the random variable x has mean 8 and standard deviation 2. the random variable w is defined as w=7 4x . what are the mean and standard deviation of w ?

Answers

Answer 1

The random variable x's mean and standard deviation are 8 and 2, respectively. W=7+ 4x is the formula for the random variable w. The mean of w is E(W) =39

Explain about the Mean?

A dataset's mean is calculated by dividing the sum of all values by the total number of values. The term "average" is frequently used to describe it because it is the most widely used central tendency metric.

Divide the entire number of values by the total number of numbers to find the average. A mean is the term used to describe the mathematical average of a set of two or more data values. Average is also referred to as mean or arithmetic mean.

The mean is the average value of the data. It's easy to calculate: just add up all the numbers, then divide by the total number of numbers. Or, to put it another way, it is equal to the sum divided by the quantity.

The mean is then determined as follows:

E(W) = E (7 + 4X)

This results

E(W) = 7 + 4 E (X)

We thus have:

E(W) = 7 + 4 x 8

E(W) =39

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Answer 2

Standard deviation = 8 and mean = 39.

What is standard deviation?

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed over a wider range, a low standard deviation suggests that the values tend to be close to the mean (also known as the anticipated value) of the collection.

Given, the formula for mean is E(W) = 7 + 4(X)

∴ E(W) = 7 + 4E(X)

Mean, E(X) equals to 8, hence substituting in the above equation, we get,

E(W) = 7 + 4×8

⇒E(W) = 39

Since, E(W) = 7 + 4(X)

Var(W) = Var(7) + Var(4X)

Since, Var(constant)=0,

Var(W) = Var(4X)

Var(W) = 4²×Var(X), where Var(X)=σₓ²

⇒ Var(W) = 16×σₓ², where σₓ²=2²

⇒ Var(W) = 16×4

⇒ Var(W) = 64

Standard Deviation (SD) = √64 = 8

Thus, standard deviation = 8 and mean = 39.

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Related Questions

Question 9 An S corporation is generally set up to: a)implement an expansion strategy b)attract capital c)reduce tax burdens d)easy entry into an industry e)take advantage of limited liability

Answers

All of the above options a) implement an expansion strategy b)attract capital c)reduce tax burdens d)easy entry into an industry e)take advantage of limited liability ,are correct.

A corporation is generally set up to take advantage of limited liability. This means that the owners of the corporation (the shareholders) are not personally responsible for the debts and obligations of the corporation. The other options you have listed are also potential reasons for setting up a corporation, but they are not the primary purpose of a corporation.

An expansion strategy refers to a company's plan for growth and expansion, and setting up a corporation can be one way to implement this strategy. Attracting capital refers to the process of raising funds for a business, and a corporation may be able to attract more capital because it is a separate legal entity that can issue stocks and bonds. Reducing tax burdens refers to the process of minimizing the amount of taxes a business has to pay, and a corporation may be able to do this because it is taxed as a separate entity. Finally, setting up a corporation can also make it easier for a business to enter an industry because it provides a legal framework for the business and can make it easier to raise capital.

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Which term describes the red curve in the figure below?
A.
Circle
B.
Ellipse
C.
Parabola
D.
Hyperbola

Answers

Answer:

D

Step-by-step explanation:

A Hyperbola looks like a Parabola and its reflection, each Parabola curving opposite directions.

Answer:

D.  Hyperbola

Step-by-step explanation:

A conic is the intersection of a plane and a right circular cone.

Circle

Formed when a cone is intersected by a plane so that the plane is parallel to the circular base.

Ellipse

Formed when a cone is intersected by a plane so that the plane is at an angle with respect to the circular base.

Parabola

Formed when a cone is intersected by a plane so that the plane is parallel to an edge.

Hyperbola

Formed when a double-cone is intersected by a plane so that the plane is perpendicular to the circular bases.

help pls I am stuck math is over my head

Answers

Okay for 6. I’m going with D. It could be B. But I don’t know if there could be negative numbers so the one I’m sure could be the answer is D.
For 7. The answer is B.
For 8. The answer is C.
Hope this helps :)

Answer:

6. X, Y and Z are different numbers. X is a factor of Y. Z is a multiple of Y. Which of the following is DEFINITELY true?

B. Z is divisible by X

7. The following graph shows Vinit's journey as he cycled from his home to a park, 4 kilometers away in 800 seconds. Which of these can be said based on this graph?

B. He stopped at a place in between for 50 seconds,

8. How many TENS must be added to 7 000 to make it 70 000.

(70 000 - 7 000) / 10 = 6 300C. 6 300

Step-by-step explanation:

heart and star pls <3 brainliest will be appreciated <3(っ◔◡◔)っ  -{ elyna s }-

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with mass 2kg, the acceleration of the object is 26 m/s^2 If the same force acts upon another object whose mass is 13kg, what is this object's acceleration?

Answers

A ∝ 1/M

A = K/M

A is the acceleration and M is the mass of the object.

The object's acceleration for an object of mass 13 kg is 4 m/s²

What is an equation?

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4 = 8 is an equation.

We have,

When a constant force acts upon an object, the acceleration of the object varies inversely with its mass.

This means,

A ∝ 1/M

A is the acceleration and M is the mass of the object.

Now,

A = K/M

26 = K / 2

K = 26 x 2

k = 52

Now,

M = 13

A = K/M

A = 52/13

A = 4 m/s²

Thus,

The object's acceleration for an object of mass 13 kg is 4 m/s²

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an equation is written to represent the relationship between the temperature in alaska during a snow storm, y, as it relates to the time in hours, x, since the storm started. if the storm lasted five hours and the temperature saw a drop from 0o to - 20o, which quadrant(s) of a coordinate grid should be used to display this data?

Answers

The first and fourth quadrant of a coordinate grid should be used to display the given data .

In the question ,

it is given that ,

from the time the storm has started the temperature change is from 0° to - 20° .

we know that time cannot be in negative , and temperature can be both negative and positive .So only quadrant 1 and 4 can be used for representation .

Y = temperature

X = time

Quadrant 1 = (+x , +y) this can be used because x can only be positive and y is also positive.

Quadrant II = (-x , +y) this cannot be used because x cannot be negative

Quadrant III = (-x , -y) this cannot be used because x cannot be negative

Quadrant IV = (+x , -y) this can be used because x can only be positive and y can be negative.

Therefore , only 1 and 4 quadrants can be used .

The given question is incomplete , the complete question is

An equation is written to represent the relationship between the temperature in Alaska during a snow storm, y, as it relates to the time in hours, x, since the storm started. if the storm lasted five hours and the temperature saw a drop from 0° to - 20°, which quadrant(s) of a coordinate grid should be used to display this data ?

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A laundromat has a wash-and-fold service for a monthly fee of $26.00. The laundromat will wash and fold clothes at
$0.53 per pound for those customers with a laundry service. One customer paid $37.66 total for the month.
Which equation can be used to determine the pounds of laundry the customer brought in to be washed and folded that month?
OA. 26.00-0.53x = 37.66
OB. 0.53x + 37.66 = 26.00
OC. 37.66+26.00 = 0.53x
OD. 0.53x+26.00 = 37.66

Answers

The equation that can be used to determine the pounds of laundry the customer brought in to be washed and folded that month is;

D. 0.53x + 26.00 = 37.66

How to solve linear equation word problems?

We are given that;

Monthly service fee for Lundromat = $26

They wash and fold clothes at $0.53 per pound  for those customers with a laundry service.

Now, we are told that a customer paid $37.66 total for the month.

If the number of pounds of clothes is denoted as x, then it means that the equation for this will be;

0.53x + 26.00 = 37.66

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The perimeter is less than
or equal to 51 meters.
10 m
8m
8 m
10 m

Solve the inequality

Answers

Form the inequality. Remember, the perimeter is the sum of all sides.

(8•2)+(10•2)+x≤51

16+20+x≤51

36+x≤51

x≤51-36

x≤15

Therefore,

(8•2)+(10•2)+15≤51

16+20+15≤51

51≤51


Which of the rational numbers -5/16, -13/24, -3/4, -7/12 is the smallest?

Answers

-5/16 = -.3125
-13/24 = -.5417
-3/4 = -.75
-7/12 = .583

The answer is -5/16 :)

The smallest rational number among -5/16, -13/24, -3/4, and -7/12 is -3/4.

We have,

To determine the smallest rational number among -5/16, -13/24, -3/4, and -7/12, we need to compare their values.

Let's convert all the given rational numbers to have a common denominator of 48:

-5/16 = -15/48

-13/24 = -26/48

-3/4 = -36/48

-7/12 = -28/48

Now, the values of these rational numbers, when expressed with a common denominator, are:

-15/48, -26/48, -36/48, -28/48

Among these values, the smallest one is -36/48, which is equivalent to -3/4.

Therefore,

The smallest rational number among -5/16, -13/24, -3/4, and -7/12 is -3/4.

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Anne bought a television for 75% off she spent 24 dollars what was the original price

Answers

the original price was "x", which oddly enough is the 100%.

now, we know the TV is 75% off, that means the sale price is 100% - 75% = 25%, and we know that's 24 bucks.

[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x & 100\\ 24& 25 \end{array} \implies \cfrac{x}{24}~~=~~\cfrac{100}{25} \implies \cfrac{ x }{ 24 } ~~=~~ 4\implies x=96[/tex]

9. If f(1) = 8 and f(n)=1/2f(n-1) + 2 then which of the following is the value of f(3)
(1) 5
(2) 7
(3) 3
(4) 6
COMMON CORE ALGEBRA I, UNIT REVIEWS-UNIT #4
MATHINSTRUCTION, RED HOOK. NY 12571 ©2015

Answers

In the Algebra prompt above, If f(1) = 8 and f(n)=1/2f(n-1) + 2 then  the value of f(3) is 5.

What is Algebra?

Algebra is the branch of mathematics that aids in the representation of problems or situations using mathematical expressions.

We are given the following:

f(n)=1/2f(n-1) + 2; and

f(1) = 8

Thus,

f(2) = 1/2 x 8 + 2

= 4 + 2

f(2 )=  6

Hence,

f(3) = 1/2 x 6 + 2

= 3 + 2; thus,

f(3) = 5

Therefore,  it is correct to state that if f(1) = 8 and f(n)=1/2f(n-1) + 2 then  the value of f(3) is 5.

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The Big Top tent at the traveling circus has a cylindrical wall that is 30 feet tall and has a diameter of 72 feet. A steel pole in the center holds up the conical tent on top.

If the slant height of the conical tent (from the peak of the steel pole to the top of the edge of the cylindrical wall) is 45 feet, what is the total height of the steel pole?

Answers

Using Pythagoras theorem, the length of the pole is 57 feet

What is Pythagoras Theorem

Pythagoras theorem states that “In a right-angled triangle,  the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.

In this problem, assuming the pole runs down to the ground.

We can apply Pythagoras's theorem to find the height of the the conical roof.

Taking half the length of the the wall, i.e it's diameter = 72 /2 = 36ft

Using Pythagoras theorem;

45² = 36² + x²

x² = 45² - 36²

x² = 729

x = √729

x = 27 feet

The height of the conical roof is 27

The length of the pole = height of the conical roof + height of cylindrical wall

Length of pole = 27 + 30 = 57 ft

The length of the pole is 57ft

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The equation T^2 =A^3 shows the relationship between a planets orbital period, T , and the planets mean distance for the sun, A, is astronomical unit, AU. If planet Y is k times the mean distance from the sun as a planet X, by what factor is the orbital period increased

Answers

The increase in the orbital period is by a factor of k^3/2. Option D

What is the Kepler laws?

From the Kepler's laws, we know that the square of the period of the planet is directly proportional to the cube of the distance of the planet from the sun. We can see that this has been typified by the expression; T^2 =A^3 where T is the period of the planet and A is the distance between the planet and the sun.

Now, we can see that from the relationship, If planet Y is k times the mean distance from the sun as a planet X then the orbital period would be increased by a factor of about k^3/2.

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19. Select all tables that represent a proportional relationship between x and y.

Answers

From the given options, Option A and Option D will represent the proportionality relation between x and y.

The proportional relationship between 2 variables:

Equivalence between two variables that are related to one another and preserve a particular amount is referred to as a proportional relationship.

It is a mathematical concept that describes how two variables are related when they do so in equivalency and is also known as the "Relation of Proportionality."

Let the variables x and y are proportional to each other

=> x ∝ y

=> x = ky

=> x/y = k  [ where k is proportionality constant ]  

Here we will use the formula x/y = k to check the given variables' proportionality

Now check given options given below

Option A

x  0    1/5    2/5    3/5

y  0   1/10  2/10     3/10  

For  x = 1/5 and y = 1/10

=>  [tex]\frac{x}{y} = \frac{1}{5} \times \frac{10}{1}[/tex]  = 2

For  x = 2/5 and  y= 2/10

=>  [tex]\frac{x}{y} = \frac{2}{5} \times \frac{10}{2}[/tex]  = 2

Therefore, Table A represents the proportionality relation

Option B:

x -   0     1/2   1/3   1/4

y -   0     1/3   1/4   1/5

For  x = 1/2 and y = 1/3

=>  [tex]\frac{x}{y} = \frac{1}{2} \times \frac{3}{1}[/tex]  = 3/2

For  x = 1/3 and y = 1/4

=>  [tex]\frac{x}{y} = \frac{1}{3} \times \frac{4}{1}[/tex]  =  4/3  

Therefore, Table B doesn't represent the proportionality relation

Option C:

x -  0    1    3     5  

y -  0    1    9    25

For  x = 1 and y = 1

=>  [tex]\frac{x}{y} = \frac{1}{1} = 1[/tex]    

For  x = 3 and 9

=>  [tex]\frac{x}{y} = \frac{9}{3} = 3[/tex]  

Therefore, Table C doesn't represent the proportionality relation

Option D:

x -   0    1      3      4

y -   0    5    15    20

For  x = 1 and y = 5

=>  [tex]\frac{x}{y} = \frac{1}{5} = 1/5[/tex]    

For  x = 3 and y = 15

=>  [tex]\frac{x}{y} = \frac{3}{15} = \frac{1}{5}[/tex]  

Therefore, Table D will represent the proportionality relation

Therefore,

From the given options, Option A and Option D will represent the proportionality relation between x and y.

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A well-mixed cookie dough will produce cookies with a mean of 7 chocolate chips apiece. What is the probability of getting a cookie with no more than 4 chips? Round
your answer to four decimal places

Answers

Answer:

I have solved this on Paper and attached an image in the explanation part!

Step-by-step explanation:

If a shopkeeper made a profit of Rs100 by selling 10 pens, how much had the shopkeeper paid for buy one pen? ten pen =RS.1200​

Answers

Answer:

Rs. 110

Step-by-step explanation:

Details provided:Profit of Rs 100 by selling 10 pens.Selling price of 10 pens is Rs 1200.Solution:

Given,

No. of pens the shopkeeper has = 10

Selling price of 10 pens = Rs. 1200

Profit made by selling them = Rs 100

So,

Actual price or Cost price of 10 pens

= Rs (1200 - 100)

= Rs 1100

Now,

Cost price for each pen

= [tex]\frac{Total cost of the pens}{No. of pens}[/tex]

= [tex]Rs \frac{1100}{10}[/tex]

= Rs 110

Hence,

The cost price for each pen the shopkeeper bought is Rs. 110 (Ans)

A function of x is shown on the coordinate plane. Over which intervals is the function increasing ??

Quickest gets brainlest

Answers

Answer:

B

Step-by-step explanation:

The function is increasing anywhere the slope is positive.  This corresponds to the intervals -4<x<-2 and 0<x<2.  So, answer B is correct.

State whether True or False.
(a) All rectangles are squares
(b) All rhombuses are parallelograms
(c) All squares are rhombuses and also rectangles
(d) All squares are not parallelograms (e) All kites are rhombuses
(f) All rhombuses are kites (g) All parallelograms are trapeziums
(h) All squares are trapeziums

Answers

All rectangles are square is a false statement

The given statement is false statement.

What is a rectangle and square?

A rectangle is a quadrilateral with opposite sides parallel and equal and each angle is a right angle, where as a square is quadrilateral with opposite sides parallel and each side is equal. and every angle is a right angle.

We are given a statement All rectangle are squares.

As every side of a square is of equal length And only opposite sides are of equal length in rectangle

All rectangles are not square

Hence the statement is not true

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a non-for-profit consumer agency wanted to investigate the economic and humanitarian contribution of this country's pharmaceutical companies by sampling large companies and businesses of all types. it was decided to sample the pharmaceutical companies first. after surveying the pharmaceutical companies, someone at the consumer agency wanted to distribute the data early. what, if any, will be the most noticeable bias in distributing the survey at this point in time?

Answers

Under coverage of the population will be the most noticeable bias in distributing the survey at his point in time.

Undercoverage bias happens when segments of the target population are entirely executed or loses represented in the sample than they are in the population. This means that these segments are executes from the sampling process. Non response bias occurs when parts of the sampled population are unable or refuse to respond.

Undercoverage occurs when an element of the target population is not represented on the survey frame and therefore not given any chance of selection in the survey sample; that is the element has zero probability of selection into the sample. It refers to a type of sampling bias that occurs when a piece of information from your sample responses goes missing or uncovered in the results. This significant entity goes unselected or has zero chance of getting in your representing sample.

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The quadratic equation x2+20x+60=0
can be rewritten as the equation below, where p
and q
are constants.

(x−p)2=q


What is the value of p
?

Answers

By completing squares in the quadratic equation, we can see that the values of p and q are:

p = -10

q = 40

How to rewrite the quadratic equation?

Here we want to complete squares for the following quadratic equation:

x^2+20x+60=0

Remember that the perfect square trinomial is:

(a + b)^2 = a^2 + 2ab + b^2

So we can rewrite our equation as:

x^2 + 2*10*x + 60 = 0

If we add and subtract 10^2 = 100 we will get:

x^2 + 2*10*x + 10^2 - 10^2 + 60 = 0

(x^2 + 2*10*x + 100) - 100 + 60 = 0

(x + 10)^2 - 40 = 0

(x + 10)^2 = 40

So the value of p is p = -10 (the negative sign comes because in the given equation p is being subtracted) adnt he value of q is q = 40.

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Please help me!!!!!!!!!

Answers

The system of equations is:

28cm = 2*(W + L)

28.8cm = 2*(0.9*L + 1.2*W)

b) Solving that we will get L = cm and W = 6cm

c) The figure becomes a square of sides of 7.2cm

How to write the system of equations?

First, let's define the variables:

W = width of the rectangle.L = length of the rectangle.

Remember that the perimeter of a rectangle is:

P = 2*(W + L)

We know that the perimeter is 28cm, then:

28cm = 2*(W + L)

And if we decrease the length by 10% and increase the width by 20% the perimeter is 28.8cm, then

28.8cm = 2*(0.9*L + 1.2*W)

Then the system of equations is:

28cm = 2*(W + L)

28.8cm = 2*(0.9*L + 1.2*W)

We can isolate L on the first equation to get:

28cm/2 - W = L

14cm - W = L

Replacing that in the other equation we get:

28.8cm = 2*(0.9*(14cm - W) + 1.2*W)

28.8cm = 1.8*(14cm - W) + 2.4*W

28.8cm = 25.2cm + 0.6*W

28.8cm - 25.2cm =  0.6*W

3.6cm/0.6 = W = 6 cm

So the width is 6cm, then the length is:

L  = 14cm - 6cm = 8cm

c) The modified dimensions are:

0.9*L = 0.9*8cm = 7.2 cm

The new width is:

1.2*W = 1.2*6cm = 7.2 cm

So the length is equal to the width, then the figure becomes a square.

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find the percentage change of the first quantity with
reference to the second quantity: 480 units, 560 units.

Answers

The percentage change of the first quantity with reference to the second quantity: 480 units, 560 units is: -14.29%.

How to find the percentage change?

First step is to find the difference between the two numbers

Difference = New Number - Original Number

Difference =  480 -560

Decrease  = -80

Now let find the percentage change

Percentage change = Decrease  / Original Number × 100

Percentage change = -80 /560 × 100

Percentage change = -14.29%

Therefore we can conclude that the percentage change is -14.29%.

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Pls help me limited time i’ll give brainliest

Answers

Answer:

2.4 would be the answer i took this before

Step-by-step explanation:

Which statements are true? Select all that apply.
A) The equation |-x - 4| = 8 will have two solutions.
B) The equation 3.4|0.5x - 42.1| = -20.6 will have one solution.
C) The equation |1/2x - 3/4| = 0 will have no solutions.
D) The equation |2x - 10| = -20 will have two solutions.
E) The equation |0.5x - 0.75| + 4.6 = 0.25 will have no solutions.
F) The equation |1/8x - 1| = 5 will have infinitely many solutions.

Answers

Answer:

The following statements are true:

A) The equation |-x - 4| = 8 will have two solutions.

D) The equation |2x - 10| = -20 will have two solutions.

E) The equation |0.5x - 0.75| + 4.6 = 0.25 will have no solutions.

The other statements are not true. The equation 3.4|0.5x - 42.1| = -20.6 will not have one solution, as the absolute value of a number cannot be negative. The equation |1/2x - 3/4| = 0 will not have no solutions, as the absolute value of a number cannot be zero. The equation |1/8x - 1| = 5 will not have infinitely many solutions, as the absolute value of a number cannot be negative.

Step-by-step explanation:

A middle school is having a fundraiser. Edwin wants to buy two candles for $5.95 each, three cans of candy for $2.50 each, and an ornament for $7.95.

Answers

Answer:

$27.35

Step-by-step explanation:

To solve this, we just set up an equation based on the situation given:

2 candles for 5.95 each would be (2 x 5.95)

3 cans of candy for 2.50 each would be (3 x 2.50)

1 ornament for 7.95 would just be 7.95

(2 x 5.95) + (3 x 2.50) + 7.95 = total cost

   11.90     +     7.50     + 7.95 = total cost

                $27.35 = total cost

Please help,100 points will give the brainiest.
Given the equation, 3x2 + 4x – 2 = 0, calculate the discriminant and determine the number and nature of the solutions.

1.d = 40; 2 irrational
2.d = 40; 2 rational
3.d = −8; 2 complex

Answers

Answer:

1.   d = 40; 2 irrational

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Discriminant}\\\\$b^2-4ac$ \quad when $ax^2+bx+c=0$\\\\when $b^2-4ac > 0 \implies$ two real solutions.\\when $b^2-4ac=0 \implies$ one real solution.\\when $b^2-4ac < 0 \implies$ no real solutions.\\\end{minipage}}[/tex]

Given quadratic equation:

[tex]3x^2+4x-2=0[/tex]

Therefore:

a = 3b = 4c = -2

Substitute the values of a, b and c into the discriminant formula:

[tex]\begin{aligned}\implies b^2-4ac&=(4)^2-4(3)(-2)\\&=16-12(-2)\\&=16+24\\&=40\end{aligned}[/tex]

Therefore, as d = 40 and 40 > 0:

[tex]\implies b^2 - 4ac > 0 \implies \text{two real solutions}.[/tex]

To determine if the solutions are irrational or rational, simply square root the discriminant.

[tex]\implies \sqrt{d}=\sqrt{40}=2 \sqrt{10}[/tex]

As the discriminant is not a perfect square, then its square root is irrational and so the solutions of the quadratic equation are irrational.

solve each of these equations. explain or show your reasoning.

2(x+5)=3x+1


3y-4=6-2y

3(n+2)=9(6-n)

Answers

Answer: n = 4

9 = x

y = 2

Step-by-step explanation:

2 ( x + 5 ) = 3x + 1

2x +10 = 3x + 1

10 = 1x + 1

- 1       -1

9 = 1x

9 = x

3y - 4 = 6 - 2y

5y -4 =6

5y = 10

y = 2

3 (n + 2) = 9 ( 6-n)

3n + 6 = 54 -9n

3n +9n = 54 - 6

12n =54 -6

12n =48

n = 4

What is the volume of the figure below if a = 9 units and b = 7 units?
A.
760.5 cubic units
B.
1,296 cubic units
C.
1,012.5 cubic units
D.
364.5 cubic units

Answers

Base (cube): [tex]V=s^3[/tex]

   [tex]V=9\cdot9\cdot9=729[/tex]

Top (triangular prism): [tex]V=\frac{1}{2}bhl[/tex]

   [tex]V = \frac{1}{2}(9\cdot7)\cdot9=283.5[/tex]

Together:

   [tex]V = 729+283.5 =1012.5[/tex]

C.

1012.5 cubic units.

if a snowball melts so that its surface area decreases at a rate of 1cm2/min1cm2/min, find the rate at which the diameter decreases when the diameter is 10cm10cm.

Answers

The rate at which the diameter decreases is  -0.16cm/min

Diameter:

In geometry, diameter refers the straight line that goes from one side to the other side of a circle, passing through the center.

Given,

Here we need to find if a snowball melts so that its surface area decreases at a rate of 1cm^2/min, find the rate at which the diameter decreases when the diameter is 10 cm. Finish solving the problem. Write an equation that relates the quantities.

Here  we obtained the equation that relates the surface area S and the diameter D of a sphere given by

=> S = πD²

Now, we have differentiate the equation as,

=> dS/dt = d/dt (πD²)

=> dS/dt = π d/dt (D²)

​=> dS/dt = 2πD dD/dt

Now, Solving for dD/dt, which is the unknown for this problem, we have

=> dD/dt ​= 1/2πD​ x dS​/dt

Now, substituting the given values, the rate of change of the diameter when D=10 cm and dS/dt as (-1) is

=> dD/dt = 1/2 x π x 10 (-1)

=> dD/dt = -1/20π

=> dD/dt = -0.16cm/min

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ec question 14: t distributions homeworkunanswereddue today, 11:59 pm which of the following statements are true regarding the t distribution. select all that apply. multiple answers: multiple answers are accepted for this question select one or more answers and submit. for keyboard navigation...show more a the t distribution is left-skewed. b the t distribution is right-skewed. c the t distribution is symmetric. d the t distribution is defined by its degrees of freedom. e the t distribution is equivalent to the normal distribution. f as the degrees of freedom of a t distribution increase it approaches a standard normal distribution g a distribution is used for testing the population mean when the population standard deviation is known. h a distribution is used for testing the population mean when the population standard deviation is unknown.

Answers

The standardized distribution known as the T distribution is a member of the one-parameter family. The degrees of freedom are the only input for the t distribution.

What is population variances?

A measure of the distribution of a set of data points is called population variance. It measures the mean squared departure from the mean, specifically. As a result, the variance will be minimal if all of the data points are very near to the mean. The variation will be high if the data points are dispersed throughout a wide range.

The standardized distribution known as the T distribution is a member of the one-parameter family. The degrees of freedom are the only input for the t distribution. Because sample size is used to assess this degree of freedom, degrees of freedom are dependent on sample size.

The t distribution tends to follow a normal distribution as sample size rises. The degree of freedom is ultimately determined by the sample size, so as the degree of freedom rises, the t distribution tends to be a normal distribution.

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how many possible 5 card poker hands with at least 3 aces can be dealt from a standard deck of 52 cards?

Answers

There are 6 probability  5 card poker hands with at least 3 Aces that can be dealt from a standard deck of 52 cards.

A standard deck of 52 cards contains 4 Aces, so the maximum number of Aces that can be dealt in a 5 card hand is 3. To determine the number of possible 5 card poker hands with at least 3 Aces, we must first consider the different combinations of 3 Aces in a 5 card hand. There are 6 possible combinations: AAAxx, AAxxA, AxxAA, xAAAX, xAxxA, and xxAAA. This means that there are 6 possible 5 card poker hands with at least 3 Aces that can be dealt from a standard deck of 52 cards. To calculate this, we first counted the number of Aces in the deck and then calculated the number of possible combinations of 3 Aces in a 5 card hand. Finally, we multiplied this number by the number of remaining cards in the deck (48) to get the total number of possible hands.

4 Aces x 6 combinations = 24

24 x 48 remaining cards = 1,152

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