)^{2}[/tex]
= 9000 * [tex]10^{-6}[/tex]
= 9 * [tex]10^{-3}[/tex] J
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In a particular electrolysis process, eocathode = -1. 151 v and eoanode = 1. 548 v. what minimum voltage must be applied to drive the nonspontaneous process?
In a particular electrolysis process, Eο cathode = -1.151 v and Eο anode = 1.548 V. The minimum voltage must be applied to drive the non-spontaneous process is 2.699V.
Electrode Potential Or Voltage is the emf of a galvanic cell where emf is called as the Electromotive force.
Electrode Potential of a spontaneous cell is positive. Hence to make a non-spontaneous cell into a spontaneous cell, the voltage or potential applied should be positive to make the cell working.
We know that,
Electrode Potential = Electrode Potential of cathode - Electrode Potential of anode
where, Electrode Potential of cathode = -1.151V
Electrode Potential of anode = 1.548V
On substituting,
⇒ Electrode Potential = -1.151V - 1.548V
⇒ Electrode Potential = - 2.699V
Hence, the minimum voltage to drive a non-spontaneous cell into a spontaneous cell should be at least 2.699V.
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An object having a fixed emissivity of 0. 725 radiates heat at a rate of 10 w when it is at an absolute temperature t. If its temperature is doubled to 2t, at what rate will it now radiate?.
If the temperature is doubled to 2t, the rate at which it will now radiate is 160 W.
What is meant by emissivity?The ability of a substance to reflect heat radiation from its surface is measured by its emissivity. Thermal radiation is a type of electromagnetic radiation that includes infrared radiation, which the human eye cannot perceive, as well as visible radiation (light). According to the Stefan-Boltzmann law, emissivity is the quantitative comparison between the thermal radiation of a surface and that of an ideal black surface at a given temperature. Between 0 and 1 is the ratio's range.What is energy radiation?The emissivity of a substance is a measurement of how well it reflects heat radiation from its surface. Two elements that affect power dissipation in the form of radiation are the material's surface emissivity and the temperature difference between the chip surface and the surrounding air.To learn more about emissivity visit:
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A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. What strength of magnetic field will it have at its center?
A solenoid with 500 turns is 0. 10 m long and carries a current of 4. 0. The strength of magnetic field at its center will be 2.5 * [tex]10^{-2}[/tex] H
Magnetic Field is the region around a magnetic material or a moving electric charge within which the force of magnetism acts.
A coil of wire which is designed to generate a strong magnetic field within the coil is called a solenoid. Wrapping the same wire many times around a cylinder creates a strong magnetic field when an electric current is passed through it. N denotes the number of turns the solenoid has.
Magnetic field at the center of the solenoid = mu0 * I * N / L
I = current in the solenoid
N = number of turns in the solenoid
L = length of the coil
B = 4π * [tex]10^{-7}[/tex] * 4 * 500 / 0.10
= 251200 * [tex]10^{-7}[/tex] H
= 2.5 * [tex]10^{-2}[/tex] H
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Glycerin at a temperature of 30 degrees celcius flows at a rate of 8×10−6m3/sthrougha horizontal tube with a 30mmdiameter. what is the pressure drop in pascals per100m?
The pressure drop in pascal is 3.824*10^4 Pascals.
To find the answer, we need to know about the Poiseuille's formula.
How to find the pressure drop in pascal?We have the Poiseuille's formula,[tex]Q=\frac{\pi r^4P}{8\beta l}[/tex]
where, Q is the rate of flow, P is the pressure drop, r is the radius of the pipe, is the coefficient of viscosity (0.95Pas-s for Glycerin) and l being the length of the tube.By substituting values and rearranging we will get the pressure drop as,[tex]P=3.284Pascals[/tex]
Thus, we can conclude that, the pressure drop in pascal is 3.824*10^4.
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A large plate carries a uniform charge density σ = 8. 85 × 10-9 c/m2. a pattern showing equipotential surfaces with a 5 v potential difference would appear as:_________
The potential difference comes out to be
[tex]10 \times 10 {}^{ - 3} m[/tex]
Given:
σ = 8. 85 × 10-9 c/m2
we know,
[tex]E = \frac{σ}{2ε0}[/tex]
[tex]E = \frac{8.85 \times 10 {}^{ - 9} }{2ε0}[/tex]
[tex]E = \frac{v}{d} [/tex]
given the potential difference between two equipotential surface=5v
E=∆v
∆d=∆v/E
[tex] = \frac{5 \times 8.85 \times 10 { }^{ - 12} \times 2 }{8.85 \times 10 {}^{ - 9} } [/tex]
[tex]Δ = 10 \times 10 {}^{ - 3} m[/tex]
Thus the potential difference is
[tex]10 \times 10 {}^{ - 3} m[/tex]
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A proton moving at 7. 0 × 10^4 m/s horizontally enters a region where a magnetic field of 0. 10 t is present, directed vertically downward. What magnitude force acts on the proton due to this field?
A proton moving at 7. 0 × 10^4 m/s horizontally enters a region where a magnetic field of 0. 10 t is present, directed vertically downward. The magnitude force acts on the proton due to this field will be 1.12 * [tex]10^{-23}[/tex] N
Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.
Force in a magnetic field = q. ( v * B )
where
q = charge of particle = 1.6 * [tex]10^{-27}[/tex] C
v = velocity of particle = 7. 0 × [tex]10^{4}[/tex] m/s
B = 0. 10 T
Force = 1.6 * [tex]10^{-27}[/tex] * 7. 0 × [tex]10^{4}[/tex] * 0. 10
= 1.12 * [tex]10^{-23}[/tex] N
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When a solid is heated, it emits electromagnetic radiation known as ________________. an example of such radiation is the element of a stove top burning bright red.
Answer:
I think the answer is thermal radiation
What is the specific heat of a substance that requires 99,100 J of thermal energy to heat 3.47 kg of this substance from 11°C to 45°C?
Answer: [tex]\Large\boxed{0.84~J/g^\circ C}[/tex]
Explanation:
Given information
[tex]Q~(Energy)=99,100~J[/tex]
[tex]m=3.47~kg[/tex]
[tex]\Delta T=(T_{Final}-T_{Initial})=(45-11)=34^\circ C[/tex]
Given formula
[tex]Q=m\times c\times\Delta T[/tex]
[tex]Q=Energy\\m=mass\\c=specific~heat\\\Delta T=Change~in~temperature[/tex]
Convert the unit of mass into Grams
[tex]1~kg=1000~g\\[/tex]
[tex]3.47~kg=3.47\times 1000=3470~g[/tex]
Substitute values into the given formula
[tex](99100)=(3470)\times c \times(34)[/tex]
Simplify by multiplication
[tex]99100=117980~c[/tex]
Divide 117980 on both sides
[tex]99100\div117980=117980~c\div117980[/tex]
[tex]\Large\boxed{c=0.84~J/g^\circ C}[/tex]
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What is the net force on a rock that has a force of 4.9N down and 2.8N up applied to it
7.7N up
-7.7N down
-2.1N down
2.1N down
The net force on a rock that has a force of 4.9N down and 2.8N up applied to it is 2.1N down.
Define force.
A force is an effect that can alter an object's motion according to physics. An mass-laden object can change its velocity, or accelerate, as a function of a force. An obvious method of describing force is as a push or a pull. A force is a vector quantity because it possesses both magnitude and direction.
Thrust, which increases an object's velocity; drag, which decreases an object's velocity; and torque, which causes changes in an object's rotational speed, are all concepts connected to force. Each part of an extended body often exerts stresses on the sections that are nearby.
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1. what is the electric force between a point charge and a point charge if they are separated by a distance of 5.0 cm? show your work.
-14.4 N is the electric force between a point charge and a point charge if they are separated by a distance of 5.0 cm.
The electrostatic force between two-point charges is given by:
[tex]F = K_{e}\frac{q1q2}{r^{2} }[/tex]
where,
[tex]K_{e}[/tex] is the Coulomb's constant
q1 and q2 are the two charges
r is the distance between them
In our problem, charge 1 is
[tex]q1=+2=+2.0 *10^{-6}C[/tex]
while charge 2 is
[tex]q2=-2=-2.0 *10^{-6}C[/tex]
and their distance is
r=5.0 cm=0.05 m
So, the electrostatic force between them is
[tex]F=8.99*10^{9} Nm^{2}C^{-2} \frac{(+2.0*10^{-6} )(-2*10^{-6} )}{(0.05m^{2} )}=-14.4N[/tex]
And the negative sign means the force is attractive, because the two charges have opposite sign.
What is electric force?The electrostatic force between two-point charges separated by a distance is directly proportional to the multiplication of the magnitudes of the charges and inversely proportional to the square of the distance between the charges.
What are some electrostatic force examples?The force of attraction of the plastic wrap to one’s hand and later when hand is removed from the wrap.The attraction of paper to a charged scale by rubbing to hair.The apparently spontaneous explosion of grain silos.Photocopier & laser printer operation.Learn more about electric force:
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The right answer is F= 3.59502N
According to Coulomb’s law if two point charges q1 and q2 are separated by a distance r then the magnitude of the force of repulsion or attraction between them is
F=k|q1| |q2|r2 where k=8.9876*109N.m2C2
What is Coulomb's law?
The product of the charges and the square of the distance between them determine the force of attraction or repulsion occurring in a straight line between two electric charges.
This is the strength of the force that each charge has on the other charge, according to Newton's third law. The symbol k as it is used here has nothing to do with any spring constants or Boltzmann's constant; it has to do with electrical forces!
In the event that charges q1 and q2 have the same sign (either they are both positive or negative), The force on each charge points away from the other charge and is mutually repelling.The force is reciprocal if the charges have opposite signs (one positive, one negative).
Each charge is attracted to the other by its own force.. This is illustrated in
The constant k is often written as
k=140 where 0=8.85419*10-12C2N.m2
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A 4. 0 g sample of ra-226 decays to 1. 0 g. if the half-life of ra-226 is 1620 years, how much time has elapsed?
The time elapsed is 3229.2 days.
First-order reactions include those in radioactive decay. The reduction in radioactive nuclei per unit of time is the rate of decay, or activity, of a sample of a radioactive substance.
The Radioactive Formula is given by
[tex]N =[/tex] N₀ [tex](\frac{1}{2} )^\frac{t}{T}[/tex]
Where N₀ = The initial quantity of the substance.
N = The quantity remained.
T = the half-life of the decaying quantity.
t = time elapsed
The initial quantity of the substance = 4.0 g
The quantity remained = 1.0 g
The half-life of the decaying quantity = 1620 years
Using formula;
[tex]1.0 = 4.0 (\frac{1}{2} )^\frac{t}{1620} \\[/tex]
[tex]log \frac{1.0}{4.0} = \frac{1}{1620} log \frac{1}{2}\\[/tex]
[tex]log 0.25 = \frac{t}{1620} log 0.5\\[/tex]
[tex]-0.60 = \frac{t}{1620} (-0.301)\\[/tex]
[tex]t = \frac{972}{0.301} \\[/tex]
[tex]t= 3229.2 sec[/tex]
Therefore, the time elapsed is 3229.2 days
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b.
How
6. An astronaut on the moon throws a wrench straight up with a speed of 4.0m/s. Three
seconds later, it is falling down with a speed of 0.80m/s.
a.What is the acceleration of the wrench?
b.How far above the point of release will the wrench be after 3.0s?
C.How long would it take for the wrench to return to its starting position?
Answer:
Kinematics of the parabolic movement
To solve the problem we will apply the kinematic equations of linear motion, which are an essential part in the characterization of parabolic motion. In this case we require the definition of acceleration described mathematically as,
a
=
v
f
−
v
i
t
Here,
v
f
=
Final Velocity
v
i
=
Initial Velocity
t
=
Time
Answer and Explanation: 1
Become a Study.com member to unlock this answer! Create your account
According to the information provided we have to
{eq}\text{Initial Velocity} = v_i = 4.0\text{ m/s}\\ \text{Initial Velocity} = v_f = 0.80\text{
Approximating the eye as a single thin lens 2. 75 cmcm from the retina, find the eye's near-point distance if the smallest focal length the eye can produce is 2. 20 cm.
The near-point distance of the eye is 11 cm.
What is the eye's near-point distance?The near-point distance of the eye is the closest possible distance an object can be from the eye in order for its image to be formed on the retina. It can also be termed the closest distance of accommodation.
The near-point distance of the eye in the given scenario can be calculated using the lens formula given below:
1/f = 1/v + 1/u
where;
f = focal length
v = image distance
u = object distance
From the data provided;
f = 2.20 cm
v = 2.75 cm
u = ?
Solving for u:
1/u = 1/f - 1/v
1/u = 1/2.20 - 1/2.75
1/u = 0.91
u = 11 cm
In conclusion, the lens formula is used to determine the eye's near-point distance.
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Which of the following identifies the cause and effect relationship shown in the data?
A
An increase in light intensity causes an increase in electric current.
B
An increase in light intensity causes a decrease in electric current.
C
An increase in electric current causes an increase in light intensity.
D
An increase in electric current causes a decrease in light intensity.
An increase in light intensity causes an increase in electric current.
The rate of electron passage in a conductor is known as electric current. The ampere is the electric current's SI unit. Electrons are little particles that are part of a substance's molecular structure. These electrons can be held loosely or securely depending on the situation.
Electric current is measured in a SI unit known as an ampere, or A. It is determined by assuming that the elementary charge, e, has a fixed numerical value of 1.602 176 634 x 10-19 when expressed in unit C, which is equivalent to the second in terms of VCs.
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You are walking out on a frozen lake and you begin to hear the ice cracking beneath you. What is your best strategy for getting off the ice safely?
A Final statement or concluding statement
As, Pressure(P)=(Force(F))/(Area(A)) . So, By Lying down flat on the ice and crawl towards shore will help to get off the ice safely.
What is the relationship between Area and Pressure?Pressure and area of contact are related in such a way that they are inversely proportional to each other.
As the area shrinks, so does the pressure.
Consider the difference between the pressure exerted by a finger pressing on the skin and the pressure exerted by a needle attached to a syringe.
When pressed, the finger may cause a slight depression on the skin but may not cause any pain.
When the same force is applied to a needle, however, the pressure produced is sufficient to puncture the skin.
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An individual is running around a turn with a 17 m radius at 6. 64m/s. Compute the runner’s centripetal acceleration.
Answer:
2.59 ms^2
Explanation:
Radius, r= 17m
Velocity,v = 6.64m/s
Ac= V^2/r
Ac= (6.64)^2/17
Ac= 2.59 m/s^2
Twelve seconds after starting from rest a freely-falling cantaloupe has a speed of_______.
Twelve seconds after starting from rest a freely falling of cantaloupe has a speed of 114 m/s
When a body moves exclusively under the influence of the Earth's gravity, it is said to be in freefall. The motion of the ball will be accelerated as a result of an external force acting on it. This free-fall acceleration is also known as acceleration due to gravity.
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics.
from kinematic equation of motion`
v = u+ at
=u + gt (The acceleration for a free-falling object is g)
since, starting from rest
initial velocity = u = 0
time = 12 seconds
g= 9.81 m/ [tex]s^{2}[/tex]
v = u + gt
= 0 + 9.8 * 12
= 117.6 m/s
≈ 118 m/s
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What must the amplitude of a traveling wave of frequency 72.0 hz be in order for the average power carried by the wave to be 0.363 w ? express your answer with the appropriate units.
The tension in the wire, the wave's speed, its frequency, and its average power are used to calculate the wave's amplitude.
To find the answer, we have to know about the simple harmonic motion.
How to find the amplitude of a traveling wave?We have the expression for average power carried by the wave as,P = (¹/₂)(T/v²)(ω²)(A²)(v)
P = (¹/₂)(T/v)(ω²)(A²)
P = (¹/₂)(T/v)(2πf)²(A²)
where; U is the average power of the wave, T is the tension e wire, ω angular frequency of the wave, A is amplitude of the wave, v is the speed of the wave and f is frequency of the wave.
Thus, the tension in the wire, the wave's speed, its frequency, and its average power are used to calculate the wave's amplitude.
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The world’s longest organ pipe, in the boardwalk hall auditorium in atlantic city, is 64 feet long. what is the fundamental frequency of this openopen pipe?
The fundamental frequency of this open-open pipe is 8.82 Hz
The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Frequency is the number of full cycles per second in the alternating current direction for an oscillating or fluctuating current. The hertz, also known as Hz, is the accepted unit of frequency.
The temporal rate of change observed in oscillatory and periodic phenomena, such as mechanical vibrations, audio signals (sound), radio waves, and light, is specified by the frequency, an essential parameter in science and engineering.
Assume vs = 344 m/s
f1 = vs/2L
= 344 m/s/ 2∙64 ft/(3.281 ft/m)
= 8.82 Hz
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When discharging, what percentage of the starting voltage will the capacitor reach after 5rc?
When discharging equivalent of 0% starting voltage will the capacitor reach after 5RC.
V(t) = V0e-t/RC = V0b initially.
What is capacitor?In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.The terminals in a capacitor are connected to two metal plates that are spaced apart by a dielectric, a non-conducting material. Two pieces of aluminum foil, along with a piece of paper, can be used to create a capacitor (and some electrical clips). It won't have a lot of storage capacity, so it won't be a great capacitor, but it will still function.What are the different types of capacitors?The numerous kinds of capacitors and their applications.
Frequently utilized in radio tuning circuits is air.Mylar: The material most frequently used in timer circuits for clocks, alarms, and counting.Good for high-voltage applications is glass.Ceramic is used in X-ray, MRI, and other high-frequency devices.a powerful capacitor fuels hybrid and electric vehicles.Learn more about capacitors here:
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50. a kangaroo can jump over an object 2.50 m high. (a) calculate its vertical speed when it leaves the ground. (b) how long is it in the air?
Answer:
The easiest way to do this is to realize that the time to fall is the same as the rise time (conservation of energy can easily verify this)
S = 1/2 g t^2 time to fall 2.5 m
t = (5 / 9.8)^1.2 = .714 sec time in air
v = a t = 9.8 * .714 = 7 m/s initial vertical speed
Check:
S = v t - 1/2 g t^2 where v is the initial vertical speed
S = 7 * .714 - 4.9 * .714^2 = 2.5 m total vertical distance traveled
A car has 400 kgm/s worth of
momentum and runs into a truck initially at rest. After the collision,
the truck has 500 kgm/s
worth of momentum.
What must be the final momentum of the car?
A. 100 kgm/s
B. 500 kgm/s
C. -100 kgm/s
D. 400 kgm/s
Hello and Good Morning/Afternoon
Let's take this problem step-by-step:
By the Law of Conservation of momentum
⇒ the total momentum always remains constant before and after the
collision
Pc: the momentum of the car initially before collisionPcf: the momentum of the car after the collisionPt: the momentum of the truckPc = Pt + PcF
400 = 500 + PcF
PcF = -100 kg * m/s
Therefore the car's final momentum is -100 kg*m/s
Answer: -100 kg*m/s or choice (C)
Hope that helps!
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