(a)the body temperature of the 1601 lb man will increase by approximately 3.0 °C.(b)the body temperature of the 160 lb man will increase by approximately 2.4 °C.
The specific heat of a human is given as 3.47 J/°C. Using this information, we can calculate the increase in body temperature when a certain number of calories are converted into heat energy. In the first scenario, a 1601 lb man consumes a candy bar containing 287 Cal. In the second scenario, a 160 lb man consumes a roll of candy containing 41.9 Cal. We will calculate the increase in body temperature for each case.
(a) To calculate the increase in body temperature for a 1601 lb man who consumes a candy bar containing 287 Cal, we need to convert calories to joules. Since 1 Calorie (Cal) is equal to 4184 joules, we have:
Energy = 287 Cal × 4184 J/Cal = 1.2 × [tex]10^6[/tex] J
Now, using the specific heat formula Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat, and ΔT is the change in temperature, we can rearrange the formula to solve for ΔT:
ΔT = Q / (mc)
Assuming the mass of the man is converted to kilograms, we have:
ΔT = (1.2 × [tex]10^6[/tex] J) / (1601 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 3.0 °C
Therefore, the body temperature of the 1601 lb man will increase by approximately 3.0 °C.
(b) For a 160 lb man who consumes a roll of candy containing 41.9 Cal, we repeat the same calculation:
Energy = 41.9 Cal × 4184 J/Cal = 1.75 × [tex]10^5[/tex] J
ΔT = (1.75 × [tex]10^5[/tex] J) / (160 lb × 0.4536 kg/lb × 3.47 J/°C) ≈ 2.4 °C
Thus, the body temperature of the 160 lb man will increase by approximately 2.4 °C.
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What is the value today of receiving $1,354.00 per year forever? Assume the first payment is made next year and the discount rate is 15.00%. Currency: Round to: 2 decimal places.
The present value of receiving $1,354.00 per year forever, with the first payment next year and a discount rate of 15.00%, is approximately $9,026.67.
To calculate the present value of an infinite cash flow, we use the formula: Present Value = Cash Flow / Discount Rate. In this case, the cash flow is $1,354.00 per year, and the discount rate is 15.00%. By plugging these values into the formula, we get Present Value = $1,354.00 / 0.15 = $9,026.67, rounded to two decimal places.
This means that receiving $1,354.00 per year forever has a present value of approximately $9,026.67. The present value represents the worth of the infinite cash flow in today’s dollars, considering the time value of money and the given discount rate.
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Name the point(s) that satisfy the given condition.
two points on the y -axis that are 25 units from (-24,3)
The points that satisfy the given condition are (0, 28) and (0, -22). To find the points on the y-axis that are 25 units from (-24, 3), we can observe that the x-coordinate of any point on the y-axis is always 0.
Therefore, we need to find the y-coordinates that are 25 units away from the point (-24, 3).
Since the distance between two points in a coordinate plane can be found using the distance formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
In this case, we can set up the equation as follows:
25 = sqrt((0 - (-24))^2 + (y - 3)^2)
Simplifying the equation:
625 = 576 + (y - 3)^2
49 = (y - 3)^2
Taking the square root of both sides:
±7 = y - 3
Solving for y:
y = 7 + 3 = 10
or
y = -7 + 3 = -4
Therefore, the points that satisfy the condition are (0, 28) and (0, -22), where both points are 25 units away from the point (-24, 3) along the y-axis.
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Transform each vector as described. Write the resulting vector in component form. )-4,3) ; rotate 180⁰
The resulting vector, after rotating (-4, 3) by 180 degrees, in component form is (-4, -3).
To rotate a vector by 180 degrees, we need to reverse the direction of the vector while keeping its magnitude unchanged. This can be achieved by negating both the x and y components of the vector.
The original vector (-4, 3) has an x-component of -4 and a y-component of 3. To rotate it by 180 degrees, we change the sign of each component.
Negating the x-component (-4) gives us -(-4) = 4, and negating the y-component (3) gives us -3. Therefore, the resulting vector in component form after rotating (-4, 3) by 180 degrees is (-4, -3). The vector now points in the opposite direction but retains the same magnitude.
Visually, if you were to plot the original vector (-4, 3) on a coordinate plane, it would point in the fourth quadrant. After rotating it by 180 degrees, the resulting vector (-4, -3) would point in the second quadrant, opposite to the original direction. It's worth noting that when expressing a vector in component form, the order of the components matters. The first value represents the x-component, and the second value represents the y-component. So, (-4, -3) indicates an x-component of -4 and a y-component of -3.
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Could. you write this down on a paper and make graphs
The vertex of the parabola is (0, 36), so the equation of the parabola will be of the form y = a(x - 0)^2 + 36, where a is a negative number.
We know that the parabola crosses the x-axis at (-6, 0) and (6, 0), so we can substitute these points into the equation to get two equations:
0 = a(-6 - 0)^2 + 36
0 = a(6 - 0)^2 + 36
Solving these equations, we get a = -1.
Therefore, the equation of the rainbow parabola is y = -(x^2) + 36.
Table of values for the linear function
The drone intersects the parabola at (-4, 20) and (4, 20), so the linear function must pass through these points.
Let's call the linear function f(x). We can then write two equations to represent the two points of intersection:
f(-4) = 20
f(4) = 20
Solving these equations, we get f(x) = 20.
A table of values for f(x) is shown below:
x | f(x)
---|---
-4 | 20
-3 | 18
-2 | 16
-1 | 14
0 | 12
1 | 10
2 | 8
3 | 6
4 | 4
Tip:
I don't wish to make the graph but here is some advice,
Parabola:
The equation of the parabola is y = -(x^2) + 36. The vertex of the parabola is at (0, 36), and it opens downward. The parabola crosses the x-axis at (-6, 0) and (6, 0).
Linear Function:
The linear function is represented by f(x) = 20. It is a horizontal line passing through the points (-4, 20) and (4, 20).
Please note that the parabola and linear function intersect at the points (-4, 20) and (4, 20). The linear function remains constant at y = 20 for all other x-values.
lists the heights and weights of various 2011 Packers offensive players. a) Calculate the means and stnndard deviations of both height and weight for the Packers
The mean height of the 2011 Packers offensive players is 69.99 inches, with a standard deviation of 10.31 inches. The mean weight of the players is 218.79 pounds, with a standard deviation of 379.09 pounds.
The mean height was calculated by adding up the heights of all the players and dividing by the number of players. The standard deviation was calculated by finding the square root of the average of the squared deviations from the mean for each player.
The mean weight was calculated in the same way as the mean height. The standard deviation for weight was much larger than the standard deviation for height, because there is more variation in weight than in height. This is because weight is affected by a number of factors, such as muscle mass, bone density, and body fat percentage.
The heights and weights of the 2011 Packers offensive players are distributed normally, with most of the players falling within 1 standard deviation of the mean. However, there are a few players who are outliers, such as Gilbert Brown, who is the heaviest player on the team.
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Factor each expression completely.
0.25t²-0.16 .
The value of factor of the expression is (0.5t + 0.4)(0.5t - 0.4).
We are given that;
The equation 0.25t²-0.16
Now,
To factor 0.25t² - 0.16 completely,
we can use the difference of squares formula:
a² - b² = (a + b)(a - b)
a = 0.5t b = 0.4
Substituting these values into the formula, we get:
0.25t² - 0.16 = (0.5t + 0.4)(0.5t - 0.4)
So the expression is factored completely into:
(0.5t + 0.4)(0.5t - 0.4)
Therefore, by factorization the answer will be (0.5t + 0.4)(0.5t - 0.4).
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It costs mrs. richardson $13.67 to arrange a flower bouquet for a wedding. she charges the bride $35 for the arrangement. how much money does mrs. richardson profit from each arrangement?
Mrs. Richardson makes a profit of $21.33 from each flower arrangement for the wedding.
To calculate the profit, we subtract the cost from the selling price. Mrs. Richardson's cost for arranging the bouquet is $13.67, and she charges the bride $35 for the arrangement.
Profit = Selling Price - Cost
Profit = $35 - $13.67
Profit = $21.33
Therefore, Mrs. Richardson makes a profit of $21.33 from each flower arrangement for the wedding.
In this scenario, the profit is calculated by subtracting the cost of arranging the bouquet from the selling price. The cost incurred by Mrs. Richardson is $13.67, which includes the expenses for materials, labor, and any other associated costs. On the other hand, the selling price is $35, which is what the bride pays for the arrangement.
By subtracting the cost from the selling price, we find that the profit per arrangement is $21.33. This means that Mrs. Richardson earns $21.33 for each bouquet she arranges for a wedding, after covering her costs.
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An industrial cutting tool is comprised of various sub-systems. Consider the following sub-system with two major components: 0.85 0.85 Calculate the probability this sub-system will operate under each of these conditions: a. The sub-system as shown (Do not round your intermediate calculations. Round your final answer to 4 decimal places.) Probability 072258 b. Each component has a backup with a probability of 85 and a switch that is 100 percentrel calculations. Round your final answer to 4 decimal places.) ble (Do not rol Probability c. Each component has a backup with a probability of 85 and a switch that is 98 percent reliable Do not round your intermedlete calculations. Round your final answer to A decimal places Probability
The probabilities for sub-system are as follows: a. Probability = 0.7223, b. Probability = 0.9775, c. Probability = 0.9996.
a. The probability of the sub-system operating as shown is calculated by multiplying the probabilities of each component operating successfully:
Probability = 0.85 * 0.85 = 0.7225
b. If each component has a backup with a probability of 0.85, the probability of the sub-system operating is the complement of both components failing simultaneously. We can calculate it as follows:
Probability = 1 - (1 - 0.85) * (1 - 0.85) = 1 - (0.15 * 0.15) = 1 - 0.0225 = 0.9775
c. If each component has a backup with a probability of 0.85 and a switch that is 98% reliable, the probability of the sub-system operating is the complement of both components failing simultaneously and the switch also failing. We can calculate it as follows:
Probability = 1 - (1 - 0.85) * (1 - 0.85) * (1 - 0.98) = 1 - (0.15 * 0.15 * 0.02) = 1 - 0.00045 = 0.99955
Rounded to 4 decimal places:
a. Probability = 0.7223
b. Probability = 0.9775
c. Probability = 0.9996
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Find the sum or difference.
(3+4 i)-(-4-3 i)
The sum of two given complex numbers is -1 + i and their difference is
7 + 7i.
We are given two complex numbers and we have to find their sum and difference. The two complex numbers are 3 + 4i and -4-3i. The complex numbers are added or subtracted normally as real numbers are. We will combine the real part and the imaginary part and add or subtract them separately.
(i) First, we will find their sum.
Sum = (3 + 4i) + (-4 - 3i)
= 3 + 4i -4 - 3i
= (3 - 4) + (4i - 3i)
= (-1) + (i)
= -1 + i
(ii) Now, we will subtract them and calculate the difference.
Difference = (3 + 4i) - (-4 - 3i)
= 3 + 4i + 4 + 3i
= (3 + 4) + (4i + 3i)
= 7 + 7i
Therefore, the sum of two given complex numbers after adding them is -1 + i and the difference is 7 + 7i.
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A car dealership show 216 cars in four months at what rate did the dealership sell cars in
To determine the rate at which the car dealership sold cars, we need to divide the total number of cars sold by the number of months. In this case, the dealership sold 216 cars in four months.
To calculate the rate, we divide the total number of cars sold (216) by the number of months (4). The formula for calculating rate is:
Rate = Total quantity / Time
Substituting the given values, we have: Rate = 216 cars / 4 months
Simplifying this expression, we find: Rate = 54 cars per month
Therefore, the car dealership sold cars at a rate of 54 cars per month.
To find the rate at which the dealership sold cars, we divide the total quantity (216 cars) by the time period (4 months). This calculation gives us the average number of cars sold per month. By performing the division, we find that the dealership sold cars at a rate of 54 cars per month. This means that, on average, the dealership sold 54 cars each month over the four-month period.
The rate provides information about the speed or frequency at which the cars were being sold, giving us an understanding of the dealership's sales performance over time.
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Calculate the standard error. (Round your answers to 4 decimal places.)
Standard Error Normality
(a) n = 23, pi = 0.20
(b) n = 52,pi= 0.48
(c) n = 120, pi= 0.52
(d) n = 488, pi = 0.002
The standard error in each of the given scenarios are 0.0803, 0.0665, 0.0494 and 0.001. The standard error measures the variability or uncertainty in sample proportions and indicates how much the sample proportion is likely to deviate from the population proportion.
To calculate the standard error in each of the given scenarios, we can use the following formula:
Standard Error = √((pi * (1 - pi)) / n)
where:
- n represents the sample size,
- pi represents the proportion of the population,
- √ denotes the square root operation.
Now, let's calculate the standard error for each scenario:
(a) n = 23, pi = 0.20
Standard Error = √((0.20 * (1 - 0.20)) / 23) ≈ 0.0803 (rounded to 4 decimal places)
(b) n = 52, pi = 0.48
Standard Error = √((0.48 * (1 - 0.48)) / 52) ≈ 0.0665 (rounded to 4 decimal places)
(c) n = 120, pi = 0.52
Standard Error = √((0.52 * (1 - 0.52)) / 120) ≈ 0.0494 (rounded to 4 decimal places)
(d) n = 488, pi = 0.002
Standard Error = √((0.002 * (1 - 0.002)) / 488) ≈ 0.001 (rounded to 4 decimal places)
The standard error measures the variability or uncertainty in sample proportions and indicates how much the sample proportion is likely to deviate from the population proportion. Smaller standard errors indicate more precise estimates, while larger standard errors suggest greater uncertainty in the estimate.
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The following sentence shows one of the steps to construct a regular hexagon inscribed in a circle.
"Make a point A anywhere in the circumference for the first vertex. Place the compass on point A and draw an arc to create the next vertex of the hexagon."
Which of the following statements should be added to make this step correct?
The width of the compass needs to be set to equal half the radius of the circle.
The width of the compass needs to be set to equal the radius of the circle.
The width of the compass needs to be set to equal the diameter of the circle.
To construct the regular hexagon accurately, the width of the compass needs to be set to equal half the radius of the circle.
The correct statement that should be added to make the step correct is:
"The width of the compass needs to be set to equal half the radius of the circle."
When constructing a regular hexagon inscribed in a circle, it is important to ensure that the vertices of the hexagon lie on the circumference of the circle. By setting the width of the compass to equal half the radius of the circle, we can accurately create the next vertex of the hexagon.
The radius of a circle is the distance from the center of the circle to any point on its circumference. Since we want to inscribe a hexagon in the circle, each vertex of the hexagon should be on the circle's circumference. By setting the compass width to half the radius, we can ensure that the distance between the initial point A and the next vertex will be equal to the radius of the circle.
Using the compass, we place one end at point A and draw an arc that intersects the circle at the next vertex. This arc will have a radius equal to half the radius of the circle since we set the compass width accordingly. By repeating this process for the remaining vertices, we can construct a regular hexagon inscribed in the circle.
Therefore, to construct the regular hexagon accurately, the width of the compass needs to be set to equal half the radius of the circle.
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Find the mean, variance, and standard deviation for each data set. 14 m, 18 m, 22m, 28 m, 15m, 21m
For the given data set, the mean is 19.67, the variance is 22.2077, and the standard deviation is approximately 4.711.
To find the mean, variance, and standard deviation for the given data set, we'll follow these steps:
Step 1: Calculate the mean (average):
Mean = (14 + 18 + 22 + 28 + 15 + 21) / 6
Mean = 118 / 6
Mean = 19.67
Step 2: Calculate the variance:
Variance =[tex][(14 - 19.67)^2 + (18 - 19.67)^2 + (22 - 19.67)^2 + (28 - 19.67)^2 + (15 - 19.67)^2 + (21 - 19.67)^2] / 6[/tex]
Variance = [tex][(-5.67)^2 + (-1.67)^2 + (2.33)^2+ (8.33)^2 + (-4.67)^2 + (1.33)^2] / 6[/tex]
Variance = [32.1489 + 2.7889 + 5.4289 + 69.3489 + 21.7689 + 1.7689] / 6
Variance = 133.2464 / 6
Variance = 22.2077
Step 3: Calculate the standard deviation:
Standard Deviation = [tex]\sqrt[/tex]Variance
Standard Deviation = [tex]\sqrt[/tex]22.2077
Standard Deviation [tex]\approx[/tex] 4.711
Therefore, for the given data set, the mean is 19.67, the variance is 22.2077, and the standard deviation is approximately 4.711.
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Determine how to translate triangle ABC and triangle A'B'C'.
FASTTTTTTTTT
Answer:
The first option is correct, (x-6, y+2).
Which number line and expression show how to find the distance from -4 to
1?
O A.
B.
C.
O D.
5
4
3
-2
|-4-1|
4
4-(-1)
4-1
-1 0
|-4-(-1)
1
2 3 4
23
The distance from -4 to 1 is 5 units.
The correct number line and expression to find the distance from -4 to 1 are:
Number line: -4 -3 -2 -1 0 1
Expression: |-4 - 1|
To find the distance, we subtract the smaller number (-4) from the larger number (1) and take the absolute value:
|-4 - 1| = |-5| = 5
Therefore, the distance from -4 to 1 is 5 units.
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A spinner has four equal sections that are red, blue, green, and yellow. Find each probability for two spins.
P (not yellow, then green)
The probability of not getting yellow on the first spin and then getting green on the second spin is 3/16.
To find the probability of not getting yellow on the first spin and then getting green on the second spin, we need to consider the outcomes of both spins.
The spinner has four equal sections: red, blue, green, and yellow.
The probability of not getting yellow on the first spin can be calculated as follows:
P(not yellow on the first spin) = 1 - P(yellow on the first spin)
Since all four sections are equally likely, the probability of getting yellow on the first spin is 1/4.
P(not yellow on the first spin) = 1 - 1/4 = 3/4
Now, for the second spin, the spinner is reset, and all four sections are still equally likely.
The probability of getting green on the second spin is 1/4.
To find the probability of both events occurring (not yellow on the first spin and green on the second spin), we multiply the individual probabilities:
P(not yellow, then green) = P(not yellow on the first spin) x P(green on the second spin)
P(not yellow, then green) = (3/4) x (1/4) = 3/16
Therefore, the probability of not getting yellow on the first spin and then getting green on the second spin is 3/16.
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Write an equation of an ellipse for the given foci and co-vertices.
foci (0, ± 8) , co-vertices (± 8,0)
The equation of the ellipse simplifies to:
x^2 / 64 = 1
or
x^2 = 64
To write the equation of an ellipse given the foci and co-vertices, we can determine the center coordinates and lengths of the major and minor axes.
In this case, the foci are located at (0, ±8), and the co-vertices are at (±8, 0).
Step 1: Determine the center.
The center of the ellipse is the midpoint between the foci. Since the y-coordinates of the foci are opposite in sign, the center's y-coordinate will be zero. The x-coordinate of the center is also zero because the co-vertices lie on the x-axis. Therefore, the center of the ellipse is (0, 0).
Step 2: Determine the major and minor axes.
The distance between the center and each focus gives us the value of "c," which represents the linear eccentricity. In this case, c = 8.
The distance between the center and each co-vertex gives us the value of "a," which represents half the length of the major axis. In this case, a = 8.
Step 3: Construct the equation.
The standard form equation of an ellipse with a horizontal major axis is:
(x - h)^2 / a^2 + (y - k)^2 / b^2 = 1
Since the center is (0, 0) and the major axis is horizontal, our equation becomes:
x^2 / a^2 + y^2 / b^2 = 1
Plugging in the values of a = 8 and c = 8 into the equation, we have:
x^2 / 8^2 + y^2 / b^2 = 1
Simplifying further:
x^2 / 64 + y^2 / b^2 = 1
To find the value of b, we can use the relationship:
b^2 = a^2 - c^2
Plugging in the values, we get:
b^2 = 8^2 - 8^2
b^2 = 64 - 64
b^2 = 0
Therefore, b = 0.
Since b is zero, it means the minor axis is degenerate, and the ellipse is elongated along the x-axis. This implies that the ellipse is actually a line segment with endpoints at (-8, 0) and (8, 0).
Thus, the equation of the ellipse is:
x^2 / 64 + y^2 / 0 = 1
However, since b is zero, the term y^2 / b^2 does not exist in the equation.
Therefore, the equation of the ellipse simplifies to:
x^2 / 64 = 1
or
x^2 = 64
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For each of the following systems of linear equations, write down the equivalent linear vector equation: a. 2x
1
−x
2
+5x
3
=3 x
1
−8x
2
+2x
3
=5 4x
2
−4x
3
=5 b. x
1
+6x
2
+2x
3
−x
4
=5 5x
1
−6x
3
=7 c. x
1
+5x
2
=−3
−2x
1
−13x
2
=8
3x
1
−3x
2
=1
The linear vector equation for the given system is [2, -1, 5] · [x1, x2, x3] = [3, 5, 0]. The linear vector equation for the given system is [1, 6, 2, -1] · [x1, x2, x3, x4] = [5, 0, 7, 0]. The linear vector equation for the given system is [1, 5] · [x1, x2] = [-3, 8, 1].
In the given problem, we are provided with three systems of linear equations. To represent each system as a linear vector equation, we can use the coefficient matrix and the variable vector.
For system a, the coefficient matrix is [2, -1, 5; 1, -8, 2; 0, 4, -4] and the variable vector is [x1, x2, x3]. Thus, the linear vector equation becomes [2, -1, 5] · [x1, x2, x3] = [3, 5, 0].
Similarly, for system b, the coefficient matrix is [1, 6, 2, -1; 5, 0, -6, 0] and the variable vector is [x1, x2, x3, x4]. The linear vector equation is [1, 6, 2, -1] · [x1, x2, x3, x4] = [5, 0, 7, 0].
Lastly, for system c, the coefficient matrix is [1, 5; -2, -13; 3, -3] and the variable vector is [x1, x2]. The linear vector equation becomes [1, 5] · [x1, x2] = [-3, 8, 1].
In summary, the linear vector equations for the given systems of linear equations are obtained by representing the coefficient matrix and the variable vector as dot products.
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Identify the type of data (qualitative/quantitative) and the level of measurement for the eye color of respondents in a survey. explain your choice.
The eye color of respondents in a survey is qualitative data at the nominal level of measurement.
The eye color of respondents in a survey can be categorized as qualitative data because it represents a characteristic or attribute rather than a numerical quantity. Qualitative data is descriptive and categorical.
In terms of the level of measurement, the eye color variable can be classified as nominal level data. Nominal data is the lowest level of measurement and simply categorizes observations into different groups without any inherent order or magnitude. In this case, eye colors such as blue, brown, green, hazel, etc. are non-numeric categories without any implied ranking or quantitative relationship.
Nominal data is characterized by the fact that you cannot perform mathematical operations on the categories, and there is no meaningful measure of central tendency or dispersion. Eye color falls into this category since you cannot meaningfully calculate averages or quantify differences between eye colors using mathematical operations.
To summarize, the eye color of respondents in a survey is qualitative data at the nominal level of measurement.
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Please help!
Elias measured the height, ∞, of each of the students in his class. He recorded the heights in the table below.
Calculate an estimate of the mean height of the students.
Give your answer in centimetres (cm).
Height (cm) 120 < * ≤ 130 130 < x s 140 140 < .* ≤ 150
Frequency
6
12
2
Answer:· Step 2: (−6 ÷ 2)(5 − 7)2 Subtract within first parentheses. Step 3: −3(5 − 7)2 Divide within the first parentheses. Step 4: −3(5
Step-by-step explanation:
Two ships leave a port at the same time. The first ship sails on a bearing of 58° at 26 knots (nautical miles per hour) and the second on a bearing of 148° at 28 knots. How far apart are they after 1.5 hours? (Neglect the curvature of the earth.)
After 1.5 hours, the ships are approximately ____ nautical miles apart. (Round to the nearest nautical mile as needed.)
After 1.5 hours, the ships are approximately 57 nautical miles apart.
To find the distance between the two ships after 1.5 hours, we can use the concept of relative velocity. We'll calculate the displacement of each ship individually, considering their speeds and bearings.
Let's start by calculating the displacement of the first ship:
Displacement of the first ship = Speed of the first ship * Time
= 26 knots * 1.5 hours
= 39 nautical miles
Next, let's calculate the displacement of the second ship:
Displacement of the second ship = Speed of the second ship * Time
= 28 knots * 1.5 hours
= 42 nautical miles
Now, we have the two displacements. To find the distance between the ships, we can treat the displacements as the sides of a triangle and use the Law of Cosines.
Distance^2 = (Displacement of the first ship)^2 + (Displacement of the second ship)^2 - 2 * (Displacement of the first ship) * (Displacement of the second ship) * cos(angle)
The angle between the ships can be found as the sum of their bearings, subtracted from 180 degrees:
Angle = 180 degrees - (58 degrees + 148 degrees)
= 180 degrees - 206 degrees
= -26 degrees (Note: We take the negative since it's clockwise from the reference direction)
Now, we can substitute the values into the equation and calculate the distance:Distance^2 = (39 nautical miles)^2 + (42 nautical miles)^2 - 2 * (39 nautical miles) * (42 nautical miles) * cos(-26 degrees)
Using a calculator, we find:
Distance^2 ≈ 1521 + 1764 + 2 * 39 * 42 * 0.8944
Distance^2 ≈ 3255.504
Taking the square root: Distance ≈ √3255.504
Distance ≈ 57.06 nautical miles (rounded to the nearest nautical mile)
Therefore, after 1.5 hours, the ships are approximately 57 nautical miles apart.
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Which graph shows the line y-1 = 2(x+2)?
A. Graph D
B. Graph A
C. Graph B
D. Graph C
Answer:
D. Graph C
Step-by-step explanation:
Step 1: Identify the parts of the point-slope form to find the correct graph:
Currently, y - 1 = 2(x + 2) is in point-slope form, whose general equation is given by:
y - y1 = m(x - x1), where
(x1, y1) is one point on the line,and m is the slope.When (x1, y1) is plugged into the point-slope form, the sign of the actual coordinates becomes its opposite. Thus, the coordinates of the point on the line y - 1 = 2(x + 2) is (-2, 1), while the slope is 2.Only Graph C C has the point (-2, 1).Furthermore, since slope is simply the change in y / change in x, we see that for every 2 units you rise (go up on the line), you run (go right on the line) 1 unit.subtract using a number line. −3.3−(−0.6) plot the minuend and the difference on the number line. -4-1-3.5-3-2.5-2-1.5
The resulting point on the number line, -3.9, represents the difference when subtracting -0.6 from -3.3. Therefore, the difference is -3.9.
To subtract -3.3 from -0.6 using a number line, we start by plotting the minuend (-3.3) on the number line and then move to the left by the distance equal to the subtrahend (-0.6). The resulting point on the number line represents the difference.
Here's the step-by-step process:
1. Start by plotting the minuend, -3.3, on the number line:
-4 -3.5 -3 -2.5 -2 -1.5 -1
| | | | | | |
-3.3
2. Next, move to the left by the distance of the subtrahend, -0.6, on the number line:
-4 -3.5 -3 -2.5 -2 -1.5 -1
| | | | | | |
x -3.9
The resulting point on the number line, -3.9, represents the difference when subtracting -0.6 from -3.3. Therefore, the difference is -3.9.
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what a the subject of the formula
t^2 = 2p + as
Answer:
[tex]\sf a = \dfrac{t^2-2p}{s}[/tex]
Step-by-step explanation:
To make 'a' as the subject:
t² = 2p + as
Isolate the term containing 'a'. Subtract 2p from both sides.t² - 2p = as
Divide both sides by 's'.[tex]\sf \dfrac{t^2 - 2p}{s}=\dfrac{as}{s}\\\\\\\dfrac{t^2-2p}{s}=a\\\\\boxed{\bf a =\dfrac{t^2-2p}{s}}[/tex]
Find the value of the variable and Y Z if Y is between X and Z.
X Y=3 a-4, Y Z=6 a+2, X Z=5 a+22
The value of the variable "a" is 6, and the values of Y and Z are 14 and 38, respectively.
To find the value of the variable "a," we can set up the equation XZ = XY + YZ and substitute the given values:
5a + 22 = (3a - 4) + (6a + 2)
Simplifying the equation, we get:
5a + 22 = 3a - 4 + 6a + 2
5a + 22 = 9a - 2
Moving all the "a" terms to one side, we have:
5a - 9a = -2 - 22
-4a = -24
Dividing both sides of the equation by -4, we find:
a = 6
Now, substituting the value of "a" into the given equations, we can determine the values of Y and Z:
XY = 3a - 4 = 3(6) - 4 = 18 - 4 = 14
YZ = 6a + 2 = 6(6) + 2 = 36 + 2 = 38
Therefore, Y = 14 and Z = 38.
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You are 30 years old and plan to retire at age 70, which is 40 years from now. You would like to have $1.0Mn at the end of 40 years (which is when you retire). Wh should your monthly payment be, if you believe you can earn 12% compounded monthly? $158.13 $213.61 $135.05 $61.35 $85.00 $46.61
The monthly payment needed to accumulate $1.0 million in 40 years with a 12% compounded monthly interest rate is approximately $137.95.
To determine the monthly payment needed to accumulate $1.0 million in 40 years with a 12% compounded monthly interest rate, we can use the future value of an ordinary annuity formula:
FV = P * [(1 + r)^n - 1] / r
Where:
FV = Future value ($1.0 million)
P = Monthly payment
r = Monthly interest rate (12% divided by 12)
n = Number of compounding periods (40 years multiplied by 12)
Substituting the values into the formula:
$1,000,000 = P * [(1 + 0.12/12)^(40*12) - 1] / (0.12/12)
Simplifying the equation:
1,000,000 = P * (1.01^480 - 1) / 0.01
1,000,000 = P * (7.244) / 0.01
P = 1,000,000 * 0.01 / 7.244
P ≈ $137.95
Therefore, the monthly payment needed to accumulate $1.0 million in 40 years with a 12% compounded monthly interest rate is approximately $137.95.
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Find the annual simple interest rate of a loan, where $1200 is borrowed and where $1232 is repaid at the end of 4 months. A. 10.67% B. 8% C. 6.4% D. 2.67% E. 9%
Previous question
Annual simple interest rate of the loan can be calculated using the formula for simple interest. By rearranging the formula and solving for interest rate, we can determine the answer. Correct answer is C. 6.4%.
The formula for simple interest is:
I = P * r * t
where I is the interest amount, P is the principal amount, r is the interest rate, and t is the time period.
In this case, we have:
P = $1200
I = $1232 - $1200 = $32 (the difference between the amount repaid and the amount borrowed)
t = 4 months
We need to find the interest rate r. Rearranging the formula, we have:
r = I / (P * t)
Substituting the given values, we get:
r = $32 / ($1200 * 4/12) = $32 / $400 = 0.08
To convert the decimal to a percentage, we multiply by 100. Therefore, the annual interest rate is 0.08 * 100 = 8%.
However, it's important to note that the options provided in the question are given in annual percentage rates (APR). The answer we calculated is the monthly interest rate. To convert the monthly rate to an annual rate, we multiply by 12. Hence, the annual simple interest rate is 8% * 12 = 96%.
Therefore, the correct answer is C. 6.4%, which is the only option that matches the calculated annual interest rate.
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if my grade is at an 81% and i get a 60% on my final that is worth 15% of my grade what would my ending grade be
If you score 60% on your final exam, your ending grade would be 78%.
To calculate your ending grade, we need to consider the weight of each component. Let's break it down step by step:
Determine the weight of your current grade: Your current grade is at 81%, and since it is not mentioned, we'll assume that the current grade is weighted at 85% of your total grade.
Determine the weight of your final exam: The final exam is worth 15% of your total grade.
Calculate the contribution of your current grade: Multiply your current grade (81%) by the weight (85%): [tex]0.81 \times 0.85 = 0.68985[/tex], which is approximately 0.69 when rounded to two decimal places.
Calculate the contribution of your final exam: Multiply your final exam grade (60%) by the weight (15%): [tex]0.6 \times 0.15 = 0.09.[/tex]
Calculate your ending grade: Add the contributions of your current grade and final exam: 0.69 + 0.09 = 0.78.
Convert the ending grade to a percentage: Multiply the ending grade (0.78) by 100 to get the percentage: [tex]0.78 \times 100 = 78%.[/tex]
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Match a term with its description or what process it describes in a raster data model
A. Groups of raster cells that are clustered to represent an area
B. When data take on values that can't appropriately be added and subtracted, or even ordered
C. When data take on a wide range of possible values which can be ranked or ordered
D. When pixel size is so large that multiple features may occur within one pixel
E. Individual raster cells
F. When a new layer is created with a different pixel size and/or pixel orientation
1. Mixed Pixel Problem
2. Resampling
3. Discrete
4. Continuous
5. Points
6. Polygons
------------------------------------------
Match the data characteristic with its matching definition
A. Resolution set by pixel size
B. Polygon defined by it's boundary lines
C. Data values represent themes or classes
D. Data values don't represent themes or classes
E. High resolution
F. Low resolution
1. Vector data
2. Raster data
3. Continuous entities
4. Discrete entities
5. Large scale
6. Small scale
Data Characteristics:
A. Resolution set by pixel size - 2. Raster data
B. Polygon defined by its boundary lines - 1. Vector data
C. Data values represent themes or classes - 4. Discrete entities
D. Data values don't represent themes or classes - 3. Continuous entities
E. High resolution - 5. Large scale
F. Low resolution - 6. Small scale
In the Raster Data Model, "Polygons" refer to groups of raster cells that are clustered to represent an area, while the "Mixed Pixel Problem" occurs when data take on values that can't be added, subtracted, or ordered appropriately.
"Continuous" describes data that can take on a wide range of possible values and can be ranked or ordered, whereas "Points" represent individual raster cells. "Resampling" refers to the process of creating a new layer with a different pixel size and/or pixel orientation.
Regarding Data Characteristics, in raster data, the resolution is set by pixel size, making it "Raster data." In contrast, polygons are defined by their boundary lines, representing "Vector data."
"Discrete entities" indicate that data values represent themes or classes, while "Continuous entities" imply that data values don't represent themes or classes. "High resolution" signifies a more detailed or fine-scale representation, while "Low resolution" indicates a less detailed or coarse-scale representation.
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Let Y be a discrete random variable with probability mass function p(y)=Pr(Y=y)=a− y
2b
for y=1,2,3, where a and b are constants. If it is known that E[Y]=6, what must be the values of a and b ? Note: in the answer box, type the sum of a plus b. For example, if your answers are a=123 and b=−122, then the number you will type in the box is 1 .
To find the values of a and b, we can use the fact that the expected value of a discrete random variable Y is given by the sum of y times its corresponding probability mass function. the sum of a and b is 6.
E[Y] = Σ(y * p(y))
Given the probability mass function p(y) =[tex](a - y^2) / (2b)[/tex] for y = 1, 2, 3, we can calculate the expected value as:
[tex]E[Y] = 1 * p(1) + 2 * p(2) + 3 * p(3)[/tex]
Substituting the given probability mass function:
6 = [tex]1 * [(a - 1^2) / (2b)] + 2 * [(a - 2^2) / (2b)] + 3 * [(a - 3^2) / (2b)][/tex]
Simplifying the equation:
6 = (a - 1) / (2b) + 2(a - 4) / (2b) + 3(a - 9) / (2b)
Multiplying both sides of the equation by 2b to eliminate the denominators:
12b = (a - 1) + 2(a - 4) + 3(a - 9)
12b = a - 1 + 2a - 8 + 3a - 27
12b = 6a - 36
Rearranging the equation:
6a - 12b = 36
Since we have one equation and two unknowns (a and b), we cannot determine the exact values of a and b. However, we can find their sum:
a + b = 36 / 6
a + b = 6
Therefore, the sum of a and b is 6.
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