The contribution to the percentage error in the freezing point depression due to the errors in the thermometer readings is 1.76%.
The freezing point depression is a colligative property that depends only on the molality of the solute particles in a solution and is independent of the identity of the solute. Therefore, the freezing point depression is given by the equation:
ΔTf = Kf x molality
where ΔTf is the change in the freezing point, Kf is the freezing point depression constant for the solvent, and molality is the concentration of solute particles in moles per kilogram of solvent.
However, in this case, there are errors in the thermometer readings that can contribute to the uncertainty in the calculated freezing point depression. The errors are +0.12°C for the initial thermometer and -0.11°C for the borrowed thermometer.
The total error due to thermometer readings is the sum of the errors from both thermometers, which is:
Total error = +0.12°C - 0.11°C = +0.01°C
The percentage error due to the thermometer readings can be calculated as:
Percentage error = (total error / measured freezing point) x 100%
The measured freezing point is the sum of the actual freezing point depression and the error due to the thermometer readings. Assuming that the actual freezing point depression was accurately measured, the measured freezing point can be expressed as:
Measured freezing point = actual freezing point depression + total error
Since the molality of the solution is given as 0.30, the actual freezing point depression can be calculated using the freezing point depression constant for the solvent.
Assuming a typical freezing point depression constant for the water of 1.86°C/m, the actual freezing point depression would be:
actual freezing point depression = Kf x molality = 1.86°C/m x 0.30 mol/kg = 0.558°C
Therefore, the measured freezing point would be:
Measured freezing point = actual freezing point depression + total error = 0.558°C + 0.01°C = 0.568°C
The percentage error due to the thermometer readings would be:
Percentage error = (total error / measured freezing point) x 100% = (0.01°C / 0.568°C) x 100% = 1.76%
To learn more about freezing point depression
https://brainly.com/question/12844810
#SPJ4
draw the products formed when the following alkene is treated with o3 followed by zn, h2o. be sure to answer all parts.
The given alkene can undergo ozonolysis in the presence of ozone (O3) followed by reduction with zinc (Zn) and water (H2O) to yield two products.
The ozonolysis reaction cleaves the double bond in the alkene and generates two carbonyl compounds, which can then be reduced by zinc to form aldehydes or primary alcohols depending on the reaction conditions.
The ozonolysis of the given alkene, 2-methyl-2-pentene, results in the formation of two carbonyl compounds: propanal and 2-methylpropanal. These carbonyl compounds can then undergo reduction with zinc and water to form the corresponding aldehydes or primary alcohols.
The reduction of propanal with zinc and water results in the formation of propan-1-ol, which is a primary alcohol. The reaction involves the addition of hydrogen atoms to the carbonyl group of propanal, followed by the removal of the resulting oxygen atom as water. The reduction of 2-methylpropanal with zinc and water results in the formation of 2-methylpropan-1-ol, which is also a primary alcohol. The reduction mechanism is similar to that of propanal, but with the addition of hydrogen atoms to the carbonyl group of 2-methylpropanal instead.
In summary, the products formed when 2-methyl-2-pentene is treated with ozone followed by zinc and water are propan-1-ol and 2-methylpropan-1-ol. These products are formed by ozonolysis of the alkene to generate carbonyl compounds, followed by reduction of the carbonyl compounds to primary alcohols with zinc and water. This reaction demonstrates the versatility of ozonolysis and reduction reactions in synthesizing aldehydes and primary alcohols from alkenes, which are important building blocks in organic chemistry.
To know more about alkene: https://brainly.com/question/13910028
#SPJ4
the mass of a proton is 1.0074 amu, the mass of a neutron is 1.0087 amu, and the mass of an electron is 0.00054858 amu. given this information, what can you predict for the mass of a single atom of 3h (tritium)?
It will have a mass of 3.025 amu. This is because the mass of a tritium atom is made up of the mass of one proton, two neutrons, and three electrons.
The mass of a single atom of 3H (tritium) can be predicted by adding the mass of the three protons, three neutrons, and three electrons in the atom. Since a single atom of 3H (tritium) contains 3 protons, 3 neutrons, and 3 electrons, the mass of a single atom of 3H (tritium) can be calculated by adding the mass of each of these particles together.
The mass of a single atom of 3H (tritium) can be calculated using the equation:
Mass of 3H (tritium) = [tex](3 * Mass of Proton) + (3 * Mass of Neutron) + (3 * Mass of Electron)[/tex]
Mass of 3H (tritium) =[tex](3 *1.0074 amu) + (3 *1.0087 amu) + (3 * 0.00054858 amu)[/tex]
Mass of 3H (tritium) = [tex]3.0218 amu[/tex]
Therefore ,he mass of a single atom of 3h (tritium) is 3.0218 amu
learn more about tritium Refer:brainly.com/question/13559964
#SPJ4
complete question:the mass of a proton is 1.0074 amu, the mass of a neutron is 1.0087 amu, and the mass of an electron is 0.00054858 amu. given this information, what can you predict for the mass of a single atom of 3h (tritium)?
it will have a mass of exactly 3 amu
it will have a mass of 1.008 amu
it will have a mass of 3.025 amu
it will have a mass somewhat greater than 3.025 amu
it will have a mass somewhat less than 3.025 amu
list Two examples of seeds that are dispersal by water
Answer:
okay
Explanation:
Coconut, palm, mangroves, water lily, water mint, are a few examples of plants whose seed are dispersed by the water.
The molecular formula of sucrose is C12H22O11.
A sucrose sample contains 3.6 × 1024 atoms of
carbon. How many molecules of sucrose are in the
sample?
3.6 x 1024 atoms C 1 molecule C₁2H22 011
12 atoms C
[?] x 10 molecules C12H22011
X
Coefficient (green)
Exponent (yellow)
There are 1.81 × 10²⁴ molecules of sucrose in the given sample.
How many molecules of sucrose are in the sample?
To calculate the number of molecules of sucrose in the given sample, we need to first determine the number of moles of carbon atoms present in the sample, and then use the molecular formula of sucrose to calculate the number of molecules.
Calculate the number of moles of carbon atoms in the sample:
We know that the sample contains 3.6 × 10²⁴ atoms of carbon. The molar mass of carbon is approximately 12 g/mol.
Therefore, the mass of carbon in the sample can be calculated as follows:
mass of carbon = number of atoms of carbon × molar mass of carbon
= 3.6 × 10²⁴ × 12 g/mol
= 4.32 × 10²⁵ g
To calculate the number of moles of carbon in the sample, we divide the mass of carbon by the molar mass of carbon:
number of moles of carbon = mass of carbon / molar mass of carbon
= 4.32 × 10²⁵ g / 12 g/mol
= 3.6 × 10²⁴ mol
Calculate the number of molecules of sucrose in the sample:
To calculate the number of molecules of sucrose in the sample, we can use the following formula:
number of molecules of sucrose = (number of moles of carbon / 12) × Avogadro's number
where;
Avogadro's number is approximately 6.02 × 10²³ molecules/mol.Substituting the values, we get:
number of molecules of sucrose = (3.6 × 10²⁴ mol / 12) × 6.02 × 10²³ molecules/mol
= 1.81 × 10²⁴ molecules
Learn more about number of molecules here: https://brainly.com/question/15379971
#SPJ1
if the rate of appearance of no2 is equal to 0.560 mol/min at a particular moment, what is the rate of appearance of o2 at that moment?
the rate of appearance of O2 at that particular moment would be 0.280 mol/min for no2 is equal to 0.560 mol/min at a particular moment.
The balanced chemical equation for the reaction that produces NO2 and O2 would be helpful to answer this question. Assuming the reaction is:
2 NO → 2 NO2 + O2
The stoichiometry of the reaction tells us that for every 2 moles of NO that disappear, 2 moles of NO2 and 1 mole of O2 are produced. Therefore, the rate of appearance of O2 would be half the rate of appearance of NO2, or:
Rate of appearance of O2 = (0.560 mol/min) / 2 = 0.280 mol/min
So the rate of appearance of O2 at that particular moment would be 0.280 mol/min.
To know more about O2 :-
brainly.com/question/10685852
#SPJ4
what type of bonding involves the transfer of electrons to form cations and anions?
An ionic bond is a stable bond created by the full transfer of the valence electron.
What is electron transfer?When an electron moves from one atom or molecule to another one of these chemical entities, this is known as electron transfer. When it comes to specific redox reactions involving the transfer of electrons, ET is a mechanistic description. ETRs are electrochemical processes.
ETRs are electrochemical processes. Transition metal complexes are frequently used in ET processes, which are relevant to respiration and photosynthesis. ET is a step in various commercial polymerization processes in organic chemistry. It serves as the basis for photoredox catalysis.
Learn more about electron transfer here:
https://brainly.com/question/15271406
#SPJ1
You would like to determine if the temperature inside a freezer is lower than 0°C. Using a glass of liquid water, describe how you could estimate the temperature. Could you determine if the freezer has a temperature of −10°C by just using the glass of water?
Yes, you can determine if the temperature inside a freezer is below 0°C by using a glass of liquid water. Here's how:
Fill a glass with room-temperature water.Place the glass of water inside the freezer and let it sit for a few minutes, until the water has stabilized at the temperature of the freezer.Observe the state of the water. If the water is still liquid, then the temperature inside the freezer is above 0°C. If the water is beginning to freeze, with ice forming on the surface, then the temperature is below 0°C.However, it is not possible to determine the exact temperature of the freezer by just using a glass of water. The temperature can only be estimated by observing the state of the water and making a rough guess based on the extent of the freezing.
For example, if the water is just starting to freeze, then the temperature could be close to 0°C. If the water has mostly frozen, then the temperature could be closer to -10°C. However, without a thermometer, the exact temperature cannot be determined.
To learn more about temperature refer this link
https://brainly.com/question/11384928
#SPJ4
what piece of lab equipment would you use to estimate the volume of a drop of water?
To estimate the volume of a drop of water, you can use a piece of lab equipment called a micropipette.
A micropipette is a precision instrument that is used to measure and transfer small volumes of liquid. It works by suctioning up a known volume of liquid and then dispensing it into a test tube or other vessel. The micropipette is accurate to within 0.1-1% of the total volume, making it ideal for measuring small volumes such as drops of water.
To know more about micropipette please refer:
https://brainly.com/question/17207502
#SPJ4
What is the mass of sulfur in
2.0 moles of Al2(SO4)3?
A. 192.42 g
B. 32.07 g
C. 64.14 g
D. 160.35 g
Answer:
I guess your answer would be A even thought it is not actually correct it is the closest to being correct.
Explanation:
The molar mass of Al2(SO4)3 is 342.15 g/mol. This means that 1 mole of Al2(SO4)3 has a mass of 342.15 g.To find the mass of sulfur in 2.0 moles of Al2(SO4)3, we first need to determine the number of moles of sulfur in 1 mole of Al2(SO4)3. There are 3 moles of sulfur in 1 mole of Al2(SO4)3, so there are 6 moles of sulfur in 2 moles of Al2(SO4)3.To find the mass of sulfur in 2.0 moles of Al2(SO4)3, we can use the following calculation:Mass of sulfur = (moles of sulfur) x (molar mass of sulfur)
Mass of sulfur = 6 mol x 32.06 g/mol
Mass of sulfur = 192.36 gTherefore, the mass of sulfur in 2.0 moles of Al2(SO4)3 is 192.36 grams.
In water, a substance that ionizes completely in solution is called a a. weak electrolyte b. nonelectrolyte c. nonconductor d. strong electrolyte
In water, a substance that is ionizes totally and completely in solution is called strong electrolyte.
Ionization is a process in which a neutral snippet or patch earnings or loses one or further electrons. The performing charged snippet/ patch is called an ion. A appreciatively charged ion is called a cation, while a negatively charged ion is called an anion.
The ionization process is used in a wide variety of outfit, for illustration, spectrometer, radiation remedy, fluorescent lights,etc.
Strong electrolytes are ones that completely ionise or dissociate in their aqueous solution.
These electrolytes have a higher extension of ionisation and a high electrical conductivity.
Learn more about Strong electrolyte:
https://brainly.com/question/2285692
#SPJ4
What is the boiling point, in °C, of a 0.527 m aqueous solution of LiBr?
BP(water) = 100 °C
Kb (water) = 0.512 °C/m [ ? ] °C
To solve this we must know the concept behind the phenomenon of elevation in boiling point when a non volatile solute is added to any solvent. Therefore, boiling point in °C of a 0.527 m aqueous solution of LiBr is 100.54 °C.
Mathematically,
ΔT= Kb× molality
The complete balanced equation can be written as
LiBr → Li⁺ + Br⁻ [two ions]
substituting all the given values in the above mathematical expression, we get
(0.527 m LiBr) x (2 mol ions / 1 mol LiBr) = 1.054 m ions
(0.512 °C/m) x (1.054 m) = 0.540 °C change
100.00°C + 0.540 °C = 100.54 °C
Therefore, the boiling point in °C of a 0.527 m aqueous solution of LiBr is 100.54 °C.
What is elevation in boiling point ?
The boiling point of a solvent rises whenever a non-volatile solute is added.To know more about elevation in boiling point, click the link given below:
brainly.com/question/16922336
#SPJ1
a piston confines 0.200 mol ne(g) in 1.20 l at 25 8c. two experiments are performed. (a) the gas is allowed to expand through an additional 1.20 l against a constant pressure of 1.00 atm. (b) the gas is allowed to expand reversibly and isothermally to the same final volume. which process does more work?
A piston confines 0.200 mol Ne(g) in 1.20 l at 25 °C . Two experiments are performed. The process does more work is the second experiment.
(a) The gas is allowed to expand through the additional 1.20 L against the constant pressure of the 1.00atm
Irreversible path is as :
W = -Pex × ΔV
Where
Pex = 1.00 atm
ΔV = 1.20 L
W = - (1.00 atm) × 1.20 L
W = -1.20 L. atm × 101.325 J /1 L.atm
W = -121.59 J
(b) The gas is allowed to expand the reversibly and the isothermally to the same final volume is as :
W = - nRT ln (V final / V initial)
Where
n = the number of moles = 0.200
R = gas constant = 8.3145 J/K.mol
T = 298 Kelvin
V final / V initial = 2.40 / 1.20 = 2
W = - (0.200mol) × 8.3145 J/K.mol × 298K × ln(2.4/1.2)
W = - 343.5 J
Thus the second one does the more work.
To learn more about work here
https://brainly.com/question/13945379
#SPJ4
supposing the stock room wants to prepare 50.0 ml a 0.080 m solution of oxalic acid (h2c2o4). explain the entire process showing all the necessary calculations. ensure you are watching the significant figures.
Oxalic acid is a colorless, crystalline, organic compound belonging to the family of carboxylic acids. It is a strong dicarboxylic acid, with the molecular formula [tex]H2C2O4[/tex].
Given the volume of oxalic acid (h2c2o4) = 50mL
the concentration of oxalic acid = 0.080M
1. Calculate the moles of [tex]H2C2O4[/tex] needed for the solution:
Moles of [tex]H2C2O4[/tex] = (50.0 mL x 0.080 M) / 1000 mL = 0.004 moles
2. Calculate the mass of [tex]H2C2O4[/tex] needed for the solution:
Mass of [tex]H2C2O4[/tex] = 0.004 moles x 90.03 g/mol = 0.3609 g
3. Place 0.3609 g of [tex]H2C2O4[/tex] into a beaker and add 50.0 mL of distilled water.
4. Stir the solution to dissolve the [tex]H2C2O4[/tex].
5. If necessary, add more distilled water to make sure all of the oxalic acid has dissolved.
6. Measure the final volume of the solution and calculate the molarity:
Molarity = (0.004 moles x 1000 mL) / Final Volume (mL)
To learn more about oxalic acid click here https://brainly.com/question/10967292
#SPJ4
How the angle b/w AB6 type molecules is 90
The angle between AB6 molecules is determined by the number of bonds between the atoms. AB6 molecules are molecules that are composed of six atoms in a ring. Each of the atoms is connected to two other atoms.
What is the atoms?Atoms are the basic building blocks of all matter. They are the smallest particles of an element that still retain their chemical identity. Atoms are composed of a nucleus made of protons and neutrons, surrounded by electrons in shells. The number of protons in an atom determines the element it is, and the number of neutrons can vary to give different isotopes of the same element. Atoms can be combined by chemical bonds to form molecules and other compounds. The properties of an atom are determined by its electron configuration which can be altered by chemical reactions.
To learn more about atoms
https://brainly.com/question/6258301
#SPJ1
.What is the gram-formula mass of a compound if 5 moles of the compound have a mass
of 100 grams?
The gram formula mass of a compound if 5 moles of the compound have a mass of 100 grams would be 20 grams/mole.
What is gram-formula mass?The gram formula mass of a compound is the total weight of all atoms in a molecule or a formula unit of a substance.
It is also the ratio of the mass of a compound and the number of moles present in the mass of the compound.
Gram formula mass = mass/mole
In this case, mass = 100 grams, and mole = 5 moles
Gram formula mass = 100/5
= 20 grams/mole
In other words, the gram formula mass of the compound is 20 grams/mole.
More on gram formula mass can be found here: https://brainly.com/question/15232447
#SPJ1
why was it important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution
It important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution because it affects the freezing point of the solution.
When a solute dissolves in a solvent, it reduces the solvent's freezing point, which implies the solution must be chilled to a lower temperature than the pure solvent in order to freeze. This is referred to as freezing point depression.
If the solute is not entirely dissolved in the solvent, the resultant solution may have a non-uniform composition, with greater concentrations of solute in certain places than in others. This might cause the freezing point of the solution to be lower than predicted, as well as the production of crystals or other solid particles, which can interfere with the experiment's accuracy.
Furthermore, if the solute is not entirely dissolved, the resultant solution may not be homogenous, and its characteristics may differ from one section of the sample to the next. This might result in inconsistencies and inaccuracies in the experiment.
For more such questions on cyclohexane, click on:
https://brainly.com/question/28559170
#SPJ4
two porous containers are filled with hydrogen and neon respectively. under identical conditions, 2/3 of the hydrogen escape in 6 hours. how long will it take for half the neon to escape?
Using Grahams law, after calculation it takes about 2 * (1/0.223) = 2.24 times as long for half of the neon to escape, or approximately 13.44 hours.
We can use Graham's Law to solve this problem, as it relates the rate of effusion of a gas to its molar mass. According to Graham's Law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.
Let's assume that the rate of effusion of hydrogen is 1. We need to find the time it takes for half of the neon to escape, given that 2/3 of the hydrogen has escaped in 6 hours.
From Graham's Law, we know that:
(rate of effusion of hydrogen) / (rate of effusion of neon) = sqrt(molar mass of neon) / sqrt(molar mass of hydrogen)
We can rearrange this equation to solve for the rate of effusion of neon:
(rate of effusion of neon) = (sqrt(molar mass of hydrogen) / sqrt(molar mass of neon)) * (rate of effusion of hydrogen)
Since we know that the rate of effusion of hydrogen is 1, we can simplify the equation to:
(rate of effusion of neon) = (sqrt(molar mass of hydrogen) / sqrt(molar mass of neon))
We can find the ratio of the molar mass of hydrogen to neon from the periodic table. The molar mass of hydrogen is 1 g/mol, and the molar mass of neon is 20.18 g/mol. Therefore:
(sqrt(molar mass of hydrogen) / sqrt(molar mass of neon)) = (sqrt(1 g/mol) / sqrt(20.18 g/mol)) = 0.223
So, the rate of effusion of neon is 0.223 times the rate of effusion of hydrogen. If 2/3 of the hydrogen has escaped in 6 hours, then 1/3 of the hydrogen is still in the container after 6 hours. Since the rate of effusion of neon is 0.223 times the rate of effusion of hydrogen, we can assume that the rate of effusion of neon is constant and also 0.223. Therefore, it will take 1/2 * (1/0.223) = 2.24 times as long for half of the neon to escape, or approximately 13.44 hours.
To learn more about Grahams law Click here:
brainly.com/question/12415336
#SPJ4
Which mass of Carbon id produced?
Answer:
(c) 4.4g
Explanation:
Given:
mass of calcium carbonate (mCaCO3) = 10g
MrCaCO3 = 100
To find: mCO2
Solution:
CaCO3 + 2HCl → CaCl 2 + H2O + CO2
Now,
MrCaCO3 = 40 + 12 + 16.3 = 100
Therefore,
Number of moles (n) = m/Mr
nCaCO3 = 10/100 = 0.1
The amount of moles is proportional to the coefficient of the reaction. Since both calcium carbonate (CaCO3) and carbon dioxide (CO2) have the same coefficient.
nCO2 = 0.1
MrCO2 = 12 + 16.2 = 44
mCO2 = 0.1 × 44 = 4.4g
pls help thank you very much
Answer:
a copper is the answer to ur
magnesium po hahahahahaha
Write the net ionic equation for the precipitation reaction that occurs when aqueous magnesium chloride is mixed with aqueous sodium phosphate. Be sure to include the physical states of all species. Determine the mass of precipitate that forms when 125 mL of 0.222 M aqueous magnesium chloride it mixed with 225 mL of 0.105 M aqueous sodium phosphate.
The net ionic equation for the precipitation reaction when aqueous sodium phosphate and magnesium chloride are combined is 3MgCl2 (aq) + 2Na3(PO4) (aq) -----> Mg3(PO4)2 (s) + 3Na+ (aq) + 3Cl- (aq).
Taken moles of magnesium chloride equal 0.125 * 0.22, or 0.02775 moles.
Taken moles of sodium phosphate equal 0.225*0.105, or 0.023625 moles.
Magnesium chloride is the limiting reagent in the process, according to stoichiometry.
Hence, the moles of magnesium phosohate that will develop are: 0.02775/3 = 0.00925
Mass of magnesium phosphate ppt is therefore equal to moles*MW = 0.00925*263 = 2.432 g.
MgCl2 and H2 are produced when solid magnesium interacts with HCl. It goes like this: Mg(s) + 2HCl(aq) = MgCl2(aq) + H2 (g). HCl and solid magnesium carbonate react to form MgCl2, CO2, and H2O.
Learn more about magnesium chloride here:
https://brainly.com/question/13927229
#SPJ4
if the temperature of the hydrogen gas was underestimated, would this error cause the gas constant to be overestimated, underestimated, or remain unaffected? please explain your reasoning.
This error would cause the gas constant to be underestimated because the gas constant is a function of temperature and pressure.
If the temperature is underestimated, then the pressure calculated would be too high, resulting in an underestimation of the gas constant. The gas constant would remain unaffected because it does not depend on the temperature of the hydrogen gas. The gas constant is a physical constant which is the same for all gases regardless of their temperature or pressure. The gas constant is defined as the ratio of the universal gas constant (R) to the molar mass (M) of a particular gas. It is a measure of the ideal gas law and is equal to 8.3144598 joules per Kelvin per mole (J/K/mol). Therefore, an error in the temperature of the hydrogen gas would not affect the gas constant.
To learn more about hydrogen click here https://brainly.com/question/11837837
#SPJ4
7) Using the following balanced equation 4 Fe(s) + 302(g) → 2Fe2O3(s)
a) How many moles of product would be produced by complete reaction of 0.15 moles of iron? (Be sure to show
your work including the mole ratio you used)
Answer:
0.075 moles
Explanation:
Looking at the balanced equation, 4 moles of Fe(s) react with 3 moles of [tex]O_{2}[/tex] to produce 2 moles of [tex]Fe_{2}O_{3}[/tex] (s). In other words, for every 4 moles of Fe(s) used, there are 2 moles of product. The mole ratio is therefore 4:2, or 2:1. In other words, you divide the moles of Fe by two to find the moles of product.
There are 0.15 moles of Fe, so the moles of product should be half of this according to the molar ratio.
0.15 / 2 = 0.075Your answer is 0.075 moles.
Hope this helps!
Please help
What volume, in liters, of 4.0 M LiBr solution can be made using 100.0 g LiBr?
(LiBr; 86.44 g/mol) [?] L
ANS = 0.288 L can be made.
How can we find the volume?The first thing that you need to do here is to convert the mass of lithium bromide to moles by using the compound's molar mass.
The number of moles of the solute—in your example, lithium bromide—present per 1.00 L of the solution is simply referred to as the molarity of the solution.
For every 1.00 L of this solution, 4.00 moles of lithium bromide must be present in order to create a 4.00-M solution.
You may calculate how many litres of this solution can be made using the molarity of the solution as a conversion factor because you already know that your sample contains 1.1515 moles of lithium bromide.
To know more about volume visit:
https://brainly.com/question/1578538
#SPJ1
Calculate the volume of oxygen that will be spent on burning 300 liters of ethane containing 5.8% non-combustible impurities
Answer:
To calculate the volume of oxygen that will be required to burn 300 liters of ethane containing 5.8% non-combustible impurities, we need to determine the amount of pure ethane present.
Since the ethane contains 5.8% non-combustible impurities, 100 - 5.8 = 94.2% of the 300 liters of ethane is pure and can be burned.
The amount of pure ethane is 94.2% * 300 liters = 282.6 liters.
The stoichiometric equation for the complete combustion of ethane is:
C2H6 + 7O2 -> 4H2O + 6CO2
This equation tells us that for every molecule of ethane that is burned, 7 molecules of oxygen are required.
The volume of oxygen required for burning 282.6 liters of ethane is 282.6 liters * 7 = 1989.2 liters.
So, the volume of oxygen that will be required to burn 300 liters of ethane containing 5.8% non-combustible impurities is 1989.2 liters.
Assuming that the non-combustible impurities have no effect on the combustion of ethane, we can calculate the volume of oxygen required to burn 300 liters of ethane as follows:
Write the balanced chemical equation for the combustion of ethane:
C2H6 + 3.5 O2 -> 2 CO2 + 3 H2O
Determine the stoichiometry of the reaction, which tells us the molar ratio of ethane to oxygen required for complete combustion. From the balanced equation, we see that 1 mole of ethane reacts with 3.5 moles of oxygen.
Convert the volume of ethane from liters to moles, using the ideal gas law:PV = nRT
where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the gas constant, and T is the temperature of the gas. Assuming standard temperature and pressure (STP), which is 1 atm and 0°C, we have:
n = PV/RT = (1 atm * 300 L)/(0.08206 Latm/molK * 273 K) = 12.5 moles of ethane
Calculate the amount of oxygen required for combustion, using the stoichiometry of the reaction:3.5 moles of O2 are required for 1 mole of ethane, so for 12.5 moles of ethane, we need:
12.5 moles of ethane * 3.5 moles of O2/mole of ethane = 43.75 moles of O2
Convert the moles of oxygen to volume, again using the ideal gas law:V = nRT/P = (43.75 mol * 0.08206 Latm/molK * 273 K)/1 atm = 994.8 L of O2
Therefore, approximately 994.8 liters of oxygen will be spent on burning 300 liters of ethane containing 5.8% non-combustible impurities.
Select all the correct answers.
Fireworks are chemical reactions that release energy. Which of these phenomena are caused by chemical reactions that release energy?
A) Muscles work to perform a task.
B) Fuel burns and heats the surroundings
C) A battery supplies current to a device.
D) A car's air bag expands by igniting a chemical.
PLEASE BE ACCURATE!!! Thank you very much:)
Answer:
B) Fuel burns and heats the surroundings
D) A car's air bag expands by igniting a chemical.
Explanation:
These two phenomena are caused by chemical reactions that release energy. In the case of B, fuel burning releases energy in the form of heat and light. In the case of D, the ignition of a chemical in a car's air bag rapidly releases a large amount of energy, causing the air bag to rapidly inflate and protect the occupants of the car during an accident.
ALLEN
Answer:
D) A car's air bag expands by igniting a chemical.
Explanation:
Fireworks are a type of pyrotechnic display that are created by chemical reactions that release energy in the form of light, heat, and sound. These chemical reactions are usually accomplished through the use of oxidizers, fuel, and various chemicals that are carefully combined to produce the desired effects.
A) Muscles work to perform a task is not caused by a chemical reaction that releases energy. Instead, it is caused by the contraction of muscle fibers, which generate force to move the body or an object.
B) Fuel burns and heats the surroundings is caused by a chemical reaction that releases energy. When fuel, such as gasoline or wood, is burned, it reacts with oxygen in the air to release heat and light.
C) A battery supplies current to a device is not caused by a chemical reaction that releases energy. Instead, it is caused by the flow of electrons through a conductive material, such as a wire.
D) A car's air bag expands by igniting a chemical is caused by a chemical reaction that releases energy. The air bag is typically activated by a chemical reaction between two substances that generates a large amount of gas, which rapidly inflates the air bag to protect the occupants of the vehicle.
Copper is an element. How do these images of copper illustrate this?
Copper is an element which comprises of same kind of atoms which can be illustrated by the images.
What is an element?It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.
Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.
Learn more about elements,here:
https://brainly.com/question/13516179
#SPJ9
Your question is incomplete, but most probably your full question with attached image is:Copper is an element. How do these images of copper illustrate this?
1. Calculate pH of 5M solution of NaOH.
Answer:
the pH of the solution is 5.5.
Explanation:
the concentration is 5 moles per liter and the acidity or alkalinity is 0.5 moles per liter.
what kind of bonds are responsible for the unique cohesion, surface tension, and adhesion properties of water molecules?
can you substitute confectioners sugar for granulated sugar.true/false
The answer is true, confectioners sugar can be substituted for granulated sugar but it may not always be an exact 1:1 substitution.
Confectioners sugar (also known as powdered sugar or icing sugar) can be substituted for granulated sugar in some recipes, but it may not always be an exact 1:1 ratio substitution.
Confectioners sugar is a very fine powder that contains cornstarch, which is added to prevent caking. Due to its fine texture, it can dissolve quickly in recipes and can add a slightly different texture to baked goods. It can also affect the sweetness level of the recipe as it usually contains cornstarch or other additives, which can also influence the texture of the final product.
In general, substituting confectioners sugar for granulated sugar works best in recipes that don't require the sugar to dissolve completely, such as frosting or glazes. For recipes that require the sugar to dissolve, such as in baking or making meringues, it's best to use granulated sugar.
So, the answer is "True", but the substitution may not be appropriate for all recipes.
To learn more about granulated sugar Click here:
brainly.com/question/30634284
#SPJ4
Draw the structure of cis-jasmone, a natural product isolated from jasmine flowers, formed by treatment of alkyne A with H2, in the presence of the Lindlar catalyst. Click the "draw structure" button to launch the drawing utility.
The resulting product is cis-jasmone, which has the following structure:
H
|
CH3-CH-CH=CH-CH=O
|
CHO
The synthesis of cis-jasmone involves the hydrogenation of an alkyne in the presence of a Lindlar catalyst. Specifically, alkyne A is treated with hydrogen gas (H2) and a Lindlar catalyst, which is a type of palladium catalyst that selectively hydrogenates alkynes to cis-alkenes. The reaction conditions prevent complete reduction of the alkyne to an alkane. The molecule has a six-carbon ring with a double bond between carbons 2 and 3 and a carbonyl group (C=O) attached to carbon 6. The two methyl groups attached to carbons 1 and 2 are both on the same side of the ring, giving the molecule a cis configuration.
To learn more about cis-jasmone refer to this link
https://brainly.com/question/30667001
#SPJ4
