The point on the graph that lies on the y-axis (vertical axis) is called the y-intercept. What does the y-intercept tell you about the runner? ( look at photo)
the ending position of the runner

Choices:

the runners distance from the state

the starting position of the runner

the runners speed

The Point On The Graph That Lies On The Y-axis (vertical Axis) Is Called The Y-intercept. What Does The

Answers

Answer 1

Answer:

The starting position of the runner.

Explanation:

When you look at the graph, you can see that the first point on the graph is twenty on the y-axis.

The runner starts at twenty, and ends at thirty.

Therefore, the runner starts at twenty on the y-axis, so it's the starting position of the runner.

Answer 2

The y-intercept tell you about the starting position of the runner.

What is y-intercept of a function?

The intersection of the graph of the function with the y-axis gives y-intercept of that function. The y-intercept is the value of y on the y-axis at which the considered function intersects it.

Assume that we've got: y = f(x)

At y-axis, we've got x = 0, so putting it will give us the y-intercept.

Thus, y-intercept of y = f(x) is y = f(0)

When we look at the graph, we can see that the first point on the graph is twenty on the y-axis.

The runner starts at twenty and ends at thirty.

Thus, the runner starts at twenty on the y-axis, so it is the starting position of the runner.

The y-intercept tell you about the starting position of the runner.

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Related Questions

you play a video game for 20 minutes. you lose 160 points. what is the mean change in points per minute

Answers

The mean change in points per minute is -8 points per minute.

To calculate the mean change in points per minute, we need to divide the total change in points by the number of minutes.

Let's assume that the change in points is represented by ΔP and the time elapsed is represented by Δt. Therefore, the mean change in points per minute is given by:

Mean change in points per minute = ΔP/Δt

We are given that the change in points is -160 (loss of 160 points). We are also given that the time elapsed is 20 minutes. Substituting these values in the above equation gives:

Mean change in points per minute = -160/20

Mean change in points per minute = -8

Therefore, the mean change in points per minute is -8 points per minute.

In this scenario, we have calculated the mean change in points per minute for a video game played for 20 minutes resulting in a loss of 160 points. It turns out that the mean change in points per minute is -8 points per minute, which implies that on average the player loses 8 points every minute of gameplay.

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A Ferris wheel with radius RRR = 13.0 mm is turning about a horizontal axis through its center in (Figure 1). The linear speed of a passenger on the rim is constant and equal to 6.40 m/sm/s. A- What is the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion? B- What is the direction of the passenger's acceleration as she passes through the lowest point in her circular motion? C- What is the magnitude of the passenger's acceleration as she passes through the highest point in her circular motion? D- What is the direction of the passenger's acceleration as she passes through the highest point in her circular motion? E- How much time does it take the Ferris wheel to make one revolution?

Answers

(A) The magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion is a ≈ 20.48 m/s^2.

(B) The direction of the acceleration at the lowest point is directed towards the center of the circle, i.e., it is radially inward.

(C) The magnitude of the passenger's acceleration at the highest point is approximately 20.48 m/s^2.

(D)Similar to the lowest point, the direction of the acceleration at the highest point is directed towards the center of the circle, i.e., radially inward.

(E)It takes approximately 0.0407 seconds for the Ferris wheel to make one revolution.

A) To find the magnitude of the passenger's acceleration at the lowest point, we can use the centripetal acceleration formula:

a = v^2 / R

where a is the acceleration, v is the linear speed, and R is the radius of the Ferris wheel. Substituting the given values:

a = (6.40 m/s)^2 / 13.0 mm

First, we need to convert the radius from millimeters to meters:

R = 13.0 mm = 13.0 × 10^-3 m

Substituting this value into the equation:

a = (6.40 m/s)^2 / (13.0 × 10^-3 m)

Calculating the result:

a ≈ 20.48 m/s^2

Therefore, the magnitude of the passenger's acceleration at the lowest point is approximately 20.48 m/s^2.

B) The direction of the acceleration at the lowest point is directed towards the center of the circle, i.e., it is radially inward. This is because the acceleration is always directed towards the center of the circular motion.

C) To find the magnitude of the passenger's acceleration at the highest point, we can use the same formula as in part A, since the linear speed remains constant throughout the motion:

a = v^2 / R

Substituting the given values:

a = (6.40 m/s)^2 / 13.0 × 10^-3 m

Calculating the result:

a ≈ 20.48 m/s^2

Therefore, the magnitude of the passenger's acceleration at the highest point is approximately 20.48 m/s^2.

D) Similar to the lowest point, the direction of the acceleration at the highest point is directed towards the center of the circle, i.e., radially inward.

E) The time taken for one revolution of the Ferris wheel is equal to the time period of circular motion. The formula for the time period is given by:

T = 2πR / v

where T is the time period, R is the radius, and v is the linear speed. Substituting the given values:

T = 2π × 13.0 × 10^-3 m / 6.40 m/s

Calculating the result:

T ≈ 0.0407 seconds

Therefore, it takes approximately 0.0407 seconds for the Ferris wheel to make one revolution.

In summary, the magnitude of the passenger's acceleration is 20.48 m/s^2 at both the lowest and highest points. The direction of the acceleration is radially inward at both points. The time taken for one revolution of the Ferris wheel is approximately 0.0407 seconds.

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consider the following experimentally measured current outputs at different forward bias voltages applied to a si solar cell irradiated with sunlight: v (v) i (a) 0.75 0 0.6 -0.14 0.5 -0.42 0.4 -0.65 0.3 -1.27 0.1 -2.8 (a) at which applied voltage is the power output of the cell maximized? (b) if you use a different solar cell material with a narrower band gap than si (egsi

Answers

a) Power output of the cell is maximized at 0.40 V because this is the voltage at which the highest power output (-0.260 W) is obtained ; b) To increase the power output of the solar cell, one approach is to use a material with a narrower bandgap.

(a) To find the voltage at which the power output of the cell is maximized, the power output at each voltage must first be calculated using the formula P=VI.

Here's the table with the calculated power output:

| P(v) | I(A)  | P(W)   |

|------|-------|--------|

| 0.75 |  0.00 |  0.00  |

| 0.60 | -0.14 | -0.084 |

| 0.50 | -0.42 | -0.210 |

| 0.40 | -0.65 | -0.260 |

| 0.30 | -1.27 | -0.381 |

| 0.10 | -2.80 | -0.280 |

We can see that the power output of the cell is maximized at 0.40 V because this is the voltage at which the highest power output (-0.260 W) is obtained.

(b) The solar cell's power output is proportional to the product of the current and voltage, which is the point at which the power output is maximized.

To increase the power output of the solar cell, one approach is to use a material with a narrower bandgap. The narrow-bandgap solar cell is expected to have a higher open-circuit voltage (Voc), but a lower short-circuit current (Isc) than the silicon solar cell. As a result, the power output may be improved by changing the cell material.

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How is the answer D?

Answers

The graph that corresponds to 0.1 s in one complete cycle is graph D.

option D is the correct answer.

What is the period of a wave?

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years.

Also, the period of a wave is the amount of time it takes for a wave to complete one wave cycle or wavelength.

From the given parameter, the coil rotates 10 times in one second. The period of the coil is calculated as;

Period = 1 s / 10

Period = 0.1 s

From the graphs, the only option that has one complete cycle in one second is option D.

Check option D, half cycle is 0.05 s and one full cycle is 0.1 s.

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26. A single-turn wire loop is 2.0 cm in diameter and carries a 650- mA current. Find the magnetic field strength (a) at the loop center and (b) on the loop axis, 20 cm from the center.

Answers

The magnetic field strength at the center of the single-turn wire loop is approximately 1.03 μT (microtesla). On the loop axis, 20 cm from the center, the magnetic field strength is approximately 0.52 μT.

The magnetic field strength at the center of a single-turn wire loop carrying current can be calculated using the formula:

(a) B(center) = (μ₀ * I) / (2 * R)

Where μ₀ is the permeability of free space, I is the current, and R is the radius of the loop. Given that the diameter of the loop is 2.0 cm, the radius can be calculated as R = 1.0 cm = 0.01 m. The current is 650 mA, which is 0.65 A. Plugging in these values into the formula:

B(center) = (4π * 10^(-7) * 0.65) / (2 * 0.01) ≈ 1.03 μT

On the loop axis, 20 cm from the center, the magnetic field strength can be calculated using the formula:

(b) B(axis) = (μ₀ * I * R²) / (2 * (R² + d²)^(3/2))

Where d is the distance from the center of the loop to the point on the axis. Given that d = 20 cm = 0.2 m, plugging in the values into the formula:

B(axis) = (4π * 10^(-7) * 0.65 * (0.01)²) / (2 * ((0.01)² + (0.2)²)^(3/2)) ≈ 0.52 μT

Therefore, the magnetic field strength at the center of the loop is approximately 1.03 μT, and on the loop axis, 20 cm from the center, it is approximately 0.52 μT.

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acceleration always refers as an

Answers

Answer:

Acceleration is a vector, and thus has a both a magnitude and direction. Acceleration can be caused by either a change in the magnitude or the direction of the velocity.

Explanation:

a non-rechargeable battery can best be described as a/an energy system and a/an material system.

Answers

A non-rechargeable battery can best be described as a closed energy system and an open material system. The main answer is an open material system The battery is an electrical device that contains one or more cells with terminals that can generate electric current.

The device can either be rechargeable or non-rechargeable.Non-rechargeable batteries have a single usage, and once their energy is used up, they can no longer produce an electric current. Their components cannot be re-energized, meaning the battery is a closed energy system that converts stored chemical energy into electrical energy. An open material system, on the other hand, is one that permits matter to enter and leave

, such as a non-rechargeable battery since its components can be removed and replaced when it has depleted its energy or is expired.A rechargeable battery, on the other hand, is a semi-open energy system that can be charged repeatedly and converted from electrical to chemical energy and vice versa.

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On an annual basis, match the following terms with the proper value and unit for the following situation: Assume the energy required to produce a conventional steel vehicle (CV) is 100 million BTUs and that the conventional steel vehicle gets around 33 miles per gallon (mpg). Suppose an aluminum intensive vehicle (AIV) requires 15% more energy to produce than a conventional vehicle. However, the inclusion of aluminum in the body lightens the vehicle by 6% by mass, resulting in an increase of fuel economy from 33 mpg to 34 mpg. For both cars, assume a 15 year lifetime and 12,000 miles driven per year. Assume that the energy content of gasoline is 114,000 BTU/gallon and that the production of a gallon of gas requires 26,000 BTU. CV annual gasoline use 364 galdyr CV Ed [Choose ] AIV Ed [Choose ] CV Eiot (over its lifetime) [Choose ] AIV Eiot (over its lifetime) [Choose ] AIV Eic [Choose] CV Ei [Choose ] Same problem as above (CV vs. AIV). Life cycle energy use is the total input of direct and indirect energy over the systems lifetime. What is the life cycle energy use for the CV in this problem. Report using 3 significant figures and in MBTU. Same problem as above (CV vs. AIV). What is the life cycle energy use for the AIV in this problem. Report using 3 significant figures and in MBTU. Same problem as above (CV vs. AIV). If it took 15% more energy for the end of life processes for the CV as compared to the AIV, which car would have LOWER life cycle energy use?

Answers

The conventional steel vehicle (CV) uses 39,336 gallons of gasoline per year, resulting in an annual energy consumption of 100,000 MBTU. The CV's total life cycle energy use is 115,000  MBTU.

Annual gasoline use for CV:

CV's annual gasoline use = (12,000 miles/year) / (33 miles/gallon) = 364 gallons.

Energy consumption during operation (Ed) for CV:

CV's annual energy consumption during operation = (364 gallons/year) × (114,000 BTU/gallon) = 41,496,000 BTU.

Converting to MBTU: CV Ed = 41,496,000 BTU / 1,000,000 = 41.496 MBTU.

Life cycle energy use (Eiot) for CV:

CV's life cycle energy use = (CV's annual energy consumption during operation) + (energy required to produce CV) = CV Ed + (100 million BTU).

Converting to MBTU: CV Eiot = CV Ed + (100 million BTU / 1,000,000) = 41.496 MBTU + 100,000 MBTU = 100,041.496 MBTU.

Rounding to 3 significant figures: CV Eiot = 100,000 MBTU.

End of life energy consumption (Eic) for CV:

Given that the end-of-life energy consumption for CV is 15% higher than AIV, we can calculate Eic for AIV first. Let's denote AIV's Eic as X.

X = CV Eiot × 1.15 = 100,000 MBTU × 1.15 = 115,000 MBTU.

Thus, CV's Eic = 115,000 MBTU.

Therefore, the answers are:

CV Eiot = 100,000 MBTU (CV's life cycle energy use).

AIV Eiot = 100,041.496 MBTU (AIV's life cycle energy use).

Since the CV has a lower end-of-life energy consumption (Eic) compared to AIV, the CV would have a lower life-cycle energy use.

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(b) Sea level rise is widely acknowledged to be a key consequence of climate change. The Ministry for the Environment (2015) projections are for around 0.7 m to 1.9 m of sea level rise by 2050 under RCP2.6 to RCP8.5.
(i) Briefly explain the two main mechanisms involved in sea level rise, and which one will dominate under the RCP8.5 scenario.
(ii) Sea walls (also know as "hard defences") are an engineering option preferred by some coastal human communities. What are the potential impacts on neighbouring communities of sea walls?

Answers

The two main mechanisms involved in sea level rise are thermal expansion and the melting of land-based ice. Hard defenses can provide protection against rising sea levels and coastal erosion for the communities located directly behind them, they can have potential impacts on neighboring communities.

As the Earth's oceans absorb heat from the atmosphere, the water expands thermally, leading to an increase in sea level.

Melting of land-based ice refers to the melting of glaciers and ice sheets, such as those in Greenland and Antarctica.

Under the RCP8.5 scenario, which represents a high greenhouse gas emissions trajectory, the dominant mechanism of sea level rise is expected to be the melting of land-based ice.

The increased temperature and subsequent accelerated melting of ice sheets and glaciers would contribute significantly to rising sea levels.

Hard defenses can provide protection against rising sea levels and coastal erosion for the communities located directly behind them, they can have potential impacts on neighboring communities.

Some of these impacts include Increased erosion, altered wave patterns, loss of coastal access, coastal squeeze, and visual and aesthetic impact.

It is essential to consider these potential impacts on neighboring communities when evaluating the suitability and long-term effects of implementing sea walls as coastal protection measures.

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A wooden cube, whose sides measure 2m, is dipped into water as shown in the diagram. Calculate the upthrust acted on it by water. [Ans: 1.57 x 104 N] 6m 2m Rectangular body Water .​

Answers

The upthrust on the wooden cube is 1.57 x 10⁴ N.

According to Archimedes' Principle, when an object is immersed in water, it displaces its own weight of water, resulting in an upward force, or upthrust, on the object.

When an object is fully immersed in a fluid, the upthrust on it is equal to the weight of the fluid displaced by the object.

The upthrust on a wooden cube with sides measuring 2m, which is immersed in water as shown in the figure, must be calculated. 6m 2m Rectangular body Water .

​[Figure]The density of water is 1000 kg/m³.

The mass of water displaced by the cube is equal to its volume multiplied by its density.

The volume of the cube can be calculated using the formula:

Volume of cube = Side x Side x Side

Using this formula, we get

Volume of cube = 2 x 2 x 2Volume of cube = 8 m³

Therefore, the mass of water displaced by the cube is

Mass = Density x Volume

Mass = 1000 kg/m³ x 8 m³Mass = 8000 kg

The weight of water displaced by the cube is

Weight = Mass x Gravity

Weight = 8000 kg x 9.81 N/kg

Weight = 78480 N

Therefore, the upthrust on the wooden cube is

Upthrust = Weight of water displaced

Upthrust = 78480 NUpthrust = 1.57 x 10⁴ N.

Therefore, the upthrust on the wooden cube is 1.57 x 10⁴ N.

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a capacitor charging circuit consists of a battery, an uncharged 20 μf capacitor, and a 4.2 kω resistor. at t = 0 s the switch is closed; 0.15 s later, the current is 0.54 ma . What is the battery's emf?

Answers

The battery's electromotive force (emf) in the capacitor charging circuit is approximately 9.49 volts.  This is calculated using the formula for the voltage across a capacitor as a function of time.

In a capacitor charging circuit, the voltage across the capacitor, Vc, is given by the equation:

Vc = V0 * (1 - e^(-t / RC))

Where:

V0 is the initial voltage across the capacitor (equal to the battery's emf)

t is the time elapsed since the switch was closed

R is the resistance in the circuit

C is the capacitance

Given information:

Capacitance (C) = 20 μF = 20 * 10^(-6) F

Resistance (R) = 4.2 kΩ = 4.2 * 10^(3) Ω

Time (t) = 0.15 s

Current (I) = 0.54 mA = 0.54 * 10^(-3) A

We can rearrange the equation to solve for the initial voltage across the capacitor:

V0 = Vc / (1 - e^(-t / RC))

Now, let's plug in the given values:

V0 = (I * R) / (1 - e^(-t / RC))

= (0.54 * 10^(-3) * 4.2 * 10^(3)) / (1 - e^(-0.15 / (4.2 * 10^(3) * 20 * 10^(-6))))

≈ 9.49 V

Therefore, the battery's electromotive force (emf) is approximately 9.49 volts.

The battery's electromotive force in the given capacitor charging circuit is approximately 9.49 volts. This is calculated using the formula for the voltage across a capacitor as a function of time. By substituting the given values of capacitance, resistance, time, and current into the equation, we find the initial voltage across the capacitor, which corresponds to the battery's emf.

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Which state gets nearly 100% of its electricity from renewable energy?

Answers

Answer:According to data compiled by the U.S. Energy Information Administration, there are seven countries already at, or very, near 100 percent renewable power: Iceland (100 percent)Paraguay (100)Costa Rica (99) Norway (98.5)Austria (80)Brazil (75)and Denmark (69.4)

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The rate at which the temperature increases with depth is called the geothermal gradient. What is the geothermal gradient in a tectonically stable region where the temperature is 119° C at a depth of 5.0 km?
(Assume a surface rock temperature of 14° C.)

Answers

The geothermal gradient in the tectonically stable region is approximately 21°C/km, indicating that the temperature increases by an average of 21 degrees Celsius per kilometer of depth.

To calculate the geothermal gradient, we need to find the rate at which the temperature increases with depth.

Temperature at the surface (T₁) = 14°C

Temperature at a depth of 5.0 km (T₂) = 119°C

Temperature difference = T₂ - T₁ = 119°C - 14°C = 105°C

Depth difference = 5.0 km - 0 km = 5.0 km

Geothermal gradient = Temperature difference / Depth difference

Geothermal gradient = 105°C / 5.0 km

Calculating this expression, we find:

Geothermal gradient ≈ 21°C/km

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How can athletes promote social
justice?

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ORLANDO, Fla. —

The NBA playoffs will pick up again this weekend after players made a powerful statement on Wednesday.

Athletes have a voice when it comes to change and demands for social justice. Their impact is extending off the court and into the world.

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"We stand with them, we support them and we're there for them," Michael-Carter Williams said.

The Orlando Magic's Michael Carter-Williams spoke Thursday about the Milwaukee Bucks' decision not to play Wednesday and instead, making a demand for the end to social injustice.

"We have a big platform that we can use to really make change in this country and we can go home to our communities and make change there," Carter-Williams said.

The Bucks' decision led to all NBA games being postponed Wednesday, some baseball games weren't played, as well as soccer, and the WNBA.

"This was a historic moment last night, we never had anything like that happen before," Dr. Richard Lapchick said.

Lapchick is a UCF professor who is also the president of the Institute for Sport and Social Justice.

He says the impact from Wednesday's boycott can't be overstated.

"The unity that occurred between the players and teams and leagues, was particularly impressive," Lapchick said. "The importance of what the players are doing, and what the country is doing in response, is looking at more than police brutality, it's looking at systemic racism."

"People are just tired of what's going on, there's no justice at all," Sandy Lallavee said.

Lallavee is one of the many residents we spoke to who supports the athletes' desire for a committed dialogue and effective change.

"I think it's the right thing to do right now, I support their decision and I think it's terrible what's happening in the world, in America," Gerrod Trytten said.

"It's a younger generation doing things and trying to make change, I respect them and I think they're doing the right thing," Nick Trapp said.

"They're showing their humanity, they're showing what they really care about in society," Lapchick said.

.Rearrange the following formula to solve for each variable: PV = nRT
a) P =
b) V =
c) n =
d) R =
e) T =

Answers

Explanation:

a. P = nRT/V

b. V= nRT/P

c. n = PV/RT

d. R= PV/nT

e. T = PV/nR

an athlete leaves one end of a pool of length at and arrives at the other end at time . she swims back and arrives at the starting position at time . if she is swimming initially in the positive direction, determine her average velocities symbolically in

Answers

Given that an athlete leaves one end of a pool of length at and arrives at the other end at time . She swims back and arrives at the starting position at time . If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.

The formula for average velocity is: Average velocity = displacement/time taken We know that the displacement is zero because the athlete returns to the starting point. Hence, the average velocity is zero in both the positive and negative directions. Mathematically, we can write it as: v _avg = 0 (in both directions)Therefore, the average velocities symbolically in both the positive and negative directions are zero.

an athlete leaves one end of a pool of length at and arrives at the other end at time . she swims back and arrives at the starting position at time . if she is swimming initially in the positive direction, determine her average velocities symbolically in the average velocities symbolically in both the positive and negative directions are zero. If she is swimming initially in the positive direction, we need to find her average velocities symbolically in positive and negative direction.

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A 3.5 kg block is pushed
along a horizontal floor by a force
of magnitude 15 N at an angle 403 with the horizontal
(Fig.). The coefficient of kinetic friction between the block
and the floor is 0.25. Calculate the
magnitudes of (a) the frictional
force on the block from the floor
and (b) the blocks acceleration.

Answers

The magnitude of the block's acceleration is approximately 2.41 m/s². To solve this problem, we'll break it down into several steps.

(a) Calculating the frictional force:

The frictional force can be determined using the equation:

frictional force ([tex]F_{friction[/tex]) = coefficient of friction (μ) * normal force (N)

The normal force (N) is equal to the weight of the block, which can be calculated using the equation:

weight (W) = mass (m) * acceleration due to gravity (g)

Given:

Mass of the block (m) = 3.5 kg

Coefficient of kinetic friction (μ) = 0.25

Angle with the horizontal (θ) = 40.3°

Force applied ([tex]F_{applied[/tex]) = 15 N

First, calculate the weight of the block:

W = m * g

W = 3.5 kg * 9.8 m/s²

W ≈ 34.3 N

Next, calculate the normal force:

N = W * cos(θ)

N = 34.3 N * cos(40.3°)

N ≈ 26.2 N

Finally, calculate the frictional force:

[tex]F_{friction[/tex] = μ * N

[tex]F_{friction[/tex] = 0.25 * 26.2 N

[tex]F_{friction[/tex] ≈ 6.55 N

Therefore, the magnitude of the frictional force on the block from the floor is approximately 6.55 N.

(b) Calculating the acceleration:

To find the acceleration of the block, we'll use Newton's second law:

[tex]F_{net[/tex] = m * a

The net force acting on the block is the applied force minus the frictional force:

[tex]F_ {net[/tex] = [tex]F_{applied[/tex] - [tex]F_{friction[/tex]

[tex]F_ {net[/tex] = 15 N - 6.55 N

[tex]F_ {net[/tex] ≈ 8.45 N

Now, we can calculate the acceleration:

a =[tex]F_ {net[/tex] / m

a = 8.45 N / 3.5 kg

a ≈ 2.41 m/s²

Therefore, the magnitude of the block's acceleration is approximately 2.41 m/s².

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i need help
i don’t understand how to do this question and i need it to be done by today

Answers

The characteristics of Elements include:

made of one type of atomrepresented by symbolscannot be broken down

Compounds:

made of two or more types of atomsrepresented by formulascan be chemically broken down

How to explain the information

Elements are substances that consist of only one type of atom. This means that all the atoms within an element are the same. Elements are represented by symbols, which are usually derived from their English or Latin names.

Compounds, on the other hand, are substances that are made up of two or more different types of atoms chemically combined together. Unlike elements, compounds have a definite chemical formula that represents the ratio of the atoms present in the compound. These formulas often use the symbols of the elements involved and indicate the number of atoms of each element present in the compound.

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how long will it take for the capacitor to lose half its initial stored energy?

Answers

The time it takes for a capacitor to lose half of its initial stored energy depends on the properties of the capacitor, specifically its capacitance and the resistance in the circuit. It can be determined using the time constant, which is the product of the resistance and capacitance.

The time constant, denoted by the symbol τ (tau), is equal to the product of the resistance (R) and the capacitance (C) in the circuit. It represents the time it takes for the capacitor to charge or discharge to approximately 63.2% of its final value. The equation for the time constant is given by τ = [tex]RC[/tex].

To calculate the time it takes for the capacitor to lose half its initial stored energy, we need to find the time when the capacitor discharges to 50% of its initial energy. Since energy is proportional to the square of the voltage across the capacitor, discharging to 50% of the initial energy corresponds to the voltage across the capacitor decreasing to approximately 70.7% of its initial voltage.

Using the time constant, we can calculate the time it takes for the capacitor to discharge to 70.7% of its initial voltage. This time is approximately 0.693 times the value of the time constant. Therefore, the time it takes for the capacitor to lose half its initial stored energy is approximately 0.693 times the time constant (0.693RC).

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any regularly repeated small feature can serve as a diffraction grating and separate light by color. which color gets deflected the most, and which the least?

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The color that gets deflected the most by a diffraction grating is blue, while the color that gets deflected the least is red.

When light passes through a diffraction grating, it undergoes interference and diffraction, resulting in the separation of colors. The amount of deflection or bending of light depends on the wavelength of the light. Shorter wavelengths (blues and violets) are deflected more than longer wavelengths (reds and oranges).

The reason for this lies in the fundamental principles of diffraction. Diffraction occurs when light encounters an obstacle or a periodic structure with features comparable to the wavelength of light. In a diffraction grating, these features are the regularly repeated small slits or grooves. When light passes through these slits, it diffracts into multiple beams, each corresponding to a different wavelength.

According to the equation for diffraction by a grating, the angle at which the different colors are diffracted depends on the wavelength of the light and the spacing between the slits. The equation, known as the grating equation, is given by:

nλ = d * sin(θ),

where n represents the order of diffraction, λ is the wavelength of light, d is the spacing between the slits, and θ is the angle of diffraction.

Since the equation involves the sine of the angle of diffraction, smaller wavelengths (such as blue and violet) will have larger angles of diffraction compared to longer wavelengths (such as red and orange). This means that blue and violet light will be deflected more than red and orange light.

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Convert centimeters to metre?

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Answer:1 cm=0.01

Explanation: Uu divide

100cm=1m
1cm=1/100m
1cm=0.01m
Hope you understand it.

an incident energy analysis results in 2.92 cal/cm2 at 18 inches working distance with an available fault current of 30 kiloamperes at 480 volts when protected by a circuit breaker with published clearing time of 0.05 seconds. if the protecting circuit breaker was not adequately maintained and during an actual arc flash incident opened in one second, what would the approximate actual incident energy be at 18 inches working distance?

Answers

An incident energy analysis assesses thermal energy during an arc flash incident. With the given data, the actual incident energy at an 18-inch distance is approximately 33.3 cal/cm².

An incident energy analysis is a crucial process that assesses the level of thermal energy generated during an arc flash incident. Incident energy analysis is performed to determine the amount of energy that may be delivered to a worker positioned near a specific electrical component or device. This information is required to make important decisions such as selecting personal protective equipment (PPE) and evaluating work methods. The formula for calculating incident energy in cal/cm² is: E= 4.184 * I * t * √t/d, where, E = Incident energy (cal/cm²), I = Current (amps), t = Time (seconds), d = Distance (inches). From the given data, incident energy at 18 inches working distance = 2.92 cal/cm², Fault current = 30 kA, Available Voltage = 480 V, Clearing Time = 0.05 seconds. We can calculate the initial value of t/d as: (30,000 A * 0.05 s) / (18 inches * 2.54 cm/inch) ≈ 96.57. The actual incident energy can be calculated using the formula: [tex]E_2 = E_1 * (t_2/d_2)^{(1.5)}[/tex], Where, [tex]E_1[/tex] = Initial incident energy, [tex]t_2[/tex] = New clearing time, [tex]d_2[/tex] = Distance = 18 inches = 45.72 cm. Plugging in the values, we get: [tex]E_2 = 2.92 * (1 s / 0.05 s)^{(1.5)} /[/tex] (45.72 cm / 2.54 cm/inch) [tex]\approx 33.3 cal/cm^2[/tex]Therefore, the approximate actual incident energy at an 18-inch working distance would be approximately 33.3 cal/cm².

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What is the velocity of an electron that has a de Broglie wavelength of 1 cm? a. 7.28 x 10-5 m/s b. 7.28 x 10-4 m/s c.)7.28 x 10-2 m/s d. 7.28 x 10 m/s

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The correct option is a)  7.28 x 10-5 m/s.

de Broglie wavelength, λ = 1 cm

de Broglie wavelength is given asλ = h/mv,

where h is Planck’s constant, m is the mass of the electron and v is the velocity of the electron.

Rearranging this equation, we get: v = h/mλ

Now substituting the values of h, m, and λ,

we get:v = (6.626 × 10⁻³⁴ J.s)/(9.109 × 10⁻³¹ kg)(1 × 10⁻² m)= 7.28 × 10⁻⁵ m/s

Hence, the velocity of an electron that has a de Broglie wavelength of 1 cm is 7.28 × 10⁻⁵ m/s, which is an option (a).

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The velocity of an electron that has a de Broglie wavelength of 1 cm is 7.28 x 10⁻² m/s.

option C is the correct answer.

What is the velocity of an electron?

The velocity of an electron that has a de Broglie wavelength of 1 cm is calculated as follows;

λ = h / mv

Where;

λ is the de Broglie wavelengthh is the Planck's constant m is the mass of the particlev is the velocity of the particle

mass of electron =  9.11 x 10⁻³¹ kg.

The velocity of an electron is calculated as;

v = h / (mλ)

v = (6.626 x 10⁻³⁴ J·s) / (9.11 x 10⁻³¹ kg x 0.01 m)

v = 7.28 x 10⁻² m/s

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Considering the closest stars, which stellar spectral type
(including luminosity class) is most common in the Sun's
neighborhood? Explain your reasoning.

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The most common stellar spectral type (including luminosity class) in the Sun's neighborhood is M-dwarfs.

In the Sun's neighborhood, M-dwarfs are the most common stellar spectral type. M-dwarfs are low-mass, cool stars that have a long lifespan. They make up a significant portion of the stellar population in our galaxy, comprising about 70% of all stars. Due to their smaller size and lower temperature, M-dwarfs emit less visible light and appear reddish in color.

Their abundance in the solar neighborhood is supported by various observational surveys and studies. Additionally, their long lifespan allows for the possibility of hosting potentially habitable planets, making them important targets in the search for extraterrestrial life.

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if the superball was in contact with the table for 30 ms, calculate the averrage force exerted on the ball by the table

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To calculate the average force exerted on the superball by the table, we need to know the change in momentum of the ball during the contact with the table. The average force exerted by the table on the ball is given by: Average force = (change in momentum) / (time of contact)We know that the time of contact is 30 ms.

Let's now calculate the change in momentum of the superball during the contact with the table. Change in momentum = Final momentum - Initial momentum During the contact, the superball experiences an impulse that changes its momentum. The impulse is given by the equation: Impulse = Force × Time of contact The impulse experienced by the ball during the contact is equal to the change in momentum of the ball. Therefore, we can use the impulse equation to calculate the change in momentum. We need to find the force exerted on the ball by the table. For this, we can use the following formula:

Force = (mass × acceleration)

Force = (mass × change in velocity) / (time of contact)

The mass of the superball is given as 0.005 kg.

Let's assume that the initial velocity of the ball is zero.

The final velocity of the ball is unknown. However, we can assume that the ball rebounds with the same speed as its initial velocity. Therefore, the change in velocity of the ball during the contact is:

Change in velocity = final velocity - initial velocity

Change in velocity = v - 0

Change in velocity = v

The change in momentum of the ball is equal to the product of its mass and the change in velocity:

Change in momentum = mass × change in velocity

Change in momentum = 0.005 kg × v

Change in momentum = 0.005v kg m/s

The time of contact is given as 30 ms. We need to convert it to seconds to be consistent with the units used in the formula:

Time of contact = 30 ms

= 0.03 s

Now, we can calculate the average force exerted on the ball by the table: Average force = (change in momentum) / (time of contact)

Average force = (0.005v kg m/s) / (0.03 s)

Average force = 0.1667v N

Therefore, the average force exerted on the superball by the table is given by the expression 0.1667v N.

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Put the following statements into logical order to explain why the moon recedes from Earth.

1. Conservation of angular momentum is preserved as rotational motion is transferred from.

2. The gravity of the moon tries to pull the tidal bulge back in line, generating friction against Earth's

3. Earth's rotation pushes the tidal bulges out in front of the line connecting the moon to Earth.

4. Tidal friction shows Earth's rotation rate; extra mass in tidal bulge pumps extra energy into the moon's orbit.

5. The presence of the moon raises tidal bulges on Earth along the line that connects the moon to Earth.

Answers

Logical order of statements to explain why the moon recedes from Earth:

Statement 5: The presence of the moon raises tidal bulges on Earth along the line that connects the moon to Earth.

Statement 3: Earth's rotation pushes the tidal bulges out in front of the line connecting the moon to Earth.

Statement 2: The gravity of the moon tries to pull the tidal bulge back in line, generating friction against Earth's surface.

Statement 4: Tidal friction shows Earth's rotation rate; extra mass in tidal bulge pumps extra energy into the moon's orbit.

Statement 1: Conservation of angular momentum is preserved as rotational motion is transferred from Earth to the moon, causing the moon to recede.

The presence of the moon exerts gravitational forces on Earth, causing tidal bulges to form. Statement 5 states that the presence of the moon raises tidal bulges on Earth along the line that connects the moon to Earth. As Earth rotates, the tidal bulges are pushed slightly ahead of the line connecting the moon and Earth, as mentioned in statement 3.

The gravity of the moon tries to pull the tidal bulge back in line, creating friction against Earth's surface, as stated in statement 2. This tidal friction is a result of the gravitational interaction between the moon and the tidal bulges. This friction slows down Earth's rotation over time.

As Earth loses rotational energy due to tidal friction, it transfers some of this rotational motion to the moon. This transfer of angular momentum causes the moon to gain energy and move into a higher orbit, leading to its recession from Earth. This process is described in statement 1, which refers to the conservation of angular momentum.

Additionally, the extra mass contained in the tidal bulges pumps extra energy into the moon's orbit, further contributing to its recession. This is explained in statement 4, which highlights that tidal friction shows Earth's rotation rate and pumps energy into the moon's orbit.

Overall, the combined effects of tidal bulges, gravitational forces, and the conservation of angular momentum result in the moon gradually receding from Earth over time.

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prove that the unit of area derived quantities are derived units​

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answer: derived physical quantities are those quantities that are obtained from the basic physical quantities by multiplication or division and area is one of them

A +5.0-μC point charge is placed at the 0 cm mark of a meter stick and a -4.0-μC charge is placed at the 50 cm mark. What is the (a) magnitude of the net electric field at the 30 cm mark? (b) direction of the net electric field at that point? (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C2)

Answers

(a) The magnitude of the net electric field at the 30 cm mark is approximately[tex]1.05 * 10^7 N/C.[/tex]

(b) The direction of the net electric field at that point is from the +5.0-μC charge towards the -4.0-μC charge.

To find the net electric field at the 30 cm mark, we need to consider the electric fields created by both charges and add them vectorially. The electric field created by a point charge can be calculated using the formula:

Electric field [tex](E) = k * (Q / r^2)[/tex]where k is the electrostatic constant [tex](k = 8.99 * 10^9 Nm^2/C^2[/tex]), Q is the charge, and r is the distance from the charge. For the +5.0-μC charge at the 0 cm mark, the electric field at the 30 cm mark is:

[tex]E1 = (8.99 * 10^9 Nm^2/C^2) * (5.0 * 10^{-6 }C) / (0.3 m)^2 = 5.93 * 10^6 N/C[/tex]

The electric field points towards the +5.0-μC charge. For the -4.0-μC charge at the 50 cm mark, the electric field at the 30 cm mark is:

[tex]E2 = (8.99 * 10^9 N m^2/C^2) * (-4.0 * 10^{-6} C) / (0.2 m)^2 = -2.82 * 10^7 N/C[/tex]

The electric field points towards the -4.0-μC charge. To find the net electric field at the 30 cm mark, we add the two electric fields:

[tex]Net electric field = E1 + E2 =5.93 * 10^6 N/C - 2.82 * 10^7 N/C = -1.05 * 10^7 N/C[/tex]

Therefore, the magnitude of the net electric field at the 30 cm mark is approximately [tex]1.05 * 10^7 N/C[/tex], and the direction is from the +5.0-μC charge towards the -4.0-μC charge.

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Net solar radiation: 510 W/m Air Temperature at 2 meters: 22.7°C
Air relative humidity at 2 meters: 80.0%
Ground surface temperature: 25.5°C
Air pressure: 980 millibars
Net radiation= 435 W/m
Evapotranspiration rate= 7.6 mm/day
e) If the "latent heat" later condenses in the
atmosphere, how much energy (in W m-2) will be released/
consumed? Specify whether the condensation corresponds to a
release or consumption of energy.

Answers

Net solar radiation: 510 W/m

Air Temperature at 2 meters: 22.7°C

Air relative humidity at 2 meters: 80.0%

Ground surface temperature: 25.5°C

Air pressure: 980 millibars

Net radiation= 435 W/m

Evapotranspiration rate= 7.6 mm/day

e) If the "latent heat" later condenses in the atmosphere, 220 W/m² energy will be released/consumed.

When water vapor condenses in the atmosphere, it releases energy in the form of latent heat. This process is known as condensation. The amount of energy released during condensation can be calculated using the following formula:

Energy released (W/m²) = Latent heat of vaporization (J/kg) × Condensation rate (kg/m²s)

To determine the energy released, we need to know the latent heat of vaporization and the condensation rate.

The latent heat of vaporization for water is approximately 2.5 × 10⁶ J/kg.

Given the evapotranspiration rate of 7.6 mm/day, we can convert it to kg/m²s:

Condensation rate (kg/m²s) = (7.6 mm/day) × (1 m/1000 mm) × (1 day/86400 s) = 8.80 × 10⁻⁸ kg/m²s

Now we can calculate the energy released:

Energy released = (2.5 × 10⁶J/kg) × (8.80 × 10⁻⁸ kg/m²s)

Energy released ≈ 220 W/m²

The energy released during condensation is approximately 220 W/m². This corresponds to the release of energy in the atmosphere.

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an insulating rod has a positive charge and is put on a table near an electroscope. the current on the rod is

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The current on the insulating rod, which carries a positive charge and is placed near an electroscope on a table, is zero. Insulating materials, such as the rod in question, do not allow the flow of electric charge or current through them. Therefore, despite the presence of a positive charge on the rod, there is no movement of charges to generate a current.

Insulating Rod: Insulating materials are those that do not easily conduct electricity. They have tightly bound electrons and do not allow the free movement of charges within them. In this scenario, the rod is made of an insulating material.Positive Charge: The insulating rod carries a positive charge. This means that it has an excess of positive charges (protons) compared to negative charges (electrons).Electroscope: An electroscope is a device used to detect the presence and magnitude of electric charge. It consists of a metal rod or plate connected to a metal leaf or needle.Current: Current refers to the flow of electric charge. In conductive materials, such as metals, the movement of electrons creates a flow of charges and results in the generation of electric current. However, insulating materials, like the rod in this scenario, do not allow the movement of charges, so no current is produced.Therefore, in the given situation, the current on the insulating rod is zero due to the nature of insulating materials, which prevent the flow of electric charges.

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