The sum of two point charges is -15µC. They attract each other with a force of 9 x 10-2 N when kept 5m apart. Find their charges.​

The Sum Of Two Point Charges Is -15C. They Attract Each Other With A Force Of 9 X 10-2 N When Kept 5m

Answers

Answer 1

According to the question the two charges are -7.5 µC and -7.5 µC.

What is charges?

Charges are fees or payments for services or goods. Charges can be one-time payments, recurring payments, or fees associated with using a product or service. Charges can be for products, services, or activities. Examples of charges include fees for using a credit card, fees for using a bank account, fees for renting a car, fees for using a mobile phone plan, fees for using a subscription service, fees for using a streaming service, and fees for using a gym membership.

Let the two charges be x and ( -15 - x ) µC.

According to Coulomb's law,

F = (k × x × ( -15 - x ))/r2

Where k is the Coulomb's constant,

k = 9 × 109 N × m2/C2

Given, F = 9 × 10-2 N

r = 5 m

Substituting these values in the equation,

9 × 10-2 = (9 × 109 × x × ( -15 - x ))/252

⇒ x2+ 15x - 4.5 × 10-4 = 0

Solving this equation,

x = -7.5 µC and ( -15 - x ) = -7.5 µC

Therefore, the two charges are -7.5 µC and -7.5 µC.

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Related Questions

What is the calculated radius of an electron beam when the accelerating voltage
is 150 V and the coil current is 1.3 A?

Answers

The radius of the electron beam when the accelerating voltage is 150 V and the coil current is 1.3 A is 0.0054 meters.

What is an electron beam?

An electron beam is known as a stream of electrons that an electric field has rapidly accelerated. It is commonly produced by an electron cannon, which releases electrons from a heated cathode and accelerates and concentrates the electron beam using a series of electrodes.

The following equation can be used to determine an electron beam's radius: r = (m x v / (B x q)

r is the radius of the beam

m is the mass of the electron

v is the velocity of the electron

B is the magnetic field strength

q is the charge of the electron

Finding the electron's velocity is necessary to solve for the electron beam's radius. The rate of an electron can be determined using the following equation:

v = (2 x e x V / m)²

e is the electron's basic charge.

V is the accelerating voltage

m is the mass of the electron

v =  [tex]\sqrt{2 * 1.602 * 10 ^{-19} * 150 / 9.109 * \ 10^{-31}[/tex]

= 3.23 x  m/s

The radius can now be obtained by substituting this value into the first equation together with the other supplied values:

r = (9.109 x 10⁻³¹ kg × 3.23 x 10⁶ m/s) / (0.2 T × 1.602 x 10⁻¹⁹ C)

= 0.0054 m

As a result, the electron beam's calculated radius is around 0.0054 meters.

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Suppose that you and your friend are inertial observers (that is, both reference
frames are inertial) with relative velocity c=2. Your watches both \tick" t = 0 at
the instant that you pass each other
(a) Draw the two worldlines on a spacetime diagram in your frame of reference,
and draw and label (i) the event where your watch \ticks" t = 1 second and
(ii) the event where your friend's watch \ticks" t = 1 second. At what time
is the second event in your reference frame? Did you draw it in the right
place?
(b) On the same diagram, sketch the line of events which are at t = 1 second
as determined by your frame of reference. This is your t = 1 second line of
simultaneity.
(c) On the same diagram, sketch the line of events which are at t = 1 second
as determined by your friend's frame of reference. (Hint: At what time in
your frame of reference does his watch tick t = 1 second?) This is your
friend's t = 1 second line of simultaneity.
(d) Consider the event where your friend's t = 1 second line of simultaneity
crosses your worldline. What time does your friend assign to this event?
What time do you assign to this event?
(e) Consider the event where your t = 1 second line of simultaneity crosses your
friend's worldline. What time do you assign to this event? What time does
your friend assign to this event?

Answers

Two inertial observers with relative velocity c=2 have different time measurements due to time dilation and relativity of simultaneity.

Define time dilation ?

Time dilation is a phenomenon predicted by Einstein's theory of relativity, where time appears to pass slower for an observer in motion relative to a stationary observer.

a) The event where your watch ticks t=1 second would be one second above your worldline, and the event where your friend's watch ticks t=1 second would be 2 seconds to the left of that point on your friend's worldline. Therefore, the event where your friend's watch ticks t=1 second is at t=-1 seconds in your reference frame. The event is drawn correctly.

b) To sketch the line of events at t=1 second as determined by your frame of reference, we draw a horizontal line across the diagram one second above your worldline. This line represents all events that are simultaneous with your watch ticking t=1 second.

c) To sketch the line of events at t=1 second as determined by your friend's frame of reference, we first need to find out at what time in your frame of reference his watch ticks t=1 second. Since your friend's watch is moving with velocity c=2 relative to you, time dilation occurs, and his watch appears to tick slower than yours. Therefore, the time in your frame of reference when his watch ticks t=1 second is given by:

[tex]t' = t / \sqrt{(1 - v^2/c^2)} = 1 \sqrt{(1 - 2^2/3^2)} = 3/5 seconds[/tex]

So, the line of events at t=1 second in your friend's frame of reference is a diagonal line sloping upwards to the right with a slope of 3/2.

d) The event where your friend's t=1 second line of simultaneity crosses your worldline is the event where your friend sees your watch ticking t=1 second. In your frame of reference, this event occurs at t'=1/5 seconds (since your friend's watch appears to tick slower). In your friend's frame of reference, he assigns a time of t=2 seconds to this event, since that is the time shown on his watch when he sees your watch ticking.

e) The event where your t=1 second line of simultaneity crosses your friend's worldline is the event where you see your friend's watch ticking t=1 second. In your frame of reference, this event occurs at t'=1/5 seconds. In your friend's frame of reference, he assigns a time of t=-2 seconds to this event, since that is the time shown on your friend's watch when you see his watch ticking.

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22. A rock is thrown straight up with an initial velocity of 24.5 m/s. What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80 m/s².)
a. 9.80 m
b. 19.6 m
c. 24.5 m
d. 30.6 m​

Answers

Answer:

(d) 30.6 m

Explanation:

We can use the kinematic equation to find the maximum height reached by the rock:

vf^2 = vi^2 + 2ad

where vf is the final velocity (which is zero at the maximum height), vi is the initial velocity, a is the acceleration due to gravity, and d is the displacement (the maximum height reached).

Substituting the given values, we get:

0 = (24.5 m/s)^2 + 2(-9.80 m/s^2)d

Solving for d, we get:

d = (24.5 m/s)^2 / (2 × 9.80 m/s^2)
= 30.6 m

Therefore, the maximum height reached by the rock before starting to fall downward is 30.6 m.

.

18 question check the photo and answer me

Answers

Q 17. The high-temperature reservoir has a temperature of 689.39°C.

Q 18. (Rounded to two decimal places) The frictional coefficient between the plane and the body is 0.51.

How to calculate temperature and frictional coefficient?

For Q17:

Efficiency of real engine = 80% of efficiency of Carnot engine

η_real = 0.8η_Carnot

Efficiency of Carnot engine = 1 - T_Low/T_High

η_Carnot = 1 - (273+30)/(T_High+273)

Output power of engine = rate of heat discharge into low temp reservoir x efficiency

250 W = 450 J/s x 0.8η_Carnot

η_Carnot = 0.6944

0.6944 = 1 - 303/T_High

T_High = 962.39 K

Temperature of high-temperature reservoir = 962.39 - 273 = 689.39°C

Therefore, the temperature of the high-temperature reservoir is 689.39°C.

For Q18:

Let u be the initial velocity of the body

Let f be the frictional coefficient between the plane and the body

Let g be the acceleration due to gravity

Using the equations of motion:

Time of ascent = t₁ = usin30/g

Time of descent = t₂ = usin30/g

Given that t₁ = (1/2)t₂

Therefore, t₂ = 2t₁ = 2×(u×sin30/g)

Using the law of conservation of energy:

Initial kinetic energy + initial potential energy = final kinetic energy + final potential energy + work done against friction

(1/2)3u² + 39.81usin30 = (1/2)3(ucos30)² + 0 + f39.81×cos30

Simplifying this equation:

(3/2)u² + 44.145u - 44.145×f = 0

Given that t₁ = (1/2)t₂:

t₁ = usin30/g = (1/2)usin30/g

Simplifying this equation:

u² = (2g×sin30)t1

u^2 = 9.81t1

Substituting this value of u² in the previous equation:

(3/2)9.81t₁ + 44.145√(9.81t1) - 44.145×f = 0

Solving for f:

f = 0.505 Ns/m

Therefore, the frictional coefficient between the plane and the body is 0.51 (rounded to two decimal places).

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Which of the following shows evidence of the carbon cycle?
a. A fox getting its energy from a mouse and a mouse getting its energy
from the grass.
b. Plants growing in a greenhouse.
c. Water falling as rain then evaporating back into the atmosphere.
d. A river flowing to the ocean.

Answers

A fox getting its energy from a mouse and a mouse getting its energy from the grass  shows evidence of the carbon cycle

What is the carbon cycle?

The carbon cycle is a necessary component within the global interchange between living species and the environment.

Through photosynthesis, plants absorb carbon dioxide from the atmosphere and convert it into vitalizing organic matter for consumption by animals; these organisms expend the energy obtained and consequently expel carbon dioxide back up into the air via respiration.

Moreover, when animals meet their demise and decompose, the carbon in their bodies is redeposited into Earth's soil only to eventually be delivered once again to the atmosphere through erosive activities or those generated from volcanoes.

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an object is placed at a distance of 27.0 cm away from a thin convex lens with a focal length of 9.00 cm. how far from the lens is the image located and what type of image is formed ?

Answers

Answer:

The image formed by a thin convex lens with a focal length of 9.00 cm when an object is placed at a distance of 27.0 cm away from the lens is located 18 cm away from the lens. The image formed is an upright, virtual image.

can you give me the brilliant mark?

Answer:

di = 13.5 cm

Virtual image and upright


Explanation:

We can use the thin lens equation to determine the location of the image formed by a thin convex lens:

1/f = 1/do + 1/di

where f is the focal length of the lens, do is the distance of the object from the lens, and di is the distance of the image from the lens.

Substituting the given values, we get:

1/9 = 1/27 + 1/di

Simplifying and solving for di, we get:

1/di = 1/9 - 1/27 = 2/27

di = 27/2 = 13.5 cm

Therefore, the image is located 13.5 cm away from the lens.

To determine the type of image formed, we can use the following rules:

If di is positive, the image is real and located on the opposite side of the lens from the object.
If di is negative, the image is virtual and located on the same side of the lens as the object.
If di is greater than do, the image is inverted.
If di is less than do, the image is upright.
Substituting the values we have found, we get:

di - do = 13.5 cm - 27.0 cm = -13.5 cm

Since di is negative, the image is virtual and located on the same side of the lens as the object. Also, since di is less than do, the image is upright.

Therefore, the image formed by the thin convex lens is a virtual and upright image located 13.5 cm away from the lens.

An object of mass 3.0 kg is attached to the hook of a spiral balance and the balance is suspended from the roof of a lift. What is the reading on the spring balance when the lift goes down with an acceleration of 0.1 m/s2​

Answers

The force acting on the object is the weight of the object, which is given by:

F = m * g

where m = 3.0 kg is the mass of the object and g = 9.81 m/s^2 is the acceleration due to gravity.

F = 3.0 kg * 9.81 m/s^2 = 29.43 N

The net force acting on the object when the lift goes down is the difference between the weight of the object and the force required to accelerate it downward:

Fnet = F - m * a

where a = 0.1 m/s^2 is the acceleration of the lift.

Fnet = 29.43 N - 3.0 kg * 0.1 m/s^2 = 29.13 N

The reading on the spring balance is equal to the net force acting on the object, which is 29.13 N.

reflection in general physics

Answers

Explanation:

Reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves.

A 50.0kg football player strikes a 75.0kg tackle dummy causing it to accelerate at 3.00 m/s2. What is the force on the football player?

Answers

Answer:

We can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration, to solve this problem.

The force on the tackle dummy can be calculated as follows:

F = m * a

F = 75.0 kg * 3.00 m/s^2

F = 225 N

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, the force on the football player is also 225 N, but in the opposite direction to the force on the tackle dummy.

So the force on the football player is 225 N, directed opposite to the direction of the tackle dummy's acceleration.

mark me brilliant

Final answer:

The force on the football player is 150.0N.

Explanation:

To calculate the force on the football player, we can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration. In this case, the mass of the football player is 50.0kg and the acceleration is 3.00 m/s2. Therefore, the force on the football player is:

Force = mass x acceleration

Force = 50.0kg x 3.00 m/s2

Force = 150.0 N

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3. The hydraulic jack is filled with oil as shown in the figure 9 below. If F1 = 2580 N is applied piston with diameter d₁ = 5 cm and d2 = 10 cm. Calculate the force applied to a large piston F2. A. 1.34 x 108 N 5 cm diaricte Figure 9 10 cm diameter Vertical 01 S 0.85) [2]​

Answers

Answer:

The force applied to the large piston is 1.34 x 10^8 N.

The horizontal surface on which the block slides is frictionless. If F-23 N and M-5,0 kg, what is the magnitude of the resulting acceleration of the block?

Answers

The magnitude of resulting acceleration of the block on frictionless surface is found to be 3.99 m/s².

The force applied at an angle can be resolved into its components along the x and y directions,

Fx = Fcos(30°)

Fx = (23N)cos(30°)

Fx = 19.95 N

Fy = Fsin(30°)

Fy= (23N)sin(30°)

Fy = 11.5 N

Since the horizontal surface is frictionless, the only force acting on the block is the component of the applied force in the x direction. Therefore, the net force acting on the block is Fnet = Fx.

Fx = 19.95 N

Using Newton's second law of motion, we can find the acceleration of the block Fnet = Ma, mass of the block is M and resulting acceleration is a. Solving for a, we get,

a = Fnet / M

a = 19.95 N/5.0 kg ≈ 3.99 m/²

Therefore, the magnitude of the resulting acceleration of the block is approximately 3.99 m/s².

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An 8.0-kg block is released from rest on a rough incline. The block moves a distance of 1.6-m down the incline, in a time interval of 0.80 s, and acquires a velocity of v2 = 4.0 m/s. How much work does gravity do on the block during this process?

Answers

Gravity does 62.72 J of work on the block during this process.

What is work done?

Work is defined as the energy transferred to or from an object by the application of a force over a distance. In other words, work is done when a force acts on an object to cause it to move in the direction of the force.

To calculate the work done by gravity on the block, we need to find the change in the gravitational potential energy of the block as it moves down the incline. We can do this by using the formula:

ΔU = mgh

where ΔU is the change in potential energy, m is the mass of the block, g is the acceleration due to gravity, and h is the height change of the block.

The height change of the block is equal to the vertical distance it moves down the incline, which can be found using trigonometry:

h = d sin θ

where d is the distance the block moves down the incline and θ is the angle of the incline.

We are given that the block moves a distance of 1.6 m down the incline, but we are not given the angle of the incline. However, we can use the given information about the block's velocity to find the angle.

The block starts from rest and acquires a velocity of 4.0 m/s after moving a distance of 1.6 m in 0.80 s. We can use the kinematic equation:

v2 = v1 + 2ad

where v1 is the initial velocity (which is zero), a is the acceleration, and d is the distance.

Rearranging this equation gives:

a = (v2 - v1) / (2d) = 5.0 m/s^2

The acceleration of the block is equal to the component of gravity parallel to the incline, which is g sin θ, where g is the acceleration due to gravity (9.8 m/s^2). So we have:

g sin θ = a

sin θ = a / g = 0.51

Taking the inverse sine of both sides gives:

θ = 30°

Now we can calculate the height change of the block:

h = d sin θ = 1.6 m * sin 30° = 0.8 m

Finally, we can calculate the work done by gravity:

ΔU = mgh = (8.0 kg) * (9.8 m/s^2) * (0.8 m) = 62.72 J

Therefore, gravity does 62.72 J of work on the block during this process.

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If I add 38444 J of energy to an ideal gas inside a balloon, causing the internal energy to increase by 7949 J, how much work is done on the environment by the gas as the balloon expands?

Answers

The work done on the environment by the gas as the balloon expands is 30495 J.

Define work done ?

In physics, work is defined as the energy transferred when a force applied to an object moves that object. In other words, work is done on an object when a force causes a displacement in the direction of the force.

According to the first law of thermodynamics:

ΔU = Q - W,

where ΔU is the change in internal energy of the gas, Q is the heat added to the gas, and W is the work done by the gas on the environment.

In this problem, ΔU = 7949 J and Q = 38444 J. Solving for W, we get:

W = Q - ΔU = 38444 J - 7949 J = 30495 J

Therefore, the work done on the environment by the gas as the balloon expands is 30495 J.

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A light rigid rod with two masses attached to its ends is pivoted about a horizontal axis into the page. The system rotates with a constant angular velocity w. What is the angular momentum of the system?

Answers

The angular momentum of the system is given by the product of the moment of inertia and the angular velocity. Since the rod is light and rigid, we can consider the two masses as point masses located at the ends of the rod.

Let m1 and m2 be the masses at the ends of the rod, and let r be the distance from the axis of rotation to each mass. The moment of inertia of each mass about the axis of rotation is given by I = mr^2. Since the masses are symmetrically arranged about the axis of rotation, the total moment of inertia of the system is I = 2mr^2.

The angular momentum of each mass is L = Iw = 2mr^2w. The angular momentum of the system is the sum of the angular momentum of each mass, so we have:

L_total = L1 + L2 = 2mr^2w + 2mr^2w = 4mr^2w

Therefore, the angular momentum of the system is 4mr^2w

What is one danger that astronauts would face going to the moon, visiting the moon, or returning to Earth?​

Answers

One danger that astronauts would face going to the moon, visiting the moon, or returning to Earth is exposure to radiation. The space environment exposes astronauts to high levels of ionizing radiation from cosmic rays and solar flares, which can damage their DNA and increase their risk of developing cancer or other health problems. Additionally, during a moon landing or takeoff, astronauts are exposed to radiation from the lunar surface, which contains radioactive elements such as uranium and thorium. To minimize this risk, spacecraft and spacesuits are designed to provide some protection from radiation, and astronauts are carefully monitored for radiation exposure.

Look at the simple machine shown below and determine the mechanical
advantage.
3.4m
A. 3.0
OB. 4.9
C. 0.2
D. 1.4
0.7 m

Answers

The basic machine in the question has a mechanical advantage of 4.9, B.

How to determine mechanical advantage?

To determine the mechanical advantage of the simple machine, use the formula:

Mechanical Advantage (MA) = output force / input force

Use the formula for the lever arm:

lever arm = distance from pivot to point of force

For the input force, the lever arm is 0.7 meters. For the output force, the lever arm is 3.4 meters.

So, the mechanical advantage is:

MA = output force / input force = lever arm of output force / lever arm of input force = 3.4 / 0.7 = 4.9

Therefore, the mechanical advantage of the simple machine shown in the question is 4.9.

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The practice of science can answer only scientific questions. And scientific questions guide the design of investigations. What is usually true of the possible answers to a scientific question?

Answers

Scientific question can be resolved by experimentation, observation, or other data collection methods.

A scientific investigation is an effort to use the scientific method to resolve a topic.

Since, they must be testable and objective, scientific questions vary from other types of questions. This implies that a scientific theory must be able to be frequently verified as true.

By examining quantifiable data and supporting evidence, it can be resolved by experimentation, observation, or other data collection methods.

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During a wild fire in a forest of the Rocky Mountains, the trunks of some dry oak trees (k 0.17 W/m-K and a 1.28 x 107 m²/s) that are initially at a uniform temperature of 303 K are exposed to hot gases at 623 K for a period of 4 hours, with a heat transfer coefficient of 65 W/ m² - K on the surface. The ignition temperature of the trees is 583 K. Treating the trunks of the trees as 1D rectangular slabs with a thickness of D-0.2 m. (1) Write down the differential equation and the corresponding initial and boundary conditions to describe the temperature distribution with time and space across the slab. (ii) Nondimensionalize the equation​

Answers

The nondimensional initial and boundary conditions are: At ξ=0, θ(0,t)=0, At ξ=1, θ(1,t)=1 ,At t=0, θ(ξ,0)=0

What is boundary?

A boundary is an imaginary line that marks the limits of an area. It is used to separate different areas and to define ownership. Boundaries can be physical, such as a fence or an invisible line that marks a property line. Boundaries can also be social, such as the division between two countries or cultures.

(i) The 1-D steady-state energy equation for conduction of heat in a slab is:

d2T/dx2 = (1/k) (q''/A)

where T is the temperature, x is the position, k is the thermal conductivity, q'' is the heat flux per unit area, and A is the area of the slab.

The initial and boundary conditions for the slab are:

At x=0, T(0,t)=T0=303 K

At x=D, T(D,t)=T1=623 K

At t=0, T(x,0)=T0=303 K

(ii) Nondimensionalizing the equation, we obtain:

d2θ/dξ2 = (1/β) (Φ/A)

where θ is the nondimensional temperature (θ=T-T0)/(T1-T0), ξ=x/D is the nondimensional position, β=kD/[A(T1-T0)] is the Biot number, and Φ=q''D/(A(T1-T0)) is the nondimensional heat flux.

The nondimensional initial and boundary conditions are:

At ξ=0, θ(0,t)=0

At ξ=1, θ(1,t)=1

At t=0, θ(ξ,0)=0

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which step should be completed next

Answers

Answer: The answer would be B since the students have only tested the smaller ramp so far.

Explanation:

Before modern astronomy and the advancement of technology, all objects that were not sharp points of light were given the same name, rebuläe. Which means what in latin?

Answers

I'm sorry, but I'm not aware of the word "rebuläe" in Latin or any other language. It doesn't appear to be a commonly used word or term in the context of astronomy, either. However, the word "stellae" in Latin refers to stars, and it's possible that this is the word you're thinking of. Before the development of modern astronomy, all objects in the night sky that were not sharp points of light, including planets and other celestial bodies, were often referred to as "wandering stars" or "planets." It wasn't until the development of more advanced telescopes and astronomical instruments that these objects could be studied and identified more accurately.

You should now have one more object to place on the cardboard. Using the task 1 setup and the additional object, plan a controlled experiment to investigate how changing the mass of an object changes its acceleration. The net force on the object must stay the same. Record your plan here. BIUX² X₂ 15px V A 三 三 三​

Answers

If the mass of the object is high then there will be less acceleration and vice verse. mass is offers inertia and resistance to motion of the object. high mass leads to high force to produce acceleration.

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force. Balanced forces are those forces which are opposite in direction and equal in magnitude. When Net force acting on a body is zero then we call it as balanced force. Balanced force is not responsible for the motion of the body. ex. when two persons pulling rope on both end with equal magnitude which cause them to be balanced force have 0 net force.

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which best describe thermal energy

Answers

Answer: Thermal energy is a physical content thermal energy can come from friction or something hot or cold

Explanation:

i go a 100 on my thermal energy quiz

(ii) Given instead that G=0 and the forces are in equilibrium, find the values of F and alpha

Answers

If G = 0 and the forces are in equilibrium, then the net force on the object must be 0. This means that the sum of the forces must be 0. The values of F and α are 8N and -19.47° .

What is force ?

Force is a physical quantity that describes the interaction between two or more objects. It is a vector quantity, meaning it has both magnitude and direction. Forces can cause an object to accelerate, decelerate, change direction, or remain in its current state of motion. Some examples of forces include gravity, friction, and electromagnetic forces. Force is one of the most fundamental concepts in physics and is the basis of many physical phenomena. It is essential to understand forces in order to understand how the universe works.

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A driver of a car going at 25 ms−1suddenly notices a train blocking the road. At the instant the brakes are applied, the train is 60 m away. The car decelerates uniformly and strikes the train 3 s after. With what speed did the car strike the train?

Answers

We can use the following kinematic equation:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

First, we need to find the acceleration of the car. We know that it decelerates uniformly, so we can use the formula:

a = (v-u)/t

where u = 25 m/s (initial velocity), v = 0 (final velocity), and t = 3 s (time taken to stop the car).

a = (0 - 25)/3 = -8.33 m/s^2 (negative sign indicates deceleration)

Next, we can use the formula for distance travelled during uniform acceleration:

s = ut + (1/2)at^2

where s is the distance travelled, u is the initial velocity, a is the acceleration, and t is the time.

We need to find the distance travelled by the car before it hits the train. Let's call this distance x.

x = ut + (1/2)at^2 = 25(3) + (1/2)(-8.33)(3)^2 = 37.5 m

Now we know that the car and the train collide when the car has travelled a distance of 60 m + 37.5 m = 97.5 m.

Finally, we can use the same kinematic equation as before to find the final velocity of the car when it hits the train. This time, u = 25 m/s (initial velocity), a = -8.33 m/s^2 (deceleration), t = 6 s (time taken to travel 97.5 m).

v = u + at = 25 + (-8.33)(6) = -10 m/s

The negative sign means that the car is moving in the opposite direction to its initial velocity, i.e. towards the train. So the speed at which the car strikes the train is:

|v| = |-10| = 10 m/s

Therefore, the car strikes the train at a speed of 10 m/s.

The final velocity with which the car strike the train is 15 m/s.

What is meant by velocity ?

Velocity of an object is the time rate of change of displacement covered by the object.

Here,

Initial velocity of the car, u = 25 m/s

Time taken, t = 3 s

Displacement of the car after applying the brake, s = 60 m

The average velocity ,

v' = displacement/time

v' = s/t

Also, the average velocity can be given as,

v' = (u + v)/2

So,

s/t = (u + v)/2

Therefore, the final velocity with which the car strike the train,

v = (2s/t) - u

v = (2 x 60/3) - 25

v = 15 m/s

Hence,

The final velocity with which the car strike the train is 15 m/s.

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The potential difference of a cell or battery tells you the size of the _____, and how much _____ can be transferred by the charges.


Chapter: Potential Difference

Answers

The potential difference of a cell or battery tells you the size of the voltage, and how much energy can be transferred by the charges.

What is energy?

Energy is the ability to do work. It is a fundamental part of nature and it takes several different forms. These forms include kinetic energy, potential energy, thermal energy, electrical energy, chemical energy, and nuclear energy. Kinetic energy is the energy of motion and it can be found in moving objects. Potential energy is the stored energy an object has due to its position or state. Thermal energy is heat and it is related to the motion of molecules. Electrical energy is the energy of electric current and it is carried by electrons. Chemical energy is the energy stored in the bonds of atoms and molecules. Nuclear energy is the energy stored in the nucleus of an atom, released through nuclear reactions such as fission and fusion. In order to do work, energy must be transformed from one form to another. This is done through energy conversion, which involves the transfer of energy from one form to another.


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Answer:

The potential difference of a cell or battery tells you the size of the voltage, and how much energy can be transferred by the charges.

Explanation:

Potential difference is defined as the amount of work done per unit charge in moving a charge from one point to another in an electric field. In the case of a cell or battery, the potential difference between its terminals is a measure of the electrical energy that can be transferred by the charges as they flow through an external circuit. The higher the potential difference, the more electrical energy can be transferred per unit charge.

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A crate of aluminum recyelables (mass m =4.00 kg ) is launched from rest by a spring that is compressed by 25.0 cm. The spring constant is 2750 N/m. The first crate collides With a second crate that is initially at rest. Immediately after the collision, the first crate bounces off to the left at 1.50 m/s, and the second crate slides to the right at 4.50 m/. The second crate then collides and sticks to a third Crate mass 3kg ), and they continue traveling to the right.
Solve for the speed of the first crate (m1) immediately before the first collision.
Solve for the mass of the second crate (m2).
Solve for the speed of the third crate (m3) after its collision.
How much energy is lost in the first collision?
How much energy is lost in the second collision?

Answers

The speed of the first crate (m1) immediately before the first collision is 8.97 m/s. The mass of the second crate (m2) is 4.00 kg.

What is speed ?

Speed is a measure of how quickly an object or person moves from one point to another. It is usually expressed in units of distance per unit of time, such as miles per hour or meters per second. Speed is a scalar quantity, meaning it only has magnitude and not direction. This means that when an object moves faster, its speed increases, but its direction remains the same. Speed can also refer to the rate at which something happens, such as the speed at which a chemical reaction occurs.

The speed of the third crate (m3) after its collision is 2.40 m/s.The energy lost in the first collision is 271.4 J.The energy lost in the second collision is 89.8 J.

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How does today's stereotyping, bias, and racial profiling intersect with religion? Are personal opinions fueled by social media outlets affecting how we understand or view religious beliefs?

Answers

Answer:

Today's stereotyping, bias, and racial profiling can intersect with religion in several ways. In many cases, individuals who are members of certain religious groups may be subject to stereotyping and prejudice based on their beliefs, dress, or appearance. This can lead to bias and discrimination in employment, housing, and other areas of life.

Racial profiling, or the use of race or ethnicity as a factor in law enforcement practices, can also intersect with religion in cases where individuals of certain religious groups are targeted for surveillance or scrutiny based on their perceived association with terrorism or other criminal activities. This can lead to a breakdown of trust between law enforcement and the affected communities, and can have negative consequences for public safety.

Personal opinions fueled by social media outlets can also affect how we understand or view religious beliefs. Social media can provide a platform for individuals to express their opinions and beliefs, but it can also perpetuate stereotypes and misinformation about certain religious groups. This can lead to polarization and divisiveness, and can contribute to a climate of fear and suspicion towards certain religious groups.

To address these issues, it's important to promote education and awareness about different religious beliefs and practices, and to work towards building inclusive and respectful communities. This can involve engaging in dialogue with individuals from different religious backgrounds, challenging stereotypes and prejudices, and advocating for policies that promote equity and justice for all.

Explanation:

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Vincent carrying his luggage with a mass of 10.5kg . If he does 100J of work to what height will raise it?

Answers

The height of the luggage with work done of 100J with a mass of 10.5 kg is 0.97m.

Work done equals the product of force and displacement. The energy that gets transferred by the force to move a object is called work done. Work done is equal to the potential energy of the object.

Work done = potential energy

                   = m×g×h

m is the mass of the luggage = 10.5 kg

g is the acc. due to gravity = 9.8 m/s

W is the work done = 100J

h (height) = W / (m×g)

               = 100 / ( 10.5×9.8)

              = 0.97 m

Thus, the luggage rises above the ground with a height of 0.97 m.

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A uniform bar of length 24 m and...

Answers

The magnitude of horizontal force, is 33.27 N.

Length of the uniform bar, L = 24 m

Mass of the uniform bar, m = 5 kg

Angle between the cord and the bar, θ₁ = 90°

Angle between the cord and the wall, θ₂ = 50°

For the horizontal equilibrium,

Hₓ = T sinθ₂

Hₓ = T x sin 50

Hₓ = 0.766 T

For the vertical equilibrium,

Hy + T cosθ₂ = mg

Hy + T cos 50 = 5 x 9.8

Hy + 0.642 T = 49 N

For rotational equilibrium,

mg (L/2) = T x L

So,

T = mg/2 = 5 x 9.8/2

T = 24.5 N

Therefore, the magnitude of horizontal force,

Hy = 49 - (0.642 x 24.5)

Hy = 49 - 15.73

Hy = 33.27 N

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What energy transformation takes place when you climb a ladder?
A. Mechanical energy transforms into elastic energy.
B. Potential energy transforms into thermal energy.
O C. Potential energy transforms into kinetic energy.
D. Kinetic energy transforms into potential energy.
SUBM

Answers

When you climb a ladder, your potential energy increases as you move upwards against gravity. Therefore, the energy transformation that takes place when you climb a ladder is:

Potential energy transforms into kinetic energy.

So, the correct answer is C.

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