the student repeats this process several times for different values of y . which variables should be plotted on the horizontal and vertical axes to yield a linear graph?

Answers

Answer 1

To yield a linear graph, the variables that should be plotted on the horizontal and vertical axes depend on the nature of the process being repeated by the student. If the process involves measuring the dependent variable y for different values of an independent variable x, then x should be plotted on the horizontal (x-axis) and y on the vertical (y-axis). This is because the independent variable is usually plotted on the x-axis, while the dependent variable is plotted on the y-axis. The resulting graph will show how y varies with respect to x, and if the relationship between x and y is linear, the graph will be a straight line.

On the other hand, if the process involves measuring the dependent variable y for different values of another independent variable z, then z should be plotted on the horizontal (x-axis) and y on the vertical (y-axis). This is because in this case, the variable being plotted on the x-axis is still the independent variable, while the dependent variable is still plotted on the y-axis.

In summary, the choice of variables to plot on the horizontal and vertical axes to yield a linear graph depends on the nature of the process being repeated by the student, and whether the process involves measuring the dependent variable y for different values of an independent variable x or another independent variable z.

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Related Questions

identify if the following statement is a proper interpretation of a 95 confidence interval : 95% of the possible samples from this population will have sample statistics in this particular interval

Answers

Yes, the statement is a proper interpretation of a 95% confidence interval. A confidence interval is a range of values that is likely to contain the true population parameter with a certain degree of confidence.

The given statement is: "95% of the possible samples from this population will have sample statistics in this particular interval."

This statement is not a proper interpretation of a 95% confidence interval. A correct interpretation would be: "We are 95% confident that the true population parameter falls within this particular interval."

The key difference is that a confidence interval provides an estimated range for the population parameter, rather than describing the proportion of samples that fall within the interval.

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For parts a and b​, use technology to estimate the following.
​a) The critical value of t for a ​% confidence interval with df.
​b) The critical value of t for a ​% confidence interval with df.

Answers

The critical value of t depends on both the confidence level and the degrees of freedom.

The sample size increases, the degrees of freedom also increase, and the t-distribution approaches the normal distribution.

The z-distribution to find the critical value of z for a given confidence level.

The critical value of t for a given confidence level and degrees of freedom, we can use statistical software or online calculators.

These tools typically provide tables or functions that allow us to look up or calculate the appropriate value.

The critical value of t for a 95% confidence interval with 10 degrees of freedom.

Using an online t-distribution calculator, we can enter the values of the confidence level and degrees of freedom and obtain the result, which in this case is approximately 2.228.

If we want to construct a 95% confidence interval for a sample with 10 degrees of freedom, we would use the formula:

[tex]\bar x \pm t \times (s/\sqrt n)[/tex]

[tex]\bar x[/tex] is the sample mean, s is the sample standard deviation, n is the sample size, and t is the critical value we just obtained.

The critical value of t for a confidence interval, we need to know the confidence level and degrees of freedom, and we can use statistical software or online calculators to obtain the appropriate value.

This value is used in the formula for constructing the confidence interval, which depends on the sample statistics and the size of the sample.

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The time, in minutes, it took each of 11 students to complete a puzzle was recorded and is shown in the following list. 9, 17, 20, 21, 27, 29, 30, 31, 32, 35, 58 one of the students who completed the puzzle claimed that there were two outliers in the data set. Based on the 1. 5×iqr rule for outliers, is there evidence to support the student’s claim?.

Answers

Based on the 1.5 × IQR rule for outliers, there is no evidence to support the student's claim because there is only one outlier at 58 minutes.

What is an interquartile range of the data?

The interquartile range is the difference between upper and lower quartiles. The semi-interquartile range is half the interquartile range. When the data set is small, it is simple to identify the values of quartiles.

Mathematically, interquartile range (IQR) is the difference between quartile 1 (Q₁) and quartile 3 (Q₃):

IQR = Q₃ - Q₁

The following interquartile ranges was calculated by using Excel:

Q₃ = 31.5

Q₁ = 20.5

Now, the interquartile range (IQR) is given by:

IQR = Q₃ - Q₁

IQR = 31.5 - 20.5

IQR = 11

Based on the 1.5 × IQR rule for outliers, we have:

1.5 × IQR = 1.5 × 11 = 16.5

Therefore, our fences will be 16.5 points below Q₁ and 16.5 points above Q₃:

Lower fence = 20.5 - 16.5 = 4.5

Upper fence = 4.5 + 31.5 = 36.

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Find the missing side.
X
11
7 x = [?]
Round to the nearest tenth.
Enter

Answers

A right angled triangle with height = 7, base = 11, by using the Pythagorean theorem, we can calculate the hypotenuse is approximately 13. Therefore, the missing side, x = 13.

In a right angled triangle, using the Pythagorean theorem: sum of the squares of the base and height is equal to the square of the hypotenuse, we can find the hypotenuse x.

[tex]x^2 = 7^2 + 11^2[/tex]

[tex]x^2 = 49 + 121[/tex]

[tex]x^2 = 170[/tex]

Taking the square root of both sides, we get:

x ≈ 13.0384

Rounding this to the nearest tenth, we get:

x ≈ 13.0

Therefore, the length of x is approximately 13.0 units (rounded to the nearest tenth).

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A circle with center is shown in the figure below.
S
T
W
R
U
V
(a) Name a radius:

(b) Name a diameter:
(c) Name a chord:
(d) If the length of is units,
what is the length of ?

Answers

The names of the radius , chord and diameter of a circle are as follow,

Radius of the circle are PQ, PM , And PR.

Diameter of the circle is QM

Chord of the circle is ON.

Length of QM in the circle = 4units.

In the attached figure of the circle,

Center of the circle is P.

radius of the circle is a distance from the center of the circle to its circumference.

Radius = PQ, PM , And PR.

Diameter of the circle passing through center P is QM.

Chord of the circle representing a line segment having endpoints on the circumference of the circle.

Chords are ON and MQ.

Diameter is the longest chord.

length of PR is 2 units,

PR is radius

QM is diameter

QM = 2(PR)

length of QM = 2(2)

                      = 4 units.

Therefore, for the given circle we have,

Radius are PQ, PM , And PR.

Diameter is QM

Chord is ON.

Length of QM = 4units.

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The above question is incomplete, the complete question is:

A circle with center P is shown in the figure below.

(a) Name a diameter:

(b) Name a radius:

(c) Name a chord:

(d) If the length of PR is 2 units, what is the length of QM

Attached figure.

In an examination, Tunde's marks are 21 more than Muhammad's marks. If Muhammad had scored twice his marks, then Tunde would have five marks less.what was scored by Muhammad?

Answers

Let's use algebra to solve the problem.

Let M be the marks scored by Muhammad.

According to the problem, Tunde's marks are 21 more than Muhammad's marks, so Tunde's marks are M + 21.

If Muhammad had scored twice his marks, he would have scored 2M. And if Tunde had scored 5 marks less than that, he would have scored 2M - 5.

We know that Tunde's actual marks are M + 21. So we can set up an equation:

M + 21 = 2M - 5

Simplifying this equation, we get:

26 = M

Therefore, Muhammad scored 26 marks.

Find the minimum sample size you should use to assure that your estimate of p^ will be within the required margin of error around the population p.
Margin of error: 0.011; confidence level: 92%; p^ and ^q unknown
Group of answer choices
6328
6327
40
637

Answers

For a sample with margin of error 0.011 and confidence level 92%, the minimum sample size we should use to assure that your estimate of [tex] \hat p \: = 0.5[/tex] is 6328. So, option (a) is right one.

The sample size is a sample attribute and it is determined by the formula of margin of error with a confidence level. The size of the sample must be appropriate so that sample can estimate the population parameter with a small sampling error.

We have a sample with the following details, Margin of error, MOE = 0.011

Confidence level = 92%

The population proportion= p

Sample proportion [tex] \hat p \: = 0.5[/tex]

Now, using the table value of z score for 92% of confidence interval is equals to 1.75. So, [tex]Z_{ \frac{0.08}{2}} = 1.405[/tex]. The margin of error at the 93% confidence coefficient is [tex]ME = Z_{ \frac{0.08}{2}} × \sqrt{\frac{\hat p(1 - \hat p)}{n}}[/tex]

Substitute all known values in above formula, [tex]0.011= 1.750 × \sqrt{\frac{0.5(1 - 0.5)}{n}}[/tex]

Squaring both sides,

[tex]0.011² = ( 1.75)² (\frac{ 0.25}{n})[/tex]

=> [tex]n = \frac{ (1.75)² × 0.25}{0.011²}[/tex]

=> n = 6328

Hence, required value is 6328.

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Rounding up, the minimum sample size required is 6328

The minimum sample size required to ensure that the estimated proportion (p^) is within a desired margin of error with a certain level of confidence can be determined using a formula.

n = (z-score)^2 * p^(1-p^) / (margin of error)^2

Where:

The z-score is the standard normal distribution's critical value for the specified confidence level (92% with this case).

p^ is the estimated proportion of the population with the characteristic of interest (unknown in this case, so we can use 0.5 as a conservative estimate)

(1-p^) is the complementary proportion to p^

margin of error is the maximum allowed difference between the sample proportion and the true population proportion.

Inputting the values provided yields:

n = (1.751)^2 * 0.5 * 0.5 / (0.011)^2 n ≈ 6327.98

The formula considers the margin of error, confidence level, and estimated population proportion.

In this case, the margin of error is given as 0.011, the confidence level is 92%, and the population proportion is unknown. Using a conservative estimate of 0.5 for the population proportion, the minimum sample size is calculated as 6327.98, which is rounded up to 6328.

Therefore, a sample size of at least 6328 is required to ensure that the estimated proportion is within 0.011 of the true population proportion with a confidence level of 92%. Adequate sample size is important to obtain accurate estimates of population parameters and minimize sampling errors.

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the gestation period for humans are normally distributed, with a mean of 272 days and a standard deviation of 14 days. random samples of size 24 women are drawn from the population: a. find the mean of the sampling distribution of sample means: b. find the standard deviation or standard error of the sampling distribution of sample means: c. draw or describe the graph of the sampling distribution of sample means: d. suppose samples of size 28 are drawn instead of size 24. write what happens to the mean and standard error of the sampling distribution. draw or describe the graph of this distribution labeling the mean and standard error.

Answers

The mean of the sampling distribution of sample means is equal to the population mean.

In this case, it is 272 days.

a. The standard deviation (or standard error) of the sampling distribution of sample means can be calculated using the formula: σ_sample = σ_population / √n, where σ_sample is the standard error, σ_population is the population standard deviation, and n is the sample size. In this case, σ_sample = 14 days / √24 ≈ 2.86 days.

b. The graph of the sampling distribution of sample means will be a normal distribution with a mean of 272 days and a standard deviation of 2.86 days. The curve will be symmetrical around the mean value and will have a bell shape.

c. If the sample size is increased to 28, the mean of the sampling distribution remains the same (272 days) since it's equal to the population mean. However, the standard error will decrease because the sample size is larger: σ_sample = 14 days / √28 ≈ 2.65 days. The graph of this distribution will still be a normal distribution with a mean of 272 days, but it will be slightly narrower due to the smaller standard error of 2.65 days.

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you and a friend each roll two dice. what is the probability that you both have the same two numbers? (the two cases are whether you role doubles or not)

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The probability that you and your friend both have the same two numbers is approximately 0.4823, or about 48.23%.

If you and your friend each roll two dice, there are two possible cases:

You both roll doubles (i.e., both dice show the same number).

You both roll non-doubles (i.e., the two dice show different numbers).

Let's calculate the probability of each case separately:

The probability of rolling doubles on one die is 1/6, since there are six possible outcomes (1, 2, 3, 4, 5, or 6) and only one of them will result in doubles. The probability of rolling doubles on both dice is the product of the probabilities of rolling doubles on each die, which is (1/6) * (1/6) = 1/36. Therefore, the probability that you and your friend both roll doubles is (1/36) * (1/36) = 1/1296.

The probability of rolling non-doubles on one die is 5/6, since there are five possible outcomes (2, 3, 4, 5, or 6) that will result in non-doubles, out of a total of six possible outcomes. The probability of rolling non-doubles on both dice is the product of the probabilities of rolling non-doubles on each die, which is (5/6) * (5/6) = 25/36. Therefore, the probability that you and your friend both roll non-doubles is (25/36) * (25/36) = 625/1296.

Therefore, the overall probability that you and your friend both have the same two numbers is the sum of the probabilities of the two cases:

1/1296 + 625/1296

= 626/1296

= 0.4823 (rounded to four decimal places)

So, the probability that you and your friend both have the same two numbers is approximately 0.4823, or about 48.23%.

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there are 90 students enrolled in a major. a very important course that students try to enroll in does not have a large enrollment capacity. the number of students that are not able to schedule the elective into their course of study 14. what is the sigma level of the scheduling process?

Answers

as a sigma level of less than 99% indicates a high rate of defects.

What is the percentage?

A percentage that represents a tenth of a quantity. One percent, denoted by the symbol 1%, is equal to one-hundredth of something; hence, 100 percent denotes the full thing, and 200 percent designates twice the amount specified. A portion per hundred is what the percentage denotes. The percentage refers to one in a hundred. The % sign is used to denote it.

We can calculate the sigma level of the scheduling process using the formula:

Sigma level = (1 - (Number of defects / Number of opportunities)) * 100%

In this case, the number of opportunities is the total number of students enrolled in the major, which is 90. The number of defects is the number of students who were not able to schedule the elective into their course of study, which is 14. So we have:

Sigma level = (1 - (14 / 90)) * 100% ≈ 84.44%

So the sigma level of the scheduling process is approximately 84.44%. This suggests that there is room for improvement in the scheduling process, as a sigma level of less than 99% indicates a high rate of defects.

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Is it true that If A is a 3×3 matrix with three pivot positions, there exist elementary matrices E1,...,Ep such that Ep⋯E1A = I.

Answers

Yes, it is true that if A is a 3x3 matrix with three pivot positions, then there exist elementary matrices E1, ..., Ep such that Ep...E1A = I, where I is the 3x3 identity matrix.

This is a consequence of the fact that any invertible matrix can be written as a product of elementary matrices. An elementary matrix is a matrix that can be obtained from the identity matrix by performing a single elementary row operation. There are three types of elementary row operations: interchanging two rows, multiplying a row by a nonzero constant, and adding a multiple of one row to another row.

Since A has three pivot positions, it can be reduced to the identity matrix by a sequence of elementary row operations. Each elementary row operation can be represented by an elementary matrix, and the product of these elementary matrices will give us the desired product Ep...E1A = I.

So, in summary, if A is a 3x3 matrix with three pivot positions, then there exist elementary matrices E1, ..., Ep such that Ep...E1A = I.

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speed is measured by the time required to run a distance of 40 yards, with smaller times indicating more desirable (faster) speeds. from previous speed data for all players in this position, the times to run 40 yards have a mean of 4.60 seconds and a standard deviation of 0.15 seconds, with a minimum time of 4.40 seconds, as shown in the table below. time to run 40 yards mean 4.60 seconds standard deviation 0.15 seconds minimum 4.40 seconds based on the relationship between the mean, standard deviation, and minimum time, is it reasonable to believe that the distribution of 40-yard running times is approximately normal? explain.

Answers

the minimum time of 4.40 seconds is not significantly far from the mean of 4.60 seconds, which further supports the normality assumption.

It is reasonable to believe that the distribution of 40-yard running times is approximately normal based on the central limit theorem, which states that the distribution of sample means tends to be normal, regardless of the underlying population distribution, as long as the sample size is sufficiently large. In this case, we are given the mean and standard deviation for all players in the position, which suggests that the population distribution is approximately normal.

what is second?

A second is a unit of time. It is defined as the duration of 9,192,631,770 periods of the radiation corresponding to the transition between two hyperfine levels of the ground state of the caesium-133 atom.

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Pls help me quick with this question ( will give brainy for correct )

Answers

The inequality solved for y is:

y ≥ 21/25

How to solve the ienquality for y?

To solve an inequality for one variable, we need to isolate that variable.

Here we have:

(8/7)y -1 ≥ (3/7)y - 2/5

Move the terms with y to the left side and the others to the right side.

(8/7)y - (3/7)y ≥ -2/5 + 1

(5/7)y ≥ (3/5)

Now multiply both sides by 7/5, we will get:

y  ≥ (3/5)*(7/5)

y ≥ 21/25

That is the solution simplfied.

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Use The Theorem 1. 4. 5 And Then Use The Inversion Algorithm To Find A^-1 , If It ExistsA=[a b][c d]In invertible if and only ad - bc ≠ 0, in which case the inverse is given by the formulaA-¹=1/ad/bc[d -b][-c a]a. A = [1 4][2 7]b. A = [ 2 -4][-4 8]

Answers

a.) The inverse of matrix A is [7 -4][-2 1].

b.) det(A) is zero, we know that A is not invertible.

Theorem 1.4.5 states that a matrix A is invertible if and only if its determinant, which is defined as ad-bc, is nonzero. If A is invertible, then its inverse A⁻¹ is given by the formula:

A⁻¹ = 1/det(A) * [d -b][-c a],

where det(A) = ad-bc is the determinant of A.

Now, let's use this theorem and the inversion algorithm to find the inverses of the given matrices:

a. A = [1 4][2 7]

First, we need to calculate the determinant of A:

det(A) = ad-bc = (1 * 7) - (4 * 2) = 1

Since det(A) is nonzero, we know that A is invertible. Now, we can apply the formula for A⁻¹:

A⁻¹ = 1/det(A) * [d -b][-c a]

= 1/1 * [7 -4][-2 1]

= [7 -4][-2 1]

b. A = [2 -4][-4 8]

Again, we need to calculate the determinant of A:

det(A) = ad-bc = (2 * 8) - (-4 * -4) = 0

Here the det is zero there is no invertible matrix for B.

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consider a binary search algorithm to search an ordered list of numbers. which of the following choices is closest to the maximum number of times that such an algorithm will execute its main comparison loop when searching a list of 1 million numbers?

Answers

The maximum number of times the main comparison loop will execute for a list of 1 million numbers is closest to 20.

What is binary search?

An effective algorithm for narrowing down a list of things is binary search. It divides the section of the list that might contain the item in half repeatedly until there is only one viable position left. In the beginning tutorial's guessing game, binary search was used.

In a binary search algorithm, the main comparison loop divides the search interval in half at each iteration until the target value is found or the search interval is empty. Therefore, the number of times the loop executes is proportional to the number of times the search interval can be divided in half before reaching a length of 1.

For a list of 1 million numbers, the initial search interval includes all 1 million numbers. At the first iteration, the interval is divided in half, leaving 500,000 numbers to search. At the second iteration, the interval is divided in half again, leaving 250,000 numbers. This process continues until the interval contains only one number, which is either the target value or not present in the list.

The number of times the loop executes is equal to the number of times the interval can be divided in half before reaching a length of 1. In this case, the interval length is divided by 2 at each iteration, so the number of iterations required to reach a length of 1 is log base 2 of 1 million:

log2(1,000,000) = 19.93

Therefore, the maximum number of times the main comparison loop will execute for a list of 1 million numbers is closest to 20.

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Data set X: 8, 20, 36, 36, 54, 88
Data set Y: 8, 20, 36, 36, 54
Which of the following statements about the given data sets is true?
A. The mean of data set X is greater than the mean of data set Y.
B. The mean of data set X is less than the mean of data set Y.
C.The median of data set X is greater than the median of data set Y.
D. The median of data set X is less than the median of data set Y.

Answers

The true statement is the mean of data set X is greater than the mean of data set Y. (option A)

What is the true statement?

The mean is a measure of central tendency that determines the average of a set of numbers.

Mean of data set X = (8 + 20 + 36 + 36 + 54 + 88) / 6 = 40.33

Mean of data set Y = (8 + 20 + 36 + 36 + 54) / 5 = 30.80

Median is a measure of central tendency that determines the number in the middle of a dataset that has been arranged in either ascending or descending order.

Median of data set X = 36

Median of data set y = 36

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A population proportion is 0.30. A sample of size 300 will be taken and the sample proportion p will be used to estimate the population proportion. (Round your answers to four decimal places.) (a) What is the probability that the sample proportion will be within 10.03 of the population proportion? (b) What is the probability that the sample proportion will be within 10.05 of the population proportion?

Answers

The probability that the sample proportion will be within 10.05 of the population proportion is approximately 0.0139.

What is probability?

Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1, where 0 means the event is impossible and 1 means the event is certain to happen.

(a) To find the probability that the sample proportion will be within 10.03 of the population proportion, we need to first calculate the standard error of the sample proportion:

SE = sqrt(p*(1-p)/n) = sqrt(0.3*(1-0.3)/300) = 0.0308

Then, we can use the normal distribution to find the probability:

P(|p - 0.3| <= 0.1003) = P(-0.1003/0.0308 <= (p - 0.3)/0.0308 <= 0.1003/0.0308)

≈ P(-3.2565 <= Z <= 3.2752) = 2*P(Z <= 3.2752) - 1 ≈ 0.0146

where Z is the standard normal distribution.

Therefore, the probability that the sample proportion will be within 10.03 of the population proportion is approximately 0.0146.

(b) To find the probability that the sample proportion will be within 10.05 of the population proportion, we can follow the same steps as in part (a), but with a different margin of error:

SE = sqrt(0.3*(1-0.3)/300) = 0.0308

P(|p - 0.3| <= 0.1005) = P(-0.1005/0.0308 <= (p - 0.3)/0.0308 <= 0.1005/0.0308)

≈ P(-3.2649 <= Z <= 3.2836) = 2*P(Z <= 3.2836) - 1 ≈ 0.0139

where Z is the standard normal distribution.

Therefore, the probability that the sample proportion will be within 10.05 of the population proportion is approximately 0.0139.

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A group of 500 middle school students were randomly selected and asked about their preferred frozen yogurt flavor. A circle graph was created from the data collected.

a circle graph titled preferred frozen yogurt flavor with five sections labeled Dutch chocolate 21.5 percent, country vanilla 28.5 percent, sweet coconut 13 percent, espresso 10 percent, and cake batter

How many middle school students preferred cake batter-flavored frozen yogurt?

27
50
72
135

Answers

Answer:

72

Step-by-step explanation:

Final answer:

50 middle school students preferred cake batter-flavored frozen yogurt, calculated by applying the percentage given to the total number of students surveyed.

Explanation:

This question requires a basic understanding of percentages and how to apply them in a real-world context. The circle graph indicates that 10 percent of the students surveyed prefer cake batter as their favorite frozen yogurt flavor.

We're given that the total number of students surveyed is 500. To figure out the number of students who prefer cake batter, we multiply the total number of students by the percentage that prefer cake batter, expressed as a decimal.

So, 500 (total students) * 10/100 (percentage who prefer cake batter) = 50 students.

Therefore, 50 middle school students preferred cake batter-flavored frozen yogurt.

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a fruit company delivers fruit in two different size boxes: large and small. a delivery of 3 large boxes and 4 small boxes has a total weight of \69\) kilograms. a delivery of 5 large boxes and small boxes has a total weight of 73 kilograms. how much does each type of box weigh?

Answers

In the equation, the large book weight is 11kg and small book weight is

9 kg.

What is equation?

The definition of an equation in algebra is a mathematical statement that demonstrates the equality of two mathematical expressions. For instance, the equation 3x + 5 = 14 consists of the two equations 3x + 5 and 14, which are separated by the 'equal' sign.

Here let us take weight of large book as x and weight of small book as y.

Then,  3 large boxes and 4 small boxes has a total weight of 69 then,

=> 3x+4y = 69 --------> 1

And 5 large boxes and  2 small boxes has a total weight of 73kg then,

=> 5x+2y = 73 ----------> 2

Now multiply second equation by 2 then,

=> 10x+4y = 146 ----------> 3

Now 3 -1 then,

=>    10x+4y =   146

  (-)    3x+4y =    69

-------------------------------

     7x          =     77

=>  x = 77/7 = 11kg.

put x=11 kg into 1 then,

=> 3(11)+4y=69

=> 4y = 69-33

=> 4y = 36

=> y = 36/4 = 9 kg.

Hence the large book weight is 11kg and small book weight is 9 kg.

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if katie scored a 93 on a test and her calculated z score was 2.14, what does that mean

Answers

A z-score of 2.14 indicates that Katie's score on the test is quite high and unusual, and places her in the top 2% of the scores in the population.

Katie scored a 93 on a test and her calculated z score was 2.14, that means that her score is 2.14 standard deviations above the mean of the test scores.

A z score represents the number of standard deviations a data point is from the mean of the data set.

A positive z score means that the data point is above the mean, while a negative z score means that the data point is below the mean.

The mean of the test scores was, 80 with a standard deviation of 5, then Katie's z score would be calculated as:

z = (x - μ) / σ

= (93 - 80) / 5

= 2.6

Z scores are useful for comparing data points from different data sets or for comparing data points within the same data set that are measured on different scales.

Katie's score is 2.6 standard deviations above the mean.

A z score of 2.14 would mean that Katie's score is slightly below this value, but still significantly above the mean.

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suppose you have a graph with vertices and edges that satisfies . must the graph be a tree? prove your answer.

Answers

If a graph has vertices and edges such that there are no cycles (i.e. it is acyclic) and it is connected, then the graph must be a tree.

To prove this, we first note that a tree is defined as a connected, acyclic graph. Therefore, if we can show that a graph with the given properties is also connected and acyclic, then it must be a tree.

First, let us prove that the graph is connected. Since there are no cycles, every vertex must be part of a path. Moreover, since there are no isolated vertices, every vertex is connected to at least one other vertex. Therefore, if we start at any vertex and follow any path, we will eventually reach all other vertices. Hence, the graph is connected.

Next, let us prove that the graph is acyclic. Suppose, for the sake of contradiction, that the graph contains a cycle. Let v1, v2, ..., vn be the vertices of the cycle in order. Since the graph is connected, there must be a path from v1 to vn that does not include any of the vertices v2, ..., vn-1 (otherwise, we could "short-circuit" the cycle). But this path, together with the edges (v1, v2) and (vn-1, vn), forms a cycle, contradicting our assumption that the graph is acyclic. Therefore, the graph is acyclic.

Since the graph is both connected and acyclic, it must be a tree. Therefore, a graph with vertices and edges that satisfies the given conditions must be a tree.

No, the graph does not necessarily have to be a tree.

How to determine the proof

The formula v = e + 1 signifies that one more than the number of edges (e) is the number of vertices (v).

This formula is valid for all connected graphs with one extra edge, besides the necessary edges for forming a tree.

Thus, it is possible that the diagram remains with loops and more offshoots, classifying it as a graph that is connected, yet not a tree.

The equation v = e + 1 does not limit the graph's structure beyond its connectedness.

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a union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the u.s. the union will choose a random sample of wages and then estimate using the mean of the sample. what is the minimum sample size needed in order for the union to be confident that its estimate is within of ? suppose that the standard deviation of wages of foodservice workers in the u.s. is about . carry your intermediate computations to at least three decimal places. write your answer as a whole number (and make sure that it is the minimum whole number that satisfies the requirements).

Answers

The union needs a minimum sample size of 140 to be 95% confident that their estimate of μ is within $0.35 of the true value.

To achieve this level of confidence, the union needs to determine the minimum sample size required. The sample size is important because it affects the precision of the estimate. A larger sample size generally leads to a more precise estimate.

To find the minimum sample size needed, we need to use a formula that relates the sample size, the confidence level, the standard deviation of the population, and the margin of error. The formula is:

n = (z² * σ²) / E²

where n is the sample size, z is the z-score associated with the desired confidence level (in this case, 1.96 for 95% confidence), σ is the standard deviation of the population, and E is the margin of error (in this case, $0.35).

Plugging in the given values, we get:

n = (1.96² * 2.25²) / 0.35² n = 139.79

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Complete Question:

A union of restaurant and food service workers would like to estimate the mean hourly wage, μ , of food service workers in the U.S. The union will choose a random sample of wages and then estimate μ using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of μ ?

Suppose that the standard deviation of wages of food service workers in the U.S. is about $2.25. Carry your intermediate computations to at least three decimal places. Write your answer as a whole number (and make sure that it is the minimum whole number that satisfies the requirements).

Janice has a coin collection that began with 26 coins. Since then, she has been adding to her collection at a rate of 5 coins every 3 months.

Answers

Answer:

66 coins.

Step-by-step explanation:

There are 4 quarters in a year, so 2 years is 8 quarters.

Since Janice adds 5 coins every 3 months, in one year (or 4 quarters), she will add:

5 coins/3 months x 4 quarters = 20 coins

So in 2 years (8 quarters), she will add:

20 coins/year x 2 years = 40 coins

Therefore, after 2 years, the total number of coins in Janice's collection will be:

26 + 40 = 66 coins.

The dimensions of a rectangle can be expressed as x+6, and x-2. If the area of the rectangle is 65 in^2, find the dimensions of the rectangle

Answers

The dimensions of the rectangle for the given area 65 square inches are 13in and 5in.

Dimensions of the rectangle are length and width.

Let us consider length of the rectangle = x + 6

And width of the rectangle = x -2

Area of the rectangle = 65 square inches

Area of the rectangle = length × width

Substitute the values we have,

⇒ 65 = ( x + 6 ) × ( x -2 )

⇒65 = x² + 4x -12

⇒x² + 4x - 77 = 0

⇒x² + 11x - 7x - 77 = 0

⇒ x( x+ 11 ) -7 ( x + 11 ) =0

⇒ ( x+ 11) ( x - 7) = 0

⇒ x = -11 or x = 7

Dimensions can not be negative.

⇒ x = 7

Length = 7 + 6

            = 13 in

Width = 7 - 2

          = 5in.

Therefore, the dimensions of the rectangle are 13in and 5in.

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An article reported on a school​ district's magnet school programs. Of the 1882
qualified​ applicants, 987 were​ accepted, 309 were​ waitlisted, and 586
were turned away for lack of space. Find the relative frequency for each decision​ made, and write a sentence summarizing the results.

Answers

The school district's magnet school programs, of the 1882 qualified applicants, 52.44% were accepted, 16.41% were waitlisted, and 31.15% were turned away for lack of space.

The relative frequency for each decision made by the school district regarding their magnet school programs.
First, let's define relative frequency.

It is the fraction or proportion of the total data that belongs to a particular category or class. In this case, the categories are "accepted," "waitlisted," and "turned away."
To find the relative frequency for each decision, we need to divide the number of applicants in each category by the total number of qualified applicants, which is 1882.
So, the relative frequency for "accepted" is:
987/1882 = 0.524 or 52.4%
The relative frequency for "waitlisted" is:
309/1882 = 0.164 or 16.4%
And the relative frequency for "turned away" is:
586/1882 = 0.312 or 31.2%
To summarize the results, we can say that out of the 1882 qualified applicants for the school district's magnet school programs, 52.4% were accepted, 16.4% were waitlisted, and 31.2% were turned away due to lack of space.

This indicates that there is high demand for these programs and the school district needs to consider expanding their capacity to accommodate more students.

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Measurement of the distance between the canine tooth and last molar for 25 wolf upper jaws were made by a researcher. His sample yielded a mean waiting time of 10.5 cm with a standard deviation of 0.5cm. Construct a 99% confidence interval for the population mean distance between the canine tooth and last molar. Assume that such distance for the population form a normal distribution.

Answers

We can be 99% confident that the population mean distance between the canine tooth and last molar is between 10.25 cm and 10.75 cm, based on the sample of wolf upper[tex]25[/tex] jaws.

Confidence Interval = Sample Mean ± Z-score (Standard Error)

where the Z-score is based on the level of confidence and the standard error is calculated as the standard deviation divided by the square root of the sample size.

Using a 99% confidence level, the critical value for a two-tailed test with  [tex]24[/tex] degrees of freedom is [tex]2.492.[/tex]

Confidence Interval[tex]= 10.5 ± 2.492[/tex] × [tex](0.5 / sqrt(25))[/tex]

[tex]= 10.5 ± 0.2492[/tex]

[tex]= (10.25, 10.75)[/tex]

Therefore, we can be 99% confident that the population mean distance between the canine tooth and last molar is between [tex]10.25[/tex] cm and [tex]10.75[/tex]cm, based on the sample of [tex]25[/tex] wolf upper jaws .

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The line L is normal to the curve defined by 2xy2 -3y = 18 at the point (3,2). The slope of line L is:

(A) 21/8 (B) 32/3 (C) - 10/21 (D) 8/21 (E) - 8/21

Answers

Slope of the normal L is 21/8.

Hence the correct option is (A).

Slope of normal to a function f(x) = y is given by = -dx/dy

Given the equation of the curve is,

2xy² - 3y = 18

Differentiating the function with respect to 'x' we get,

2x*2y*dy/dx + 2y²*1 - 3 dy/dx = 0

4xy*dy/dx + 2y² - 3dy/dx = 0

(3 - 4xy)dy/dx = 2y²

dy/dx = 2y²/(3 - 4xy)

-dx/dy = (4xy - 3)/2y²

Slope of the normal L at the point (3, 2) = (4*3*2 - 3)/(2*2²) = (24 - 3)/8 = 21/8

Hence the correct option is (A).

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Why does the government give unemployment?

Answers

Answer:

i don't have idea for answer

Step-by-step explanation:

i

don't

have

idea

for

answer

a doctor is measuring body temperature for patients visiting the office. the doctor believes the average body temperature is less than 98.6 degrees fahrenheit and would like to test this claim. during the process of hypothesis testing, the doctor computes a value from the sample data, which will be used to compare the sample data to the population parameter. what value did the doctor compute? select the correct answer below: critical value test statistic p-value significance level

Answers

Answer: its B) test statistic

Step-by-step explanation:

find the end behavior for g
the equation is y=g(x)

Answers

Answer 83$
Plus 68
Executive: 828388
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