the pilot of an airplane notes that the compass indicates a heading due west. the airplane's speed relative to the air is 170 km/h. the air is moving in a wind at 26.0 km/h toward the north. find the velocity of the airplane relative to the ground.

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Answer 1

The velocity of the airplane relative to the ground is 171.28 km/h.

Given,Speed of the airplane relative to the air = 170 km/hVelocity of the wind = 26 km/hThe compass indicates a heading due west. So, the plane is traveling in the west direction.The velocity of the airplane is made up of two components, velocity relative to the air and velocity relative to the ground. We have to find the velocity of the airplane relative to the ground.Velocity of the airplane relative to the ground can be found using Pythagoras theorem. Let v be the velocity of the airplane relative to the ground.Then, v² = (170)² + (26)²v² = 28,900 + 676v² = 29,576v = sqrt(29,576)v = 171.28 km/h.

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Related Questions

Discuss whether any work is being done by each of the following agents and, if so, whether the work is positive or negative. (c) a crane lifting a bucket of concrete

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The crane lifting the bucket of concrete is doing positive work as it applies a force in the direction of the displacement.

In the case of a crane lifting a bucket of concrete, work is indeed being done. The work done by the crane can be determined by the equation:

Work = Force x Distance x cos(θ)

Here, the force is the upward force exerted by the crane on the bucket, the distance is the vertical displacement of the bucket, and θ is the angle between the force and the displacement.

Since the crane is lifting the bucket upward, the force exerted by the crane and the displacement of the bucket are in the same direction. Therefore, the angle θ between them is 0 degrees, and the cosine of 0 degrees is 1. As a result, the work done by the crane is positive.

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For the beam and loading shown, determine the minimum required width 6, knowing that for the grade of timber used, Call = 18 MPa and Tall = 975 kPa. b = 43 mm Х 2.0 kN 6.8 KN 8.4 kN B D E 300 mm 4 m 4 m 4m 0.50 m

Answers

The minimum required width b of the beam is 200 mm.

The following steps were used to calculate the minimum required width:

Calculate the maximum bending moment Mmax at the center of the beam.

Mmax = (2.0 kN)(4 m) + (6.8 kN)(4 m) + (8.4 kN)(4 m) = 67.2 kNm

Calculate the required modulus of section Z to resist the maximum bending moment.

Z = Mmax / Tall = 67.2 kNm / 975 kPa

Z = 68.8 cm^3

Calculate the required cross-sectional area A of the beam.

A = Z / b = 68.8 cm^3 / 200 mm

A = 0.344 m^2

Calculate the required width b of the beam.

b = A / h = 0.344 m^2 / 0.50 m = 0.688 m

b= 200 mm

The minimum required width of the beam is 200 mm.

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