The sum of two numbers is 37 and the difference is 15 . What are the numbers?
Answers
the first number is 11 and the second one is 26
Answer:
this is the answer with the working
Related Questions
Please help me with this
I would really appreciate it
thank you
Answers
Answer:
1) x=58, y=109
2) x=72, y=36
3) x=60, y=48
Step-by-step explanation:
1) 58 and x are so-called "F-angles" (a.k.a "corresponding angles), so x=58°
The angle on the other side of the 58 is 180-58 = 122 because they are supplementary. We need this one to calculate y.
The sum of angles in a quadrilateral is 360°, so 71 + 58 + 122 + y = 360, so y = 109
2) There are two isosceles triangles. Due to the symmetry, the bottom left angle is also 72, leaving 180-72-72 = 36 for y. The top triangle is the same triangle rotated, so x = 72.
3) Due to the parallel lines, the left angle of the top triangle is also 72, making the supplementary angle below it 180-72=108. The sum in the quadrilateral must be 360, so 72+108+2x+x=360, so 3x=180, x=60.
The sum in the outer triangle must be 180, so 72+y+x = 180, leaving y = 180-72-60 = 48
Determine the values of \theta if sec\;\theta=-\frac{2}{\sqrt{3}}.
Answers
Answer:
See below.
Step-by-step explanation:
So, we have:
[tex]\sec(\theta)=-2/\sqrt{3}[/tex]
Recall that secant is simply the reciprocal of cosine. So we can:
[tex]\cos(\theta)=(\sec(\theta))^{-1}=(-2/\sqrt{3})^{-1}\\\cos(\theta)=-\sqrt{3}/2[/tex]
Now, recall the unit circle. Since cosine is negative, it must be in Quadrants II and/or III. The numerator is the square root of 3. The denominator is 2. The whole thing is negative. Therefore, this means that 150 or 5π/6 is a candidate. Therefore, due to reference angles, 180+30=210 or 7π/6 is also a candidate.
Therefore, the possible values for theta is
5π/6 +2nπ
and
7π/6 + 2nπ
Help with finding the slope of the line and graph find the slope 1.) (1, 6) (3,8) 2.) (7,10) (5,6) 3.) (1,-2) (3,4) 4.) (10,5) (4,7) 5.) (-2,6) (0,5) 6.) (-9,9) (7,5) 7.) (-3, 5) (0,0) (8, 10) (-7, 14) 9.) (-12, -5) (0, -8)
Answers
Answer:
1 is 1.
2 is 2.
3 is 3. (this is not a joke, keep going)
4 is -1/3.
5 is -1/2.
6 is -1/4.
7 is -5/3.
8 is -4/15, if you meant that the points are (8,10) and (-7,14). You might have typed wrong.
9 is -1/4.
10 is 1/3. Take a look at it. It goes up by 1 and it goes over 3. 1 divided by 3 is 1/3.
11 is 1. It rises 2 and goes across by 2. 2 divided by 2 is 1.
12 is -3/4, because it goes down 3 and over 4.
13 is -3/2. Do you see why?
14 is 1. It's super easy, since it only goes up 1 and over 1.
15 is easy. You have to figure this one out, but I'll give you a hint. It goes down by 3 .
Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value, and then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. Among 2160 passenger cars in a particular region, 243 had only rear license plates. Among 358 commercial trucks, 55 had only rear license plates. A reasonable hypothesis is that commercial trucks owners violate laws requiring front license plates at a higher rate than owners of passenger cars. Use a 0.05 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval.
Answers
Answer:
For 0,90 of Confidence we reject H₀
For 0,95 CI we reject H₀
Step-by-step explanation:
To evaluate a difference between two proportion with big sample sizes we proceed as follows
1.-Proportion 1
n = 2160
243 had rear license p₁ = 243/2160 p₁ = 0,1125
2.Proportion 2
n = 358
55 had rear license p₂ = 55/ 358 p₂ = 0,1536
Test Hypothesis
Null Hypothesis H₀ ⇒ p₂ = p₁
Alternative Hypothesis Hₐ ⇒ p₂ > p₁
With signficance level of 0,05 means z(c) = 1,64
T calculate z(s)
z(s) = ( p₂ - p₁ ) / √ p*q ( 1/n₁ + 1/n₂ )
p = ( x₁ + x₂ ) / n₁ + n₂
p = 243 + 55 / 2160 + 358
p = 0,1183 and then q = 1 - p q = 0,8817
z(s) = ( 0,1536 - 0,1125 ) / √ 0,1043 ( 1/ 2160 + 1 / 358)
z(s) = 0,0411 /√ 0,1043*0,003256
z(s) = 0,0411 / 0,01843
z(s) = 2,23
Then z(s) > z(c) 2,23 > 1,64
z(s) is in the rejection region we reject H₀
If we construct a CI for 0,95 α = 0,05 α/2 = 0,025
z (score ) is from z- table z = 1,96
CI = ( p ± z(0,025*SE)
CI = ( 0,1536 ± 1,96*√ 0,1043*0,003256 )
CI = ( 0,1536 ± 1.96*0,01843)
CI = ( 0,1536 ± 0,03612 )
CI = ( 0,11748 ; 0,18972 )
In the new CI we don´t find 0 value so we have enough evidence to reject H₀
Which of the following is represented by MN ?
A.
Radius of the circle
B.
Diameter of the circle
C.
A chord of the circle
D.
Circumference of the circle
Answers
Answer:
A
Step-by-step explanation:
That is the radius. Since its half of the diameter.
Answer:
A. Radius of the circle
Step-by-step explanation:
A line segment that has as endpoints the center of a circle and a point on the circle is called a radius.
Answer: A. Radius of the circle
Please answer this correctly without making mistakes
Answers
Answer:
1.2 miles
Step-by-step explanation:
5.3 - 4.1 = 1.2 miles
Answer:
1.2 milesStep-by-step explanation:
5.3 - 4.1 = 1.2
1.2 miles difference.
This is because from Washington to Lanberry it is 4.1 miles. From Washington to Newberry it is 5.3., SO, if you subtract it you will get 1.2 miles difference.
Hope this helped,
kavitha
The population of a city can be modeled with a linear equation Y equals -80 X +3450 where X is the number of years after 2000 and why is the cities population by the description of the cities population based on equation
Answers
Answer:
retype that im not understanding .
Step-by-step explanation:
How many real roots and how many complex roots exist for the polynomial
F(x) - X4+ x2 - 5x2 + x -- 6?
O A. 2 real roots and 2 complex roots
B. O real roots and 4 complex roots
O c. 3 real roots and 1 complex root
D. 4 real roots and 0 complex roots
Answers
Answer:
D. 4 real roots and 0 complex roots
Step-by-step explanation:
If I assume that the function you are saying is
[tex]F(x)=x^4+x^3-5x^2+x-6[/tex]
There should be up to "4 roots," there can't be more or less than 4 total solutions. First, we need to check how many sign changes are there in this function. There are 3 positive real roots. Now lets check for negative roots.
[tex]F(-x)=x^4-x^3-5x^2-x-6[/tex]
There are is only 1 negative real root. Since we basically have 4 real roots, and the max is 4. There should be 4 real roots and 0 complex roots.
What is the density of a brownie the shape of a cube weighing 15 grams measuring 5 cm on a side?
Answers
Answer:
0.12 g/cm³
Step-by-step explanation:
Density is the ratio of mass to volume. The volume of the brownie is the cube of its side dimension:
V = s³ = (5 cm)³ = 125 cm³
Then the density is ...
ρ = M/V = (15 g)/(125 cm³) = 0.12 g/cm³
The density of the brownie is 0.12 g/cm³.
If y>0, which of these values of x is NOT in the domain of this equation? y=x2+7x
Answers
Answer:
[tex]\boxed{\sf \ \ \ [-7,0] \ \ \ }[/tex]
Step-by-step explanation:
Hello
[tex]y=x^2+7x=x(x+7) >0\\<=> x>0 \ and \ x+7 >0 \ \ or \ \ x<0 \ and \ x+7<0\\<=> x>0 \ \ or \ \ x<-7\\[/tex]
So values of x which is not in this domain is
[tex]-7\leq x\leq 0[/tex]
which is [-7,0]
hope this helps
Write an equation of the line that passes through the point (–1, 4) with slope 2. A. y+1=−2(x−4) B. y+1=2(x−4) C. y−4=2(x+1) D. y−4=−2(x+1) CHOSE ONE!
Answers
Answer:
[tex]y-4=2\,(x+1)[/tex]
which agrees with answer C in your list of possible answers.
Step-by-step explanation:
We can use the general point-slope form of a line of slope m and going through the point [tex](x_0, y_0)[/tex]:
[tex]y-y_0=m(x-x_0)[/tex]
which in our case, given the info on the slope (2) and the point (-1, 4) becomes:
[tex]y-y_0=m\,(x-x_0)\\y-4=2\,(x-(-1))\\y-4=2\,(x+1)[/tex]
determine both the lower and upper limits of a 90% z-confidence interval for µ , the mean score for all students in the school district who are enrolled in gifted and talented programs.
Answers
Answer:
CI = ( μ - 1,64 * σ /√n ; μ + 1,64 * σ /√n )
Step-by-step explanation:
We assume Normal Distribution
For Confidence Interval, CI = 90 % and α = 10 %
α = 0,1 and α/2 = 0,05
So we will look for z score reciprocate to these values, at the two tails of the bell
z(α/2) = 1,64 at th right tail and -1,64 at the left
CI = ( μ ± 1,64 * σ /√n )
CI = ( μ - 1,64 * σ /√n ; μ + 1,64 * σ /√n )
(6/22 + 5/77) ^2 equalviant to in fraction form
Answers
Answer:
676/5929
Step-by-step explanation:
conditinal probability question. please help! :)
Answers
Answer:
P(A|B) = 1 / 6
Step-by-step explanation:
Assuming two fair sided dice with faces numbered 1 to 6.
By intuition, there can only be 6 possible outcomes, so probability is 1/6.
Illustration how to use conditional probability.
Given two events A, B, following is the equation of conditional probability
that A happens given B has already happened and observed.
P(A|B) = P( A intersect B ) / P(B)
In the given problem,
A = casting a double-six
B = casting a double
P(A) = (1 / 6) * (1 / 6) = 1/36
P(B) = (6/6) * (1/6) = 1/6
P(A|B) = 1/36 / (1/6) = 1/6
1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x) 2. If we multiply a polynomial by a constant, is the result a polynomial? 3. if deg(f+g) is less than both deg f and deg g, then must f and g have the same degree?
Answers
Answer:
1. k=0
2. yes, result is still a polynomial.
3. yes, f and g must have the same degree to have deg(f+g) < deg(f) or deg(g)
Step-by-step explanation:
1. for what constant k must f(k) always equal the constant term of f(x) for any polynomial f(x)
for k=0 any polynomial f(x) will reduce f(k) to the constant term.
2. If we multiply a polynomial by a constant, is the result a polynomial?
Yes, If we multiply a polynomial by a constant, the result is always a polynomial.
3. if deg(f+g) is less than both deg f and deg g, then must f and g have the same degree?
Yes.
If
deg(f+g) < deg(f) and
deg(f+g) < deg(g)
then it means that the two leading terms cancel out, which can happen only if f and g have the same degree.
I need the answer quick I have a time limit ( I only get an hour to complete the assignment heh )
Answers
Answer:
C (the third table, from the second picture).
Step-by-step explanation:
First, we need to find the slope of the graph.
Two conspicuous points are (0, -3) and (2, 1).
The slope is: (1 - -3) / (2 - 0) = (1 + 3) / 2 = 4 / 2 = 2.
A: In the table, the y-values increase by 2, while the x-values increase by 4. 2 / 4 = 1 / 2 = 0.5. The slope is not the same as the graph.
B: In the table, the y-values decrease by 2, while the x-values increase by 4. -2 / 4 = -1 / 2 = -0.5. The slope is not the same as the graph.
C: In the table, the y-values increase by 4, while the x-values increase by 2. 4 / 2 = 2 / 1 = 2. The slope is the same as the graph, so C is your answer.
D: In the table, the y-values decrease by 4, while the x-values increase by 2. -4 / 2 = -2 / 1 = -2. The slope is not the same as the graph.
Hope this helps!
Question 14 (5 points)
Which of the following gives the correct intercept points and vertex point for the function f(x) = x2 + 3x - 18?
A. y-intercept: (0,18); vertex point: ( – ; – 20_); xintercepts: (-3, 0) and (6,
0)
B. y-intercept: (0, -18); vertex point: (-1, – 19); x-intercepts: (-3, 0) and (-6,
0)
C. y-intercept: (0, -18); vertex point: ( - 2/3, - 20 1/4); x-intercepts: (3, 0) and (-
6,0)
D. y-intercept: (0, 18); vertex point: (-1, – 19); x-intercepts: (3,0) and (6, 0)
Answers
Answer:
C. y-intercept: (0, -18); vertex point: ( [tex]-\frac{2}{3}[/tex], [tex]-20\frac{1}{4}[/tex]); x-intercepts: (3, 0) and (-
6,0)
Step-by-step explanation:
Hope it helped
Answer:
C. y-intercept: (0, -18); vertex point: ( - 2/3, - 20 1/4); x-intercepts: (3, 0) and (-
6,0)
Step-by-step explanation:
It's a positive parabola, so that means it opens upward. Crossing the x-axis at -6 and 3 it's minimum is -20 and crosses the Y-axis at -18.
A survey of the average amount of cents off that coupons give was done by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20cents; 70cents; 50cents; 65cents; 30cents; 55cents; 40cents; 40cents; 30cents; 55cents; $1.50; 40cents; 65cents; 40cents. Assume the underlying distribution is approximately normal.
Construct a 95% confidence interval for the population mean worth of coupons .
What is the lower bound? ( Round to 3 decimal places )
What is the upper bound? ( Round to 3 decimal places )
What is the error bound? (Round to 3 decimal places)
Answers
Answer:
The lower bound = 35.443
The upper bound = 71.697
The error bound = 18.127
Step-by-step explanation:
We are given that a survey of the average amount of cents off that coupons gives was done by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News.
The following data were collected (X): 20cents; 70cents; 50cents; 65cents; 30cents; 55cents; 40cents; 40cents; 30cents; 55cents; 150 cents; 40cents; 65cents; 40cents.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean worth of coupons = [tex]\frac{\sum X}{n}[/tex] = [tex]\frac{750}{14}[/tex] = 53.57 cents
s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 31.40 cents
n = sample size = 14
[tex]\mu[/tex] = population mean worth of coupons
Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.
So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;
P(-2.16 < [tex]t_1_3[/tex] < 2.16) = 0.95 {As the critical value of t at 13 degrees of
freedom are -2.16 & 2.16 with P = 2.5%}
P(-2.16 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.16) = 0.95
P( [tex]-2.16 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}{[/tex] < [tex]2.16 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
P( [tex]\bar X-2.16 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.16 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95
95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.16 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.16 \times {\frac{s}{\sqrt{n} } }[/tex] ]
= [ [tex]53.57-2.16 \times {\frac{31.40}{\sqrt{14} } }[/tex] , [tex]53.57+2.16 \times {\frac{31.40}{\sqrt{14} } }[/tex] ]
= [35.443, 71.697]
Therefore, a 95% confidence interval for the population mean worth of coupons is [35.443, 71.697].
Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent the number of domestic stamps and let y represent the number of foreign stamps
Answers
Answer:
123 domestic stamps
89 foreign stamps
Step-by-step explanation:
Answer:
Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent the number of domestic stamps and let y represent the number of foreign stamps.
Which equation represents the total number of stamps Malik collected?
✔ x + y = 212
Which equation represents the difference in the number of foreign and domestic stamps Malik collected?
✔ x – y = 34
Which system of linear equations represents the situation?
✔ x – y = 34 and x + y = 212
Malik collects rare stamps and has a total of 212 stamps. He has 34 more domestic stamps than foreign stamps. Let x represent the number of domestic stamps and let y represent the number of foreign stamps.
This system of equations models the given information for both stamp types.
x – y = 34
x + y = 212
Solve the system of equations.
How many foreign stamps does Malik have?
✔ 89 foreign stamps
How many domestic stamps does Malik have?
✔ 123 domestic stamps
Step-by-step explanation:
its right on 2021 edge! :) hope this helps
Does the ordered pair (1,1) satisfy the following system of inequalities? {x−8y≤9−7x+5y<4
Answers
Answer:
YESStep-by-step explanation:
Substitute x = 1 and y = 1 to the both inequalities:
[tex]x-8y\leq9\\\\1-8(1)\leq9\\1-8\leq9\\-7\leq9\qquad\bold{TRUE}\\==================\\-7x+5y<4\\\\-7(1)+5(1)<4\\-7+5<4\\-2<4\qquad\bold{TRUE}[/tex]
Answer:
(1,1) does satisfy
x - 8y ≤ 9
- 7x + 5y < 4
Step-by-step explanation:
Well, first we need to plug in (1,1) into,
x - 8y ≤ 9
- 7x + 5y < 4
→ 1 - 8(1) ≤ 9
- 7(1) + 5(1) < 4
1 - 8 ≤ 9
-7 + 5 < 4
-7 ≤ 9
-2 < 4
Thus,
(1,1) does satisfy
x - 8y ≤ 9
- 7x + 5y < 4.
Hope this helps :)
Find the equation, in standard form, of the line passing through the points
(2,-3) and (4,2).
Answers
Answer:
Standard form = y = mx + c
m = Δy/Δx
m = 5/2
y = 5/2 x + c
Sub in (4,2)
2 = 10 + c
c = -8
y = 5/2 x - 8
Step-by-step explanation:
If mZNOM = 30°, then what is the length of the minor arc
NM?
Answers
Answer:
Option (B)
Step-by-step explanation:
To determine the length of arc of a circle we use the formula,
Length of arc = [tex]\frac{\theta}{360}(2\pi r)[/tex]
Where θ = measure of the central angle subtended by the arc
r = radius of the circle
For the circle given in the picture attached,
Length of arc NM = [tex]\frac{30}{360}(2\pi)(2)[/tex]
= [tex]\frac{4\pi }{12}[/tex]
= [tex]\frac{\pi }{3}[/tex]
Therefore, length of [tex]\widehat{NM}=\frac{\pi }{3}[/tex]
Option (B) will be the answer.
Answer: C
Step-by-step explanation:
4#/12 = #
Choose the correct equation for the parabola based on the given information. Given: Focus:(2,8) Directrix: y = 4 a. 2(y-2)= (x- 6)^2 b. 8(x -2) = (y -6)^2 c. 8(y - 6)= (x-2)^2 d. 2(x-2)= (y-8)^2
Answers
Explanation:
The directrix is horizontal, so the axis of symmetry is vertical. We'll have an x^2 term. The vertical distance from y = 4 to y = 8 is 4 units. Cut this in half to get 2, which is the focal distance p = 2.
The point (2,4) is directly below (2,8), and the point is on the directrix. The midpoint between (2,4) and (2,8) is (2,6). This is the vertex.
(h,k) = (2,6)
4p(y-k) = (x-h)^2
4*2(y-6) = (x-2)^2
8(y-6) = (x-2)^2
Each marble bag sold by Carmen's Marble Company contains 3 purple marbles for every 4 blue marbles. If a bag has 28 blue marbles, how many purple marbles does it contain?
Answers
Answer:
21 purple marbles
Step-by-step explanation:
my explanation is i looked at it like a ratio so ¾= x/28
then i took 28 ÷ 4 which equals 7, then i took 7 and multiplied it by 3 which gave me 21, so the answer is 21 purple marbles
Suppose that f(x,y) is a smooth function and that its partial derivatives have the values, fx(8,5)=2 and fy(8,5)=2. Given that f(8,5)=−2, use this information to estimate the value of f(9,6).
Answers
Answer:
f(9,6) = 2
Step-by-step explanation:
We know df = (df/dx)dx + (df/dy)dy
From the question, df/dx = fx(8,5) = 2 and df/dy = fy(8,5) = 2
Since we need to find f(9,6) and f(8,5) = -2
dx = 9 - 8 = 1 and dy = 6 - 5 = 1
f(9,6) = f(8,5) + df
df = (df/dx)dx + (df/dy)dy
df = fx(8,5)dx + fy(8,5)dy
Substituting the values of fx(8,5) = 2, fy(8,5) = 2, dx = 1 and dy = 1
df = 2 × 1 + 2 × 1
df = 2 + 2
df = 4
f(9,6) = f(8,5) + df
substituting the value of df and f(8,5) into the equation, we have
f(9,6) = -2 + 4
f(9,4) = 2
The value of f(9,6) = 2
What is the vertex of this parabola y=-5x^2-10x-13
Answers
Step-by-step explanation:
Vertex for your equation is (-1, -8)
Set up a rational equation and then solve the following problems. A positive integer is twice another. The difference of the reciprocals of the two positive integers is 1/18. Find the two integers.
Answers
Answer:
9 and 18
Step-by-step explanation:
2x and x are the numbers
1/x-1/2x=1/18
2/2x-1/2x=1/18
1/2x=1/18
2x=18X=9,
2x=18
The two integers are 9 and 18
For functions f(x)=2x^2−4x+3 and g(x)=x^2−2x−6, find a. (f+g)(x) b. (f+g)(3).
Answers
Answer:
a) 3x^2-6x-3
b) 6
Step-by-step explanation:
f(x)=2x^2−4x+3
g(x)=x^2−2x−6
a) (f+g)(x) = (2x^2−4x+3) + (x^2−2x−6)
collect like terms
(f+g)(x) = 2x^2+x^2-4x-2x+3-6
(f+g)(x) = 3x^2-6x-3
b) (f+g)(3). This implies that x=3
recall (f+g)(3) = 3x^2-6x-3
(f+g)(3) = 3(3)^2-6(3)-3 = 27-18-3
(f+g)(3) = 27-21 =6
How many ways can 3 boys and 2 girls stand in a row so that the two girls are not next to each other?
Answers
Answer:
3 ways← key b=boy g=girlStep-by-step explanation:
b g b gg b b gg b g bgive brainllest please °∩°
Hope it helps
Please mark my answer as BRAINLIEST
slope=4/3 find the equation of the parallel line through (5,5)
Answers
Answer:
[tex]y=\frac{4}{3}x-1.75[/tex]
Step-by-step explanation:
If the slope of a line is 4/3,
and we wanna find the equation of a line that is parallel to it and crosses through (5,5).
So we already have the slope because the slope of 2 parallel lines are the same.
y = 4/3x
Look at the image below↓
So now we just need to find the y-intercept.
After some numbers we got,
[tex]y=\frac{4}{3}x-1.75[/tex]
Look at the other image below↓
Thus,
the equation of the parallel line is [tex]y=\frac{4}{3}x-1.75[/tex].
Hope this helps :)
