the rate constant of a certain first order reaction is 45.9s^-1 at 300k. what is the value of the rate constant at 310.0 k? the energy of activation is 81.0 kj/mol?

This ratio shows that to prepare a buffer with a pH of 4.42 using formic acid, you require the ratio of [sodium formates]/[formic acid] to be 49.23:1.

Explanation:

To prepare a buffer with a pH of 4.42 using formic acid, you need to determine the ratio of [sodium formate]/[formic acid].

A buffer solution is a solution that can resist changes in pH, even when subjected to acid or base. The buffer solution comprises a weak acid or a weak base with its conjugate base or acid, respectively.

Suppose you want to prepare a buffer with a pH of 4.42 using formic acid, with a Ka of 1.8x10^-4. Find the ratio of [sodium format]/[formic acid]. Here, we can use the Henderson-Hasselbalch equation, which is:

pH = pKa + log ([A-] / [HA])

Here, [A-] represents the conjugate base concentration, and

[HA] represents the weak acid concentration.

Rearranging the above equation gives:

log([A-]/[HA]) = pH - pKa putting values gives:

log([A-]/[HA]) = 4.42 - (-log 1.8x10^-4) lo([A-]/[HA]) = 4.42 + 3.74log([A-]/[HA]) = 8.16log([A-]/[HA]) = 1.74                                                                        

Now, taking antilog of both sides: [A-]/[HA] = 10^1.74[A-]/[HA] = 49.23:1

This ratio shows that to prepare a buffer with a pH of 4.42 using formic acid, you require the ratio of [sodium formate]/ [formic acid] to be 49.23:1.

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This herd of cattle released 8.44 metric tons of methane (CH4) into the atmosphere. Methane is composed of one atom of carbon and four atoms of hydrogen, so this 8.44 metric tons of methane contained (8,440 kg) x (12.01/16.05) g/kg = 6,309 kg (6.31 metric tons).

To answer the given question, we need to know the molecular formula of methane, which is CH4. The atomic mass of carbon is 12.01 g/mol and the atomic mass of hydrogen is 1.01 g/mol. Therefore, the molecular mass of methane is:

Molecular mass of CH4 = (1 x 12.01) + (4 x 1.01) = 16.05 g/mol
Now, we need to convert the amount of methane released into metric tons.
1 metric ton = 1,000 kg
8.44 metric tons = 8.44 x 1,000 = 8,440 kg

To convert the mass of methane into mass of carbon, we need to use the ratio of the molecular masses of carbon and methane.

1 mol of CH4 contains 1 mol of carbon
1 mol of CH4 has a mass of 16.05 g
1 mol of carbon has a mass of 12.01 g

Therefore,
16.05 g of CH4 contains 12.01 g of carbon
1 kg of CH4 contains (12.01/16.05) g of carbon

To convert the mass of methane into mass of carbon, we need to multiply it by the ratio of the molecular masses of carbon and methane.
Mass of carbon = (8,440 kg) x (12.01/16.05) g/kg
= 6,309 kg

Therefore, the herd of cattle released 6,309 kg (or 6.31 metric tons) of carbon into the atmosphere through the release of 8.44 metric tons of methane.

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The true statements about the rate-limiting step in a reaction are it is the slowest step and it limits (or determines) the rate of the reaction. Therefore, option A is correct.

The rate-limiting step is the step in a reaction that has the highest activation energy and therefore proceeds at the slowest rate. It sets the overall rate of the reaction because the other steps in the reaction cannot occur faster than the rate of the rate-limiting step.

However, the rate law of the reaction is determined by the slowest elementary step, which may or may not be the rate-limiting step.

The rate-limiting step is not always the first step in a reaction. It can be any step in the reaction mechanism.

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 The combined gas law equation to get the new temperature when the gas volume decreases from 800 ml to 400 ml: P1 * V1 / T1 equals P2 * V2 / T2.

800 ml is the initial volume (V1). The original temperature is converted to Kelvin using the formula T1 (in Kelvin) = T1 (in Celsius) + 273.15 T1 = 115°C + 273.15 = 388.15 K

T2 = (V2 * T1) / V1,

T2 = (400 ml * 388.15 K) / 800 ml

T2 = 194.075 K

As a result, the new temperature is roughly 194.075 K when the gas volume is reduced to 400 ml.

Thus, The combined gas law equation to get the new temperature when the gas volume decreases from 800 ml to 400 ml: P1 * V1 / T1 equals P2 * V2 / T2.

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The type of chemical reaction that occurs when natural gas is burned is exothermic.

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The carbohydrates that cannot be hydrolyzed to give smaller molecules are monosaccharides or simple sugars.

Monosaccharides are the simplest form of carbohydrates and are not composed of smaller sugar molecules, making them indivisible. They are the building blocks of carbohydrates, and they have the general formula (CH2O)n. They are classified according to the number of carbon atoms they contain, such as trioses, pentoses, and hexoses. Examples of monosaccharides are glucose, fructose, and galactose.

Monosaccharides are important in the body's metabolic processes, particularly in the production of energy. complex molecules are broken down into glucose, which the body uses for energy. Glucose is the primary fuel for the brain, red blood cells, and other organs. However, if glucose levels are too high, it can cause damage to organs and other tissues, which is why insulin helps regulate the amount of glucose in the blood.

Therefore, monosaccharides are important nutrients for the body's proper functioning, and they cannot be broken down into smaller molecules.

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The most abundant isotope of boron found in nature is 11B. This isotope makes up approximately 80% of all boron atoms, while the other isotope 10B makes up the other 20%.

Boron is a chemical element with the symbol B and atomic number 5. Boron has two naturally occurring isotopes, 10B and 11B. Boron-11 is the most abundant of the two isotopes with an abundance of 80.1%.Boron-10 is a stable isotope of boron that accounts for 19.9% of the Earth's naturally occurring boron. The isotope has an atomic mass of 10.012937u or 10.013u.A neutron makes the difference between the isotopes of boron, which has an atomic number of 5. Boron-10 contains five protons and five neutrons, whereas boron-11 has six neutrons in addition to the five protons.

The mass number of boron-10 is ten since it contains ten particles in total (5 protons + 5 neutrons). "Boron is composed of two naturally occurring isotopes, 10B and 11B.  is the isotope boron-11 (11B) is the most abundant in nature with an abundance of 80.1%.

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Answer:

The reaction will reach equilibrium faster.

Explanation:

just took this lesson

A cholesterol sample is prepared using acetyl CoA molecules in which both the methyl group and the carboxyl functional group of the acetyl are radiolabeled with 14c. In the cholesterol product, the 14C label would appear in the acetate component.

Cholesterol is a waxy substance that your liver produces and is found in animal-based foods. Cholesterol is crucial for the functioning of your body. It helps your body produce hormones, vitamin D, and bile acids, which aid in the digestion of fat. However, having too much of it in your blood raises your risk of heart disease and stroke. 14C is a radiolabeled carbon isotope. Isotopes are variants of the same element that have a different number of neutrons. Carbon-14 (14C) is an isotope of carbon that has 6 protons and 8 neutrons in its nucleus. In the cholesterol product, the 14C label would appear in the acetate component.

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The objective of measuring the freezing point of a solution of your compound is: to determine its purity or concentration.

When a compound is dissolved in a solvent, the freezing point of the resulting solution is lower than that of the pure solvent. This is because the solute molecules lower the freezing point of the solvent by interfering with the formation of the crystal lattice. The extent of the depression of the freezing point depends on the concentration of the solute and its nature.

To measure the freezing point of a solution of your compound, the solution is cooled until it begins to solidify. The temperature at which this occurs is recorded as the freezing point of the solution. By comparing the freezing point of the solution with the freezing point of the pure solvent, the concentration or purity of the solute can be calculated using the freezing point depression equation:

ΔTf = Kf · m,

where ΔTf is the freezing point depression, Kf is the freezing point depression constant, and m is the molality of the solute in the solution.

The freezing point depression constant is a property of the solvent and is typically provided in reference tables. Once the molality of the solute is determined, the molar mass or weight percent of the solute can be calculated, allowing for the determination of the purity or concentration of the compound.

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A cell must keep a similar concentration of dissolved substances with the fluid surrounding them because it helps in maintaining homeostasis.

Homeostasis is the ability of the body to regulate its internal environment in order to maintain a stable, constant condition. For example, the body regulates temperature, blood sugar levels, pH levels, and other factors to maintain a stable internal environment.

When there is an imbalance in the concentration of dissolved substances between the cell and its surrounding fluid, the cell is at risk of losing or gaining too much water. This can cause the cell to swell or shrink, which can interfere with its normal functions.

To maintain homeostasis, the cell needs to regulate the movement of substances across its membrane in response to changes in the concentration of dissolved substances in the surrounding fluid. By doing so, the cell can maintain a stable internal environment and function properly.

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Answer:

This is just a quick tip.

Explanation:

An electric current is the movement of particles, starting at the moment when an external voltage is applied at one of the ends of the conductor. That, in turn, generates an electric field on the negatively charged electrons that are attracted to the positive terminal of the external voltage.

Acrylic acid, whose formula is CH₂=CHCOOH, has a pKa of 4.76.

This means that in a 0.76 m aqueous solution of acrylic acid, the majority of the acid will exist in its undissociated (protonated) form, with a pH of 2.19. This indicates that the solution is very acidic and the hydrogen ion concentration is very high.

Acrylic acid has a pKa of 4.76, which means that at a pH of 4.76, the acid will exist in a 1:1 ratio of its protonated (undissociated) and deprotonated (dissociated) forms.

In a 0.76 m aqueous solution of acrylic acid, the majority of the acid will exist in its undissociated form, which means that the hydrogen ion concentration is very high and the solution is very acidic with a pH of 2.19.

The presence of the hydrogen ion concentration allows the acid to be used in the manufacture of plastics.

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Answer: 15.0667

Explanation:

Pure toluene (c7h8) has a normal boiling point of 110.60oc. A solution of 7.80 g of anthracene (c14h10), in 100.0 g. toluene has a boiling point of 112.06oc. The molality of the solution is 0.438 mol/kg. and the molal boiling point elevation constant for Toluene is 3.33 °C/m.

Given that,

Molecular weight of Toluene, C7H8 = 92 g/mol

Molecular weight of Anthracene, C14H10 = 178 g/mol

Boiling point of pure Toluene, Tb° = 110.6°C

Boiling point of Toluene solution containing Anthracene, Tb = 112.06°C

We need to find the molality of the solution and the molal boiling point elevation constant for Toluene.

Molality of the solution:

Molality is defined as the number of moles of solute per kilogram of solvent.

(Here, the solvent is Toluene and the solute is Anthracene.) Number of moles of Anthracene,

n2 = Weight of Anthracene / Molecular weight of Anthracene = 7.80 g / 178 g/mol = 0.0438 moles

Number of kilograms of solvent,

w1 = Weight of Toluene / 1000 = 100.0 g / 1000 = 0.1 kg

Molality of solution, m = n2 / w1 = 0.0438 / 0.1 = 0.438 mol/kg

Therefore, the molality of the solution is 0.438 mol/kg.

Molal boiling point elevation constant for Toluene:

The elevation in the boiling point of the solvent is given by the formula:

ΔTb = Kb . m . i

where Kb is the molal boiling point elevation constant. m is the molality of the solution. i is the van't Hoff factor (which is equal to 1 for non-electrolytes like Anthracene)

ΔTb = Tb - Tb°= 112.06°C - 110.6°C = 1.46°C

We know that m = 0.438 mol/kg

Hence,1.46 = Kb . 0.438 . 1Kb = 3.33 °C/m

Therefore, the molal boiling point elevation constant for Toluene is 3.33 °C/m.

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The new volume of the gas is approximately 29.5 L when the temperature is raised to 350K and the pressure is lowered to 1.5 atm.

To solve this problem, we can use the combined gas law, which states that,

(P1 × V1) / T1 = (P2 × V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

We can plug in the given values to get,

(2.3 atm × 17 L) / 299 K = (1.5 atm × V2) / 350 K

Solving for V2,

V2 = (2.3 atm × 17 L × 350 K) / (1.5 atm × 299 K)

V2 = 29.5 L

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In the "Reactions" section of your Pre-lab notebook, you should have two reaction schemes involving the alkene. The correct answer is option d.

The Pre-lab notebook is a collection of worksheets and pre-lab assignments that students must finish before lab. This may include preparing solutions, making graphs, filling out data tables, or writing lab reports.A pre-lab notebook is a place where students may record and evaluate their work before and during a laboratory session. It is a document that is kept by the student and used to help them comprehend the material that is presented to them.

The Pre-lab notebook is divided into three sections: the Procedures section, the Data section, and the Reactions section. An alkene is a hydrocarbon that contains a carbon-carbon double bond. Alkenes are typically unsaturated and highly reactive. Alkenes are used in a variety of industries, including the production of plastics, synthetic rubbers, and fibers. Alkenes are also used as solvents in many applications.

They are known for their ability to react with a variety of other compounds. This will ensure you cover a range of possible reactions and provide a comprehensive understanding of the alkene's behavior in different situations.

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1)  moles Al : moles of HCl

        2        :     6

simplifying the ratio;

        1         :    3

2)  [tex]HCl : AlCl_{3}[/tex]

      6    :  2

       3   :  1

3)  [tex]Al : AlCl_{3}[/tex]

     2 : 2

      1 : 1

4) [tex]HCl : H_{2}[/tex]

     6    :  3

      2   :  1

5) [tex]HCl : H_{2}[/tex]

      2   :  1

       6  :  x

x = 6/2

x = 3 moles

6) [tex]HCl : H_{2}[/tex]

      2   :  1

      12  :  x

x = 12/2

x = 6 moles

7) [tex]HCl : H_{2}[/tex]

     2   :  1

      3   :  x

x = 3/2 moles

The original pressure of gas is 4 atm for given volume of 30 liters . This is taken out by boyle law.

Boyle's law is an experimental gas law that specifies the relationship between pressure and volume of a confined gas. It is also known as the Boyle-Mariotte law or Mariotte's law (particularly in France). Boyle's law states that the absolute pressure exerted by a given mass of an ideal gas is inversely proportional to the volume it occupies within a closed system if the temperature and amount of gas remain constant.According to Boyle's Law, while the temperature of a given mass of confined gas remains constant, the product of its pressure and volume remains constant as well. When comparing the same substance under two sets of conditions

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The percent yield of the reaction is 80.6%. The actual yield is the amount of product actually obtained from the reaction, usually measured in grams or moles

What is Percentage Yield?

Percentage yield is a measure of the efficiency of a chemical reaction, and it represents the proportion of the actual yield of a product obtained from the reaction compared to the theoretical yield .

The stoichiometry of the sodium borohydride reduction of a ketone like camphor is as follows:

2 R₂C=O + NaBH₄ + 3 H₂O → 2 R₂CHOH + NaBO₂ + 4 H₂

From the balanced equation, we can see that 1 mole of sodium borohydride (NaBH₄) reacts with 2 moles of ketone (R₂C=O). Therefore, the theoretical absolute minimum number of molar equivalents of sodium borohydride required for the reduction is 1 equivalent per mole of ketone.

However, in practice, it is often necessary to use an excess of reducing agent to ensure complete reduction of the ketone. In the question, it is stated that the recommended amount is 5.2 molar equivalents based on past experience.

To calculate the percent yield of the reaction, we need to know the amount of product obtained and the theoretical yield of the product. The theoretical yield is the maximum amount of product that can be obtained based on the amount of limiting reagent used. In this case, the limiting reagent is the ketone, and the theoretical yield can be calculated as follows:

moles of ketone used = (mass of ketone used) / (molar mass of ketone)

theoretical yield of product = 2 x moles of ketone used

Once the actual yield of the product is obtained, the percent yield can be calculated using the formula:

For example, if we use 2 grams of camphor (molar mass 152.23 g/mol) and obtain 1.5 grams of the reduced product, the calculations would be:

moles of camphor used = 2 g / 152.23 g/mol = 0.0131 mol

theoretical yield of product = 2 x 0.0131 mol = 0.0262 mol

% yield = (1.5 g / (0.0262 mol x 88.15 g/mol)) x 100% = 80.6%

Therefore, the percent yield of the reaction is 80.6%.

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It is about to vaporize does not describe the saturated liquid if heat is added to it. Here option B is the correct answer.

A saturated liquid is a liquid that is in equilibrium with its vapor at a given temperature and pressure. If heat is added to a saturated liquid, its temperature will increase while its pressure remains constant until it reaches the saturation temperature. At this point, the saturated liquid will start to vaporize or boil, and the temperature will remain constant until all of the liquid has been converted to vapor.

Option A - "it's about to condense" - is true for a saturated vapor if heat is removed from it. Option C - "it refers to a point on a t-v diagram" - is also true since a saturated liquid corresponds to a point on the liquid-vapor saturation line on a temperature-volume (t-v) diagram.

Option D - "it's still considered a liquid" - is true since the saturated liquid is still in the liquid state even though it is about to vaporize. Option E - "any heat added will cause some of the liquid to vaporize" - is true since any additional heat added to a saturated liquid will cause it to vaporize or boil at a constant temperature and pressure.

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Complete question:

Which of the following statement does not describe the saturated liquid if heat is added to it? multiple choice questions.

A - it's about to condense.

B - it is about to vaporize.

C - it refers to a point on a t-v diagram.

D - it's still considered a liquid.

E - any heat added will cause some of the liquid to vaporize.

The total pressure in a 2 L flask that contains 5.33 g of Ne and 13.40 g of Ar at 38°C is 5.20 atm.


To calculate the total pressure, you must use the ideal gas law equation: PV = nRT, where P is pressure, V is volume, n is the amount of gas (in moles), R is the gas constant, and T is temperature in Kelvin.

You must first convert the temperature from Celsius to Kelvin (38°C = 311.15 K). Next, you must convert the mass of each gas into moles (5.33 g Ne = 0.01502 mol, 13.40 g Ar = 0.2225 mol).

Finally, you can calculate the total pressure (P = (0.01502 mol Ne + 0.2225 mol Ar) * 0.08206 L atm K⁻¹ mol⁻¹ * 311.15 K/ (2 L) = 5.20 atm).

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To get a 30% solution of sulfuric acid, 4 oz of a 35% solution of sulfuric acid (and distilled water) must be mixed with 20 oz of a 20% solution of sulfuric acid.

A solution is a homogeneous mixture of two or more substances. For instance, two or more gases, or a gas and a solid, or a liquid and a solid, or two or more liquids could be mixed to create a solution.

First, determine the volume of sulfuric acid in each solution, then combine them to obtain the total amount of sulfuric acid. Solve the equation based on the sulfuric acid content in the final solution.

The volume of sulfuric acid in 35% solution is:

35% = 35/100

      = 0.35

V1 = volume of 35% solution of sulfuric acid and distilled water

V1 = 0.35 x V1

Suppose V2 is the volume of 20% solution of sulfuric acid, then

20% = 20/100

       = 0.2

V2 = volume of 20% solution of sulfuric acid

V2 = 0.2 x 20 oz

    = 4 oz

Let's combine the two solutions.

Total volume is (V1 + V2) ounces,

and the amount of sulfuric acid is 0.35V1 + 0.2V2 ounces.

The volume of sulfuric acid in the final mixture is:

30% = 30/100

        = 0.3

V1 + V2 = total volume

0.35V1 + 0.2V2 = total sulfuric acid volume

(0.3 x (V1 + V2)) = 0.35V1 + 0.2V2

V1 + V2 = 40

V1 = 4 oz

Substitute the value of V1 in the equation

V1 + V2 = 40(4 oz) + V2

             = 40 V2

              = 36 oz

To solve this problem, we can use the concept of the concentration of a solution, which is given by the amount of solute (in this case sulfuric acid) divided by the total amount of solution (sulfuric acid and water) multiplied by 100.

Or

Let x be the number of ounces of the 35% solution of sulfuric acid needed to make a 30% solution. We know that we have 20 ounces of a 20% solution. We can set up an equation based on the concentration of the sulfuric acid in the two solutions:

(0.35x + 0.20(20)) / (x + 20) = 0.30

Simplifying this equation, we get:

0.35x + 4 = 0.30x + 6

0.05x = 2

x = 40

Therefore, we need 40 ounces of the 35% solution of sulfuric acid to mix with the 20 ounces of the 20% solution to obtain a 30% solution.

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The radius of a silver atom is approximately 1.44 Å.. In a face-centered cubic unit cell, each atom is surrounded by 12 atoms located at the corners of the unit cell and 6 atoms located at the center of each face.

The atoms usually touch across the diagonal of the face, which is equal to the diameter of the atom. For a silver atom in a face-centered cubic unit cell, the density is 10.5 g/cm3. Using the formula for the density, we can calculate the volume of a unit cell: density = mass / volume,

[tex]volume = mass / density = (107.87 g/mol) / (10.5 g/cm3) = 10.27 cm3/mol[/tex]

[tex]volume of a unit cell = (4 * radius^{3}) / 3[/tex]

[tex]radius = [(3 * volume of a unit cell) / (4 * pi)]^{(1/3)} = [(3 * 10.27 cm3/mol) / (4 * pi)]^{(1/3)} = 1.44 \angstroms (angstroms)[/tex]

Therefore, the radius of a silver atom in a face-centered cubic unit cell is approximately 1.44 Å.

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The increased distance across the cell will result in an increase absorbance reading.

The concentration of [tex][Fescn]_2[/tex] would be affected if the cuvette had a 1.5 cm path length rather than the 1.0 cm value used.Since the absorbance of a sample is proportional to the concentration of a sample (as described by the Beer-Lambert law), increasing the path length of the cuvette would result in a decrease in absorbance. This means that the concentration of the sample would be lower than if the 1 cm path length was used. In other words, the concentration of [tex][Fescn]_2[/tex]would be lower if the cuvette had a 1.5 cm path length than if it had a 1.0 cm path length.

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In order to ensure that 900 mL of 1/3 strength solution is delivered over 8 hours via a nasogastric tube, you must add 300 mL of water to the 1/3 strength solution.

This will give a total volume of 1.2 L, which when divided by 8 hours, equals 150 mL per hour.

Use the formula for calculating dilution, which is: Final Volume / Concentration = Amount of Solvent to be Added.

We are given the Final Volume, which is 900 mL, and the Concentration, which is 1/3 strength. We can calculate the Amount of Solvent (in this case, water) to be Added :

900 mL / (1/3) = 2700 mL

The amount of water needed to be added to the 1/3 strength solution to achieve 900 mL of 1/3 strength is 2700 mL.

However, since the total volume of the solution must not exceed 1.2 L, only 300 mL of water must be added to the 1/3 strength solution,

giving us a total volume of 1.2 L when the 900 mL of 1/3 strength is taken into consideration.

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The half-life of the reaction with an initial concentration of 0.050 m is 16.9 minutes,

which is longer than the half-life of 10.0 minutes when the initial concentration was 0.250 m.

The half-life of a second-order reaction depends on the initial reactant concentration.

When the initial concentration of a reactant is higher, the half-life of the reaction will be shorter; when the initial concentration of a reactant is lower, the half-life of the reaction will be longer.

Therefore, if a second-order reaction has a half-life of 10.0 minutes when the initial reactant concentration is 0.250 m, the half-life when the initial concentration is 0.050 m would be longer than 10.0 minutes.

To determine the exact half-life of the reaction with the lower initial concentration, we can use the integrated rate law for a second-order reaction:

ln[A]t = -kt + ln[A]0

In this equation, A

is the initial concentration of the reactant; and k is the reaction rate constant.

The half-life of the reaction with an initial concentration of 0.050 m, we can rearrange the equation to solve for t, the time in which the reactant concentration decreases to half of the initial concentration:

t = -(1/k) ln[0.5A0]

The initial concentration of 0.050 m, solve for t to get the half-life of the reaction with the lower initial concentration:

t = -(1/k) ln[0.5(0.050)] = 16.9 minutes

Therefore, the half-life of the reaction with an initial concentration of 0.050 m is 16.9 minutes, which is longer than the half-life of 10.0 minutes when the initial concentration was 0.250 m.

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The physical method that can separate a mixture of steel ball bearings and marbles is sorting.

The process of separating the components of a mixture is referred to as separation. A mixture of steel ball bearings and marbles can be separated using the sorting method. .Sorting is a process of separating components of a mixture by hand.

Steel ball bearings and marbles can be sorted based on their appearance, size, and weight. The process of sorting is the simplest method of separation that does not require any special tools or equipment. Hence, the physical method that can separate a mixture of steel ball bearings and marbles is sorting.

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Answer:

It’s D sorting

Explanation:

I got it correct duh

NADH is produced during the catabolic reactions of glycolysis, the Krebs cycle, and oxidative phosphorylation in the mitochondria.

NADH (Nicotinamide adenine dinucleotide) is an important molecule involved in cellular respiration and energy production. The production of NADH is dependent on the availability of oxygen and glucose, which serve as electron acceptors in these metabolic pathways.

However, under anaerobic conditions where oxygen is limited or unavailable, such as during intense exercise or in some microorganisms, NADH production may still occur through fermentation pathways. In these pathways, pyruvate is converted to lactate or ethanol, regenerating NAD+ to allow for further ATP production through glycolysis.

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Stoichiometric balance of a combustion reaction. A stoichiometric balance of a combustion reaction must demonstrate conservation of mass, but not conservation of moles because stoichiometry of a chemical reaction is based on the number of atoms and molecules, but not their masses or volumes.

Conservation of mass is a fundamental principle of physics and chemistry which says that in a closed system, mass cannot be created or destroyed, but only transformed from one form to another. In other words, the total mass of the reactants must be equal to the total mass of the products in a chemical reaction, regardless of the masses or volumes of the individual molecules involved.

On the other hand, conservation of moles refers to the fact that in a balanced chemical equation, the number of moles of each reactant and product is equal. However, since different molecules have different masses, conservation of moles does not necessarily imply conservation of mass.

For example, if one mole of oxygen reacts with one mole of hydrogen to form one mole of water, the number of moles of each substance is conserved, but the mass is not, since the mass of water is greater than the combined mass of oxygen and hydrogen.

The stoichiometric balance of a combustion reaction must demonstrate conservation of mass because the reactants and products involved in combustion reactions are typically gases or liquids that can be easily measured by volume or weight.

Since the number of atoms and molecules involved in the reaction is fixed by the stoichiometry of the equation, the conservation of mass principle ensures that the mass of the reactants is equal to the mass of the products, even if the masses or volumes of individual molecules differ.

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